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(1,1)(1,1) L-space knots

Joshua Evan Greene Department of Mathematics, Boston College
Chestnut Hill, MA 02467
joshua.greene@bc.edu
Sam Lewallen Princeton Neuroscience Institute, Princeton University
Princeton, NJ 08544
lewallen@princeton.edu
 and  Faramarz Vafaee Mathematics Department, California Institute of Technology
Pasadena, CA 91125
vafaee@caltech.edu

Abstract. We characterize the (1,1)(1,1) knots in the three-sphere and lens spaces that admit non-trivial L-space surgeries. As a corollary, 1-bridge braids in these manifolds admit non-trivial L-space surgeries. We also recover a characterization of the Berge manifold amongst 1-bridge braid exteriors.

1. Introduction.

An L-space is a rational homology sphere YY with the “simplest” Heegaard Floer invariant: HF^(Y)\widehat{HF}(Y) is a free abelian group of rank |H1(Y;)||H_{1}(Y;{\mathbb{Z}})|. Examples abound and include lens spaces and, more generally, connected sums of manifolds with elliptic geometry [OS05]. One of the most prominent problems in relating Heegaard Floer homology to low-dimensional topology is to give a topological characterization of L-spaces. Work by many researchers has synthesized a bold and intriguing proposal that seeks to do so in terms of taut foliations and orderability of the fundamental group [Juh15, Conjecture 5].

A prominent source of L-spaces arises from surgeries along knots. Suppose that KK is a knot in a closed three-manifold YY. If KK admits a non-trivial surgery to an L-space, then KK is an L-space knot. Examples include torus knots and, more generally, Berge knots in S3S^{3} [Ber]; two more constructions especially pertinent to our work appear in [HLV14, Vaf15]. If an L-space knot KK admits more than one L-space surgery – for instance, if YY itself is an L-space – then it admits an interval of L-space surgery slopes, so it generates abundant examples of L-spaces [RR15]. With the lack of a compelling guiding conjecture as to which knots are L-space knots, and as a probe of the L-space conjecture mentioned above, it is valuable to catalog which knots in various special families are L-space knots. This is the theme of the present work.

The manifolds in which we operate are the rational homology spheres that admit a genus one Heegaard splitting, namely the three-sphere and lens spaces. The knots we consider are the (1,1)(1,1) knots in these spaces: these are the knots that can be isotoped to meet each Heegaard solid torus in a properly embedded, boundary-parallel arc. Our main result, Theorem 1.2 below, characterizes (1,1)(1,1) L-space knots in simple, diagrammatic terms.

A (1,1)(1,1) diagram is a doubly-pointed Heegaard diagram (Σ,α,β,z,w)(\Sigma,\alpha,\beta,z,w), where (Σ,α,β)(\Sigma,\alpha,\beta) is a genus one Heegaard diagram of a 3-manifold YY. The (1,1)(1,1) knots in YY are precisely those that admit a doubly-pointed Heegaard diagram [GMM05, Hed11, Ras05]. A (1,1)(1,1) diagram is reduced if every bigon contains a basepoint. We can transform a given (1,1)(1,1) diagram of KK into a reduced (1,1)(1,1) diagram of KK by isotoping the curves into minimal position in the complement of the basepoints: we accomplish this by successively isotoping away bigons in the complement of the basepoints and the curves in Σ\Sigma. Our characterization of (1,1)(1,1) L-space knots in S3S^{3} and lens spaces is expressed in terms of the following property of (1,1)(1,1) diagrams:

Definition 1.1.

A reduced (1,1)(1,1) diagram (Σ,α,β,z,w)(\Sigma,\alpha,\beta,z,w) is coherent if there exist orientations on α\alpha and β\beta that induce coherent orientations on the boundary of every embedded bigon (D,D)(Σ,αβ)(D,{\partial}D)\subset(\Sigma,\alpha\cup\beta). Its sign, positive or negative, is the sign of αβ\alpha\cdot\beta, with these curves coherently oriented.

Coherence is easy to spot in a diagram: see Figures 1 and 2 and the second paragraph of Subsection 2.3.

We may now state the main result of the paper:

Theorem 1.2.

A reduced (1,1)(1,1) diagram presents an L-space knot if and only if it is coherent. The knot is a positive or negative L-space knot according to the sign of the coherent diagram.

The sign of an L-space knot is the sign of an L-space surgery slope along it, which we review in Subsection 2.1. Note that a given knot may admit non-homeomorphic coherent (1,1)(1,1) diagrams. However, Theorem 1.2 implies that its reduced (1,1)(1,1) diagrams are either all incoherent or else all coherent and of the same sign. Again, see Figure 1.

We apply Theorem 1.2 to show that a broad family of (1,1)(1,1) knots are L-space knots. We recall the following construction, first studied by Berge [Ber91] and Gabai [Gab90], and state a natural generalization of it.

Definition 1.3.

A knot in the solid torus S1×D2S^{1}\times D^{2} is a 1-bridge braid if it is isotopic to a union of two arcs γδ\gamma\cup\delta such that

  • γ(S1×D2)\gamma\subset{\partial}(S^{1}\times D^{2}) is braided, i.e., transverse to each meridian pt.×D2\mathrm{pt.}\times{\partial}D^{2}, and

  • δ\delta is a bridge, i.e., properly embedded in some meridional disk pt.×D2\mathrm{pt.}\times D^{2}.

It is positive if γ\gamma is a positive braid in the usual sense. A knot in a closed three-manifold YY with a genus one Heegaard splitting is a 1-bridge braid if it is isotopic to a 1-bridge braid supported within one of the Heegaard solid tori.

J. and S. Rasmussen conjectured that a positive 1-bridge braid in S3S^{3} is a positive L-space knot at the end of [RR15]. We prove a generalization of their conjecture in Theorem 3.2. Without the sign refinement, the result reads:

Theorem 1.4.

1-bridge braids in S3S^{3} and lens spaces are L-space knots.

Krcatovich has found many examples of (1,1)(1,1) L-space knots in S3S^{3} that are not 1-bridge braids by a computer search [Krc]. A small representative is the knot K(21,4,4,11)K(21,4,4,11) in the notation of [Ras05]. He showed that it is an L-space knot by an application of Theorem 1.2, and that its Alexander polynomial distinguishes it from 1-bridge braids by comparing with a list tabulated by J. Rasmussen.

We collect the necessary background on Heegaard Floer homology and prove Theorem 1.2 in Section 2. We prove Theorem 1.4 and its sign-refined version, Theorem 3.2, in Section 3. We also use Theorem 3.2 to characterize the Berge manifold in Proposition 3.4.

We leave open two natural problems: the isotopy classification of (1,1)(1,1) L-space knots, and the determination of whether surgeries along these knots conform to [Juh15, Conjecture 5].

Acknowledgments.

We thank Matt Hedden, Jen Hom, David Krcatovich, Adam Levine, Clayton McDonald, Yi Ni, and Alex Zupan for helpful conversations. We thank the referee for a very thorough and thoughtful review. Sam Lewallen would like to thank Zoltán Szabó for suggesting he study (1,1)(1,1) L-space knots, and both Zoltán and Liam Watson for their interest and encouragement. JEG was supported by NSF CAREER Award DMS-1455132 and an Alfred P. Sloan Foundation Research Fellowship. SL was supported by an NSF Graduate Research Fellowship.

Refer to caption

wwzzα\alphaβ\beta

Figure 1. At top, two reduced diagrams of the twist knot 525_{2}, and at bottom, two reduced diagrams of the torus knot T(2,7)T(2,7). The top two are incoherent: with the β\beta curve oriented, the “rainbow” arcs over the ww basepoint do not all orient the same way. The bottom two are positive coherent, as all of the rainbow arcs do orient the same way, and αβ>0\alpha\cdot\beta>0.

2. Proof of the characterization.

We assume familiarity with (knot) Floer homology and review the essential input for our work in Subsections 2.1 and 2.2. In particular, we follow the treatment of [RR15, §2.2], with slight differences in notation. We prove Theorem 1.2 in Section 2.3.

2.1. Knot Floer homology and L-space knots.

Let KK denote a (doubly pointed) knot in a rational homology sphere YY. Let N(K)N(K) denote an open tubular neighborhood of KK, X=YN(K)X=Y\smallsetminus N(K) the knot exterior, and μX\mu\subset{\partial}X a meridian of KK. Let Spinc(Y){\mathrm{Spin}^{c}}(Y) denote the set of spinc{\mathrm{spin^{c}}} structures on YY and Spinc(X,X){\mathrm{Spin}^{c}}(X,{\partial}X) the set of relative spinc{\mathrm{spin^{c}}} structures on (X,X)(X,{\partial}X). They are torsors over the groups H1(Y;)H_{1}(Y;{\mathbb{Z}}) and H1(X;)H_{1}(X;{\mathbb{Z}}), respectively. Let Spinc(K){\mathrm{Spin}^{c}}(K) denote the set of orbits in Spinc(X,X){\mathrm{Spin}^{c}}(X,{\partial}X) under the action by [μ][\mu]. It forms a torsor over H1(X;)/[μ]H1(Y;)H_{1}(X;{\mathbb{Z}})/[\mu]\approx H_{1}(Y;{\mathbb{Z}}), and there exists a pair of torsor isomorphisms iv,ih:Spinc(K)Spinc(Y)i_{v},i_{h}:{\mathrm{Spin}^{c}}(K)\to{\mathrm{Spin}^{c}}(Y).

We work with the hat-version of knot Floer homology with {\mathbb{Z}} coefficients, graded by sSpinc(K)s\in{\mathrm{Spin}^{c}}(K):

HFK^(K)=sHFK^(K,s).\widehat{HFK}(K)=\bigoplus_{s}\widehat{HFK}(K,s).

There exists a further pair of gradings

a,m:HFK^(K,s)a,m:\widehat{HFK}(K,s)\to{\mathbb{Z}}

on each summand, the Alexander and Maslov gradings. An element is homogeneous if it is homogeneous with respect to both gradings. The group HFK^(K)\widehat{HFK}(K) comes equipped with differentials d~v\widetilde{d}_{v}, d~h\widetilde{d}_{h} that preserve the Spinc(K){\mathrm{Spin}^{c}}(K)-grading, respectively lower mm and m2am-2a by one, and respectively raise and lower aa. They are invariants of KK, and their homology calculates HF^(Y,iv(s))\widehat{HF}(Y,i_{v}(s)) and HF^(Y,ih(s))\widehat{HF}(Y,i_{h}(s)), respectively. The manifold YY is an L-space if HF^(Y,t)\widehat{HF}(Y,t)\approx{\mathbb{Z}} for all tSpinc(Y)t\in{\mathrm{Spin}^{c}}(Y).

Definition 2.1.

For a knot KK in an L-space YY and sSpinc(K)s\in{\mathrm{Spin}^{c}}(K), the group HFK^(K,s)\widehat{HFK}(K,s) is a positive chain if it admits a homogeneous basis x1,,x2n+1x_{1},\dots,x_{2n+1} such that, for all kk,

d~v(x2k)=±x2k1,d~h(x2k)=±x2k+1,d~v(x2k1)=d~h(x2k1)=0.\widetilde{d}_{v}(x_{2k})=\pm x_{2k-1},\quad\widetilde{d}_{h}(x_{2k})=\pm x_{2k+1},\quad\widetilde{d}_{v}(x_{2k-1})=\widetilde{d}_{h}(x_{2k-1})=0.

The group HFK^(K)\widehat{HFK}(K) consists of positive chains if HFK^(K,s)\widehat{HFK}(K,s) is a positive chain for all ss.

For example, a positive chain with 2n+1=72n+1=7 generators takes the form shown here:

x2\textstyle{\langle x_{2}\rangle\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}d~v\scriptstyle{\widetilde{d}_{v}}d~h\scriptstyle{\widetilde{d}_{h}}x4\textstyle{\langle x_{4}\rangle\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}d~v\scriptstyle{\widetilde{d}_{v}}d~h\scriptstyle{\widetilde{d}_{h}}x6\textstyle{\langle x_{6}\rangle\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}d~v\scriptstyle{\widetilde{d}_{v}}d~h\scriptstyle{\widetilde{d}_{h}}x1\textstyle{\langle x_{1}\rangle}x3\textstyle{\langle x_{3}\rangle}x5\textstyle{\langle x_{5}\rangle}x7\textstyle{\langle x_{7}\rangle}

Each arrow represents a component of the differential and is an isomorphism between the groups it connects. Similarly, a negative chain is the dual complex to a positive chain with respect to the defining basis. Reversing the arrows above gives an example of a negative chain.

Note that the requirement that the positive chain basis elements are homogeneous does not appear in [RR15, Definition 3.1]. For example, we could alter the positive chain basis displayed above to an inhomogeneous one by replacing x2x_{2} by x2+x1x_{2}+x_{1}. However, homogeneity is an intended property of a positive chain basis in the literature. Moreover, an inhomogeneous positive chain basis gives rise to a homogeneous one by replacing each basis element by its homogeneous part of highest bigrading. Therefore, our definition is no more restrictive, and its precision is more convenient when we invoke it in the proofs of Lemmas 2.3 and 2.4.

Let λX\lambda\subset{\partial}X denote the rational longitude of KK, the unique slope that is rationally null-homologous in XX. Note that μλ\mu\neq\lambda, since YY is a rational homology sphere. Another slope αX\alpha\subset{\partial}X is positive or negative according to the sign of (μλ)(λα)(αμ)(\mu\cdot\lambda)(\lambda\cdot\alpha)(\alpha\cdot\mu), for any orientations on these curves. The knot KK is a positive or a negative L-space knot if it has an L-space surgery slope of that sign. The following theorem characterizes positive L-space knots in L-spaces in terms of their knot Floer homology. Ozsváth and Szabó originally proved it for the case of knots in S3S^{3} [OS05, Theorem 1.2]. Boileau, Boyer, Cebanu, and Walsh promoted a significant component of their result to knots in rational homology spheres [BBCW12]. Building on it, J. and S. Rasmussen established the definitive form of the result that we record here: see [RR15, Lemmas 3.2, 3.3, 3.5], including the proofs of these results.

Theorem 2.2.

A knot KK in an L-space YY is a positive L-space knot if and only if HFK^(K)\widehat{HFK}(K) consists of positive chains. ∎

Similarly, KK is a negative L-space knot if and only if HFK^(K)\widehat{HFK}(K) consists of negative chains. The reason amounts to the behavior of Dehn surgery and knot Floer homology under mirroring.

2.2. Calculating the invariants from a Heegaard diagram.

The invariants can be calculated from any doubly-pointed Heegaard diagram D=(Σ,α,β,z,w)D=(\Sigma,\alpha,\beta,z,w) of KK after making some additional analytic choices. Here, as usual, Σ\Sigma denotes a closed, oriented surface of some genus gg; α\alpha and β\beta are gg-tuples of homologically linearly independent, disjoint, simple closed curves in Σ\Sigma; and the two basepoints ww and zz lie in the complement of the α\alpha and β\beta curves on Σ\Sigma. The curve collections induce tori 𝕋α,𝕋β{\mathbb{T}}_{\alpha},{\mathbb{T}}_{\beta} in the gg-fold symmetric product Symg(Σ)\mathrm{Sym}^{g}(\Sigma). The underlying group of the Floer chain complex CFK^(D)\widehat{CFK}(D) is freely generated by 𝔗(D)=𝕋α𝕋β{\mathfrak{T}}(D)={\mathbb{T}}_{\alpha}\cap{\mathbb{T}}_{\beta}. The elements of 𝔗(D){\mathfrak{T}}(D) fall into equivalence classes in 1-1 correspondence with Spinc(K){\mathrm{Spin}^{c}}(K): two elements x,yx,y lie in the same equivalence class iff the set π2(x,y)\pi_{2}(x,y) of homotopy classes of Whitney disks from xx to yy is non-empty. Write 𝔗(D,s){\mathfrak{T}}(D,s) for the equivalence class corresponding to sSpinc(K)s\in{\mathrm{Spin}^{c}}(K) and CFK^(D,s)\widehat{CFK}(D,s) for the subgroup of CFK^(D)\widehat{CFK}(D) generated by the elements in 𝔗(D,s){\mathfrak{T}}(D,s). Each Whitney disk ϕπ2(x,y)\phi\in\pi_{2}(x,y) has a pair of multiplicities nz(ϕ)n_{z}(\phi), nw(ϕ)n_{w}(\phi) and a Maslov index μ(ϕ)\mu(\phi). The Alexander and Maslov gradings on CFK^(D,s)\widehat{CFK}(D,s) are characterized up to an overall shift by the relations

a(x)a(y)=nz(ϕ)nw(ϕ),m(x)m(y)=μ(ϕ)2nw(ϕ)a(x)-a(y)=n_{z}(\phi)-n_{w}(\phi),\quad m(x)-m(y)=\mu(\phi)-2n_{w}(\phi)

for all x,y𝔗(D,s)x,y\in{\mathfrak{T}}(D,s) and ϕπ2(x,y)\phi\in\pi_{2}(x,y). There exist endomorphisms d0,dv,dhd_{0},d_{v},d_{h} of CFK^(D,s)\widehat{CFK}(D,s) defined on generators x𝔗(D,s)x\in{\mathfrak{T}}(D,s) by the same general prescription:

d(x)=y,ϕ#^(ϕ)y.d(x)=\sum_{y,\phi}\#\widehat{\mathcal{M}}(\phi)\cdot y.

Here yy ranges over 𝔗(D,s){\mathfrak{T}}(D,s); ϕ\phi ranges over the elements of π2(x,y)\pi_{2}(x,y) with Maslov index μ(ϕ)=1\mu(\phi)=1 and a constraint on the multiplicities nw(ϕ)n_{w}(\phi), nz(ϕ)n_{z}(\phi); and #^(ϕ)\#\widehat{\mathcal{M}}(\phi) is the count of pseudo-holomorphic representatives of ϕ\phi. The specific constraints on the multiplicities are nw(ϕ)=nz(ϕ)=0n_{w}(\phi)=n_{z}(\phi)=0 for d=d0d=d_{0}; nw(ϕ)=0,nz(ϕ)>0n_{w}(\phi)=0,n_{z}(\phi)>0 for d=dvd=d_{v}; and nw(ϕ)>0,nz(ϕ)=0n_{w}(\phi)>0,n_{z}(\phi)=0 for d=dhd=d_{h}. The maps d0,d0+dv,d0+dhd_{0},d_{0}+d_{v},d_{0}+d_{h} are all differentials. The differential d0+dvd_{0}+d_{v} lowers mm by one and is filtered with respect to aa. The differential d0+dhd_{0}+d_{h} lowers m2am-2a by one and is filtered with respect to a-a. The differential d0d_{0} is the aa-filtration-preserving component of each. The groups HFK^(K,s)\widehat{HFK}(K,s), HF^(Y,iv(s))\widehat{HF}(Y,i_{v}(s)), and HF^(Y,ih(s))\widehat{HF}(Y,i_{h}(s)) are the homology groups of CFK^(D,s)\widehat{CFK}(D,s) with respect to d0d_{0}, d0+dvd_{0}+d_{v}, and d0+dhd_{0}+d_{h}, respectively, and the Alexander and Maslov gradings on CFK^(D,s)\widehat{CFK}(D,s) descend to the respective gradings on HFK^(K,s)\widehat{HFK}(K,s). The maps d0+dvd_{0}+d_{v} and d0+dhd_{0}+d_{h} induce the differentials d~v\widetilde{d}_{v} and d~h\widetilde{d}_{h} on HFK^(K,s)\widehat{HFK}(K,s), respectively.

The Alexander and Maslov gradings enable us to constrain the existence of pseudo-holomorphic disks for L-space knots.

Lemma 2.3.

Suppose that DD is a doubly-pointed Heegaard diagram for KK, d0d_{0} vanishes on CFK^(D,s)\widehat{CFK}(D,s), and HFK^(K,s)\widehat{HFK}(K,s) is a positive chain with basis x1,,x2n+1x_{1},\dots,x_{2n+1}. If there exist generators x,y𝔗(D,s)x,y\in{\mathfrak{T}}(D,s) and a disk ϕπ2(x,y)\phi\in\pi_{2}(x,y) with μ(ϕ)=1\mu(\phi)=1 and #(ϕ)0\#{\mathcal{M}}(\phi)\neq 0, then x=x2kx=x_{2k} and y=x2k±1y=x_{2k\pm 1} for some kk. Furthermore, nz(ϕ)=0n_{z}(\phi)=0 if j=2k+1j=2k+1 and nw(ϕ)=0n_{w}(\phi)=0 if j=2k1j=2k-1.

Proof.

Definition 2.1 and the paragraph preceding it show that the positive chain basis satisfies

a(x2k)a(x2k1)=bk,m(x2k)m(x2k1)=1a(x_{2k})-a(x_{2k-1})=b_{k},\quad m(x_{2k})-m(x_{2k-1})=1

and

a(x2k)a(x2k+1)=ck,m(x2k)m(x2k+1)=12ck,a(x_{2k})-a(x_{2k+1})=-c_{k},\quad m(x_{2k})-m(x_{2k+1})=1-2c_{k},

for some positive integers bk,ckb_{k},c_{k}, k=1,,nk=1,\dots,n. In particular, the Maslov and Alexander gradings of the xlx_{l} both decrease with the index ll. The generators x,y𝔗(D,s)x,y\in{\mathfrak{T}}(D,s) are homogeneous with respect to both gradings, as are the positive chain basis elements, so it follows that x=±xix=\pm x_{i} and y=±xjy=\pm x_{j} for some ii, jj, and choices of sign.

The assumption that #(ϕ)0\#{\mathcal{M}}(\phi)\neq 0 implies that nw(ϕ),nz(ϕ)0n_{w}(\phi),n_{z}(\phi)\geq 0, and at least one inequality is strict, since d0=0d_{0}=0. Thus,

(1) a(xi)a(xj)=nz(ϕ)nw(ϕ)andm(xi)m(xj)=12nw(ϕ)1.a(x_{i})-a(x_{j})=n_{z}(\phi)-n_{w}(\phi)\quad\textup{and}\quad m(x_{i})-m(x_{j})=1-2n_{w}(\phi)\leq 1.

In the case of equality m(xi)m(xj)=1m(x_{i})-m(x_{j})=1, then j=i1j=i-1, and either i=2ki=2k, which gives the desired conclusion, or else j=2kj=2k, which we must rule out. In this case, nw(ϕ)=0n_{w}(\phi)=0 and nz(ϕ)>0n_{z}(\phi)>0. Since YY is a rational homology sphere, it follows that ϕπ2(x,y)\phi\in\pi_{2}(x,y) is the unique disk with μ(ϕ)=1\mu(\phi)=1, so the coefficient on yy in d~v(x)\widetilde{d}_{v}(x) is #(ϕ)0\#{\mathcal{M}}(\phi)\neq 0. However, this implies that d~v(x2k+1)0\widetilde{d}_{v}(x_{2k+1})\neq 0, which violates the form of the positive chain.

Otherwise, m(xi)m(xj)1m(x_{i})-m(x_{j})\leq-1, so i<ji<j. We have

(2) a(xi)a(xj)=l=ij1a(xl)a(xl+1),m(xi)m(xj)=l=ij1m(xl)m(xl+1).a(x_{i})-a(x_{j})=\sum_{l=i}^{j-1}a(x_{l})-a(x_{l+1}),\quad m(x_{i})-m(x_{j})=\sum_{l=i}^{j-1}m(x_{l})-m(x_{l+1}).

Each term in the second sum is odd, and their total sum is odd, so it contains an odd number of terms. The terms of the first sum alternately take the form bk-b_{k} and ck-c_{k}, while the terms of the second sum alternately take the form 1-1 and 12ck1-2c_{k}. Let bb denote the sum of the values bkb_{k} that appear and cc the sum of the ckc_{k} that appear. All of values bkb_{k} are positive, so b0b\geq 0, and b=0b=0 only if ii is even and j=i+1j=i+1, and b=1b=1 only if ii is odd and j=i+1j=i+1. The first sum in (2) equals bc-b-c, while the second sum equals 12c1-2c or 12c-1-2c, according to whether ii is even or odd. Comparing with the second sum in (1) gives nw(ϕ)=cn_{w}(\phi)=c or c+1c+1, according to whether ii is even or odd. Comparing with the first sum in (1) then gives nz(ϕ)=bn_{z}(\phi)=-b or b+1-b+1, according to whether ii is even or odd. If ii is even, then 0nz(ϕ)=b0\leq n_{z}(\phi)=-b gives nz(ϕ)=0n_{z}(\phi)=0 and j=i+1j=i+1, which gives the desired conclusion. If ii is odd, then 0nz(ϕ)=b+10\leq n_{z}(\phi)=-b+1 again gives nz(ϕ)=0n_{z}(\phi)=0 and j=i+1j=i+1. However, in this case it follows as before that yy appears with coefficient #(ϕ)0\#{\mathcal{M}}(\phi)\neq 0 in d~h(x)\widetilde{d}_{h}(x), which once again violates the form of the positive chain. ∎

2.3. (1,1) knots.

Now assume that DD is a (1,1)(1,1)-diagram, so Σ\Sigma has genus one. In this case, the differentials on CFK^(D)\widehat{CFK}(D) admit an explicit description that requires no analytic input, owing to the Riemann mapping theorem and the correspondence between holomorphic disks in the Riemann surface Σ=Sym1(Σ)\Sigma=\mathrm{Sym}^{1}(\Sigma) and its universal cover {\mathbb{C}}. Specifically, the conditions that ϕπ2(x,y)\phi\in\pi_{2}(x,y) and μ(ϕ)=1\mu(\phi)=1 imply that #^(ϕ)=±1\#\widehat{\mathcal{M}}(\phi)=\pm 1 for any choice of analytic data. Furthermore, these conditions are met if and only if the image of ϕ\phi lifts under the universal covering map π:2Σ\pi:{\mathbb{R}}^{2}\to\Sigma to a bigon cobounded by lifts of α\alpha and β\beta. See [GMM05] and [OS04, pp.89-96] for more details.

Refer to caption

zzww

Figure 2. Standard form for a reduced (1,1)(1,1) diagram, taken from [Ras05, Figure 2]. The left and right sides of the square are identified in the standard way and the top and bottom sides by a twist.

Assuming now that DD is reduced, we have d0=0d_{0}=0 and HFK^(K,s)CFK^(D,s)\widehat{HFK}(K,s)\approx\widehat{CFK}(D,s). We proceed to analyze the differentials d~h\widetilde{d}_{h} and d~v\widetilde{d}_{v}. Without loss of generality, we henceforth fix Σ=2/2\Sigma={\mathbb{R}}^{2}/{\mathbb{Z}}^{2}, z=π(2)z=\pi({\mathbb{Z}}^{2}), a horizontal line α~22{\widetilde{\alpha}}\subset{\mathbb{R}}^{2}\smallsetminus{\mathbb{Z}}^{2}, and α=π(α~)\alpha=\pi({\widetilde{\alpha}}). After a further homeomorphism, we may assume that DD takes the form shown in Figure 2. Observe that the embedded bigons in DD are the obvious ones cobounded by the α\alpha with the “rainbow” arcs of β\beta above ww and below zz. Coherence is the condition that when the β\beta curve is oriented, all of the rainbow arcs around a fixed basepoint orient the same way. This makes it easy to check coherence from a diagram in standard form.

Let H±H^{\pm} denote the upper and lower half-planes bounded by α~{\widetilde{\alpha}}. Choose a lift to α~{\widetilde{\alpha}} of any point in 𝔗(D,s){\mathfrak{T}}(D,s). There exists a unique lift β~s2{\widetilde{\beta}}_{s}\subset{\mathbb{R}}^{2} that passes through it. The points of α~β~s{\widetilde{\alpha}}\cap{\widetilde{\beta}}_{s} are in 1-1 correspondence with 𝔗(D,s){\mathfrak{T}}(D,s) under π\pi, and there are an odd number 2n+12n+1 of them, since α~β~s=χ(CFK^(D,s))=1{\widetilde{\alpha}}\cdot{\widetilde{\beta}}_{s}=\chi(\widehat{CFK}(D,s))=1 with appropriate orientations on the curves. The curve β~s{\widetilde{\beta}}_{s} meets each half-plane in one closed ray and nn compact arcs. These compact arcs cobound positive bigons Dk+H+D_{k}^{+}\subset H^{+} and negative bigons DkHD_{k}^{-}\subset H^{-} with α~{\widetilde{\alpha}} for k=1,,nk=1,\dots,n. A positive bigon attains a local maximum, and its image under π\pi is the top of one of the rainbow arcs above ww. Consequently, it contains a lift of the bigon in DD cobounded by that rainbow arc with α\alpha. Thus, nw(Dk+)>0n_{w}(D_{k}^{+})>0, and similarly nz(Dk)>0n_{z}(D_{k}^{-})>0, for all kk. Lastly, the positive bigons go from their left-most corner to their right-most corner, and vice versa for the negative bigons.

Lemma 2.4.

If DD is a reduced (1,1)(1,1) diagram of KK and HFK^(K,s)\widehat{HFK}(K,s) is a positive chain, then

  1. (1)

    nz(Dk+)=0n_{z}(D_{k}^{+})=0 and nw(Dk)=0n_{w}(D_{k}^{-})=0 for all kk;

  2. (2)

    the positive bigons are exactly the ones that contribute to d~v\widetilde{d}_{v}, the negative bigons are exactly the ones that contribute to d~h\widetilde{d}_{h}, and there are no other bigons; and

  3. (3)

    if α\alpha and β\beta are oriented so that αβ>0\alpha\cdot\beta>0, then α~{\widetilde{\alpha}} and β~s{\widetilde{\beta}}_{s} induce coherent orientations on the boundaries of all of the bigons they cobound.

Proof.
(1) The conditions of Lemma 2.3 are met by each positive and negative bigon and its corners, since DD is a reduced (1,1)(1,1) diagram and each positive and negative bigon is an embedded bigon in 2{\mathbb{R}}^{2}. The conclusion now follows from the last conclusion of Lemma 2.3 and the remark about multiplicities just before this Lemma. (2) The positive chain basis elements are homogeneous and in different bigradings, while generators are homogeneous. It follows that the positive chain basis is comprised of generators (up to sign). Suppose that there exists an embedded bigon with nw=0n_{w}=0 that goes from a lift of a generator xx to a lift of a generator yy in α~β~s{\widetilde{\alpha}}\cap{\widetilde{\beta}}_{s}. Then it is the unique such bigon, and the coefficient of yy in d~v(x)\widetilde{d}_{v}(x) is non-zero. Moreover, d~v(x)=±y\widetilde{d}_{v}(x)=\pm y, because xx and yy are (signed) positive chain basis elements. By part (1), each of the nn positive bigons contributes to d~v\widetilde{d}_{v} and connects a different pair of generators. Since rkHFK^(K,s)=2n+1{\mathrm{rk}}\,\widehat{HFK}(K,s)=2n+1, positive bigons are precisely those that contribute to d~v\widetilde{d}_{v}. The same remarks apply to the negative bigons and d~h\widetilde{d}_{h}. Lemma 2.3 shows that there are no other bigons. (3) By part (2) and the remark just before the Lemma, it follows that the points of intersection between α~{\widetilde{\alpha}} and β~s{\widetilde{\beta}}_{s} occur in the same order along these curves, up to reversal. Suppose that αβ>0\alpha\cdot\beta>0, so α~β~s=+1{\widetilde{\alpha}}\cdot{\widetilde{\beta}}_{s}=+1. Without loss of generality, α~{\widetilde{\alpha}} orients from left to right. It suffices to check coherence on the boundary of the bigon with a corner at the leftmost point of intersection xα~β~sx\in{\widetilde{\alpha}}\cap{\widetilde{\beta}}_{s}. Note that xx is a positive point of intersection, as the signs of the intersections alternate along α~{\widetilde{\alpha}} and sum to +1+1. If there is no such bigon, then the conclusion is automatic (and rkHFK^(K,s)=1\mathrm{rk}\,\widehat{HFK}(K,s)=1 in this case). If there is a bigon, label its other corner yy. If it is a positive bigon, then d~h(x)=y\widetilde{d}_{h}(x)=y, while d~v(x)=0\widetilde{d}_{v}(x)=0, in violation of the form of HFK^(K,s)\widehat{HFK}(K,s). Therefore, it is a negative bigon, and its boundary is coherently oriented by α~{\widetilde{\alpha}} and β~s{\widetilde{\beta}}_{s}.

Drawing on the proof of Lemma 2.4, we make a definition and prove a converse.

Definition 2.5.

A curve β~2{\widetilde{\beta}}\subset{\mathbb{R}}^{2} is graphic if its intersection points with α~\widetilde{\alpha} occur in the same or opposite orders along α~\widetilde{\alpha} and β~\widetilde{\beta}. It is positive if they occur in opposite orders and negative if they occur in the same order.

The bottom right picture in Figure 3 displays a positive graphic curve. The reason for the terminology is that a curve β~2{\widetilde{\beta}}\subset{\mathbb{R}}^{2} is graphic iff there exists a homeomorphism of 2{\mathbb{R}}^{2} taking (α~,β~)({\widetilde{\alpha}},{\widetilde{\beta}}) to the pair consisting of the xx-axis and the graph of an odd degree polynomial with all roots real and distinct. Its sign, positive or negative, is minus the sign of the leading coefficient of the polynomial.

Proposition 2.6.

If DD is a reduced (1,1)(1,1) diagram of KK, then HFK^(K,s)\widehat{HFK}(K,s) is a positive or a negative chain if and only if β~s{\widetilde{\beta}}_{s} is positive or negative graphic, respectively.

Proof.

If HFK^(K,s)\widehat{HFK}(K,s) is a positive chain, then Lemma 2.4 parts (2) and (3) show that β~s{\widetilde{\beta}}_{s} is positive graphic. Conversely, suppose that β~s{\widetilde{\beta}}_{s} is positive graphic. Label the points of intersection in α~β~s{\widetilde{\alpha}}\cap{\widetilde{\beta}}_{s} by x1,,x2n+1x_{1},\dots,x_{2n+1} in the order they occur along α~{\widetilde{\alpha}}. The only bigons cobounded by α~{\widetilde{\alpha}} and β~s{\widetilde{\beta}}_{s} are the positive and negative bigons. This latter fact can be verified using the equivalent definition of a graphic curve mentioned after Definition 2.5. Therefore,

d~v(x2k)=δkx2k1,d~h(x2k)=ϵkx2k+1,d~v(x2k1)=d~h(x2k1)=0,\widetilde{d}_{v}(x_{2k})=\delta_{k}\cdot x_{2k-1},\quad\widetilde{d}_{h}(x_{2k})=\epsilon_{k}\cdot x_{2k+1},\quad\widetilde{d}_{v}(x_{2k-1})=\widetilde{d}_{h}(x_{2k-1})=0,

for all kk and some δk,ϵk{1,0,+1}\delta_{k},\epsilon_{k}\in\{-1,0,+1\}. A value δk\delta_{k} or ϵk\epsilon_{k} is 0 iff the corresponding bigon contains both zz and ww basepoints. Since

H(HFK^(K,s),d~v)HF^(Y,iv(s))andH(HFK^(K,s),d~h)HF^(Y,ih(s)),H_{*}(\widehat{HFK}(K,s),\widetilde{d}_{v})\approx\widehat{HF}(Y,i_{v}(s))\approx{\mathbb{Z}}\quad\textup{and}\quad H_{*}(\widehat{HFK}(K,s),\widetilde{d}_{h})\approx\widehat{HF}(Y,i_{h}(s))\approx{\mathbb{Z}},

it follows that δk,ϵk0\delta_{k},\epsilon_{k}\neq 0 for all kk, and HFK^(K,s)\widehat{HFK}(K,s) is a positive chain. The corresponding statements for a negative chain and negative coherent diagram follow as well. ∎

Proof of Theorem 1.2.

Let DD denote a reduced (1,1)(1,1)-diagram of KK.

Suppose first that KK is a positive L-space knot. Orient α\alpha and β\beta so that αβ>0\alpha\cdot\beta>0, and suppose that BB is an embedded bigon in DD. We must show that α\alpha and β\beta coherently orient B{\partial}B. Suppose that the corners of BB belong to 𝔗(s){\mathfrak{T}}(s), and let B~\widetilde{B} denote the lift of BB to 2{\mathbb{R}}^{2} with corners in α~β~s{\widetilde{\alpha}}\cap{\widetilde{\beta}}_{s}. We have α~β~s=+1{\widetilde{\alpha}}\cdot{\widetilde{\beta}}_{s}=+1. Since KK is a positive L-space knot, Theorem 2.2 implies that HFK^(K,s)\widehat{HFK}(K,s) is a positive chain, and by Lemma 2.4(3), the orientations on α~{\widetilde{\alpha}} and β~s{\widetilde{\beta}}_{s} coherently orient the boundaries of all of the bigons they cobound. In particular, they coherently orient B~{\partial}\widetilde{B}, so α\alpha and β\beta coherently orient B{\partial}B. Therefore, DD is positive coherent.

Conversely, suppose that DD is positive coherent. Orient α\alpha and β\beta so that αβ>0\alpha\cdot\beta>0 and α~{\widetilde{\alpha}} orients from left to right. Fix sSpinc(K)s\in{\mathrm{Spin}^{c}}(K) and select any xα~β~sx\in{\widetilde{\alpha}}\cap{\widetilde{\beta}}_{s}. It is the endpoint of a closed ray of β~s{\widetilde{\beta}}_{s} oriented out of it. If this ray meets α~{\widetilde{\alpha}} in another point, then let yy denote the first such point. The arc of β~s{\widetilde{\beta}}_{s} from xx to yy cobounds a bigon B~\widetilde{B} with α~{\widetilde{\alpha}}. If yy lies to the left of xx, then B~{\partial}\widetilde{B} is incoherently oriented by α~{\widetilde{\alpha}} and β~s{\widetilde{\beta}}_{s}. The arc of β~s{\widetilde{\beta}}_{s} has an extremal (highest or lowest) point which lifts the extremal point of a rainbow arc. Projecting B~\widetilde{B} to DD by π\pi, it follows that this rainbow arc cobounds an embedded bigon with α\alpha that is incoherently oriented by α\alpha and β\beta, a contradiction. Therefore, yy lies to the right of xx. It follows by induction that the points of α~β~s{\widetilde{\alpha}}\cap{\widetilde{\beta}}_{s} occur in the opposite orders along α~{\widetilde{\alpha}} and β~s{\widetilde{\beta}}_{s} with respect to these curves’ orientations. It follows that β~s{\widetilde{\beta}}_{s} is graphic, and since αβ>0\alpha\cdot\beta>0, it is positive graphic. By Proposition 2.6, HFK^(K,s)\widehat{HFK}(K,s) is a positive chain. Therefore, HFK^(K)\widehat{HFK}(K) consists of positive chains, and KK is a positive L-space knot by Theorem 2.2.

The corresponding statements for negative coherent diagrams and negative L-space knots follow by a similar argument. ∎

3. 1-bridge braids.

This section consists of two parts. The first is devoted to the proof of Theorem 1.4 and its sign-refined version, Theorem 3.2. The second is a vignette on how Theorem 3.2 pertains to solid torus fillings on 1-bridge braid exteriors. Specifically, we give a novel argument in Proposition 3.4 to characterize the Berge manifold amongst 1-bridge braid exteriors.

3.1. 1-bridge braids are L-space knots

We prepare by describing a reduced (1,1)(1,1)-diagram of a 1-bridge braid in a rational homology sphere.

Let γδS1×D2\gamma\cup\delta\subset S^{1}\times D^{2} denote a 1-bridge braid. Identify (S1×D2){\partial}(S^{1}\times D^{2}) with the flat torus Σ\Sigma in such a way that meridians θ×D2\theta\times{\partial}D^{2} lift to horizontal lines and longitudes S1×xS^{1}\times x lift to vertical lines under π:2Σ\pi:{\mathbb{R}}^{2}\to\Sigma. Isotope γ\gamma rel endpoints into a geodesic on Σ\Sigma, so that π1(γ)\pi^{-1}(\gamma) consists of parallel line segments in 2{\mathbb{R}}^{2} of some common slope s(γ)P1()s(\gamma)\in P^{1}({\mathbb{R}}). Orient γ\gamma and write γ=zw{\partial}\gamma=z-w so that in each lift of γ\gamma to 2{\mathbb{R}}^{2}, the lift of zz lies below that of ww.

Form a genus one rational homology sphere YY by gluing a solid torus VV to S1×D2S^{1}\times D^{2} along their boundaries, and let KK denote the image of γδ\gamma\cup\delta in YY. Let α\alpha denote a meridian of S1×D2S^{1}\times D^{2} and let β0\beta_{0} denote the curve to which the meridian of VV attaches, which we take to be a geodesic. In meridian-longitude coordinates, β0\beta_{0} has some slope p/q0/1p/q\neq 0/1, and YY is homeomorphic to L(p,q)L(p,q) if p1p\neq 1 and S3S^{3} otherwise. Assume that α\alpha and β0\beta_{0} are disjoint from γ{\partial}\gamma. Isotope β0\beta_{0} by a finger-move along γ\gamma into a curve β1\beta_{1} disjoint from γ\gamma. Observe that (Σ,α,β1,z,w)(\Sigma,\alpha,\beta_{1},z,w) is a doubly-pointed Heegaard diagram for KYK\subset Y. Put it into reduced form by further isotoping β1\beta_{1} so as to eliminate all bigons that do not contain basepoints, one by one, resulting in a curve β2\beta_{2}. Let D=(Σ,α,β2,z,w)D=(\Sigma,\alpha,\beta_{2},z,w) denote the resulting reduced diagram of KYK\subset Y. Figure 3 exhibits this procedure for the inclusion of the 1-bridge braid K(7,4,2)K(7,4,2) into S3S^{3}, the pretzel knot P(2,3,7)P(-2,3,7). The notation derives from the braid presentation of 1-bridge braids; see [Ber91, Gab90, Wu04]. The 11–bridge braid K(ω,b,m)K(\omega,b,m) denotes the closure of the braid word (σbσb1σ1)(σω1σω2σ1)m(\sigma_{b}\sigma_{b-1}\cdots\sigma_{1})(\sigma_{\omega-1}\sigma_{\omega-2}\cdots\sigma_{1})^{m} in S1×D2S^{1}\times D^{2}, where the σi\sigma_{i} are the generators of the braid group BwB_{w}. Note that K(ω,b,m)K(\omega,b,m) and K(ω,b,m+ω)K(\omega,b,m+\omega) differ by a full twist, so there is a diffeomorphism of the solid torus that carries one to the other. Therefore, we may assume that 0m<w0\leq m<w.

Refer to caption

zzwwα\alphaγ\gammaβ0\beta_{0}β1\beta_{1}β2\beta_{2}

Figure 3. Constructing a positive coherent diagram of P(2,3,7)P(-2,3,7), the inclusion of K(7,4,2)K(7,4,2) into S3S^{3}. Moving from left to right illustrates the procedure described in the proof of Theorem 1.2. At top are diagrams on Σ\Sigma and at bottom their lifts to 2{\mathbb{R}}^{2}. The bigons at bottom right are shaded for emphasis.

A pair of distinct slopes s1,s2P1()s_{1},s_{2}\in P^{1}({\mathbb{Q}}) determines an interval [s1,s2]P1()[s_{1},s_{2}]\subset P^{1}({\mathbb{Q}}) oriented from s1s_{1} to s2s_{2} in the counterclockwise sense; thus, [s1,s2][s2,s1]=P1()[s_{1},s_{2}]\cup[s_{2},s_{1}]=P^{1}({\mathbb{Q}}) and [s1,s2][s2,s1]={s1,s2}[s_{1},s_{2}]\cap[s_{2},s_{1}]=\{s_{1},s_{2}\}.

Proposition 3.1.

The diagram DD is coherent. Furthermore, it is positive if s(γ)[0,p/q]s(\gamma)\in[0,p/q] and negative if s(γ)[p/q,0]s(\gamma)\in[p/q,0].

Note that Proposition 3.1 does not characterize the sign of the coherence in terms of s(γ)s(\gamma). Theorem 3.2 does so in terms of the slope interval, and its proof relies on Proposition 3.1.

Proof.

Choose lifts of α\alpha and β0\beta_{0} to 2{\mathbb{R}}^{2}. They meet in a single point of intersection x1x_{1}. Consider the lifts of γ\gamma that meet both α~{\widetilde{\alpha}} and β~0{\widetilde{\beta}}_{0} and in that order relative to their lifted orientations. Observe that these lifts meet the same component of α~x1{\widetilde{\alpha}}-x_{1}. Label the points of intersection between these lifts and α~{\widetilde{\alpha}} by y2,,yny_{2},\dots,y_{n} in the order that they appear along this component, moving away from x1x_{1}. The isotopy from β0\beta_{0} to β1\beta_{1} lifts to one from β~0{\widetilde{\beta}}_{0} to β~1{\widetilde{\beta}}_{1}. Nearby each yiy_{i} is a pair of intersection points x2i,x2i+1x_{2i},x_{2i+1} between α~{\widetilde{\alpha}} and β~1{\widetilde{\beta}}_{1}. The points x1,,x2n+1x_{1},\dots,x_{2n+1} occur in that order along both α~{\widetilde{\alpha}} and β~1{\widetilde{\beta}}_{1}. Thus, β~1{\widetilde{\beta}}_{1} is graphic. The isotopy from β1\beta_{1} to β2\beta_{2} lifts to one from β~1{\widetilde{\beta}}_{1} to β~2{\widetilde{\beta}}_{2}. Each elimination of a bigon eliminates a pair of intersection points that are consecutive along both α~{\widetilde{\alpha}} and β~1{\widetilde{\beta}}_{1}. Therefore, the intersection points between α~{\widetilde{\alpha}} and β~2{\widetilde{\beta}}_{2} are a subset of those between α~{\widetilde{\alpha}} and β~1{\widetilde{\beta}}_{1}, and they occur in the same order along α~{\widetilde{\alpha}} and β~2{\widetilde{\beta}}_{2}. It follows that β~2{\widetilde{\beta}}_{2} is graphic, as well. Furthermore, β~2{\widetilde{\beta}}_{2} is positive graphic if the xx-coordinates of x1,,x2n+1x_{1},\dots,x_{2n+1} decrease with index and negative graphic if they increase with index. This is the case if s(γ)s(\gamma) belongs to [0,p/q][0,p/q] or in [p/q,0][p/q,0], respectively. In particular, it is independent of the choice of lift of β2\beta_{2}. Thus, all lifts of β2\beta_{2} are ε\varepsilon-graphic for the same choice of sign ε\varepsilon. It follows that DD is coherent, and the sign-refined statement follows as well. ∎

Proof of Theorem 1.4.

Immediate from Proposition 3.1 and Theorem 1.2. ∎

Refer to caption
Figure 4. At left, a braid with closure the 1-bridge braid K(7,4,2)S1×D2K(7,4,2)\subset S^{1}\times D^{2}. The bold points suggest its decomposition into the form γδ\gamma\cup\delta. At right, a sweep-out of arcs in 2{\mathbb{R}}^{2} indicating that I(γ)=[5/2,3]I(\gamma)=[5/2,3]. The bold points arise in the proof of Proposition 3.4.

We proceed to sharpen the statement of Theorem 1.4. To do so, we introduce the notion of a strict 1-bridge braid and its basic invariants: the winding number and slope interval. Choose the lift of γ\gamma with one endpoint at (0,0)(0,0). Its other endpoint takes the form (t,ω)×(t,\omega)\in{\mathbb{R}}\times{\mathbb{Z}}. We have ω>0\omega>0 by our convention on the basepoints, and tt is not a proper divisor of ω\omega. Moreover, ω\omega is an invariant of the isotopy type of KK, since [K]=ω[S1×x]H1(S1×D2;)[K]=\omega\cdot[S^{1}\times x]\in H_{1}(S^{1}\times D^{2};{\mathbb{Z}}). This is the winding number ω(K)\omega(K).

Consider the sweep-out of line segments with one endpoint at (0,0)(0,0) and the other endpoint varying along line y=ωy=\omega. There exists a maximal slope interval I(γ)P1()I(\gamma)\subset P^{1}({\mathbb{Q}}) containing s(γ)s(\gamma) and so that the sweep-out of line segments through slopes in I(γ)I(\gamma) contains no lattice point in its interior. If ω=1\omega=1, then I(γ)=P1(){0}I(\gamma)=P^{1}({\mathbb{Q}})\smallsetminus\{0\}, and otherwise I(γ)=[s(γ),s+(γ)]I(\gamma)=[s_{-}(\gamma),s_{+}(\gamma)] with s(γ)s+(γ)s_{-}(\gamma)\leq s_{+}(\gamma). The sweep-out descends to an isotopy through 1-bridge braids with slopes in the interior of I(γ)I(\gamma). If a line segment of slope s±(γ)s_{\pm}(\gamma) has endpoint (q,ω)2(q,\omega)\in{\mathbb{Z}}^{2}, then write (q,ω)=(dq,dω)(q,\omega)=(dq^{\prime},d\omega^{\prime}), where d=gcd(q,ω)d=\gcd(q,\omega). Let μ\mu denote the meridian of the torus knot T(q,ω)T(q^{\prime},\omega^{\prime}) and λ\lambda the surface framing, oriented so that μλ=+1\mu\cdot\lambda=+1. If d=1d=1, then KK is isotopic to the torus knot T(q,ω)T(q,\omega), and if d>1d>1, then KK is isotopic to the (dλ±μ)(d\lambda\pm\mu)-cable of T(q,ω)T(q^{\prime},\omega^{\prime}), where the sign is positive or negative if the slope of the line segment is s+(γ)s_{+}(\gamma) or s(γ)s_{-}(\gamma), respectively. We call such a cable an exceptional cable of a torus knot. Otherwise, if no line segment has endpoint (q,ω)2(q,\omega)\in{\mathbb{Z}}^{2}, then we call KK a strict 1-bridge braid (and justify the terminology in Corollary 3.3). In this case, there exists a unique mm\in{\mathbb{Z}} so that m<t<m+1m<t<m+1, and s(γ)s_{-}(\gamma) and s+(γ)s_{+}(\gamma) are consecutive terms in the Farey sequence of fractions from ω/(m+1)\omega/(m+1) to ω/m\omega/m whose denominators are bounded by |m||m| when expressed in lowest terms.

For the following result, assume p>q0p>q\geq 0 are coprime integers, and let L(1,0)L(1,0) denote S3S^{3}. A simple knot in L(p,q)L(p,q) is a (1,1)(1,1) knot whose defining arcs are contained in meridian disks in the respective Heegaard solid tori, where the disks’ boundaries meet in pp transverse points of intersection. We permit the degenerate case that the the cable arc γ\gamma is a simple closed curve and the bridge δ\delta is a point, in which case the simple knot is an unknot. Equivalently, a simple knot is a knot admitting a (1,1)(1,1) diagram in which all points of intersection between α\alpha and β\beta have the same sign. Note that every simple knot is a 1-bridge braid: to see this, push one of the defining arcs onto the Heegaard torus.

Theorem 3.2.

The inclusion of a strict 1-bridge braid γδS1×D2\gamma\cup\delta\subset S^{1}\times D^{2} into L(p,q)L(p,q) is

  1. (1)

    a positive L-space knot iff s(γ)[0,p/q]s_{-}(\gamma)\in[0,p/q];

  2. (2)

    a negative L-space knot iff s+(γ)[p/q,0]s_{+}(\gamma)\in[p/q,0]; and

  3. (3)

    a simple knot iff p/qI(γ)p/q\in I(\gamma).

For example, the inclusion of K(7,4,2)K(7,4,2) into L(p,q)L(p,q) is a simple knot iff p/q[5/2,3]p/q\in[5/2,3].

Proof of Theorem 3.2.

The reverse directions of (1) and (2) follow from Proposition 3.1 and Theorem 1.2.

For the forward directions, suppose first that s+(γ)(0,p/q)s_{+}(\gamma)\in(0,p/q). Write s+(γ)=r/ss_{+}(\gamma)=r/s in lowest terms, s>0s>0. As before, let γ~{\widetilde{\gamma}} denote the lift of γ\gamma with one endpoint at (0,0)(0,0) and the other at (t,ω)×(t,\omega)\in{\mathbb{R}}\times{\mathbb{Z}}. Note that ω>|r|\omega>|r|. Let α~22{\widetilde{\alpha}}\subset{\mathbb{R}}^{2}\smallsetminus{\mathbb{Z}}^{2} denote a horizontal line that separates (s,r)(s,r) from (t,ω)(t,\omega), and let β~022{\widetilde{\beta}}_{0}\subset{\mathbb{R}}^{2}\smallsetminus{\mathbb{Z}}^{2} denote a line of slope p/qp/q that separates (s,r)(s,r) from (0,0)(0,0). Then α~{\widetilde{\alpha}}, β~0{\widetilde{\beta}}_{0}, and γ~{\widetilde{\gamma}} intersect in pairs, and since r/s(0,p/q)r/s\in(0,p/q), they cobound a triangle containing (s,r)(s,r) in its interior. See Figure 5(a).

Follow the procedure for producing a coherent diagram DD for KYK\subset Y using the curves α=π(α~),β0=π(β~0)Σ\alpha=\pi({\widetilde{\alpha}}),\beta_{0}=\pi({\widetilde{\beta}}_{0})\subset\Sigma. The isotopy from β~0{\widetilde{\beta}}_{0} to β~1{\widetilde{\beta}}_{1} captures (s,r)(s,r) in a negative bigon and (t,ω)(t,\omega) in a positive bigon in (2,α~β~1)({\mathbb{R}}^{2},{\widetilde{\alpha}}\cup{\widetilde{\beta}}_{1}). See Figure 5(b). These points remain in bigons of the respective types following the isotopy from β~1{\widetilde{\beta}}_{1} to β~2{\widetilde{\beta}}_{2}. It follows that HFK^(K,s)\widehat{HFK}(K,s) is a positive chain of rank greater than one for the spinc{\mathrm{spin^{c}}} structure ss corresponding to the pair of lifts α~,β~2{\widetilde{\alpha}},{\widetilde{\beta}}_{2}. Thus, KK is not a negative L-space knot, which gives the forward direction of (2). The forward direction of (1) follows the same line of reasoning.

Since a simple knot is both a positive and a negative L-space knot, the forward direction of (3) follows. Finally, taking a 1-bridge presentation of KK in which γ\gamma has slope p/qp/q results in a diagram DD of a simple knot, and the reverse direction of (3) follows. ∎

The following result recovers the isotopy classification of 1-bridge braids from Theorem 3.2. Compare [Gab90, Proposition 2.3], which does so in terms of braid parameters.

Corollary 3.3.

If K=γδS1×D2K=\gamma\cup\delta\subset S^{1}\times D^{2} is a strict 1-bridge braid, then the slope interval I(γ)I(\gamma) is an invariant of the isotopy type of KK. Its isotopy type is determined by its slope interval and winding number, and KK is not isotopic to a torus knot or an exceptional cable thereof.

Proof.

The slope interval is characterized by Theorem 3.2 as the set of surgery slopes for which KK includes as a simple knot, so it is an isotopy invariant. It and the winding number together determine a sweep-out of arcs which in turn specify the isotopy type of KK. If KK is a strict 1-bridge braid, then it does not include as a simple knot in any lens space of order |ω(K)||\omega(K)| or less. However, every torus knot T(q,ω)S1×D2T(q,\omega)\subset S^{1}\times D^{2} and exceptional cable thereof includes as an unknot in the lens space obtained by (ω/q)(\omega/q)-filling on the outer torus. ∎

Refer to caption

(a)(b)

Figure 5. Capturing a lattice point.

3.2. Solid torus fillings.

Gabai proved that a knot in the solid torus with a non-trivial solid torus surgery is a 1-bridge braid in [Gab90], and Berge classified them in [Ber91]. Berge found that, up to mirroring, K(7,4,2)K(7,4,2) is the unique strict 1-bridge braid that admits more than one such surgery. Its exterior is known as the Berge manifold. Menasco and Zhang studied 1-bridge braids whose exteriors admit a solid torus filling on the outer torus in [MZ01], and Wu classified them in [Wu04].

We indicate a line of approach towards Wu’s result using Theorem 3.2. Suppose that KK is a 1-bridge braid in S1×D2S^{1}\times D^{2} and (p/q)(p/q)-filling on its outer torus is a solid torus; equivalently, the inclusion of KK into L(p,q)L(p,q) is a knot with solid torus exterior. A knot in L(p,q)L(p,q) has a solid torus exterior if and only if it is simple and homologous to the oriented core of a Heegaard solid torus. Since [K][K] equals ω\omega times a generator of H1(S1×D2;)H_{1}(S^{1}\times D^{2};{\mathbb{Z}}), the uniqueness of genus one Heegaard splittings of L(p,q)L(p,q) implies that either

(3) (a)ω±1(modp)or(b)ωq±1(modp);(a)\quad\omega\equiv\pm 1\pmod{p}\quad\mathrm{or}\quad(b)\quad\omega\cdot q\equiv\pm 1\pmod{p};

the 2×22\times 2 possibilities correspond to the two Heegaard solid tori and the two orientations. Therefore, Theorem 3.2 reduces the problem Wu solved to one about lattice points. However, it appears to require considerable effort to extract Wu’s result from it. Nevertheless, we can quickly derive the following characterization of the Berge manifold:

Proposition 3.4.

Up to mirroring, the knot K(7,4,2)K(7,4,2) is the unique strict 1-bridge braid whose exterior admits three distinct solid torus fillings on the outer torus.

Wu points out that this result follows from the work of Berge and Gabai, which is an amusing exercise [Wu04, §4(1)]. By contrast, we deduce Proposition 3.4 from Theorem 3.2 and the uniqueness of genus one Heegaard splittings of lens spaces.

Given linearly independent v,w2v,w\in{\mathbb{Z}}^{2}, let Δ(v,w)\Delta(v,w) denote the triangle with vertices 0, vv, ww. It is empty if it contains no lattice points besides its vertices, i.e. {v,w}\{v,w\} is a basis of 2{\mathbb{Z}}^{2}.

Proof.

Suppose that KS1×D2K\subset S^{1}\times D^{2} is a strict 1-bridge braid with winding number ω\omega and slope interval [b/d,a/c](ω/(m+1),ω/m)[b/d,a/c]\subset(\omega/(m+1),\omega/m), mm\in{\mathbb{Z}}. Let XX denote the exterior of KK. Suppose that (p/q)(p/q)-Dehn filling on the outer torus of XX is a solid torus. Thus, p/q[b/d,a/c]p/q\in[b/d,a/c], and one of the congruences in (3) holds.

If (3)(b) holds, then there must exist ss\in{\mathbb{Z}} so that Δ((s,ω),(p,q))\Delta((s,\omega),(p,q)) is empty. If p/q(b/d,a/c)p/q\in(b/d,a/c), then this triangle contains (c,a)(c,a) if sms\leq m and (d,b)(d,b) if sm+1s\geq m+1. Therefore, we must have p/q{a/c,b/d}p/q\in\{a/c,b/d\}. Furthermore, s=ms=m if p/q=a/cp/q=a/c and s=m+1s=m+1 if p/q=b/dp/q=b/d.

If instead p>ωp>\omega, then it follows that (3)(a) holds, and we obtain ω=p1\omega=p-1. Furthermore, (q,ω+1)=(q,p)(q,\omega+1)=(q,p) is in the cone bounded by the rays from (0,0)(0,0) through (d,b)(d,b) and (c,a)(c,a). Since m+1ωm+1\leq\omega, it follows that (q,ω+1)=(m+1,ω+1)(q,\omega+1)=(m+1,\omega+1). Moreover, (m+1)/(ω+1)(m+1)/(\omega+1) is the mediant of d/bd/b and c/ac/a, meaning that a+b=ω+1a+b=\omega+1 and c+d=m+1c+d=m+1.

Hence, if XX has three distinct solid torus fillings, then they have slopes a/ca/c, b/db/d, and (a+b)/(c+d)(a+b)/(c+d) (in conformity with the cyclic surgery theorem [CGLS87]). We assume this going forward.

Suppose that (3)(b) holds for both b/db/d and a/ca/c. It follows that all lattice points interior to Δ((m,ω),(m+1,ω))\Delta((m,\omega),(m+1,\omega)) fall on the rays generated by (d,b)(d,b) and (c,a)(c,a). In particular, (m,ω1)(m,\omega-1) is a multiple of exactly one of these two points, meaning that ω1(mode)\omega\equiv 1\pmod{e} for a unique value e{a,b}e\in\{a,b\}. Thus, (3)(a) holds for whichever of b/db/d and a/ca/c has numerator different from ee.

On the other hand, if (3)(a) holds for some p/q{a/c,b/d}p/q\in\{a/c,b/d\}, then it must hold with the sign +1+1, since otherwise one of aa or bb divides the other, a contradiction. Since (m,ω1)(m,\omega-1) is the unique lattice point in Δ((m,ω),(m+1,ω))\Delta((m,\omega),(m+1,\omega)) with its yy-coordinate, it follows that it is a multiple of (q,p)(q,p). Thus, (3)(a) holds for at most one of a/c,b/da/c,b/d.

In total, (3)(a) holds for one of a/ca/c, b/db/d and (3)(b) holds for the other. Applying the linear map (x,y)(yx,y)(x,y)\mapsto(y-x,y) exchanges KK with its mirror (see [Wu04, §4]). Thus, we may assume that (3)(a) holds for a/ca/c and (3)(b) for b/db/d. We have k(c,a)=(m,ω1)k\cdot(c,a)=(m,\omega-1) for some kk\in{\mathbb{Z}}, k>0k>0. Since (m+1,ω+1)=(c,a)+(d,b)(m+1,\omega+1)=(c,a)+(d,b), we obtain (m+1,ω+1)=k(c,a)+(1,2)(m+1,\omega+1)=k\cdot(c,a)+(1,2), and so (k1)(c,a)+(1,2)=(d,b)(k-1)\cdot(c,a)+(1,2)=(d,b). Hence

1=|dbca|=|12ca|=a2cand1=|m+1ωdb|=|m+1ω+1db|+d=1+d.1=\left|\begin{matrix}d&b\\ c&a\end{matrix}\right|=\left|\begin{matrix}1&2\\ c&a\end{matrix}\right|=a-2c\quad\mathrm{and}\quad 1=\left|\begin{matrix}m+1&\omega\\ d&b\end{matrix}\right|=\left|\begin{matrix}m+1&\omega+1\\ d&b\end{matrix}\right|+d=-1+d.

We deduce in turn that d=2d=2, k=2k=2, c=1c=1, a=3a=3, b=5b=5, ω=7\omega=7, and m=2m=2. Since (7/3,5/2,3/1,7/2)(7/3,5/2,3/1,7/2) is the Farey sequence of fractions between ω/(m+1)\omega/(m+1) and ω/m\omega/m, the slope interval of KK is [5/2,3/1][5/2,3/1], and it has winding number 77. See Figure 4. These invariants specify KK(7,4,2)K\simeq K(7,4,2). ∎

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