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An improved eigenvalue estimate for embedded minimal hypersurfaces in the sphere

Jonah A. J. Duncan Johns Hopkins University, 404 Krieger Hall, Department of Mathematics, 3400 N. Charles Street, Baltimore, MD 21218, US. jdunca33@jhu.edu Yannick Sire Johns Hopkins University, 404 Krieger Hall, Department of Mathematics, 3400 N. Charles Street, Baltimore, MD 21218, US. ysire1@jhu.edu  and  Joel Spruck Johns Hopkins University, 404 Krieger Hall, Department of Mathematics, 3400 N. Charles Street, Baltimore, MD 21218, US. jspruck1@jhu.edu
Abstract.

Suppose that Σn𝕊n+1\Sigma^{n}\subset\mathbb{S}^{n+1} is a closed embedded minimal hypersurface. We prove that the first non-zero eigenvalue λ1\lambda_{1} of the induced Laplace-Beltrami operator on Σ\Sigma satisfies λ1n2+an(Λ6+bn)1\lambda_{1}\geq\frac{n}{2}+a_{n}(\Lambda^{6}+b_{n})^{-1}, where ana_{n} and bnb_{n} are explicit dimensional constants and Λ\Lambda is an upper bound for the length of the second fundamental form of Σ\Sigma. This provides the first explicitly computable improvement on Choi & Wang’s lower bound λ1n2\lambda_{1}\geq\frac{n}{2} without any further assumptions on Σ\Sigma.

1. Introduction

An important problem in geometric analysis is to understand the spectrum of the Laplace-Beltrami operator on a Riemannian manifold, and to study its relation to the underlying intrinsic and/or ambient geometry. From the geometric perspective, it is of particular interest to address such questions for manifolds embedded in spaces of constant curvature. In this paper, we obtain a new lower bound for the first non-zero eigenvalue λ1(Σ)\lambda_{1}(\Sigma) of the induced Laplace-Beltrami operator ΔΣ-\Delta^{\Sigma} on a smooth closed hypersurface Σn\Sigma^{n} minimally embedded in the unit sphere 𝕊n+1\mathbb{S}^{n+1} (which we always assume to be equipped with the round metric).

In this direction, an argument of Choi & Wang [6], later refined by Brendle [1], gives the lower bound

λ1(Σ)>n2.\displaystyle\lambda_{1}(\Sigma)>\frac{n}{2}. (1.1)

An important application of (1.1) and the Yang-Yau inequality [16] is an area bound for embedded minimal surfaces in 𝕊3\mathbb{S}^{3} in terms of their genus; this plays a crucial role in the compactness theory of Choi & Schoen [5]. Moreover, (1.1) provides evidence towards a famous conjecture of Yau [17], which predicts that λ1(Σ)\lambda_{1}(\Sigma) is equal to nn. Note that the restriction to 𝕊n+1\mathbb{S}^{n+1} of each coordinate function on n+2\mathbb{R}^{n+2} is an eigenfunction for ΔΣ-\Delta^{\Sigma} with eigenvalue nn, and thus the upper bound λ1(Σ)n\lambda_{1}(\Sigma)\leq n is clear.

Despite an extensive literature relating to the study of λ1(Σ)\lambda_{1}(\Sigma) under additional assumptions on Σ\Sigma since the work of Choi & Wang (see e.g. [4, 15] and the references therein), (1.1) has remained the strongest explicit lower bound that is known to hold for a general embedded minimal hypersurface in 𝕊n+1\mathbb{S}^{n+1}. In this paper, we obtain an explicit improvement on (1.1) which depends only on the dimension nn and an upper bound on the length A=traceA2\|A\|\mathrel{\hbox to0.0pt{\raisebox{1.29167pt}{$\cdot$}\hss}\raisebox{-1.29167pt}{$\cdot$}}=\sqrt{\operatorname{trace}A^{2}} of the second fundamental form of Σ\Sigma. Our main result is as follows:

Theorem 1.1.

Let Σn𝕊n+1\Sigma^{n}\subset\mathbb{S}^{n+1} be a closed embedded minimal hypersurface and denote Λ=maxΣA\Lambda=\max_{\Sigma}\|A\|. Then there exist constants

an(n1)n232000andbn5n2216\displaystyle a_{n}\geq\frac{(n-1)n^{2}}{32000}\quad\text{and}\quad b_{n}\leq\frac{5n^{2}}{216} (1.2)

such that

λ1(Σ)n2+anΛ6+bn.\displaystyle\lambda_{1}(\Sigma)\geq\frac{n}{2}+\frac{a_{n}}{\Lambda^{6}+b_{n}}. (1.3)
Remark 1.2.

In the proof of Theorem 1.1, we will actually show that one can take

an3(n1)n7/23200arctan3(13n)andbn5n7/28arctan3(13n).\displaystyle a_{n}\geq\frac{3(n-1)n^{7/2}}{3200}\arctan^{3}\bigg{(}\frac{1}{3\sqrt{n}}\bigg{)}\quad\text{and}\quad b_{n}\leq\frac{5n^{7/2}}{8}\arctan^{3}\bigg{(}\frac{1}{3\sqrt{n}}\bigg{)}. (1.4)

The inequalities in (1.2) follow since for n2n\geq 2 we have 7200n3/2arctan3(13n)127\frac{7}{200}\leq n^{3/2}\arctan^{3}(\frac{1}{3\sqrt{n}})\leq\frac{1}{27}.

Whilst we are only interested in explicitly computable lower bounds for λ1(Σ)\lambda_{1}(\Sigma) in this paper, we note that upper bounds for either λ1(Mn,g)\lambda_{1}(M^{n},g) or λ1(Mn,g)Vol(Mn,g)2/n\lambda_{1}(M^{n},g)\cdot\operatorname{Vol}(M^{n},g)^{2/n} on Riemannian manifolds (Mn,g)(M^{n},g) have also been studied extensively – see for instance the classical works of Cheng [3], Li & Yau [10, 11], Yang & Yau [16] and Korevaar [9]. In particular, recall that for a closed orientable Riemannian surface (Σ2,g)(\Sigma^{2},g) of genus γ\gamma, the Yang-Yau inequality [16, 7] states that λ1(Σ,g)Area(Σ,g)8πγ+32\lambda_{1}(\Sigma,g)\operatorname{Area}(\Sigma,g)\leq 8\pi\lfloor\frac{\gamma+3}{2}\rfloor, where x\lfloor x\rfloor denotes the integer part of xx. The following result is then an immediate corollary of the Yang-Yau inequality and Theorem 1.1:

Corollary 1.3.

Let Σ2𝕊3\Sigma^{2}\subset\mathbb{S}^{3} be a closed embedded minimal surface of genus γ\gamma and denote Λ=maxΣA\Lambda=\max_{\Sigma}\|A\|. Then there exist constants ana_{n} and bnb_{n} satisfying (1.2) such that

Area(Σ)(n2+anΛ6+bn)18πγ+32.\displaystyle\operatorname{Area}(\Sigma)\leq\bigg{(}\frac{n}{2}+\frac{a_{n}}{\Lambda^{6}+b_{n}}\bigg{)}^{-1}8\pi\bigg{\lfloor}\frac{\gamma+3}{2}\bigg{\rfloor}. (1.5)
Remark 1.4.

As a consequence of our method for proving Theorem 1.1, we will also obtain an explicit volume bound for closed embedded mean-convex hypersurfaces in 𝕊n+1\mathbb{S}^{n+1} in terms of nn and Λ\Lambda – see Proposition 2.2. We note that our proof of Proposition 2.2 does not invoke any lower bound for λ1\lambda_{1}.

To put Theorem 1.1 into context, we now briefly discuss some related results. We first observe that, in light of the strictness of the inequality in (1.1), non-explicit improved lower bounds depending only on quantities such as dimension, index, topological type and curvature bounds follow from suitable compactness results. For example, if 𝒜(Λ,n)\mathcal{A}(\Lambda,n) denotes the class of closed embedded minimal hypersurfaces in 𝕊n+1\mathbb{S}^{n+1} satisfying maxΣAΛ\max_{\Sigma}\|A\|\leq\Lambda, then it is well-known that 𝒜(Λ,n)\mathcal{A}(\Lambda,n) is compact in the CkC^{k} topology for any k2k\geq 2. Combined with (1.1), it follows that there exists a constant α(Λ,n)>0\alpha(\Lambda,n)>0 such that

λ1(Σ)n2+α(Λ,n)for all Σ𝒜(Λ,n).\displaystyle\lambda_{1}(\Sigma)\geq\frac{n}{2}+\alpha(\Lambda,n)\quad\text{for all }\Sigma\in\mathcal{A}(\Lambda,n). (1.6)

We stress that, in contrast with (1.6), the estimate (1.3) obtained in Theorem 1.1 provides an explicitly computable improvement on (1.1). Moreover, our lower bound (1.3) is obtained by arguing more directly in the spirit of [6], rather than appealing to any compactness theory.

CkC^{k} compactness results have also been established in other classes. For example, Choi & Schoen showed in [5] that the class (γ)\mathcal{B}(\gamma) of closed embedded minimal surfaces in 𝕊3\mathbb{S}^{3} with genus less than γ\gamma is compact in the CkC^{k} topology for any k2k\geq 2. In combination with (1.1), this implies the existence of a constant β(γ)>0\beta(\gamma)>0 such that

λ1(Σ)1+β(γ)for all Σ(γ).\displaystyle\lambda_{1}(\Sigma)\geq 1+\beta(\gamma)\quad\text{for all }\Sigma\in\mathcal{B}(\gamma). (1.7)

A more recent compactness of result of Sharp [13, Corollary 2.6] shows that the class 𝒞(V,I,n)\mathcal{C}(V,I,n) of closed embedded minimal hypersurfaces in 𝕊n+1\mathbb{S}^{n+1} with volume bounded from above by VV and index bounded from above by II is compact in the CkC^{k} topology for k2k\geq 2 when 2n62\leq n\leq 6. Combined with (1.1), this implies the existence of a constant δ(V,I,n)>0\delta(V,I,n)>0 such that

λ1(Σ)n2+δ(V,I,n)for all Σ𝒞(V,I,n) when 2n6.\displaystyle\lambda_{1}(\Sigma)\geq\frac{n}{2}+\delta(V,I,n)\quad\text{for all }\Sigma\in\mathcal{C}(V,I,n)\text{ when }2\leq n\leq 6. (1.8)

In a similar vein to Theorem 1.1, it would be interesting to derive improved lower bounds for λ1(Σ)\lambda_{1}(\Sigma) with explicit dependence on quantities such as genus (when n=2n=2), volume and/or index. Such results could provide a step towards proving Yau’s conjecture within certain classes of minimal hypersurfaces in 𝕊n+1\mathbb{S}^{n+1}. Recently, Yau’s conjecture was established for the class of embedded isoparametric minimal hypersurfaces in 𝕊n+1\mathbb{S}^{n+1} – see Tang & Yan [15] and the references therein. We refer also to the work of Choe & Soret [4], where Yau’s conjecture was established for a class of symmetric minimal surfaces in 𝕊3\mathbb{S}^{3}.

Remark 1.5.

The aforementioned results of [6, 5, 13] apply more generally when 𝕊n+1\mathbb{S}^{n+1} is replaced by a closed manifold (Mn+1,g)(M^{n+1},g) whose Ricci curvature satisfies Ricgkg\operatorname{Ric}_{g}\geq kg for some constant k>0k>0. The bound (1.1) is then replaced by λ1(Σ)>k2\lambda_{1}(\Sigma)>\frac{k}{2}, and our subsequent discussion generalises in the obvious way. In attempting to generalise Theorem 1.1 to this more general context, it seems that our method introduces constants that depend on sectional curvature bounds. To keep the exposition simple, and since the case of the sphere is the one of most interest, we will not discuss such generalisations in this paper.

The plan of the paper is as follows. In Section 2 we prove a preliminary result on the embeddedness of parallel hypersurfaces in 𝕊n+1\mathbb{S}^{n+1}. As a corollary, we obtain an explicit volume bound for closed embedded mean-convex hypersurfaces in 𝕊n+1\mathbb{S}^{n+1} in terms of an upper bound for A\|A\|. In Section 3 we prove Theorem 1.1. The key here is to estimate a positive term which is dropped in the estimate of Choi & Wang in [6]. Here, our integral estimates require working in a neighbourhood of Σ\Sigma whose thickness is controlled away from zero; this control is provided by our results in Section 2.

2. Embeddedness of parallel hypersurfaces

Suppose that Σn\Sigma^{n} is a smooth, closed and embedded hypersurface in 𝕊n+1\mathbb{S}^{n+1}. As observed in [6], Σ\Sigma divides the sphere into two components 𝕊n+1=M1M2\mathbb{S}^{n+1}=M_{1}\cup M_{2}, where M1=M2=Σ\partial M_{1}=\partial M_{2}=\Sigma. Let NΣN\Sigma denote the normal bundle of Σ𝕊n+1\Sigma\subset\mathbb{S}^{n+1} and expNΣ\operatorname{exp}^{N\Sigma} the corresponding exponential map. We fix the orientation on Σ\Sigma determined by the unit normal vector field XX on Σ\Sigma pointing into M1M_{1}, and for tt\in\mathbb{R} we define

Σt={expNΣ(p,tXp)𝕊n+1:pΣ}.\displaystyle\Sigma^{t}=\{\operatorname{exp}^{N\Sigma}(p,tX_{p})\in\mathbb{S}^{n+1}:p\in\Sigma\}. (2.1)

Geometrically, Σt\Sigma^{t} is the hypersurface parallel to Σ\Sigma and of signed distance tt to Σ\Sigma. It is well-known (see e.g. Theorems 2.1 and 2.2 in [2]) that if κ1(p),,κn(p)\kappa_{1}(p),\dots,\kappa_{n}(p) are the principal curvatures of Σ\Sigma at pp and κmax=maxpΣ,i{1,,n}|κi(p)|\kappa_{\operatorname{max}}=\max_{p\in\Sigma,i\in\{1,\dots,n\}}|\kappa_{i}(p)|, then Σt\Sigma^{t} is a smooth immersed hypersurface in 𝕊n+1\mathbb{S}^{n+1} for

|t|<arctan(κmax1)=TΣ.\displaystyle|t|<\arctan(\kappa_{\operatorname{max}}^{-1})=\mathrel{\hbox to0.0pt{\raisebox{1.29167pt}{$\cdot$}\hss}\raisebox{-1.29167pt}{$\cdot$}}T_{\Sigma}. (2.2)

Moreover, we may consider nn continuous functions κi(,):Σ×(TΣ,TΣ)\kappa_{i}(\cdot,\cdot):\Sigma\times(-T_{\Sigma},T_{\Sigma})\rightarrow\mathbb{R} defined by

κi(,t)=κi(,0)+tant1κi(,0)tant,κi(,0)=κi().\displaystyle\kappa_{i}(\cdot,t)=\frac{\kappa_{i}(\cdot,0)+\tan t}{1-\kappa_{i}(\cdot,0)\tan t},\quad\kappa_{i}(\cdot,0)\mathrel{\hbox to0.0pt{\raisebox{1.29167pt}{$\cdot$}\hss}\raisebox{-1.29167pt}{$\cdot$}}=\kappa_{i}(\cdot). (2.3)

Then for each t(TΣ,TΣ)t\in(-T_{\Sigma},T_{\Sigma}), the quantities κ1(p,t),,κn(p,t)\kappa_{1}(p,t),\dots,\kappa_{n}(p,t) are the principal curvatures of Σt\Sigma^{t} at expNΣ(p,tXp)\operatorname{exp}^{N\Sigma}(p,tX_{p}), with respect to the orientation on Σt\Sigma^{t} determined by parallel transporting XX along geodesics normal to Σ\Sigma by a signed distance tt.

Whilst it is well-known that Σt\Sigma^{t} remains embedded for tt sufficiently small, in general the range of tt for which Σt\Sigma^{t} is embedded is not controlled by the curvature of Σ\Sigma, since Σ\Sigma may be arbitrarily close to ‘self-touching’. We show that in the case that Σ\Sigma is mean-convex (that is, the mean curvature HΣH_{\Sigma} of Σ\Sigma is nonnegative), we do in fact have such control:

Proposition 2.1.

Suppose Σn𝕊n+1\Sigma^{n}\subset\mathbb{S}^{n+1} is a smooth, closed and embedded mean-convex hypersurface. Then Σt\Sigma^{t} is a smooth, closed and embedded strictly mean-convex hypersurface in 𝕊n+1\mathbb{S}^{n+1} for |t|(0,TΣ)|t|\in(0,T_{\Sigma}).

Proof.

We consider the case t>0t>0; the case t<0t<0 is similar. Let

t=sup{t>0:Σt is smooth and embedded},\displaystyle t_{*}=\sup\{t>0:\Sigma^{t}\text{ is smooth and embedded}\}, (2.4)

and suppose for a contradiction that t=arctan(εκmax1)t_{*}=\arctan(\varepsilon\kappa_{\operatorname{max}}^{-1}) for some 0<ε<10<\varepsilon<1. Since t<TΣt_{*}<T_{\Sigma}, by the discussion above Σt\Sigma^{t_{*}} is a smooth, immersed, non-embedded hypersurface. Therefore, for some point xΣtx\in\Sigma^{t_{*}}, there exist distinct points p,qΣp,q\in\Sigma such that x=expNΣ(p,tXp)=expNΣ(q,tXq)x=\operatorname{exp}^{N\Sigma}(p,t_{*}X_{p})=\operatorname{exp}^{N\Sigma}(q,t_{*}X_{q}). Now, locally near pp (resp. qq), Σt\Sigma^{t} is a smooth graph over a neighbourhood of the origin in TpΣT_{p}\Sigma (resp. TqΣT_{q}\Sigma) for ttt\leq t_{*}. Denote these graphs by Σpt\Sigma^{t}_{p} and Σqt\Sigma^{t}_{q}, respectively. Then by (2.3), on Σpt\Sigma_{p}^{t} we have

κi(p,t)=κi(p,0)+tant1κi(p,0)tant\displaystyle\kappa_{i}(p,t_{*})=\frac{\kappa_{i}(p,0)+\tan t_{*}}{1-\kappa_{i}(p,0)\tan t_{*}} =κi(p,0)+(1+κi(p,0)2)tant1κi(p,0)tant\displaystyle=\kappa_{i}(p,0)+\frac{(1+\kappa_{i}(p,0)^{2})\tan t_{*}}{1-\kappa_{i}(p,0)\tan t_{*}}
>κi(p,0)+(1+κi(p,0)2)tant1ε,\displaystyle>\kappa_{i}(p,0)+\frac{(1+\kappa_{i}(p,0)^{2})\tan t_{*}}{1-\varepsilon}, (2.5)

and likewise on Σqt\Sigma_{q}^{t} we have

κi(q,t)>κi(q,0)+(1+κi(q,0)2)tant1ε.\displaystyle\kappa_{i}(q,t_{*})>\kappa_{i}(q,0)+\frac{(1+\kappa_{i}(q,0)^{2})\tan t_{*}}{1-\varepsilon}. (2.6)

Summing over ii in (2) and (2.6), and using mean-convexity of Σ\Sigma to assert iκi(p,0)0\sum_{i}\kappa_{i}(p,0)\geq 0 and iκi(q,0)0\sum_{i}\kappa_{i}(q,0)\geq 0, we see that the mean curvature HΣptH_{\Sigma^{t_{*}}_{p}} of Σpt\Sigma_{p}^{t_{*}} at the point xx satisfies

HΣpt(x)>(n+A(p)2)tant1ε>0,\displaystyle H_{\Sigma^{t_{*}}_{p}}(x)>\frac{(n+\|A(p)\|^{2})\tan t_{*}}{1-\varepsilon}>0, (2.7)

and likewise

HΣqt(x)>(n+A(q)2)tant1ε>0.\displaystyle H_{\Sigma^{t_{*}}_{q}}(x)>\frac{(n+\|A(q)\|^{2})\tan t_{*}}{1-\varepsilon}>0. (2.8)
x{\textstyle x}Σ~pt\widetilde{\Sigma}_{p}^{t_{*}}Σqt\Sigma_{q}^{t_{*}}Br(x)B_{r}(x)ν\nud1>0,d2>0d_{1}>0,\ d_{2}>0d1<0,d2>0d_{1}<0,\ d_{2}>0d1<0,d2<0d_{1}<0,\ d_{2}<0
Figure 1.

Now, by minimality of tt_{*}, the graphs Σpt\Sigma^{t_{*}}_{p} and Σqt\Sigma^{t_{*}}_{q} meet tangentially at xx and thus have opposite orientations at xx. Let us denote by Σ~pt\widetilde{\Sigma}_{p}^{t_{*}} the hypersurface Σpt\Sigma_{p}^{t_{*}} but with the opposite orientation. Then by (2.7) and (2.8), we have

HΣ~pt(x)<0<HΣqt(x).\displaystyle H_{\widetilde{\Sigma}^{t_{*}}_{p}}(x)<0<H_{\Sigma^{t_{*}}_{q}}(x). (2.9)

Now denote by d1d_{1} the signed distance to Σ~pt\widetilde{\Sigma}_{p}^{t_{*}} and d2d_{2} the signed distance to Σqt\Sigma_{q}^{t_{*}}, so that the functions did_{i} are positive in the direction ν\nu of the common orientation of Σ~pt\widetilde{\Sigma}_{p}^{t_{*}} and Σqt\Sigma_{q}^{t_{*}}; note that the functions did_{i} are well defined in a sufficiently small geodesic ball Br(x)B_{r}(x) (see Figure 1). Since HΣ~pt(x)=Δd1(x)H_{\widetilde{\Sigma}^{t_{*}}_{p}}(x)=-\Delta d_{1}(x) and HΣqt(x)=Δd2(x)H_{\Sigma^{t_{*}}_{q}}(x)=-\Delta d_{2}(x), (2.9) can be rewritten as

Δd1(x)<0<Δd2(x),\displaystyle-\Delta d_{1}(x)<0<-\Delta d_{2}(x), (2.10)

and by continuity it follows that Δd1<0<Δd2-\Delta d_{1}<0<-\Delta d_{2} in Br(x){d1>0}B_{r}(x)\cap\{d_{1}>0\} for sufficiently small rr, i.e. Δ(d2d1)<0\Delta(d_{2}-d_{1})<0 in Br(x){d1>0}B_{r}(x)\cap\{d_{1}>0\}. But d2d10d_{2}-d_{1}\geq 0 in Br(x){d1>0}B_{r}(x)\cap\{d_{1}>0\} and (d2d1)(x)=0(d_{2}-d_{1})(x)=0. By the Hopf lemma, either d2d1d_{2}-d_{1} is constant in Br(x){d1>0}B_{r}(x)\cap\{d_{1}>0\}, or ν(d2d1)(x)>0\nabla_{\nu}(d_{2}-d_{1})(x)>0. In either case we obtain a contradiction: the first possibility contradicts the strict inequality Δ(d2d1)<0\Delta(d_{2}-d_{1})<0 in Br(x){d1>0}B_{r}(x)\cap\{d_{1}>0\}, and the second possibility contradicts the fact that νd1(x)=νd2(x)=1\nabla_{\nu}d_{1}(x)=\nabla_{\nu}d_{2}(x)=1.

We have therefore shown that t=TΣt_{*}=T_{\Sigma}. It is also clear from the computations (2)–(2.8) that Σt\Sigma^{t} is strictly mean convex for t(0,TΣ)t\in(0,T_{\Sigma}), which completes the proof of the proposition. ∎

As a corollary of Proposition 2.1 we obtain an explicit volume bound for closed embedded mean-convex hypersurfaces in 𝕊n+1\mathbb{S}^{n+1}:

Proposition 2.2.

Suppose Σn𝕊n+1\Sigma^{n}\subset\mathbb{S}^{n+1} is a smooth, closed and embedded mean-convex hypersurface with maxΣAΛ\max_{\Sigma}\|A\|\leq\Lambda, and define

IΛ=0arctan(Λ1)(cost)n(1Λtant)n𝑑t.\displaystyle\operatorname{I}_{\Lambda}=\int_{0}^{\arctan(\Lambda^{-1})}(\cos t)^{n}(1-\Lambda\tan t)^{n}\,dt. (2.11)

Then

Vol(Σn)12IΛVol(𝕊n+1).\displaystyle\operatorname{Vol}(\Sigma^{n})\leq\frac{1}{2\operatorname{I}_{\Lambda}}\operatorname{Vol}(\mathbb{S}^{n+1}). (2.12)

In particular, there exists a dimensional constant cn253(54)n2c_{n}\leq\frac{25}{3}\big{(}\frac{5}{4}\big{)}^{n-2} such that

Vol(Σn)cnΛVol(𝕊n+1)\displaystyle\operatorname{Vol}(\Sigma^{n})\leq c_{n}\Lambda\operatorname{Vol}(\mathbb{S}^{n+1}) (2.13)

whenever Λ14\Lambda\geq\frac{1}{4}.

Remark 2.3.

Suppose in addition to the hypotheses of Proposition 2.2 that Σ\Sigma is minimal and not totally geodesic. Then by the inequality ΣA2(A2n)𝑑Sg0\int_{\Sigma}\|A\|^{2}(\|A\|^{2}-n)\,dS_{g}\geq 0 of Simons [14], Λn\Lambda\geq\sqrt{n} and thus the assumption Λ14\Lambda\geq\frac{1}{4} is automatically satisfied. Note that the restriction Λ14\Lambda\geq\frac{1}{4} is somewhat arbitrary, allowing us to make a crude estimation of the quantity IΛ\operatorname{I}_{\Lambda} in the proof below.

Proof.

Let V±(R)V^{\pm}(R) denote the volume of region swept out by the parallel hypersurfaces Σ±t\Sigma^{\pm t} for 0tR0\leq t\leq R. Then by [8, Exercise 3.5] and Proposition 2.1, the following formula is valid for Rarctan(Λ1)R\leq\arctan(\Lambda^{-1}):

V±(R)=Σ(0R(cost)ni=1n(1κitant)dt)𝑑S.\displaystyle V^{\pm}(R)=\int_{\Sigma}\bigg{(}\int_{0}^{R}(\cos t)^{n}\prod_{i=1}^{n}(1\mp\kappa_{i}\tan t)\,dt\bigg{)}\,dS. (2.14)

Taking R=arctan(Λ1)R=\arctan(\Lambda^{-1}), we therefore see that

Vol(𝕊n+1)\displaystyle\operatorname{Vol}(\mathbb{S}^{n+1}) V+(arctan(Λ1))+V(arctan(Λ1))\displaystyle\geq V^{+}(\arctan(\Lambda^{-1}))+V^{-}(\arctan(\Lambda^{-1}))
2Σ(0arctan(Λ1)(cost)n(1Λtant)n𝑑t)𝑑S=2IΛVol(Σn),\displaystyle\geq 2\int_{\Sigma}\bigg{(}\int_{0}^{\arctan(\Lambda^{-1})}(\cos t)^{n}(1-\Lambda\tan t)^{n}\,dt\bigg{)}\,dS=2\operatorname{I}_{\Lambda}\operatorname{Vol}(\Sigma^{n}), (2.15)

which proves (2.12).

Now suppose that Λ14\Lambda\geq\frac{1}{4}. Then on the interval [0,554Λ][0,\frac{5}{54\Lambda}] it is easy to verify that cost910\cos t\geq\frac{9}{10} and tant27t25110Λ\tan t\leq\frac{27t}{25}\leq\frac{1}{10\Lambda}, and moreover 554Λarctan(Λ1)\frac{5}{54\Lambda}\leq\arctan(\Lambda^{-1}). Therefore, by (2) we obtain

Vol(𝕊n+1)2Vol(Σn)0554Λ(cost)n(1Λtant)n𝑑t527(910)2nVol(Σn)Λ,\displaystyle\operatorname{Vol}(\mathbb{S}^{n+1})\geq 2\operatorname{Vol}(\Sigma^{n})\int_{0}^{\frac{5}{54\Lambda}}(\cos t)^{n}(1-\Lambda\tan t)^{n}\,dt\geq\frac{5}{27}\bigg{(}\frac{9}{10}\bigg{)}^{2n}\frac{\operatorname{Vol}(\Sigma^{n})}{\Lambda}, (2.16)

from which the estimate (2.13) easily follows with cn253(54)n2c_{n}\leq\frac{25}{3}\big{(}\frac{5}{4}\big{)}^{n-2}. ∎

3. The improved estimate

In this section we prove Theorem 1.1. We begin in Section 3.1 by recalling the argument of Choi & Wang [6]. In Section 3.2 we give the proof of Theorem 1.1 assuming the validity of two propositions. In Sections 3.3 and 3.4 we give the proofs of these two propositions.

3.1. The estimate of Choi & Wang

Our proof of Theorem 1.1 initially proceeds in the same way as in [6]; we derive the relevant estimate of [6] here for the convenience of the reader. The starting point is the following identity due to Reilly [12], which is an integral version of Bochner’s formula:

Lemma 3.1 (Reilly’s formula).

Let (Xn+1,g)(X^{n+1},g) be a smooth orientable Riemannian manifold with boundary Σn=Xn+1\Sigma^{n}\mathrel{\hbox to0.0pt{\raisebox{1.29167pt}{$\cdot$}\hss}\raisebox{-1.29167pt}{$\cdot$}}=\partial X^{n+1}. Denote by dvgdv_{g} the volume element on (Xn+1,g)(X^{n+1},g), dSgdS_{g} the volume element of the induced metric on Σ\Sigma, uνu_{\nu} the outward normal derivative of uu on Σ\Sigma, Σ\nabla^{\Sigma} the gradient operator of the induced metric on Σ\Sigma, AA the second fundamental form of Σ\Sigma defined with respect to the inward unit normal, and HH the mean curvature of Σ\Sigma with respect to the inward unit normal. Then for uC2(X¯)u\in C^{2}(\overline{X}),

X((Δu)2|2u|2)𝑑vg\displaystyle\int_{X}\big{(}(\Delta u)^{2}-|\nabla^{2}u|^{2}\big{)}\,dv_{g} =XRicX(u,u)𝑑vg+Σ(ΔΣuHuν)uν𝑑Sg\displaystyle=\int_{X}\operatorname{Ric}_{X}(\nabla u,\nabla u)\,dv_{g}+\int_{\Sigma}(\Delta^{\Sigma}u-Hu_{\nu})u_{\nu}\,dS_{g}
ΣΣu,Σuν𝑑SgΣA(Σu,Σu)𝑑Sg.\displaystyle\quad-\int_{\Sigma}\langle\nabla^{\Sigma}u,\nabla^{\Sigma}u_{\nu}\rangle\,dS_{g}-\int_{\Sigma}A(\nabla^{\Sigma}u,\nabla^{\Sigma}u)\,dS_{g}. (3.1)
Remark 3.2.

Our convention that AA and HH be defined with respect to the inward unit normal on Σ\Sigma is opposite to the convention used in [6].

Recall that under the setup of Theorem 1.1, we may write 𝕊n+1=M1M2\mathbb{S}^{n+1}=M_{1}\cup M_{2}, where M1=M2=Σ\partial M_{1}=\partial M_{2}=\Sigma. Denote by Ψ\Psi an L2L^{2}-normalised eigenfunction corresponding to the first non-zero eigenvalue λ1\lambda_{1} of ΔΣ-\Delta^{\Sigma}, so that ΔΣΨ=λ1Ψ-\Delta^{\Sigma}\Psi=\lambda_{1}\Psi and ΨL2(Σ)=1\|\Psi\|_{L^{2}(\Sigma)}=1, and let uu be the unique solution to

{Δu=0in M1u=Ψon Σ.\displaystyle\begin{cases}\Delta u=0&\text{in }M_{1}\\ u=\Psi&\text{on }\Sigma.\end{cases} (3.2)

In what follows, we fix the orientation on Σ\Sigma pointing into M1M_{1}, and we denote by gg the round metric on 𝕊n+1\mathbb{S}^{n+1}. We may assume that ΣA(Σu,Σu)𝑑Sg0-\int_{\Sigma}A(\nabla^{\Sigma}u,\nabla^{\Sigma}u)\,dS_{g}\geq 0, otherwise we work on M2M_{2} instead. Then by Reilly’s formula and minimality of Σ\Sigma, the solution uu to (3.2) satisfies

M1|2u|2𝑑vg\displaystyle-\int_{M_{1}}|\nabla^{2}u|^{2}\,dv_{g} nM1|u|2𝑑vg+ΣuνΔΣu𝑑SgΣΣu,Σuν𝑑Sg\displaystyle\geq n\int_{M_{1}}|\nabla u|^{2}\,dv_{g}+\int_{\Sigma}u_{\nu}\Delta^{\Sigma}u\,dS_{g}-\int_{\Sigma}\langle\nabla^{\Sigma}u,\nabla^{\Sigma}u_{\nu}\rangle\,dS_{g}
=nM1|u|2𝑑vg+2ΣuνΔΣu𝑑Sg\displaystyle=n\int_{M_{1}}|\nabla u|^{2}\,dv_{g}+2\int_{\Sigma}u_{\nu}\Delta^{\Sigma}u\,dS_{g}
=nM1|u|2𝑑vg2λ1Σuνu𝑑Sg.\displaystyle=n\int_{M_{1}}|\nabla u|^{2}\,dv_{g}-2\lambda_{1}\int_{\Sigma}u_{\nu}u\,dS_{g}. (3.3)

On the other hand, integration by parts and the fact that Δu=0\Delta u=0 on M1M_{1} gives

Σuνu𝑑Sg=M1(|u|2+uΔu)𝑑vg=M1|u|2𝑑vg,\displaystyle\int_{\Sigma}u_{\nu}u\,dS_{g}=\int_{M_{1}}\big{(}|\nabla u|^{2}+u\Delta u\big{)}\,dv_{g}=\int_{M_{1}}|\nabla u|^{2}\,dv_{g}, (3.4)

and substituting (3.4) back into (3.1) yields

2(λ1n2)M1|u|2𝑑vg\displaystyle 2\bigg{(}\lambda_{1}-\frac{n}{2}\bigg{)}\int_{M_{1}}|\nabla u|^{2}\,dv_{g} M1|2u|2𝑑vg0.\displaystyle\geq\int_{M_{1}}|\nabla^{2}u|^{2}\,dv_{g}\geq 0. (3.5)

This is precisely the estimate derived in [6]; the lower bound λ1n2\lambda_{1}\geq\frac{n}{2} follows immediately from (3.5), since |u|0|\nabla u|\not\equiv 0. We note that in [1], Brendle gave a refinement of the above argument to show that λ1>n2\lambda_{1}>\frac{n}{2}, although we will not need to use this strict inequality in our subsequent arguments.

3.2. Proof of Theorem 1.1

As seen above, the term M1|2u|2𝑑vg\int_{M_{1}}|\nabla^{2}u|^{2}\,dv_{g} in (3.5) is simply dropped in the argument of Choi & Wang. In order to prove Theorem 1.1, we obtain a lower bound for M1|2u|2𝑑vg\int_{M_{1}}|\nabla^{2}u|^{2}\,dv_{g} in terms of M1|u|2𝑑vg\int_{M_{1}}|\nabla u|^{2}\,dv_{g}.

Our proof of Theorem 1.1 can be decomposed into two main propositions, which we describe now. We introduce parameters 0<εΛ20<\varepsilon\leq\frac{\Lambda}{2} and β>0\beta>0, which are to be fixed later in the proof of Theorem 1.1 but assumed sufficiently small for now so that γ=2nΛεΛε(nΛ2+1)β>0\gamma\mathrel{\hbox to0.0pt{\raisebox{1.29167pt}{$\cdot$}\hss}\raisebox{-1.29167pt}{$\cdot$}}=\sqrt{2n}-\frac{\Lambda\varepsilon}{\Lambda-\varepsilon}(\frac{n}{\Lambda^{2}}+1)-\beta>0. We also define δ=narctan(εn)\delta=n\arctan(\frac{\varepsilon}{n}) and T=δ2Λ2T=\frac{\delta}{2\Lambda^{2}}, and for t0t\geq 0 we denote M1t={xM1:d(x)>t}M_{1}^{t}=\{x\in M_{1}:d(x)>t\}, where dd is the distance to Σ\Sigma in M1M_{1}. Note M1t=Σt\partial M_{1}^{t}=\Sigma^{t} is a smooth embedded hypersurface for 0t<arctan(Λ1)0\leq t<\arctan(\Lambda^{-1}) by Proposition 2.1, and in particular this holds for 0t<2T0\leq t<2T. Our two main propositions are then as follows:

Proposition 3.3.

Suppose ε,β,γ,δ\varepsilon,\beta,\gamma,\delta and TT are as above, and Λn\Lambda\geq\sqrt{n}. Then

M1|u|2𝑑vg2Λ2δγM1T\M12T|u|2𝑑vg+1βγM1|2u|2𝑑vg.\displaystyle\int_{M_{1}}|\nabla u|^{2}\,dv_{g}\leq\frac{2\Lambda^{2}}{\delta\gamma}\int_{M_{1}^{T}\backslash M_{1}^{2T}}|\nabla u|^{2}\,dv_{g}+\frac{1}{\beta\gamma}\int_{M_{1}}|\nabla^{2}u|^{2}\,dv_{g}. (3.6)
Proposition 3.4.

Suppose ε,β,γ,δ\varepsilon,\beta,\gamma,\delta and TT are as above. Then

M1T|u|2𝑑vg16Λ4(n1)δ2M1|2u|2𝑑vg.\displaystyle\int_{M_{1}^{T}}|\nabla u|^{2}\,dv_{g}\leq\frac{16\Lambda^{4}}{(n-1)\delta^{2}}\int_{M_{1}}|\nabla^{2}u|^{2}\,dv_{g}. (3.7)

Assuming the validity of Propositions 3.3 and 3.4 for now, we proceed to give the proof of Theorem 1.1:

Proof of Theorem 1.1.

By Simons’ inequality ΣA2(A2n)𝑑Sg0\int_{\Sigma}\|A\|^{2}(\|A\|^{2}-n)\,dS_{g}\geq 0 for minimal hypersurfaces in 𝕊n+1\mathbb{S}^{n+1} [14], if Λ<n\Lambda<\sqrt{n} then A0A\equiv 0 and thus Σ\Sigma is a totally geodesic nn-sphere. In this case, it is well-known that λ1(Σ)=n\lambda_{1}(\Sigma)=n, and so (1.3) clearly holds. For the remainder of the proof, we may therefore assume that Λn\Lambda\geq\sqrt{n}.

Substituting the estimate (3.7) of Proposition 3.4 back into the estimate (3.6) of Proposition 3.3, we obtain

M1|u|2𝑑vg(32Λ6(n1)δ3γ+1βγ)M1|2u|2𝑑vg.\displaystyle\int_{M_{1}}|\nabla u|^{2}\,dv_{g}\leq\bigg{(}\frac{32\Lambda^{6}}{(n-1)\delta^{3}\gamma}+\frac{1}{\beta\gamma}\bigg{)}\int_{M_{1}}|\nabla^{2}u|^{2}\,dv_{g}. (3.8)

Therefore

M1|2u|2𝑑vganΛ6+bnM1|u|2𝑑vg\displaystyle\int_{M_{1}}|\nabla^{2}u|^{2}\,dv_{g}\geq\frac{a_{n}}{\Lambda^{6}+b_{n}}\int_{M_{1}}|\nabla u|^{2}\,dv_{g} (3.9)

where

an=(n1)δ3γ32andbn=(n1)δ332β.\displaystyle a_{n}=\frac{(n-1)\delta^{3}\gamma}{32}\quad\text{and}\quad b_{n}=\frac{(n-1)\delta^{3}}{32\beta}. (3.10)

Now, since we assume εΛ2\varepsilon\leq\frac{\Lambda}{2} we have ΛΛε2\frac{\Lambda}{\Lambda-\varepsilon}\leq 2, and since we assume Λn\Lambda\geq\sqrt{n} we have nΛ21\frac{n}{\Lambda^{2}}\leq 1. Substituting these inequalities back into the definition of γ\gamma, we see

γ\displaystyle\gamma =2nΛεΛε(nΛ2+1)βn(24εnβn).\displaystyle=\sqrt{2n}-\frac{\Lambda\varepsilon}{\Lambda-\varepsilon}\bigg{(}\frac{n}{\Lambda^{2}}+1\bigg{)}-\beta\geq\sqrt{n}\bigg{(}\sqrt{2}-\frac{4\varepsilon}{\sqrt{n}}-\frac{\beta}{\sqrt{n}}\bigg{)}. (3.11)

Choosing β=n20\beta=\frac{\sqrt{n}}{20} and ε=n3\varepsilon=\frac{\sqrt{n}}{3}, we then see that γn(243120)3n100\gamma\geq\sqrt{n}(\sqrt{2}-\frac{4}{3}-\frac{1}{20})\geq\frac{3\sqrt{n}}{100} and δ=narctan(εn)=narctan(13n)\delta=n\arctan(\frac{\varepsilon}{n})=n\arctan(\frac{1}{3\sqrt{n}}). Therefore

an3(n1)n7/23200arctan3(13n)andbn5n7/28arctan3(13n).\displaystyle a_{n}\geq\frac{3(n-1)n^{7/2}}{3200}\arctan^{3}\bigg{(}\frac{1}{3\sqrt{n}}\bigg{)}\quad\text{and}\quad b_{n}\leq\frac{5n^{7/2}}{8}\arctan^{3}\bigg{(}\frac{1}{3\sqrt{n}}\bigg{)}. (3.12)

As explained in Remark 1.2, this completes the proof of the theorem. ∎

The rest of the paper is devoted to the proofs of Propositions 3.3 and 3.4.

3.3. Proof of Proposition 3.3

To describe our setup for the proof of Proposition 3.3, let dd be the signed distance to Σ\Sigma in 𝕊n+1\mathbb{S}^{n+1}:

d(x)={dist(x,Σ)if xM2¯dist(x,Σ)if xM1.\displaystyle d(x)=\begin{cases}-\operatorname{dist}(x,\Sigma)&\text{if }x\in\overline{M_{2}}\\ \operatorname{dist}(x,\Sigma)&\text{if }x\in M_{1}.\end{cases} (3.13)

As before, we equip the surfaces Σd\Sigma^{d} with the orientation induced by Σ\Sigma, i.e. the orientation given by the normal vector field d\nabla d on Σd\Sigma^{d}. Then the mean curvature of Σd\Sigma^{d} is given by HΣd=divd=ΔdH_{\Sigma^{d}}=-\operatorname{div}\nabla d=-\Delta d.

By Proposition 2.1, the parallel hypersurfaces Σd\Sigma^{d} are smooth and embedded for

|d|[0,arctan(Λ1)).\displaystyle|d|\in\big{[}0,\arctan(\Lambda^{-1})\big{)}. (3.14)

However, to gain control on the mean curvature of the hypersurfaces parallel to Σ\Sigma, in the proof of Proposition 3.3 we will need to work in a neighbourhood around Σ\Sigma of thickness smaller than that determined by (3.14). To this end, for 0<εΛ20<\varepsilon\leq\frac{\Lambda}{2} we define

Dε=arctan(εΛ2).\displaystyle D_{\varepsilon}=\arctan(\varepsilon\Lambda^{-2}). (3.15)

Since εΛ<1\frac{\varepsilon}{\Lambda}<1, clearly Dε<arctan(Λ1)D_{\varepsilon}<\arctan(\Lambda^{-1}) and thus Σt\Sigma^{t} is a smooth embedded hypersurface for |t|[0,Dε]|t|\in[0,D_{\varepsilon}]. Our first estimate towards the proof of Proposition 3.3 is an upper bound on the mean curvature of the hypersurfaces Σt\Sigma^{t} parallel to Σ\Sigma when t[0,Dε]t\in[0,D_{\varepsilon}]:

Lemma 3.5.

Let 0<εΛ20<\varepsilon\leq\frac{\Lambda}{2}. Then for t[0,Dε]t\in[0,D_{\varepsilon}],

HΣtε~=ΛεΛε(nΛ2+1).\displaystyle H_{\Sigma^{t}}\leq\widetilde{\varepsilon}\mathrel{\hbox to0.0pt{\raisebox{1.29167pt}{$\cdot$}\hss}\raisebox{-1.29167pt}{$\cdot$}}=\frac{\Lambda\varepsilon}{\Lambda-\varepsilon}\bigg{(}\frac{n}{\Lambda^{2}}+1\bigg{)}. (3.16)
Proof.

Summing over ii in (2.3) and appealing to minimality of Σ\Sigma, we see that for t[0,Dε]t\in[0,D_{\varepsilon}] we have

HΣt=i=1n(κi(,0)+(1+κi(,0)2)tant1κi(,0)tant)=i=1n(1+κi(,0)2)tant1κi(,0)tant.\displaystyle H_{\Sigma^{t}}=\sum_{i=1}^{n}\bigg{(}\kappa_{i}(\cdot,0)+\frac{(1+\kappa_{i}(\cdot,0)^{2})\tan t}{1-\kappa_{i}(\cdot,0)\tan t}\bigg{)}=\sum_{i=1}^{n}\frac{(1+\kappa_{i}(\cdot,0)^{2})\tan t}{1-\kappa_{i}(\cdot,0)\tan t}. (3.17)

Now, by definition of DεD_{\varepsilon}, we have 1κi(,0)tantΛεΛ1-\kappa_{i}(\cdot,0)\tan t\geq\frac{\Lambda-\varepsilon}{\Lambda} on [0,Dε][0,D_{\varepsilon}] for each ii, and it therefore follows from (3.17) that for t[0,Dε]t\in[0,D_{\varepsilon}],

HΣtΛΛε(n+Λ2)tant\displaystyle H_{\Sigma^{t}}\leq\frac{\Lambda}{\Lambda-\varepsilon}(n+\Lambda^{2})\tan t =ΛΛε(nΛ2+1)Λ2tantΛεΛε(nΛ2+1),\displaystyle=\frac{\Lambda}{\Lambda-\varepsilon}\bigg{(}\frac{n}{\Lambda^{2}}+1\bigg{)}\Lambda^{2}\tan t\leq\frac{\Lambda\varepsilon}{\Lambda-\varepsilon}\bigg{(}\frac{n}{\Lambda^{2}}+1\bigg{)}, (3.18)

as claimed. ∎

We now use Lemma 3.5 to show:

Lemma 3.6.

Let 0<εΛ20<\varepsilon\leq\frac{\Lambda}{2} and suppose vv is a smooth function defined on M1¯\overline{M_{1}}. Then for t[0,Dε]t\in[0,D_{\varepsilon}] and any β>0\beta>0,

Σ|v|2𝑑SgΣt|v|2𝑑Sg+(ε~+β)M1\M1t|v|2𝑑vg+β1M1\M1t|2v|2𝑑vg.\displaystyle\int_{\Sigma}|\nabla v|^{2}\,dS_{g}\leq\int_{\Sigma^{t}}|\nabla v|^{2}\,dS_{g}+(\widetilde{\varepsilon}+\beta)\int_{M_{1}\backslash M_{1}^{t}}|\nabla v|^{2}\,dv_{g}+\beta^{-1}\int_{M_{1}\backslash M_{1}^{t}}|\nabla^{2}v|^{2}\,dv_{g}. (3.19)
Proof.

Recall that if x𝕊n+1x\in\mathbb{S}^{n+1} is a signed distance ss from Σ\Sigma, then HΣs(x)=Δd(x)H_{\Sigma^{s}}(x)=-\Delta d(x). By (3.18), we therefore have

M1\M1t|v|2Δ𝑑dvgε~M1\M1t|v|2𝑑vg.\displaystyle-\int_{M_{1}\backslash M_{1}^{t}}|\nabla v|^{2}\Delta d\,dv_{g}\leq\widetilde{\varepsilon}\int_{M_{1}\backslash M_{1}^{t}}|\nabla v|^{2}\,dv_{g}. (3.20)

On the other hand, by the divergence theorem

M1\M1t|v|2Δ𝑑dvg\displaystyle-\int_{M_{1}\backslash M_{1}^{t}}|\nabla v|^{2}\Delta d\,dv_{g} =M1\M1td,|v|2𝑑vgΣΣt|v|2d,ν𝑑Sg,\displaystyle=\int_{M_{1}\backslash M_{1}^{t}}\langle\nabla d,\nabla|\nabla v|^{2}\rangle\,dv_{g}-\int_{\Sigma\cup\Sigma^{t}}|\nabla v|^{2}\langle\nabla d,\nu\rangle\,dS_{g}, (3.21)

where ν\nu is the outward pointing unit normal to the region M1\M1tM_{1}\backslash M_{1}^{t}. By definition of dd, we have d,ν=1\langle\nabla d,\nu\rangle=-1 on Σ\Sigma and d,ν=1\langle\nabla d,\nu\rangle=1 on Σt\Sigma^{t}. Therefore, by (3.21), for any β>0\beta>0 we have

M1\M1t|v|2Δ𝑑dvg\displaystyle-\int_{M_{1}\backslash M_{1}^{t}}|\nabla v|^{2}\Delta d\,dv_{g} 2M1\M1t|v||2v|𝑑vg+Σ|v|2𝑑SgΣt|v|2𝑑Sg\displaystyle\geq-2\int_{M_{1}\backslash M_{1}^{t}}|\nabla v||\nabla^{2}v|\,dv_{g}+\int_{\Sigma}|\nabla v|^{2}\,dS_{g}-\int_{\Sigma^{t}}|\nabla v|^{2}\,dS_{g}
βM1\M1t|v|2𝑑vgβ1M1\M1t|2v|2𝑑vg+Σ|v|2𝑑Sg\displaystyle\geq-\beta\int_{M_{1}\backslash M_{1}^{t}}|\nabla v|^{2}\,dv_{g}-\beta^{-1}\int_{M_{1}\backslash M_{1}^{t}}|\nabla^{2}v|^{2}\,dv_{g}+\int_{\Sigma}|\nabla v|^{2}\,dS_{g}
Σt|v|2𝑑Sg.\displaystyle\qquad-\int_{\Sigma^{t}}|\nabla v|^{2}\,dS_{g}. (3.22)

Substituting (3.3) into (3.20) and rearranging, we arrive at (3.19). ∎

Whilst the desired estimate in Proposition 3.3 involves M1|u|2𝑑vg\int_{M_{1}}|\nabla u|^{2}\,dv_{g} on the LHS, the estimate in Lemma 3.6 (therein taking v=uv=u) involves Σ|u|2𝑑Sg\int_{\Sigma}|\nabla u|^{2}\,dS_{g} on the LHS. These two quantities are related by the following lemma:

Lemma 3.7.

The solution uu to (3.2) satisfies

Σ|u|2𝑑Sg2nM1|u|2𝑑vg.\displaystyle\int_{\Sigma}|\nabla u|^{2}\,dS_{g}\geq\sqrt{2n}\int_{M_{1}}|\nabla u|^{2}\,dv_{g}. (3.23)
Proof.

Integrating by parts, using Δu=0\Delta u=0 in M1M_{1} and the fact that u|ΣL2(Σ)=ΨL2(Σ)=1\|u|_{\Sigma}\|_{L^{2}(\Sigma)}=\|\Psi\|_{L^{2}(\Sigma)}=1, we have

(M1|u|2𝑑vg)2=(Σuνu𝑑Sg)2Σuν2𝑑SgΣu2𝑑Sg=Σuν2𝑑Sg.\displaystyle\bigg{(}\int_{M_{1}}|\nabla u|^{2}\,dv_{g}\bigg{)}^{2}=\bigg{(}\int_{\Sigma}u_{\nu}u\,dS_{g}\bigg{)}^{2}\leq\int_{\Sigma}u_{\nu}^{2}\,dS_{g}\int_{\Sigma}u^{2}\,dS_{g}=\int_{\Sigma}u_{\nu}^{2}\,dS_{g}. (3.24)

On the other hand,

Σuν2𝑑Sg=Σ|u|2𝑑SgΣ|Σu|2𝑑Sg=Σ|u|2𝑑Sgλ1,\displaystyle\int_{\Sigma}u_{\nu}^{2}\,dS_{g}=\int_{\Sigma}|\nabla u|^{2}\,dS_{g}-\int_{\Sigma}|\nabla^{\Sigma}u|^{2}\,dS_{g}=\int_{\Sigma}|\nabla u|^{2}\,dS_{g}-\lambda_{1}, (3.25)

with the second identity in (3.25) following from the variational characterisation of λ1\lambda_{1} and the fact that u|Σ=Ψu|_{\Sigma}=\Psi. Substituting (3.25) into (3.24) and applying Young’s inequality, we obtain

Σ|u|2𝑑Sgλ1+(M1|u|2𝑑vg)22λ11/2M1|u|2𝑑vg.\displaystyle\int_{\Sigma}|\nabla u|^{2}\,dS_{g}\geq\lambda_{1}+\bigg{(}\int_{M_{1}}|\nabla u|^{2}\,dv_{g}\bigg{)}^{2}\geq 2\lambda_{1}^{1/2}\int_{M_{1}}|\nabla u|^{2}\,dv_{g}. (3.26)

The desired estimate (3.23) then follows from (3.26) and the fact that λ1n2\lambda_{1}\geq\frac{n}{2}. ∎

We are now in a position to give the proof of Proposition 3.3:

Proof of Proposition 3.3.

We first take v=uv=u in the estimate (3.19) of Lemma 3.6, where uu is the solution to (3.2). Substituting (3.23) back into (3.19), we therefore arrive at

(2nε~β)=:γM1|u|2𝑑vgΣt|u|2𝑑Sg+β1M1|2u|2𝑑vg.\displaystyle\underbrace{(\sqrt{2n}-\widetilde{\varepsilon}-\beta)}_{=:\gamma}\int_{M_{1}}|\nabla u|^{2}\,dv_{g}\leq\int_{\Sigma^{t}}|\nabla u|^{2}\,dS_{g}+\beta^{-1}\int_{M_{1}}|\nabla^{2}u|^{2}\,dv_{g}. (3.27)

Now recall that we define δ=narctan(εn)\delta=n\arctan(\frac{\varepsilon}{n}). Noting that δx2arctan(εx2)\frac{\delta}{x^{2}}\leq\arctan(\frac{\varepsilon}{x^{2}}) for xnx\geq\sqrt{n}, we see that δΛ2arctan(εΛ2)=Dε\frac{\delta}{\Lambda^{2}}\leq\arctan(\frac{\varepsilon}{\Lambda^{2}})=D_{\varepsilon} for Λn\Lambda\geq\sqrt{n}. In particular, we are justified in integrating both sides of (3.27) with respect to tt over the interval [T,2T][T,2T], where T=δ2Λ2T=\frac{\delta}{2\Lambda^{2}}. This yields (3.6), completing the proof of Proposition 3.3. ∎

3.4. Proof of Proposition 3.4

The proof of Proposition 3.4 is a consequence of two lemmas. The first of these is as follows:

Lemma 3.8.

Let Ω𝕊n+1\Omega\subset\mathbb{S}^{n+1} be a domain and vv a smooth function defined on Ω\Omega satisfying Δv=0\Delta v=0 in Ω\Omega. Then

Δ|v|2=2|2v|2+2n|v|2in Ω.\displaystyle\Delta|\nabla v|^{2}=2|\nabla^{2}v|^{2}+2n|\nabla v|^{2}\quad\text{in }\Omega. (3.28)
Proof.

This is an immediate consequence of the Bochner formula

Δ|w|2=2Δw,w+2|2w|2+2Ricg(w,w)\displaystyle\Delta|\nabla w|^{2}=2\langle\nabla\Delta w,\nabla w\rangle+2|\nabla^{2}w|^{2}+2\operatorname{Ric}_{g}(\nabla w,\nabla w) (3.29)

for a smooth function ww defined on a Riemannian manifold (N,g)(N,g), and the fact that Ricg=ng\operatorname{Ric}_{g}=ng on 𝕊n+1\mathbb{S}^{n+1} equipped with the round metric gg. ∎

For a domain Ω𝕊n+1\Omega\subset\mathbb{S}^{n+1} with smooth boundary, we denote by Ωs\Omega^{s} the set of points in Ω\Omega whose distance to Ω\partial\Omega is greater than ss. We now use Lemma 3.8 to show:

Lemma 3.9.

Let Ω𝕊n+1\Omega\subset\mathbb{S}^{n+1} be a domain with smooth boundary Ω\partial\Omega, and vv a smooth function defined on Ω\Omega satisfying Δv=0\Delta v=0 in Ω\Omega. Suppose that t>0t>0 is sufficiently small so that (Ω2t)\partial(\Omega^{2t}) is a smooth embedded hypersurface in 𝕊n+1\mathbb{S}^{n+1}. Then

Ω2t|v|2𝑑vg1n1t2Ω|2v|2𝑑vg.\displaystyle\int_{\Omega^{2t}}|\nabla v|^{2}\,dv_{g}\leq\frac{1}{n-1}t^{-2}\int_{\Omega}|\nabla^{2}v|^{2}\,dv_{g}. (3.30)
Proof.

Let ζCc(Ω)\zeta\in C_{c}^{\infty}(\Omega) be a cutoff function whose properties will be specified later in the proof. Multiplying the inequality (3.28) by ζ2\zeta^{2} and integrating over Ω\Omega, we see

Ωζ2(n|v|2+|2v|2)𝑑vg\displaystyle\int_{\Omega}\zeta^{2}(n|\nabla v|^{2}+|\nabla^{2}v|^{2})\,dv_{g} =12Ωζ2Δ|v|2𝑑vg\displaystyle=\frac{1}{2}\int_{\Omega}\zeta^{2}\Delta|\nabla v|^{2}\,dv_{g}
=Ωζζ,|v|2𝑑vg\displaystyle=-\int_{\Omega}\zeta\langle\nabla\zeta,\nabla|\nabla v|^{2}\rangle\,dv_{g}
=2Ωζ2v(v,ζ)𝑑vg\displaystyle=-2\int_{\Omega}\zeta\nabla^{2}v(\nabla v,\nabla\zeta)\,dv_{g}
Ωζ2|v|2𝑑vg+Ω|ζ|2|2v|2𝑑vg.\displaystyle\leq\int_{\Omega}\zeta^{2}|\nabla v|^{2}\,dv_{g}+\int_{\Omega}|\nabla\zeta|^{2}|\nabla^{2}v|^{2}\,dv_{g}. (3.31)

Therefore

0\displaystyle 0 (n1)Ωζ2|v|2𝑑vg+Ω(ζ2|ζ|2)|2v|2𝑑vg\displaystyle\geq(n-1)\int_{\Omega}\zeta^{2}|\nabla v|^{2}\,dv_{g}+\int_{\Omega}(\zeta^{2}-|\nabla\zeta|^{2})|\nabla^{2}v|^{2}\,dv_{g}
(n1)Ωζ2|v|2𝑑vgΩ|ζ|2|2v|2𝑑vg,\displaystyle\geq(n-1)\int_{\Omega}\zeta^{2}|\nabla v|^{2}\,dv_{g}-\int_{\Omega}|\nabla\zeta|^{2}|\nabla^{2}v|^{2}\,dv_{g}, (3.32)

which yields

Ωζ2|v|2𝑑vg1n1Ω|ζ|2|2v|2𝑑vg.\displaystyle\int_{\Omega}\zeta^{2}|\nabla v|^{2}\,dv_{g}\leq\frac{1}{n-1}\int_{\Omega}|\nabla\zeta|^{2}|\nabla^{2}v|^{2}\,dv_{g}. (3.33)

Now, for each ε>0\varepsilon>0, one can choose a smooth cutoff function ζ\zeta such that ζ0\zeta\equiv 0 in Ω\Ωt\Omega\backslash\Omega^{t}, ζ1\zeta\equiv 1 in Ω2t\Omega^{2t} and |ζ|(1+ε)t1|\nabla\zeta|\leq(1+\varepsilon)t^{-1}. Thus (3.33) implies

Ω2t|v|2𝑑vg(1+ε)2n1t2Ω|2v|2𝑑vg,\displaystyle\int_{\Omega^{2t}}|\nabla v|^{2}\,dv_{g}\leq\frac{(1+\varepsilon)^{2}}{n-1}t^{-2}\int_{\Omega}|\nabla^{2}v|^{2}\,dv_{g}, (3.34)

and the estimate (3.30) then follows after taking ε0\varepsilon\rightarrow 0 in (3.34). ∎

Proof of Proposition 3.4.

In the statement of Lemma 3.9, let Ω=M1\Omega=M_{1} and let v=uv=u, where uu is the solution to (3.2). Following the reasoning given in the proof Proposition 3.3, we are then justified in taking t=T/2t=T/2 in Lemma 3.9, where T=δ2Λ2T=\frac{\delta}{2\Lambda^{2}} as before. The desired estimate (3.7) then follows. ∎

Having established Propositions 3.3 and 3.4, the proof of Theorem 1.1 is complete, as explained in Section 3.2.

Acknowledgements

YS is partially supported by NSF DMS grant 21542192154219, “Regularity vs singularity formation in elliptic and parabolic equations”.

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