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Analytic models for active shooter incidents with civilian resistance

Liang Hong111Liang Hong is a Professor in the Department of Mathematical Sciences, The University of Texas at Dallas, 800 West Campbell Road, Richardson, TX 75080, USA. Tel.: 972-883-2161. Email address: liang.hong@utdallas.edu.
Abstract

The number of active shooter incidents in the US has been increasing alarmingly. It is imperative for the government as well as the public to understand these events. Though both analytic and agent-based models have been proposed for studying active shooter incidents, there are only a few analytic models in the literature, and none incorporate civilian resistance. This article analytically investigates the survival probability of a civilian during an active shooter incident when he can hide, fight, or run, depending on whether or not he is in a closed arena and whether or not he is armed. The key findings are (i) the civilian’s chance of survival decreases over time, irrespective of his action; (ii) there are desperate situations in which a civilian should fight back even if he is unarmed; (iii) carrying a firearm does not always increase the civilian’s chance of survival during an active shooter incident; (iv) carrying a firearm makes “resistance” more likely to be the optimal action of the civilian; (v) “hide” might be the best action even if the civilian is armed; (vi) more armed civilians might increase a civilian’s chance of survival, but it is not always the case.

Keywords and phrases: Analytic model; armed resistance; domestic terrorism; mass shooting; optimal action; probability of survival.

1 Introduction

The active shooter incident has become a regular event in our society. It has happened in all kinds of public places, such as churches, schools, supermarkets, theaters, and shopping malls, just to name a few. The FBI defines an active shooter as one or more individuals actively engaged in killing or attempting to kill people in a populated area (e.g., FBI 2024). The rate of active shooter incidents in the US has been increasing at an alarming rate in the past two decades (e.g., FBI 2016, 2019, 2023, 2024; Soni and Tekin 2020, The Violence Project 2020, Wiki 2023). These violent events lead to the deaths of multiple victims, cause lasting trauma to survivors, and instill fear in other people. Multiple government agencies, including the Department of Homeland Security, the Department of Justice, the FBI, and many local police departments, have been working tirelessly to find better ways to prevent and respond to active shooter incidents. In academia, scholars have been studying active shooter incidents for years. In terms of research goals, the literature primarily focuses on identifying key factors in mass shooting events, such as access to weapons, domestic violence, legislation, police response, shooter profile, etc; see, for instance, Gius (2015), Blum and Jaworski (2017), Cabrera and Kwon (2018), Kwon and Cabrera (2019), Silva and Greene-Colozzi (2021), Fridel (2021), Geller et al. (2021). As far as research methods are concerned, some authors rely on quantitative studies; see, for example, Lee (2013), Kingshott and McKenzie (2013), Lemieux (2014), Metzl and MaclEish (2015), Dong (2019), Ihatsu et al. (2022). In particular, Lemieux (2014) used cross-section analysis to argue that both gun culture and firearm laws have significant impacts on deaths by guns. Dong (2019) applied qualitative content analysis to find evidence that depictions of firearms in mass media coverage of mass shootings generally constituted firearms characteristics that produced feelings of fear in the intended audience. Ihatsu et al. (2022) performed an inductive content analysis on several police pre-trial investigation records and reports by the investigation commission to determine attributes of violence resembling terrorism by approaching the subject from the position of first responders.

However, most articles on active mass shootings seem to be based on quantitative studies and employ some types of quantitative models. There are three major kinds of quantitative models in the literature. The first kind is a statistical model. Usually, such a statistical model is fitted using real-world data to gain insight into active shooter incidents. For example, Lankford (2016) applied analysis of variance to empirically demonstrate that fame-seeking rampage shooters have existed for decades and have become more common in recent years and that these offenders tend to kill and wound significantly more victims. Lee et al. (2018) used a Bayesian Poisson regression model to study the casualty rate during an active shooter event with three parameters: civilian evacuation time, the response of police, and firearm discharge by the shooter and police. They found that immediate evacuation would decrease the casualty rate, and so would the rapid and well-directed deployment of first responders with high-precision discharge abilities. Lei and MacKenzie (2024) proposed a hierarchical model to quantify the risk of mass shootings at specific locations. Cao et al. (2024) applied regression analysis to develop a model of mass shooting severity; their studies suggested that factors, such as having more firepower at the shooting scenes, lack of employment, being married, and having more mental health issues, all increase casualties in mass shootings.

The second kind is an agent-based simulation model. This seems to be the dominating model in the literature. For example, Hayes et al. (2014) applied an agent-based simulation model to study the potential effectiveness of banning assault weapons and high-capacity magazines. According to their results, banning assault weapons will not affect the number of people killed or wounded in a mass shooting; however, a ban on high-capacity magazines will result in a small reduction in the number of deaths during a mass shooting. Anklam et al. (2015) used an agent-based simulation model to find that a decrease in the authority’s response time leads to reduced victim casualties. Gunn et al. (2017) proposed a solution to optimizing guidance delivery for active shooter events. Steward (2017) employed an agent-based simulation model to study how enforcement response time, civilian response strategy, and cognitive delay of the civilians might affect the expected number of casualties in a classroom shooting. She found that a slower police response time and having all civilians hide can increase the expected number of civilian casualties. Glass et al. (2018) proposed an agent-based simulation model to investigate the means of mitigating the risk of a single active shooter incident within a large event venue by increasing the number of armed off duty law enforcement officers available to respond to the incident. Their results show a negative logarithmic relationship between the number of civilians shot and the number of off-duty law enforcement officers available. Lu et al. (2023) proposed an agent-based model that incorporates both the killing force and counterforce; their model suggested that there is an optimal response time for the police to minimize civilian casualties.

The third kind is an analytic model. There is a paucity of analytic models in the literature. One exception is Sporrer (2020), who applied several analytic models to study active shooter events in different types of arenas: closed, open, and complex. So far no analytic models have accounted for civilian resistance. The purpose of this article is to investigate the survival probability of a civilian during an active shooter event when the civilian can fight, hide, or run, depending on whether or not the civilian is in a closed arena and whether or not the civilian is armed. Similar to Sporrer (2020), we will study active shooter incidents for the aforementioned three kinds of arenas. Different from Sporrer (2020) and other previous authors who focused on the expected number of civilian casualties, we are mainly interested in the best action of a civilian that maximizes his probability of survival and we allow “fight” as a possible action. We consider the case of a single armed civilian and the case of multiple armed civilians for each type of arena. To preview the key results, the following findings will be established across different scenarios:

  1. (i)

    A civilian’s chance of survival decreases over time regardless of the action he chooses.

  2. (ii)

    There are some desperate situations in which a civilian, armed or not, should fight back. This confirms the prediction made in Section 5.2 of Sporrer (2020).

  3. (iii)

    Carrying a firearm might increase a civilian’s chance of survival in some cases. However, carrying a firearm does not necessarily increase a civilian’s chance of survival in every case.

  4. (iv)

    Everything else being equal, carrying a firearm makes “resistance” more likely to be the best action of a civilian.

  5. (v)

    There are some circumstances where “hide” is the best option even if a civilian is armed and the authority cannot arrive quickly.

  6. (vi)

    A civilian’s chance of survival is not necessarily an increasing function of the number of armed civilians. Indeed, when the number of armed civilians exceeds a threshold, a civilian’s chance of survival will decrease due to the increased likelihood of “friendly fire”.

These findings can be applied by a variety of audiences. For example, law enforcement agencies can learn from (i) that a quick response to an active shooter incident is critical. Parents who are looking for schools for their children can also gain insight from (i): the distance between the school and the nearest police station is an important variable to consider especially when a school is located in a rural area. For another example, (v) dispels the misconception in some folks’ minds that they should always fight back during an active shooter incident if they are armed.

Finally, a remark on the choice of our terminology “Fight/Hide/Run”. This is similar to the term “Avoid/Barricade/Counter” used in the ABC active shooter training at many workplaces, except that the former is slightly more general than the latter. If the arena is closed (e.g., a school or office building), they are the same. However, if the arena is open like a theater or concert hall, “hide” will be a more appropriate term than “barricade”.

The remainder of this article is organized as follows. In Section 2, we study the case where there is only one possibly armed civilian. We will derive the survival probabilities of a civilian over time and use them to decide the optimal action of a civilian. Next, in Section 3, we investigate the case where there are multiple possibly armed civilians. Finally, we conclude the article with some remarks in Section 4.

2 One possibly armed civilian

In this section, we assume there is one civilian of focus who may or may not be armed. No other civilians might fight back. In addition, the following common assumptions are taken throughout this section.

  1. (a)

    There is only one active shooter. He shoots indiscriminately into the crowd unless he meets resistance. He will always kill those who fight first if he meets resistance.

  2. (b)

    The authority will arrive in T2T_{2} minutes, where T2T_{2} is a positive integer. When the authority arrives, the shooter will kill himself or surrender himself to the authority; otherwise, the authority will neutralize the shooter immediately.

  3. (c)

    All civilians are rational decision-makers. They make their decisions without collaborating with others. Each of them wants to maximize their own chance of survival.

  4. (d)

    At the beginning of each minute, a civilian makes his decision for his action during that minute and sticks to it until the beginning of the next minute.

  5. (e)

    All civilians will be hit by the shooter with equal probabilities.

  6. (f)

    A bullet strikes at most one person. That is, there are no secondary casualties.

2.1 Closed arena

Similar to Sporrer (2020), a closed arena is understood to be an area that does not offer people the opportunity to exit. A typical example is a classroom during a campus shooting. When such an event occurs, the civilian of focus can find himself either already in a closed arena or in the hallway where one can quickly enter a closed arena. Let us first examine the case where a civilian is already in the closed arena.

2.1.1 Already in the closed arena

This is the situation where a student or teacher finds himself in a classroom when a campus shooting occurs. In this case, we also assume the following:

  1. (i)

    There are NN civilians in the closed arena, where NN is a positive integer. The active shooter is not considered as a civilian.

  2. (ii)

    The shooter is already at the only door of the closed arena. There is no other place to exit the room. Therefore, the civilian of focus can either fight or hide. A civilian who does not fight will be killed by the shooter with equal probability. The shooter will walk around until every civilian is dead.

  3. (iii)

    The shooter is equipped with a rifle, and his killing rate is mm people per minute where mm is a positive integer and N=T1mN=T_{1}m for some positive integer T1T_{1}. He carries plenty of magazines that are far more than enough to kill all the NN civilians. His rifle will not malfunction during the shooting. He plans to kill as many civilians as possible.

  4. (iv)

    If an unarmed civilian fights back, his chance of success will be p1p_{1}. If an armed civilian fights back, his probability of success will be p2p_{2}, where p2>p1>0p_{2}>p_{1}>0.

To avoid repetitions in our presentation, we will use pp to denote the survival probability of the civilian of focus, where p=p1p=p_{1} if he is unarmed and p=p2p=p_{2} if he is armed.

It is clear from our Assumption (iii) that T1T_{1} is the number of minutes the shooter needs to kill all the civilians in the arena. Thus, T1T_{1} plays a vital role in our analysis. In particular, we need to consider two cases: (I) T1>T2T_{1}>T_{2} and (II) T1T2T_{1}\leq T_{2}. When T1>T2T_{1}>T_{2}, the authority will arrive before the shooter can kill all the civilians in the arena; hence, every civilian should stand a nonzero chance of survival anytime. However, if T1T2T_{1}\leq T_{2}, the shooter will murder all the civilians before the authority arrives; as a result, the chance of survival of each civilian should be zero after T1T_{1} minutes. Our analysis below confirms this intuition.

Case I: T1>T2T_{1}>T_{2}

For the first minute, if the civilian fights, his survival probability will be pp; if he hides, his chance of survival will be (1m/N)(1-m/N). For the latter probability, note that the shooter will kill mm civilians in the first minute and each of the NN civilians is equally likely to be among these mm unfortunate victims. It follows that the civilian’s chance of being killed during the first minute is (N1m1)/(Nm)=m/N{N-1\choose m-1}/{N\choose m}=m/N, implying the chance of survival is (1m/N)(1-m/N). Note that if the civilian fights, he will either end the shooting or get himself killed right away. However, if he hides, he may still choose to fight or hide in the next minute provided he has survived the previous minute. Therefore, if the civilian fights during the second minute, his chance of survival equals

P(succeed in fighting back)×P{survived the first minute}=p(1mN).P(\text{succeed in fighting back})\times P\{\text{survived the first minute}\}=p\left(1-\frac{m}{N}\right). (1)

But if he decides to hide again during the second minute, his survival probability is

P(survive the second minute  survived the first minute)×P{survived the first minute}\displaystyle P(\text{survive the second minute $\mid$ survived the first minute})\times P\{\text{survived the first minute}\} (2)
=\displaystyle= [(Nm)mNm](1mN)=12mN.\displaystyle\left[\frac{(N-m)-m}{N-m}\right]\left(1-\frac{m}{N}\right)=1-\frac{2m}{N}.

Following the same line of reasoning, we can derive the civilian’s survival probabilities at other times up to T2T_{2} minutes. After T2T_{2} minutes, the authority arrives. Thus, the civilian is surely to live regardless of his action, provided he has survived the previous T2T_{2} minutes. That is, the conditional probability of survival given that the civilian has survived the first T2T_{2} minutes is 11. Therefore, the survival probability of the civilian beyond T2T_{2} minutes is

P(survived the first T2 minutes)×1=(NT2mN)×1=1T2mN,P(\text{survived the first $T_{2}$ minutes})\times 1=\left(\frac{N-T_{2}m}{N}\right)\times 1=1-\frac{T_{2}m}{N}, (3)

where 11 stands for the civilian’s conditional probability of survival given that he has survived the first T2T_{2} minutes.

minute 11 22 \ldots T2T_{2} T2+1T_{2}+1 \ldots T1T_{1}
fight pp p(1mN)p\left(1-\frac{m}{N}\right) \ldots p[1(T21)mN]p\left[1-\frac{(T_{2}-1)m}{N}\right] 1T2mN1-\frac{T_{2}m}{N} \ldots 1T2mN1-\frac{T_{2}m}{N}
hide 1mN1-\frac{m}{N} 12mN1-\frac{2m}{N} \ldots 1T2mN1-\frac{T_{2}m}{N} 1T2mN1-\frac{T_{2}m}{N} \ldots 1T2mN1-\frac{T_{2}m}{N}
Table 1: Survival probabilities of the civilian of focus in a closed arena when T1>T2T_{1}>T_{2}, where the ii-th cell of the “fight” row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back at the beginning of the ii-th minute.

Table 1 provides the civilian’s survival probabilities over time, where the ii-th cell of the “fight” row is his survival probability when he hides for the first (i1)(i-1)-th minutes and starts to fight back at the beginning of the ii-th minute. Table 1 offers some insight into civilian resistance during an active shooter incident. First, if the civilian decides to hide, his chance of survival decreases over time until the authority arrives. The same can be said for the civilian if he plans to fight back. Since N=T1mN=T_{1}m and T2<T1T_{2}<T_{1}, we know that 1T2/m>01-T_{2}/m>0. That is, if the authority is able to arrive quickly, a civilian will have a positive chance of survival if he decides to hide. This means the authority response time is critical in an active shooter event. For parents who are considering new schools for their children, they might want to take this into consideration. Everything else being equal, a school that is close to a police station or staffed with an armed guard should be chosen over the one that is not. Also, some schools in rural areas are usually far away from the authority, they should consider adding an armed guard if they do not have one yet.

Next, if p>(1m/N)p>(1-m/N), then the civilian should fight back at the inception of the shooting. More generally, if p[1(k1)m/N]>(1km/N)p[1-(k-1)m/N]>(1-km/N) for some 1kT21\leq k\leq T_{2} but p[1(j1)m/N]<(1jm/N)p[1-(j-1)m/N]<(1-jm/N) for 1jk11\leq j\leq k-1, then a civilian should fight back during the kk-th minute; otherwise, “hide” will be a better option. For an unarmed civilian (i.e., p=p1p=p_{1}), this analytically confirms the prediction made in Sporrer (2020) that there are some desperate situations where the best option of an unarmed civilian is to fight the shooter. This shows that hiding is not always the only rational option for an unarmed civilian. On the other hand, if p[1(k1)m/N]<(1km/N)p[1-(k-1)m/N]<(1-km/N) for all 1kT21\leq k\leq T_{2}, or, equivalently, p<[Nkm]/[N(k1)m]=1m/[N(k1)m]p<[N-km]/[N-(k-1)m]=1-m/[N-(k-1)m] for all 1kT21\leq k\leq T_{2}, then a civilian should hide all the way through. Note that 1m/[N(k1)m]1-m/[N-(k-1)m] is decreasing in kk; therefore, the condition p<1m/[N(k1)m]p<1-m/[N-(k-1)m] for all 1kT21\leq k\leq T_{2} is equivalent to the condition p<1m/(Nm)p<1-m/(N-m).

Moreover, if p2>1m/[N(k1)m]p_{2}>1-m/[N-(k-1)m] for some 1kT21\leq k\leq T_{2}, then p2>max{p1,1m/[N(k1)m]}p_{2}>\max\{p_{1},1-m/[N-(k-1)m]\}, showing that carrying a firearm may increase a civilian’s chance of survival in some cases. However, carrying a firearm does not always increase one’s chance of survival. For example, if p2<1m/[N(k1)m]p_{2}<1-m/[N-(k-1)m] for all 1kT21\leq k\leq T_{2}, then a civilian would better hide throughout even if he is armed.

Finally, it is possible that p2>1m/[N(k1)m]p_{2}>1-m/[N-(k-1)m] but p1<1m/[N(k1)m]p_{1}<1-m/[N-(k-1)m] for some 1kT21\leq k\leq T_{2}. In this case, carrying a firearm increases the odds that “fight” is the best option.

Case II: T1T2T_{1}\leq T_{2}

By similar analysis as in the case where T1>T2T_{1}>T_{2}, we can obtain the civilian’s survival probabilities over time that are given by Table 2.

minute 11 22 \ldots T1T_{1}-1 T1T_{1} T1+1T_{1}+1 \ldots T2T_{2}
fight pp p(1mN)p\left(1-\frac{m}{N}\right) \ldots p[1(T12)mN]p\left[1-\frac{(T_{1}-2)m}{N}\right] p[1(T11)mN]p\left[1-\frac{(T_{1}-1)m}{N}\right] 0 \ldots 0
hide 1mN1-\frac{m}{N} 12mN1-\frac{2m}{N} \ldots 1(T11)mN1-\frac{(T_{1}-1)m}{N} 0 0 \ldots 0
Table 2: Survival probabilities of the civilian of focus in a closed arena when T1T2T_{1}\leq T_{2}, where the ii-th cell of the “fight” row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back at the beginning of the ii-th minute.

A few remarks in order. First, if the civilian wants to hide and wait for the authority, his chance of survival will decrease over time and become zero before the authority arrives. The same can be said for the civilian if he plans to fight back. That is, if the authority is unable to arrive quickly (e.g., a campus shooting in a rural area), the civilian will stand no chance of surviving in a closed arena shooting after a certain time point, regardless of whether he decides to hide and wait for the authority.

Second, if p>(1m/N)p>(1-m/N), then a civilian should fight back right away. More generally, if p[1(k1)m/N]>(1km/N)p[1-(k-1)m/N]>(1-km/N) for some 1kT11\leq k\leq T_{1} but p[1(j1)m/N]<(1jm/N)p[1-(j-1)m/N]<(1-jm/N) for all 1jk11\leq j\leq k-1, then a civilian should fight back during the kk-th minute; otherwise, he had better to hide. Again, the aforementioned prediction made in Sporrer (2020) is confirmed here analytically. It is worth underlining that even if p[1(k1)m/N]<(1km/N)p[1-(k-1)m/N]<(1-km/N) for all 1kT111\leq k\leq T_{1}-1, or, equivalently, p<1m/[N(k1)m]p<1-m/[N-(k-1)m] for all 1kT111\leq k\leq T_{1}-1, the civilian should fight in the T1T_{1}-th minute because his chance of survival is zero if he hides during the T1T_{1}-th minute.

We see again that, if p2>1m/[N(k1)m]=max{p1,1m/[N(k1)m]}p_{2}>1-m/[N-(k-1)m]=\max\{p_{1},1-m/[N-(k-1)m]\} for some 1kT21\leq k\leq T_{2}, then carrying a firearm will increase a civilian’s chance of survival. Once again, this does not imply that carrying a firearm will necessarily increase one’s chance of survival because it is possible that p2<1m/[N(k1)m]p_{2}<1-m/[N-(k-1)m] for all 1kT11\leq k\leq T_{1}. Hence, an armed civilian should not always choose to fight. If p2>1m/[N(k1)m]p_{2}>1-m/[N-(k-1)m] but p1<1m/[N(k1)m]p_{1}<1-m/[N-(k-1)m] for some 1kT11\leq k\leq T_{1}, then carrying a firearm will increase the chance of civilian resistance when everything else being equal.

2.1.2 Hallway interaction

A typical example of this is when a student or teacher finds himself in the hallway when a campus shooting happens. Besides the common assumptions in Section 2, we also assume the following:

  1. (1)

    There are MM civilians in the hallway, where MM is a positive integer.

  2. (2)

    There are KK separate closed arenas close to each civilian. The shooter will search these KK closed arenas one by one to look for his victims. The shooter will not re-enter a closed arena he has searched. Once the shooter enters a closed arena, he will not move to another closed arena until he kills all civilians in the current arena.

  3. (3)

    Each civilian can either run or hide in one of the KK closed arenas. In addition, the civilian of focus can also fight.

  4. (4)

    If an unarmed civilian fights, his chance of success will be p~1\tilde{p}_{1}. If an armed civilian fights back, his probability of success will be p~2\tilde{p}_{2}, where p~2>p~1>0\tilde{p}_{2}>\tilde{p}_{1}>0. Note that p~1\tilde{p}_{1} may or may not equal to p1p_{1}. Similarly, p~2\tilde{p}_{2} may or may not equal to p2p_{2}. We will use p~\tilde{p} to denote the survival probability of a civilian, where p~=p~1\tilde{p}=\tilde{p}_{1} if he is unarmed and p~=p~2\tilde{p}=\tilde{p}_{2} if he is armed.

  5. (5)

    If a civilian runs, he can safely exit the area with a probability of pr>0p_{r}>0.

  6. (6)

    If a civilian decides to hide in one of the KK nearby closed arenas, he will succeed with a probability ph>0p_{h}>0.

  7. (7)

    The hallway interaction ends within a minute.

  8. (8)

    The authority will not arrive during hallway interaction.

  9. (9)

    There will be NN civilians in each of the KK closed arenas once the hallway interaction ends, where N<M/KN<M/K.

The decision of the civilian of focus during hallway interaction (i.e., the first minute) is easy. If ph>max{pr,p~}p_{h}>\max\{p_{r},\tilde{p}\}, then he should hide into a closed arena; if pr>max{ph,p~}p_{r}>\max\{p_{h},\tilde{p}\}, then he should run; if p~>max{pr,ph}\tilde{p}>\max\{p_{r},p_{h}\}, then he should fight back.

At the beginning of the second minute, the shooter may enter the closed arena where the civilian of focus is hiding with a probability 1/K1/K. If this happens, then the results in Section 2.1.1 will apply from the second minute to the max{T1+1,T2+1}\max\{T_{1}+1,T_{2}+1\}-th minute. However, if the shooter enters an arena other than where the civilian of focus is hiding at the beginning of the second minute, which happens with a probability 1/K21-/K^{2}, then the civilian of focus will hide from the second minute until the (T1+1)(T_{1}+1)-th minute. In this case, if T2T1+1T_{2}\leq T_{1}+1, the civilian of focus will surely survive. However, if T2>T1+1T_{2}>T_{1}+1, then at the beginning of the (T1+2)(T_{1}+2)-th minute we will be in the same situation as the one we face at the beginning of the second minute, except now KK is being replaced by K1K-1. Then, the shooter might enter the arena where the civilian is hiding with a probability 1/(K1)1/(K-1), in which case the results in Section 2.1.1 will apply again from the (T1+2)(T_{1}+2)-th minute until the max{2T1+1,T1+T2+1}\max\{2T_{1}+1,T_{1}+T_{2}+1\}-th minute. The analysis for the rest of the time until the (KT1+1)(KT_{1}+1)-th minute is similar. The larger KK is, the longer the whole event will last and hence the more likely the civilian of focus will have a nonzero chance of survival as time passes.

2.2 Open arena

By an open area, we mean an area that allows people to exit in an unconstrained manner. A typical example is an outdoor area for a festival. Besides the common assumptions in Section 2, we make the following assumptions:

  1. (1)

    There are NN civilians in the open arena, where NN is a positive integer.

  2. (2)

    The shooter is equipped with a rifle, and his killing rate is mm people per minute, where mm is a positive integer. The shooter carries plenty of magazines that are far more than enough to kill all the NN civilians. His rifle will not malfunction during the shooting. He plans to kill as many civilians as possible.

  3. (3)

    The crowd exits the open arena at a rate of ee people per minute, where ee is a positive integer and e<Nme<N-m. For each minute, none of the ee civilians who exit the arena is among the mm civilians who are killed during that minute.

  4. (4)

    There is a positive integer T1T_{1} such that N=T1(e+m)N=T_{1}(e+m) for some positive integer T1T_{1}.

  5. (5)

    Every civilian can hide or run. In addition, the civilian of focus can also fight. The shooter will hit anyone who does not fight with equal probability.

  6. (6)

    If the civilian of focus runs, he can safely exit the arena in a minute with a probability pr>0p_{r}>0. That is, with a probability prp_{r}, he will be one of the ee civilians who can safely exit the arena.

  7. (7)

    If an unarmed civilian fights, his chance of success will be p1p_{1}. If an armed civilian fights back, his probability of success will be p2p_{2}, where p2>p1>0p_{2}>p_{1}>0. We still use pp to denote the survival probability of a civilian when he fights back, where p=p1p=p_{1} if he is unarmed and p=p2p=p_{2} if he is armed.

2.2.1 Case I: T1>T2T_{1}>T_{2}

In this case, the incident will not last beyond time T2T_{2}. Note that if a civilian chooses to run, he can either exit the area or get killed in a minute. If he fights back, he will either subdue the shooter with a probability pp or get killed immediately. But if he hides, he can still choose to fight, hide, or run in the next minute. Employing a similar argument as in Section 2.1.1, we can obtain the survival probabilities of the civilian of focus over time. These probabilities are summarized in . For example, the civilian is still in the area at the beginning of the second minute if and only if he chooses to hide in the first minute. This happens with a probability 1m/(Ne)1-m/(N-e) because, according to our assumption, none of the ee civilian who exit the open arena is shot during the first minute. It follows that there are N(m+e)N-(m+e) civilians left in the arena at the end of the first minute. If he chooses to hide again at the beginning of the second minute, then his chance of surviving during the second minute would be

(1mNe)[1mN(e+m)e]=k=12[1m(Ne)(k1)(e+m)].\left(1-\frac{m}{N-e}\right)\left[1-\frac{m}{N-(e+m)-e}\right]=\prod_{k=1}^{2}\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right]. (4)
minute 11 22 \ldots T2T_{2}
fight pp p(1mNe)p\left(1-\frac{m}{N-e}\right) \ldots pk=1T21[1m(Ne)(k1)(e+m)]p\prod_{k=1}^{T_{2}-1}\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right]
hide 1mNe1-\frac{m}{N-e} k=12[1m(Ne)(k1)(e+m)]\prod_{k=1}^{2}\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right] \ldots k=1T2[1m(Ne)(k1)(e+m)]\prod_{k=1}^{T_{2}}\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right]
run prp_{r} pr(1mNe)p_{r}\left(1-\frac{m}{N-e}\right) \ldots prk=1T21[1m(Ne)(k1)(e+m)]p_{r}\prod_{k=1}^{T_{2}-1}\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right]
Table 3: Survival probabilities of the civilian of focus in an open arena when T1>T2T_{1}>T_{2}, where the ii-th cell of the “fight” (respectively “run”) row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back (respectively “run”) at the beginning of the ii-th minute.

Note that the assumptions on e,me,m, and NN imply that all probabilities in Table 3 are positive. Based on Table 3, we can make almost the same observations as for the case T1>T2T_{1}>T_{2} in Section 2.1.1. For the sake of brevity, they will not be repeated here. The same will be done for the remainder of the paper unless new insight arises. Readers will see that Observations (i)–(vi) at the end of Section 1 will hold in all cases.

2.2.2 Case II: T1T2T_{1}\leq T_{2}

In this case, the event will end at time T1T_{1} if not before. Similar to the case where T1>T2T_{1}>T_{2}, we can obtain the survival probabilities of the civilian over time; see Table 4.

minute 11 22 \ldots T11T_{1}-1 T1T_{1} T1+1T_{1}+1 \ldots T2T_{2}
fight pp pA1pA_{1} \ldots pk=1T12Akp\prod_{k=1}^{T_{1}-2}A_{k} pk=1T11Akp\prod_{k=1}^{T_{1}-1}A_{k} 0 \ldots 0
hide A1A_{1} k=12Ak\prod_{k=1}^{2}A_{k} \ldots k=1T11Ak\prod_{k=1}^{T_{1}-1}A_{k} 0 0 \ldots 0
run prp_{r} prA1p_{r}A_{1} \ldots prk=1T12Akp_{r}\prod_{k=1}^{T_{1}-2}A_{k} prk=1T11Akp_{r}\prod_{k=1}^{T_{1}-1}A_{k} 0 \ldots 0
Table 4: Survival probabilities of the civilian of focus in an open arena when T1T2T_{1}\leq T_{2}, where Ak=[1m(Ne)(k1)(e+m)]A_{k}=\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right] and the ii-th cell of the “fight” (respectively “run”) row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back (respectively “run”) at the beginning of the ii-th minute.

Similar to the case where T1>T2T_{1}>T_{2}, it is easy to see that all probabilities in Table 4 are positive. In addition, all survival probabilities after the (T11)(T_{1}-1)-th minute in the “hide” row are zeros because N=T1(e+m)N=T_{1}(e+m), i.e., all civilians will have either exited the arena or been killed at the end of the T1T_{1}-th minute. Again, we can make almost the same observations as in Section 2.1.2. For example, if the civilian of focus chooses to hide during the first T11T_{1}-1 minutes, then he should either fight back or run during the T1T_{1}-th minute.

2.3 Complex arena

Following Sporrer (2020), we take a complex arena to be an area that allows people to escape through only a finite number of exits. Most mass shootings in a theater or shopping mall fall into this category. Similar to Sporrer (2020), let us partition the process of such an incident into three phases:

  1. Phase 0: initiation,

  2. Phase 11: maximum capacity,

  3. Phase 22: seek and shoot.

Phase 0 is the first few moments after the shooting starts. Civilians during Phase 0 often fail to recognize what is going on due to confusion; hence, they do not fight, hide, or run. Phase 11 is the time interval during which civilians realize the nature of the incident and many of them rush to escape the arena through the few exits. People cannot exit the arena freely during Phase 11 because the highest exit rate of each exit is reached. Phase 22 is the last stage of the incident when the density of evacuees is low enough to allow them to exit the arena freely. Since the majority of civilians will have either exited the arena or been killed, the shooter needs to seek out potential targets during Phase 22. Thus, his killing rate drops during Phase 22.

Besides the common assumptions in Section 2, let us also take the following assumptions:

  1. (1)

    There are NN civilians in the complex arena, where NN is a positive integer.

  2. (2)

    Due to confusion, no one fights, hides, or runs during Phase 0.

  3. (3)

    The shooter will kill NN1N-N_{1} people during Phase 0, where N1N_{1} is a positive integer such that N>N1N>N_{1}. His killing rates during Phase 1 and Phase 2 are m1m_{1} people per minute and m2m_{2} people per minute respectively, where m1m_{1} and m2m_{2} are positive integers and m1>m2m_{1}>m_{2}. The shooter is equipped with a rifle and plenty of magazines that are far more than enough to kill all the NN civilians.

  4. (4)

    Those who decide to hide during Phase 1 will not fight or run during that phase.

  5. (5)

    Phase 1 lasts nn minutes. The crowd exits the arena at a rate of e1e_{1} people per minute during Phase 1, where e1e_{1} is a positive integer. During each minute of Phase 1, none of the e1e_{1} civilians who exit the arena is killed.

  6. (6)

    If an unarmed civilian fights back during Phase 1, his chance of success will be p~1\tilde{p}_{1}. If an armed civilian fights back during Phase 1, his probability of success will be p~2\tilde{p}_{2} where p~2>p~1>0\tilde{p}_{2}>\tilde{p}_{1}>0. We will use p~\tilde{p} to denote the survival probability of a civilian where p~=p~1\tilde{p}=\tilde{p}_{1} if he is unarmed and p~=p~2\tilde{p}=\tilde{p}_{2} if he is armed.

  7. (7)

    The crowd exits the area at rate of e2e_{2} people per minute during Phase 2, where e2e_{2} is a positive integer. For each minute of Phase 2, none of the e2e_{2} civilians who exit the arena is killed.

  8. (8)

    If an unarmed civilian fights back during Phase 2, his chance of success will be p1p_{1}. If an armed civilian fights back during Phase 2, his probability of success will be p2p_{2} where p2>p1>0p_{2}>p_{1}>0. We will use pp to denote the survival probability of a civilian who fights back, where p=p1p=p_{1} if he is unarmed and p=p2p=p_{2} if he is armed.

  9. (9)

    If a civilian runs during Phase 1, he can safely exit the arena in a minute with a probability of prp_{r}. If a civilian runs during Phase 2 he can safely exit the arena in a minute with a probability of p~r\tilde{p}_{r}.

  10. (10)

    Let N2=N1n(e1+m1)N_{2}=N_{1}-n(e_{1}+m_{1}) be the number of people in the complex arena at the beginning of Phase 2. We assume N2=T1(e2+m2)N_{2}=T_{1}(e_{2}+m_{2}) for some positive integer T1T_{1}.

  11. (11)

    The shooter seeks and shoots during phase 2 until every remaining civilian in the arena is dead.

During Phase 0, the crowd size goes from NN to N1N_{1}. Hence, the survival probability of each civilian is N1/NN_{1}/N. The survival probabilities of the civilian during Phase 11 are the same as those probabilities in Table 3, with appropriate substitutions. For example, if the civilian chooses to hide for the first i1i-1 minutes but fights back during the ii-th minute of Phase 1, then his survival probability is

p~N1Nk=1i1[1m1(Ne1)(k1)(e1+m1)],i=1,,n.\frac{\tilde{p}N_{1}}{N}\prod_{k=1}^{i-1}\left[1-\frac{m_{1}}{(N-e_{1})-(k-1)(e_{1}+m_{1})}\right],\quad\text{$i=1,\ldots,n$}.

2.3.1 When T1>T2T_{1}>T_{2}

Note that if a civilian is still in the arena and alive at the beginning of Phase 2, he must have survived Phase 0 and Phase 1 and his action in Phase 1 must be “hide”. Thus, the probability that the civilian is alive in the arena at the beginning of Phase 2, denoted as psp_{s}, is given by

ps=N1Nk=1n[1m1(Ne1)(k1)(e1+m1)].p_{s}=\frac{N_{1}}{N}\prod_{k=1}^{n}\left[1-\frac{m_{1}}{(N-e_{1})-(k-1)(e_{1}+m_{1})}\right]. (5)

Following the same line of reasoning as in Section 2.2, we can obtain a civilian’s probabilities of survival over time during Phase 2. Table 5 summarizes these probabilities. We again make similar observations as in Section 1.2.1 and Section 2.2.1.

minute 11 22 \ldots T2T_{2}
fight psp~p_{s}\tilde{p} psp~(1m2N2e2)p_{s}\tilde{p}\left(1-\frac{m_{2}}{N_{2}-e_{2}}\right) \ldots psp~k=1T21(1m2Nk)p_{s}\tilde{p}\prod_{k=1}^{T_{2}-1}\left(1-\frac{m_{2}}{N^{\prime}_{k}}\right)
hide ps(1m2N2e2)p_{s}\left(1-\frac{m_{2}}{N_{2}-e_{2}}\right) psk=12(1m2Nk)p_{s}\prod_{k=1}^{2}\left(1-\frac{m_{2}}{N_{k}^{\prime}}\right) \ldots psk=1T2(1m2Nk)p_{s}\prod_{k=1}^{T_{2}}\left(1-\frac{m_{2}}{N_{k}^{\prime}}\right)
run psp~rp_{s}\tilde{p}_{r} psp~r(1m2N2e2)p_{s}\tilde{p}_{r}\left(1-\frac{m_{2}}{N_{2}-e_{2}}\right) \ldots psp~rk=1T21(1m2Nk)p_{s}\tilde{p}_{r}\prod_{k=1}^{T_{2}-1}\left(1-\frac{m_{2}}{N_{k}^{\prime}}\right)
Table 5: Survival probability of the civilian of focus in a complex arena during Phase 2 when T1>T2T_{1}>T_{2}, where psp_{s} is given by (5), Nk=(N2e2)(k1)(e2+m2)N^{\prime}_{k}=(N_{2}-e_{2})-(k-1)(e_{2}+m_{2}), and the ii-th cell of the “fight” (respectively “run”) row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back (respectively “run”) at the beginning of the ii-th minute.

2.3.2 When T1T2T_{1}\leq T_{2}

Similar to the case where T1<T2T_{1}<T_{2}, we can derive all the survival probabilities in Table 6. Observations in this case are completely analogous to those in Section 1.2.2 and Section 2.2.2.

minute 11 22 \ldots T11T_{1}-1 T1T_{1} T1+1T_{1}+1 \ldots T2T_{2}
fight psp~p_{s}\tilde{p} psp~B1p_{s}\tilde{p}B_{1} \ldots psp~k=1T12Bkp_{s}\tilde{p}\prod_{k=1}^{T_{1}-2}B_{k} psp~k=1T11Bkp_{s}\tilde{p}\prod_{k=1}^{T_{1}-1}B_{k} 0 \ldots 0
hide psB1p_{s}B_{1} psk=12Bkp_{s}\prod_{k=1}^{2}B_{k} \ldots psk=1T11Bkp_{s}\prod_{k=1}^{T_{1}-1}B_{k} 0 0 \ldots 0
run psp~rp_{s}\tilde{p}_{r} psp~rBkp_{s}\tilde{p}_{r}B_{k} \ldots psp~rk=1T12Bkp_{s}\tilde{p}_{r}\prod_{k=1}^{T_{1}-2}B_{k} psp~rk=1T11Bkp_{s}\tilde{p}_{r}\prod_{k=1}^{T_{1}-1}B_{k} 0 \ldots 0
Table 6: Survival probability of the civilian of focus in a complex arena during Phase 2 when T1T2T_{1}\leq T_{2}, where psp_{s} is given by (5), Bk=(1m2Nk)=[1m2((N2e2)(k1)(e2+m2))]B_{k}=\left(1-\frac{m_{2}}{N^{\prime}_{k}}\right)=\left[1-\frac{m_{2}}{((N_{2}-e_{2})-(k-1)(e_{2}+m_{2}))}\right], and the ii-th cell of the “fight” (respectively “run”) row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back (respectively “run”) at the beginning of the ii-th minute.

3 Multiple possibly armed civilians

In this section, we examine the case where there are multiple civilians of focus who may or may not carry a firearm and no other civilians will fight back. In such a case, it will be shown that the survival probability of a civilian of focus is not necessarily an increasing function of the number of armed civilians. Intuitively, when “too many” civilians have guns and start to shoot, it will cause confusion and lead to civilian deaths. An extreme case is when the active shooter is dressed in ordinary clothes and carries a handgun, and every civilian in a closed area is armed with a handgun too. Then an armed civilian is unlikely to identify who the shooter is. Also, any armed civilian can mistakenly kill another civilian when he is fighting the shooter. This is even more true when the civilian is under the stress of life and death. A key finding in this section is that, as the number of armed civilians increases, the survival probability of a civilian of focus in this case may first increase and then decrease. Throughout this section, we assume

  1. (1)

    There is only one active shooter. He shoots indiscriminately into the crowd unless he meets resistance. He will always kill those who fight back first if he meets resistance.

  2. (2)

    The authority will arrive in T2T_{2} minutes, where T2T_{2} is a positive integer. When the authority arrives, the shooter will kill himself or surrender himself to the authority; otherwise, the authority will neutralize the shooter immediately.

  3. (3)

    All civilians are rational decision-makers. They make their decisions without collaborating with others. Each of them wants to maximize their own chance of survival.

  4. (4)

    At the beginning of each minute, a civilian makes his decision for his action during that minute and sticks to it until the beginning of the next minute.

  5. (5)

    All civilians will be hit by the shooter with equal probabilities.

  6. (6)

    A bullet strikes at most one person. That is, there are no secondary casualties.

  7. (7)

    If an unarmed civilian fights back, no other civilians, armed or not, will follow him. If an armed civilian fights back, no unarmed civilians will follow him.

  8. (8)

    For i1i\geq 1, the number of survived civilians and armed civilians at the beginning of ii-th minute are NiN_{i} and KiK_{i} respectively, where KiNiK_{i}\leq N_{i}, N=N1N2N=N_{1}\geq N_{2}\geq\ldots, and NK1K2N\geq K_{1}\geq K_{2}\geq\ldots. If one of the armed civilians fights back at the beginning of the ii-th minute, then jKi1j_{K_{i}}-1 of them will follow immediately, where 1jKiKi1\leq j_{K_{i}}\leq K_{i} and jKijKi1j_{K_{i}}\leq j_{K_{i-1}}.

3.1 Closed arena

3.1.1 Already in the closed arena

Besides the common assumptions for Section 3, we also take the following assumptions in this section:

  1. (a)

    There are NN civilians in the closed arena, where NN is a positive integer. The active shooter is not considered as a civilian.

  2. (b)

    The shooter is already at the only door of the closed arena. There is no other place to exit the room. Therefore, a civilian of focus can either fight or hide. A civilian who does not fight will be killed by the shooter with equal probability. The shooter will walk around until every civilian is dead.

  3. (c)

    The shooter is equipped with a rifle, and his killing rate is mm people per minute, where mm is a positive integer, and KiKi1<mK_{i}-K_{i-1}<m, and N=T1mN=T_{1}m for some positive integer T1T_{1}. He carries plenty of magazines that are far more than enough to kill all the NN civilians. His rifle will not malfunction during the shooting. He plans to kill as many civilians as possible.

  4. (d)

    When an armed civilian fights back, he will kill the shooter with a probability p2p_{2}. At the same time, he may also mistakenly kill another civilian with a probability of pfp_{f}, where pf=cp2p_{f}=cp_{2} for some 0<c<10<c<1.

  5. (e)

    If an unarmed civilian fights back, he will subdue the shooter with a probability p1p_{1}, where p2>p1>0p_{2}>p_{1}>0.

Let us look at the ii-th minute. First, the probability that no civilian is mistakenly killed when an armed civilian fights back equals (1pf)jKi(1-p_{f})^{j_{K_{i}}}. Next, the event that an armed civilian fights back and survives the shooting is the same as the event that the shooter is killed by an armed civilian or the remaining jKi1j_{K_{i}}-1 armed civilians who follow him and, at the same, he is not mistakenly killed by the other jKi1j_{K_{i}}-1 armed civilians. The probability that the shooter is killed by one of the jKij_{K_{i}} armed civilians is 1(1p2)jKi1-(1-p_{2})^{j_{K_{i}}}. The probability that an armed civilian is not killed by another armed civilian when he fights back is [1pf/(Ni1)]jKi1[1-p_{f}/(N_{i}-1)]^{j_{K_{i}}-1} where Ni=N(i1)mN_{i}=N-(i-1)m. Hence,

g(Ki)\displaystyle g(K_{i}) \displaystyle\equiv {an armed civilians fights back and survives}\displaystyle\mathbb{P}\{\text{an armed civilians fights back and survives}\} (6)
=\displaystyle= [1(1p2)jKi][1pf/(Ni1)]jKi1,\displaystyle[1-(1-p_{2})^{j_{K_{i}}}][1-p_{f}/(N_{i}-1)]^{j_{K_{i}}-1},

where Ki{1,2,,Ni}K_{i}\in\{1,2,\ldots,N_{i}\}.

Proposition 1.

Suppose jKi=Kij_{K_{i}}=K_{i} and [1pf/(Ni1)][(1pf/(Ni1))(1p2)](1p2)2>1\frac{[1-p_{f}/(N_{i}-1)]}{[(1-p_{f}/(N_{i}-1))(1-p_{2})]^{(1-p_{2})^{2}}}>1. Then the function gg, given by (6), first increases and then decreases.

Proof.

Let f(x)=[1(1p2)x][1pf/(Ni1)]x1f(x)=[1-(1-p_{2})^{x}][1-p_{f}/(N_{i}-1)]^{x-1} where x1x\geq 1. Then f(x)f(x) is proportion to [1pf/(Ni1)]x[(1p2)(1pf/(Ni1))]x[1-p_{f}/(N_{i}-1)]^{x}-[(1-p_{2})(1-p_{f}/(N_{i}-1))]^{x}. Therefore,

f(x)\displaystyle f^{\prime}(x) \displaystyle\propto [1pf/(Ni1)]xln[1pf/(Ni1)]\displaystyle[1-p_{f}/(N_{i}-1)]^{x}\ln[1-p_{f}/(N_{i}-1)]
[(1p2)(1pf/(Ni1))]xln[(1p2)(1pf/(Ni1))]\displaystyle-\left[(1-p_{2})(1-p_{f}/(N_{i}-1))]^{x}\ln[(1-p_{2})(1-p_{f}/(N_{i}-1))\right]
=\displaystyle= [1pf/(Ni1)]x[ln(1pf/(Ni1))(1p2)xln[(1pf/(Ni1))(1p2)]]\displaystyle[1-p_{f}/(N_{i}-1)]^{x}\left[\ln(1-p_{f}/(N_{i}-1))-(1-p_{2})^{x}\ln[(1-p_{f}/(N_{i}-1))(1-p_{2})]\right]
=\displaystyle= [1pf/(Ni1)]xln[(1pf/(Ni1))[(1pf/(Ni1))(1p2)](1p2)x].\displaystyle[1-p_{f}/(N_{i}-1)]^{x}\ln\left[\frac{(1-p_{f}/(N_{i}-1))}{[(1-p_{f}/(N_{i}-1))(1-p_{2})]^{(1-p_{2})^{x}}}\right]. (8)

Therefore, f(x)>0f^{\prime}(x)>0 if and only if

[1pf/(Ni1)][(1pf/(Ni1))(1p2)](1p2)x>1.\frac{[1-p_{f}/(N_{i}-1)]}{[(1-p_{f}/(N_{i}-1))(1-p_{2})]^{(1-p_{2})^{x}}}>1. (9)

In particular, f(2)>0f^{\prime}(2)>0 if and only if

[1pf/(Ni1)][(1pf/(Ni1))(1p2)](1p2)2>1.\frac{[1-p_{f}/(N_{i}-1)]}{[(1-p_{f}/(N_{i}-1))(1-p_{2})]^{(1-p_{2})^{2}}}>1. (10)

Therefore, the proposition follows. ∎

Remark. The condition [1pf/(Ni1)][(1pf/(Ni1))(1p2)](1p2)2>1\frac{[1-p_{f}/(N_{i}-1)]}{[(1-p_{f}/(N_{i}-1))(1-p_{2})]^{(1-p_{2})^{2}}}>1 is relatively mild. For example, it is satisfied when p2=0.45p_{2}=0.45, pf=0.2p_{f}=0.2, and Ni=20N_{i}=20; see Figure 1 for a plot of gg in this case.

Refer to caption
Figure 1: Plot of g(Ki)g(K_{i}) when jKi=Kij_{K_{i}}=K_{i}, p2=0.45p_{2}=0.45, pf=0.2p_{f}=0.2, and Ni=20N_{i}=20.

Proposition 1 shows that more armed civilians do not necessarily increase the survival probability of a civilian of focus. Quite the opposite, when there are “too many” armed civilians, the survival probability of a civilian of focus starts to decrease due to the increased likelihood of “friendly fire”. An interesting practical implication of this is that the scenario where everyone carries a firearm might be worse than the scenario where only a few of them has a firearm.

For i=1,,max{T1,T2}i=1,\ldots,\max\{T_{1},T_{2}\}, we put p2i=[1(1p2)jKi][1pf/(Ni1)]jKi1p_{2i}=[1-(1-p_{2})^{j_{K_{i}}}][1-p_{f}/(N_{i}-1)]^{j_{K_{i}}-1} if a civilian is armed and p2i=p1p_{2i}=p_{1} if he is unarmed. Similar to our analysis in Section 2.1, we can derive the survival probabilities of a civilian over times for both T1>T2T_{1}>T_{2} and T1T2T_{1}\leq T_{2}. We summarize the results in Table 7 and Table 8 respectively. The respective observations for both cases are similar to those in Section 2.1.1. For example, in the case where T1>T1T_{1}>T_{1}, if p2Ti[1(i1)m/N]>(1im/N)p_{2T_{i}}[1-(i-1)m/N]>(1-im/N) for some 1iT21\leq i\leq T_{2} but p2j[1(j1)m/N]<(1jm/N)p_{2j}[1-(j-1)m/N]<(1-jm/N) for 1ji11\leq j\leq i-1, then a civilian of focus should fight back during the ii-th minute; otherwise, “hide” will be a better option. On the other hand, if p2i[1(i1)m/N]<(1im/N)p_{2i}[1-(i-1)m/N]<(1-im/N) for all 1iT21\leq i\leq T_{2}, or, equivalently, p2i<[Nim]/[N(i1)m]=1m/[N(i1)m]p_{2i}<[N-im]/[N-(i-1)m]=1-m/[N-(i-1)m] for all 1iT21\leq i\leq T_{2}, then a civilian of focus should hide.

minute 11 22 \ldots T2T_{2} T2+1T_{2}+1 \ldots T1T_{1}
fight p21p_{21} p22(1mN)p_{22}\left(1-\frac{m}{N}\right) \ldots p2T2[1(T21)mN]p_{2T_{2}}\left[1-\frac{({T_{2}}-1)m}{N}\right] 1T2mN1-\frac{{T_{2}}m}{N} \ldots 1T2mN1-\frac{{T_{2}}m}{N}
hide 1mN1-\frac{m}{N} 12mN1-\frac{2m}{N} \ldots 1T2mN1-\frac{{T_{2}}m}{N} 1T2mN1-\frac{{T_{2}}m}{N} \ldots 1T2mN1-\frac{{T_{2}}m}{N}
Table 7: Survival probabilities of a civilian of focus in a closed arena when T1>T2T_{1}>T_{2}, where the ii-th cell of the “fight” row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back at the beginning of the ii-th minute.

minute 11 22 \ldots T11T_{1}-1 T1T_{1} T1+1T_{1}+1 \ldots
fight p21p_{21} p22(1mN)p_{22}\left(1-\frac{m}{N}\right) \ldots p2(T11)[1(T12)mN]p_{2(T_{1}-1)}\left[1-\frac{(T_{1}-2)m}{N}\right] p2T1[1(T11)mN]p_{2T_{1}}\left[1-\frac{(T_{1}-1)m}{N}\right] 0 \ldots
hide 1mN1-\frac{m}{N} 12mN1-\frac{2m}{N} \ldots 1(T11)mN1-\frac{(T_{1}-1)m}{N} 0 0 \ldots
Table 8: Survival probabilities of a civilian in a closed arena when T1T2T_{1}\leq T_{2}, where the ii-th cell of the “fight” row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back at the beginning of the ii-th minute.

3.1.2 Hallway interaction

As for the hallway interaction, the assumptions, analysis, and observations are similar to those in Section 2.1.2 except that p2p_{2} is replaced by p21p_{21}. It is easy to see again that the survival probability of a civilian of focus, as a function of the number of armed civilians, first increases and then decreases.

3.2 Open arena

The first six assumptions in Section 2.2 will be taken here along with Assumption (a) in Section 3.1. The survival probabilities of a civilian of focus are the same as in Section 2.2 except that pp is replaced by p2ip_{2i} in all expressions for 1imax{T1,T2}1\leq i\leq\max\{T_{1},T_{2}\}; see Table 9 and Table 10. Our observations are the same as in Section 2.2. Again, we can easily see that a civilian’s survival probability, as a function of the number of armed civilians, first increases and then decreases.

minute 11 22 \ldots T2T_{2}
fight p21p_{21} p22(1mNe)p_{22}\left(1-\frac{m}{N-e}\right) \ldots p2T1k=1T21[1m(Ne)(k1)(e+m)]p_{2T_{1}}\prod_{k=1}^{T_{2}-1}\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right]
hide 1mNe1-\frac{m}{N-e} k=12[1m(Ne)(k1)(e+m)]\prod_{k=1}^{2}\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right] \ldots k=1T2[1m(Ne)(k1)(e+m)]\prod_{k=1}^{T_{2}}\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right]
run prp_{r} pr(1mNe)p_{r}\left(1-\frac{m}{N-e}\right) \ldots prk=1T21[1m(Ne)(k1)(e+m)]p_{r}\prod_{k=1}^{T_{2}-1}\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right]
Table 9: Survival probabilities of a civilian of focus in an open arena when T1>T2T_{1}>T_{2}, where the ii-th cell of the “fight” (respectively “run”) row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back (respectively “run”) at the beginning of the ii-th minute.
minute 11 22 \ldots T11T_{1}-1 T1T_{1} T1+1T_{1}+1
fight p21p_{21} p22A1p_{22}A_{1} \ldots p2(T11)k=1T12Akp_{2(T_{1}-1)}\prod_{k=1}^{T_{1}-2}A_{k} p2T1k=1T11Akp_{2T_{1}}\prod_{k=1}^{T_{1}-1}A_{k} 0
hide 1mNe1-\frac{m}{N-e} k=12Ak\prod_{k=1}^{2}A_{k} \ldots k=1T11Ak\prod_{k=1}^{T_{1}-1}A_{k} 0 0
run prp_{r} prA1p_{r}A_{1} \ldots prk=1T12Akp_{r}\prod_{k=1}^{T_{1}-2}A_{k} prk=1T11Akp_{r}\prod_{k=1}^{T_{1}-1}A_{k} 0
Table 10: Survival probabilities of a civilian in an open arena when T1T2T_{1}\leq T_{2}, where Ak=[1m(Ne)(k1)(e+m)]A_{k}=\left[1-\frac{m}{(N-e)-(k-1)(e+m)}\right] and the ii-th cell of the “fight” (respectively “run”) row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back (respectively “run”) at the beginning of the ii-th minute..
Example 1.

Suppose N=210N=210, m=15m=15, e=25e=25, pr=0.1p_{r}=0.1, p1=0.05p_{1}=0.05, p2=0.3p_{2}=0.3, c=1/3c=1/3 (i.e., pf=0.1p_{f}=0.1), Ki=Ni/4K_{i}=\lfloor N_{i}/4\rfloor, jKi=Ni/20j_{K_{i}}=\lfloor N_{i}/20\rfloor, and T2=4T_{2}=4, where a\lfloor a\rfloor is the greatest integer less than or equal to aa. In this case, T1=N/(e+m)=5T_{1}=N/(e+m)=5 and Table 9 specializes to Table 11.

minute 11 22 33 44 55 66 \ldots
fight (armed) 0.9680.968 0.8630.863 0.7240.724 0.5340.534 0.2760.276 0.2760.276 \ldots
fight (unarmed) 0.0500.050 0.0460.046 0.0410.041 0.0350.035 0.0270.027 0.0270.027 \ldots
hide 0.9190.919 0.8240.824 0.7060.706 0.5430.543 0.2170.217 0.2170.217 \ldots
run 0.1000.100 0.0920.092 0.0830.083 0.0710.071 0.0540.054 0.0540.054 \ldots
Table 11: Survival probabilities in Table 9 when N=210N=210, m=15m=15, e=25e=25, pr=0.1p_{r}=0.1, p1=0.05p_{1}=0.05, p2=0.3p_{2}=0.3, pf=0.1p_{f}=0.1, Ki=Ni/4K_{i}=N_{i}/4, jKi=Ni/20j_{K_{i}}=N_{i}/20, and T2=4T1=5T_{2}=4\leq T_{1}=5.
Refer to caption
Figure 2: Plots of the survival probabilities in Table 11, where the circle, triangle, plus sign, and rectangle, symbols denote “fight (armed)”, “fight (unarmed)”, “hide”, and “run” rows respectively. .

Figure 2 displays a scatter plot of the survival probabilities in Table 11. Clearly, if a civilian of focus is unarmed, he should hide throughout. However, if he is armed, the should always fight except during the fourth minute where he should hide. Table 12 is the special case of Table 3 under the same setup when there is exactly one possibly armed civilian of focus. Comparing the first row of Table 11 with that of Table 12, we see that it might be better to fight earlier when there are more armed civilians, and more armed civilian will significantly increase the survival chance of an armed civilian because some armed civilians will join him when he fights back. This is different from the situation depicted by Figure 1 where more armed civilians is not necessary better. Table 12 also shows that the civilian should hide throughout. Therefore, “hide” might be the best strategy when there is only one armed civilian, and when there are more armed civilians, “fight” might be the optimal action.

minute 11 22 33 44 55 66 \ldots
fight (armed) 0.3000.300 0.2760.276 0.2490.249 0.2130.213 0.1620.162 0.1620.162 \ldots
fight (unarmed) 0.0500.050 0.0460.046 0.0410.041 0.0350.035 0.0270.027 0.0270.027 \ldots
hide 0.9190.919 0.8240.824 0.7060.706 0.5430.543 0.2170.217 0.2170.217 \ldots
run 0.1000.100 0.0920.092 0.0830.083 0.0710.071 0.0540.054 0.0540.054 \ldots
Table 12: Survival probabilities of a civilian of focus in an open arena when N=210N=210, m=15m=15, e=25e=25, pr=0.1p_{r}=0.1, p1=0.05p_{1}=0.05, p2=0.3p_{2}=0.3, and T2=4T1T_{2}=4\leq T_{1} when there is only one possibly armed civilian.

3.3 Complex arena

In this section, we take all assumptions in Section 2.3 except that Assumption (6) there will be replaced by

  1. (6’)

    If an unarmed civilian fights back during Phase 2, his chance of success will be p~1\tilde{p}_{1}. If an armed civilian fights during Phase 2, his probability of success will be p~2\tilde{p}_{2} where p~2>p~1>0\tilde{p}_{2}>\tilde{p}_{1}>0.

We will also make the following assumptions:

  1. (13)

    When an armed civilian fights back during Phase 1, he will kill the shooter with a probability p~2\tilde{p}_{2}. At the same time, he may also mistakenly kill another civilian with a probability of p~f\tilde{p}_{f}. We assume that these two events are independent and that 0<p~f<p~20<\tilde{p}_{f}<\tilde{p}_{2}.

  2. (14)

    We assume jKiKiNi=N2(i1)(e2+m2)j_{K_{i}}\leq K_{i}\leq N^{\prime}_{i}=N_{2}-(i-1)(e_{2}+m_{2}), where N2=Nn(e1+m1)N_{2}=N-n(e_{1}+m_{1}).

For i=1,,max{T1,T2}i=1,\ldots,\max\{T_{1},T_{2}\}, we put p~2i=[1(1p~2)jKi][1p~f/(Ni1)]jKi1\tilde{p}_{2i}=[1-(1-\tilde{p}_{2})^{j_{K_{i}}}][1-\tilde{p}_{f}/(N^{\prime}_{i}-1)]^{j_{K_{i}}-1} if a civilian is armed and p~2i=p~1\tilde{p}_{2i}=\tilde{p}_{1} if he is unarmed. Then all results in Section 2.3 carry over here except that p~\tilde{p} is replaced by p~2i\tilde{p}_{2i} in all expressions for 1imax{T1,T2}1\leq i\leq\max\{T_{1},T_{2}\}; see Table 13 and Table 14.

minute 11 22 \ldots T2T_{2}
fight psp~21p_{s}\tilde{p}_{21} psp~22(1m2N2e2)p_{s}\tilde{p}_{22}\left(1-\frac{m_{2}}{N_{2}-e_{2}}\right) \ldots psp~2T2k=1T21(1m2Nk)p_{s}\tilde{p}_{2T_{2}}\prod_{k=1}^{T_{2}-1}\left(1-\frac{m_{2}}{N^{\prime}_{k}}\right)
hide ps(1m2N2e2)p_{s}\left(1-\frac{m_{2}}{N_{2}-e_{2}}\right) psk=12(1m2Nk)p_{s}\prod_{k=1}^{2}\left(1-\frac{m_{2}}{N^{\prime}_{k}}\right) \ldots psk=1T2(1m2Nk)p_{s}\prod_{k=1}^{T_{2}}\left(1-\frac{m_{2}}{N_{k}^{\prime}}\right)
run psp~rp_{s}\tilde{p}_{r} psp~r(1m2N2e2)p_{s}\tilde{p}_{r}\left(1-\frac{m_{2}}{N_{2}-e_{2}}\right) \ldots psp~rk=1T21(1m2Nk)p_{s}\tilde{p}_{r}\prod_{k=1}^{T_{2}-1}\left(1-\frac{m_{2}}{N_{k}^{\prime}}\right)
Table 13: Survival probability of a civilian of focus in a complex arena during Phase 2 when T1>T2T_{1}>T_{2}, where psp_{s} is given by (5), Nk=(N2e2)(k1)(e2+m2)N_{k}^{\prime}=(N_{2}-e_{2})-(k-1)(e_{2}+m_{2}), and the ii-th cell of the “fight” (respectively “run”) row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back (respectively “run”) at the beginning of the ii-th minute.
minute 11 22 \ldots T11T_{1}-1 T1T_{1} T1+1T_{1}+1
fight psp~21p_{s}\tilde{p}_{21} psp~22C1p_{s}\tilde{p}_{22}C_{1} \ldots psp~2(T11)CT12p_{s}\tilde{p}_{2(T_{1}-1)}C_{T_{1}-2} psp~2T1CT11p_{s}\tilde{p}_{2T_{1}}C_{T_{1}-1} 0
hide psphC1p_{s}p_{h}C_{1} psC2p_{s}C_{2} \ldots psCT11p_{s}C_{T_{1}-1} 0 0
run psp~rp_{s}\tilde{p}_{r} psp~rC1p_{s}\tilde{p}_{r}C_{1} \ldots psp~rCT12p_{s}\tilde{p}_{r}C_{T_{1}-2} psp~rCT11p_{s}\tilde{p}_{r}C_{T_{1}-1} 0
Table 14: Survival probability of a civilian of focus in a complex arena when T1T2T_{1}\leq T_{2}, where psp_{s} is given by (5), Nk=(1m2Nk)=[1m2((N2e2)(k1)(e2+m2))]N_{k}^{\prime}=\left(1-\frac{m_{2}}{N^{\prime}_{k}}\right)=\left[1-\frac{m_{2}}{((N_{2}-e_{2})-(k-1)(e_{2}+m_{2}))}\right], Ci=k=1i(1m2Nk)=k=1i[1m2((N2e2)(k1)(e2+m2))]C_{i}=\prod_{k=1}^{i}\left(1-\frac{m_{2}}{N_{k}^{\prime}}\right)=\prod_{k=1}^{i}\left[1-\frac{m_{2}}{((N_{2}-e_{2})-(k-1)(e_{2}+m_{2}))}\right], and the ii-th cell of the “fight” (respectively “run”) row is the survival probability of the civilian when he hides for the first (i1)(i-1) minutes and starts to fight back (respectively “run”) at the beginning of the ii-th minute..

4 Concluding remarks

The past two decades have witnessed an increasing number of active shooter incidents in the US. Several scholars have proposed analytical and agent-based simulation models to study these events. However, no analytical model has taken civilian response into consideration. Also, most of these models focus on the expected number of civilian casualties. We have investigated the optimal action of a civilian during an active shooter event where a civilian can fight, hide, or run. Unlike previous authors, we incorporated civilian resistance into our models and focused on the survival probability of a civilian. We considered three types of arenas: closed, open, and complex. For each type of arena, we investigated the case where there is one possibly armed civilian and the case where there are multiple possibly armed civilians. We have found the following results:

  1. (i)

    A civilian’s chance of survival decreases over time, irrespective of his action.

  2. (ii)

    There are desperate situations in which a civilian should fight back even if he is unarmed.

  3. (iii)

    Carrying a firearm does not always increase the civilian’s chance of survival during an active shooter incident.

  4. (iv)

    Carrying a firearm makes “resistance” more likely to be the optimal action of the civilian.

  5. (v)

    “Hide” might be the best action even if the civilian is armed.

  6. (vi)

    More armed civilians might increase a civilian’s chance of survival during an active shooter event, though that is not always the case.

The setup of our model is simpler than that of many agent-based models in the literature. However, this should be a reason to dismiss an analytic model. In an analytic model approach, the number of scenarios we need to consider grows exponentially when the number of factors increases. If there are nn factors and each of them has a binary outcome, then we need to consider 2n2^{n} scenarios. Therefore, we limited the number of factors in our model only to a few essential ones to make the analysis manageable. This is one inherent limitation of an analytic model. However, the conclusions reached using analytic models are analytically valid—an agent-based model can never achieve that. On the other hand, an agent-based model has the advantage that many factors can be included. Thus, they are equally important in the sense they can provide important insight empirically.

Conflict of interest

The author has no conflict of interest to disclose.

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