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thanks: Forthcoming from the American Journal of Physics.

Complementarity and entanglement in a simple model of inelastic scattering

David Kordahl dkordahl@centenary.edu Department of Physics and Engineering, Centenary College of Louisiana, Shreveport, LA 71104
Abstract

A simple model coupling a one-dimensional beam particle to a one-dimensional harmonic oscillator is used to explore complementarity and entanglement. This model, well-known in the inelastic scattering literature, is presented under three different conceptual approaches, with both analytical and numerical techniques discussed for each. In a purely classical approach, the final amplitude of the oscillator can be found directly from the initial conditions. In a partially quantum approach, with a classical beam and a quantum oscillator, the final magnitude of the quantum-mechanical amplitude for the oscillator’s first excited state is directly proportional to the oscillator’s classical amplitude of vibration. Nearly the same first-order transition probabilities emerge in the partially and fully quantum approaches, but conceptual differences emerge. The two-particle scattering wavefunction clarifies these differences and allows the consequences of quantum entanglement to be explored.

I Introduction

An understanding of quantum concepts is often built by overlapping classical analogies, analytical models, and numerical illustrations. After learning about a particle’s classical momentum, students are shown that a particle’s de Broglie wavelength depends on the inverse of that momentum. Students may then analytically model the one-dimensional (ID) reflection and transmission of de Broglie waves from a potential barrier, whose analogous classical counterparts would all have been stopped by that same barrier. Further insights can be gained by numerically modeling such reflection and transmission events using wave packets. Each of these approaches teases out new qualitative and quantitative connections 1.

Recent years have seen an increasing consensus that the concept of entanglement—the inability of some quantum states to be written as the product of individual particle states—should be a part of every student’s quantum tookit. As Daniel V. Schroeder pointed out in “Entanglement isn’t just for spins,” entanglement generically arises when quantum particles interact with each other 2. In that paper, Schroeder presented two dynamical models showing how entanglement emerges, but lamented that such examples are rarely included in quantum mechanics textbooks. “The reason,” he conceded, “is probably that despite their conceptual simplicity, a quantitative treatment of either scenario requires numerical methods.”

This paper presents a conceptually simple model that can model entanglement without resorting to numerical methods. The level of mathematical difficulty in this treatment is similar to that of the commonly taught models involving potential barriers. The model is a simplified 1D treatment of inelastic scattering. It is well-known to the electron spectroscopy community 3, and is similar to the model of a 1D atom scattering off a 1D harmonic oscillator presented in this journal several decades ago by Knudson 4, though this treatment differs in its attention to the time-evolution of the scattering process.

Refer to caption
Figure 1: In the model being studied, one variable (xx) represents the position of a beam particle, and the other (yy) represents the vibrational displacement of an oscillator. The beam and oscillator are coupled via H1H^{1}, a potential that depends on the product of a coupling constant α\alpha, the oscillator displacement yy, and some spatially-dependent function f(x)f(x), which may depend implicitly on an impact parameter bb.

In the model under review, a beam particle is coupled to a harmonic oscilator, as illustrated in Fig. 1. The model Hamiltonian sums the contributions of a 1D free particle of mass mm (position variable xx, conjugate momentum pxp_{x}), a 1D harmonic oscillator of reduced mass μ\mu and resonance frequency ω0\omega_{0} (position variable yy, conjugate momentum pyp_{y}), and an interaction term H1H^{1} that couples the two systems:

H\displaystyle H =\displaystyle= Hbeam0\displaystyle H^{0}_{\mathrm{beam}} +\displaystyle+ HHO0\displaystyle H^{0}_{\mathrm{HO}}\qquad +\displaystyle+ H1\displaystyle H^{1}\quad
=\displaystyle= px22mbeam\displaystyle\underbrace{\frac{p_{x}^{2}}{2m}}_{\text{beam}} +\displaystyle+ py22μ+12μω02y2harmonic oscillator\displaystyle\underbrace{\frac{p_{y}^{2}}{2\mu}+\frac{1}{2}\mu\omega_{0}^{2}y^{2}}_{\text{harmonic oscillator}}\, \displaystyle- αyf(x)interaction.\displaystyle\underbrace{\alpha\,y\,f(x)}_{\text{{interaction}}}. (1)

The coupling constant α\alpha rationalizes units and tunes the strength of the interaction, and the spatially-varying “window function” f(x)f(x) is taken to have units of length-2, and to die off as xx approaches ±\pm\infty. The negative sign in H1H^{1} means that the oscillator is attracted toward the beam when α\alpha and f(x)f(x) are positive, but changing this sign would not significantly alter any results.

Though its form is simple, this model can be used to capture real physics. For instance, in “Characterizing Localized Surface Plasmons Using Electron Energy-Loss Spectroscopy,” Cherqui et al.5 derive “classical” and “quantum” Hamiltonians for the electron-plasmon interaction (their Eqs. 14 and 15) that map respectively onto our Eq. I and Eq. 30, but for the fact that an electron couples to infinitely many plasmonic modes, while our beam couples to just one oscillator. For the plasmonic case, as an electron nears a nanoparticle, a surface charge is induced, which in turn interacts with the electron via the Coulomb potential. The physics in this model is analogous, with the passing beam tugging on the oscillator, and the oscillator in turn tugging back on the beam.

In addition to its discussion of entanglement, this presentation also highlights conceptual issues surrounding classical/quantum complementarity.6 Complementarity is explored implicitly as different approaches to the model are presented—a classical approach (Sec. II), and, after a review of perturbation theory (Sec. III), partially and fully quantum approaches (Secs. IV and V). Complementarity then is addressed explicitly in Sec. VI, where the transition from one approach to the next is discussed, and Sec. VII explores post-interaction entanglement, showing how predictions may change in entangled systems following a measurement. Sec. VIII is a short summary.

II Classical Approach

Solving the model in the classical approach requires only standard tools. Applying Hamilton’s equations

dxdt\displaystyle\frac{dx}{dt} =Hpx\displaystyle=\frac{\partial H}{\partial p_{x}} dydt\displaystyle\,\frac{dy}{dt} =Hpy\displaystyle=\frac{\partial H}{\partial p_{y}} (2)
dpxdt\displaystyle\frac{dp_{x}}{dt} =Hx\displaystyle=-\frac{\partial H}{\partial x} dpydt\displaystyle\,\frac{dp_{y}}{dt} =Hy\displaystyle=-\frac{\partial H}{\partial y} (3)

to Eq. I yields the classical equations of motion for the beam position xx and oscillator displacement yy

md2xdt2=αydfdxμd2ydt2=μω02y+αf(x)\begin{split}m\frac{d^{2}x}{dt^{2}}&=\alpha y\frac{df}{dx}\\ \mu\frac{d^{2}y}{dt^{2}}&=-\mu\omega_{0}^{2}y+\alpha f(x)\end{split} (4)

which can be solved either by analytical or numerical methods.

II.1 Analytical Calculation

If we suppose that the kinetic energy of our beam far exceeds the magnitude of the interaction energy between the beam and the harmonic oscillator, we will be safe in approximating the motion of the beam particle as

xvt.x\approx vt. (5)

Under this approximation, the equation of motion for the oscillator becomes that of a driven harmonic oscillator:

μd2ydt2=μω02y+αf(vt).\mu\frac{d^{2}y}{dt^{2}}=-\mu\omega_{0}^{2}y+\alpha f(vt). (6)

Using the Fourier transform convention

f~(ω)=12π+𝑑teiωtf(vt),\tilde{f}(\omega)=\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{+\infty}dte^{i\omega t}f(vt), (7)

we can transform both sides of Eq. 6 to obtain

μω2y~(ω)=μω02y~(ω)+αf~(ω),-\mu\omega^{2}\tilde{y}(\omega)=-\mu\omega_{0}^{2}\tilde{y}(\omega)+\alpha\tilde{f}(\omega), (8)

which can easily be solved algebraically to give us

y~(ω)=αf~(ω)μ(ω2ω02).\tilde{y}(\omega)=\frac{-\alpha\tilde{f}(\omega)}{\mu(\omega^{2}-\omega_{0}^{2})}. (9)

In principle, the story that this tells is simple. As the beam passes, it pulls on the oscillator a bit, and once the beam is far enough away, the oscillator will be left vibrating with whatever amplitude it had once the beam and oscillator were sufficiently separated to effectively decouple. And in principle, we should be able to find the final amplitude of the oscillator’s vibration by performing the inverse Fourier transform of Eq. 9 to find y(t)y(t).

In practice, however, we would like our calculation to depend less sensitively on phases, so instead we can calculate the work done on the beam. This work will be negative, since the beam loses energy as it passes, but the magnitude of this energy loss equals the magnitude of the energy gain by the oscillator, since the combined system is energy-conserving. This transfer can then be used to calculate the oscillator amplitude.

To calculate the work done on the beam, one can (a) rewrite the work integral as an integral over time; (b) insert the expression for y(t)y(t) as an inverse Fourier transform; (c) reverse the order of the time and frequency integrals; and (d) perform the frequency integral by slightly displacing the poles off the real axis by iϵi\epsilon and using the residue theorem. These steps are carried out in detail in the Appendix. This gives us the result that

Wbeam=πα2μ|f~(ω0)|2W_{\mathrm{beam}}=-\frac{\pi\alpha^{2}}{\mu}\left|\tilde{f}(\omega_{0})\right|^{2} (10)

The work done on the oscillator by the beam will have the same magnitude, but with the opposite sign:

WHO=πα2μ|f~(ω0)|2.W_{\mathrm{HO}}=\frac{\pi\alpha^{2}}{\mu}\left|\tilde{f}(\omega_{0})\right|^{2}. (11)

We might notice that this work done on the oscillator is proportional to to the oscillator amplitude squared. If the oscillator’s classical amplitude is ymy_{m}, we can write

WHO=12μω02ym2,W_{\mathrm{HO}}=\frac{1}{2}\mu\omega_{0}^{2}y_{m}^{2}, (12)

which in turn gives us that

ym=2παμω0|f~(ω0)|.y_{m}=\frac{\sqrt{2\pi}\alpha}{\mu\omega_{0}}\left|\tilde{f}(\omega_{0})\right|. (13)

For specificity, let’s consider an example. Suppose we approximate a dipole potential with a thinner-tailed Gaussian 7, such that our window function f(x)f(x) is

f(x)=b2ex2/b2.f(x)=b^{-2}e^{-x^{2}/b^{2}}. (14)

If we insert our approximate solution xvtx\approx vt into this

f(vt)=b2ev2t2/b2,f(vt)=b^{-2}e^{-v^{2}t^{2}/b^{2}}, (15)

we can take the Fourier transform (Eq. 7) to yield

f~(ω)=eb2ω2/4v22bv,\tilde{f}(\omega)=\frac{e^{-b^{2}\omega^{2}/4v^{2}}}{\sqrt{2}bv}, (16)

so the work done on the oscillator (Eq. 11) is

WHO=πα22μv2b2eb2ω02/2v2.W_{\mathrm{HO}}=\frac{\pi\alpha^{2}}{2\mu v^{2}b^{2}}e^{-b^{2}\omega_{0}^{2}/2v^{2}}. (17)

and the oscillator’s vibrational amplitude (Eq. 13) is

ym=παμω0eb2ω02/4v2vb.y_{m}=\frac{\sqrt{\pi}\alpha}{\mu\omega_{0}}\frac{e^{-b^{2}\omega_{0}^{2}/4v^{2}}}{vb}. (18)
Refer to caption
Figure 2: Time-evolution of a classical oscillator (yy) for different initial speeds of passing beam (xx): v0=1.0v_{0}=1.0 (top left), v0=3.0v_{0}=3.0 (top right), v0=7.0v_{0}=7.0 (bottom left), and v0=15v_{0}=15 (bottom right). The final amplitude ymy_{m} is given for each case.

II.2 Numerical Calculation

Of course, one may avoid Fourier transforms altogether and simply evolve the equations of motion numerically, using, for instance, the Euler-Richardson method 8. Using units where =ω0=m=1\hbar=\omega_{0}=m=1, b=10b=10, and μ=100\mu=100, and using the window function specified in Eq. 14, the results of this are shown in Fig. 2 for four different initial velocities of the beam particle (i.e., of dx/dtdx/dt at tb/vt\ll-b/v), of vv equal to 1.0, 3.0, 7.0, and 15. In each of the subplots, the classical amplitude ymy_{m} has been checked numerically, and matches the value predicted analytically by Eq. 18.

III Perturbation Theory Review

But there is a problem. The classical approach is empirically inadequate for micro- or mesoscopic systems, since the beam particle in fact will not lose energy each time it passes the (generalized) oscillator. Sometimes the beam particle will be observed to lose energy, but most of the time it will pass by without any energy loss at all.

As a result, we will want to develop a quantum version of the model. We are interested in both analytical and numerical solutions, and when we want analytical solutions in quantum mechanics, we often turn to perturbation theory. So let’s briefly remind ourselves, now, about time-dependent perturbation theory 9.

Suppose we have an unperturbed Hamiltonian operator H0^\hat{H_{0}} whose eigenvectors |n0\ket{n^{0}} are known:

H0^|n0=En0|n0.\hat{H^{0}}\ket{n^{0}}=E_{n}^{0}\ket{n^{0}}. (19)

Solutions of the Schrodinger equation

i|ψt=H^|ψi\hbar\frac{\partial\ket{\psi}}{\partial t}=\hat{H}\ket{\psi} (20)

can be written, without loss of generality, in terms of coefficients cn(t)c_{n}(t):

|ψ(t)=ncn(t)eiEn0t/|n0.\ket{\psi(t)}=\sum_{n}c_{n}(t)e^{-iE_{n}^{0}t/\hbar}\ket{n^{0}}. (21)

When the Hamiltonian in question is the unperturbed Hamiltonian H^=H0^\hat{H}=\hat{H^{0}}, one can substitute Eq. 21 into the Schrodinger equation to confirm that the coefficients cnc_{n} are constant in time. When the Hamiltonian is perturbed by a weak (and possibly time-dependent) term H1^(t)\hat{H^{1}}(t) such that H^=H0^+H1^(t)\hat{H}=\hat{H^{0}}+\hat{H^{1}}(t), the cnc_{n} coefficients will still be useful, since they vary more slowly in time than state coefficients would without factoring out exp(iEn0t/)\exp(-iE_{n}^{0}t/\hbar).

Applying the operator f0|exp(+iEf0t/)\bra{f^{0}}\exp(+iE_{f}^{0}t/\hbar) to both sides of Eq. 20 and inserting the expansion of Eq. 21, we can find the time-dependence of any state coefficient cfc_{f} as

idcfdt=nf0|H1(t)|n0eiωfnti\hbar\frac{dc_{f}}{dt}=\sum_{n}\bra{f^{0}}H^{1}(t)\ket{n^{0}}e^{i\omega_{fn}t} (22)

where

ωfn=Ef0En0.\omega_{fn}=\frac{E_{f}^{0}-E_{n}^{0}}{\hbar}. (23)

For a system that begins in initial state |i0\ket{i^{0}} with energy EiE_{i} at time t=t=-\infty, Eq. 22 leads to a first-order perturbation coefficient cfc_{f} for exciting the system to some final state |f0\ket{f^{0}} with energy EfE_{f} as

cf(t)=δfiitf0|H1(t)|i0eiωfit𝑑t,c_{f}(t)=\delta_{fi}-\frac{i}{\hbar}\int_{-\infty}^{t}\bra{f^{0}}H^{1}(t^{\prime})\ket{i^{0}}e^{i\omega_{fi}t^{\prime}}dt^{\prime}, (24)

which means the first-order probability of transition to state |f0\ket{f^{0}} is found by allowing tt\rightarrow\infty and calculating

Pf=|cf(t=+)|2P_{f}=|c_{f}(t=+\infty)|^{2} (25)

from the Born rule. When the initial and final states are distinct, inserting Eq. 24 into Eq. 25 yields

Pf=12|+f|H1^(t)eiωfit|i𝑑t|2,P_{f}=\frac{1}{\hbar^{2}}\left|\int_{-\infty}^{+\infty}\bra{f}\hat{H^{1}}(t^{\prime})e^{i\omega_{fi}t^{\prime}}\ket{i}dt^{\prime}\right|^{2}, (26)

which will be sufficient to let us calculate excitation probabilities analytically for both of the common quantum-mechanical approaches to the model being reviewed.

IV Partially Quantum Approach

The partially quantized approach has us treat the oscillator as quantized while treating the beam only as the source of a time-dependent perturbation. If the beam is still modeled as a classical particle whose path follows xvtx\approx vt, the Hamiltonian that acts on the oscillator wavefunction is

H^=py22μ+12ω02μy2^H^0αyf(vt)^H^1(t).\hat{H}=\underbrace{\frac{p_{y}^{2}}{2\mu}+\frac{1}{2}\omega_{0}^{2}\mu y^{2}}_{\centering\text{{\hbox{\hat{H^0}}}}\@add@centering}-\underbrace{\alpha yf(vt)}_{\centering\text{{\hbox{\hat{H^1}(t)}}}\@add@centering}. (27)

This form will allow us to use perturbation theory, since the energy eigenstates of the quantum harmonic oscillator |n\ket{n}, with En=(n+1/2)ω0E_{n}=(n+1/2)\hbar\omega_{0}, are well-known.

IV.1 Analytical Calculation

Of course, for the quantum harmonic oscillator yy and pyp_{y} do not commute, but follow

[y,py]=ypypyy=i.[y,p_{y}]=yp_{y}-p_{y}y=i\hbar. (28)

The typical move, now, is to rewrite the Hamiltonian in terms of creation and annihilation operators

a=12ω0μ(ωoμyipy)a=12ω0μ(ωoμy+ipy),\begin{split}a^{\dagger}&=\frac{1}{\sqrt{2\hbar\omega_{0}\mu}}\left(\omega_{o}\mu y-ip_{y}\right)\\ a&=\frac{1}{\sqrt{2\hbar\omega_{0}\mu}}\left(\omega_{o}\mu y+ip_{y}\right),\end{split} (29)

which recasts the reduced Hamiltonian (Eq. 27) as

H=ω0(aa+12)^H_0αf(vt)2ω0μ(a+a)^H^1(t).H=\underbrace{\hbar\omega_{0}\left(a^{\dagger}a+\frac{1}{2}\right)}_{\text{{\hbox{\hat{H_0}}}}}-\underbrace{\alpha f(vt)\sqrt{\frac{\hbar}{2\omega_{0}\mu}}\left(a+a^{\dagger}\right)}_{\text{{\hbox{\hat{H^1}(t)}}}}. (30)

If the quantized oscillator begins its ground state of |0\ket{0} with energy E0=ω0/2E_{0}=\hbar\omega_{0}/2, we can calculate its probability of being kicked into its excited energy eigenstate |n\ket{n} at energy En=(n+1/2)ω0E_{n}=(n+1/2)\hbar\omega_{0} using Eqn. 26:

Pn=12|+n|H1^(t)einω0t|0𝑑t|2P_{n}=\frac{1}{\hbar^{2}}\left|\int_{-\infty}^{+\infty}\bra{n}\hat{H^{1}}(t)e^{in\omega_{0}t}\ket{0}dt\right|^{2} (31)

This expression predicts that the only possible transition (considering first-order perturbations) is from |0|1\ket{0}\rightarrow\ket{1}, with the probability

P1=πα2μω0|f~(ω0)|2.P_{1}=\frac{\pi\alpha^{2}}{\hbar\mu\omega_{0}}|\tilde{f}(\omega_{0})|^{2}. (32)

We might pause, now, to reflect on how this compares to the outcome of the purely classical system. In the purely classical system, we found that the final amplitude of the oscillator ymy_{m} could be calculated deterministically as a function of the the initial beam speed. For the partially quantum system, the same can be said of the probability P1P_{1} of finding the quantum harmonic oscillator in its first excited state.

In fact, if we compare ymy_{m} and P1P_{1}, we find that

P1=μω02ym2.P_{1}=\frac{\mu\omega_{0}}{2\hbar}y_{m}^{2}. (33)

or, equivalently, that

ym=2μωP1y_{m}=\sqrt{\frac{2\hbar}{\mu\omega}P_{1}} (34)

To belabor this point, we notice that the probability P1P_{1} is proportional to the square of the magnitude of the coefficient to |1\ket{1}, so, to first order, the classical oscillation amplitude is directly proportional to the magnitude of the quantum amplitude of the |0|1\ket{0}\rightarrow\ket{1} transition.

IV.2 Numerical Calculation

Refer to caption
Figure 3: A classical beam (v0=7.0v_{0}=7.0) is coupled to a quantum oscillator. Left: ψ(y)ψ(y)\psi^{*}(y)\psi(y) for the quantum harmonic oscillator in the partially quantum approach is shown as a function of tt in black and white, and the expectation value for the oscillator’s displacement, y\langle y\rangle, is overlaid as a dashed line. Right: The probabilities of measuring the oscillator in state |0\ket{0} (top) or |1\ket{1} (bottom) are shown as a function of tt.

What about a straightforward numerical solution? Suppose we begin with the oscillator in its ground state, represented as the normalized position wavefunction

ψ0(y)=y|0=(1πσy2)1/4ey2/2σy2,\psi_{0}(y)=\braket{y}{0}=\left(\frac{1}{\pi\sigma_{y}^{2}}\right)^{1/4}e^{-y^{2}/2\sigma_{y}^{2}}, (35)

and we want to know its probability of transitioning to its first excited state

ψ1(y)=y|1=2σy(1πσy2)1/4yey2/2σy2\psi_{1}(y)=\braket{y}{1}=\frac{\sqrt{2}}{\sigma_{y}}\left(\frac{1}{\pi\sigma_{y}^{2}}\right)^{1/4}y\,e^{-y^{2}/2\sigma_{y}^{2}} (36)

where in both ψ0(y)\psi_{0}(y) and ψ1(y)\psi_{1}(y)

σy=μω0.\sigma_{y}=\sqrt{\frac{\hbar}{\mu\omega_{0}}}. (37)

The most direct way to proceed is simply to use the time-dependent Schrodinger equation

itψ(y)=H^(t)ψ(y)i\hbar\frac{\partial}{\partial t}\psi(y)=\hat{H}(t)\psi(y) (38)

where in the position representation the time-dependent Hamiltonian operator looks like

H^(t)=22μ2y2+12μωo2y2αyf(vt).\hat{H}(t)=-\frac{\hbar^{2}}{2\mu}\frac{\partial^{2}}{\partial y^{2}}+\frac{1}{2}\mu\omega_{o}^{2}y^{2}-\alpha yf(vt). (39)

If the system starts in its ground state at some time tb/vt\ll-b/v, then it be can evolved forward in time using finite-difference time-domain (FDTD) methods 10.

The numerical calculation for this is shown in Fig. 3, for v=7v=7 and the other model parameters kept the same as for the classical simulations, as quoted in Sec. IV.2. The dashed purple trace in the figure is the numerically calculated expected value of the oscillator displacement

y=+𝑑yψ(y)yψ(y).\langle y\rangle=\int_{-\infty}^{+\infty}dy\,\psi^{*}(y)\,y\,\psi(y). (40)

which, as we might expect, follows the classical result y(t)y(t) for v=7v=7 shown in Fig. 2, as will be further established in our discussion of complementarity below (Sec. VI).

From there, one can also calculate the overlap between the wavefunction and its various energy eigenstates to find probabilities. One may numerically calculate

ψ1|ψ=+𝑑yψ1(y)ψ(y)\braket{\psi_{1}}{\psi}=\int_{-\infty}^{+\infty}dy\,\psi_{1}^{*}(y)\psi(y) (41)

to find the probability of transition from |0|1\ket{0}\rightarrow\ket{1} as

P1=|ψ1|ψ|2,P_{1}=|\braket{\psi_{1}}{\psi}|^{2}, (42)

and similarly to find the probability of remaining in state |0\ket{0} as P0P_{0}. These probabilities are shown on the right in Fig. 3, and they match the analytical prediction of Eq. 32.

V Fully Quantum Approach

If we want to treat our model in a fully quantum-mechanical way, the simplest way is to include the beam and the oscillator in a combined quantum state.

To make the problem analytically tractable, it will be useful to introduce a box length LL over which our wavefunction runs in xx, so as to make it normalizable. This will allow us to smuggle in classical notions like the velocity of the particle, since the time integral as the beam goes from L/2-L/2 to +L/2+L/2 can be written, if we consider that the beam travels at a speed of approximately vv throughout, as going from t=L/2vt_{-}=-L/2v to t+=+L/2vt_{+}=+L/2v.

Plane waves constitute energy eigenfunctions of the free particle, which we can write in terms of kk-vectors with k=mv/k=mv/\hbar. We can also reuse the energy eigenstates of the harmonic oscillator, which we will now express as |ny\ket{n}_{y}. So we can write a general quantum-mechanical state for the beam-oscillator system as

|ψ(x,y,t)=kx,nckx,n(t)(eikxxLeiEkt/)(|nyeiEnt/)\begin{split}&\ket{\psi(x,y,t)}\\ &\,\,=\sum_{k_{x},n}c_{k_{x},n}(t)\left(\frac{e^{ik_{x}x}}{\sqrt{L}}e^{-iE_{k}t/\hbar}\right)\left(\ket{n}_{y}e^{-iE_{n}t/\hbar}\right)\end{split} (43)

where the L\sqrt{L} in the denominator is for plane-wave normalization, and the energies are just

Ek=2kx22m,En=(n+1/2)ω0.\begin{split}E_{k}&=\frac{\hbar^{2}k_{x}^{2}}{2m},\\ E_{n}&=\left(n+1/2\right)\hbar\omega_{0}.\end{split} (44)

V.1 Analytical Calculation

The Hamiltonian operator in the position basis is

H^=22m2x222μ2y2+12μωo2y2αyf(x).\begin{split}\hat{H}=&-\frac{\hbar^{2}}{2m}\frac{\partial^{2}}{\partial x^{2}}-\frac{\hbar^{2}}{2\mu}\frac{\partial^{2}}{\partial y^{2}}+\frac{1}{2}\mu\omega_{o}^{2}y^{2}\\ &-\alpha yf(x).\end{split} (45)

Products of the plane waves along xx and harmonic oscillator states along yy are energy eigenstates of this combined Hamiltonian, but for the coupling term linking the two:

H1=αyf(x).H^{1}=-\alpha yf(x). (46)

Using this, we can proceed here just as above, calculating the transition coefficient ckx,nc_{k_{x},n} as tt\rightarrow\infty using Eq. 24.

The initial state |i0\ket{i^{0}}, with energy EiE_{i}, can be written as

|i0=eik0xL|0yEi=2k022m+ω0/2,\begin{split}\ket{i^{0}}&=\frac{e^{ik_{0}x}}{\sqrt{L}}\ket{0}_{y}\\ E_{i}&=\frac{\hbar^{2}k_{0}^{2}}{2m}+\hbar\omega_{0}/2,\end{split} (47)

and the final state |f0\ket{f^{0}}, with energy EfE_{f}, as

|f0=eik1xL|nyEf=2k122m+(n+1/2)ω0.\begin{split}\ket{f^{0}}&=\frac{e^{ik_{1}x}}{\sqrt{L}}\ket{n}_{y}\\ E_{f}&=\frac{\hbar^{2}k_{1}^{2}}{2m}+\left(n+1/2\right)\hbar\omega_{0}.\end{split} (48)

It is worth noticing that while the energy eigenstates of the oscillator are fairly well-localized in yy, the plane-wave energy eigenstates of the beam are spread out over the entire space in xx. Though these plane-wave beam states connect only loosely to “particle” concepts, their status as energy eigenstates of the uncoupled beam allows us to use standard perturbation theory.

At this point, we can once again use Eq. 26 to calculate our first-order transition probabilities. We first find

f0|H1|i0=αn|yy|0y1LL/2+L/2𝑑xei(k1k0)xf(x).\begin{split}\bra{f^{0}}&H^{1}\ket{i^{0}}\\ &=-\alpha\bra{n}_{y}y\ket{0}_{y}\frac{1}{L}\int_{-L/2}^{+L/2}dx\,e^{-i(k_{1}-k_{0})x}f(x).\end{split} (49)

The n|yy|0y\bra{n}_{y}y\ket{0}_{y} term is zero unless n=1n=1, leading again to the prediction that only |0y|1y\ket{0}_{y}\rightarrow\ket{1}_{y} transitions are allowed to first order. Next, we notice that the integral here has the form of a spatial Fourier transform:

f¯(kx)=limL12πL/2+L/2𝑑xeikxxf(x)=12π+𝑑xeikxxf(x).\begin{split}\bar{f}(k_{x})&=\lim_{L\to\infty}\frac{1}{\sqrt{2\pi}}\int_{-L/2}^{+L/2}dxe^{-ik_{x}x}f(x)\\ &=\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{+\infty}dxe^{-ik_{x}x}f(x).\end{split} (50)

Putting these together, when n=1n=1 in |f0\ket{f^{0}} we find

f0|H1|i0=αLπμω0f¯(k1k0).\bra{f^{0}}H^{1}\ket{i^{0}}=-\frac{\alpha}{L}\sqrt{\frac{\hbar\pi}{\mu\omega_{0}}}\bar{f}(k_{1}-k_{0}). (51)

This time-independent expression can be used to calculate the first-order transition coefficient in Eq. 24:

ckx=k1,n=1=iαLπμω0f¯(k1k0)L/2v+L/2v𝑑teiωfit.c_{k_{x}=k_{1},n=1}=\frac{i}{\hbar}\frac{\alpha}{L}\sqrt{\frac{\hbar\pi}{\mu\omega_{0}}}\bar{f}(k_{1}-k_{0})\int_{-L/2v}^{+L/2v}dt\,e^{i\omega_{fi}t}.

Ultimately, this coefficient should not depend on the box length LL, since that length was chosen for convenience. But the only way for LL dependence to vanish is if ωfi=0\omega_{fi}=0, a condition that forces energy to be conserved as it is exchanged between the beam and the oscillator.

Presuming that n=1n=1 for the oscillator in its final state, setting ωfi=0\omega_{fi}=0 fixes the possible wavenumber k1k_{1} for the scattered electron state:

ωfi=(EfEi)/=00=2m(k12k02)+ω0.\begin{split}\omega_{fi}&=(E_{f}-E_{i})/\hbar=0\\ \rightarrow 0&=\frac{\hbar}{2m}\left(k_{1}^{2}-k_{0}^{2}\right)+\omega_{0}.\end{split} (52)

Taking ωfi=0\omega_{fi}=0 also leads to the first-order transition coefficient of

ckx=k1,n=1=iαLπμω0f¯(k1k0)L/2v+L/2v𝑑teiωfit1=iαvπμω0f¯(k1k0),\begin{split}c_{k_{x}=k_{1},n=1}&=\frac{i}{\hbar}\frac{\alpha}{L}\sqrt{\frac{\hbar\pi}{\mu\omega_{0}}}\bar{f}(k_{1}-k_{0})\int_{-L/2v}^{+L/2v}dt\,\cancelto{1}{e^{i\omega_{fi}t}}\\ &=\frac{i}{\hbar}\frac{\alpha}{v}\sqrt{\frac{\hbar\pi}{\mu\omega_{0}}}\bar{f}(k_{1}-k_{0}),\end{split}

which, squaring, yields the transition probability:

P1=πα2μω0v2|f¯(k1k0)|2.P_{1}=\frac{\pi\alpha^{2}}{\hbar\mu\omega_{0}v^{2}}|\bar{f}(k_{1}-k_{0})|^{2}. (53)

This resembles Eq. 32 above, and we can show that the two expressions match when k1k0k_{1}-k_{0} is small. For our allowed first-order transition, we may write ωfi=0\omega_{fi}=0 as

0=2m(k12k02)+ω00=2m[(k1k0)20+2k0(k1k0)]+ω0,\begin{split}0&=\frac{\hbar}{2m}(k_{1}^{2}-k_{0}^{2})+\omega_{0}\\ \rightarrow 0&=\frac{\hbar}{2m}\left[\cancelto{0}{(k_{1}-k_{0})^{2}}+2k_{0}(k_{1}-k_{0})\right]+\omega_{0},\end{split}

which, if we rearrange and use k0=mv/k_{0}=mv/\hbar, yields

k1k0ω0/v,k_{1}-k_{0}\approx-\omega_{0}/v, (54)

which, in turn, allows us to write

P1πα2μω0v2|f¯(ω0/v)|2P_{1}\approx\frac{\pi\alpha^{2}}{\hbar\mu\omega_{0}v^{2}}|\bar{f}(\omega_{0}/v)|^{2} (55)

which, comparing f¯(kx)\bar{f}(k_{x}) in Eq. 50 and f~(ω)\tilde{f}(\omega) in Eq. 7, reveals that this P1P_{1} indeed matches that of Eq. 32.

V.2 Numerical Calculation (Setup Only)

The numerical calculation for the purely quantum model may at first seem like a straightforward generalization of the methods of Sec. IV.2. That is, there is nothing to stop one from using the Hamiltonian representation of Eq. 45, setting up a large box, and following the time evolution of the Schrodinger equation

itψ(x,y)=H^ψ(x,y)i\hbar\frac{\partial}{\partial t}\psi(x,y)=\hat{H}\psi(x,y) (56)

using FDTD methods just as above.

But this calculation is not likely to be terribly informative. Regardless of how sharply peaked the beam particle’s spatial wavefunction begins, it will tend to become increasingly broad with time 11. Understanding the final state, then, will require us to take the spatial Fourier transform of the spread-out wavefunction in xx to disentangle probabilities for possible measurements of entangled harmonic oscillator and beam momentum states.

Of course, we might start out with a partially transformed wavefunction ψ¯(kx,y)\bar{\psi}(k_{x},y) and time evolve that using FDTD. However, the equation of motion for this

itψ¯(kx,y)=(2kx22m22μ2y2+12μω02y2)ψ¯(kx,y)α2πyf¯(kx)ψ¯(kx,y),\begin{split}i\hbar\frac{\partial}{\partial t}&\bar{\psi}(k_{x},y)=\\ &\left(\frac{\hbar^{2}k_{x}^{2}}{2m}-\frac{\hbar^{2}}{2\mu}\frac{\partial^{2}}{\partial y^{2}}+\frac{1}{2}\mu\omega_{0}^{2}y^{2}\right)\bar{\psi}(k_{x},y)\\ &-\frac{\alpha}{\sqrt{2\pi}}y\bar{f}(k_{x})*\bar{\psi}(k_{x},y),\end{split} (57)

involves a convolution in each time-step

f¯(kx)ψ¯(kx,y)=+𝑑kf¯(k)ψ¯(kxk,y),\bar{f}(k_{x})*\bar{\psi}(k_{x},y)=\int_{-\infty}^{+\infty}dk^{\prime}\,\bar{f}(k^{\prime})\,\bar{\psi}(k_{x}-k^{\prime},y), (58)

which is possible, but which (as discussed below) would obscure the xx-dependence and would make it difficult to distinguish between the “initial” and “final” states.

V.3 Approximate Solution

In the parts of the wavefunction ψ(x,y)\psi(x,y) where the beam position x0x\ll 0 and f(x)0f(x)\approx 0, we should expect the “initial” wavefunction to be essentially that defined by Eq. 47, up to a phase factor. When the beam energy is much greater than the magnitude of the interaction energy, we should expect very little of the beam’s incoming wave to be reflected. When the beam reaches the region x0x\gg 0 where again f(x)0f(x)\approx 0, the beam and oscillator once again will evolve without interaction. In this region, the “final” wavefunction could be sampled over a large range with x0x\gg 0 and the Fourier transform could be taken in xx to disentangle the outcome probabilities.

To visualize this, we may construct an approximate first-order wavefunction for the scattering states 12. From our first-order results, we may write 13

|ψf(kx,y,t)(|k0x|0y+d1P1|k1x|1y)eiEit/\begin{split}&\ket{\psi_{f}(k_{x},y,t)}\approx\\ &\quad\left(\ket{k_{0}}_{x}\ket{0}_{y}+d_{1}\sqrt{P_{1}}\ket{k_{1}}_{x}\ket{1}_{y}\right)e^{-iE_{i}t/\hbar}\end{split} (59)

where EiE_{i} is just the system energy established in Eq. 47, d1d_{1} is a complex phase factor with |d1|=1|d_{1}|=1, and the relationship between k0k_{0} and k1k_{1} is set by Eq. 52.

Refer to caption
Figure 4: A schematic visualization of the two-particle wavefunction density, before (left) and after (right) scattering.

In this “final” region where x0x\gg 0, there will be negligible further interactions between the beam and the oscillator. Hence the probability density of this approximate solution will not evolve further in time:

ψf|ψfδkx,k0|ψ0(y)|2+P1δkx,k1|ψ1(y)|2\braket{\psi_{f}}{\psi_{f}}\approx\delta_{k_{x},k_{0}}|\psi_{0}(y)|^{2}+P_{1}\delta_{k_{x},k_{1}}|\psi_{1}(y)|^{2} (60)

This is plotted in Fig. 4, using the same parameters as in Fig. 3, albeit with the kxk_{x}-states broadened for visibility. Visualized in this way, it is easy to imagine these possibilities as distinct “branches” of the wavefunction.

But if this final state density is stationary in time, how would one go down from the higher-level descriptions of ψ(x,y)\psi(x,y) or ψ¯(kx,y)\bar{\psi}(k_{x},y) to the less informative descriptions of ψ(y)\psi(y) or just the classical xx and yy? This is the essential question of complementarity, to which we now turn.

VI Complementarity

How might one relate the fully quantum approach to the partially quantum approach? The fully quantum approach of Sec. V uses maximally dispersed plane waves states to describe the beam, while the partially quantum approach of Sec. IV treats the beam as a classical particle whose position is sharply defined at all times. Yet the reduced wavefunction ψ(y)\psi(y) should follow

ψ(y)=+𝑑xψ(x,y).\psi(y)=\int_{-\infty}^{+\infty}dx\,\psi(x,y). (61)

What assumptions might allow this to be true?

Thinking it through more carefully, we can integrate out xx on both sides of the two-particle Schrodinger equation (Eq. 56) to obtain a correct expression for the dynamics of ψ(y)\psi(y), assuming that the wavefunction and its derivatives vanish at infinity. In this case, we find that

itψ(y)=22μ2y2ψ(y)+12μωo2y2ψ(y)+𝑑xαyf(x)ψ(x,y).\begin{split}i\hbar\frac{\partial}{\partial t}\psi(y)=&-\frac{\hbar^{2}}{2\mu}\frac{\partial^{2}}{\partial y^{2}}\psi(y)+\frac{1}{2}\mu\omega_{o}^{2}y^{2}\psi(y)\\ &-\int_{-\infty}^{+\infty}dx\,\alpha\,y\,f(x)\,\psi(x,y).\end{split} (62)

Comparing this to the Hamiltonian of the partially quantum approach (Eq. 27), we can see that the only difference will occur in the interaction terms of the two approaches. Setting these terms equal, we find

+𝑑xf(x)ψ(x,y)f(vt)+𝑑xψ(x,y).\int_{-\infty}^{+\infty}dx\,f(x)\,\psi(x,y)\approx f(vt)\int_{-\infty}^{+\infty}dx\,\psi(x,y). (63)

In other words, for the partially and fully quantum approaches to agree, f(x)f(x) must both be moved outside the integral, which is reasonable only if f(x)f(x) varies much more slowly in xx than ψ(x,y)\psi(x,y), and must also follow f(x)f(vt)f(x)\approx f(vt), which is reasonable only when xx is near x\langle x\rangle, presuming that xvt\langle x\rangle\approx vt. Since the region near x\langle x\rangle is also where the interaction term will be most significant to the dynamics of the combined wavefunction, such an approximation may be less egregious than it first seems.

On a more limited level, how might we recover the time-dependence of ψ(y)ψ(y)\psi^{*}(y)\psi(y) when our approximate ψf|ψf\braket{\psi_{f}}{\psi_{f}} appears to be stationary in time? Here we need to integrate out the |kx\ket{k}_{x} parts of |ψ(kx,y,t)\ket{\psi(k_{x},y,t)}, including their time dependence. We can do this reduction explicitly for our approximate final-state wavefunction, Eq. 59:

|ψ(y,t)=kxkx|eiEkt/|ψ(kx,y,t)=|0yeiω0t/2+d1P1|1ye3iω0t/2.\begin{split}\ket{\psi(y,t)}&=\sum_{k_{x}}\bra{k_{x}}e^{iE_{k}t/\hbar}\ket{\psi(k_{x},y,t)}\\ &=\ket{0}_{y}e^{-i\omega_{0}t/2}+d_{1}\sqrt{P_{1}}\ket{1}_{y}e^{-3i\omega_{0}t/2}.\end{split} (64)

An easy way to check that this reproduces the dynamics of ψ(y)\psi(y) as calculated in Sec. IV is to obtain the expected value of yy. For our reduced approximate wavefunction (Eq. 64), we can calculate y\langle y\rangle as

ψ(y,t)|y|ψ(y,t)=2P1μω0Re[d1eiω0t].\bra{\psi(y,t)}y\ket{\psi(y,t)}=\sqrt{\frac{2\hbar P_{1}}{\mu\omega_{0}}}\mathrm{Re}\left[d_{1}e^{-i\omega_{0}t}\right]. (65)

The amplitude of the oscillation for this expected value exactly matches the amplitude of the classical displacement for the oscillator (Eq. 34), just as it should.

The single-particle wavefunction ψ(y)\psi(y) can also be linked to the classical oscillator displacement yy using Ehrenfest’s theorem 14. For any quantum operator A^\hat{A}, Ehrenfest’s theorem predicts

ddtA^=1i[A^,H^]+A^t.\frac{d}{dt}\langle\hat{A}\rangle=\frac{1}{i\hbar}\langle[\hat{A},\hat{H}]\rangle+\left\langle\frac{\partial\hat{A}}{\partial t}\right\rangle. (66)

We may apply this machinery to connect the partially quantum approach to the classical approach. Using the Hamiltonian Eq. 27 and the position-momentum commutator Eq. 28, we can easily calculate

[p^y,H^]=+i(μω2y+αf(vt)),[\hat{p}_{y},\hat{H}]=+i\hbar\left(-\mu\omega^{2}y+\alpha f(vt)\right), (67)

which can be inserted into Eq. 66 to yield

dp^ydt=μω02y+αf(vt).\frac{d\langle\hat{p}_{y}\rangle}{dt}=-\mu\omega_{0}^{2}\langle y\rangle+\alpha f(vt). (68)

This can be compared with the classical equation

dpydt=μω02y+αf(vt),\frac{dp_{y}}{dt}=-\mu\omega_{0}^{2}y+\alpha f(vt), (69)

demonstrating that p^y\langle\hat{p}_{y}\rangle and pyp_{y} follow the same dynamics. The same exercise can be carried out for y\langle y\rangle and yy, and the first-order equations in time can then be combined to yield second-order equations a la Eq. 4 above.

VII Entanglement

Schroeder has pointed out that interactions in quantum systems generically introduce entanglement 2. Returning to the approximate final-state wavefunction of Eq. 59, we can easily confirm that the state is indeed entangled, since it cannot be written as the product of single-particle wavefunctions. How, then, would our expectations about measurements be altered by the order in which we measure the oscillator and the beam?

In the usual way of discussing quantum mechanics, the wavefunction |ψ\ket{\psi} “collapses” upon measurement 15. The modified wavefunction post-measurement |ψ\ket{\psi^{\prime}} can be written in terms of a projection operator Π^\hat{\Pi} as

|ψ=Π^|ψψ|Π^|ψ.\ket{\psi^{\prime}}=\frac{\hat{\Pi}\ket{\psi}}{\sqrt{\bra{\psi}\hat{\Pi}\ket{\psi}}}. (70)

The projection operator, here, collapses the wavefunction into a determinate state for whatever relevant quantity has just been measured, and the denominator serves to reinforce normalization on the collapsed wavefunction.

Measuring one particle in a system but not the other requires us to alter the final state wavefunction using a partial projection operator 16. For instance, were we first to measure the final momentum of our beam particle with a value k1k_{1}, the projection operator

Π^k1=|k1k1|x1^y,\hat{\Pi}_{k_{1}}=\ket{k_{1}}\bra{k_{1}}_{x}\otimes\hat{1}_{y}, (71)

could be applied to our wavefunction approximation (Eq. 59) to produce a post-collapse wavefunction of

|ψ=|k1x|1y,\ket{\psi^{\prime}}=\ket{k_{1}}_{x}\ket{1}_{y}, (72)

where we have omitted the factor of d1eiEit/d_{1}e^{-iE_{i}t/\hbar}, since this is a phase factor of unit magnitude. Notice, then, that any subsequent predictions for the oscillator would simply match those of its first energy eigenstate.

Likewise, were we first to measure the oscillator’s displacement as yy^{\prime}, we could update our wavefunction using the projection operator

Π^y=1^x|yy|y,\hat{\Pi}_{y^{\prime}}=\hat{1}_{x}\otimes\ket{y^{\prime}}\bra{y^{\prime}}_{y}, (73)

which, realizing that y|ny=ψn(y)\braket{y^{\prime}}{n}_{y}=\psi_{n}(y^{\prime}), would lead to the updated wavefunction (again, omitting a phase factor) of

|ψ=ψ0(y)|k0x|yy+d1P1ψ1(y)|k1x|yy|ψ0(y)|2+|ψ0(y)|2.\begin{split}&\ket{\psi^{\prime}}=\\ &\quad\frac{\psi_{0}(y^{\prime})\ket{k_{0}}_{x}\ket{y^{\prime}}_{y}+d_{1}\sqrt{P_{1}}\psi_{1}(y^{\prime})\ket{k_{1}}_{x}\ket{y^{\prime}}_{y}}{\sqrt{|\psi_{0}(y^{\prime})|^{2}+|\psi_{0}(y^{\prime})|^{2}}}.\end{split} (74)

From this, we find that a measurement of yy^{\prime} far from the origin increases the probability that the beam has reduced its momentum from k0k_{0} to k1k_{1}, since the oscillator’s ground-state wavefunction ψ0(y)\psi_{0}(y) (Eq. 35) has thinner tails than the excited-state wavefunction ψ1(y)\psi_{1}(y) (Eq. 36).

Refer to caption
Figure 5: Left: If the beam momentum is measured first as k0\hbar k_{0} (top left), the oscillator displacement predictions can be found by integrating over the ground-state wavefunction |ψ0(y)|2|\psi_{0}(y)|^{2}. If the beam momentum is measured first as k1\hbar k_{1} (bottom left), the oscillator displacement predictions can be found by integrating over the excited-state wavefunction |ψ1(y)|2|\psi_{1}(y)|^{2}. Right: Given a measurement of oscillator displacement yy^{\prime}, smaller magnitudes of yy^{\prime} increase the probability of measuring the beam in its original momentum state k0\hbar k_{0} (top right), and larger magnitudes of yy^{\prime} increase the probability of measuring the beam in its reduced momentum state k1\hbar k_{1} (bottom right).

These results are summarized in Fig. 5, which uses all the same model parameters as in Figs. 3 and 4. If the beam momentum is measured first, this changes our predictions for the oscillator displacement probabilities. If the oscillator displacement is measured first, this changes our predictions for the beam momentum probabilities.

While such claims are undoubtedly of academic interest, we should concede how minimally they bear on most real experiments. To make an analogy with real experiments, the “oscillator” is just the sample being studied, and the “beam” is just the probe being used. Given the results of Fig. 5, why is the order of quantum measurements not a critical part of all experimental protocols?

It is because any “measurement” typically involves further interactions, and thus further branching and entanglement. The entanglement of the sample with the probe allows experimental measurements of the probe to tell us something about the sample 17, but it typically is difficult to make further measurements on the sample that preserve quantum coherence. After all, most quantum systems whose positions can be pinned down (e.g., an atomic defect in a crystal) interact with their substrates and the beam alike, and the intrusions of environmental decoherence conspire to obviate the need for such worries.18

VIII Conclusion

What, then, has been learned? Three complementary approaches to a simple model Hamiltonian yield results that conceptually differ, but quantitatively match. In the classical approach, the beam particle transfers a predictable quantity of energy to the oscillator as it passes. When the classical oscillator is replaced by a quantum oscillator, the quantum oscillator’s displacement expectation value oscillates with an amplitude matching that of the classical oscillator, and the quantum amplitude of the first excited state has a magnitude that is directly proportional to the classical amplitude. When both the beam particle and the harmonic oscillator are treated as quantum objects, however, the interaction between the two objects induces entanglement. The conditions allowing these three approaches to match were explored, and the consequences of partial wavefunction “collapse” on measurements of entangled systems were demonstrated.

ACKNOWLEDGMENTS

The anonymous reviewers and the journal editor offered helpful suggestions that improved this manuscript.

AUTHOR DECLARATIONS

Conflict of Interest

The author has no conflicts of interest to disclose.

Code Availability

The Python scripts used to generate figures are available in the Supplemental Materials.

Appendix A Classical Work Calculation

To calculate the classical work done on the beam as it passes the harmonic oscillator, one can rewrite the work integral as an integral over time

Wbeam=+𝑑xFx=+v𝑑t[αy(t)1vdfdt],W_{\mathrm{beam}}=\int_{-\infty}^{+\infty}dx\cdot F_{x}=\int_{-\infty}^{+\infty}vdt\left[\alpha y(t)\frac{1}{v}\frac{df}{dt}\right],

insert y(t)y(t) (from y(ω)y(\omega) in Eq. 9) as an inverse Fourier transform

Wbeam=α+𝑑t[(12π+𝑑ωeiωtαf~(ω)μ(ω2ω02))dfdt],W_{\mathrm{beam}}=\alpha\int_{-\infty}^{+\infty}dt\left[\left(\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{+\infty}d\omega e^{-i\omega t}\frac{-\alpha\tilde{f}(\omega)}{\mu(\omega^{2}-\omega_{0}^{2})}\right)\frac{df}{dt}\right],

and reverse the order of the time and frequency integrals:

Wbeam=α2μ+𝑑ωf~(ω)(ω2ω02)12π+𝑑teiωtdfdt.W_{\mathrm{beam}}=-\frac{\alpha^{2}}{\mu}\int_{-\infty}^{+\infty}d\omega\frac{\tilde{f}(\omega)}{(\omega^{2}-\omega_{0}^{2})}\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{+\infty}dt\,e^{-i\omega t}\frac{df}{dt}.

The time integral can be made into the complex conjugate of a Fourier transform after an integration by parts, and the frequency integral may be performed by slightly displacing the poles off the real axis by iϵi\epsilon:

Wbeam=α2μ+𝑑ωf~(ω)(iω)f~(ω)(ωω0+iϵ)(ω+ω0iϵ).W_{\mathrm{beam}}=-\frac{\alpha^{2}}{\mu}\int_{-\infty}^{+\infty}d\omega\frac{\tilde{f}(\omega)(-i\omega)\tilde{f}^{*}(\omega)}{(\omega-\omega_{0}+i\epsilon)(\omega+\omega_{0}-i\epsilon)}.

Using the residue theorem, we find

Wbeam=πα2μ|f~(ω0)|2.W_{\mathrm{beam}}=-\frac{\pi\alpha^{2}}{\mu}\left|\tilde{f}(\omega_{0})\right|^{2}. (75)

This is the expression reported above as Eq. 10.

References

  • 1 See, for instance, Chapters 1.1, 4.1, and 4.6 of Kenneth S. Krane, Modern Physics, Fourth Edition (Wiley, 2021).
  • 2 Daniel V. Schroeder, “Entanglement isn’t just for spins,” Am. J. Phys. 85, 11 (2017).
  • 3 A.A. Lucas and M. Šunjić, “Fast-electron spectroscopy of collective excitations in solids,” Progress in Surface Science, 2, 2 (1972).
  • 4 Stephen K. Knudson, “Solution of a simple inelastic scattering model,” Am. J. Phys. 43, 11 (1975).
  • 5 Charles Cherqui, Niket Thakkar, Guoliang Li, Jon P. Camden, and David J. Masiello, “Characterizing Localized Surface Plasmons Using Electron Energy-Loss Spectroscopy,” Annu. Rev. Phys. Chem. 67, 331–57 (2016).
  • 6 Wendell G. Holladay, “The nature of particle-wave complementarity,” Am. J. Phys. 66, 1 (1998).
  • 7 In fact, the electrostatic potential for a dipole oriented along the vertical axis (see Fig. 1) would require a window function f(x)=b/(x2+b2)3/2f(x)=b/(x^{2}+b^{2})^{3/2}, which would allow the energy transfer to the harmonic oscillator to be expressed in terms of a modified Bessel function: WHO=(2α2ω02/μv4)K12(bω0/v)W_{\mathrm{HO}}=\left(2\alpha^{2}\omega_{0}^{2}/\mu v^{4}\right)K_{1}^{2}\left(b\,\omega_{0}/v\right). A similar expression for dipole scattering can be found in Eq. 4 of C. Dwyer, “Localization of high-energy electron scattering from atomic vibrations,” Phys. Rev. B, 89 (5), 054103 (2014).
  • 8 For an elementary tutorial, see Daniel V. Schroeder, Physics Simulations in Python: A Lab Manual (2018), p. 15-17. Available online at <https://physics.weber.edu/schroeder/scicomp/PythonManual.pdf>.
  • 9 This discussion closely follows the treatment of R. Shankar, Principles of Quantum Mechanics (Plenum Press, 1980), p. 482-483.
  • 10 For an elementary tutorial, see Ian Cooper, “Solving the [1D] Time Dependent Schrodinger Equation with the Finite Difference Time Development method,” in Doing Physics With Matlab (2021). Available online at <https://d-arora.github.io/Doing-Physics-With-Matlab/mpDocs/se_fdtd.pdf>. More advanced methods are discussed in Wytse van Dijk, “On numerical solutions of the time-dependent Schrödinger equation,” Am. J. Phys. 91, 8 (2023).
  • 11 Interactive animations showing this process have been shared by Erik Koch in his course materials for Applied Quantum Mechanics (2021). Available online at <https://www.cond-mat.de/teaching/QM/JSim/wpack.html>.
  • 12 The “partially quantum” approach of Sec. V is simple enough that it can be solved exactly, as is done in Lucas and Šunjić 3, yielding probabilities for oscillator energy eigenstates |n\ket{n} of eP1P1n/n!e^{-P_{1}}P_{1}^{n}/n! (i.e., the probabilities form a Poisson distribution). Higher-order contributions to a scattering wavefunction could be constructed using this, but little would be gained beyond algebraic clutter.
  • 13 The approximate wavefunction of Eq. 59 is nearly normalized since P1P_{1} is small, but readers who would like strict normalization may introduce a 1P1\sqrt{1-P_{1}} before the first term. Again, little would be gained.
  • 14 Nicholas Wheeler, “Remarks concerning the status & some ramifications of Ehrenfest’s Theorem,” in Quantum Mechanics: Miscellaneous Essays (1998). Available online at <https://www.reed.edu/physics/faculty/wheeler/documents/Quantum%20Mechanics/Miscellaneous%20Essays/Ehrenfest’s%20Theorem.pdf>.
  • 15 David H. McIntyre, Quantum Mechanics: A Paradigms Approach (Pearson, 2012), p. 46.
  • 16 Y.D. Chong, “Quantum Entanglement: Partial Measurements,” in Quantum Mechanics III (2021). Available online at <https://phys.libretexts.org/Bookshelves/Quantum_Mechanics/Quantum_Mechanics_III_(Chong)/03%3A_Quantum_Entanglement/3.02%3A_Partial_Measurements>.
  • 17 A helpful overview of how the entanglement of probes and samples leads to experimental outcomes can be found Section 3 of Christian Dwyer, “Atomic-Resolution Core-Level Spectroscopy in the Transmission Electron Microscope,” in Advances in Imaging and Electron Physics: Volume 175 (Elsevier, 2013), edited by Peter W. Hawkes.
  • 18 E. Joos, “Elements of Environmental Decoherence,” in Decoherence: Theoretical, Experimental, and Conceptual Problems (Springer-Verlag, 2000), edited by P. Blanchard, D. Giulini, E. Joos, C. Kiefer, and I.-O. Stamatesch.