Diophantine equations of the form over function fields
Abstract.
Let and be (not necessarily distinct) prime numbers and be a global function field of characteristic with field of constants . Assume that there exists a prime of which has degree , and let be the subring of consisting of functions with no poles away from . Let be a polynomial in with coefficients in . We study solutions to diophantine equations of the form which lie in , and in particular, show that if and satisfy additional conditions, then there are no non-constant solutions. The results obtained apply to the study of solutions to in certain rings of integers in -extensions of known as constant -extensions. We prove similar results for solutions in the polynomial ring , where is any field of characteristic , showing that the only solutions must lie in . We apply our methods to study solutions of diophantine equations of the form , where are integers.
1. Introduction
Let be an integer and be a finite field of characteristic . Let be a global function field with field of constants and assume that there exists a prime of of degree . In other words, we assume that there is a prime , which is totally inert in the composite . The ring of integers shall consist of all functions with no poles away from . Given a polynomial with coefficients in , we study solutions to the diophantine equation for which both and lie in . More precisely, we prove that if certain additional conditions are met, then there are no non-constant solutions, i.e., and must both belong to the field of constants . Equations of the form are of significant interest. We shall apply our analysis to study a class of diophantine equations which involve perfect powers in arithmetic progressions. Let be integers and let , then, there has been significant interest in the classification of integral solutions to the diophantine equation
cf. for instance, [BGP04, BZ13, Haj15, BPS17, BPSS18, KP18, Pat18, AGP20].
We also explore themes motivated by the Iwasawa theory of function fields. Mazur initiated the Iwasawa theory of elliptic curves over number fields (cf. [Maz72]), which had applications to the study of growth of Mordell–Weil ranks of elliptic curves in certain infinite towers of number fields. One hopes to extend such lines of investigation to curves of higher genus (cf. [Ray22]) and more generally, study the stability and growth of solutions to any diophantine equation in an infinite tower of global fields. In this paper, we shall study certain function field analogues of such questions, however, instead of elliptic curves, we consider the class of diophantine equations of the form , where has constant coefficients. Let us explain our results in greater detail. Given any integer , there is a unique extension such that is isomorphic to . Given a prime , set to denote and set to denote the composite . This gives rise to a tower of function field extensions
Let denote the ring of -adic integers, i.e., the valuation ring of . The constant -extension of is the infinite union
It is easy to see that the Galois group is isomorphic to . Let denote the class number of (cf. [Ros02, Chapter 5]). Note that since is assumed to have degree , it remains inert in for all . Let (resp. ) be the ring of integers of (resp. ), i.e., the functions with no poles away from . We now state the main result.
Theorem (Theorem 3.2).
Let be a prime number and be a global function field of characteristic . Let be the field of constants of , and let and be prime numbers that are not necessarily distinct. Assume that . Let be a polynomial with coefficients in satisfying following conditions.
-
(1)
The polynomial factorizes into
where and are distinct elements in , are positive integers and .
-
(2)
At least two of the exponents are not divisible by .
Then, the following assertions hold.
-
(1)
Suppose that and are distinct. Then, for all sufficiently large numbers , the only solutions to that are contained in are constant.
-
(2)
Suppose that , then the only solutions to that are contained in are constant.
As a consequence of the above result, we find that for any prime , there are only finitely many numbers , that are not powers of , for which has solutions in . A more specific criterion applies to any function field , cf. Theorem 2.4. The methods used in proving the above result are applied to study another question of independent interest. Let be a field of positive characteristic and be the polynomial ring .
Theorem (Theorem 4.1).
With respect to above notation, let be a polynomial with all of its coefficients and roots in . Let be a prime number and assume that the following conditions are satisfied.
-
(1)
factorizes into
where and are distinct elements in , are positive integers and .
-
(2)
At least two of the exponents are not divisible by .
Then, any solution to
(1.1) |
is constant, i.e., and are both in .
It follows from the above result that if is not a power of , then does not have non-constant solutions in .
Organization: Including the introduction, the manuscript consists of sections. In section 2, we prove criteria for the constancy of solutions to in global function fields . The main result proven in section 2 is Theorem 2.4. In section 3, we extend the results in section 2 to prove the constancy of solutions to the above equation in -extensions of . It is in this section that we prove the main result of the paper, i.e., Theorem 3.2. In section 4, we prove similar results for the polynomial rings over a field. Finally, in section 5, we study the specific case when .
2. Constancy of solutions to in a global function field
In this section, we introduce basic notions and prove results about the solutions to certain diophantine equations over global function fields. Throughout this section, be a prime number and be an integral domain of characteristic with field of constants . We introduce the notion of a discrete valuation on .
Definition 2.1.
A function is said to be a discrete valuation if the following conditions are satisfied.
-
(1)
The values taken by are non-negative.
-
(2)
Let be the identity element of , we have that .
-
(3)
Given non-zero elements , we have that ,
-
(4)
,
-
(5)
suppose that , then .
Let be the subring of consisting of all elements for which . Given , we say that divides if for some . It is clear that if divides then .
Lemma 2.2.
Proof.
Suppose by way of contradiction that , or . Assume first that . Set , from (2.1), we find that divides . As a result, , hence by the property (5), we find that
Therefore, we have deduced that . Rewrite (2.1) as
and expand the left hand side of the above equation via the binomial expansion
Note that since , we find that for all such that ,
and therefore,
This implies that , a contradiction. On the other hand, if we assume that (instead of assuming that ), the same argument applies. ∎
We shall illustrate the above result in various cases of interest. In this section, we study diophantine equations over global function fields . Let be a prime number and denote by the finite field with elements (i.e. ). Fix an algebraic closure of . Let be the algebraic closure of in , and let be the algebraic closure of in . Set to denote the composite of with .
Following [Ros02, Chapter 5], a prime of is by definition the maximal ideal of a discrete valuation ring with fraction field equal to . A divisor of is a finite linear combination of primes . In the above sum, are all integers, and the set of primes for which is referred to as the support of . Given a function , denote by the associated principal divisor. Note that any principal divisor has degree . Two divisors are considered equivalent if the differ by a principal divisor. The class group of is the group of divisor classes of degree , and has finite cardinality (cf. [Ros02, Lemma 5.6]). Denote by the class number, i.e., the number of elements in the class group. Given a natural number , denote by the cardinality of the -torsion in class group.
The field is identified with the field of fractions of a projective algebraic curve over . A point is also referred to a prime of , since it corresponds to a valuation ring with fraction field . Given a prime of and a prime of , we say that lies above (or divides) if the natural inclusion of fields induces an inclusion of valuation rings . Given a function (resp. ), denote by (resp. ) the order of vanishing of at (resp. ). We refer to (resp. ) the order of the pole of at (resp. ). Given a finite and nonempty set of primes of , the ring of -integers consists of all functions such that for all primes . Let be the set of primes of that lie above . Let denote the composite . A function satisfies the property that for all , . According to our conventions, is the ring of integers where . Since is a prime of degree , is totally inert in . By abuse of notation, the single prime in is also denoted .
We list some basic properties of the function on . The following result applies for any ring of -integers.
Lemma 2.3.
Let and be a functions in and be a point in . Then, the following assertions hold.
-
(1)
Suppose that for all , then, is a constant function,
-
(2)
,
-
(3)
suppose that , then, .
Proof.
Note that since is contained in , for all points . Therefore, the assumption that implies that has no poles, and thus must be a constant function. This proves part (1).
Part (2) clearly follows from the relation .
For part (3), we note that , and since it is assumed that , it follows that vanishes at . As a result, and thus,
which proves the result. ∎
Recall that is a prime of degree and is the associated ring of integers in .
Theorem 2.4.
Let be a prime number and be a global function field of characteristic . Let be the ring of integers of . Denote by the field of constants of . Let be a polynomial with coefficients in . Let be a prime number and let be the least integer such that . Assume that the following conditions are satisfied.
-
(1)
factorizes into
where and are distinct elements in , are positive integers and .
-
(2)
At least two of the exponents are not divisible by .
Then, any solution to
(2.2) |
for which is constant, i.e., and are both in .
Proof.
Since the elements are distinct elements of , we find that for all such that , is a non-zero element of . Therefore, for , the divisors and have disjoint supports.
From the equation (5.3), we find that
(2.3) |
Since the divisors in the above sum have disjoint supports, and therefore for all , there are divisors such that . Recall that it is assumed that there are two distinct indices and such that and . Without loss of generality, assume that and . Therefore, there exist divisors and such that for . The divisor classes and in the class group are in the -torsion subgroup of the class group. Since , we find that is principal for . Let and be functions in such that
Thus we find that and , where and are contained in . Note that since has no poles away from , the same is true for and , hence, . Setting , we may replace by and by , and thus assume that and for some elements . We find that is a non-zero element of . The pair satisfies the properties (1) to (5), and therefore by Lemma 2.2. Therefore, by part (1) of Lemma 2.3, we find that and are both in . Hence, is in and thus so is . ∎
Remark 2.5.
We make the following observations.
-
•
Theorem 2.4 above implies that if .
-
•
If the roots are not contained in , we may base change by an extension of which is generated by the roots .
-
•
Suppose that satisfies the conditions of Theorem 2.4. Then, since for all but finitely many primes , thus has no non-constant solutions in for all but finitely many primes . In fact, it is easy to see that Theorem 2.4 implies that has no non-constant solutions for all but finitely many natural numbers .
3. Constancy of solutions to in the constant -extension of a function field
In this section, we apply Theorem 2.4 proven in the previous section, to study questions motivated by Iwasawa theory. Given primes and (not necessarily distinct) let denote , the cardinality of the -torsion in the class group of .
Theorem 3.1 (Leitzel, Rosen).
Let and be (not necessarily distinct) prime numbers and be a function field of characteristic . The following assertions hold
-
(1)
Suppose that and are distinct. Then, as goes to infinity, the quantity is bounded.
-
(2)
Suppose that does not divide . Then, for all .
Proof.
Recall notation from the introduction. The prime is totally inert in for any prime . We set to denote the ring of integers of , i.e., the functions with no poles outside . The following is the main result of this manuscript.
Theorem 3.2.
Let be a prime number and be a global function field with field of constants . Let and be prime numbers that are not necessarily distinct, and assume that . Let be a polynomial with coefficients in satisfying the conditions of Theorem 2.4.
Then, the following assertions hold.
-
(1)
Suppose that and are distinct. Then, for all sufficiently large numbers , the only solutions to in are constant.
-
(2)
Suppose that , then the only solutions to in are constant.
Proof.
First, we consider the case when . It follows from part (1) of Theorem 3.1 that is bounded as goes to infinity. Let be such that be larger than . It follows from Theorem 2.4 that has no non-constant solutions in for all , and therefore, no non-constant solutions in . Hence, there are no non-constant solutions in as well.
4. Constancy of solutions to in a polynomial ring in -variables
In this section, we study solutions to equations of the form in polynomial rings over a field. Let be any field of characteristic and be the polynomial ring . Given a polynomial , let be the degree of viewed as a polynomial in over the subring . The pair satisfies the conditions (1)–(5) of Definition 2.1. The class group denotes the group of equivalence classes of Weil divisors. Since is a unique factorization domain, we have that .
Theorem 4.1.
With respect to above notation, let be a polynomial with all of its coefficients in . Let be a prime number and assume that the following conditions are satisfied.
-
(1)
factorizes into
where and are distinct elements in , are positive integers and .
-
(2)
At least two of the exponents are not divisible by .
Then, any solution to
(4.1) |
is constant, i.e., and are both in .
Proof.
Note that the algebraic closure of in is equal to . We may as well replace by its algebraic closure and assume without loss of generality the is algebraically closed and that and . Since the class group of is trivial, the same argument as in the proof of Theorem 2.4 shows that and for . Therefore, we find that , an element of . Lemma 2.2 then implies the for all , hence are both in . The result follows from this. ∎
5. Perfect powers that are sums of powers in arithmetic progressions
In this section, we apply the results proven in previous sections to study the solutions of the diophantine equation involving perfect powers in arithmetic progressions
(5.1) |
Here, are integers such that and . Viewing as a polynomial with integral coefficients let denote its discriminant.
Theorem 5.1.
Let be a function field with characteristic and field of functions . Let be a prime. Assume that the following conditions are satisfied.
-
(1)
All roots of are contained in ,
-
(2)
,
-
(3)
at least one of the following conditions are satisfied:
-
(a)
,
-
(b)
and .
-
(a)
Let be the minimal value such that . Then, there are no non-constant solutions to
in .
Proof.
Following notation from the statement of Theorem 2.4, we write
where are all distinct elements of . The result follows from Theorem 2.4 provided the following conditions are satisfied
-
(1)
.
-
(2)
At least two of the exponents are not divisible by .
Note that if , then all roots of are distinct in , hence, for all and . In particular, both of the above conditions are satisfied.
On the other hand, assume that . Clearly, all values are less than or equal to , and since , it follows that for all . It suffices to check that if . Suppose not, then is of the form , for some .
Expanding , one obtains
Since and , we find that
for all values of . In particular, we find that
Theorem 5.2.
Let be a function field with characteristic and field of functions . Let be a prime. Assume that the following conditions are satisfied.
-
(1)
All roots of are contained in ,
-
(2)
,
-
(3)
at least one of the following conditions are satisfied:
-
(a)
,
-
(b)
and .
-
(a)
Let be any prime number. The following assertions hold.
-
(1)
Suppose that . Then for all large enough values of , there are no non-constant solutions to in .
-
(2)
Suppose that and . Then, there are no non-constant solutions to in .
Proof.
Theorem 5.3.
Let be a field of characteristic and let be the polynomial ring . Let be a prime. Assume that the following conditions are satisfied.
-
(1)
All roots of are contained in ,
-
(2)
,
-
(3)
at least one of the following conditions are satisfied:
-
(a)
,
-
(b)
and .
-
(a)
Then, any solution to
(5.3) |
is constant, i.e., and are both in .
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