Geometry of Spaces of Orthogonally Additive Polynomials on
Abstract
00footnotetext: Keywords: Orthogonally additive; Homogeneous polynomial; Banach Lattice; Regular Polynomial; Extreme point; Exposed point; Isometry.00footnotetext: MSC(2010): 46G25; 46G20; 46E10; 46B42; 46B04; 46E27.We study the space of orthogonally additive -homogeneous polynomials on . There are two natural norms on this space. First, there is the usual supremum norm of uniform convergence on the closed unit ball. As every orthogonally additive -homogeneous polynomial is regular with respect to the Banach lattice structure, there is also the regular norm. These norms are equivalent, but have significantly different geometric properties. We characterise the extreme points of the unit ball for both norms, with different results for even and odd degrees. As an application, we prove a Banach-Stone theorem. We conclude with a classification of the exposed points.
1 Introduction
A real function on a Banach lattice is said to be orthogonally additive if whenever and are disjoint. Non-linear orthogonally additive functions on function spaces often have useful integral representations — see, for example the papers of Chacon, Friedman and Katz [8, 12, 13], Mizel [21] and Rao [24]. In 1990, Sundaresan [26] initiated the study of orthogonally additive -homogeneous polynomials with particular reference to the spaces and for . Building on the work of Mizel, he showed that, for every orthogonally additive -homogeneous polynomial on with , there exists a unique function , where , such that
(1) |
for every . When , there are no non-zero orthogonally additive -homogeneous polynomials on . He went on to show that the Banach space of orthogonally additive -homogeneous polynomials on is isometrically isomorphic to where the latter space is equipped not with the usual norm, but with the equivalent norm .
The next significant development was the discovery of an integral representation for orthogonally additive -homogeneous polynomials on spaces by Pérez and Villanueva [23] and by Benyamini, Lassalle and Llavona [3], who proved a representation of the form
(2) |
where is a regular Borel signed measure on . The integral representations (1) and (2) have been extended and generalized in various directions in recent years. See, for example, [22, 17, 1, 30].
Orthogonally additive -homogeneous polynomials are also of interest in the study of multilinear operators on Banach lattices and, more generally, on vector lattices. If are vector lattices, an -linear mapping is orthosymmetric if whenever and are disjoint for some pair of distinct indices . Orthosymmetric multilinear mappings are automatically symmetric [4]. In [5], Bu and Buskes prove that an -linear function is orthosymmetric if and only if the associate -homogeneous polynomial is orthogonally additive.
Let be a Banach lattice. For every positive element of , we may form the principal ideal
with lattice structure inherited from and the norm defined by . With this norm, is a Banach lattice. By virtue of the Kakutani representation theorem [16], the Banach lattice is canonically Banach lattice isometrically isomorphic to for some compact Hausdorff topological space , with being identified with the unit function on . The Banach lattice structure of is uniquely determined by its principal ideals. It follows that an analysis of the orthogonally additive -homogeneous polynomials on is central to an understanding of the behaviour of orthogonally additive -homogeneous polynomials on general Banach lattices.
In this paper, we focus on the geometric properties of the spaces of orthogonally additive -homogeneous polynomials on . There are two phenomena that are of particular interest. The first is that there are two natural ways to norm the space . The first is the norm of uniform convergence on the unit ball of , given by . In this norm, is a Banach space. Now also has a lattice structure and so another choice of norm is the regular norm, defined by , where is the absolute value of . In this norm, is a Banach lattice. The existence of these two norms was first observed by Bu and Buskes [5] and is hinted at in the paper of Sundaresan [26]. These norms are equivalent, but we shall see that they have significantly different geometric properties.
The second phenomenon is the influence of the parity of the degree on the structure of the space for the two norms. Bu and Buskes [5] showed that, when is odd, the supremum and regular norms on are the same and that they are equivalent when is even. We sharpen their results, using the strategy of working first on and then extending to general Banach lattices. The integral representation (2) gives a canonical isomorphism between and , the space of regular Borel signed measures on . The regular norm on corresponds to the usual variation norm on , but the supremum norm is identified with a different norm on , given by . We show that is isometrically isomorphic to the dual space of , where is endowed with the norm and we show that this norm is closely related to the diameter seminorm (see, for example, [6]). We use these identifications to give a complete description of the extreme points of the unit ball of for both norms, extending the results in [7]. Our starting point is a characterisation of the extreme points in for the norm and for the norm . This allows us to prove a Banach-Stone theorem for .
We finish with a study of the exposed points of the unit ball of the space . The identification of this space with the space of measures , which is a dual space for both norms, allows us to use the theory of Šmul’yan [28, 29]. Using this machinery, we characterise the weak∗ exposed and the weak∗ strongly exposed points of the unit ball.
Preliminaries
Let be a real Banach space and let be a natural number. A function is an -homogeneous polynomial if there exists a necessarily unique, bounded -linear function such that for all . We write if and are related in this way. The space of -homogeneous polynomials is a Banach space with the supremum norm,
The Banach space is a dual space. We refer to the book by Dineen [10] for this and other facts about -homogeneous polynomials.
Now assume that is a Banach lattice. A partial order is defined on by if for all . In particular, an -homogeneous polymonial is said to be positive if in the sense of this order and is regular if it is the difference of two positive -homogeneous polynomials. The regular polynomials are precisely those that have an absolute value, which is given by the formula
(3) |
where denotes the set of partitions of , namely, all finite sets of positive elements of whose sum is [5].
The space of regular -homogeneous polynomials on is a Banach lattice with the regular norm,
We have and in general these norms are not equivalent on . Every regular -homogeneous polynomial can be decomposed canonically as the difference of two positive -homogeneous polynomials, so that and . We refer to the paper of Bu and Buskes [5] for further details. For example, they show that is a dual Banach lattice.
Let be a compact, Hausdorff space. The space of continuous real functions on is a Banach lattice with the supremum norm, . We denote by the space of regular Borel signed measures on . Then the Banach lattice dual of can be identified with under the variation norm, which we denote by . Thus,
where , are the positive and negative parts of .
2 Orthogonally additive -homogeneous polynomials
Let be a Banach lattice and a positive integer. A function is called an orthogonally additive -homogeneous polynomial if is a bounded -homogeneous polynomial with the property that whenever are disjoint. The space of orthogonally additive -homogeneous polynomials on is denoted by . It is easy to see that is a closed subspace of the space of bounded -homogeneous polynomials with the supremum norm. Thus , with this norm, is a Banach space. When , this space is simply the dual space , since every bounded linear functional is orthogonally additive.
We have the following integral representation for orthogonally additive -homogeneous polynomials on spaces, due to Pérez-García and Villanueva [23] and Benyami, Lassalle and Llavona [3] (see also [7]).
Theorem 1.
Let be a compact, Hausdorff topological space. For every orthogonally additive -homogeneous polynomial on there is a regular Borel signed measure on such that
for all .
In general, there is no guarantee that a Banach lattice supports any non-trivial orthogonally additive polynomials of degree greater than one. Sundaresan [26] showed that there are no non-zero orthogonally additive -homogeneous polynomials on for . In the case of , it is easy to see that an -homogeneous polynomial is orthogonally additive if and only if there exists a bounded sequence of real numbers, , such that
for every , and that . Thus is isometrically isomorphic to for every .
To put the results of the previous paragraph in a general context, we recall that a Banach lattice is an AL-space if the norm is additive on the positive cone: for all . The Kakutani representation theorem [15, 18] states that every AL-space can be decomposed into a disjoint sum of copies of and spaces. Accordingly, is Banach lattice isometrically isomorphic to a space of the form
In this representation, the unit basis vectors in are in one-to-one correspondence with the atoms in of unit norm. We recall that a positive element of is said to be an atom if implies that is a scalar multiple of . We can write the second component in this representation as , where is the product of the Lebesgue measures on the sets . Thus, we see that can be represented as the disjoint sum , where the measure is nonatomic.
Proposition 1.
Let be an AL-space and let . There is a non-zero orthogonally additive -homogeneous polynomial on if and only if contains at least one atom.
Proof.
Let be the Kakutani representation of as described above.
Suppose that contains an atom. Then the set in the Kakutani representation is non-empty. Choose and define for and for . Then is a non-zero orthogonally additive -homogeneous polynomial.
Conversely, suppose that has no atoms. Then the Kakutani representation of is where the measure is nonatomic. The proof in this case can be gleaned from [26], but we can give a direct proof as follows. We treat the case for simplicity. Suppose that is an orthogonally additive -homogeneous polynomial on , where is nonatomic. Let be the bounded, symmetric bilinear form that generates . Then is orthosymmetric: if are disjoint, then [5, Lemma 4.1]. It follows from the fact that is isometrically isomorphic to that there exists such that
If we take , to be the characteristic functions of arbitrary disjoint measurable sets, this integral is zero and so we have
for all , where is the diagonal. However, if has no atoms, then the product measure of the diagonal is zero. Hence for every . ∎
The Banach lattices , where is nonatomic, do not support any real valued lattice homomorphisms. Our next result indicates that the existence of non-trivial -homogeneous orthogonally additive polynomials on a Banach lattice is closely related to the existence of lattice homomorphisms.
Proposition 2.
Let be a Banach lattice, let and let . The -homogeneous polynomial defined by is orthogonally additive if and only if either or is a lattice homomorphism.
Proof.
Suppose that or is a lattice homomorphism. Then if and are disjoint, we have either or and so .
Conversely, suppose that is orthogonally additive. For every , the vectors and are disjoint for all . Therefore
for every . Hence either or . If we can show that (or ) is positive, then it follows that (or ) is a lattice homomorphism.
Let be a positive element of . The principal ideal generated by is isometrically Banach lattice isomorphic to for some compact Hausdorff topological space . The functional is represented by a regular Borel signed measure on and the fact that or for all implies that the support of consists of a single point. It follows that either or is positive on . Now is the union of the principal ideals , which are upwards directed by inclusion. Thus, if (or ) is positive on one , then (or ) is positive on all of . ∎
A Banach lattice is an AM-space if the norm has the property that implies . In contrast with AL-spaces, there is a good supply of orthogonally additive -homogeneous polynomials on every AM-space. The Kakutani representation theorem for AM-spaces [16] shows that the real valued lattice homomorphisms on an AM-space separate the points of . It follows that there is a rich supply of orthogonally additive -homogeneous polynomials of every degree on .
We now look at some properties of orthogonally additive polynomials on general Banach lattices. Our starting point is the fact that every orthogonally additive -homogeneous polynomial on a Banach lattice is regular. This has been shown by Toumi [27, Theorem 1]. One may also argue as follows. Let be an orthogonally additive -homogeneous polynomial on a Banach lattice . As is the upwards directed union of its principal ideals, it suffices to show that is regular on each of them. Since each principal ideal is Banach lattice isometrically isomorphic to a , we can use the integral representation in Theorem 1. Then the Jordan decomposition of the representing measure gives a decomposition of the polynomial into the difference of two positive orthogonally additive -homogeneous polynomials. Therefore is regular.
Let be a regular -homogeneous polynomial on . The absolute value of is given by [5, 19]
(4) |
for , where denotes the set of partitions of , namely, all finite sets of positive vectors whose sum is . In general, we have
(5) |
for every and is the smallest positive -homogeneous polynomial, in the sense of the lattice structure of , with this property. The space is a Banach lattice in the regular norm,
It follows from (5) that for every . In general, these norms are not equivalent.
Now is complete in the regular norm; indeed, it is even a dual Banach lattice [5, Theorem 5.4]. It follows that the supremum and regular norms are equivalent on this space. Thus, there is a sequence of positive real numbers such that for every and every . Bu and Buskes [5] show that the two norms are the same for odd values of . For even values of , they show that , the polarization constant. We shall show that, in fact, for even values of and that this is sharp. This will follow from estimates we give for the value of at positive points in .
If is a bounded linear functional on , then [20]
for every . It would be suprising if there were such a simple formula for when is a regular -homogeneous polynomial. As a linear functional, acts on an -fold symmetric tensor power of and the set of vectors satisfying is now a set of tensors, rather than elements of . However, if is orthogonally additive, it is possible to establish a relatively simple estimate for the values of .
Theorem 2.
Let be an orthogonally additive -homogeneous polynomial on the Banach lattice .
-
(a)
If is odd, then
for every in .
-
(b)
If is even, then
for every in .
Proof.
Let . It follows from (3) that the value is unchanged if we consider as an -homogeneous polynomial on the principal ideal generated by . Now is Banach lattice isomorphic to for some compact topological space . Since is orthogonally addive there exists a regular signed Borel measure on such that
for every . The symmetric -linear form on that generates is given by
Thus, for ,
and it follows that
for .
Now in general, for a nonnegative function we have
Therefore
where we are identifying elements of with continuous functions on . We now consider separately the cases where is odd and even.
(a) We first consider the case when odd.
If , let .
Then and . Therefore
Thus we have
and it is easy to see that the reverse inequality also holds.
(b) We now consider the case when even.
We have
Given satisfying , we define by
Then , and so
It follows from that . Therefore
(6) |
since is even.
∎
To see that the bound in (6) for even values of is sharp, consider the example on with any Banach lattice norm. The bound is attained for the vector .
Corollary 1.
Let is an orthogonally additive -homogeneous polynomial on a Banach lattice . Then if is odd and if is even. These inequalities are sharp.
3 Orthogonally additive polynomials on
In this section, we study the supremum and regular norms on the spaces of orthogonally additive -homogeneous polynomials on .
The integral representation for orthogonally additive -homogeneous polynomials on allows us to identify the vector space with , the space of regular Borel signed measures on . The natural norm on is the dual norm. This is the variation norm for measures: . We shall see that this norm corresponds to the regular norm on the spaces of orthogonally additive -homogeneous polynomials. However, the supremum norm on corresponds to a different, but equivalent norm on the space of regular Borel signed measures.
The space is a Banach lattice with the regular norm, as is the dual Banach lattice with the variation norm. We shall see that the lattice structures of these two Banach lattices are the same. We note that the lattice structure of as the dual of is the same as the lattices structure of considered as a sublattice of the lattice of Borel signed measures on . In other words, a measure is positive, in the sense that for every nonnegative , if and only if for every Borel subset of [25, Theorem 2.18].
Proposition 3.
Let be a compact Hausdorff topological space and let be an orthogonally additive -homogeneous polynomial on , given by
Then the absolute value of is given by
Proof.
To prove the reverse inequality, we start with the definition of the absolute value:
for Taking each of to be the trivial partition gives
applying the partition form of the Riesz-Kantorovich formula for the absolute value of a linear functional [2, Theorem 1.16] to the measure in and using the fact that .
∎
Theorem 3.
Let be a compact, Hausdorff space. Let be given by
-
(a)
For every , is a Banach lattice isometric isomorphism from onto .
-
(b)
If is odd, then the regular and supremum norms coincide on and so is an isometric isomorphism for the supremum norm on .
-
(c)
If is even, then is an isometric isomorphism for the norm on defined by
and the supremum norm on .
Proof.
Cleary, is linear and surjective. To see that it is injective, suppose that the -homogeneous polynomial is zero. The associated symmetric -linear form is
and so for all . Taking , we have for every and so .
(a) Clearly, is positive. If we show that is also positive, then it will follow that is a lattice homomorphism [2, Theorem 7.3]. Let be a positive element of , with satisfying . Then, for every nonnegative , we have and so is positive. Therefore is a lattice isomorphism for every .
By Proposition 3, the regular norm of is , since is increasing on the positive cone of . Therefore is both a lattice isomorphism and an isometry.
(b) This has already been proved in Corollary 1.
(c) Let and let . It follows from (a) that and . We have
for every . As for and is even, it follows that .
Now let be a Hahn decomposition of , with positive on and negative on . If is compact, then by a standard argument using Urysohn’s lemma (see, for example, [14, Theorem 12.41]) there is a decreasing sequence of continuous functions on with values in that converges almost everywhere with respect to to , the characteristic function of . Then, by the bounded convergence theorem,
It follows from the regularity of that . Similarly, . Therefore . ∎
We summarize the identifications of the various norms, bearing in mind that the supremum and regular norms coincide for positive polynomials.
Corollary 2.
Let be an orthogonally additive -homogeneous polynomial on , with corresponding measure . Then
-
(a)
.
-
(b)
If is odd, then .
-
(c)
If is even, then .
We note that the norm is easily seen to be equivalent to the dual (variation) norm on . In fact, we have
for every .
It will be useful to have an alternative expression for the norm on . Using the identity for non-negative real numbers, we have
Thus, we have
(7) |
These results clarify the geometric properties of the spaces ; for the regular norm, these spaces are all essentially the same as the dual space with the variation norm. The case of with the supremum norm and even is substantially different. To understand this, we must study the extreme point structure of the unit ball of for the norm .
4 Extreme points in
In this section, we study the extreme points of the unit ball of the space . We begin with the regular norm. We have seen in Proposition 3 that there is an isometric isomorphism
where denotes the variation norm on , the space of regular Borel signed measures on . Furthermore, when the degree is odd, the supremum and regular norms on coincide.
It is a classical result that the extreme points of the unit ball of for the variation norm are the measures of the form , where (see, for example, [11, V.8.6]). The isomorphism between and associates the polynomial with the measure . Thus, we have
Proposition 4.
Let be a compact Hausdorff topological space. The extreme points of the closed unit ball of the space are the -homogeneous polynomials , where and .
This result is given in [7] for the supremum norm, but the proof given there is not valid for polynomials of even degree. However, this does not affect the results that follow in [7]. In particular, their elegant proof of the integral representation still stands. Essentially, all that is required for their arguments to work is that is a dual space and that the extreme points of the unit ball are as described above.
We now turn to the geometry of for the supremum norm, where the degree is even. We have the isometric isomorphism
where . We will show that is the dual of a norm on that is equivalent to the supremum norm.
The norm we seek is related to the diameter seminorm on , which is defined by
It is easy to see that we also have
The kernel of is the one dimensional subspace of constant functions. As in [6], we use to denote the quotient space . It is a Banach space under the norm
where is the quotient map. Following Cabello-Sanchez [6], we note that this means that is isometrically isomorphic, up to a a constant factor , to the quotient space of by the subspace of constant functions. Therefore the dual space is isometrically isomorphic, up to a constant factor , to a subspace of , the space of regular Borel signed measures with the variation norm. This subspace is the space of measures satisfying and on it we have [6]
Theorem 4 (Cabello-Sanchez [6]).
Let be a compact Hausdorff topological space. A regular Borel signed measure is an extreme point of the unit ball of the dual space if and only if , where and are distinct points of .
In order to apply this result, we first need to identify the predual of the norm on .
Theorem 5.
Let be a compact Hausdorff topological space. Let be the norm on defined by
(8) |
where is the diameter seminorm. Then the dual space of is isometrically isomorphic to the space of regular Borel signed measures on with the norm .
Proof.
A routine calculation shows that the formula defines a norm on . To establish the second equality in (8), we consider two cases.
-
(a)
Suppose the function has constant sign. Then and one of , is zero. Therefore .
-
(b)
If changes sign, then .
Therefore for every .
Let us denote the dual norm of by . If and , then
Now
and similarly
Therefore
and so .
Fix and let . Let be a Hahn decomposition for , where is a positive set and a negative set. Since is regular, there exist compact sets and such that . By Urysohn’s lemma, there is a continuous function that takes the values and on the sets and respectively. Then and
It follows that
Similarly,
Thus, for every
Therefore for every . ∎
4.1 The extreme points of the unit ball of
The extreme points of the closed unit ball of with the supremum norm are the constant functions . Our next result shows that changing to the equivalent norm given in the preceding proposition leads to a different set of extreme points.
Theorem 6.
A function is an extreme point of the closed unit
ball of if and only if
either
(i) or for every ,
or
(ii) or for every
(and in each case.)
Proof.
To show that every such function is extreme, let , with for and for , where is a nonempty subset of . Suppose that
where with and . Then, for , . But and it follows that for every .
Now, if , then . But and imply that for every and hence for every . Therefore for every and so is an extreme point. The case in which takes values and is done in exactly the same way.
We now show that every extreme point is of this type. Let be an extreme point. Since , there are two cases to consider.
Case 1: and . Then takes its values either in or . Suppose it is the latter. Then there is at least one point at which . Suppose there is a point for which . Then, by a standard argument, there is a function with values in and supported by a neighbourhood of , such that . Clearly, we also have . This implies that is not extreme and so we have a contradiction. Therefore can only have values or .
Case 2: and . There exist points in such that . Without loss of generality we may assume that . Then takes its values in the interval . If there exists such that , then, using the same perturbation argument as in the proof of Case 1, it follows that is not extreme. Therefore has precisely two distinct values, and .
Suppose that . Then, for sufficiently small , we have , which implies that is not extreme. Therefore either and , or and .
∎
Note that if is connected, then the closed unit ball of for both the supremum norm and the norm has the same extreme points — the constant functions and . However, if has more than one connected component, then there are functions that are extreme for but not , and vice versa.
4.2 The extreme points of the unit ball of
The isometric isomorphism
now enables us to identify the extreme points of the unit ball of .
Theorem 7.
Let be a compact Hausdorff topological space. A regular Borel signed measure on is an extreme point of the unit ball of if and only if it is one of the following:
-
(a)
, where ;
-
(b)
, where , are distinct points in .
Proof.
Step 1. We show that every extreme point must
be one of the types described in the statement.
Let be the space , with
the sum topology, where carries the product
topology. For , let
be the continuous function on
defined by for
and for .
The fact that
shows that the mapping is an isometric embedding of into a closed subspace of . It follows from [11, V.8.6] that every extreme point of the unit ball of is either for some , or for some .
Step 2. are extreme points: Suppose that
where , , and . Applying to the function , we have
On the other hand, implies that for . Therefore and it follows from that . Since is an extreme point of the unit ball of for the variation norm, it follows that . Therefore is an extreme point of the unit ball of .
Step 3. is extreme for every pair of distinct points : Suppose that
where , , and . Without loss of generality, we may assume that . As , we have . On the other hand,
and it follows that and for . Therefore , and all lie in , the space of regular Borel signed measures on that are zero on . Furthermore, these measures are all unit vectors in this space, since the variation norm is exactly twice the dual norm in . It follows from the result of Cabello-Sanchez (Theorem 4 above) that . Therefore is an extreme point of the unit ball of .
∎
We can now describe the extreme points of the unit ball of for the supremum norm. Recall that, when is odd, the supremum and regular norms coincide. Thus, by Propositions 3, 4 and Theorem 7 we have the following result.
Corollary 3.
Let be a compact, Hausdorff space.
-
(a)
If is odd, then is an extreme point of the closed unit ball of the space if and only if , for some , where
-
(b)
If is even, then is an extreme point of the closed unit ball of the space if and only if is one of the following:
-
(i)
for some , where ;
-
(ii)
, where are distinct points in , and
-
(i)
Example 1.
Suppose that the compact, Hausdorff space has just two points, . Then the vector lattice can be identified with , where corresponds to the function , . The supremum norm on is identified with the supremum norm on . The orthogonally additive -homogeneous polynomials on have the form . The regular and supremum norms are
The diagrams below show the unit balls for both norms.
Unit ball of for any
and for odd.
Unit ball of
for even.
4.3 The isometries of
We would like next to determine the isometries of the spaces , both for the regular and the supremum norms. Our results show that this reduces to the problem of finding the isometries between the spaces for the variation norm and the equivalent norm .
The Banach-Stone theorem [11, V.8.8] uses the classification of the extreme points of the space of regular Borel signed measures to determine the isometries of spaces with the supremum norm. We recall the statement of this theorem: if is an isometric isomorphism between and , then there exists a homeomorhism and a function with values , such that
(9) |
for all , . We shall say that an linear bijection, , from to is canonical if it has this form. In other words,
where , are as described above.
Consider the space . By Theorem 7, the set of extreme points of the unit ball of is . The crucial step in showing that an isometry of from to is canonical is to establish that , the transpose of , maps each to for some in . This leads to the following proposition.
Proposition 5.
Let and be compact Hausdorff topological spaces and let be an isometric isomorphism. Let . If contains more than one point, then is canonical. Moreover, in addition, will either take the constant value or on .
Proof.
Assume that and is non-empty. Choose . Then we have that for some and in . Since , there are and in with so that and for some and in with . We now claim that and so there in so that with . Without loss of generality suppose that and . Then we have and . Hence
and therefore . Since is a bijection we have which is impossible. Let in be such that with . Then is an extreme point of the unit ball of . However,
Since , , is not an extreme point of the unit ball of . This is a contradiction. Hence, if , then .
Note that is an isomorphism since the norms and are equivalent. Further, since , we have that for every in there is in such that . Hence maps extreme points of the unit ball of to the extreme points of the unit ball of in one to one manner. Hence and . This gives us that is an isometric isomorphism. Hence we can now apply Banach-Stone theorem to find a homeomorphism from to and a function with for all such that
Now let us see that is constant on . To see this suppose that
and
are both non empty. Choose in and in . Suppose that and that . Then is an extreme point of the unit ball of yet is not extreme point of the unit ball of . The result now follows and we get that
∎
Let us now consider the case when and show that we can construct a non canonical isometry in this case. To help understand this result, we first consider the following example.
Example 2.
Let and . We observe that we can identify both and with . Let in and set and . Then and the norm of is given by
Now define by
Clearly, is a continuous linear bijection. We can also show that
We have that
and hence is an isometry. However, is not canonical since
Guided by Proposition 5 and the above example, we now have the following result.
Theorem 8.
Let and be compact Hausdorff topological spaces.
-
(a)
Suppose that and do not contain isolated points. Then every isometric isomorphism from onto has the form
for some homeomorphism .
-
(b)
Suppose that either or contains an isolated point. Let be an isometric isomorphism. Then is one of the following types.
-
(i)
for some homeomorphism .
-
(ii)
There exist in and in and a homeomorphism such that , where
-
(i)
Proof.
(a) Note that . We claim that, if , then contains an isolated point. Suppose that and, without loss of generality, . Then
For any , a similar calculation shows that . As and and is continuous, it follows that and are disjoint closed sets. Therefore is an isolated point of . Therefore, if does not contain isolated points then and Proposition 5 gives us that is canonical.
(b) We only need to consider the case as otherwise Proposition 5 gives us that is canonical. Suppose contains an isolated point and an isolated point . For each in the function as defined in (b) is continuous and the mapping is easily seen to be an isometry.
Let us see that if is not canonical then this is the form that an isometry can take. By definition and the fact that is invertible we have that , where is the set of points in for which for some . Let and . Then . Let us suppose that . We claim that for each in we have for some in . Otherwise we have that is extreme but is not. The mapping now induces a bijection so that . Since the mapping , , is continuous, will be continuous. As is a continuous bijection from the compact space to the Hausdorff space it is a homeomorphism. Rewriting in terms of , we see that . When , we obtain . ∎
Our characterisation of the isometries of onto allows us to construct isometries of onto . Given a homeomorphism we use to denote the composition operator defined by for each in . The transpose of the canonical isometry of onto determined by now gives rise to the isometry given by .
To understand the isometries from to induced by non canonical isometries of onto we note that if and have isolated points and respectively then we have that is isometrically isomorphic to while is isometrically isomorphic to . Hence, if is an -homogeneous orthogonally additive polynomial on then we can write as where . It follows that the transpose of each non canonical isometry from onto gives an isometry from onto of the form
where is a homeomorphism of to .
In a similar manner, we can construct canonical isometries from onto .
5 Exposed points in
In this section we shall characterise the weak∗ exposed and weak∗ strongly exposed point of the unit ball of . We have an upper bound for this set. We know that it is contained in the set of extreme points of the unit ball of and that the set of extreme points of this set is equal to .
Let us begin with some definitions.
Definition 1.
Let be a Banach space. A point in the closed unit ball of is said to be an exposed point if there exists with such that
If this is the case then we say that exposes .
Definition 2.
We say that is a strongly exposed point of the closed unit ball of if there exists such that
and whenever is a sequence in with then converges to in norm. We will say that strongly exposes .
If is a dual Banach space and the point is exposed (respectively, strongly exposed) by in we say that is a weak∗ exposed (respectively, weak∗ strongly exposed) point of and that weak∗ exposes (respectively, weak∗-strongly exposes) the unit ball of at .
We also observe that if each , and each , with are of norm in . Hence, if is exposed by then we must have . Conversely, if is exposed by then we must have .
We note that if is a compact Hausdorff topological space then a net converges to in if and only if converges to for every in .
5.1 Gâteaux differentiability of the norm
We start with a characterisation of Gâteaux differentiability of the norm on .
Theorem 9.
Let be a compact Hausdorff topological space. Let , with . Then the following are equivalent
-
(a)
The norm of is Gâteaux differentiable at with derivative .
-
(b)
-
(i)
and .
-
(ii)
If is a sequence of points in such that then has a subnet, such that converges to .
-
(i)
-
(c)
is the unique point in with and .
Proof.
First observe that Šmul’yan [28, 29] (see also [9]) showed that a point in weak∗ exposes the unit ball of at if and only if the norm of is Gâteaux differentiable at with derivative . Hence we have that (a) implies (c).
Let us see that (c) implies (b). Clearly we have that (c) implies (b) (i).
Suppose that (c) is true and that (b) part (ii) fails. Then there is a sequence in with but that for all subnets of there is in such that . As is compact, we can choose a subnet of and in so that . We claim that . Suppose . Then for every in we have that contrary to what we have assumed. As and is continuous we have which contradicts (c). Hence, we see that (c) implies (b).
Next suppose that (b) is true and that (a) is false. Then we can find in , and a sequence of positive numbers converging to so that
for every positive integer .
Note that as we actually have that is non-negative and therefore we have
for every positive integer .
Each of the functions attains its norm either at a point of the form or at a point . As choosing sufficiently large we can assume that attains its norm at a point of the first type. Hence, for each in , we can find in and so that
Then we have
As is a null sequence we have that converges to as tends to . Hence we have that . However, as , we have for all . Hence, without loss of generality, we may assume that for all and therefore we have .
Then we have that
However this means that there is no subnet of so that converges to and so (b) (ii) is false. ∎
We recall that a function is said to peak at a point if is the unique point at which attains its maximum.
Lemma 1.
Let be a compact Hausdorff topological space and . Then there is in which peaks at if and only if is a subset of .
Proof.
We first suppose that is a subset of . Then we can find a sequence of open sets so that . As is compact and Hausdorff it is completely regular. Hence, for each we can find a continuous function such that and . Now let be defined by
Then we have and for , . So peaks at .
Conversely, if there is in which peaks at , for each let . Then . As each is open, is a set.∎
The weak∗ exposed points of the ball of the form are characterised by the following proposition.
Proposition 6.
Let be a compact Hausdorff topological space. Then is contained in the set of weak∗ exposed points of the unit ball of if and only if is first countable.
Just as we have characterised the weak∗ exposed points of the ball of the form we now characterise weak∗ exposed points of the form . Replacing with in Theorem 9 we obtain the following result.
Theorem 10.
Let be a compact Hausdorff topological space. Let , with . Then the following are equivalent
-
(a)
The norm of is Gâteaux differentiable at with derivative .
-
(b)
-
(i)
and .
-
(ii)
If and are sequences of points in such that then and have subnets and which converge to and respectively.
-
(i)
-
(c)
is the unique pair of points in with and .
As the proof of the following lemma is similar to that of Lemma 1 we omit it.
Lemma 2.
Let be a compact Hausdorff topological space and with . Then there is in such that , and for if and only if and are sets.
The weak∗ exposed points of the ball of the form are now characterised by the following proposition.
Proposition 7.
Let be a compact Hausdorff topological space and be an even integer. Then is contained in the set of weak∗ exposed points of the unit ball of if and only if is first countable.
Propositions 6 and 7 can be rephrased in terms of spaces of orthogonally additive polynomials. Since we have canonically identified the space with the space , we may transfer the weak∗ topology on to the space . References to the weak∗ topology on should be understood in this sense. It is easy to see that this is the topology of pointwise convergence on .
Proposition 8.
Let be a compact Hausdorff topological space and be an even integer. Then is equal to the set of weak∗ exposed points of the unit ball of if and only if is first countable.
5.2 Fréchet differentibility of the norm
We now characterise Fréchet differentiability of the norm on .
Theorem 11.
Let be a compact Hausdorff topological space. Let , with . Then the following are equivalent.
-
(a)
The norm of is Fréchet differentiable at with derivative .
-
(b)
-
(i)
and .
-
(ii)
If is a sequence of points in such that then is eventually equal to .
-
(i)
-
(c)
weak∗ strongly exposes the unit ball of at .
Proof.
First observe that Šmul’yan [28, 29] (see also [9]) showed that a point in weak∗ strongly exposes the unit ball of at if and only if the norm of is Fréchet differentiable at with derivative . Thus (a) and (c) are equivalent.
If the norm of is Fréchet differentiable at with derivative then it is Gâteaux differentiable at with derivative . Theorem 9 now implies that (b) (i) holds.
Suppose that (c) is true. Then in weak∗ strongly exposes the unit ball of at . If then . As weak∗-strongly exposes the unit ball of at we have that in norm. However, as whenever we see that only way we can have converge to is that the sequence is eventually equal to .
The implication (b) implies (a) is similar to the corresponding part of the proof of Theorem 9 where instead of using the fact that has a subsequence that converges to we use the fact that has a subsequence so that it is eventually equal to .∎
Corollary 4.
Let be a compact Hausdorff topological space and . Then is a weak∗ strongly exposed point of the unit ball of if and only if is an isolated point of .
Proof.
If is an isolated point of then the function given by
is continuous on . Moreover, if then is eventually equal to .
Conversely, if is not an isolated point of . Choose a sequence of points with , all , so that converges to . Let be any function in with and . Then we have that . However, as is not eventually equal to we see that condition (b) (ii) of Theorem 11 is not satisfied and therefore no in with can expose the unit ball at .∎
Theorem 12.
Let be a compact Hausdorff topological space. Let , with . Then the following are equivalent
-
(a)
The norm of is Fréchet differentiable to with differential .
-
(b)
-
(i)
and .
-
(ii)
If and are sequences of points in such that then and are eventually the constant sequences and respectively.
-
(i)
-
(c)
weak∗ strongly exposes the unit ball of at .
Proof.
The proof is similar to Theorem 11 and therefore omitted.∎
Corollary 5.
Let be a compact Hausdorff topological space and with . Then is a weak∗ strongly exposed point of the unit ball of if and only if and are isolated points of .
We can rephrase these results in terms of spaces of orthogonally additive polynomials as follows.
Proposition 9.
Let be a compact Hausdorff topological space, let be an even integer and let be distinct points in .
-
(a)
is a weak∗ strongly exposed point of the unit ball of if and only if is an isolated point of .
-
(b)
() is a weak∗ strongly exposed point of the unit ball of if and only if and are isolated points of .
In particular, we see that if has no isolated points, then the unit ball of does not contain any weak∗ strongly exposed points.
Acknowledgements
We thank Dirk Werner and Tony Wickstead for helpful discussions.
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Christopher Boyd, School of Mathematics & Statistics, University
College Dublin, Belfield, Dublin 4, Ireland.
e-mail: Christopher.Boyd@ucd.ie
Raymond A. Ryan, School of Mathematics, Statistics and Applied
Mathematics, National University of Ireland Galway, Ireland.
e-mail: ray.ryan@nuigalway.ie
Nina Snigireva, School of Mathematics, Statistics and Applied
Mathematics, National University of Ireland Galway, Ireland.
e-mail: nina.snigireva@nuigalway.ie