Improved bounds for Serre’s open image theorem
Abstract.
Let be an elliptic curve over the rationals which does not have complex multiplication. Serre showed that the adelic representation attached to has open image, and in particular there is a minimal natural number such that the mod representation is surjective for any prime . Assuming the Generalized Riemann Hypothesis, Mayle-Wang gave explicit bounds for which are logarithmic in the conductor of and have explicit constants. The method is based on using effective forms of the Chebotarev density theorem together with the Faltings-Serre method, in particular, using the ‘deviation group’ of the -adic representations attached to two elliptic curves.
By considering quotients of the deviation group and a characterization of the images of the -adic representation by Rouse and Zureick-Brown, we show in this paper how to further reduce the constants in Mayle-Wang’s results. Another result of independent interest are improved effective isogeny theorems for elliptic curves over the rationals.
2020 Mathematics Subject Classification:
11G05, 11F801. Introduction
Let be an elliptic curve over without complex multiplication. Serre showed in [14] that the adelic representation attached to has open image, in particular, there is a minimal natural number such that the mod representation is surjective for any prime .
In determining effective bounds on , one typically uses effective versions of the Chebotarev density theorem under the assumption of the Generalized Riemann Hypothesis (GRH) as was first done by Serre. The bounds on usually depend on the radical of the conductor of over . In Serre’s original treatment [15], the following theorem was shown. By GRH, we mean the conjecture which applies to the Artin -functions of Galois extensions ; unless otherwise stated, .
Theorem 1.1.
[15, Theorem 21] Assume GRH. Let and be two elliptic curves defined over . Suppose that and are not -isogenous. Then there exists a prime of good reduction for and such that and satisfying the inequality
(1.1) |
where is an absolute constant.
Based on the method used, the constant here is unfortunately rather large. Recent work of Mayle-Wang [9] has given an explicit result on the smallest prime which achieves . The constants are quite small, and like Serre, depend on only knowledge of the primes of bad reduction of the two elliptic curves and .
Theorem 1.2.
[9, Theorem 2] Assume GRH. Let and be two elliptic curves over without complex multiplication. Suppose and are not -isogenous. Then there exists a prime of good reduction for and such that and satisfying the inequality
(1.2) |
where and denote the conductors of and , respectively.
The method is based on using effective forms of the Chebotarev density theorem together with the Faltings-Serre method, in particular, by studying the ‘deviation group’ of the -adic representations attached to two elliptic curves.
In our work, we explain how to replace with smaller quotients in Mayle-Wang’s original arguments. Using these smaller quotients allows us to prove an improved effective isogeny theorem for elliptic curves over with a certain condition on the mod representations.
Theorem 1.3.
Assume GRH. Let and be two elliptic curves over . Suppose and are not -isogenous. Assume the mod 2 representations and are not isomorphic, or if they are isomorphic that they are absolutely irreducible. Then there exists a prime of good reduction for and such that and satisfying the inequality
(1.3) |
Remark 1.4.
Mayle-Wang, in Theorem 1.2, include a hypothesis that the elliptic curves and be without complex multiplication; in Proposition 5.1 and Theorem 1.3, we have dropped this assumption. All we require here is the existence of a prime of good reduction such that , which is satisfied once we assume the two elliptic curves are not -isogenous, a consequence of Faltings’ Theorem [7] (see translation in [6]).
We also prove another improved effective isogeny theorem which applies for elliptic curves over which are quadratic twists of each other and do not have complex multiplication.
Theorem 1.5.
Assume GRH. Let and be two elliptic curves over which are quadratic twists of each other and do not have complex multiplication. Suppose and are not -isogenous. Then there exists a prime of good reduction for and such that and satisfying the inequality
(1.4) |
This version requires the results of Rouse and Zureick-Brown [12] which characterizes the images of the -adic representations attached to an elliptic curve over .
Using Theorem 1.2, Mayle-Wang [9, Theorem 1] prove the following bound for Serre’s open image theorem.
Theorem 1.6.
Assume GRH. Let an elliptic curve over without complex multiplication. Then
A consequence of our improved effective isogeny Theorems 1.3 and 1.5 is an improvement in the constants for Serre’s open image theorem.
Theorem 1.7.
Assume GRH. Let an elliptic curve over without complex multiplication. Then
The Magma computational algebra system [2] was used for verifying assertions in this paper. The electronic resources are available from
2. Explicit forms of the Chebotarev density theorem
Let be a finite Galois extension with Galois group . Define the counting function , for a conjugacy class of the Galois group of , to be the function
Theorem 2.1 (Chebotarev Density Theorem).
Let be as above. Then,
Effective versions of Chebotarev’s Density Theorem exist as well and we shall be applying results in which the constants are explicitly computable in terms of the discriminants of and , as well as the degree of each extension over . The first of these was given by Lagarias and Odlyzko [8]. Their result relies on the validity of GRH.
We now state the first explicit form of Theorem 2.1.
Theorem 2.2.
[8, Theorem 1.1] There exists an effectively computable positive absolute constant such that if GRH holds for the Dedekind zeta function of , then for every ,
An important corollary, one that we shall make use of, is finding an such that .
Corollary 2.3.
[8, Corollary 1.2] There exists an effectively computable positive absolute constant such that if GRH holds for the Artin -functions of , , then for every conjugacy class of there exists an unramified prime ideal of such that
and
If , then is a solution.
The above is a non-nullity result about ; it asserts the size of we must take to ensure that is nonzero, that is, there is some unramified prime ideal of whose Artin symbol hits and with norm smaller than .
Theorem 2.4.
[10, Théorème 4] There exists an effectively computable positive absolute constant such that if GRH and Artin’s Conjecture (AC) hold for the Artin L-functions of , , then for every conjugacy class of , we have that
for all such that .
Oesterlé [10, Théorème 4] finds that , although his proof was seemingly never published. An improvement to Lagarias and Odlyzko is given by Bach-Sorenson [1]:
Theorem 2.5.
[1, Theorem 5.1] Assume GRH. Let be a Galois extension of number fields, with . Let denote the discriminant of . Let denote the degree of . Let be a nonempty subset closed under conjugation. Then, there is a prime of unramified in with
satisfying
for some triple taken from [1, Table 3] according to the quantities and . We may take , , and to cover all cases of and .
A corollary to the above is given in Mayle-Wang [9, Corollary 6] when we need to pick the prime to be coprime to a given positive integer .
Corollary 2.6.
[9, Corollary 6] Assume GRH. Let be a Galois extension of number fields, with . Let be a positive integer, and set . Denote to be the absolute value of the discriminant of . Let denote the degree of . Let be a nonempty subset that is closed under conjugation. Then there exists a prime number not dividing that is unramified in with and satisfying
for some triple taken from [1, Table 3] according to the quantities and . We may take , , and to cover all cases of and .
For a fixed , we say a triple is bigger than a triple (resp. a triple is smaller than a triple ) if
for all values of in a row of [1, Table 3].
We give our own version of Theorem 2.5 and Corollary 2.6. The idea is to collapse [1, Table 3] into a 1-dimensional table, removing the condition on so that each triple is valid for a range of . We do this by picking a “pivot” triple for each column, for which all triples appearing before the pivot are absorbed into a special constant , and all triples appearing after are checked to be smaller than the pivot triple.
2 | |
---|---|
3-4 | |
5-9 | |
10-14 | |
15-49 | |
50-128 |
Proposition 2.7.
Assume GRH. Let be a Galois extension of number fields with . Let be a positive integer, and set . Denote to be the discriminant of . Let denote the degree of . Let be a nonempty subset that is closed under conjugation. Then there exists a triple taken from Table 1, a special constant , and a prime number not dividing that is unramified in with and satisfying
(2.1) | ||||
(2.2) |
where . If we only have an upper bound for , then we have to replace each of with the maximum of their values over entries in Table 1 with , respectively, and with .
Proof.
Lemma 2.8.
[9, Lemma 7] If is a nontrivial finite Galois extension, then
where is the absolute value of the discriminant of .
3. The deviation group
In this section, we wish to construct a finite group, called the deviation group, denoted , from which we can find a finite subset that will determine if the two representations are isomorphic or not.
Our treatment of the deviation group will follow the exposition given in Ignasi’s thesis [11]. We note that Ignasi’s exposition is, itself, taken from Chênevert’s thesis [5], whose work follows the work of Serre [16] (the propositions and lemmas which appear here, with the exception of Lemma 3.8, can also be found in [5, Chapter 5]).
Let be a group, and be a finite extension of , for prime, with ring of integers , maximal ideal , and residue field . We let be a uniformizer, so . Let be two -adic representations. We begin by extending the map from to the group ring .
We define the map to be
Let be the full image of inside , and consider the composition map .
Definition 3.1.
[11, Definition 2.1.1] The image of inside is called the deviation group of the pair of representations .
Remark 3.2.
Since is a subalgebra of , it might be tempting to think is a subgroup of but this may not be the case. See the remark after [11, Definition 2.1.1].
The deviation group turns out to be finite, as described by the following proposition.
Proposition 3.3.
[11, Proposition 2.1.2] The group is finite, and in particular we have .
Proof.
is a submodule of the free -module . Since is a local ring, is free and is of rank , where satisfies
Given is a -module, is a -algebra of dimension . Hence,
as claimed. ∎
Remark 3.4.
Let us turn our attention now to the practical use of , that being its ability to help us determine when two representations are isomorphic.
Proposition 3.5.
[11, Proposition 2.1.3] Let be a subset that surjects onto . Then, if and only if for all .
Before we introduce the next proposition, some further explanations are needed (following [11]). We assume now the representations are not isomorphic, that is, they are not conjugate in , but that the residual representations and obtained from and by reduction modulo are isomorphic. We then have an equality for some matrix .
Define to be the largest integer such that and are conjugated modulo , that is, there is a matrix such that ; we then have , since . In addition, there is an integer such that and ; in particular, and are not conjugate modulo , so . Given that and are conjugate modulo but not conjugate modulo , if we replace with a conjugate we may assume but .
Hence, for any , we have
(3.1) |
for some and a uniformizer of . Rearranging, we get an equation for of the form
(3.2) |
where is the identity matrix. Let be the map , and notice that (3.2) becomes
(3.3) |
Proposition 3.6.
[11, Proposition 2.2.1] Let be representations that are not isomorphic, and suppose are isomorphic. Let be the largest integer such that and are conjugate modulo , and as above, assume has been replaced by a conjugate such that . Let
(3.4) |
where the semidirect product is with respect to the action of on by conjugation, that is multiplication is given by
Then is a group homomorphism which factors through the deviation group .
Remark 3.7.
The homomorphism may not be injective. See [11, Remark 2.2.2].
Lastly, we state a general lemma regarding determinants of matrices that we shall employ later.
Lemma 3.8.
[11, Lemma 2.2.3] Let be a discrete valuation ring with uniformizer , and its field of fractions. For any ,
It can be difficult to compute the exact size of , or find a tighter upper bound for it. We will, in the following section, work to replace with in the case of -adic representations. The codomain of is easily understood, and hence a bound for is easily computable. This is what allows us to prove Theorem 1.3.
4. The tools of Mayle-Wang
The methodology of Mayle-Wang relies on the following proposition that is due to Serre (a proof of which can be found in [3, Theorem 4.7]). The proposition which follows is a refined version of Serre’s original argument due to Mayle-Wang [9, Proposition 12] in which we have reworked the statement and proof to follow the work and notation done in Section 3. We note that the statement is similar to that of Proposition 3.5: here, we show that if the representations are not isomorphic, then their traces must disagree on some finite set. While the proofs are very similar, the advantage of the following proposition is that it is in a form to which we may readily apply Chebotarev.
Proposition 4.1.
[9, Proposition 12] Let a positive integer. Let be a group and be representations, and the deviation group of with respect to the two representations and . Suppose that there exists an element such that . Then there exists a subset for which
-
(1)
the set is non-empty and closed under conjugation by , and
-
(2)
if the image in of an element belongs to , then .
Proof.
Let . Let denote the -subalgebra of generated by the image of under the product map
Recall that is the image of under in .
Let be the largest nonnegative integer such that for each , one has that
As is a -subalgebra generated by the image of under , it follows that the congruence holds for each pair . We obtain the -module homomorphism given by
Since , we may consider the induced -module homomorphism .
Let be the set of elements in whose image under in all are nonzero. From the definition of and the linearity of the trace map, there exists such that
Note that the image of in is contained in , so is nonempty. Also, is closed under conjugation since the trace map is invariant under conjugation.
Finally, suppose that is such that the image of in is contained in . Then, , and in particular . ∎
Remark 4.2.
In the notation and we suppress the dependence on the representations and as they are usually fixed in the context.
We now give an analogous version of Proposition 4.1 in the case where the mod 2 representations are isomorphic and absolutely irreducible. This allows us to replace in Proposition 4.1 with from Proposition 3.6, a set which is easier to estimate the size of. The idea to replace with comes from Chênevert [5, pg. 114], in which he gives a remark that, in the -adic case, Serre [16] implies that . However, in a conversation with Chênevert, Serre mentions he might not have proven the map was an isomorphism, but, in an unpublished letter to Tate, that the in the proof of Proposition 3.5 is equal to the coming from the construction of the function if the residual representation is surjective. We show, in the 2-adic case, that , and that we can replace in Proposition 4.1 with and get the same conclusion, that is, there is a subset that is a conjugacy class, and if is such that , then .
In order to prove this special case, we require a theorem of Carayol [4].
Theorem 4.3.
[4, Theorem 1] Let be a local ring, an -algebra, and let be two representations of of the same dimension . Suppose that the residual representation , where is the residue field of , is absolutely irreducible. Suppose that the traces for and are the same for every . Then, and are isomorphic as representations, that is, there exists a matrix such that for all .
We now prove the special case.
Proposition 4.4.
Let be a positive integer. Let be a group and be representations, and suppose their reductions are isomorphic and absolutely irreducible. Suppose that there exists an element such that . Then there exists a subset for which
-
(1)
the set is non-empty and closed under conjugation by , and
-
(2)
if the image in of an element belongs to , then .
Proof.
Our setup begins, as it did, in Section 3. Let be the largest nonnegative integer such that for each , we have
In addition, we let be the largest integer such that and are conjugated modulo , that is, there is a matrix such that . As demonstrated before, we have . Also, given that and are conjugate modulo but not conjugate modulo , if we replace with a conjugate for , we may assume
(4.1) |
This implies for any . In particular, we get for some , which we can write as
(4.2) |
In particular, note that
(4.3) |
by the invariance of trace under conjugation.
We now show . Extend the maps to the group ring by , for and and . Then, notice that
(4.4) |
Since we satisfy the hypotheses of Theorem 4.3 with and , we can find a matrix such that for all . However, is the largest integer such that and are conjugate modulo , so , implying .
Recall, from (3.4), the map is defined by
(4.5) |
We note our use of the notation , for , to denote the residue class of modulo .
Define the map by
(4.6) |
where the product of matrices is taken to be the action of on , and the trace is considered to be modulo . By (4.5), notice
(4.7) |
where we have used (4.3) above (with replaced with , since ) and the fact that, for a matrix with for entries along the diagonal, we have
(4.8) |
which shows the final equality (noting our use of in (4.8) to denote the residue class of a -adic integer ).
Let be the set of elements in that take a nonzero value under the map . From the definition of and the linearity of the trace map, there exists such that
Note that the image of in is inside , so is nonempty. In addition, let for some ; then, given is a homomorphism (Proposition 3.6) and by (4.7) and the invariance under conjugation of the trace map,
(4.9) |
so is closed under conjugation. Finally, suppose that is such that the image of in is contained in . Then, , in particular . ∎
5. Improved bounds for the effective isogeny theorem
For a prime and an elliptic curve , we define
We begin with the proof of Proposition 5.1. We note that the work which follows is the same as that of Mayle-Wang [9], except for our use of Proposition 2.7 and Table 1.
Let and be two elliptic curves over and let . Let . We may regard the -adic representations and as representations of instead of since and are subfields of .
The representation and is a continuous homomorphism with image being as defined in the proof of Proposition 4.1. Since is closed inside , we see that is a closed subgroup of and hence by the fundamental theorem of infinite Galois theory corresponds to a finite Galois extension with .
The set (defined in Proposition 3.6) is a subset of a very explicit semi-direct product, and estimating gives a smaller bound.
Proposition 5.1.
Assume GRH. Let and be two elliptic curves over . Suppose and are not -isogenous. Let be the deviation group of with respect to the -adic representations and .
Choose the triple from Table 1 for . Then there exists a prime of good reduction for and such that such that
(5.3) |
Furthermore, if and are such that their mod 2 representations are isomorphic and absolutely irreducible, then we may replace with .
Proof.
Let . Let and apply Proposition 4.1 with , , , and the -adic representations and . By Faltings theorem [7], since the two elliptic curves and are not -isogenous, and are not isomorphic; therefore, by Serre [13, pg. IV-15], there is some prime such that . By Proposition 4.1, there exists a conjugacy class obeying the stated conclusion of this proposition.
Let be the subfield of for which . Choosing , Proposition 2.7 produces a prime not dividing such that and
(5.4) |
where and are the maximum of their values over entries in Table 1 with , respectively. It follows from Proposition 4.1 that
and consequently .
The abelian variety has good reduction at some prime if and only if both and have good reduction at . Thus, is unramified outside of the prime divisors of . As is the compositum of and , the primes that ramify in are precisely those that ramify in or in . Since , and rad rad, we have that
(5.5) |
Now, applying Lemma 2.8 to (5.4) gives us
which matches (5.3).
Now we give a proof of Theorem 1.3.
Proof of Theorem 1.3.
We split our analysis into two cases. If the mod representations are not isomorphic, then mod already distinguishes the traces. Define
(5.6) |
by . Let be the image of the map . Let
(5.7) |
Apply Proposition 2.7 to the field , whose Galois group is , the conjugacy class given in (5.7), and , so that we get a prime unramified in and such that (implying ) and satisfying
(5.8) | ||||
(5.9) |
Taking gives us
(5.10) |
Next, assume that the mod 2 representations and are isomorphic and absolutely irreducible. Apply Proposition 5.1, and replace with (since the mod 2 representations are isomorphic and absolutely irreducible) to get a prime such that and satisfying
From (3.2) and Lemma 3.8, we have for any ,
(5.11) |
As we have being the cyclotomic character, so the above can be rewritten as , which, after multiplying through by implies
In particular, the map from Proposition 3.6 takes values in , where denotes the matrices with trace with entries in . Therefore, we have . We find from Proposition 2.7 that
(5.12) |
We now improve the bound in (5.12) by using the following two results.
Proposition 5.2.
Let be a group and be a group homomorphism, and suppose the mod 2 representations are isomorphic. Let be the elements such that the characteristic polynomials of and coincide. Then for , the order of in is .
Proof.
See [5, Proposition 5.5.6]. ∎
Corollary 5.3.
Let be a group and be a group homomorphism, and suppose the mod 2 representations are isomorphic. Let be a quotient having a conjugacy class of order . If is such that , then .
From (5.1) and (5.2), the possible sizes of are
(5.13) |
As the possible orders are small, it is possible to enumerate in Magma all isomorphism classes of groups of these sizes. The group therefore lies in an explicit finite list which can be computed.
By Corollary 5.3, if has a quotient with an element of order , then we may replace by . We check this in Magma for each value of and find that either has such a quotient with strictly smaller size in the given list of (5.13) or it is in a small list of problematic groups. We list for each size , the Magma labels of the isomorphism classes of the problematic groups of that order.
# of isomorphism classes | problematic groups | |
---|---|---|
192 | 1543 | 1023, 1025, 1541 |
144 | 197 | none |
128 | 2328 | 2326, 2327, 2328 |
96 | 231 | 204 |
72 | 50 | none |
64 | 267 | 266, 267 |
48 | 52 | 3, 50 |
36 | 14 | 11 |
32 | 51 | 49, 50, 51 |
Consider the homomorphism . The possible orders of the image are:
(5.14) |
Using Magma, we check if , there is no homomorphism from a problematic group to a subgroup of order or in the codomain of . Hence, either or the image of is . In either case, we can replace by a quotient of order . Hence, (5.12) is improved to the same bound in (5.10).
∎
6. The results of Rouse and Zureick-Brown on -adic images
The -adic representation of an elliptic curve over has open image in and the properties that is surjective and is an element with determinant and trace for a complex conjugation. With this in mind, the authors in [12] make the following definition:
Definition 6.1.
An open subgroup is arithmetically maximal if
-
(1)
is surjective,
-
(2)
there is an element of with determinant and trace , and
-
(3)
the is no subgroup satisfying (1) and (2) with and so that the genus of is .
The idea behind this definition is that arithmetically maximal subgroups are maximal among the subgroups satisfying (1) and (2), except possibly when is contained in a subgroup such that has genus . For instance, if and has genus , it would be easier and sufficient to determine the -rationals point rather than .
For an arithmetically maximal subgroup , either has infinitely many -rational points (hence has genus ) or has finitely many -rational points. The union of the latter cases leads to a finite list of -invariants.
In [12], it is shown there are arithmetically maximal subgroups up to conjugation such that . There are an additional arithmetically maximal subgroups up to conjugation such that . Thus, there are a total of arithmetically maximal subgroups . Among these, there are which have genus and of these are such that has infinitely many -rational points.
In [12, Theorem 1.1], the possible images of are determined in the following sense:
Theorem 6.2.
Let be a subgroup and let be an elliptic curve such that the image of is contained in a conjugate of . Then one of the following holds:
-
(1)
The modular curve has infinitely many -rational points (hence has genus ).
-
(2)
The elliptic curve has complex multiplication.
-
(3)
The -invariant of is one of
(6.1)
We rephrase the above theorem for the purposes of proving the main results of this paper.
7. Improved bounds for Serre’s open image theorem
In Theorem 1.3, there is a hypothesis that is absolutely irreducible. While we do not have an argument to remove this condition and achieve better bounds than Theorem 1.2, we are able to do so in the case when and are quadratic twists of each other and do not have complex multiplication.
Proof of Theorem 1.5.
Suppose is a twist of by a quadratic character associated to the extension . Then . Since does not have complex multiplication, and are not -isogenous.
Assume and hence are not absolutely irreducible.
If is not a subfield of , then is a degree extension of . Hence, the identity automorphism of extends to an automorphism of such that . It follows that and where is the identity element. This means that so we may apply the proofs of Theorem 1.3 and Proposition 4.4 (no need for Theorem 4.3) to get the desired conclusion.
Otherwise lies in the field . In [12] (see Theorem 6.3), the possible -adic images of an elliptic curve are determined up to conjugacy. Every such image contains the principal congruence subgroup of level and can be regarded as a subgroup of for . In order to apply [12, Lemma 3.3], without loss of generality we take .
Let . The character corresponds to a subgroup of index inside . Either or
(7.1) |
so has order . In the latter case, is a maximal subgroup of , hence by [12, Lemma 3.3], we obtain again that .
It follows that factors through
(7.2) |
Consider the product representation
(7.3) |
We note that
(7.4) |
Let be defined as:
(7.5) | ||||
The map is an isomorphism which is the identity when restricted to and
(7.6) |
is the subgroup of given by the graph of , namely,
(7.7) |
Hence, it follows that the inclusion
(7.8) | ||||
(7.9) |
is an isomorphism. Composing with the homomorphism , we obtain a homomorphism
(7.10) |
Since , we see that where is the diagonal homomorphism. Thus, . Thus, we see that the kernel of the map contains and hence factors through
(7.11) |
Using Magma, we check that each one of the possibilities for does not have a quotient which factors through and is isomorphic to one of the problematic groups of order , , or in Table 2, if the image of is not absolutely irreducible. We conclude that it is possible to replace with a quotient of order . It is also checked that the elliptic curves over with -invariant in the finite list of Theorem 6.2 (3) have .
Hence, we obtain the bound
(7.12) |
∎
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