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                           NT@UW-09-18
Electromagnetic Form Factors and Charge Densities From Hadrons to Nuclei

Gerald A. Miller Department of Physics, University of Washington
Seattle, Washington 98195-1560
Abstract

A simple exact covariant model in which a scalar particle Ψ\Psi is modeled as a bound state of two different particles is used to elucidate relativistic aspects of electromagnetic form factors F(Q2)F(Q^{2}). The model form factor is computed using an exact covariant calculation of the lowest-order triangle diagram. The light-front technique of integrating over the minus-component of the virtual momentum gives the same result and is the same as the one obtained originally by Gunion et al. by using time-ordered perturbation theory in the infinite-momentum-frame. The meaning of the transverse density ρ(b)\rho(b) is explained by providing a general derivation, using three spatial-coordinates, of its relationship with the form factor. This allows us to identify a mean-square transverse size b2=d2bb2ρ(b)=4dFdQ2(Q2=0)\langle b^{2}\rangle=\int d^{2}b\;b^{2}\rho(b)=-4{dF\over dQ^{2}}(Q^{2}=0). The quantity b2\langle b^{2}\rangle is a true measure of hadronic size because of its direct relationship with the transverse density. We show that the rest-frame charge distribution is generally not observable by studying the explicit failure to uphold current conservation. Neutral systems of two charged constituents are shown to obey the conventional lore that the heavier one is generally closer to the transverse origin than the lighter one. It is argued that the negative central charge density of the neutron arises, in pion-cloud models, from pions of high longitudinal momentum that reside at the center. The non-relativistic limit is defined precisely, and the ratio of the binding energy BB to the mass {\cal M} of the lightest constituent is shown to govern the influence of relativistic effects. We show that the exact relativistic formula for F(Q2)F(Q^{2}) is the same as the familiar one of the three-dimensional Fourier transform of a square of a wave function for very small values of B/B/{\cal M}, but this only occurs values of B/B/{\cal M} less than about 0.001. For masses that mimic the quark-di-quark model of the nucleon we find that there are substantial relativistic corrections to the form factor for any value of Q2Q^{2}. A schematic model of the lowest ss-states of nuclei is developed. Relativistic effects are found to decrease the form factor for light nuclei but to increase the form factor for heavy nuclei. Furthermore, these lowest ss-states are likely to be strongly influenced by relativistic effects that are order 15-20%.

Nuclear Form Factors, Nuclear Charge Densities
pacs:
11.80.-m, 12.39.Ki,13.40.Gp,25.30.Bf
preprint: NT@UW-09-??

I Introduction

The text-book interpretation of nucleon electromagnetic form factors is that their three-dimensional Fourier transforms are measurements of the charge and magnetization densities. This interpretation is deeply buried in our thinking and continues to guide intuition as it has since the days of the Nobel prize-winning work of HofstadterHofstadter:1956qs . Nevertheless, the relativistic motion of the constituents of the system causes the text-book interpretation to be incorrect.

The preceding statement leads to a number of questions, the first being: Is the statement correct? If correct, how relativistic does the motion of the constituents have to be? Why is it that the relativistic motion of the constituents and not that of the entire system that causes the non-relativistic approach to fail? It is probably true that the answers to these questions are displayed within the existing literature. However, obtaining general clear answers has been sufficiently difficult that posing even the first question of this paragraph would not lead to a unanimous answer by all professionals in the field.

This paper offers the strategy of using a simple model, a generalization of the ϕ3\phi^{3} model used by Weinberg Weinberg:1966jm to illustrate advantages of using the infinite momentum by choosing frame that was used by Gunion et al. Gunion:1973ex to explore form factors and hadronic interactions at high-momentum transfer. We take the interaction Lagrangian density to be of the form gΨϕξg\Psi\phi\xi in which all of the fields are bosons.The Ψ\Psi particle of mass MM represents the bound state of the two different constituents ϕ,ξ\phi,\xi of masses m1,m2m_{1},m_{2} respectively. Thus the Ψ\Psi represents the hadron or nucleus with the ϕ,ξ\phi,\xi representing the quark or nucleonic constituents. Mass renormalization effects are ignored. We can choose either or both of the constituents to be charged and thus discuss charged and neutral Ψ\Psi particles.

The motivation to pose questions regarding the meaning of electromagnetic form factors at this point in time arises from recent experimental work, especially the discovery that the ratio of the proton’s electric to magnetic Sachs form factors GE/GMG_{E}/G_{M} drops rapidly (please see the reviews reviews ) and from our recent finding Miller:2007uy , based on measurements and the use of the transverse density that the charge density at the neutron’s center is negative. The nucleon transverse density ρ(b)\rho(b), the two-dimensional Fourier transform of F1F_{1} is the infinite momentum frame charge densitynotation located at a transverse separation bb from the center of transverse momentumsoper1 ; mbimpact ; diehl2 ; Carlson:2008zc . This quantity has a direct relationship to matrix element of a density operator. The usual three-dimensional Fourier transforms of GEG_{E} and GMG_{M} do not because the initial- and final-state nucleons have different momentum, and therefore different wave functions. This is because the relativistic boost operator that transforms a nucleon at rest into a moving one changes the wave function in a manner that depends on the momentum of the nucleon. However, we expect that there are non-relativistic conditions for which the text-book interpretation is correct. We aim to explore those conditions by choosing appropriate values of the masses m1,m2,Mm_{1},m_{2},M.

Here is the outline we follow. The form factor for the situation in which the Ψ\Psi and ϕ\phi carry a single unit of charge, but the ξ\xi is neutral, is computed using an exact covariant calculation of the lowest-order triangle diagram in Sect. II. This is followed by a another derivation using the light-front technique of integrating over the minus-component of the virtual momentum in Sect. III that obtains the same form factor. This is also the result obtained originally by Gunion:1973ex by using time-ordered perturbation theory in the infinite-momentum-frame IMF. Thus three different approaches yield the same exact result for this model problem. Any approximation that does not yield the same form factor is simply not correct. The asymptotic limit of very high momentum transfer Q2Q^{2} is also studied. The next section (IV) explains the transverse density of the model, its central value, a general derivation of its relationship with the form factor using three dimensional spatial coordinates and the meaning of hadronic radii. Section V displays the spatial wave function in terms of three spatial coordinates. Section VI shows that the rest-frame charge distribution is generally not observable. Section VII is concerned with the question of whether neutral systems of two constituents obey the conventional lore that the heavier one is generally closer to the origin than the lighter one. The non-relativistic limit is defined and applied to a variety of examples in Section VIII. The exact formula for the form factor morphs into the familiar one of the three-dimensional Fourier transform for sufficiently large values of the constituent mass divided by the binding energy of the system. Examples that are motivated by the pion, deuterium, nucleon and heavy nuclei are provided. This work is summarized in Section IX.

II Exact form factors using a simple model

Refer to caption
Figure 1: Feynman diagram for the form factor with the photon coupling to the ϕ\phi particle of mass m1m_{1}. The initial and final hadron Ψ\Psi carry momentum, PP and P+qP+q. The ξ\xi is a spectator.

The model Lagrangian density is given by gΨϕξg\Psi\phi\;\xi where Ψ,ϕ\Psi,\phi and ξ\xi represent three scalar fields of masses M,m1M,m_{1} and m2m_{2} respectively and gg is a coupling constant. One can take two or three of these fields to carry charge to make up a system of definite charge (including the case when the hadron Ψ\Psi is neutral). The effects of mass renormalization are not considered here because we aim to use a simple model to provide easily calculable examples and illustrate specific points. The condition m1+m2>Mm_{1}+m_{2}>M is used to insure that the hadron Ψ\Psi is stable.

We start with the situation in which the Ψ,ϕ\Psi,\phi each carry a single positive charge and ξ\xi is neutral. The form factor F(q2)F(q^{2}) for a space-like incident photon of four-momentum qμ(q2<0,Q2=q2)q^{\mu}\;(q^{2}<0,Q^{2}=-q^{2}), incident on a target Ψ\Psi of four-momentum PμP^{\mu} interacting with the ϕ\phi of mass m1m_{1} is given, to lowest order in gg, by the single Feynman diagram of Fig. 1. We take the model electromagnetic current JμJ^{\mu} (in units of the proton charge) as given by

Jμ=ϕμϕ,\displaystyle J^{\mu}=\phi\stackrel{{\scriptstyle\leftrightarrow}}{{\partial}}^{\mu}\phi, (1)

and find

P+q|Jμ(0)|P\displaystyle\langle P+q|J^{\mu}(0)|P\rangle\equiv F(Q2)(2Pμ+qμ)\displaystyle F(Q^{2})(2P^{\mu}+q^{\mu}) (3)
=ig2d4k(2π)41(k2m12+iϵ)(2kμ+qμ)1((k+q)2m12+iϵ)1((Pk)2m22+iϵ).\displaystyle=-ig^{2}\int{d^{4}k\over(2\pi)^{4}}{1\over(k^{2}-m_{1}^{2}+i\epsilon)}(2k^{\mu}+q^{\mu}){1\over((k+q)^{2}-m_{1}^{2}+i\epsilon)}{1\over((P-k)^{2}-m_{2}^{2}+i\epsilon)}.

Proceed by combining the denominators using the Feynman procedure and shifting the origin of the convergent integral to find

F(Q2)(2Pμ+qμ)=i2g2d4κ(2π)401𝑑x01x𝑑yqμ(12y)+2Pμx[κ22+iϵ]3,\displaystyle F(Q^{2})(2P^{\mu}+q^{\mu})=-i2g^{2}\int{d^{4}\kappa\over(2\pi)^{4}}\int_{0}^{1}dx\int_{0}^{1-x}dy{q^{\mu}(1-2y)+2P^{\mu}x\over[\kappa^{2}-{\cal M}^{2}+i\epsilon]^{3}}, (4)

where 2=Q2y(y+x1)+M2x(1x)m12(1x)m22.{\cal M}^{2}=Q^{2}y(y+x-1)+M^{2}x(1-x)-m_{1}^{2}(1-x)-m_{2}^{2}. Use

d4κ(2π)41(κ22+iϵ)3=iπ2(2π)41212\displaystyle\int{d^{4}\kappa\over(2\pi)^{4}}{1\over(\kappa^{2}-{\cal M}^{2}+i\epsilon)^{3}}=-i{\pi^{2}\over(2\pi)^{4}}{1\over 2}{1\over{\cal M}^{2}} (5)

to find

F(Q2)(2Pμ+qμ)=g216π201𝑑x01x𝑑yqμ(12y)+2PμxQ2y(y+x1)+M2x(1x)m12(1x)m22x.\displaystyle F(Q^{2})(2P^{\mu}+q^{\mu})=-{g^{2}\over 16\pi^{2}}\int_{0}^{1}dx\int_{0}^{1-x}dy{q^{\mu}(1-2y)+2P^{\mu}x\over Q^{2}y(y+x-1)+M^{2}x(1-x)-m_{1}^{2}(1-x)-m_{2}^{2}x}. (6)

The integral over yy can be done in closed form with the result

F(Q2)(2Pμ+qμ)=4g216π2(qμ+2Pμ)01𝑑xxTanh1[Q2(1x)4xm22+4(1x)m12x(1x)M2+(1x)2Q2]Q24xm22+4(1x)m124x(1x)M2+(1x)2Q2.\displaystyle F(Q^{2})(2P^{\mu}+q^{\mu})=4{g^{2}\over 16\pi^{2}}(q^{\mu}+2P^{\mu})\int_{0}^{1}dx{x{\rm Tanh}^{-1}\left[{\sqrt{Q^{2}}(1-x)\over\sqrt{4x\;m_{2}^{2}+4(1-x)m_{1}^{2}-x(1-x)M^{2}+(1-x)^{2}Q^{2}}}\right]\over\sqrt{Q^{2}}\sqrt{4x\;m_{2}^{2}+4(1-x)m_{1}^{2}-4x(1-x)M^{2}+(1-x)^{2}Q^{2}}}. (7)

The above expression shows that current conservation is satisfied and that the form factor can be obtained from any component of the current operator JμJ^{\mu}. The final result for the form factor is

F(Q2)=g24π201𝑑xxTanh1[Q2(1x)4xm22+4(1x)m12x(1x)M2+(1x)2Q2]Q24xm22+4(1x)m124x(1x)M2+(1x)2Q2.\displaystyle F(Q^{2})={g^{2}\over 4\pi^{2}}\int_{0}^{1}dx{x{\rm Tanh}^{-1}\left[{\sqrt{Q^{2}}(1-x)\over\sqrt{4x\;m_{2}^{2}+4(1-x)m_{1}^{2}-x(1-x)M^{2}+(1-x)^{2}Q^{2}}}\right]\over\sqrt{Q^{2}}\sqrt{4x\;m_{2}^{2}+4(1-x)m_{1}^{2}-4x(1-x)M^{2}+(1-x)^{2}Q^{2}}}. (8)

This closed form expression is the key result of this paper. It can be modified to describe a variety of different physical situations.

III Infinite momentum frame/Light Front Representation

We derive the light front representation by starting with the form factor of Eq. (3) and integrating over kk^{-}. This procedure is simplified by choosing q+=0q^{+}=0, so that Q2=𝐪2Q^{2}={\bf q}^{2} notation and evaluating the ++ component of the electromagnetic current operator. In the present Section the convention is that A±=A0±A3A^{\pm}=A^{0}\pm A^{3} for the four-vector AμA^{\mu}. Then Eq. (3) becomes

2P+F(Q2)=ig2d4k(2π)4[2k+(k2m12+iϵ)1((k+q)2m12+iϵ)1((Pk)2M2+iϵ)]\displaystyle 2P^{+}F(Q^{2})=-ig^{2}\int{d^{4}k\over(2\pi)^{4}}\left[{2k^{+}\over(k^{2}-m_{1}^{2}+i\epsilon)}{1\over((k+q)^{2}-m_{1}^{2}+i\epsilon)}{1\over((P-k)^{2}-M^{2}+i\epsilon)}\right] (9)
=ig2d4k(2π)42k+k+2(P+k+)1(k(𝐤2+m12)k++iϵk+)1(k((𝐤+𝐪)2+m12)k++iϵk+)1(Pk(𝐏𝐤)2+m22)P+k++iϵP+k+)\displaystyle=-ig^{2}\int{d^{4}k\over(2\pi)^{4}}{2k^{+}\over{k^{+}}^{2}(P^{+}-k^{+})}{1\over(k^{-}-{({\bf k}^{2}+m_{1}^{2})\over k^{+}}+{i\epsilon\over k^{+}})}{1\over(k^{-}-{(({\bf k}+{\bf q})^{2}+m_{1}^{2})\over k^{+}}+{i\epsilon\over k^{+}})}{1\over(P^{-}-k^{-}-{({\bf P}-{\bf k})^{2}+m_{2}^{2})\over P^{+}-k^{+}}+{i\epsilon\over P^{+}-k^{+}})} (10)

If we integrate over the upper half of the complex kk^{-} plane we find a non-zero contribution only for the case 0<k+<P+0<k^{+}<P^{+}. Carrying out the integral leads to

2P+F(Q2)=g2(2π)3d2𝐤dk+k+(P+k+)1P𝐤2+m12k+(𝐏𝐤)2+m22P+k+1P(𝐤+𝐪)2+m12k+(𝐏𝐤)2+m22P+k+\displaystyle 2P^{+}F(Q^{2})={g^{2}\over(2\pi)^{3}}\int d^{2}{\bf k}\int{dk^{+}\over k^{+}(P^{+}-k^{+})}{1\over P^{-}-{{\bf k}^{2}+m_{1}^{2}\over k^{+}}-{({\bf P}-{\bf k})^{2}+m_{2}^{2}\over P^{+}-k^{+}}}{1\over P^{-}-{({\bf k}+{\bf q})^{2}+m_{1}^{2}\over k^{+}}-{({\bf P}-{\bf k})^{2}+m_{2}^{2}\over P^{+}-k^{+}}} (11)

Next change variables by defining

xk+P+,\displaystyle x\equiv{k^{+}\over P^{+}}, (12)

so that

F(Q2)=g22(2π)3d2𝐤01dxx(1x)1P+P𝐤2+m12x(𝐏𝐤)2+m221x1P+P(𝐤+𝐪)2+m12x(𝐏𝐤)2+m221x.\displaystyle F(Q^{2})={g^{2}\over 2(2\pi)^{3}}\int d^{2}{\bf k}\int_{0}^{1}{dx\over x(1-x)}{1\over P^{+}P^{-}-{{\bf k}^{2}+m_{1}^{2}\over x}-{({\bf P}-{\bf k})^{2}+m_{2}^{2}\over 1-x}}{1\over P^{+}P^{-}-{({\bf k}+{\bf q})^{2}+m_{1}^{2}\over x}-{({\bf P}-{\bf k})^{2}+m_{2}^{2}\over 1-x}}. (13)

Further define the relative transverse momentum

𝜿(1x)𝐤x(𝐏𝐤)=𝐤x𝐏,\displaystyle\mbox{\boldmath$\kappa$}\equiv(1-x){\bf k}-x({\bf P}-{\bf k})={\bf k}-x{\bf P}, (14)

so that the form factor can be re-expressed as

F(Q2)=g22(2π)3d2𝜿01dxx(1x)1M2𝜿2+m12x𝜿2+m221x1M2(𝜿+(1x)𝐪)2+m12x(𝜿+(1x)𝐪)2+m221x.\displaystyle F(Q^{2})={g^{2}\over 2(2\pi)^{3}}\int d^{2}\mbox{\boldmath$\kappa$}\int_{0}^{1}{dx\over x(1-x)}{1\over M^{2}-{\mbox{\boldmath$\kappa$}^{2}+m_{1}^{2}\over x}-{\mbox{\boldmath$\kappa$}^{2}+m_{2}^{2}\over 1-x}}{1\over M^{2}-{(\mbox{\boldmath$\kappa$}+(1-x){\bf q})^{2}+m_{1}^{2}\over x}-{(\mbox{\boldmath$\kappa$}+(1-x){\bf q})^{2}+m_{2}^{2}\over 1-x}}. (15)

This is the expression obtained in Ref. Gunion:1973ex , by using time-order-perturbation theory in the infinite momentum frame. Integration over kk^{-} leads to the same result for this example.

It is useful to re-express the result Eq. (15) in terms of a wave function ψ\psi with

ψ(x,𝜿)g[M2𝜿2+m12x𝜿2+m221x]1.\displaystyle\psi(x,\mbox{\boldmath$\kappa$})\equiv g[M^{2}-{\mbox{\boldmath$\kappa$}^{2}+m_{1}^{2}\over x}-{\mbox{\boldmath$\kappa$}^{2}+m_{2}^{2}\over 1-x}]^{-1}. (16)

In that case

F(Q2)=12(2π)3d2𝜿01dxx(1x)ψ(x,𝜿+(1x)𝐪)ψ(x,𝜿),\displaystyle F(Q^{2})={1\over 2(2\pi)^{3}}\int d^{2}\mbox{\boldmath$\kappa$}\int_{0}^{1}{dx\over x(1-x)}\psi^{*}(x,\mbox{\boldmath$\kappa$}+(1-x){\bf q})\psi(x,\mbox{\boldmath$\kappa$}), (17)

as found in Ref. Gunion:1973ex .

The integration over 𝜿\kappa is convergent so we carry out the integration over 𝜿\kappa by combining the propagators and shifting the origin. This gives

F(Q2)=g2π2(2π)301𝑑x01𝑑zx(1x)(1x)m12+xm22x(1x)M2+(1x)2𝐪2z(1z).\displaystyle F(Q^{2})={g^{2}\pi\over 2(2\pi)^{3}}\int_{0}^{1}{dx}\int_{0}^{1}dz{x(1-x)\over(1-x)m_{1}^{2}+xm_{2}^{2}-x(1-x)M^{2}+(1-x)^{2}{\bf q}^{2}z(1-z)}. (18)

The integral over zz can be done with the result that

F(Q2)=g24π201𝑑xxTanh1[Q2(1x)4xm22+4(1x)m12x(1x)M2+(1x)2Q2]Q24xm22+4(1x)m124x(1x)M2+(1x)2Q2\displaystyle F(Q^{2})={g^{2}\over 4\pi^{2}}\int_{0}^{1}dx{x{\rm Tanh}^{-1}\left[{\sqrt{Q^{2}}(1-x)\over\sqrt{4x\;m_{2}^{2}+4(1-x)m_{1}^{2}-x(1-x)M^{2}+(1-x)^{2}Q^{2}}}\right]\over\sqrt{Q^{2}}\sqrt{4x\;m_{2}^{2}+4(1-x)m_{1}^{2}-4x(1-x)M^{2}+(1-x)^{2}Q^{2}}} (19)

This is the same as our previous exactly computed result, Eq. (8). Thus evaluation in the infinite momentum frame or the equivalent (for this model) light front technique of integration over kk^{-} yields the exact result.

III.1 Asymptotic Behavior of the Form Factor

The limit of very high Q2Q^{2} is of considerable interest. One wants to see how the quark counting rules emerge from an exact calculation, even if the model is very simple. To this end we note, that the integral Eq. (19) can be evaluated exactly in the limit that m1=m2=mm_{1}=m_{2}=m with M=0M=0. Then measuring QQ2Q\equiv\sqrt{Q^{2}} in units of mm (Q/mQQ/m\rightarrow Q) we find

F(Q2)=g24π2log2(12(Q(Q2+4+Q)+2))+88Q2Q2+4log(12(Q(Q2+4+Q)+2))2Q3\displaystyle F(Q^{2})={g^{2}\over 4\pi^{2}}\frac{\log^{2}\left(\frac{1}{2}\left(Q\left(\sqrt{Q^{2}+4}+Q\right)+2\right)\right)+8}{8Q^{2}}-\frac{\sqrt{Q^{2}+4}\log\left(\frac{1}{2}\left(Q\left(\sqrt{Q^{2}+4}+Q\right)+2\right)\right)}{2Q^{3}} (20)

so that

limQ2F(Q2)=12log2(1Q)+log(1Q)+1Q2+log(1Q)1Q4+.\displaystyle\lim_{Q^{2}\rightarrow\infty}F(Q^{2})=\frac{\frac{1}{2}\log^{2}\left(\frac{1}{Q}\right)+\log\left(\frac{1}{Q}\right)+1}{Q^{2}}+\frac{\log\left(\frac{1}{Q}\right)-1}{Q^{4}}+\cdots. (21)

Thus the leading asymptotic behavior is

limQ2F(Q2)12log2Q2Q2.\displaystyle\lim_{Q^{2}\rightarrow\infty}F(Q^{2})\sim\frac{{\frac{1}{2}\log}^{2}Q^{2}}{Q^{2}}. (22)

Thus the power-law fall-off expected from the quark-counting rules appears, but it is modified by the presence of the logarithms. This behavior is not associated with taking MM to zero because in all cases we have m1+m2>Mm_{1}+m_{2}>M as required for the particle to be stable. Thus the asymptotic behavior (Q2m12,m22Q^{2}\gg m_{1}^{2},m_{2}^{2}) associated with Eq. (22) is expected to be universal for this model. Note however, from Eq. (21) that the approach to this asymptotic form is very slow.

IV Electromagnetic form factors measure transverse densities and transverse radii

The expression Eq. (17) is noteworthy because the form factor is expressed as a three-dimensional integration that involves momentum-space wave functions evaluated at different initial and final momenta. If the (1x)(1-x) factor multiplying 𝐪{\bf q} were replaced by a constant Eq. (17) would be similar to the usual expression for the form factor. We clarify this comparison by expressing the wave function of Eq. (16) and Eq. (17) in transverse position space, with 𝐁{\bf B} canonically conjugate to the transverse momentum variable 𝜿\kappa:

ψ(x,𝐁)=1x(1x)d2𝜿(2π)2ei𝜿𝐁ψ(x,𝜿),\displaystyle\psi(x,{\bf B})=\frac{1}{\sqrt{x(1-x)}}\int{d^{2}\mbox{\boldmath$\kappa$}\over(2\pi)^{2}}e^{i\mbox{\boldmath$\kappa$}\cdot{\bf B}}\psi(x,\mbox{\boldmath$\kappa$}), (23)
=x(1x)2πgK0(m12(1x)+m22xM2x(1x)B),\displaystyle={\sqrt{x(1-x)}\over 2\pi}gK_{0}(\sqrt{m_{1}^{2}(1-x)+m_{2}^{2}x-M^{2}x(1-x)}\;B), (24)

with the phase space factor 1x(1x)\frac{1}{\sqrt{x(1-x)}} incorporated in the wave function. Then the form factor Eq. (17) can be re-expressed as

F(Q2)=12(2π)301𝑑xd2𝐁|ψ(x,B)|2ei𝐪(1x)𝐁.\displaystyle F(Q^{2})={1\over 2(2\pi)^{3}}\int_{0}^{1}dx\int d^{2}{\bf B}|\psi(x,B)|^{2}e^{-i{\bf q}\cdot(1-x){\bf B}}. (25)

Further simplify by replacing the relative transverse position variable 𝐁{\bf B} by the transverse position variable of the charged parton 𝐛1𝐛{\bf b}_{1}\equiv{\bf b}. We have

𝐁=𝐛1𝐛2\displaystyle{\bf B}={\bf b}_{1}-{\bf b}_{2} (26)
0=𝐛1(x)+𝐛2(1x),\displaystyle 0={\bf b}_{1}(x)+{\bf b}_{2}(1-x), (27)
𝐁=𝐛/(1x),\displaystyle{\bf B}={\bf b}/(1-x), (28)

where the middle equation sets the transverse center of P+P^{+} momentum to zero. Use Eq. (28) in Eq. (25) to find

F(Q2)=12(2π)301dx(1x)2d2𝐛|ψ(x,𝐛1x)|2ei𝐪𝐛,\displaystyle F(Q^{2})={1\over 2(2\pi)^{3}}\int_{0}^{1}{dx\over(1-x)^{2}}\int d^{2}{\bf b}|\psi(x,{{\bf b}\over 1-x})|^{2}e^{-i{\bf q}\cdot{\bf b}}, (29)

which can be re-written as

F(Q2)=1(2π)2d2𝐛ρ(b)ei𝐪𝐛\displaystyle F(Q^{2})={1\over(2\pi)^{2}}\int d^{2}{\bf b}\rho(b)e^{-i{\bf q}\cdot{\bf b}} (30)

with the transverse density ρ(b)\rho(b) given by

ρ(b)=14π01dx(1x)2|ψ(x,𝐛1x)|2=g22(2π)301𝑑xx(1x)K02(m12(1x)+m22xM2x(1x)b1x)\displaystyle\rho(b)={1\over 4\pi}\int_{0}^{1}{dx\over(1-x)^{2}}|\psi(x,{{\bf b}\over 1-x})|^{2}={g^{2}\over 2(2\pi)^{3}}\int_{0}^{1}dx{x\over(1-x)}K_{0}^{2}(\sqrt{m_{1}^{2}(1-x)+m_{2}^{2}x-M^{2}x(1-x)}\;{b\over 1-x}) (31)

The transverse density ρ(b)\rho(b) has been derived previously mbimpact ; diehl2 as the integral of the impact parameter generalized parton distributions GPD ρ(x,b)\rho(x,b) over all values of xx. The quantity ρ(x,b)\rho(x,b) gives the probability that a quark of longitudinal momentum fraction xx resides at a transverse position mbimpact ; diehl2 . For the present model

ρ(x,b)=g22(2π)3x(1x)K02(m12(1x)+m22xM2x(1x)b1x).\displaystyle\rho(x,b)={g^{2}\over 2(2\pi)^{3}}{x\over(1-x)}K_{0}^{2}(\sqrt{m_{1}^{2}(1-x)+m_{2}^{2}x-M^{2}x(1-x)}\;{b\over 1-x}). (32)

The transverse density is also the integral of the three-dimensional infinite momentum frame density ρ(x,b)\rho(x^{-},b) over all values of the longitudinal position coordinate miller:2009qu .

The transverse density is directly obtainable from experiment via the inverse Fourier transform of Eq. (30) provided the electromagnetic form factor is measured for sufficiently large values of Q2Q^{2}. The momentum transfer is transverse in direction so that information about the longitudinal position or momentum is not available. There is no way to use only measured values of F(Q2)F(Q^{2}) to determine ρ(x,b)\rho(x,b).

IV.1 Singular central density

Before proceeding it is worthwhile to point out that the model central density is singular. This arises as a consequence of the zero range nature of the Ψϕξ\Psi\phi\xi coupling. The transverse density ρ(b)\rho(b) is an integral involving the singular function K0(x)K_{0}(x) which varies as log1x\log{1\over x} for x<<1x<<1. The question of the singularity of the central transverse density ρ(b)\rho(b) is interesting to the present author because of recent work miller:2009qu showing that for the pion ρ(b)\rho(b) is likely to approach infinity as bb approaches zero. We may study the limit as bb approaches 0 by using the asymptotic limit of the form factor Eq. (22). The density for bb near zero is controlled by the form factor at large values of Q2Q^{2}. We use the inverse of Eq. (29) to write

limb0ρ(b)Q0ϵ/bdQQln2(Q),\displaystyle\lim_{b\rightarrow 0}\rho(b)\sim\int_{Q_{0}}^{\epsilon/b}{dQ\over Q}\ln^{2}(Q), (33)

where Q0Q_{0} is a momentum transfer large enough so that so that Eq. (22) is valid, and ϵ\epsilon is a fixed positive number small enough so that J0(ϵ)=1J_{0}(\epsilon)=1 to any desired precision. Changing variables to u=lnQu=\ln Q shows that

limb0ρ(b)ln3(b)/3,\displaystyle\lim_{b\rightarrow 0}\rho(b)\sim\ln^{3}(b)/3, (34)

which is the central singular charge density arising from the log2Q2/Q2\log^{2}Q^{2}/Q^{2} behavior of the asymptotic form factor.

IV.2 Transverse Charge Density from a more general perspective

For a spin-0 system, the form factor F(Q2)F(Q^{2}), Eq. (3) may be computed, in the Drell-Yan DY frame (q+=0,Q2>0=𝐪2)(q^{+}=0,Q^{2}>0={\bf q}^{2}), by using

F(Q2)=p|J+(0)|p2p+.\displaystyle F(Q^{2})={\langle p^{\prime}|J^{+}(0)|p\rangle\over 2p^{+}}. (35)

The spatial structure of a nucleon can be examined if one uses soper1 ; mbimpact ; diehl2 . The state with transverse center of mass 𝐑{\bf R} set to 0 is formed by taking a linear superposition of states of transverse momentum:

|p+,𝐑=𝟎,𝒩d2𝐩(2π)2|p+,𝐩,,\left|p^{+},{\bf R}={\bf 0},\right\rangle\equiv{\cal N}\int\frac{d^{2}{\bf p}}{(2\pi)^{2}}\left|p^{+},{\bf p},\right\rangle, (36)

where |p+,𝐩,λ\left|p^{+},{\bf p},\lambda\right\rangle are plane wave states and 𝒩{\cal N} is a normalization factor satisfying |𝒩|2d2𝐩(2π)2=1\left|{\cal N}\right|^{2}\int\frac{d^{2}{\bf p}_{\perp}}{(2\pi)^{2}}=1. The normalization of the states is given by

p+,𝐩|p+,𝐩=2p+(2π)3δ(p+p+)δ(2)(𝐩𝐩).\displaystyle\langle{p^{\prime}}^{+},{\bf p}^{\prime}|{p}^{+},{\bf p}\rangle=2p^{+}(2\pi)^{3}\delta({p^{\prime}}^{+}-p^{+})\delta^{(2)}({{\bf p}}^{\prime}-{\bf p}). (37)

References mb1 ; diehl use wave packet treatments that avoid states normalized to δ\delta functions, but this leads to the same results as using Eq. (36). Note however, the relevant range of integration in Eq. (36) must be restricted to |𝐩|p+|{\bf p}|\ll p^{+} to maintain the interpretation of a nucleon moving with well-defined longitudinal momentummb1 . Thus we use a frame with very large p+p^{+}. It is in just such a frame that the interpretation of a nucleon as a set of a large number of partons is valid.

We evaluate the density operator in the infinite momentum frame in which the spatial coordinates are x=(tz)/2,𝐛x^{-}=(t-z)/\sqrt{2},{\bf b}, and time is x+=(t+z)/2=0x^{+}=(t+z)/\sqrt{2}=0. We therefore do not write the x+x^{+} dependence in any function below. The infinite momentum frame charge density operator (in units of the proton charge) is given by

ρ^(x,𝐛)J+(x,𝐛)=ϕ++ϕ(x,𝐛),\displaystyle\hat{\rho}_{\infty}(x^{-},{\bf b})\equiv J^{+}(x^{-},{\bf b})=\phi\stackrel{{\scriptstyle\leftrightarrow}}{{\partial^{+}}}\phi(x^{-},{\bf b}), (38)

and the density itself by

ρ(x,𝐛)=p+,𝐑=𝟎|ρ^(x,𝐛)|p+,𝐑=𝟎p+,𝐑=𝟎|p+,𝐑=𝟎.\displaystyle{\rho}_{\infty}(x^{-},{\bf b})={\left\langle p^{+},{\bf R}={\bf 0}\right|\hat{\rho}_{\infty}(x^{-},{\bf b})\left|p^{+},{\bf R}={\bf 0}\right\rangle\over\left\langle p^{+},{\bf R}={\bf 0}|p^{+},{\bf R}={\bf 0}\right\rangle}. (39)

Use translational invariance in the form ρ^(x,𝐛)=eip^+xei𝐩𝐛ρ^(0)e+i𝐩𝐛eip^+x\hat{\rho}_{\infty}(x^{-},{\bf b})=e^{i\hat{p}^{+}x^{-}}e^{-i{\bf p}\cdot{\bf b}}\hat{\rho}_{\infty}(0)e^{+i{\bf p}\cdot{\bf b}}e^{-i\hat{p}^{+}x^{-}} along with Eq. (39), Eq. (36) and Eq. (3) to determine that

𝑑xρ(x,𝐛)=1(2π)2d2𝐪F(Q2=𝐪2)ei𝐪𝐛=ρ(b).\displaystyle\int dx^{-}\rho_{\infty}(x^{-},{\bf b})=\frac{1}{(2\pi)^{2}}\int d^{2}{\bf q}F(Q^{2}={\bf q}^{2})e^{-i{\bf q}\cdot{\bf b}}=\rho(b). (40)

Thus one recovers the two-dimensional Fourier transform of Eq. (30).

IV.3 Mean-squared transverse radii and mean-squared effective radii

The two-dimensional Fourier transform of Eq. (30) may be expanded as a power series in Q2Q^{2} as

limQ20F(Q2)=1Q24b2,\displaystyle\lim_{Q^{2}\rightarrow 0}F(Q^{2})=1-{Q^{2}\over 4}\langle b^{2}\rangle, (41)

where the mean-squared transverse radius b2\langle b^{2}\rangle is given in terms of the transverse density as

b2=d2bb2ρ(b),\displaystyle\langle b^{2}\rangle=\int d^{2}bb^{2}\rho(b), (42)

and a direct relation with the transverse density is evident. In contrast, the usual procedure is to write

limQ20F(Q2)=1Q26R2,\displaystyle\lim_{Q^{2}\rightarrow 0}F(Q^{2})=1-{Q^{2}\over 6}{R^{*}}^{2}, (43)

where we denote R2{R^{*}}^{2} the effective mean-squared radiusMiller:2007kt . The quantity R2{R^{*}}^{2} has no direct relationship with a density unless the system is non-relativistic. Thus we maintain that b2\langle b^{2}\rangle is the basic quantity related to an underlying density. However, once the effective mean-squared radius R2{R^{*}}^{2} is determined, the fundamental b2\langle b^{2}\rangle is known immediately because a comparison of Eq. (41) and Eq. (43) reveals that

b2=23R2.\displaystyle\langle b^{2}\rangle={2\over 3}{R^{*}}^{2}. (44)

V Wave function as a function of three position variables

The previous section shows that the form factor is simply related to the three-dimensional coordinate-space density that depends on (x,𝐛)(x^{-},{\bf b}) in the infinite momentum frame. Given the simplicity of our model, we should be able to identify a wave function and density.

The basic idea is that the position variable of a particle xx^{-} is canonically conjugate to the plus-component of the momentum. The momentum of the charged constituent is k+=xP+k^{+}=xP^{+}, and its canonical longitudinal position variable is xx^{-} with [x,k+]=i=[x,x]P+[x^{-},k^{+}]=i=[x^{-},x]P^{+} Pirner:2009zz . The canonical longitudinal position variable for the other particle can be taken as x-x^{-}. So we can convert the wave function ψ(x,𝐁)\psi(x,{\bf B}) of Eq. (24) to one expressed entirely in coordinate space. We find

ψ(x,𝐁)=P+2π01𝑑xψ(x,𝐁)eixP+x,\displaystyle\psi(x^{-},{\bf B})=\sqrt{P^{+}\over 2\pi}\int_{0}^{1}\;dx\;\psi(x,{\bf B})e^{ixP^{+}x^{-}}, (45)

which preserves the normalization condition that F(Q2=0)=1F(Q^{2}=0)=1. Note that 𝐁{\bf B} is a relative variable and that xx^{-} is the variable for the position of the charged constituent. This wave function displays no spherical symmetry–the longitudinal xx^{-} and transverse position dependence 𝐁{\bf B} are not related. Another point is that the wave function Eq. (45) explicitly depends on the momentum P+P^{+}. As P+P^{+} approaches infinity, the value of xx^{-} must be very small to prevent xP+x^{-}P^{+} from being very large and causing the integral on Eq. (45) to vanish. This means that the system can be thought of as having a pancake or disc shape. For this reason, the position b=0b=0 really does correspond to the center of the hadron. We shall show below, that in the non-relativistic limit, rotational symmetry emerges.

The wave function can be computed in closed form for the special case M=0,m1=m2=mM=0,m_{1}=m_{2}=m. Using Eq. (24) in Eq. (45) with the stated parameters leads to the result

ψ(x,𝐁)=P+2πei12P+xgK0(mB)01𝑑xx(1x)2πeixP+x\displaystyle\psi(x^{-},{\bf B})=\sqrt{P^{+}\over 2\pi}e^{i{1\over 2}P^{+}x^{-}}g\;K_{0}({m}\;B)\int_{0}^{1}\;dx\;{\sqrt{x(1-x)}\over 2\pi}e^{ixP^{+}x^{-}} (46)
=P+2πei12P+xgK0(mB)πJ1(P+x2)4P+x\displaystyle=\sqrt{P^{+}\over 2\pi}e^{i{1\over 2}P^{+}x^{-}}g\;K_{0}({m}\;B)\frac{\pi J_{1}\left(\frac{P^{+}x^{-}}{2}\right)}{4P^{+}x^{-}} (47)

For this simple example, the xx^{-} and 𝐁{\bf B} dependence factorizes, showing the explicit violation of rotational symmetry. The formula Eq. (47) shows also how the spatial extent contracts with the increase in value P+P^{+}. We note that it is not useful to use the spatial wave function to compute the form factor because of the appearance of the factor 1x1-x in the exponential of Eq. (25).

VI The Rest Frame Charge Distribution is Generally Not Observable

The concept of a charge density that depends on three spatial variables, but not on the time, is inherently non-relativistic. This is because the use of only three variables involves replacing a four-dimensional quantity by one involving only three dimensions. One procedure, discussed above in Sect. II, is to evaluate the Feynman diagram of Fig. 1 by integrating over the kk^{-} component of the virtual momentum kk. This leads to a formalism in which the form factor depends on a Fourier transform of the square of a wave function that depends both on position 𝐁{\bf B} and momentum xx variables.

One can try to recover the more familiar three-spatial dimension formalism by evaluating the Feynman diagram of Fig. 1 using the time-ordered-perturbation theory TOPT formalism in the rest frame. One proceeds by integrating over all times, with the exponential oscillating factors converted into energy denominators. In the TOPT formalism any given Feynman diagram is the sum of several TOPT diagrams. In the present case, the sum of the two TOPT diagrams of Fig. 2 leads to the Feynman diagram of Fig. 1. Only Fig. 2a corresponds to measuring a density. The term of Fig. 2b corresponds to the hadronic part of the incident photon wave function interacting with the target.

Refer to caption
Figure 2: Two TOPT diagrams for the form factor with the photon coupling to the particle of mass m1m_{1}.

One can examine the contribution of the term of Fig. 2a, F2a(Q2)F_{2a}(Q^{2}). It is given Gunion:1973ex by

P+q|Jμ(0)|P(2P+q)μF2a(Q2)=g2(2π)3d3p2E12E12E2(p1μ+p1μ)(EPE1E2)(E𝐏+𝐪E1E2),\displaystyle\langle P+q|J^{\mu}(0)|P\rangle\rightarrow(2P+q)^{\mu}F_{2a}(Q^{2})={g^{2}\over(2\pi)^{3}}\int{d^{3}p\over 2E_{1}{2E_{1}}^{\prime}2E_{2}}{(p^{\mu}_{1}+{p^{\prime}}^{\mu}_{1})\over(E_{P}-E_{1}-E_{2})(E_{{\bf P}+{\bf q}}-{E^{\prime}}_{1}-E_{2})}, (48)

an expression that leads to the correct result in the infinite momentum frame (PP\rightarrow\infty) Gunion:1973ex . This expression can be interpreted as involving an initial and a final state wave function if one interprets the energy denominators (multiplied by phase space factors) as wave function expressed in momentum space. The symbol \rightarrow used above refers to the approximation of keeping only a single TOPT diagram. For simplicity we take the example, m1=m2=mm_{1}=m_{2}=m and also work in the target rest frame: 𝐏=𝟎{\bf P}=\bf{0} to isolate the rest frame charge distribution. Then EP=P2+M2=M,E𝐏+𝐪=(𝐏+𝐪)2+M2=𝐪2+M2,E1=p2+m2,E1=(𝐩+𝐪)2+m2E_{P}=\sqrt{P^{2}+M^{2}}=M,\;E_{{\bf P}+{\bf q}}=\sqrt{({\bf P}+{\bf q})^{2}+M^{2}}=\sqrt{{\bf q}^{2}+M^{2}},\;E_{1}=\sqrt{p^{2}+m^{2}},\;{E^{\prime}}_{1}=\sqrt{({\bf p}+{\bf q})^{2}+m^{2}}. The four vector (p1μ+p1μ)=[E1+E1,2𝐩+𝐪](p^{\mu}_{1}+{p^{\prime}}^{\mu}_{1})=[E_{1}+{E^{\prime}}_{1},2{\bf p}+{\bf q}]. There are three integrals appearing on the right-hand-side of Eq. (48):

I1(𝐪2)d3p2E12E12E2(p2+m2+(𝐩+𝐪)2+m2)(EPE1E2)(E𝐏+𝐪E1E2)\displaystyle I_{1}({\bf q}^{2})\equiv\int{d^{3}p\over 2E_{1}{2E_{1}}^{\prime}2E_{2}}{(\sqrt{p^{2}+m^{2}}+\sqrt{({\bf p}+{\bf q})^{2}+m^{2}})\over(E_{P}-E_{1}-E_{2})(E_{{\bf P}+{\bf q}}-{E^{\prime}}_{1}-E_{2})} (49)
𝐪^J2(𝐪2)d3p2E12E12E22𝐩(EPE1E2)(E𝐏+𝐪E1E2)\displaystyle\hat{{\bf q}}J_{2}({\bf q}^{2})\equiv\int{d^{3}p\over 2E_{1}{2E_{1}}^{\prime}2E_{2}}{2{\bf p}\over(E_{P}-E_{1}-E_{2})(E_{{\bf P}+{\bf q}}-{E^{\prime}}_{1}-E_{2})} (50)
𝐪^J3(𝐪2)d3p2E12E12E2𝐪(EPE1E2)(E𝐏+𝐪E1E2).\displaystyle\hat{{\bf q}}J_{3}({\bf q}^{2})\equiv\int{d^{3}p\over 2E_{1}{2E_{1}}^{\prime}2E_{2}}{{\bf q}\over(E_{P}-E_{1}-E_{2})(E_{{\bf P}+{\bf q}}-{E^{\prime}}_{1}-E_{2})}. (51)

Thus we arrive at the four-vector equality

(2P+q)μF2a(Q2)=g2(2π)3[I1,𝐪^(J2+J3)],\displaystyle(2P+q)^{\mu}F_{2a}(Q^{2})={g^{2}\over(2\pi)^{3}}[I_{1},\hat{{\bf q}}(J_{2}+J_{3})], (52)

Maintaining current conservation requires that the matrix element of qμJμq_{\mu}J^{\mu} vanishes. Taking the scalar product of Eq. (52) with qμq_{\mu} leads to the requirement:

0=q0I1|𝐪|(J2+J3)CCI1(𝐪2=0),\displaystyle 0=q^{0}I_{1}-|{\bf q}|(J_{2}+J_{3})\equiv CC\;I_{1}({\bf q}^{2}=0), (53)

where q0=𝐪2+M2Mq_{0}=\sqrt{{\bf q}^{2}+M^{2}}-M. The right-hand-side of Eq. (53) is defined as CCI1(0)CC\;I_{1}(0) so that comparing CCCC to unity provides a reasonable measure of the failure of this approximation to uphold current conservation. We express all momenta and mass in units of the target mass (=1), take as an examples m=0.501, 0.51m=0.501,\;0.51 and 0.6 and plot the numerical results in Fig. 3. Both CCCC and 𝐪2=Q2{\bf q}^{2}=Q^{2} are measured in units of the target mass MM, taken as unity. Thus the natural scale of any quantity is unity. We see that current conservation is massively violated in the rest frame for systems in which B/m=(2mM)/mB/m=(2m-M)/m is not very small. In that case, the expression that potentially depends on the square of the wave function or density has no independent physical reality.

Refer to caption
Figure 3: Non-conservation of current is measured by the deviation of CCCC from 0 as a function of 𝐪2=Q2{\bf q}^{2}=Q^{2} (in units of M2M^{2}). Solid curve m=0.51B/M=0.04m=0.51\;B/M=0.04, short-dashed curve m=0.501B/M=0.004m=0.501\;B/M=0.004 long-dashed curve m0.6B/M=0.33m0.6\;B/M=0.33 ( mmin units of MM)

VII Neutral Systems

Previous work Miller:2007uy showed that the central transverse density of the neutron is negative. This contrasts with the long held view that there must be positive charge density at the center to neutralize the effects of a negatively charged pionic cloud that occupies the exterior. This result demands interpretation Miller:2008jc -Rinehimer:2009sz .

One relevant question is whether or not the intuition that a neutral system consisting of a heavy charge positively charged particle and a negatively charged lighter particle disobeys the standard intuition that the averaged squared charged radius is negative, when the charge density is evaluated in the infinite momentum frame. We examine this question in our model by taking the ϕ\phi (of mass m1m_{1}) to be positively charged and the ξ\xi (of mass m2<m1m_{2}<m_{1} to be negatively charged.

The form factor of this model can be obtained by using Eq. (8) by including a second term obtained by interchanging m1m_{1} and m2m_{2} and putting a minus sign in front. That operation gives the result

F(Q2)=g24π201dxx[Tanh1[Q2(1x)4xm22+4v(1x)m12x(1x)M2+(1x)2Q2]Q24xm22+4(1x)m12x(1x)M2+(1x)2Q2\displaystyle F(Q^{2})={g^{2}\over 4\pi^{2}}\int_{0}^{1}dxx[{{\rm Tanh}^{-1}[{\sqrt{Q^{2}}(1-x)\over\sqrt{4x\;m_{2}^{2}+4v(1-x)m_{1}^{2}-x(1-x)M^{2}+(1-x)^{2}Q^{2}}}]\over\sqrt{Q^{2}}\sqrt{4x\;m_{2}^{2}+4(1-x)m_{1}^{2}-x(1-x)M^{2}+(1-x)^{2}Q^{2}}}-
Tanh1[Q2(1x)4xm12+4(1x)m22x(1x)M2+(1x)2Q2]Q24xm22+4(1x)m12x(1x)M2+(1x)2Q2].\displaystyle{{\rm Tanh}^{-1}[{\sqrt{Q^{2}}(1-x)\over\sqrt{4x\;m_{1}^{2}+4(1-x)m_{2}^{2}-x(1-x)M^{2}+(1-x)^{2}Q^{2}}}]\over\sqrt{Q^{2}}\sqrt{4x\;m_{2}^{2}+4(1-x)m_{1}^{2}-x(1-x)M^{2}+(1-x)^{2}Q^{2}}}]. (54)

The results of a numerical evaluation using m1=Mm_{1}=M and m2=0.14Mm_{2}=0.14M are shown in Fig. 4. One observes the rise of F(Q2)F(Q^{2}) from zero, which is the effect expected from non-relativistic, rest-frame considerations. The effective squared radius, defined in Eq. (43) is indeed negative. This is the same as expected from the intuition that the negatively charged light particle resides on the outside edge of the system.

Refer to caption
Figure 4: Form factor for a neutral system with one heavy m2=Mm_{2}=M and one light m1=0.14Mm_{1}=0.14\;M negatively charged constituent.

One obtains the analytic result for the charge radius by taking the limit of very low Q2Q^{2} in the expression for the form factor Eq. (54). The expression is simplified if one uses the (relevant for nucleon)assum case of m1=Mm_{1}=M. Then one finds:

M2R2=g296π2((m22M21)(2tan1(m22M2(4m22M2)m22)m22M2(m22M25)24m22M2)m22(4m22M2)3/2log(m22M2)).\displaystyle M^{2}{R^{*}}^{2}=-{g^{2}\over 96\pi^{2}}\left(\frac{\left(\frac{m_{2}^{2}}{M^{2}}-1\right)\left(-2\tan^{-1}\left(\frac{\sqrt{{m_{2}^{2}\over M^{2}}\left(4-\frac{m_{2}^{2}}{M^{2}}\right)}}{m_{2}^{2}}\right)\sqrt{\frac{m_{2}^{2}}{M^{2}}}\left(\frac{m_{2}^{2}}{M^{2}}-5\right)-2\sqrt{4-\frac{m_{2}^{2}}{M^{2}}}\right)}{m_{2}^{2}\left(4-\frac{m_{2}^{2}}{M^{2}}\right){}^{3/2}}-\log\left(\frac{m_{2}^{2}}{M^{2}}\right)\right). (55)

A very accurate approximation (better than 1% for m220.14M2m^{2}_{2}\leq 0.14M^{2}) is

M2R2=g24π2(M248m22+196(14log(m22M2))+11512πm22M25π192m22M27m22288M2).\displaystyle M^{2}{R^{*}}^{2}=-{g^{2}\over 4\pi^{2}}\left(\frac{M^{2}}{48m_{2}^{2}}+\frac{1}{96}\left(1-4\log\left(\frac{m_{2}^{2}}{M^{2}}\right)\right)+\frac{11}{512}\pi\sqrt{\frac{m_{2}^{2}}{M^{2}}}-\frac{5\pi}{192\sqrt{\frac{m_{2}^{2}}{M^{2}}}}-\frac{7m_{2}^{2}}{288M^{2}}\right). (56)

The radius is dominated by a singular term proportional to 1/m221/m_{2}^{2}. Thus as expected the lighter constituent drifts to the edge of the nucleon. The conventional expectation is borne out on the light front. This is shown in more detail by plotting bρ(b)b\rho(b), as shown in Fig. 5. The positive charge density is concentrated at the center and the negative at the edge. This finding does not contradict the explanations offered in Refs. Miller:2008jc -Rinehimer:2009sz . Ref.Miller:2008jc argues that negative charge at high xx corresponds to negative charge at small values of bb. The NπN\pi model of Ref. Rinehimer:2009sz shows that one must include the finite size of the nucleon to obtain a computed F1F_{1} that looks like the measured function. Thus the point-like nature of the constituents used here is unsurprisingly not relatistic. Moreover, in that model negatively charged pions reside both at the edge and at the center of the nucleon. The implication of Miller:2008jc is that the pions may have large values of longitudinal momentum fraction. This expectation is borne out by the model calculation Strikman:2009bd . Thus in pion cloud models of the nucleon pions that have a large longitudinal momentum tend to reside near the center of the nucleon.

Refer to caption
Figure 5: Transverse charge density for a neutral system of a positively charged heavy object and a negatively charged lighter object

VIII Non-relativistic Limit

The conventional lore is that the electromagnetic form factor is the Fourier transform of the charge density. In this section we see how this idea emerges by taking the non-relativistic limit.

Our starting point is the wave function Eq. (16) and the form factor Eq. (17). Recall that the quantity x=k+/P+x=k^{+}/P^{+}. We work in the rest frame and take the non-relativistic limit in which the energy k0=m1k^{0}=m_{1}, and k+=m1+κ3k^{+}=m_{1}+\kappa^{3}, where κ3\kappa^{3} is the third-component of the relative longitudinal momentum. Then Brodsky:1989pv ; Frankfurt:1981mk

x=m1+κ3M,1x=Mm1κ3M=m2Bκ3M,\displaystyle x=\frac{m_{1}+\kappa^{3}}{M},\quad 1-x=\frac{M-m_{1}-\kappa^{3}}{M}=\frac{m_{2}-B-\kappa^{3}}{M}, (57)

where in conformation with non-relativistic notation, we define the positive binding energy BB so that

Mm1+m2B.\displaystyle M\equiv m_{1}+m_{2}-B. (58)

To obtain the non-relativistic expression we express the denominator appearing in Eq. (16) in terms of κ3\kappa^{3}. This gives

M2𝜿2+m12x𝜿2+m221x\displaystyle M^{2}-{\mbox{\boldmath$\kappa$}^{2}+m_{1}^{2}\over x}-{\mbox{\boldmath$\kappa$}^{2}+m_{2}^{2}\over 1-x} (59)
=M2M[𝜿2+m12m1+κ3+𝜿2+m22m2Bκ3]\displaystyle=M^{2}-M[{\mbox{\boldmath$\kappa$}^{2}+m_{1}^{2}\over m_{1}+\kappa^{3}}+{\mbox{\boldmath$\kappa$}^{2}+m_{2}^{2}\over m_{2}-B-\kappa^{3}}] (60)
M2M[𝜿2+m12m1(1κ3m1+(κ3m1)2)+𝜿2+m22m2(1+κ3+Bm2+(κ3+Bm2)2)]\displaystyle\approx M^{2}-M[{\mbox{\boldmath$\kappa$}^{2}+m_{1}^{2}\over m_{1}}\left(1-{\kappa^{3}\over m_{1}}+({\kappa^{3}\over m_{1}})^{2}\right)+{\mbox{\boldmath$\kappa$}^{2}+m_{2}^{2}\over m_{2}}\left(1+{\kappa^{3}+B\over m_{2}}+({\kappa^{3}+B\over m_{2}})^{2}\right)] (61)
(𝜿2+κ32)(1m1+1m2)+m1+m2+B]\displaystyle\approx(\mbox{\boldmath$\kappa$}^{2}+\kappa_{3}^{2})({1\over m_{1}}+{1\over m_{2}})+m_{1}+m_{2}+B] (62)
=2M(Bκ22μ),\displaystyle=2M(-B-{\kappa^{2}\over 2\mu}), (63)

where

κ2𝜿2+κ32,κ=𝜿+κ3𝐳^,μm1m2m1+m2.\displaystyle{\kappa}^{2}\equiv\mbox{\boldmath$\kappa$}^{2}+\kappa_{3}^{2},\;\vec{\kappa}=\mbox{\boldmath$\kappa$}+\kappa^{3}\hat{{\bf z}},\;\mu\equiv{m_{1}m_{2}\over m_{1}+m_{2}}. (64)

In going from Eq. (59) to Eq. (63) we have ignored terms in v/c=k/mv/c=k/m of order three and higher. The result is that Eq. (63) is recognizable as 2M2M times the inverse of the non-relativistic propagator.

The next step is to determine the coordinate form of the non-relativistic wave function ψNR(r)\psi_{NR}(\vec{r}) (where r\vec{r} is canonically conjugate to κ\vec{\kappa}) and to show that the non-relativistic form factor is a three-dimensional Fourier transform of |ψNR(r)|2\left|\psi_{NR}(\vec{r})\right|^{2}. First use the non-relativistic approximation Eq. (63) in Eq. (16) to find

ψNR(κ)=2μgκ2+λ2,λ22μB.\displaystyle\psi_{NR}(\vec{\kappa})={-2\mu g\over\kappa^{2}+\lambda^{2}},\;\lambda^{2}\equiv 2\mu B. (65)

The coordinate-space wave function ψNR(r)\psi_{NR}(\vec{r}) is given by

ψNR(r)=1(2π)3/2d3κeiκrψNR(κ)=μgMπ2eλrr.\displaystyle\psi_{NR}(\vec{r})={1\over(2\pi)^{3/2}}\int d^{3}\kappa e^{i\vec{\kappa}\cdot\vec{r}}\psi_{NR}(\vec{\kappa})=-{\mu g\over M}\sqrt{\pi\over 2}{e^{-\lambda r}\over r}. (66)

The expression Eq. (66) is seen as the standard result obtained for the bound state of a two-particle system interacting via an attractive delta function potential.

The wave functions Eq. (65) and Eq. (66) enable us to examine the condition needed for the approximations Eq. (57) to be valid. For Eq. (57) to work we need κ2m1,22\kappa^{2}\ll m_{1,2}^{2}, but from the wave functions κ2λ2\kappa^{2}\sim\lambda^{2} so that we require

μBm1,221\displaystyle{\mu B\over m_{1,2}^{2}}\ll 1 (67)

for the non-relativistic approximation to be valid. More specifically let {\cal M} be the lighter of m1,m2m_{1},m_{2}, then we may write the approximate condition as

B<<1.\displaystyle{B\over{\cal M}}<<1. (68)

The non-relativistic form factor FNR(Q2)F_{NR}(Q^{2}) is obtained by using Eq. (65) in the expression for the form factor Eq. (17), and taking the non-relativistic limit defined by the expressions:

dxdκ3(m1+m2)\displaystyle dx\rightarrow{d\kappa^{3}\over(m_{1}+m_{2})} (69)
x(1x)m1m2m1+m2\displaystyle x(1-x)\rightarrow{m_{1}m_{2}\over m_{1}+m_{2}} (70)
(1x)𝐪m2m1+m2𝐪.\displaystyle(1-x){\bf q}\rightarrow{m_{2}\over m_{1}+m_{2}}{\bf q}. (71)

The result is

FNR(Q2)=12(2π)3μd3r|ψNR(r)|2ei𝐪𝐫m2m1+m2.\displaystyle F_{NR}(Q^{2})={1\over 2(2\pi)^{3}\mu}\int d^{3}r\left|\psi_{NR}(\vec{r})\right|^{2}e^{-i{\bf q}\cdot{\bf r}{m_{2}\over m_{1}+m_{2}}}. (72)

This is the usual expectation that the form factor is a three-dimensional Fourier transform of the wave function. We may evaluate the integral immediately to find

FNR(Q2)=tan1Qm22(m1+m2)λQm22(m1+m2)λ,\displaystyle F_{NR}(Q^{2})={\tan^{-1}{Qm_{2}\over 2(m_{1}+m_{2})\lambda}\over{Qm_{2}\over 2(m_{1}+m_{2})\lambda}}, (73)

where Q=|𝐪|Q=|{\bf q}| and the coupling constants and other constants enter in such a manner as to make FNR(Q2=0)=1F_{NR}(Q^{2}=0)=1.

In the remainder of this section we study the accuracy of the non-relativistic approximation by comparing the results of using Eq. (73) with the model-exact results of using Eq. (8) for several examples.

VIII.1 Bound state of two equal mass particles

With equal masses m1=m2=mm_{1}=m_{2}=m the bound state can be thought of as a toy meson or a deuteron. Use m1=m2=mm_{1}=m_{2}=m in Eq. (65) leads to the non-relativistic wave function ψNR(2)(κ)\psi_{NR}^{(2)}(\kappa) with

ψNR(2)(κ)=g2M(κ2+λ22),\displaystyle\psi_{NR}^{(2)}(\kappa)={g\over 2M(\kappa^{2}+\lambda_{2}^{2})}, (74)

with

λ22=mB.\displaystyle\lambda_{2}^{2}=mB. (75)

The coordinate space wave function ψNR(r)\psi_{NR}(r) is then

ψNR(2)(r)=π2g2Meλ2rr.\displaystyle\psi_{NR}^{(2)}(r)=\sqrt{\pi\over 2}{g\over 2M}{e^{-\lambda_{2}r}\over r}. (76)

Thus the wave function is the usual bound state wave function one obtains with a delta function binding interaction. We obtain the non-relativistic version of the form factor by using m1=m2=m,λλ2m_{1}=m_{2}=m,\lambda\rightarrow\lambda_{2} in Eq. (73) to find

FNR(2)(Q2)=tan1Q4λ2Q4λ2,\displaystyle F_{NR}^{(2)}(Q^{2})={\tan^{-1}{Q\over 4\lambda_{2}}\over{Q\over 4\lambda_{2}}}, (77)

where Q=|𝐪|Q=|{\bf q}| and the coupling constants and other constants enter in such a manner as to make FNR(2)(Q2=0)=1F_{NR}^{(2)}(Q^{2}=0)=1.

Refer to caption
Figure 6: Exact vs non-relativistic form factors for the case m1=m2=mm_{1}=m_{2}=m. Solid curve- exact result, dashed curve-non-relativistic limit. Upper panel deuterium-like kinematics in which B=0.002MB=0.002M. Lower panel- B=0.1MB=0.1M.

We study the non-relativistic approximation numerically by comparing the exact model results Eq. (17) with those of the non-relativistic approximation Eq. (77). See Fig. 6. The figure shows two sets of results. In the upper panel the binding energy B=0.002MB=0.002\;M. This corresponds roughly to deuteron kinematics, in which the binding energy is of the order of a 0.004 of the deuteron mass. We see that the non-relativistic approximation is not accurate for values of Q2/M2Q^{2}/M^{2} greater than about 1. If one increases the binding energy to 0.1 MM, one sees that the non-relativistic approximation is not accurate for any value of Q2Q^{2}. If one approximates a nucleon by taking M=M= 1 GeV, then m=0.55m=0.55 GeV, which is much larger than a u,du,d constituent quark mass. Thus the range of masses for which the non-relativistic approximation is valid is very narrow indeed.

We can gain some insight into the nature of the relativistic corrections to the charge radius by studying the low Q2Q^{2} limit of the form factor of Eq. (8). One finds

limQ20F(Q2)=1Q2R26,\displaystyle\lim_{Q^{2}\rightarrow 0}F(Q^{2})=1-{Q^{2}{R^{*}}^{2}\over 6}, (78)

where we use the notation R2{R^{*}}^{2} to denote an effective radius squared that is not generally associated with the expectation of the square of a radius operator weighted by a density. The explicit evaluation gives

M2R2=(1γ3+48γ)cot1(2γ)+2γ22416((2γ+12γ)cot1(2γ)1),\displaystyle M^{2}{R^{*}}^{2}=\frac{\left(\frac{1}{\gamma^{3}}+48\gamma\right)\cot^{-1}(2\gamma)+\frac{2}{\gamma^{2}}-24}{16\left(\left(2\gamma+\frac{1}{2\gamma}\right)\cot^{-1}(2\gamma)-1\right)}, (79)

and

γ2m2M214=B2M+B24M2.\displaystyle\gamma^{2}\equiv{m^{2}\over M^{2}}-{1\over 4}={B\over 2M}+{B^{2}\over 4M^{2}}. (80)

The non-relativistic limit corresponds to the limit of small values of γ\gamma, which corresponds to a small value of B/MB/M. So we expand the previous result to order B/MB/M to find

M2R2(122882816π2+195π4)B48Mπ4+BM(1282252π2)4π3+645π28π2+2BMπ+M4B\displaystyle M^{2}{R^{*}}^{2}\approx\frac{\left(12288-2816\pi^{2}+195\pi^{4}\right)B}{48M\pi^{4}}+\frac{\sqrt{\frac{B}{M}}\left(128\sqrt{2}-25\sqrt{2}\pi^{2}\right)}{4\pi^{3}}+\frac{64-5\pi^{2}}{8\pi^{2}}+\frac{\sqrt{2}}{\sqrt{\frac{B}{M}}\pi}+\frac{M}{4B} (81)

The non-relativistic value of the mean square radius, RNR2R_{NR}^{2} (which is a true mean square radius) is obtained by expanding the form factor for small values of Q2Q^{2}:

RNR2=18mB14MB,\displaystyle R^{2}_{NR}={1\over 8mB}\approx{1\over 4MB}, (82)

which corresponds to the leading term of Eq. (81) in the limit that BB approaches 0. Comparing Eq. (81) with Eq. (82) shows that the former contains a series of terms that represent the boost corrections to the non-relativistic result. Each correction is positive and can be substantial. The figure 7 shows the ratio of the exact of the mean square radius to the non-relativistic approximation as a function of B/MB/M. We see that the non-relativistic approximation works well only for very small values of B/MB/M. Indeed, the ratio of the leading correction to the non-relativistic result is given by

R2RNR2RNR24π2BM.\displaystyle{{R^{*}}^{2}-R_{NR}^{2}\over R_{NR}^{2}}\approx{4\over\pi}\sqrt{2B\over M}. (83)

For this ratio to be less than 10 %, BM{B\over M} must be less than one part in a thousand! Thus, within the framework of our toy model, the relativistic corrections can generally expected to be very substantial.

Refer to caption
Figure 7: Ratio of exact to non-relativistic effective square radii for the case m1=m2=mm_{1}=m_{2}=m as a function of the ratio of the binding energy BB to the hadronic mass MM. This is also the ratio of the true value of b2\langle b^{2}\rangle to its non-relativisitic version.

VIII.2 Quark-diquark model of the nucleon

Another interesting example is motivated by recent quark-diquark models of the nucleon Oettel:2000jj ; Horikawa:2005dh ; Cloet:2008re . We take m1=m,m2=2m1=2mm_{1}=m,m_{2}=2m_{1}=2m. Then from Eq. (58) we have M=3mBM=3m-B. In these, models current quarks acquire a large constituent mass due to the effects of dynamical chiral symmetry breaking. Therefore we take m=400m=400 MeV, and M=940M=940 MeV which corresponds via Eq. (58) to B=260B=260 MeV and B/MB/M = 0.276. The non-relativistic expression for the form factor, FNRq2q(Q2)F_{NR}^{q2q}(Q^{2}) for this case is obtain using the appropriate reduced mass as

FNRq2q(Q2)=tan1Q3λ12Q3λ12,\displaystyle F_{NR}^{q2q}(Q^{2})={\tan^{-1}{Q\over 3\lambda_{12}}\over{Q\over 3\lambda_{12}}}, (84)
λ12243mB.\displaystyle\lambda_{12}^{2}\equiv{4\over 3}mB. (85)

Results comparing the exact form factor computed from Eq. (8) with that of Eq. (84) are shown in Fig. 8. The non-relativistic version gives a poor approximation to the exact form factor for all values of Q2Q^{2}. This can be understood by considering the effective squared radius Rq2q2{R^{*}}^{2}_{q2q} for this case. We find

Rq2q2RNR2RNR26ln2πBM.\displaystyle{{R^{*}}^{2}_{q2q}-R_{NR}^{2}\over R_{NR}^{2}}\approx{6-\ln 2\over\pi}\sqrt{B\over M}. (86)

The right-hand-side is evaluated as 0.887 for the present case, so that there is a substantial relativistic correction to the quantity FNR(2)1F_{NR}^{(2)}-1 for any non-zero value of Q2Q^{2}. This means that one can not take a three-dimensional Fourier transform of the form factor to get a charge density even if the constituent masses are large.

Refer to caption
Figure 8: Exact vs non-relativistic form factors for the case m2=2m1,m=400m_{2}=2m_{1},m=400 MeV, B=260MeV=0.276MB=260\;{\rm MeV}=0.276\;M. Solid curve-exact, dashed non-relativistic.

VIII.3 Nuclear Physics and m1m2m_{1}\neq m_{2}

We consider masses that correspond to electron scattering from a charged nucleon of mass mm (which is the free nucleon mass minus the average binding energy per nucleon of 8 MeV) bound in a nucleus of mass M=mAM=mA, with a spectator system of mass m2=(A1)m+Sm_{2}=(A-1)m+S, where SS is the orbital separation energy. We measure all momenta in terms of m=932m=932 MeV, and take the separation energy S=0.05S=0.05 or SmSm about 46 MeV. The results for A=4A=4 and A=208A=208 are shown in Figs. 9 and 10

Refer to caption
Figure 9: Exact vs (solid curve) non-relativistic form factors (dashed curve) for A=4A=4 for Sm=46Sm=46 MeV.
Refer to caption
Figure 10: Exact (solid curve) vs (dashed curve) non-relativistic form factors for A=208A=208 for Sm=46Sm=46 MeV.

The startling finding is that the relativistic effects reduce the form factor for light nuclei, but increase it for heavy nuclei. Furthermore, the relativistic effects are larger for heavy nuclei than for light nuclei (for a fixed value of SS.)

We obtain some analytic understanding by expanding the effective squared radius (defined in Eq. (78) in powers of SS. We find

m2R2=A14AS+(A1)A(4A(A2)log((A1)2))42A2πS+.\displaystyle m^{2}{R^{*}}^{2}=\frac{A-1}{4AS}+\frac{\sqrt{(A-1)A}\left(4A-(A-2)\log\left((A-1)^{2}\right)\right)}{4\sqrt{2}A^{2}\pi\sqrt{S}}+\cdots. (87)

We see that the first term is indeed the non-relativistic result, and that the second term changes sign for the value of AA that satisfies the equation 4A2(A2)ln(A1)=04A-2(A-2)\ln(A-1)=0 or A12A\approx 12. This displayed in Fig. 11. It is also seen that the relativity causes very significant effects on the effective radii. Except for values of AA near 12, the changes are of the order of 10-15%. I expect that the specific values shown in Fig. 11 are highly model-dependent. Covariant models other than the Ψϕξ\Psi\phi\xi model used here probably have have effects of different sizes. However, the large effects shown here cause one to wonder if relativity really may cause the true nuclear radii extracted from elastic electron scattering to differ by 10-20% from those appearing in tables. As noted above, we can expect that the model employed here is a reasonable representation of the lowest ss-state of heavy nuclei for which the range of the binding interactions is much less than the size of the system as a whole. For such states, the results of Fig. 11 should be a reasonably accurate guide, so that significant effects of relativity should be expected.

Refer to caption
Figure 11: Exact vs non-relativistic effective radii, R2RNR21\frac{{R^{*}}^{2}}{{R_{NR}^{*}}^{2}}-1 as a function of AA for Sm=46Sm=46 MeV. This is also the ratio of b2\langle b^{2}\rangle to its non-relativistic counterpart.

.

IX Summary

A relativistic model of a scalar particle Ψ\Psi is a bound state of two scalar particles ϕ\phi and ξ\xi is used to elucidate relativistic aspects of electromagnetic form factors. First, the form factor for the situation in which the Ψ\Psi and ϕ\phi carry a single unit of charge, but the ξ\xi is neutral is computed using an exact covariant calculation of the lowest-order triangle diagram. This is followed by a another derivation using the light-front technique of integrating over the minus-component of the virtual momentum in Sect. III that obtains the same form factor. This is also the result obtained originally by Gunion:1973ex by using time-ordered perturbation theory in the infinite-momentum-frame IMF. Thus three different approaches yield the same exact result for this model problem. The asymptotic limit of asymptotically high momentum transfer Q2Q^{2} is also studied with the result that F(Q2)1/2ln2Q2/Q2F(Q^{2})\sim 1/2\ln^{2}Q^{2}/Q^{2} The next section (IV) explains the meaning of transverse density ρ(b)\rho(b) of the model. Its central value varies singularly as ln3(b)/3\ln^{3}(b)/3. A general derivation of the relationship of ρ(b)\rho(b) with the form factor using three dimensional spatial coordinates is presented. This allows us to identify a mean-square transverse size b2=d2bb2ρ(b)\langle b^{2}\rangle=\int d^{2}b\;b^{2}\rho(b) that is given by b2=4dFdQ2(Q2=0)b^{2}=-4{dF\over dQ^{2}}(Q^{2}=0). The quantity b2\langle b^{2}\rangle is a true measure of hadronic size because of its direct relationship with the transverse density. Using this model it is possible to display the spatial wave function in terms of three spatial coordinates (Section V), but this is not very useful. Section VI shows that the rest-frame charge distribution is generally not observable by studying the explicit failure to uphold current conservation. Section VII shows that neutral systems of two constituents obey the conventional lore that the heavier one is generally closer to the transverse origin than the lighter one. It is also argued that the negative central charge density of the neutron arises in pion-cloud models from pions residing at the center of the nucleon. The non-relativistic limit is defined and applied to a variety of examples in Section VIII. By varying the masses one can study a continuum of examples in which the constituents move at a wide range of average velocities. The relevant quantity is the ratio of the binding energy BB to that of the mass {\cal M} of the lightest constituent (ϕ\phi or ξ\xi). For small values of B/B/{\cal M} the exact relativistic formula is shown to be the same as the familiar one of the three-dimensional Fourier transform of a square of a wave function. If the ϕ\phi and ξ\xi have equal masses mm we find that B/(2m)B/(2m) must be less than 0.001 for the relativistic corrections to mean-square radii to be be less than 10%, see Eq. (83). For the case when mξ=2mϕm_{\xi}=2m_{\phi} which mimics the quark-di-quark model of the nucleon we find that there are substantial relativistic corrections to the form factor for any value of Q2Q^{2}. This means that one can not take a three-dimensional Fourier transform of the form factor to get a charge density even if the constituent masses are large. A schematic model of the lowest ss-states of nuclei is developed by choosing mξ=(A1)mϕm_{\xi}=(A-1)m_{\phi}, where AA is the nucleon number. Relativistic effects are found to decrease the form factor for light nuclei but to increase the form factor for heavy nuclei. Furthermore, these lowest ss-states are likely to be strongly influenced by relativistic effects that are order 15-20%.

I thank the USDOE (FG02-97ER41014) for partial support of this work, S. Brodsky for advocating the use of the ϕ3\phi^{3} model as a pedagogic tool, and J. Arrington, A. Bernstein, M. Burkardt, I. Cloët, B. Jennings, E. Henley, and W. Polyzou for useful discussions.

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