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On admissible steady-state regimes of crack propagation in a square-cell lattice.

Nikolai Gorbushin, Gennady Mishuris
Department of Mathematics, Aberystwyth University,
Ceredigion SY23 3BZ, Wales, UK
Abstract

In the present work the authors revisit a classical problem of crack propagation in a lattice. Authors investigate the questions concerning possible admissible steady-state crack propagations in an anisotropic lattice. It was found that for certain values of contrast in elastic and strength properties of a lattice the stationary crack propagation is impossible. Authors also address a question of possible crack propagation at low velocity.

Keywords: Fracture, discrete lattice structure, Wiener-Hopf method

1 Introduction

The difference in the radiation of mechanical waves in discrete and continuum solids effects on crack propagation in them. It seems that the first one who noticed that was Thomson in his work [23]. Thomson used the simple model of two horizontal chains of oscillators linked together in vertical direction. It was shown that for the unstable crack propagation in one-dimensional discrete structure one should apply the load almost as twice as the load needed to break one link following Griffith’s fracture criterion. It was he who proposed the term ”lattice trapping” characterising such a phenomenon.

Somehow later and independently from Thomson, Slepyan came out with the solution for the problem of a steady-state fault propagation in one-dimensional [20] and two-dimensional [6] discrete structures. It was presented that while the fracture happens in the discrete structure not only the fracture energy is released but also the energy carried by the waves that have a crack tip as their source. Such fracture waves are spotted in the experiments [17] and numerical simulations [3]. Slepyan’s approach was successfully applied for the study of fracture problems of various structures such as bridged crack propagation [9], chain with non-local interaction [4], lattice with a structured interface [10], lattice fracture with dissipation [21]. The method was also used to analyse the problems of phase transformations [19, 24].

The most of interest in the study of crack propagation is focused on the analysis of their stability. Experimental data reveal the correlation between the crack speed and the patterns on the fracture surface [15]. Based on the triangular lattice models and the above mentioned approach there were attempts to define the ranges of the crack speeds that correspond to instabilities [2, 13]. This, however, was also done by the consideration of the continuum solids [25, 12, 14].

It should be pointed out that the computation of the dynamical crack propagation problems are time-consuming for both continuum and discrete solids. Particularly, the steady-state regime that is detected experimentally [2] can be compared with the analytical solution based on the mentioned method. The application of the analytical technique allows to obtain loading parameters that lead to a steady-state without heavy computations. Moreover, the numerical simulation of the continuum models require the discretisation of spatial and temporal domains. Due to this one may wonder whether the achieved effects are valid for the true continuous model or influenced by the discretisation. For example, FEM analysis with implemented cohesive zone elements shoes the oscillations of stress fields close to a crack tip in time [26].

One of the major theoretical results obtained by Slepyan is the dependence of the energy release rate on the crack speed. Slepyan [21] and Marder [2] marked the crack speeds that possibly correspond to the stable steady-state crack propagation.

In the last decades there was a significant progress in the study of dynamical crack growth in discrete media. For instance, different types of loads were considered and the peculiarities caused by them were studied. Among the list of the examples we can name the energy flux from infinity [20, 6, 9, 4], waves of a certain frequencies coming from infinity [10], constant displacement of lattice edges (in case of finite lattice width) [2, 13]. Notice that the problem itself is non-linear and superposition principle does not work. Furthermore, numerical simulations showed that there exist regimes that are not compatible with steady-state ones [2, 13] and the linear analysis of stability was performed [7]. Apart from that there were numerically observed [10] and theoretically explained later on in [22] so-called clustering quasi steady-state regime, where in average the crack moves regularly but within the period (cluster) it is not seen. Another periodic process,forerunning, was numerically studied [18]. It characterises by the periodic appearing of the damaged region ahead of the main running crack. Such effect is presented in experiments when the crack movement is supported by the developing microcracks ahead of it [16]. Nevertheless, there are still many details remained untouched. So, after the prediction of possible stable steady-state regimes Marder wrote [8]: ”The complete story has yet to be worked out”.

In the present work we try to answer on the some of the addressed questions. Namely, is it possible to observe stable steady-state crack propagation at low speeds which was shown in [4, 5, 11]. In these papers it was shown that the anisotropy in the properties has an impact on the obtaining such an effect which was numerically confirmed. It should be stressed that Slepyan’s approach deals with discrete difference problem of moving defect but not the original problem. Thus, the obtained steady-state regimes should be verified and their specifics should be analysed (see clustering above). Works [5, 11] referred to the one-dimensional cases but the lattice problems and these two problems have meaningful differences.

We consider a crack propagation in a square-cell lattice with different elastic properties in its orthogonal directions. We derive the solution of the problem and analyse the steady-state regimes. The solution is gained similarly to [21] but with the additional information useful for the current study. We demonstrate the peculiarities brought by anisotropy and point out details that were not mentioned previously in the literature (admissible regimes, the displacement in the direction perpendicular to the crack).

2 Analytical solution of the problem.

2.1 Mathematical formulation of the problem

We proceed to the consideration of crack propagation in 2-d lattice shown in fig.1.

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Figure 1: Infinite chain of oscillators with equal masses MM connected together by linear springs of stiffness c1c_{1} in a horizontal direction and c2c_{2} in a vertical direction. The crack position is defined by oscillator with index nn_{*}. The vertical springs of the stiffness c2c_{2} along the symmetry line break while the crack moves. aa is an equilibrium distance between the oscillators.

The derivation of the solution can be found [21] and here we present the key points of it with the extensions for the further analysis. The governing equations for this problem are:

m=0:Mu¨0,n=c1(u0,n+1+u0,n12u1,n)2c2u0,n+c2(u1,nu0,n),nn,Mu¨0,n=c1(u0,n+1+u0,n12u0,n)+c2(u1,nu0,n),n<n,m=0:\begin{array}[]{l}M\ddot{u}_{0,n}=c_{1}(u_{0,n+1}+u_{0,n-1}-2u_{1,n})-2c_{2}u_{0,n}+c_{2}(u_{1,n}-u_{0,n}),\,n\geq n_{*},\\[8.53581pt] M\ddot{u}_{0,n}=c_{1}(u_{0,n+1}+u_{0,n-1}-2u_{0,n})+c_{2}(u_{1,n}-u_{0,n}),\quad n<n_{*},\end{array}\\ (1)
m1:Mu¨m,n=c1(um,n+1+um,n+12u1,n)+c2(um+1,n+um1,n2um,n),m\geq 1:\quad\quad M\ddot{u}_{m,n}=c_{1}(u_{m,n+1}+u_{m,n+1}-2u_{1,n})+c_{2}(u_{m+1,n}+u_{m-1,n}-2u_{m,n}), (2)

where um,n=um,n(t)u_{m,n}=u_{m,n}(t) is an out of plane displacement of an oscillator in mm-th horizontal layer and nn-th vertical layer of a lattice.

The fracture condition for this problem is stated as:

u0,n=uc,u_{0,n_{*}}=u_{c}, (3)
um,n<uc,n>n.u_{m,n}<u_{c},\quad n>n_{*}. (4)

2.2 Solution for steady-state crack propagation in lattice

We switch to moving coordinate system with the origin at the crack tip by the mean of change of variable:

η=nvt,v=const\eta=n-vt,\quad v=const (5)

In (5) we take into account that the crack moves steadily with a constant speed vv and we assume that the coordinate η\eta can be treated as continuous. The crack speed is assumed to be limited by the value vcv_{c}:

v<vc=c1M.v<v_{c}=\sqrt{\frac{c_{1}}{M}}. (6)

The quantity vcv_{c} is equal to Rayleigh speed in the broken part of the chain. We also assume that the solution is a function of η\eta only in such a crack propagation regime: We assume that the solution can be presented as:

um,n(t)=um(η)u_{m,n}(t)=u_{m}(\eta) (7)

Fracture conditions (3) and (4) are modified as:

u0(0)=uc,u_{0}(0)=u_{c}, (8)
um(η)<uc,η>0.u_{m}(\eta)<u_{c},\quad\eta>0. (9)

Equations of motion (1) become:

Mv2d2dη2u0(η)=c1(u0(η+1)+u0(η1)2u0(η))2c1u0(η)H(η)+c2(u1(η)u0(η)),m=0,Mv2d2dη2um(η)=c1(um(η+1)+um(η1)2um(η))+c2(um+1(η)+um1(η)2um(η)),m1.\begin{gathered}Mv^{2}\frac{d^{2}}{d\eta^{2}}u_{0}(\eta)=c_{1}(u_{0}(\eta+1)+u_{0}(\eta-1)-2u_{0}(\eta))-2c_{1}u_{0}(\eta)H(\eta)+c_{2}(u_{1}(\eta)-u_{0}(\eta)),\,m=0,\\ Mv^{2}\frac{d^{2}}{d\eta^{2}}u_{m}(\eta)=c_{1}(u_{m}(\eta+1)+u_{m}(\eta-1)-2u_{m}(\eta))+c_{2}(u_{m+1}(\eta)+u_{m-1}(\eta)-2u_{m}(\eta)),\,m\geq 1.\end{gathered} (10)

We would like to perform the Bloch-Floquet analysis of the problem and introduce the notations for the dispersion relations that appear to be useful for the present study.

2.3 Dispersion relations

It is convenient to introduce notations for the dispersion relations that appear in the problem. The first relation is:

ω12(k)=4vc2sin2(k2)+4ω02,ω02=c2M,\omega_{1}^{2}(k)=4v_{c}^{2}\sin^{2}{\left(\frac{k}{2}\right)}+4\omega_{0}^{2},\quad\omega_{0}^{2}=\frac{c_{2}}{M}, (11)

whereas the second relation is:

ω22(k)=4vc2sin2(k2)\omega_{2}^{2}(k)=4v_{c}^{2}\sin^{2}{\left(\frac{k}{2}\right)} (12)

Relations (11), (12) define the characteristics of waves in horizontal direction. The plots of dispersion relations are shown in fig. 2 for two values of crack speed v=0.2vcv=0.2v_{c} and v=0.5vcv=0.5v_{c}.

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Figure 2: Dispersion relations for different values of crack speed and c2=c1c_{2}=c_{1}: a) v=0.2vcv=0.2v_{c}, b) v=0.5vcv=0.5v_{c}.

In the fig.2 constants zjz_{j} and pjp_{j} are positive roots of the following equations:

ω1(qj)vzj=0,j=1Z,ω2(pj)vpj=0,j=1P,\begin{gathered}\omega_{1}(q_{j})-vz_{j}=0,\quad j=1...Z,\\ \omega_{2}(p_{j})-vp_{j}=0,\quad j=1...P,\end{gathered} (13)

where ZZ and PP are their total number, respectively.

2.4 Description of problem in vertical direction

The last equations in (10) is:

Mv2d2dη2um(η)=c1(um(η+1)+um(η1)2um(η))+c2(um(η+1)+um1(η)2um(η)),m1.Mv^{2}\frac{d^{2}}{d\eta^{2}}u_{m}(\eta)=c_{1}(u_{m}(\eta+1)+u_{m}(\eta-1)-2u_{m}(\eta))+c_{2}(u_{m}(\eta+1)+u_{m-1}(\eta)-2u_{m}(\eta)),\quad m\geq 1. (14)

The application of Fourier transform to this equation gives:

[(0+ikv)2+ω22(k)+2ω02]Um(k)=ω02(Um+1(k)+Um1(k)).\left[(0+ikv)^{2}+\omega_{2}^{2}(k)+2\omega_{0}^{2}\right]U_{m}(k)=\omega_{0}^{2}(U_{m+1}(k)+U_{m-1}(k)). (15)

From now on we mean:

(0±ik)=lims0+(s±ik)(0\pm ik)=\lim_{s\to 0+}(s\pm ik) (16)

Taking advantage from the fact that the coefficients in the system of linear equations do not depend on the value of nn (or what is equivalent that the material properties of the system do not change in the direction perpendicular to the crack line we assume existence of a function λ(k)\lambda(k) such that:

Um(k)=λm(k)U0(k),m1,U_{m}(k)=\lambda^{m}(k)U_{0}(k),\quad m\geq 1, (17)

where the function λ(k)\lambda(k) should satisfy the following condition

|λ(k)|1.|\lambda(k)|\leq 1. (18)

If the measure of the set of the kk where the equality is satisfied is equal to zero:

mes𝒦={k:|λ(k)|=1},\mbox{mes}\,\mathcal{K}=\{k\in\mathbb{R}:|\lambda(k)|=1\}, (19)

then the solution of the original problem um,nu_{m,n} will vanish at infinity (mm\to\infty). Otherwise the waves profile remains visible for any mm.

Substituting (17) into (15) after some algebra one obtains a quadratic equation to determine the function λ(k)\lambda(k):

λ2(k)1ω02((0+ikv)2+ω22(k)+2ω02)λ(k)+1=0,\lambda^{2}(k)-\frac{1}{\omega_{0}^{2}}\left((0+ikv)^{2}+\omega_{2}^{2}(k)+2\omega_{0}^{2}\right)\lambda(k)+1=0,

which naturally has two solutions λj(k)\lambda_{j}(k), k=1,2k=1,2:

λ1(k)=λ(k),λ1(k)=1λ(k),\lambda_{1}(k)=\lambda(k),\quad\lambda_{1}(k)=\frac{1}{\lambda(k)}, (20)

where we have introduced a new function:

λ(k)=(0+ikv)2+ω12(k)(0+ikv)2+ω22(k)(0+ikv)2+ω12(k)+(0+ikv)2+ω22(k)\lambda(k)=\frac{\sqrt{(0+ikv)^{2}+\omega_{1}^{2}(k)}-\sqrt{(0+ikv)^{2}+\omega_{2}^{2}(k)}}{\sqrt{(0+ikv)^{2}+\omega_{1}^{2}(k)}+\sqrt{(0+ikv)^{2}+\omega_{2}^{2}(k)}} (21)

Note that the square roots in the formula are chosen in such a way that for any s>0s>0 from the limit in (16) they represent the same branches and thus are continuous. Following the same reasoning as in [21] we conclude that the root |λ(k)|1,k|\lambda(k)|\leq 1,\,k\in\mathbb{R} and, consequently, only the first root λ1(k)\lambda_{1}(k) should be taken.

By straightforward substitution it is easy to check:

λ(pj)=1,j=1,2,,P,\lambda(p_{j})=1,\quad j=1,2,...,P, (22)

and

λ(zj)=1,j=1,2,,Z.\lambda(z_{j})=-1,\quad j=1,2,...,Z. (23)

Moreover, λ(0)=1\lambda(0)=1. Note that there are two countable sets 𝒦j={k:λ(k)=(1)j}\mathcal{K}_{j}=\{k\in\mathbb{R}:\lambda(k)=(-1)^{j}\} where the condition (19) satisfies. The other cases when |λ(k)|=1|\lambda(k)|=1 but λ\lambda\in\hskip-11.38109pt\diagup\,\mathbb{R} and thus

λ(k)=eiϕλ(k),ϕλ(k),\lambda(k)=e^{i\phi_{\lambda}(k)},\quad\phi_{\lambda}(k)\in\mathbb{R}, (24)

appear only when one of the square roots are pure imaginary while the other is real and

tanϕλ(k)2=i(0+ikv)2+ω12(k)(0+ikv)2+ω22(k),(ω12(k)k2v2)(ω22(k)k2v2)<0.\tan\frac{\phi_{\lambda}(k)}{2}=-i\frac{\sqrt{(0+ikv)^{2}+\omega_{1}^{2}(k)}}{\sqrt{(0+ikv)^{2}+\omega_{2}^{2}(k)}},\quad\left(\omega_{1}^{2}(k)-k^{2}v^{2}\right)\left(\omega_{2}^{2}(k)-k^{2}v^{2}\right)<0. (25)

Function ϕλ(k)\phi_{\lambda}(k) should be chosen in such a manner that argλ(k)\mbox{arg}\lambda(k) is a continuous along the entire the real axis. One can prove that the following properties of the constructed function λ(k)\lambda(k):

|λ(k)|=|λ(k)|,argλ(k)=argλ(k),for k.|\lambda(k)|=|\lambda(-k)|,\quad\text{arg}\lambda(k)=-\text{arg}\lambda(-k),\quad\text{for }k\in\mathbb{R}. (26)

We can also write the asymptotic behaviour of the function at infinity:

λ(k)2ω02v2k2,k.\lambda(k)\sim-\frac{2\omega_{0}^{2}}{v^{2}k^{2}},\quad k\to\infty. (27)

The asymptotic behaviour of λ(k)\lambda(k) at zero comes from (35):

λ(k)=1vc2v2ω020+ik0ik+o(k),k0.\lambda(k)=1-\sqrt{\frac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}}\sqrt{0+ik}\sqrt{0-ik}+o(k),\quad k\to 0. (28)

Note also that λ(k)\lambda(k) takes only real value for p1<k<p1-p_{1}<k<p_{1}.

To illustrate the behaviour of function λ(k)\lambda(k), we present in fig.3 the graphs of |λ(k)||\lambda(k)| and arg(λ(k))\mbox{arg}(\lambda(k)) for the cases v=0.2vcv=0.2v_{c} and v=0.5vcv=0.5v_{c} for positive values of kk. In this figures it can be explicitly seen that |λ(k)|<1|\lambda(k)|<1 only when (ω12(k)(kv)2)(ω12(k)(kv)2)<0(\omega_{1}^{2}(k)-(kv)^{2})(\omega_{1}^{2}(k)-(kv)^{2})<0 which is supported by the dispersion relations in fig. 2.

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b)

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Figure 3: Absolute value and argument of λ(k)\lambda(k) for different values of crack speed and c2=c1c_{2}=c_{1}: a) v=0.2vcv=0.2v_{c}, b) v=0.5vcv=0.5v_{c}.

Note that the argλ(k)\mbox{arg}\lambda(k) is an odd continuous function satisfying the properties for positiuve values of its argument (k>0k>0)

limkargλ(k)=π,and0<argλ(k)<πonly if|λ(k)|=1.\lim_{k\to\infty}\mbox{arg}\lambda(k)=\pi,\quad\mbox{and}\quad 0<\mbox{arg}\lambda(k)<\pi\quad\mbox{only if}\quad|\lambda(k)|=1.

Another conclusion immediately follows from this analysis is that the waves profile does not vanishes at infinity (mm\to\infty).

2.5 Derivation of Wiener-Hopf type equation

Let us start from the equations (10). The use of Fourier transform reduces the problem to equations:

((0+ikv)2+ω22(k)+2ω02)U+(k)+((0+ikv)2+ω22(k))U(k)=ω02(U1(k)U(k)),m=0((0+ikv)2+ω22(k)+2ω02)Um(k)=ω02(Um+1(k)Um1(k)),m1.\begin{gathered}\Big{(}(0+ikv)^{2}+\omega_{2}^{2}(k)+2\omega_{0}^{2}\Big{)}U^{+}(k)+\Big{(}(0+ikv)^{2}+\omega_{2}^{2}(k)\Big{)}U^{-}(k)=\omega_{0}^{2}\Big{(}U_{1}(k)-U(k)\Big{)},\quad m=0\\ \Big{(}(0+ikv)^{2}+\omega_{2}^{2}(k)+2\omega_{0}^{2}\Big{)}U_{m}(k)=\omega_{0}^{2}\Big{(}U_{m+1}(k)-U_{m-1}(k)\Big{)},\quad m\geq 1.\end{gathered} (29)

where the notations are:

U(k)=U0(k)=u0(η)eikη𝑑η=U+(k)+U(k),U±(k)=u0(η)H(±η)eikη𝑑ηUm(k)=um(η)eikη𝑑η,m1.\begin{gathered}U(k)=U_{0}(k)=\int_{-\infty}^{\infty}u_{0}(\eta)e^{ik\eta}\,d\eta=U^{+}(k)+U^{-}(k),\quad U^{\pm}(k)=\int_{-\infty}^{\infty}u_{0}(\eta)H(\pm\eta)e^{ik\eta}\,d\eta\\ U_{m}(k)=\int_{-\infty}^{\infty}u_{m}(\eta)e^{ik\eta}\,d\eta,\quad m\geq 1.\end{gathered} (30)

With the introduced function λ(k)\lambda(k) in (17) the equations for m1m\geq 1 are already satisfied while the equation for m=0m=0 is reduced to:

L(k)U+(k)+U(k)=0L(k)U^{+}(k)+U^{-}(k)=0 (31)

Kernel function L(k)L(k) in this case is defined as:

L(k)=(0+ikv)2+ω12(k)(0+ikv)2+ω22(k),L(k)=\sqrt{\frac{(0+ikv)^{2}+\omega_{1}^{2}(k)}{(0+ikv)^{2}+\omega_{2}^{2}(k)}}, (32)

where the functions ω1,2(k)\omega_{1,2}(k) are defined in (11),(12) and function λ(k)\lambda(k) is presented in (21). One can also notice that function L(k)L(k) has the following properties:

|L(k)|=|L(k)|,argL(k)=argL(k),for k|L(k)|=|L(-k)|,\quad\text{arg}L(k)=-\text{arg}L(-k),\quad\text{for }k\in\mathbb{R} (33)

The asymptotic behaviour is given as:

L(k)=12ω02v2k2+O(k4),k,L(k)=1-\frac{2\omega_{0}^{2}}{v^{2}k^{2}}+O(k^{-4}),\quad k\to\infty, (34)
L(k)2ω0vc2v21(0+ik)(0ik),k0,L(k)\sim\frac{2\omega_{0}}{\sqrt{v_{c}^{2}-v^{2}}}\frac{1}{\sqrt{(0+ik)(0-ik)}},\quad k\to 0, (35)

Plots of absolute value and argument of L(k)L(k) are presented in fig.4 for v=0.2vcv=0.2v_{c} and v=0.5vcv=0.5v_{c}. In these figures we observe that function argL(k)argL(k) is a stepwise. It experiences jumps of magnitude π/2\pi/2 at poles and zeros of function L(k)L(k).

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Figure 4: Absolute value and argument of L(k)L(k) for different values of crack speed and c2=c1c_{2}=c_{1}: a) v=0.2vcv=0.2v_{c}, b) v=0.5vcv=0.5v_{c}.

2.6 Solution of the Wiener-Hopf equation (31)

We can factorise the kernel function L(k)=L+(k)L(k)L(k)=L^{+}(k)L^{-}(k) with use of the Cauchy type theorem together with Sokhotski-Plemelj relation as:

L±(k)=exp(±12πiLnL(ξ)ξk𝑑ξ).L^{\pm}(k)=\exp{\left(\pm\frac{1}{2\pi i}\int\limits_{-\infty}^{\infty}\frac{\text{Ln}{L(\xi)}}{\xi-k}\,d\xi\right)}. (36)

The factors L±(k)L^{\pm}(k) are analytic in the half-planes ±Imk>0\pm\text{Im}k>0 and satisfy the following asymptotic relations:

L±(k)1±iQk,k,Q=1π0log|L(ξ)|𝑑ξ.\begin{gathered}L^{\pm}(k)-1\sim\pm i\frac{Q}{k},\quad k\to\infty,\\ Q=\frac{1}{\pi}\int\limits_{0}^{\infty}\text{log}{|L(\xi)|}\,d\xi.\end{gathered} (37)

One can also estimate asymptotic behaviour of the factors near zero point with the use of (35) and (36):

L±(k)R±1(4ω02vc2v2)1/410ik(1+(0ik)S),k0,R=exp(1π0ArgL(ξ)ξ𝑑ξ),S=1π0log|L(ξ)|ξ2𝑑ξ.\begin{gathered}L^{\pm}(k)\sim R^{\pm 1}\left(\frac{4\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\frac{1}{\sqrt{0\mp ik}}\left(1+(0\mp ik)S\right),\quad k\to 0,\\[8.53581pt] R=\exp{\left(\frac{1}{\pi}\int\limits_{0}^{\infty}\frac{\text{Arg}L(\xi)}{\xi}\,d\xi\right)},\quad S=\frac{1}{\pi}\int\limits_{0}^{\infty}\frac{\log{|L(\xi)|}}{\xi^{2}}\,d\xi.\end{gathered} (38)

Taking into an account the asymptotic relations the right part of the last equation (31) can be modified [21]:

L+(k)U+(k)+1L(k)U(k)=C0ik+C0+ik,L^{+}(k)U^{+}(k)+\frac{1}{L^{-}(k)}U^{-}(k)=\frac{C}{0-ik}+\frac{C}{0+ik}, (39)

where C=constC=const. The solution for the Wiener-Hopf problem is:

U+(k)=C0ik1L+(k),U(k)=C0+ikL(k)U^{+}(k)=\frac{C}{0-ik}\frac{1}{L^{+}(k)},\quad U^{-}(k)=\frac{C}{0+ik}L^{-}(k) (40)

The displacement u(η)u(\eta) is obtained in terms of inverse Fourier transform:

u0(η)=12πU±(k)eikη𝑑k,±η>0u_{0}(\eta)=\frac{1}{2\pi}\int_{-\infty}^{\infty}U^{\pm}(k)e^{-ik\eta}\,dk,\quad\pm\eta>0 (41)

From (37) and (38) it follows that:

U±(k)C(±ik+Qk2),k,U+(k)=CR(vc2v24ω02)1/410ik+o(1),k+0,U(k)=CR(4ω02vc2v2)1/4(1(0+ik)3/2+S0+ik)+o(1),k0.\begin{gathered}U^{\pm}(k)\sim C\left(\pm\frac{i}{k}+\frac{Q}{k^{2}}\right),\quad k\to\infty,\\ U^{+}(k)=\frac{C}{R}\left(\frac{v_{c}^{2}-v^{2}}{4\omega_{0}^{2}}\right)^{1/4}\frac{1}{\sqrt{0-ik}}+o(1),\quad k\to+0,\\ U^{-}(k)=\frac{C}{R}\left(\frac{4\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\left(\frac{1}{(0+ik)^{3/2}}+\frac{S}{\sqrt{0+ik}}\right)+o(1),\quad k\to-0.\end{gathered} (42)

First relations in (42) give the asymptotic behaviour of solution u(η)u(\eta) at zero:

u0(η)=C(1Qη)+O(η2),η0,u_{0}(\eta)=C(1-Q\eta)+O(\eta^{2}),\quad\eta\to 0, (43)

whereas from the last 2 expressions in (42) by means of contour integration we conclude:

u0(η)=CR(vc2v24ω02)1/41πη,η,u0(η)=CR(4ω02vc2v2)1/4(2ηπ+Sπη),η\begin{gathered}u_{0}(\eta)=\frac{C}{R}\left(\frac{v_{c}^{2}-v^{2}}{4\omega_{0}^{2}}\right)^{1/4}\frac{1}{\sqrt{\pi\eta}},\quad\eta\to\infty,\\ u_{0}(\eta)=\frac{C}{R}\left(\frac{4\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\left(2\sqrt{\frac{-\eta}{\pi}}+\frac{S}{\sqrt{-\pi\eta}}\right),\quad\eta\to-\infty\end{gathered} (44)

Constant CC is found from the fracture criterion (8):

C=ucC=u_{c} (45)

With the help of (17) we can find that:

um(η)=12πλm(k)U(k)eikη𝑑k=12πλm(k)[U+(k)+U(k)]eikη𝑑k,m1.u_{m}(\eta)=\frac{1}{2\pi}\int_{-\infty}^{\infty}\lambda^{m}(k)U(k)e^{-ik\eta}\,dk=\frac{1}{2\pi}\int_{-\infty}^{\infty}\lambda^{m}(k)[U^{+}(k)+U^{-}(k)]e^{-ik\eta}\,dk,\quad m\geq 1. (46)

The asymptotic behaviour of function um(η)u_{m}(\eta) when ρ=m2+η2=m1+α2\rho=\sqrt{m^{2}+\eta^{2}}=m\sqrt{1+\alpha^{2}}\to\infty, assuming that η=αm\eta=\alpha m, is derived in Appendix. For convenience the polar coordinates were introduced:

m=ρsinθ,η=ρcosθ,cotθ=α,m=\rho\sin{\theta},\quad\eta=\rho\cos{\theta},\quad\cot{\theta}=\alpha, (47)

such that ρ\rho is a radial distance from the crack tip and θ\theta is an angle between the radius vector and axis η\eta, i.e. 0θ<π0\leq\theta<\pi for the considered configuration shown in fig.1. The result for is summarised in formula (A.8) which is given as:

um(η)2ucR(4ω02vc2v2)1/4ρ2πΦ(θ,v),ρ,u_{m}(\eta)\sim\frac{2u_{c}}{R}\left(\frac{4\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\!\!\sqrt{\frac{\rho}{2\pi}}\,\,\,\Phi(\theta,v),\quad\rho\to\infty, (48)
Φ(θ,v)=(cos2θ+vc2v2ω02sin2θcosθ)1/2,0θ<π,\Phi(\theta,v)=\left(\sqrt{\cos^{2}\theta+\frac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}\sin^{2}\theta}-\cos\theta\right)^{1/2},\quad 0\leq\theta<\pi, (49)

3 Solution analysis

In the works of Slepyan [20, 21] the energetic relations were derived. It was shown that the ratio between the local energy release rate and global energy release rate is:

G0G=R2,G0=2c1uc2a\frac{G_{0}}{G}=R^{2},\quad G_{0}=\frac{2c_{1}u_{c}^{2}}{a} (50)

where parameter RR is defined in (38). The quantity G0aG_{0}a is equal to the energy released due to the breakage of one link between the oscillators whereas GG demonstrate the bulk change of energy. Apart from these quantities we also introduce the energy that would have been released if the horizontal links would break at potential breakage position η=η\eta=\eta_{*}:

G1=12ac2(u0(η+1)u(η))2.G_{1}=\frac{1}{2a}c_{2}(u_{0}(\eta_{*}+1)-u(\eta_{*}))^{2}. (51)

In the present paper we would like to analyse the effect of introduced anisotropy of elastic and strength properties. We define the parameter that characterise contrast in elastic properties:

μ=c2c1.\mu=\frac{c_{2}}{c_{1}}. (52)

For the demonstration of the results we choose M=1,c1=1M=1,c_{1}=1 and values of μ=0.1,0.5,1,2\mu=0.1,0.5,1,2. The computations of the displacement fields require the prescribed values of vv. The examples of displacement field u0(η)u_{0}(\eta) for different values of μ\mu are shown in fig. 5.

Refer to caption

a)

Refer to caption

b)

\captiondelim

.

Figure 5: Displacement field u0(η)u_{0}(\eta) for different values of crack speed and μ\mu: a) v=0.2vcv=0.2v_{c}, b) v=0.5vcv=0.5v_{c}.

After evaluation of displacement fields we can validate the second part of fracture criterion in (9). In the presented fig.5a) we observe the fault of this criterion in the cases μ=0.5,1,2\mu=0.5,1,2 which makes these solutions unphysical for v=0.2vcv=0.2v_{c}. At the same time the criterion (9) is hold for every chosen value of μ\mu at v=0.5v=0.5 in fig. 5b). With these observations we define the following classes of the solutions:

  • We call a regime of crack propagation at a certain speed admissible if conditions (8) and (9) are satisfied for the solution .

  • Otherwise, we call such regime forbidden.

Besides that we would also check the integrity of horizontal springs of stiffness c1c_{1} within the admissible regimes. We perform such analysis by means of two different conditions. In the first condition:

Refer to caption

a)

Refer to caption

b)

\captiondelim

.

Figure 6: Dependence of energy release rate ratio G0/GG_{0}/G on crack speed. Admissible regimes – normal lines, forbidden regimes – thick lines, dash-lines – domains where the breakage of horizontal springs happen according to : a) condition (C1), b) condition (C2).
G0G1=1\frac{G_{0}}{G_{1}}=1 (C1)

we suppose the the strength in both directions is the same. For the second condition:

G0G1=μ\frac{G_{0}}{G_{1}}=\mu (C2)

we assume that the ratio released energy while fracture is proportional to the spring constant which is followed from the estimates of the theoretical strength. Posing either of these conditions allows to cut off the high values of the energy release rate as well as the high values of crack speed.

We perform the proceeding investigation of the obtained solution by means of definitions of admissible and forbidden regimes as well as the conditions (C1) and (C1). Similar analysis was carried out for a triangular cell lattice [2, 13, 8], for a chain with anisotropic properties [5] and non-local interactions [4]. The complete analysis is shown in fig.6 where the dependence of ratio G0/GG_{0}/G on crack speed is presented according to (50). In this figure admissible regimes are marked with thick lines, forbidden regimes – normal lines. Finally, the dash-line define the domains where condition (C1) (fig.6a)) or condition (C2) (fig.6b)) is failed.

As said in [21], ratio G0/GG_{0}/G demonstrate the fact that during the crack propagation not only the fracture energy (associated to term GG) is released but also the elastic energy contained by the mechanical waves radiated by the crack tip. This fact is also observed in the dynamic fracture tests of materials [17]. That is to say, the lesser ratio G0/GG_{0}/G is the more energy is carried by the fracture waves. Notice in fig. 6 that with increase of parameter μ\mu, characterising the lattice anisotropy, for a chosen value vv, ratio G0/GG_{0}/G decreases. This is reflected in the behaviour of u0(η)u_{0}(\eta) in fig. 5 by the increase of amplitude of the waves with increase of μ\mu.

1.

Refer to caption\captiondelim

.

Figure 7: Displacements um(η),m=0..40u_{m}(\eta),m=0..40 for μ=1,v=0.5vc\mu=1,v=0.5v_{c}.

Non-monotonicity of G0/GG_{0}/G leads to uncertainty in definition of an external load that causes fracture. Indeed, choosing a certain value of G0/GG_{0}/G there can happen multiple intersections with the curves in fig. 6 which induce non-unique value of vv. This ambiguousness may be avoided if the definite type of load is considered and its characteristic magnitude is plotted against a crack speed. Such dependences are shown for the cases of constant edge displacements [2, 13, 7], constant strain or force at one ends of a chain [19] or a moving load [5].

The solution analysis reveal a qualitative effect of introduced material anisotropy. Particularly, with a significant contrast in the properties some separate intervals of admissible and forbidden regimes appear within a condition (C1). This is vividly noticed for μ=0.1\mu=0.1 in fig. 6a). This gives an opportunity of a crack propagation at low speeds which is not a case for isotropic lattice. In terms of (C1) the increase of parameter μ\mu leads to the shrinkage of admissible domains and the possibility of failure of horizontal springs grows. This circumstance is related to the increase of released elastic energy with an increase of μ\mu. It finally bring a complete suppression of admissible regimes for μ=2\mu=2.

The consideration of condition (C2) effects only on the predictions of fracture of horizontal springs. In such a way for case μ=0.1\mu=0.1 the admissible domain is fully annihilated while such domain appears for μ=2\mu=2 (compare fig.6a) and fig.6b)). If condition (C1) takes place the domain of admissible regimes decreasing with an increase of μ\mu. This correlation is inverse if the condition (C1) is valid.

We also present a plot of displacements um(η),m=0..40u_{m}(\eta),m=0..40 for the case of isotropic lattice, μ=1\mu=1, and v=0.5vcv=0.5v_{c} in fig.7. Moreover, we display the figures for the behaviour of um(αm)u_{m}(\alpha m) when mm\to\infty in fig.8a) and the angle function in fig.8b) according to (48) and (49), respectively. From these figures we conclude that the amplitude of the waves in each layer mm is different (see, fig. 7) and there is a tendency in slow growth of displacements in vertical direction which can be clearly seen 8a). This growth is greater in the region occupied by the crack (η<0\eta<0) than ahead of it, which follows from the behaviour of angle function Φ(θ,v)\Phi(\theta,v) in 8b).

Additionally, we notice that the most dangerous elongations are found to be between layers m=0m=0 and m=1m=1 in the neighbourhood of a crack tip besides those layers adjacent to the symmetry line of a lattice. Nevertheless, these elongations do not exceed the threshold and remain to be less meaningful, in terms of fracture, than the elongations in horizontal direction. Additionally, we pay an attention to the fact that the displacement field in 7, essentially, is a sum of two components: the waves radiated from a crack tip which amplitude is decaying with the distance from a crack tip and monotonic deformation which increases closer to infinity.

Refer to caption

a)

Refer to caption

b)

\captiondelim

.

Figure 8: Examples in case of v=0.5vcv=0.5v_{c} and an isotropic lattice vc=ω0v_{c}=\omega_{0}: a) behaviour um(αm)u_{m}(\alpha m) according to (48), where α=cot(θ)\alpha=\cot(\theta), b) angle function Φ(θ,v)\Phi(\theta,v) in (49).

4 Conclusions

In the present work we considered the problem of straight crack propagation in an anisotropic square-cell lattice. One of the major result was the conclusion about the fact that the considerations of energetic characteristics of the problem are not enough for the reasonable predictions of stable crack propagation. The investigation of a solution is necessary.

The evaluation of displacement fields and their analysis allowed to distinguish two different regimes of crack propagation for a certain crack velocity – admissible and forbidden regimes. Here it is worth of mentioning that constructed analytical solution is indeed reached which was demonstrated in [5] for the one-dimensional chain of oscillators.

We also showed that the used approach can be effectively utilised for an analysis of integrity of horizontal springs in the lattice. For such study two different conditions were considered that were influenced by the contrast in elastic and strength properties in vertical and horizontal directions of a lattice. Particularly, we showed that for some values of material properties a steady-state crack propagation is not observed at all.

The introduced anisotropy allowed to discover a stable steady-state crack propagation at low velocities. This phenomenon is shown to be observed for high contrast in material properties. Moreover, the analysis allows to make predictions of crack velocities compatible with the stable crack movement.

Lastly, we revealed that any set of material parameters the failure of horizontal springs occurs at high values of crack speed. In such cases steady-state crack propagation can not be observed even within the admissible regimes.

Acknowledgements NG and GM acknowledge support from the EU projects CERMAT-2 (PITN-GA-2013-606878) and TAMER (IRSES-GA-2013-610547), respectively. GM also acknowledges Royal Society of London for a partial support via Wolfson Research Merit Award.

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Appendix A Appendix

The obtaining of the asymptotic relations for lattice behaviour with the growth of mm takes into an account the behaviour of functions U0(k)U_{0}^{-}(k) and λ(k)\lambda(k) at zero. Indeed, when mm\to\infty the integration in the expressions for um(η)u_{m}(\eta) is performed only within the intervals where |λ(k)|=1|\lambda(k)|=1. However, the leading term of asymptotic behaviour of um(η)u_{m}(\eta) when mm\to\infty is provided by the singularity encompassed in U0(k)U_{0}^{-}(k) when k0k\to 0. To show this, let us subtract the leading terms of U0(k)U_{0}^{-}(k) and λ(k)\lambda(k) when kk\to\infty from the expressions for um(η)u_{m}(\eta) and perform the analytical integration.

Firstly, we consider case η>0\eta>0 and the integral to estimate is:

(1A0+ik0ik)ma(0+ik)3/2eikη𝑑η,\int_{-\infty}^{\infty}(1-A\sqrt{0+ik}\sqrt{0-ik})^{m}\frac{a}{(0+ik)^{3/2}}e^{-ik\eta}\,d\eta, (A.1)

where

U(k)=a(0+ik)3/2,λ(k)=1A0+ik0ik,k0.U^{-}(k)=\frac{a}{(0+ik)^{3/2}},\quad\lambda(k)=1-A\sqrt{0+ik}\sqrt{0-ik},\quad k\to 0.

Constants a,A>0a,A>0 are defined for the sake of reducing long expressions and will be substituted for the final expressions (see (28) and (42)). Integral (A.1) can be computed using the technique of contour integration in the plane kk\in\mathbb{C}. Notice, that according to the assumption η>0\eta>0 the contour should be taken in half-plane k<0\Im k<0. Moreover, in this plane function 0ik\sqrt{0-ik} posses a branch cut along the imaginary axis. Thus, we construct contour C=[ρ,ρ]Γ1[iρ,0][0,iρ]Γ2C=[-\rho,\rho]\cup\Gamma_{1}\cup[-i\rho,0]\cup[0,-i\rho]\cup\Gamma_{2} which consists of an interval along the real line, the arch of radius ρ\rho and k>0,k<0\Re k>0,\Im k<0, two intervals along the branch cut of 0+ik\sqrt{0+ik} and the final arch of radius ρ\rho and k<0,k<0\Re k<0,\Im k<0.

Notice that 0ik\sqrt{0-ik} takes the following values along its cut:

0ik={iz,k0+,iz,k0,\sqrt{0-ik}=\begin{cases}-i\sqrt{z},\quad\Re k\to 0+,\\[5.69054pt] i\sqrt{z},\quad\Re k\to 0-,\end{cases}

where k=iz,z>0k=-iz,z>0. At the same time 0+ik=z\sqrt{0+ik}=\sqrt{z}. The Cauchy residue theorem allows to conclude that integration along contour CC the integrand in (A.1) gives zero value. The integration along arches Γ1\Gamma_{1} and Γ2\Gamma_{2} also results in zero when ρ\rho\to\infty. Thus, we get:

(1A0+ik0ik)ma(0+ik)3/2eikη=1i0(1+iAz)mazzezη𝑑z1i0(1iAz)mazzezη𝑑z=0(1+iAz)m(1iAz)mizzaezη𝑑z=01/m(1+iAz)m(1iAz)mizzaezη𝑑z+1/m(1+iAz)m(1iAz)mizzaezη𝑑z\begin{gathered}\int_{-\infty}^{\infty}(1-A\sqrt{0+ik}\sqrt{0-ik})^{m}\frac{a}{(0+ik)^{3/2}}e^{-ik\eta}\\ =-\frac{1}{i}\int_{\infty}^{0}(1+iAz)^{m}\frac{a}{z\sqrt{z}}e^{-z\eta}\,dz-\frac{1}{i}\int_{0}^{\infty}(1-iAz)^{m}\frac{a}{z\sqrt{z}}e^{-z\eta}\,dz\\ =\int_{0}^{\infty}\frac{(1+iAz)^{m}-(1-iAz)^{m}}{iz\sqrt{z}}ae^{-z\eta}\,dz\\ =\int_{0}^{1/m}\frac{(1+iAz)^{m}-(1-iAz)^{m}}{iz\sqrt{z}}ae^{-z\eta}\,dz+\int_{1/m}^{\infty}\frac{(1+iAz)^{m}-(1-iAz)^{m}}{iz\sqrt{z}}ae^{-z\eta}\,dz\end{gathered}

Next, we are interested in the solutions along the ray:

η=αm\eta=\alpha m

Then, in the last equation of derivation we apply the change of variable, say t=mzt=mz. We then notice:

(1+iAtm)meiAt,(1iAtm)meiAt,m\left(1+iA\frac{t}{m}\right)^{m}\to e^{iAt},\quad\left(1-iA\frac{t}{m}\right)^{m}\to e^{-iAt},\quad m\to\infty

With this in mind we continue derivation:

01/m(1+iAz)m(1iAz)mizzaezη𝑑z+1/m(1+iAz)m(1iAz)mizzaezη𝑑z=am0(1+iAtm)m(1iAtm)mtteαt𝑑t=2am0sinAttteαt𝑑t=2amA0sinxxxe(α/A)x𝑑x=2aAm2πα+α2+A2\begin{gathered}\int_{0}^{1/m}\frac{(1+iAz)^{m}-(1-iAz)^{m}}{iz\sqrt{z}}ae^{-z\eta}\,dz+\int_{1/m}^{\infty}\frac{(1+iAz)^{m}-(1-iAz)^{m}}{iz\sqrt{z}}ae^{-z\eta}\,dz\\ =a\sqrt{m}\int_{0}^{\infty}\frac{\left(1+iA\frac{t}{m}\right)^{m}-\left(1-iA\frac{t}{m}\right)^{m}}{t\sqrt{t}}e^{-\alpha t}\,dt\\ =2a\sqrt{m}\int_{0}^{\infty}\frac{\sin{At}}{t\sqrt{t}}e^{-\alpha t}\,dt=2a\sqrt{m}\sqrt{A}\int_{0}^{\infty}\frac{\sin{x}}{x\sqrt{x}}e^{-(\alpha/A)x}dx\\ =2aA\sqrt{m}\frac{\sqrt{2\pi}}{\sqrt{\alpha+\sqrt{\alpha^{2}+A^{2}}}}\end{gathered}

Finally, in case η>0\eta>0, we achieve:

um(αm)2πvc2v2ω02(4ω02vc2v2)1/4ucRmα+α2+vc2v2ω02,α>0,m,u_{m}(\alpha m)\sim\sqrt{\frac{2}{\pi}}\sqrt{\frac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}}\left(\frac{4\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\frac{u_{c}}{R}\frac{\sqrt{m}}{\sqrt{\alpha+\sqrt{\alpha^{2}+\frac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}}}},\quad\alpha>0,\quad m\to\infty, (A.2)

where used notations introduced in the main part of the article. Let us now turn to the situation when η<0\eta<0. The integral in (A.1) can be written as:

(1A0+ik0ik)ma(0+ik)3/2eikη𝑑η=[(1A0+ik0ik)m1]a(0+ik)3/2eikη𝑑η+a(0+ik)3/2eikη𝑑η\begin{gathered}\int_{-\infty}^{\infty}(1-A\sqrt{0+ik}\sqrt{0-ik})^{m}\frac{a}{(0+ik)^{3/2}}e^{-ik\eta}\,d\eta\\ =\int_{-\infty}^{\infty}\left[(1-A\sqrt{0+ik}\sqrt{0-ik})^{m}-1\right]\frac{a}{(0+ik)^{3/2}}e^{-ik\eta}\,d\eta+\int_{-\infty}^{\infty}\frac{a}{(0+ik)^{3/2}}e^{-ik\eta}\,d\eta\end{gathered} (A.3)

The evaluation of the second integral gives a straightforward result by means of contour integration:

a(0+ik)3/2eikη𝑑η=4aπη,η<0\int_{-\infty}^{\infty}\frac{a}{(0+ik)^{3/2}}e^{-ik\eta}\,d\eta=4a\sqrt{-\pi\eta},\quad\eta<0 (A.4)

Notice, that in this case we need consider contour in half-plane k>0\Im k>0 where 0+ik\sqrt{0+ik} possesses a cut:

0+ik={iz,k0+,iz,k0,\sqrt{0+ik}=\begin{cases}i\sqrt{z},\Re k\to 0+,\\ -i\sqrt{z},\Re k\to 0-,\end{cases}

where k=iz,z>0k=iz,\quad z>0, whereas 0ik=z\sqrt{0-ik}=\sqrt{z}. The reasoning concerning the construction of contour integration is similar to the previous case. The application of the Cauchy residue theorem and Jordan’s lemma leads to:

[(1A0+ik0ik)m1]a(0+ik)3/2eikη=0[(1+iAz)m1]azzezη𝑑z0[(1iAz)m1]azzezη𝑑z=02(1+iAz)m(1iAz)mzzaezη𝑑z=01/m2(1+iAz)m(1iAz)mizzaezη𝑑z+1/m2(1+iAz)m(1iAz)mizzaezη𝑑z\begin{gathered}\int_{-\infty}^{\infty}\left[(1-A\sqrt{0+ik}\sqrt{0-ik})^{m}-1\right]\frac{a}{(0+ik)^{3/2}}e^{-ik\eta}\\ =\int_{\infty}^{0}\left[(1+iAz)^{m}-1\right]\frac{a}{z\sqrt{z}}e^{z\eta}\,dz-\int_{0}^{\infty}\left[(1-iAz)^{m}-1\right]\frac{a}{z\sqrt{z}}e^{z\eta}\,dz\\ =\int_{0}^{\infty}\frac{2-(1+iAz)^{m}-(1-iAz)^{m}}{z\sqrt{z}}ae^{z\eta}\,dz\\ =\int_{0}^{1/m}\frac{2-(1+iAz)^{m}-(1-iAz)^{m}}{iz\sqrt{z}}ae^{z\eta}\,dz+\int_{1/m}^{\infty}\frac{2-(1+iAz)^{m}-(1-iAz)^{m}}{iz\sqrt{z}}ae^{z\eta}\,dz\end{gathered}

Again, we make a change of variable t=mzt=mz and assume that:

η=αm.\eta=-\alpha m.

Taking the limit mm\to\infty we arrive to the expression:

01/m2(1+iAz)m(1iAz)mizzaezη𝑑z+1/m2(1+iAz)m(1iAz)mizzaezη𝑑z=am01cosAttteαt𝑑t=2amA01cosxxxe(α/A)x𝑑x=4aπm(α+(α2+A2)1/4cos(arccotαA2)),\begin{gathered}\int_{0}^{1/m}\frac{2-(1+iAz)^{m}-(1-iAz)^{m}}{iz\sqrt{z}}ae^{z\eta}\,dz+\int_{1/m}^{\infty}\frac{2-(1+iAz)^{m}-(1-iAz)^{m}}{iz\sqrt{z}}ae^{z\eta}\,dz\\ =a\sqrt{m}\int_{0}^{\infty}\frac{1-\cos{At}}{t\sqrt{t}}e^{-\alpha t}\,dt=2a\sqrt{m}\sqrt{A}\int_{0}^{\infty}\frac{1-\cos{x}}{x\sqrt{x}}e^{-(\alpha/A)x}\,dx\\ =4a\sqrt{\pi m}\left(-\sqrt{\alpha}+(\alpha^{2}+A^{2})^{1/4}\cos{\left(\frac{\operatorname{arccot}{\frac{\alpha}{A}}}{2}\right)}\right),\end{gathered} (A.5)

where arccotx\operatorname{arccot}{x} is the inverse cotangent function. Sum of the last result with (A.4) provides the final for of asymptotic behaviour:

um(αη)2ucπ1R(4ω02vc2v2)1/4(α2+vc2v2ω02)1/4cos(arccot(αω02vc2v2)2)m,m,α>0u_{m}(-\alpha\eta)\sim\frac{2u_{c}}{\sqrt{\pi}}\frac{1}{R}\left(\frac{4\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\left(\alpha^{2}+\frac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}\right)^{1/4}\cos{\left(\frac{\operatorname{arccot}{\left(-\alpha\sqrt{\frac{\omega_{0}^{2}}{v_{c}^{2}-v^{2}}}\right)}}{2}\right)}\sqrt{m},\quad m\to\infty,\alpha>0

One can simplify the trigonometric term in the last expression using the following expressions:

arccot(1x)=arctan(x),arctan(x)=2arctan(x1+x2+1),cos(arctan(x))=11+x2\operatorname{arccot}{\left(\frac{1}{x}\right)}=\arctan{(x)},\quad\arctan{(x)}=2\arctan\left(\frac{x}{1+\sqrt{x^{2}+1}}\right),\quad\cos{(\arctan(x))}=\frac{1}{\sqrt{1+x^{2}}}

to obtain:

um(αη)2πvc2v2ω02(4ω02vc2v2)1/4ucRmα+α2+vc2v2ω02,α>0,mu_{m}(-\alpha\eta)\sim\sqrt{\frac{2}{\pi}}\sqrt{\frac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}}\left(\frac{4\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\frac{u_{c}}{R}\frac{\sqrt{m}}{\sqrt{-\alpha+\sqrt{\alpha^{2}+\frac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}}}},\quad\alpha>0,\quad m\to\infty

Notice, that the last expression is of the same form as in the previously considered case η<0\eta<0. Thus, we can present final formula of asymptotic expression in a general form:

um(αm)2ucR(4ω02vc2v2)1/4m2π(vc2v2ω021α+α2+vc2v2ω02)1/2,mu_{m}(\alpha m)\sim\frac{2u_{c}}{R}\left(\frac{4\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\sqrt{\frac{m}{2\pi}}\left(\dfrac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}\frac{1}{\alpha+\sqrt{\alpha^{2}+\frac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}}}\right)^{1/2},\quad m\to\infty (A.6)

One can observe that introducing the radius vector ρ=m2+η2=m1+α2\rho=\sqrt{m^{2}+\eta^{2}}=m\sqrt{1+\alpha^{2}} and the angle θ\theta, such that cotθ=α\cot\theta=\alpha (and, thus, m=ρsinθm=\rho\sin\theta, η=ρcosθ\eta=\rho\cos\theta), the representation (48) can be conveniently rewritten in the following manner:

um(η)2ucR(4ω02vc2v2)1/4ρ2πΦ(θ,v),ρ,u_{m}(\eta)\sim\frac{2u_{c}}{R}\left(\frac{4\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\!\!\sqrt{\frac{\rho}{2\pi}}\,\,\,\Phi(\theta,v),\quad\rho\to\infty, (A.7)
Φ(θ,v)=(cos2θ+vc2v2ω02sin2θcosθ)1/2,0θ<π,\Phi(\theta,v)=\left(\sqrt{\cos^{2}\theta+\frac{v_{c}^{2}-v^{2}}{\omega_{0}^{2}}\sin^{2}\theta}-\cos\theta\right)^{1/2},\quad 0\leq\theta<\pi, (A.8)

In the case of a static problem (v=0v=0) and an isotropic lattice (vc=ω0v_{c}=\omega_{0}) we have:

Φ(θ,0)=sinθ2,0θ<π,\Phi(\theta,0)=\sin\frac{\theta}{2},\quad 0\leq\theta<\pi,

that correspond to the asymptotic solution near the crack tip in homogeneous material under the Mode III deformation.

Using the relationships (50), asymptotics (A.7) can be rewritten in an equivalent form:

um(η)2aGc1(ω02vc2v2)1/4ρ2πΦ(θ,v),ρ.u_{m}(\eta)\sim 2\sqrt{\frac{aG}{c_{1}}}\left(\frac{\omega_{0}^{2}}{v_{c}^{2}-v^{2}}\right)^{1/4}\!\!\sqrt{\frac{\rho}{2\pi}}\,\,\,\Phi(\theta,v),\quad\rho\to\infty. (A.9)

It is worth of mentioning that continuum formulation similar problem with moving crack v>0v>0 under mode III in the case of homogeneous material leads to the following asymptotic behaviour of the displacement field at the crack tip (see e.g. [1, p.356-360]):

u(r,θ)2𝒢μ(1v2vc2)1/4r2π(1v2vc2sin2θcosθ),r0,u(r,\theta)\sim 2\sqrt{\frac{\mathcal{G}}{\mu}}\left(1-\frac{v^{2}}{v_{c}^{2}}\right)^{-1/4}\sqrt{\frac{r}{2\pi}}\left(\sqrt{1-\frac{v^{2}}{v_{c}^{2}}\sin^{2}{\theta}}-\cos{\theta}\right),\quad r\to 0,

where μ\mu – shear modulus, 𝒢\mathcal{G} – macroscopic energy release rate and vcv_{c} is a shear wave speed in this case. Thus, we the considered microscopic solution reflects the behaviour of the macroscopic case.