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On the Laplacian spectrum of kk-symmetric graphs

Sunyo Moon Research Institute for Natural Sciences, Hanyang University, Seoul 04763, Korea symoon89@hanyang.ac.kr  and  Hyungkee Yoo Institute of Mathematical Sciences, Ewha Womans University, Seoul 03760, Korea hyungkee@ewha.ac.kr
Abstract.

For some positive integer kk, if the finite cyclic group k\mathbb{Z}_{k} can act freely on a graph GG, then we say that GG is kk-symmetric. In 1985, Faria showed that the multiplicity of Laplacian eigenvalue 1 is greater than or equal to the difference between the number of pendant vertices and the number of quasi-pendant vertices. But if a graph has a pendant vertex, then it is at most 1-connected. In this paper, we investigate a class of 2-connected kk-symmetric graphs with a Laplacian eigenvalue 1. We also identify a class of kk-symmetric graphs in which all Laplacian eigenvalues are integers.

Key words and phrases:
Laplacian eigenvalue, kk-symmetric graph, kk-symmetric join
2020 Mathematics Subject Classification:
15A18, 05C50
The second author(Hyungkee Yoo) was supported by the National Research Foundation of Korea(NRF) grant funded by the Korea government Ministry of Education(NRF-2019R1A6A1A11051177) and Ministry of Science and ICT(NRF-2022R1A2C1003203).

1. Introduction

A simple graph G=(V,E)G=(V,E) is a combinatorial object consisting of a finite set VV and a set EE of unordered pairs of different elements of VV. The elements of VV and EE are called the vertices and the edges of the graph GG, respectively. For a given graph GG, the vertex set and the edge set of GG are denoted by V(G)V(G) and E(G)E(G), respectively.

Let GG be a graph with enumerated vertices. The Laplacian matrix L(G)L(G) of GG is defined as L(G)=D(G)A(G)L(G)=D(G)-A(G), where D(G)D(G) is the diagonal matrix of vertex degrees and A(G)A(G) is the adjacency matrix of GG. Thus the Laplacian matrix is symmetric. Note that the Laplacian matrix can be considered a positive-semidefinite quadratic form on the Hilbert space generated by V(G)V(G). Since the Laplacian matrix contains information on the structure of the graph, it has been studied importantly in various applied fields including artificial neural network research using graph shaped data [13, 14].

Let GG be a graph with nn vertices. For a square matrix MM, we denote the characteristic polynomial of MM by μ(M,x)\mu(M,x). A root of the characteristic polynomial of Laplacian matrix L(G)L(G) is called a Laplacian eigenvalue of GG. Denote the all eigenvalues of L(G)L(G) by λn(G)λn1(G)λ1(G)\lambda_{n}(G)\leq\lambda_{n-1}(G)\leq\cdots\leq\lambda_{1}(G). It is well-known that λn(G)=0\lambda_{n}(G)=0 and λ1(G)n\lambda_{1}(G)\leq n. The multiset of Laplacian eigenvalues of GG is called the Laplacian spectrum of GG. The Laplacian spectrum of the complement graph G¯\overline{G} of GG is satisfying

0=λn(G¯)nλ1(G)nλn1(G).0=\lambda_{n}(\overline{G})\leq n-\lambda_{1}(G)\leq\cdots\leq n-\lambda_{n-1}(G).

The Laplacian spectrum shows us several properties of the graph. For instance, Kirchhoff [15] proved that the number of spanning tree of a connected graph GG with nn vertices is 1nλ1(G)λn1(G)\frac{1}{n}\lambda_{1}(G)\cdots\lambda_{n-1}(G). Let mG(λ)m_{G}(\lambda) denote the multiplicity of λ\lambda as a Laplacian eigenvalue of GG. Note that the multiplcity of 0 is equal to the number of connected components of GG.

The connectivity κ(G)\kappa(G) of a graph GG is the minimum number of vertices whose removal results in a disconnected or trivial graph. A graph GG is said to be tt-connected if κ(G)t\kappa(G)\geq t. If a graph is tt-connected, then it is (t1)(t\!-\!1)-connected. Fiedler [9] proved that the second smallest Laplacian eigenvalue of GG is less than or equal to κ(G)\kappa(G).

A pendant vertex of GG is a vertex of degree 11. A quasi-pendant of GG is a vertex adjacent to a pendant. We denote the number of pendants of GG by p(G)p(G), and the number of quasi-pendant vertices by q(G)q(G). In [8], Faria showed that for any graph GG,

mG(1)p(G)q(G).m_{G}(1)\geq p(G)-q(G).

It implies that if p(G)p(G) is greater than q(G)q(G), then GG has a Laplacian eigenvalue 1. Also, such graph GG is at most 1-connected. In [1], Barik et al. found trees with a Laplacian eigenvalue 1 even though the right-hand side of the above inequality is 0. Since a tree has connectivity 1, we focus on 2-connected graph with a Laplacian eigenvalue 1.

The simplest way to obtain a 2-connected graph with a Laplacian eigenvalue 1 is the Cartesian product. The Cartesian product GHG\square H of graphs GG and HH is the graph with the vertex set V(G)×V(H)V(G)\times V(H) such that two vertices (v,v)(v,v^{\prime}) and (w,w)(w,w^{\prime}) are adjacent if v=wv=w and vv^{\prime} is adjacent to ww^{\prime} in HH, or if v=wv^{\prime}=w^{\prime} and vv is adjacent to ww in GG. Fiedler [9] showed that the Laplacian eigenvalues of the Cartesian product GHG\square H are all possible sums of Laplacian eigenvalues of GG and HH. If either GG or HH has a Laplacian eigenvalue 1, then 1 is a Laplacian eigenvalue of GHG\square H. Špacapan [20] showed that the connectivity of GHG\square H is

κ(GH)=min{κ(G)|H|,κ(H)|G|,δ(GH)},\kappa(G\square H)=\min\{\kappa(G)|H|,\kappa(H)|G|,\delta(G\square H)\},

where δ(GH)\delta(G\square H) is the minimum degree of GHG\square H. Remark that if GG and HH are connected graphs, then GHG\square H is 2-connected. Thus we concentrate a 2-connected graph that does not decompose nontrivial graphs under the Cartesian product. If a graph does not admit the nontrivial Cartesian product decomposition, then the graph is called prime with respect to the Cartesian product. In this paper, we prove the following theorem.

Theorem 1.1.

For any positive integer nn, there is a 2-connected prime graph GG with respect to the Cartesian product,

mG(1)n.m_{G}(1)\geq n.

Meanwhile, integral spectra of Laplacian matrix or adjacency matrix are studied in various application fields including physics and chemistry [3, 4, 5]. A graph with integral Laplacian spectrum is called a Laplacian integral graph. If a graph does not include the path P4P_{4} as an induced subgraph, then it is called a cograph. In [19], Merris showed that a cograph is a Laplacian integral graph. Many researchers [7, 10, 16, 17] have investigated infinitely many classes of Laplacian integral graphs that are not cographs. In section 5, we introduce a new graph 𝒞(n,m)\mathcal{C}(n,m) for some positive integers nn and mm. The graph 𝒞(n,m)\mathcal{C}(n,m) is obtained by connecting several set of vertices for mm parallel copies of nn-complete graph KnK_{n} to the corresponding vertex of K¯n\overline{K}_{n}. Later, we examine that if n2n\geq 2, then 𝒞(n,m)\mathcal{C}(n,m) has the path P4P_{4} as the induced subgraph, that is, it is not a cograph. In this paper, we also prove the following theorem.

Theorem 1.2.

There are infinitely many pairs of positive integers nn and mm, which make 𝒞(n,m)\mathcal{C}(n,m) a Laplacian integral graph.

This paper is organized as follows. In Section 2, We provide some linear algebra results needed for proof of main theorems. In Section 3, We define the kk-symmetric graph by relaxing the condition of symmetric graph, and examine its properties. In Section 4 and Section 5, we prove the main theorems and related properties.

2. Preliminaries

In this section, we introduce some definitions and properties that will be used in this paper. The set of all m×nm\times n matrices over a field 𝔽\mathbb{F} is denoted by Mm×n(𝔽)M_{m\times n}(\mathbb{F}). Denote Mn×n(𝔽)M_{n\times n}(\mathbb{F}) by Mn(𝔽)M_{n}(\mathbb{F}). We denote by InI_{n} and JnJ_{n} the n×nn\times n identity matrix and the n×nn\times n matrix whose entries are ones. Also, 1n1_{n} is the nn-vector of all ones.

Let AMn(𝔽)A\in M_{n}(\mathbb{F}) be a block matrix of the form

A=(A11A12A21A22),A=\begin{pmatrix}A_{11}&A_{12}\\ A_{21}&A_{22}\end{pmatrix},

where A11Mm(𝔽)A_{11}\in M_{m}(\mathbb{F}), A12Mm×(nm)(𝔽)A_{12}\in M_{m\times(n-m)}(\mathbb{F}), A21M(nm)×m(𝔽)A_{21}\in M_{(n-m)\times m}(\mathbb{F}) and A22Mnm(𝔽)A_{22}\in M_{n-m}(\mathbb{F}). It is well known that if A22A_{22} is invertible, then detA=detA22det(A11A12A221A21)\det{A}=\det{A_{22}}\det(A_{11}-A_{12}A_{22}^{-1}A_{21}) (see [12, Chapter 0]).

For two matrices A=(aij)Mm×n(𝔽)A=(a_{ij})\in M_{m\times n}(\mathbb{F}) and BMp×q(𝔽)B\in M_{p\times q}(\mathbb{F}), the Kronecker product of AA and BB, denoted by ABA\otimes B, is defined as

AB=(a11Ba12Ba1nBa21Ba22Ba2nBam1Bam2BamnB).A\otimes B=\begin{pmatrix}a_{11}B&a_{12}B&\cdots&a_{1n}B\\ a_{21}B&a_{22}B&\cdots&a_{2n}B\\ \vdots&\vdots&\ddots&\vdots\\ a_{m1}B&a_{m2}B&\cdots&a_{mn}B\\ \end{pmatrix}.

We state some basic properties of the Kronecker product (for more details, see [11, Chapter 4]):

  • (a)

    A(B+C)=AB+ACA\otimes(B+C)=A\otimes B+A\otimes C.

  • (b)

    (B+C)A=BA+CA(B+C)\otimes A=B\otimes A+C\otimes A.

  • (c)

    (AB)(CD)=ACBD(A\otimes B)(C\otimes D)=AC\otimes BD.

  • (d)

    If AMm(𝔽)A\in M_{m}(\mathbb{F}) and BMn(𝔽)B\in M_{n}(\mathbb{F}) are invertible, then (AB)1=A1B1(A\otimes B)^{-1}=A^{-1}\otimes B^{-1}.

  • (e)

    det(AB)=(detA)n(detB)m\det(A\otimes B)=(\det{A})^{n}(\det{B})^{m} for AMm(𝔽)A\in M_{m}(\mathbb{F}) and BMn(𝔽)B\in M_{n}(\mathbb{F}).

A matrix TMn(𝔽)T\in M_{n}(\mathbb{F}) of the form

T=(a0a1a2a(n1)a1a0a1a(n2)a2a1a0a(n3)an1an2an3a0)T=\begin{pmatrix}a_{0}&a_{-1}&a_{-2}&\cdots&a_{-(n-1)}\\ a_{1}&a_{0}&a_{-1}&\cdots&a_{-(n-2)}\\ a_{2}&a_{1}&a_{0}&\cdots&a_{-(n-3)}\\ \vdots&\vdots&\vdots&\ddots&\vdots\\ a_{n-1}&a_{n-2}&a_{n-3}&\cdots&a_{0}\\ \end{pmatrix}

is called a Toeplitz matrix. In [18], the authors gave a Toeplitz matrix inversion formula.

Theorem 2.1 ([18], Theorem 1).

Let T=(aij)i,j=1nT=(a_{i-j})^{n}_{i,j=1} be a Toeplitz matrix and let f=(0,an1a1,,a2a(n2),a1a(n1))Tf=(0,a_{n-1}-a_{-1},\cdots,a_{2}-a_{-(n-2)},a_{1}-a_{-(n-1)})^{T} and e1=(1,0,,0)Te_{1}=(1,0,\cdots,0)^{T}. If each of the systems of equations Tx=fTx=f, Ty=e1Ty=e_{1} is solvable, x=(x1,x2,,xn)Tx=(x_{1},x_{2},\ldots,x_{n})^{T}, y=(y1,y2,,yn)Ty=(y_{1},y_{2},\ldots,y_{n})^{T}, then

  • (a)

    TT is invertible;

  • (b)

    T1=T1U1+T2U2T^{-1}=T_{1}U_{1}+T_{2}U_{2}, where

    T1=(y1yny2y2y1ynyny2y1),U1=(1xnx201xn001),T_{1}=\begin{pmatrix}y_{1}&y_{n}&\cdots&y_{2}\\ y_{2}&y_{1}&\ddots&\vdots\\ \vdots&\ddots&\ddots&y_{n}\\ y_{n}&\cdots&y_{2}&y_{1}\end{pmatrix},\qquad U_{1}=\begin{pmatrix}1&-x_{n}&\cdots&-x_{2}\\ 0&1&\ddots&\vdots\\ \vdots&\ddots&\ddots&-x_{n}\\ 0&\cdots&0&1\end{pmatrix},
    T2=(x1xnx2x2x1xnxnx2x1),andU2=(0yny200yn000).T_{2}=\begin{pmatrix}x_{1}&x_{n}&\cdots&x_{2}\\ x_{2}&x_{1}&\ddots&\vdots\\ \vdots&\ddots&\ddots&x_{n}\\ x_{n}&\cdots&x_{2}&x_{1}\end{pmatrix},~{}~{}\text{and}~{}~{}U_{2}=\begin{pmatrix}0&y_{n}&\cdots&y_{2}\\ 0&0&\ddots&\vdots\\ \vdots&\ddots&\ddots&y_{n}\\ 0&\cdots&0&0\end{pmatrix}.
Corollary 2.2.

Let aIn+bJnaI_{n}+bJ_{n} be a matrix in Mn(𝔽)M_{n}(\mathbb{F}). Then

  • (a)

    det(aIn+bJn)=an1(a+nb)\det(aI_{n}+bJ_{n})=a^{n-1}(a+nb).

  • (b)

    If aIn+bJnaI_{n}+bJ_{n} is invertible, then its inverse matrix is

    1a(a+nb)((a+nb)InbJn).\frac{1}{a(a+nb)}((a+nb)I_{n}-bJ_{n}).
Proof.
  • (a)

    It is easy to check that

    det(a+bbbbba+bbbbba+bbbbba+b)=det(a0000a0000a0b2b3ba+nb).\det\begin{pmatrix}a+b&b&b&\cdots&b\\ b&a+b&b&\cdots&b\\ b&b&a+b&\cdots&b\\ \vdots&\vdots&\vdots&\ddots&\vdots\\ b&b&b&\cdots&a+b\\ \end{pmatrix}=\det\begin{pmatrix}a&0&0&\cdots&0\\ 0&a&0&\cdots&0\\ 0&0&a&\cdots&0\\ \vdots&\vdots&\vdots&\ddots&\vdots\\ b&2b&3b&\cdots&a+nb\\ \end{pmatrix}.

    Hence the determinant of aIn+bJnaI_{n}+bJ_{n} is an1(a+nb)a^{n-1}(a+nb).

  • (b)

    Note that the matrix aIn+bJnaI_{n}+bJ_{n} is Toeplitz. Let

    x=(0,,0)T and y=(a+nbba(a+nb),ba(a+nb),,ba(a+nb))T.x=(0,\ldots,0)^{T}\text{~{}~{}and~{}~{}}y=\bigg{(}\frac{a+nb-b}{a(a+nb)},\frac{-b}{a(a+nb)},\ldots,\frac{-b}{a(a+nb)}\bigg{)}^{T}.

    Then (aIn+bJn)x=0(aI_{n}+bJ_{n})x=0 and (aIn+bJn)y=e1(aI_{n}+bJ_{n})y=e_{1}. By Theorem 2.1, the inverse of aIn+bJnaI_{n}+bJ_{n} is

    1a(a+nb)((a+nb)InbJn).\frac{1}{a(a+nb)}((a+nb)I_{n}-bJ_{n}).

3. k-Symmetric graphs

Symmetry is an important property of graphs. We deal with graphs that has symmetric property. Let GG be a graph. An automorphism φ\varphi of a graph GG is a permutation of V(G)V(G) such that φ(v)\varphi(v) and φ(w)\varphi(w) are adjacent if and only if vv and ww are adjacent where vv and ww are vertices of GG. The set of all automorphisms of GG is called an automorphism group of GG and denoted by Aut(G)\text{Aut}(G). A graph GG is symmetric if Aut(G)\text{Aut}(G) acts transitively on both vertices of GG and ordered pairs of adjacent vertices. This implies that GG is regular, that is, all vertices have the same degree. However, it is a very difficult problem to determine whether a given graph is a symmetric graph. Thus we concentrate the cyclic part of Aut(G)\text{Aut}(G). In this section, we define kk-symmetric graphs and give some their properties. Also, we construct a kk-symmetric graph from other kk-symmetric graphs.

Definition 3.1.

Let kk be a positive integer. A graph GG is kk-symmetric if there is a subgroup \mathcal{H} of Aut(G)\text{Aut}(G) such that \mathcal{H} is isomorphic to k\mathbb{Z}_{k} and \mathcal{H} freely act on vertices. A generator of \mathcal{H} is called a kk-symmetric automorphism.

The above definition tells us that all graphs are 1-symmetric because the trivial group freely acts on any graph. If a graph GG with nn vertices is nn-symmetric, then the automorphism group Aut(G)\text{Aut}(G) has a cyclic subgroup \mathcal{H} which transitively acts on vertices. Thus GG is regular. However, the converse is not true even though GG is a symmetric graph. Before examining this, we check the following proposition.

Proposition 3.2.

Let GG be a graph with nn vertices. If GG is nn-symmetric, then either GG or its complement G¯\overline{G} have a Hamiltonian cycle.

Proof.

Let GG be an nn-symmetric graph with nn vertices, and let φ\varphi be an nn-symmetric automorphism of GG. Choose a vertex vv. If vv and φ(v)\varphi(v) are adjacent, then φi(v)\varphi^{i}(v) and φi+1(v)\varphi^{i+1}(v) are also adjacent for any interger ii. Since GG is nn-symmetric, the group generated by φ\varphi acts freely and transitively on V(G)V(G). Thus the sequence v,φ(v),,φn(v)v,\varphi(v),\dots,\varphi^{n}(v) induces a Hamiltonian cycle of GG. Suppose that vv and φ(v)\varphi(v) are not adjacent in GG. Then vv and φ(v)\varphi(v) are adjacent in G¯\overline{G}. Hence the sequence of vertices induces a Hamiltonian cycle of G¯\overline{G}. ∎

For example, the Petersen graph in Figure 1 is 5-symmetric because the 5-fold rotation satisfies the 5-symmetric automorphism condition. The Petersen graph is a symmetric graph with 10 vertices. But since the Petersen graph is not Hamiltonian, it is not 10-symmetric. For any positive integer kk, kk-symmetric graphs are satisfying the following properties.

Refer to caption
Figure 1. The Petersen graphs with different bases for the 5-fold rotation
Proposition 3.3.

Let GG be a kk-symmetric graph for some integer kk and let dd be a divisor of kk. Then GG is a dd-symmetric graph.

Proof.

Let φ\varphi be a kk-symmetric automorphism of GG and let k=kdk=k^{\prime}d for some integer kk^{\prime}. Define an automorphism ψ\psi of GG by ψ=φk\psi=\varphi^{k^{\prime}}. Then ψd(v)=φkd(v)=φk(v)=idG(v)\psi^{d}(v)=\varphi^{k^{\prime}d}(v)=\varphi^{k}(v)=\text{id}_{G}(v) for all vV(G)v\in V(G). The subgroup ψ\langle\psi\rangle of Aut(G)\text{Aut}(G) is isomorphic to d\mathbb{Z}_{d}. Thus GG is a dd-symmetric graph. ∎

Proposition 3.4.

Let G1G_{1} and G2G_{2} be kk-symmetric graphs for some integer kk. Then G1G2G_{1}\cup G_{2} is kk-symmetric graph.

Proof.

Let φ1\varphi_{1} and φ2\varphi_{2} be kk-symmetric automorphisms of G1G_{1} and G2G_{2}, respectively. Then the automorphism φ1+φ2\varphi_{1}+\varphi_{2} of G1G2G_{1}\cup G_{2} is defined by

(φ1+φ2)(v)={φ1(v),if vV(G1),φ2(v),if vV(G2).(\varphi_{1}+\varphi_{2})(v)=\left\{\begin{array}[]{ll}\varphi_{1}(v),&\mbox{if $v\in V(G_{1})$},\\ \varphi_{2}(v),&\mbox{if $v\in V(G_{2})$}\end{array}\right..

Hence G1G2G_{1}\cup G_{2} is a kk-symmetric graph.

Let φ\varphi be a kk-symmetric automorphism of a graph GG and let idH\operatorname{id}_{H} be the identity automorphism of a graph HH. Then the automorphism φ×idH\varphi\times\operatorname{id}_{H} of GHG\square H is kk-symmetric. Thus we obtain the following proposition.

Proposition 3.5.

Let GG be a kk-symmetric graphs for some integer kk. For any graph HH, the Cartesian product GHG\square H is kk-symmetric graph.

Let GG be a graph with a kk-symmetric automorphism φ\varphi. Then k\mathbb{Z}_{k} acts on V(G)V(G) as follows. For any iki\in\mathbb{Z}_{k} and vV(G)v\in V(G), we define iv=φi(v)i\cdot v=\varphi^{i}(v). For any vertex vv, the orbit of vv is denoted by kv\mathbb{Z}_{k}\cdot v. Let BφB_{\varphi} be a minimal subset of V(G)V(G) such that

i=0k1φi(Bφ)=V(G).\bigcup_{i=0}^{k-1}\varphi^{i}(B_{\varphi})=V(G).

Alternatively, BφB_{\varphi} is a minimal subset of V(G)V(G) such that

vBφkv=V(G).\bigcup_{v\in B_{\varphi}}\mathbb{Z}_{k}\cdot v=V(G).

The set BφB_{\varphi} is called a base of φ\varphi. Since kk choices are possible for each orbit, BφB_{\varphi} is not unique as drawn in Figure 1. Note that the size of the base BφB_{\varphi} is |V(G)|k\frac{|V(G)|}{k}.

Now we introduce how to construct a kk-symmetric graph from other kk-symmetric graphs for any positive integer kk. First we observe a graph join. Let H1H_{1} and H2H_{2} be graphs. The graph join H1H2H_{1}\!\vee\!H_{2} of H1H_{1} and H2H_{2} is a graph obtained by joining each vertex of H1H_{1} to all vertices of H2H_{2}. Since every graph is 1-symmetric with respect to identity map, we can understand graph join H1H2H_{1}\!\vee\!H_{2} as a join of the bases V(H1)V(H_{1}) and V(H2)V(H_{2}) of idH1\operatorname{id}_{H_{1}} and idH2\operatorname{id}_{H_{2}}. From this fact, we generalize graph join.

Definition 3.6.

For i{1,2}i\in\{1,2\}, let GiG_{i} be a kk-symmetric graph with a kk-symmetric automorphism φi\varphi_{i}, and let BiB_{i} be a chosen base of φi\varphi_{i}. The kk-symmetric join is a graph obtained by joining each vertex of φ1j(B1)\varphi_{1}^{j}(B_{1}) to all vertices of φ2j(B2)\varphi_{2}^{j}(B_{2}) for all jkj\in\mathbb{Z}_{k}. The kk-symmetric join is denoted by (G1,φ1,B1)k(G2,φ2,B2)(G_{1},\varphi_{1},B_{1})\vee_{k}(G_{2},\varphi_{2},B_{2}). If we choose arbitrary kk-symmetric automorphisms and its bases of G1G_{1} and G2G_{2}, then the kk-symmetric join is simply denoted by G1kG2G_{1}\vee_{k}G_{2}.

The kk-symmetric join preserves the kk-symmetry. Because the kk-symmetric automorphism of G1kG2G_{1}\vee_{k}G_{2} is φ1+φ2\varphi_{1}+\varphi_{2} and its base is B1B2B_{1}\cup B_{2}. Definition 3.6 derives that the graph join is the 1-symmetric join. Note that, nn-symmetric joins are not unique even if the base of each GiG_{i} is unique. For instance, the Cartesian product of 5-cycle C5C_{5} with K2K_{2} and the Petersen graph are both 5-symmetric joins of two 5-cycles, but they are not isomorphic as drawn in Figure 2.

Refer to caption
Figure 2. The 55-symmetric join of two 5-cycles is C5K2C_{5}\square K_{2} if both automorphisms are (1,2,3,4,5)(1,2,3,4,5), and the Petersen graph if automorphisms are (1,2,3,4,5)(1,2,3,4,5) and (1,3,5,2,4)(1,3,5,2,4)

4. 2-connected kk-symmetric graphs with Laplacian eigenvalue 1

In this section, we prove Theorem 1.1. First we consider the multiplicity of an integral Laplacian eigenvalue. Recall that for a given graph GG, the partition π=(V1,V2,,Vk)\pi=(V_{1},V_{2},\cdots,V_{k}) of V(G)V(G) is an equitable partition if for all i,j{1,2,,k}i,j\in\{1,2,\ldots,k\} and for any vViv\in V_{i} the number dij=|NG(v)Vj|d_{ij}=|N_{G}(v)\cap V_{j}| depends only on ii and jj. The k×kk\times k matrix Lπ(G)=(bij)L^{\pi}(G)=(b_{ij}) defined by

bij={dij,if ij,s=1kdisdij,if i=jb_{ij}=\left\{\begin{array}[]{ll}-d_{ij},&\mbox{if $i\neq j$},\\ \sum_{s=1}^{k}d_{is}-d_{ij},&\mbox{if $i=j$}\end{array}\right.

is called the divisor matrix of GG with respect to π\pi.

Lemma 4.1 ([2, 6]).

Let GG be a graph and let π=(V1,,Vk)\pi=(V_{1},\ldots,V_{k}) be an equitable partition of GG with divisor matrix Lπ(G)L^{\pi}(G). Then each eigenvalue of Lπ(G)L^{\pi}(G) is also an eigenvalue of L(G)L(G).

In the following theorem, we obtain the multiplicity of nn of kk-symmetric join of graphs where nn is the size of a base.

Theorem 4.2.

Let G1,,GlG_{1},\ldots,G_{l} be kk-symmetric graphs for some kk and let G=G1kkGlG=G_{1}\vee_{k}\cdots\vee_{k}G_{l} be the kk-symmetric join of G1,,GlG_{1},\ldots,G_{l}. Let n=|V(G)|kn=\frac{|V(G)|}{k}. Then

mG(n)l1.m_{G}(n)\geq l-1.
Proof.

The partition π=(V(G1),,V(Gl))\pi=(V(G_{1}),\ldots,V(G_{l})) is an equitable partition of GG. Then we have

Lπ(G)=(nn1n2nln1nn2nln1n2nnl),L^{\pi}(G)=\begin{pmatrix}n-n_{1}&-n_{2}&\cdots&-n_{l}\\ -n_{1}&n-n_{2}&\cdots&-n_{l}\\ \vdots&\vdots&\ddots&\vdots\\ -n_{1}&-n_{2}&\cdots&n-n_{l}\end{pmatrix},

where ni=|V(Gi)|kn_{i}=\frac{|V(G_{i})|}{k} for i=1,,li=1,\ldots,l. Since the characteristic polynomial of Lπ(G)L^{\pi}(G) is μ(Lπ(G),x)=x(xn)l1\mu(L^{\pi}(G),x)=x(x-n)^{l-1}, by Lemma 4.1, we obtain

mG(n)l1.m_{G}(n)\geq l-1.

If each GiG_{i} in the above theorem is nn-symmetric graph with nn vertices, then the size of a base of GG is ll.

Corollary 4.3.

Let G1,,GlG_{1},\ldots,G_{l} be nn-symmetric graphs with nn vertices. Then for any their nn-symmetric join GG,

mG(l)l1.m_{G}(l)\geq l-1.

Let GG be an nn-symmetric graph with nn vertices. Take an nn-symmetric automorphism φ\varphi of GG. Let GG^{\prime} be a graph that nn-symmetric join of mm copies of GG along φ\varphi. Then since each base of the copy of GG is a vertex, the base of GG^{\prime} induces the mm complete graph KmK_{m}. Since GG^{\prime} is constructed by same nn-symmetric automorphism, GG^{\prime} becomes the Cartesian product of GG and KmK_{m}.

Corollary 4.4.

Let GG be nn-symmetric graphs with nn vertices. Then for any positive integer mm,

mKmG(m)m1.m_{K_{m}\square G}(m)\geq m-1.

By the Špacapan’s result [20] about the connectivity of the Cartesian product in Section 1, we realize that for any positive integer mm, there is a mm-connected graph GG with mG(m)m1m_{G}(m)\geq m-1.

Now consider a special case of kk-symmetric join. For any i{1,,l}i\in\{1,\dots,l\}, let GiG_{i} be a kk-symmetric graph for some positive integer kk and let φi\varphi_{i} be an associated kk-symmetric automorphism. Let Bi1B^{1}_{i} be a base of GiG_{i}, and let Bij=φij(Bi1)B^{j}_{i}=\varphi^{j}_{i}(B^{1}_{i}). Racall that the union of G1,GlG_{1},\dots G_{l} is also kk-symmetric with the kk-symmetric automorphism φ1++φl\varphi_{1}+\cdots+\varphi_{l} and the base B11Bl1B^{1}_{1}\cup\cdots\cup B^{1}_{l}. Define a graph GG by kk-symmetric joining K¯k\overline{K}_{k} and G1GlG_{1}\cup\cdots\cup G_{l}. Then the subgraph induced by a base of GG has a cut-vertex as drawn in Figure 3 (a). From this fact, we can take an equitable partition π=(V0,V1,,Vl)\pi=(V_{0},V_{1},\ldots,V_{l}) where V0=V(K¯k)V_{0}=V(\overline{K}_{k}) and Vi=V(Gi)V_{i}=V(G_{i}) for any i{1,,l}i\in\{1,\dots,l\} as drawn in Figure 3 (b). Remark that for any distinct ii and ii^{\prime}, there is no edge connecting two subgraphs GiG_{i} and GiG_{i^{\prime}} in GG. To prove Theorem 1.1, we need the following two theorems.

Refer to caption
Figure 3. kk-symmetric graph G=K¯kk(G1Gl)G=\overline{K}_{k}\vee_{k}\left(G_{1}\cup\cdots\cup G_{l}\right)
Theorem 4.5.

Let G1,,GlG_{1},\dots,G_{l} be kk-symmetric graphs for some positive integers ll and kk, and let G=K¯kk(G1Gl)G=\overline{K}_{k}\vee_{k}\left(G_{1}\cup\cdots\cup G_{l}\right). Then

mG(1)l1.m_{G}(1)\geq l-1.
Proof.

Suppose that G1,,GlG_{1},\dots,G_{l} and GG are the graphs in the statement of the theorem. Let V0V_{0} be the vertices set of K¯k\overline{K}_{k} and let ViV_{i} be the vertices set of GiG_{i} for i=1,,li=1,\ldots,l. Our observation implies that the partition π=(V0,V1,,Vl)\pi=(V_{0},V_{1},\ldots,V_{l}) is an equitable partition of GG. Then the divisor matrix Lπ(G)L^{\pi}(G) is equal to

(nn1n2nl110010101001),\left(\begin{array}[]{ccccc}n&-n_{1}&-n_{2}&\cdots&-n_{l}\\ -1&1&0&\cdots&0\\ -1&0&1&\cdots&0\\ \vdots&\vdots&\vdots&\ddots&\vdots\\ -1&0&0&\cdots&1\\ \end{array}\right),

where ni=|Vi|kn_{i}=\frac{|V_{i}|}{k} for i=1,,li=1,\ldots,l and n=i=1lnin=\sum_{i=1}^{l}n_{i}. We can partition the matrix xILπ(G)xI-L^{\pi}(G) into four blocks as

(xnn1n2nl\hdashline1x10010x10100x1).\left(\begin{array}[]{c:cccc}x-n&n_{1}&n_{2}&\cdots&n_{l}\\ \hdashline 1&x-1&0&\cdots&0\\ 1&0&x-1&\cdots&0\\ \vdots&\vdots&\vdots&\ddots&\vdots\\ 1&0&0&\cdots&x-1\\ \end{array}\right).

Then the characteristic polynomial of Lπ(G)L^{\pi}(G) is

μ(Lπ(G),x)\displaystyle\mu(L^{\pi}(G),x) =(x1)l((xn)1x1n)\displaystyle=(x-1)^{l}\bigg{(}(x-n)-\frac{1}{x-1}n\bigg{)}
=(x1)l1((xn)(x1)n)\displaystyle=(x-1)^{l-1}((x-n)(x-1)-n)
=(x1)l1x(x(n+1)).\displaystyle=(x-1)^{l-1}x(x-(n+1)).

By Lemma 4.1, we obtain mG(1)l1m_{G}(1)\geq l-1. ∎

Theorem 4.6.

Let G1,,GlG_{1},\dots,G_{l} be connected kk-symmetric graphs for some integers l,k2l,k\geq 2. Then the graph G=K¯kk(G1Gl)G=\overline{K}_{k}\vee_{k}\left(G_{1}\cup\cdots\cup G_{l}\right) is a 2-connected prime graph with respect to Cartesian product.

Proof.

First we prove that the graph G=K¯kk(G1Gl)G=\overline{K}_{k}\vee_{k}\left(G_{1}\cup\cdots\cup G_{l}\right) is 2-connected. Suppose that there is a cut-vertex vv of GG in K¯k\overline{K}_{k}. Since k2k\geq 2, there is another vertex ww in K¯k\overline{K}_{k}. Since l2l\geq 2, there are two independent paths P1P_{1} and P2P_{2} from vv to ww passing through G1G_{1} and G2G_{2}, respectively. This implies that vv lies on the cycle P1P2P_{1}\cup P_{2}, and hence vv is not a cut-vertex. Next we suppose that a cut-vertex of GG is not lying on K¯k\overline{K}_{k}. Without loss of generality, assume that a cut-vertex vv is in G1G_{1}. Since l,k2l,k\geq 2 and GG is connected, there is a cycle containing vv in GG. It follows that vv is not a cut-vertex. Therefore, GG is 2-connected.

Now, we show that the graph GG is prime with respect to the Cartesian product. It is well-known that if two edges of a nontrivial Cartesian product are incident, then they are included in a subgraph C4C_{4} of the Cartesian product. For any vertex uu of GG in K¯k\overline{K}_{k}, two incident edges ee and ff of uu such that the endpoints of ee and ff are contained in different graphs GiG_{i} and GjG_{j} for some integers ii and jj. But there is no C4C_{4} including ee and ff. Thus we deduce that GG is prime. ∎

Theorems 4.5 and 4.6 imply Theorem 1.1. Note that, if one of the graphs G1,,GlG_{1},\ldots,G_{l} is disconnected, then there is a counterexample. For example, if G1G_{1} is K¯k\overline{K}_{k}, then G=K¯kk(G1Gl)G=\overline{K}_{k}\vee_{k}\left(G_{1}\cup\cdots\cup G_{l}\right) has a cut vertex.

5. Laplacian integral graphs

In this section, we discuss kk-symmetric graphs with integral Laplacian spectrum. Let nn and mm be positive integers. Since the nn-complete graph KnK_{n} is nn-symmetric, the disjoint union of mm copies of KnK_{n}, denoted by mKnmK_{n}, is also nn-symmetric. We consider the nn-symmetric join of K¯n\overline{K}_{n} and mKnmK_{n}. Denote the graph K¯nnmKn\overline{K}_{n}\vee_{n}mK_{n} by 𝒞(n,m)\mathcal{C}(n,m). Now we observe that a graph C(n,m)C(n,m) is not a cograph for n2n\geq 2. Let vv and ww be vertices in K¯n\overline{K}_{n}. Then there are two vertices in KnK_{n} which are adjacent to vv and ww, respectively. Thus the graph C(n,m)C(n,m) contains the path P4P_{4} as an induced subgraph. We will show that a graph 𝒞(n,m)\mathcal{C}(n,m) is Laplacian integral for some positive integers nn and mm. In the following theorem, we give the characteristic polynomial of L(𝒞(n,m))L(\mathcal{C}(n,m)).

Theorem 5.1.

Let nn and mm be positive integers. Then the characteristic polynomial of L(𝒞(n,m))L(\mathcal{C}(n,m)) is

x(x1)m1(x(n+1))(m1)(n1)(x(m+1))(x2(m+n+1)x+mn)n1.x(x-1)^{m-1}(x-(n+1))^{(m-1)(n-1)}(x-(m+1))(x^{2}-(m+n+1)x+mn)^{n-1}.
Proof.

The Laplacian matrix of 𝒞(n,m)\mathcal{C}(n,m) is

L(𝒞(n,m))=(mIn+L(K¯n)1mTIn1mInIm(In+L(Kn))).L(\mathcal{C}(n,m))=\begin{pmatrix}mI_{n}+L(\overline{K}_{n})&-1_{m}^{T}\otimes I_{n}\\ -1_{m}\otimes I_{n}&I_{m}\otimes(I_{n}+L(K_{n}))\end{pmatrix}.

We consider xIn(m+1)L(𝒞(n,m))xI_{n(m+1)}-L(\mathcal{C}(n,m)) as a matrix over the field of rational functions (x)\mathbb{C}(x). Then the characteristic polynomial of L(𝒞(n,m))L(\mathcal{C}(n,m)) is

μ(L(𝒞(n,m)),x)=\displaystyle\mu(L(\mathcal{C}(n,m)),x)= det(xIn(m+1)L(𝒞(n,m)))\displaystyle\det(xI_{n(m+1)}-L(\mathcal{C}(n,m)))
=\displaystyle= det((xm)In1mTIn1mInIm((x1)InL(Kn)))\displaystyle\det\begin{pmatrix}(x-m)I_{n}&1_{m}^{T}\otimes I_{n}\\ 1_{m}\otimes I_{n}&I_{m}\otimes((x-1)I_{n}-L(K_{n}))\end{pmatrix}
=\displaystyle= det(Im((x1)InL(Kn)))det((xm)In\displaystyle\det\big{(}I_{m}\otimes((x-1)I_{n}-L(K_{n}))\big{)}\det\big{(}(x-m)I_{n}
(1mTIn)(Im((x1)InL(Kn)))1(1mIn))\displaystyle~{}~{}-(1_{m}^{T}\otimes I_{n})(I_{m}\otimes((x-1)I_{n}-L(K_{n})))^{-1}(1_{m}\otimes I_{n})\big{)}
=\displaystyle= det((x1)InL(Kn))mdet((xm)In\displaystyle\det((x-1)I_{n}-L(K_{n}))^{m}\det\big{(}(x-m)I_{n}
m((x1)InL(Kn))1).\displaystyle~{}~{}-m((x-1)I_{n}-L(K_{n}))^{-1}\big{)}.

Since det(xInL(Kn))=μ(L(Kn),x)\det(xI_{n}-L(K_{n}))=\mu(L(K_{n}),x), we obtain

det((x1)InL(Kn))m\displaystyle\det((x-1)I_{n}-L(K_{n}))^{m} =μ(L(Kn),x1)m\displaystyle=\mu(L(K_{n}),x-1)^{m}
=(x1)m(x(n+1))m(n1).\displaystyle=(x-1)^{m}(x-(n+1))^{m(n-1)}.

Now, we compute the determinant of (xm)Inm((x1)InL(Kn))1.(x-m)I_{n}-m((x-1)I_{n}-L(K_{n}))^{-1}. By Corollary 2.2 (b), we have

((x1)InL(Kn))1\displaystyle\big{(}(x-1)I_{n}-L(K_{n})\big{)}^{-1} =((x(n+1))In+Jn)1\displaystyle=\big{(}(x-(n+1))I_{n}+J_{n}\big{)}^{-1}
=1(x1)(x(n+1))((x1)InJn).\displaystyle=\frac{1}{(x-1)(x-(n+1))}\big{(}(x-1)I_{n}-J_{n}\big{)}.

This implies that

det((xm)Inm((x1)InL(Kn))1)\displaystyle~{}\det\big{(}(x-m)I_{n}-m((x-1)I_{n}-L(K_{n}))^{-1}\big{)}
=\displaystyle= det((xm)(x1)(x(n+1))Inm((x1)InJn))(x1)n(x(n+1))n\displaystyle~{}\frac{\det\big{(}(x-m)(x-1)(x-(n+1))I_{n}-m((x-1)I_{n}-J_{n})\big{)}}{(x-1)^{n}(x-(n+1))^{n}}
=\displaystyle= det((x3(m+n+2)x2+(mn+m+n+1)xmn)In+mJn)(x1)n(x(n+1))n\displaystyle~{}\frac{\det\big{(}(x^{3}-(m+n+2)x^{2}+(mn+m+n+1)x-mn)I_{n}+mJ_{n}\big{)}}{(x-1)^{n}(x-(n+1))^{n}}

By Corollary 2.2 (a), we have

det((x3(m+n+2)x2+(mn+m+n+1)xmn)In+mJn)\displaystyle\det\big{(}(x^{3}-(m+n+2)x^{2}+(mn+m+n+1)x-mn)I_{n}+mJ_{n}\big{)}
=\displaystyle= x(x(m+1))(x(n+1))(x1)n1(x2(m+n+1)x+mn)n1.\displaystyle~{}x(x-(m+1))(x-(n+1))(x-1)^{n-1}(x^{2}-(m+n+1)x+mn)^{n-1}.

Hence the determinant of (xm)Inm((x1)InL(Kn))1(x-m)I_{n}-m((x-1)I_{n}-L(K_{n}))^{-1} is

x(x(m+1))(x2(m+n+1)x+mn)n1(x(n+1))n1(x1).\frac{x(x-(m+1))(x^{2}-(m+n+1)x+mn)^{n-1}}{(x-(n+1))^{n-1}(x-1)}.

Therefore the characteristic polynomial of L(𝒞(n,m))L(\mathcal{C}(n,m)) is

x(x1)m1(x(n+1))(m1)(n1)(x(m+1))(x2(m+n+1)x+mn)n1.x(x-1)^{m-1}(x-(n+1))^{(m-1)(n-1)}(x-(m+1))(x^{2}-(m+n+1)x+mn)^{n-1}.

The following corollary induces Theorem 1.2.

Corollary 5.2.

Let nn, mm, kk, and ll be positive integers with l1l\neq 1. Then

  • (a)

    If 𝒞(n,m)\mathcal{C}(n,m) is Laplacian integral, then 𝒞(m,n)\mathcal{C}(m,n) is also Laplacian integral.

  • (b)

    A graph 𝒞(kl,(k+1)(l1))\mathcal{C}(kl,(k+1)(l-1)) is Laplacian integral.

  • (c)

    A graph 𝒞(k2+k,k2+k)\mathcal{C}(k^{2}+k,k^{2}+k) is regular Laplacian integral.

Proof.
  • (a)

    It is obvious by Theorem 5.1.

  • (b)

    If the quadratic x2(m+n+1)x+mnx^{2}-(m+n+1)x+mn has two integer roots, then 𝒞(m,n)\mathcal{C}(m,n) is Laplacian integral, by Theorem 5.1. Let kk, ll, rr and ss be positive integers with n=kln=kl and m=rsm=rs. Suppose that krkr and lsls are roots of the quadratic. Then, by Vieta’s formulas, we have kr+ls=rs+kl+1kr+ls=rs+kl+1, that is,

    (1) (sk)r(sk)l+1=0.(s-k)r-(s-k)l+1=0.

    If s=ks=k then it is a contradiction. If sk0s-k\neq 0, then rl+1sk=0r-l+\frac{1}{s-k}=0. Since rr and ll are integers, sks-k must be 1. Plugging s=k+1s=k+1 into the equation (1), we have r=l1r=l-1. Since mm is a positive integer, ll is not equal to 11. Thus 𝒞(kl,(k+1)(l1))\mathcal{C}(kl,(k+1)(l-1)) is Laplacian integral for any positive integers kk and l1l\neq 1.

  • (c)

    If m=nm=n, then 𝒞(n,m)\mathcal{C}(n,m) is regular. By (b), a graph 𝒞(k2+k,k2+k)\mathcal{C}(k^{2}+k,k^{2}+k) is regular Laplacian integral graph.

Now, we consider the nn-complete graph KnK_{n} as a kk-symmetric graph for some divisor kk of nn. Note that a base of KnK_{n} as a kk-symmetric graph is not unique, but the kk-symmetric join of K¯k\overline{K}_{k} and mKnmK_{n} is unique up to isomorphism. We denote by 𝒞(n,k,m)\mathcal{C}(n,k,m) the graph K¯kkmKn\overline{K}_{k}\vee_{k}mK_{n}. In the similar way to the proof of Theorem 5.1, we get the characteristic polynomial of L(𝒞(n,k,m))L(\mathcal{C}(n,k,m)).

Theorem 5.3.

Let nn and mm be positive integers. Let kk be a divisor of nn and let d=n/kd=n/k. Then the characteristic polynomial of L(𝒞(n,k,m))L(\mathcal{C}(n,k,m)) is

x(x1)m1(x(n+1))m(n1)k+1(x(md+1))(x2(md+n+1)x+mdn)k1.x(x-1)^{m-1}(x-(n+1))^{m(n-1)-k+1}(x-(md+1))(x^{2}-(md+n+1)x+mdn)^{k-1}.
Proof.

The Laplacian matrix of 𝒞(n,k,m)\mathcal{C}(n,k,m) is

L(𝒞(n,k,m))=(mdIk+L(K¯k)1mT(Ik1dT)1m(Ik1d)Im(In+L(Kn))).L(\mathcal{C}(n,k,m))=\begin{pmatrix}mdI_{k}+L(\overline{K}_{k})&-1_{m}^{T}\otimes(I_{k}\otimes 1_{d}^{T})\\ -1_{m}\otimes(I_{k}\otimes 1_{d})&I_{m}\otimes(I_{n}+L(K_{n}))\end{pmatrix}.

Then the characteristic polynomial of L(𝒞(n,k,m))L(\mathcal{C}(n,k,m)) is

μ(L(𝒞(n,k,m)),x)=det(xIn(m+1)L(𝒞(n,k,m))).\mu(L(\mathcal{C}(n,k,m)),x)=\det\big{(}xI_{n(m+1)}-L(\mathcal{C}(n,k,m))\big{)}.

Consider xIn(m+1)L(𝒞(n,k,m))xI_{n(m+1)}-L(\mathcal{C}(n,k,m)) as a matrix over the field of rational functions (x)\mathbb{C}(x). Then

det(xIn(m+1)L(𝒞(n,k,m)))\displaystyle~{}~{}~{}\det\big{(}xI_{n(m+1)}-L(\mathcal{C}(n,k,m))\big{)}
=det((xmd)Ik1mT(Ik1dT)1m(Ik1d)Im((x1)InL(Kn)))\displaystyle=\det\begin{pmatrix}(x-md)I_{k}&1_{m}^{T}\otimes(I_{k}\otimes 1_{d}^{T})\\ 1_{m}\otimes(I_{k}\otimes 1_{d})&I_{m}\otimes((x-1)I_{n}-L(K_{n}))\end{pmatrix}
=det(Im((x1)InL(Kn)))det((xmd)Ik\displaystyle=\det\big{(}I_{m}\otimes((x-1)I_{n}-L(K_{n}))\big{)}\det\big{(}(x-md)I_{k}
(1mT(Ik1dT))(Im((x1)InL(Kn)))1(1m(Ik1d))\displaystyle~{}~{}-(1_{m}^{T}\otimes(I_{k}\otimes 1_{d}^{T}))(I_{m}\otimes((x-1)I_{n}-L(K_{n})))^{-1}(1_{m}\otimes(I_{k}\otimes 1_{d})\big{)}
=det((x1)InL(Kn))mdet((xmd)Ik\displaystyle=\det\big{(}(x-1)I_{n}-L(K_{n})\big{)}^{m}\det\big{(}(x-md)I_{k}
m(Ik1dT)((x1)InL(Kn))1(Ik1d)).\displaystyle~{}~{}-m\big{(}I_{k}\otimes 1_{d}^{T})((x-1)I_{n}-L(K_{n}))^{-1}(I_{k}\otimes 1_{d})\big{)}.

It is easily check that

det((x1)InL(Kn))m=(x1)m(x(n+1))m(n1).\det\big{(}(x-1)I_{n}-L(K_{n})\big{)}^{m}=(x-1)^{m}(x-(n+1))^{m(n-1)}.

Now, we compute det((xmd)Ikm(Ik1dT)((x1)InL(Kn))1(Ik1d)).\det\big{(}(x-md)I_{k}-m\big{(}I_{k}\otimes 1_{d}^{T})((x-1)I_{n}-L(K_{n}))^{-1}(I_{k}\otimes 1_{d})\big{)}. By Corollary 2.2 (b), we have

((x1)InL(Kn))1=1(x1)(x(n+1))((x1)InJn).\big{(}(x-1)I_{n}-L(K_{n})\big{)}^{-1}=\frac{1}{(x-1)(x-(n+1))}((x-1)I_{n}-J_{n}).

Note that the matrix (x1)InJn(x-1)I_{n}-J_{n} can be written in the Kronecker product form (x1)IkIdJkJd(x-1)I_{k}\otimes I_{d}-J_{k}\otimes J_{d}. It follows that

(Ik1dT)((x1)InL(Kn))1(Ik1d)\displaystyle~{}(I_{k}\otimes 1_{d}^{T})((x-1)I_{n}-L(K_{n}))^{-1}(I_{k}\otimes 1_{d})
=\displaystyle= (x1)1(x(n+1))1(Ik1dT)((x1)IkIdJkJd)(Ik1d)\displaystyle~{}(x-1)^{-1}(x-(n+1))^{-1}(I_{k}\otimes 1_{d}^{T})((x-1)I_{k}\otimes I_{d}-J_{k}\otimes J_{d})(I_{k}\otimes 1_{d})
=\displaystyle= (x1)1(x(n+1))1(d(x1)Ikd2Jk).\displaystyle~{}(x-1)^{-1}(x-(n+1))^{-1}(d(x-1)I_{k}-d^{2}J_{k}).

Then we have

det((xmd)Ikm(Ik1dT)((x1)In+L(Kn))1(Ik1d)))\displaystyle\det\big{(}(x-md)I_{k}-m\big{(}I_{k}\otimes 1_{d}^{T})((x-1)I_{n}+L(K_{n}))^{-1}(I_{k}\otimes 1_{d})\big{)}\big{)}
=\displaystyle= det((xmd)(x1)(x(n+1))Ikmd(x1)Ik+md2Jk)(x1)k(x(n+1))k.\displaystyle\frac{\det\big{(}(x-md)(x-1)(x-(n+1))I_{k}-md(x-1)I_{k}+md^{2}J_{k}\big{)}}{(x-1)^{k}(x-(n+1))^{k}}.

By Corollary 2.2 (a), we obtain

det((xmd)(x1)(x(n+1))Ikmd(x1)Ik+md2Jk)\displaystyle\det\big{(}(x-md)(x-1)(x-(n+1))I_{k}-md(x-1)I_{k}+md^{2}J_{k}\big{)}
=\displaystyle= det((x3(md+n+2)x2+(md+1)(n+1)xmdn)Ik+md2Jk)\displaystyle\det\big{(}(x^{3}-(md+n+2)x^{2}+(md+1)(n+1)x-mdn)I_{k}+md^{2}J_{k}\big{)}
=\displaystyle= x(x(md+1))(x(n+1))(x1)k1(x2(md+n+1)x+mdn)k1.\displaystyle~{}x(x-(md+1))(x-(n+1))(x-1)^{k-1}(x^{2}-(md+n+1)x+mdn)^{k-1}.

Hence the determinant of (xmd)Ikm(Ik1dT)((x1)InL(Kn))1(Ik1d)(x-md)I_{k}-m\big{(}I_{k}\otimes 1_{d}^{T})((x-1)I_{n}-L(K_{n}))^{-1}(I_{k}\otimes 1_{d}) is

x(x(md+1))(x2(md+n+1)x+mdn)k1(x1)(x(n+1))k1.\frac{x(x-(md+1))(x^{2}-(md+n+1)x+mdn)^{k-1}}{(x-1)(x-(n+1))^{k-1}}.

Thus the characteristic polynomial of L(𝒞(n,k,m))L(\mathcal{C}(n,k,m)) is

x(x1)m1(x(n+1))m(n1)k+1(x(md+1))(x2(md+n+1)x+mdn)k1.\displaystyle x(x-1)^{m-1}(x-(n+1))^{m(n-1)-k+1}(x-(md+1))(x^{2}-(md+n+1)x+mdn)^{k-1}.

The next two corollaries tell us about the relation between Laplacian integral graphs 𝒞(n,n,m)\mathcal{C}(n,n,m) and 𝒞(n,k,m)\mathcal{C}(n,k,m^{\prime}) for some positive integers nn, mm, mm^{\prime} and kk with k|nk\,|\,n.

Corollary 5.4.

Suppose that 𝒞(n,n,m)\mathcal{C}(n,n,m) is Laplacian integral for some positive integers nn and mm. Let dd be a divisor of nn. If mm is divisible by dd, then 𝒞(n,nd,md)\mathcal{C}(n,\frac{n}{d},\frac{m}{d}) is Laplacian integral.

Proof.

Suppose that 𝒞(n,n,m)\mathcal{C}(n,n,m) is Laplacaian integral for some positive integers nn and mm. Then the polynomial x2(m+n+1)x+mnx^{2}-(m+n+1)x+mn in the characteristic polynomial of 𝒞(n,n,m)\mathcal{C}(n,n,m) can be factored over the integers. Let dd be a divisor of nn. By Theorem 5.3, it is enough to show that the quadratic in the characteristic polynomial of 𝒞(n,nd,md)\mathcal{C}(n,\frac{n}{d},\frac{m}{d}) has integral roots. Since the quadratic is

x2(mddn+n+1)x+mddn=x2(m+n+1)x+mn,x^{2}-\bigg{(}\frac{m}{d}dn+n+1\bigg{)}x+\frac{m}{d}dn=x^{2}-(m+n+1)x+mn,

the graph 𝒞(n,nd,md)\mathcal{C}(n,\frac{n}{d},\frac{m}{d}) is Laplacian integral. ∎

Corollary 5.5.

Suppose that 𝒞(n,k,m)\mathcal{C}(n,k,m) is Laplacian integral for some positive integers nn, mm and kk with k|nk\,|\,n. Let d=n/kd=n/k. Then 𝒞(n,n,md)\mathcal{C}(n,n,md) is Laplacian integral.

Proof.

The proof is similar that of Theorem 5.4. Since the quadratic in the characteristic polynomial of 𝒞(n,n,md)\mathcal{C}(n,n,md) is

x2(md+n+1)x+mdn,x^{2}-(md+n+1)x+mdn,

it is easy to see that 𝒞(n,n,md)\mathcal{C}(n,n,md) is Laplacian integral. ∎

Declaration of Competing Interest

There is no competing interest.

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