Proof of the Mañé’s conjecture on surfaces.
Abstract.
We prove that generic hyperbolic Mañé sets contain a periodic periodic orbit. In dimension 2, adding a result in [7] which states that generic Mañé sets are hyperbolic we obtain Mañé’s Conjecture for surfaces in the topology: Given a Tonelli Lagrangian on a compact surface there is a open and dense set of functions such that the Mañé set of the Lagrangian is a hyperbolic periodic orbit.
Key words and phrases:
Mañé’s Conjecture, Aubry-Mather Theory, Lagrangian Systems.1991 Mathematics Subject Classification:
37J51, 37D051. Introduction.
Let be a closed riemannian manifold. A Tonelli Lagrangian is a function that is
-
(i)
Convex: , .
The uniform convexity assumption and the compactness of imply that is
-
(ii)
Superlinear: such that : .
Given , the Mañé action potential is defined as ,
(1) |
where
(2) |
The Mañé critical value is
(3) |
See [13] for several characterizations of .
A curve is semi-static if
Also is static if
The Mañé set of is
and the Aubry set is
The Euler-Lagrange equation
defines the Lagrangian flow on . The energy function ,
is invariant under the Lagrangian flow. The Mañé set is invariant under the Lagrangian flow and it is contained in the energy level (see Mañé [24, p. 146] or [13]).
Let be the set of Borel probabilities in which are invariant under the Lagrangian flow. Define the action functional as
The set of minimizing measures is
and the Mather set is the union of the support of minimizing measures:
Mañé proves (cf. Mañé [24, Thm. IV] also [11, p. 165]) that an invariant measure is minimizing if and only if it is supported in the Aubry set. Therefore we get the set of inclusions
(4) |
1.1 Definition.
We say that is hyperbolic if there are sub-bundles , of and such that
-
(i)
.
-
(ii)
, .
-
(iii)
, .
Hyperbolicity for autonomous lagrangian or hamiltonian flows is always understood as hyperbolicity for the flow restricted to the energy level.
Fix a Tonelli Lagrangian . Let
endowed with the topology. By [14, lemma 5.2, p. 661] the map is upper semi-continuous and is continuous [14, lemma 5.1]. This, together with the persistence of hyperbolicity (cf. [17, 5.1.8] or proposition A.1 below) imply that is an open set for any .
In [14] theorem C shows that generically is the support of a single minimizing measure. Mañé [23, theorem F] proves that this measure is a strong limit of invariant probabilities supported on periodic orbits.
Let
and let be its closure in . We will prove
Theorem A.
.
In [12] we proved that if is a periodic orbit, adding a potential which is locally of the form makes a hyperbolic periodic orbit (or hyperbolic singularity) for the Lagrangian flow of and also . Moreover [12, p. 934], has the locking property meaning that there is a neighborhood of such that for , the continuation of the periodic orbit in the energy level . This follows from the semicontinuity of and the expansivity of . Therefore defining
we get
Corollary B.
The set contains an open and dense set in .
With A. Figalli and L. Rifford in [7] we prove
Theorem C.
If then is open and dense.
Thus for surfaces in the topology we obtain Mañé’s Conjecture [24, p. 143]:
Corollary D.
If then contains an open and dense set in .
Observe that from the inclusions in (4), for potentials the lagrangian has a unique minimizing measure and it is supported on a hyperbolic periodic orbit or a hyperbolic singularity. The set is open in the topology, so we can approximate the lagrangian with a potential to obtain a periodic minimizing measure, but the approximation is only proved to be small.
Since in theorem A the Aubry set is hyperbolic, by the shadowing lemma is accumulated by periodic orbits. The idea of the proof is to choose a special periodic orbit nearby with small action and small period and prove that adding a channel centered at , defined in (96) produces that .
Theorem A is the same as the main theorem in the manuscript [10] which will remain unpublished. The proof below uses a simplification devised by Huang, Lian, Ma, Xu, Zhang [20], [21], see also Bochi [2]. The proof in [10], [9] is based in the fact that generic hyperbolic Mañé sets have zero topological entropy. The following proof is based on the periodic orbit which is used to prove zero entropy. The point is that the estimates of Bressaud and Quas [6] for the action and period of optimal periodic orbits nearby are so good that the cutting process in proposition 4.3 stops before the estimates get spoiled.
This proof owes a lot to the people working on ergodic optimization. Ergodic optimization was born as a baby version of Aubry-Mather theory adapted to symbolic dynamics [8]. Now the subject has matured enough to give the main ideas of the proof of an important conjecture in Aubry-Mather theory.
Main differences of lagrangian systems with ergodic optimization besides that the dynamical system depends on the lagrangian, are that perturbations need to be instead of Lipschitz and that the perturbations are defined in the configuration space and not in the phase space. These problems are solved by comparing the actions with static orbits and using Fathi’s differentiability estimates for weak KAM solutions, and observing that quasi minimizing objects inherit part of Mather’s graph property.
In section 3 we obtain periodic specifications in with exponentially small jumps and sub-exponential period. In section 4 proposition 4.3 we obtain periodic orbits nearby with small action compared to their self-approximations, called class I by Yuan-Hunt [31]. In section 5 we prove in proposition 5.3 that adding a channel centered in we obtain , thus proving theorem A. In symbolic dynamics this was known to Yuan-Hunt [31] but here we use the method of Quas-Siefken [29]. In appendix A we prove the refinement of the shadowing lemmas that we need.
2. Preliminars.
Let be the set of Borel probabilities in invariant under the Lagrangian flow. Denote by the set of minimizing measures for the Lagrangian , i.e.
(5) |
Their name is justified (cf. Mañé [24, Theorem II]) by
(6) |
Fathi and Siconolfi [16, Theorem 1.6] prove the second equality in (6) where the set of closed measures is defined by
Given a closed curve , using the closed measure in (6) we get
(7) |
Recall that a curve is static for a Tonelli Lagrangian if
(8) |
equivalently (cf. Mañé [24, pp. 142–143]), if is semi-static and
(9) |
The Aubry set is defined as
its elements are called static vectors. In this section we prove that with this definition is invariant.
2.1 Lemma (A priori bound).
For there exists such that if is a solution of the Euler-Lagrange equation with , then
Proof:.
The Euler-Lagrange flow preserves the energy function
(10) |
We have that
(11) |
Let
Then and
(12) |
By the superlinearity there is such that for all . Since , the mean value theorem implies that there is such that . Then (12) gives an upper bound on the energy of and (11) bounds the speed of .
∎
For and define
2.2 Corollary.
There exists such that if and is a solution of the Euler-Lagrange equation with
where , then
-
(a)
.
-
(b)
for all .
Proof:.
First suppose that . Then item (a) holds with . Let
(13) |
Since , there exists a curve joining to with . We have that
Now suppose that . Let be a minimal geodesic with joining to . Let . From the superlinearity property there is such that
Then
(14) | ||||
(15) | ||||
Hence
This implies item (a). From (14) and (15), we get that
Then Lemma 2.1 completes the proof.
∎
We say that a curve is a Tonelli minimizer if it minimizes the action functional on , i.e. if it is a minimizer with fixed endpoints and fixed time interval.
2.3 Corollary.
There is such that if and , is a Tonelli minimizer with
then there is such that , , .
Proof:.
If then for large enough . In this case Corollary 2.2 implies the result with the constant . If let be the constant curve. Since is a Tonelli minimizer, we have that
Lemma 2.1 implies that with . Now take .
∎
2.4 Lemma.
If is a static vector then , is a static curve, i.e. the Aubry set is invariant.
Proof:.
Let and suppose that is static. We have to prove that all is static. Let be a Tonelli minimizer with
By Corollary 2.3, for large enough, . We can assume that . Let . If then for some the curve is not , and hence it can not be a (Tonelli) minimizer of in . Thus
Thus there is a closed curve, from to itself, with negative action, and also negative action for some . Concatenating the curve with itself many times shows that . By (3) this implies that , which is a contradiction. Thus and similarly .
If , we can assume that exists. In this case is a semi-static periodic orbit of period and then is static.
Now suppose that . If , we have that
Thus is static for all .
∎
3. Optimal specifications.
Let be a matrix of with entries in . The subshift of finite type associated to is the set
endowed with the metric
and the shift transformation
3.1 Lemma.
Let be a shift of finite type with symbols and topological entropy . Then contains a periodic orbit of period at most .
Proof:.
Let be the period of the shortest periodic orbit in . We claim that a word of length in is determined by the set of symbols that it contains. First note that since there are no periodic orbits of period or less, any allowed -word must contain distinct symbols. Now suppose that and are two distinct words of length in containing the same symbols. Then, since the words are different, there is a consecutive pair of symbols, say and , in which occur in the opposite order (not necessarily consecutively) in . Then the infinite concatenation of the segment of starting at and ending at gives a word in of period at most , which contradicts the choice of .
It follows that there are at most words of length . Using the basic properties of topological entropy [22, 4.1.8]
Taking -th roots, we see that .
∎
From now on we assume that the Mañé set is hyperbolic. The definition of a specification or pseudo-orbit appears in A.12 in appendix A.
3.2 Proposition.
There are such that for large there is a periodic T-specification in , with jumps , and period such that
(16) | |||
(17) |
Proof:.
Given a specification in write , ; and , . We identify , , as the same specification. We will extend the definition of , to larger intervals, with the same formula, as needed.
Let and let be smaller than half of an expansivity constant A.8 for and smaller than in proposition A.7 applied to . Let be a minimal -spanning set for , i.e.
(18) |
where is the dynamic ball
and no proper subset of satisfies (18). Let be the bi-infinite subshift of finite type with symbols in and matrix defined by
(19) |
Given , let be a maximal -separated set in , i.e.
(20) |
and is a maximal subset of with property (20).
Given let be an itinerary in corresponding to , i.e.
If are different points, then by (20) there are and such that . Thus , i.e. , belong to different -cylinders in . Therefore
Since is smaller than an h-expansivity constant for , see remark A.9, its topological entropy can be calculated using -separated (or -spanning) sets, (c.f. Bowen [3] Thm. 2.4, p. 327), thus
There is with sub-exponential growth in such that . Then Lemma 3.1 gives a periodic orbit in with
(21) |
Given a sequence , define a specification in by from (22), and . From (19) we have that . Then by (23), with , and
(24) |
For the sequence in (21) we have that a periodic -possible specification with jumps, and period
(25) |
∎
4. Optimal periodic orbits.
A dominated function for is a function such that for any absolutely continuous and we have
(26) |
We say that the curve calibrates if the equality holds in (26) for every . Dominated functions always exist, for example, by the triangle inequality for Mañé’s potential , the functions are dominated for every . The definition of the Hamiltonian associated to implies that any function which satisfies
is dominated.
4.1 Lemma.
If is a dominated function and is a static curve then calibrates .
Proof:.
4.2 Lemma.
There are and such that if is a static vector, is a dominated function and , then in local coordinates
(28) |
where .
Proof:.
Let be a compact subset such that . Cover by a finite set of charts. Fix such that if has velocity then lies inside the domain of a chart in . There are smaller than the Lebesgue number of the covering and such that if and then in the charts
(29) |
Let be dominated and . Recall that . Write . By Lemma 2.4 the complete curve is static. By Lemma 4.1, calibrates . Let . Let with in a local chart. Define by
Then , , . In particular and we can apply (29).
Using that is a solution of the Euler-Lagrange equation and integrating by parts, we get that
(30) |
Since is dominated and calibrated by we obtain one of the inequalities in (28):
Now define by
A similar argument to (30) gives
Since is dominated we have that
Since is calibrated by we have that
Thus we get the remaining inequality
∎
The set is hyperbolic for the Euler-Lagrange flow restricted to the energy level . There is a neighborhood of in such that the set
(31) |
is hyperbolic, cf. [17, prop. 5.1.8]. We can assume that has no periodic orbits. The neighborhood can be taken so small that any periodic orbit in has period
(32) |
For write
4.3 Proposition.
For any there is a periodic orbit , such that
(33) |
where .
Proof:.
Let be very large which will be chosen at the end of the proof. Let , , be the periodic specification from proposition 3.2. Define by if and .
We will use repeatedly the constants from appendix A applied to the hyperbolic set from (31). We will show that if is chosen sufficiently large then the objects at each step are specifications and periodic orbits inside111Because they are (segments of) periodic orbits with small, and hence . Observe that is not necessarily locally maximal, then a priori shadowing objects could be outside . .
By the shadowing theorem A.13, there is a periodic Euler-Lagrange solution with energy and a continuous reparametrization , with such that
Then is a periodic orbit with a period near . We want a sequence of times nearby such that is a period for . Using canonical coordinates from A.3 define small by
Now let . Observe that the time shift is determined by the sequence which is periodic. Then the sequence is periodic with the period of and by proposition 3.2,
(34) |
By proposition A.7 there is such that for large enough there are such that
(35) | |||
(36) |
Let , . Since by 2.4 is invariant, we also have that .
By adding a constant to we can assume that
(37) |
On local charts we have that
Using that is an Euler-Lagrange solution we obtain
(38) |
Write . Then
(39) | ||||
From (36), for , the last term satisfies
(40) |
Let be a dominated function. By Lemma 4.2, if is a static vector then
(41) |
By Lemma 4.1, is necessarily calibrated by static curves. Then using (41),
(42) |
From (36) the last term satisfies
(43) |
Replacing estimate (42) for in inequality (4) we obtain
(44) | |||
Using (40) and (43) we have that | |||
(45) |
From (36) we get
(46) |
We can choose in (45) , so that
(47) |
Also from (35),
(48) |
If satisfies (33) then the proof finishes.
If does not satisfy (33) then there are , such that
(49) | ||||
using (37). Shifting the initial point of , we can assume that and . If for some we have that we replace by and shift the other accordingly. By Gronwall’s inequality the distance increases at most by a multiple, say . This insures that the times are all separated at least by 1. With this modification we get
(50) |
In the following iteration process we will compare distances of a periodic orbit with a time shifted periodic orbit . We will ensure in (73) that all the time shifts used are smaller than 1. We will take all the time shifts into account using Gronwall’s inequality by adding a multiple to the distance estimates. Write
(51) |
Let be the closed orbit which shadows the periodic specification . By (46), for large, and hence by (32), . Then for , using (34), we have that
(52) |
By theorem A.13, proposition A.7 and (51), there is such that
(53) | |||
(54) |
(55) |
In order to estimate the action of we need to compare it with a specification in . Write and . We cut the specification at and and remain with the periodic specification of period , and jumps in where and .
For we have that
(58) | ||||
(59) | ||||
where the omitted arguments in (58) are the same as in the previous inequality.
Using (58) we can separate the sums in (60) into two sums. The sums with terms or are about half of the terms in (44), with a shift of , plus a term for the new jump at . The total number of jumps is , then the same estimate (45) gives:
(61) |
The other sum uses terms with which are bounded in (59). Abbreviating the time shift , this sum writes
(62) |
(63) |
(64) |
where
(65) |
If satisfies (33) the proof finishes. If not there are , , such that
(66) |
We shadow the specification by a periodic orbit with
(67) | |||
Then
We need to compare with a specification in . Write and . Then
At the -th iteration we have
(72) |
Let be such that , where is from (31). This process can be repeated as long as holds and (33) is not satisfied. The resulting periodic is in and hence by (32) it has period larger than 10. Thus the process stops at an iterate where the period in (72) is larger than 1. This is
(73) |
Since by (16), has sub-exponential growth in , we have that and can be made arbitrarily small by choosing sufficiently large. Then the process stops not because is large, but because (33) holds.
∎
5. The perturbed minimizers.
The following Crossing Lemma is extracted for Mather [25] with the observation that the estimates can be taken uniformly on a neighbourhood of .
5.1 Lemma (Mather [25, p. 186]).
If , then there exist , , , and
(74) |
such that if , and are solutions of the Euler-Lagrange equation for with , , , and
then there exist curves such that , , , , and
(75) |
5.2 Lemma.
Given a Tonelli lagrangian and a compact subset , there are , and such that for any Tonelli lagrangian with , , and any :
-
(a)
If is a solution of the Euler-Lagrange equation for with and satisfies
then
(76) where .
-
(b)
If is a solution of the Euler-Lagrange equation for with and the curves satisfy , , , , and for all we have
then
Proof:
-
(a)
We use a coordinate system on a tubular neighbourhood of with a bound in the norm independent of and of . In case has self-intersections or short returns the coordinate system is an immersion.
We have that
here where depends on the second derivatives of on a small neighbourhood of the compact and hence it can be taken uniform on a neighbourhood of . Since satisfies the Euler-Lagrange equation for ,
This implies (76).
- (b)
The following proposition has its origin in Yuan and Hunt [31], the present proof uses some arguments by Quas and Siefken [29]. Proposition 5.3 together with proposition 4.3 imply theorem A.
5.3 Proposition.
Suppose that for every there is a periodic orbit such that
(77) |
where .
Then for any there is with such that , where is one of the periodic orbits in (77).
Idea of the Proof:
We choose sufficiently small and use the periodic orbit given by the hypothesis. We perturb the Lagrangian by a potential which is a non-negative channel centered at defined in (96). The curve is a periodic orbit for the flows of and of . We show that is contained in the Aubry set by proving that any semi-static curve for has
because by Mañé [24, Theorem V.(c)], -limits of semi-static orbits are static. This is done by calculating the action of each segment of the semi-static which is spent outside of a small neighbourhood of , and proving that it has a uniform positive lower bound. Since the total action of a semi-static is finite, the quantity of those segments is finite. Thus the semi-static eventually stays forever in a small neighbourhood of . The expansivity of implies that the -limit of the semi-static is .
5.4 Lemma.
If has no periodic orbits and is a sequence of periodic orbits with
Then .
Proof:.
Let be the period of . First we prove that . If not, we can extract a subsequence where and exist. Then is a periodic point in which contradicts the hypothesis.
Consider the points , , . Since , the quantity of these points tends to infinity. Therefore
∎
Proof of Proposition 5.3:
By adding a constant to we can assume that
(78) |
Fix such that
(79) |
Bernard [1] after Fathi and Siconolfi [16] proves that there is a critical subsolution of the Hamilton-Jacobi equation for , . Thus
(80) |
By Gronwall’s inequality and the continuity of Mañé’s critical value (see [14, Lemma 5.1]) there is and such that if , and is a periodic orbit for with energy smaller than then
(81) |
The graph property states that the projection has a Lipschitz inverse (see Mañé [24]). The Lipschitz constant is the same as in Mather’s Crossing Lemma 5.1. The Aubry set has energy and is continuous on . Then one can choose
(82) |
and , in Lemma 5.1 such that if then is a graph with Lipschitz constant .
By the upper semicontinuity of the Mañé set [14, lemma 5.2] we can choose a neighbourhood of and such that if then the set
is hyperbolic and contains . Take such that has uniform constants of hyperbolicity (A.7), expansivity (A.8, A.9) and canonical coordinates (A.3) for all .
Write
(83) |
We can assume that has no periodic points. By lemma 5.4, is small when is small. Given , choose and a periodic orbit satisfying (77) with and so small that for all ,
(84) | ||||
(85) | ||||
(86) | ||||
(87) |
and such that writing
(88) |
we have that
(89) |
and there is ,
(90) |
such that
(91) | |||
(92) | |||
(93) |
where is from Lemma A.4, and are from Lemma 5.1 with
(94) |
is from Proposition A.7 and is from Lemma 5.2 applied to the compact . Inequality (93) implies
(95) |
Let be a function such that and
(96) |
Using from (80) write
(97) |
The Euler-Lagrange flow of and the sets , are the same as those of . In particular the hyperbolicity constants (84)–(87) and Lipschitz graphs contants (94) remain valid for .
Claim 5.4.1:
Proof:
Let be the period of .
(1). Given , by (77) there are such that
If then
Since , by the graph property 5.1 for and (88), (74) we have that
Then
(2). Suppose by contradiction that there exists such that
(100) | |||
(101) |
First we check that we can apply the Crossing Lemma 5.1 to . Given we have that
depends only on the time interval and the endpoints of . Thus instead of in (97), it is enough to apply Lemma 5.1 to , for whom it holds if by (82).
Now we check the speed hypothesis in Lemma 5.1. Observe that
and that by (6)
Therefore
If is small enough
and then . By hypothesis in 5.3, . Therefore by (79),
Finally we check the distance hypothesis in Lemma 5.1. Let be such that . By (100) and the definition of in (85) we can apply Lemma 5.1 for and from (79), to and at and . Also note that by (101) we have that, as required in Lemma 5.1,
Using from Lemma 5.1 we obtain curves with , , , such that
Since and (78) we have that
(102) |
Using (77), and that is a closed curve we have that
We compute the action of the curve which joins to .
This contradicts the assumption that is semi-static for .
Since we can assume that has no periodic orbits, if is small enough
(103) |
Observe that is also a periodic orbit for . Let be the invariant probability supported on . Using (6), (78), (77) we have that
(104) |
We will prove that any semi-static curve for has -limit . Since -limits of semi-static orbits are static (Mañé [24, Theorem V.(c)]), this implies that . Thus finishing the proof of Proposition 5.3.
Since by (84), the number is smaller than the flow expansivity constant of , it is enough to prove that the tangent of any semi-static curve spends only a bounded time outside the -neighbourhood of .
Let be a semi-static curve for . Let and let be the lagrangian flow of . By (85) and (88) we have that
(105) |
By (98)-(99) and (92) we have that
(106) |
By (90) and (88) we have that . And then from (105) and (106) we get
(107) |
Also, from (105), (106) and (90) we have that
(108) |
Then by (108), (96), (104), (103) and (91), we have that
(109) |
For consider the local invariant manifolds
Also consider the canonical coordinates as in A.4 on , i.e. there are such that if and then there is , such that
(110) |
We use the canonical coordinates to parametrize the approaches of to in the following way. By (87), . The local weak stable manifold of
forms a cylinder homeomorphic to . When the strong local unstable manifold intersects this cylinder transversely and defines a unique time parameter (mod ) such that
(111) |
Since the family of strong invariant manifolds is invariant under each iterate we have that if for all then
Let be from Lemma A.4. Write and define , recursively by
(112) | ||||

Claim 5.4.2:
-
(1)
If then .
-
(2)
If then .
-
(3)
If then .
-
(4)
If then .
-
(5)
If the sequence is finite, then .
-
(6)
If then .
Proof:
(1). Suppose by contradiction that but . Let be the action potential (1) for . Since is Lipschitz, it is bounded on .
(113) |
Recall that is from the canonical coordinates A.3 for as in (110) and satisfies (87). Since we have that for all either
(114) |
(115) |
In the case (115) let be such that . We have that
(116) |
We apply Lemma A.4 with and . Using (155) we have that
(117) |
Observe that (116) implies that . Replacing and in (117) and using (115) we have that
(118) |
Observe that by (90) and (88), in case (114) inequality (118) also holds. Therefore
(119) |
Since is semi-static for we have for all that
(120) |
By (109) we have that . Letting , inequality (120) gives a contradiction.
Suppose first that . Then for all . By hypothesis , then . By (90), , and hence for all . By (86) and Proposition A.7 with we have that . Then and also .
Now suppose that . By the definition of for all we have that . This implies that .
(3). Let be as in (121). By the hypothesis and by the definition of , . Then . By (90), and then
(122) |
By the definition of we have that . But by (122), , and by the definition of , if then . Therefore and then
(123) |
By (122) and the definition of we have that
This implies that , with strict inequality by (122). By (123) and item (1) we have that implies that . Therefore
(124) |
The definition of and the continuity of on its domain imply that
(125) |
The domain of definition and continuity of contains . By the intermediate value theorem for on connected components of and (124), (125), (122), the image , and hence also , contain the closed interval . Therefore, by the definition of , we have that .
(4). Let , be from (121). If then by the definition of ,
(126) |
Therefore . Then the definition of implies that
(127) |
Since is continuous,
(128) |
By (127), (90) and (128) we have that
(129) |
This implies that . This together with (126) imply that
(130) |
By (127) and (130) the value is an infimum of a set which contains , therefore
(131) |
This proves the second inequality in item (4).
The first of the following inequalities follows from the definition of . The second inequality is (131). The third inequality follows from the definition of .
(132) |
We get that
From the definition of and , and then (128), we have that
In particular . Thus from (132), .
(5). If the sequence is finite, there is such that and . Let be from (121). By item (2) we have that . Then we can apply item (3) and use (90) to obtain
(133) |
Since , by item (1), and by item (4), . Since we have that for all . But by (133), . Since is continuous, using (86) we get that
This implies that there is a continuous function such that
By Proposition A.7 there is and such that
This implies that and that .
(6). By item (2), . By item (3) we have that . By the definition of we have that . Then by the continuity of , . Now it is enough to see that by item (4), .
Let
Claim 5.4.3:
Proof:
Let be as in (121). By the definition of we have that . By the definition of and (90), we have that
(134) |
By the definition of we have that
(135) |
By the definition of and the continuity of we have that
(136) |
Joining (134), (135) and (136) we get that
By the definition of this implies that .
If , by the definition of we have that
Then by (107),
(137) |
By the definition of we have that
(138) |
or (when does not exist). Here follows from (90), (88), (87). The arguments in (117)-(118) apply in the case (138) to obtain
(139) |
The continuity of and the definition of and give
(140) |
From Claim 5.4.3, {(137), (96)}, (104), {(89), (140), (81)}, {(95), (103)} and {(139), (109)}, we have that
(141) |
Recall from (97) that
where is from (80). Observe that the lagrangian flow for is the same as the lagrangian flow for . Also and . Using (80) and (141),
(142) |
Case 1: Suppose that .
Let be such that
Then . Let . Then . By Claim 5.4.2.(6), is -shadowed by . Therefore by inequality (180) in Proposition A.7 there is such that
(143) |
Also the choice of in Proposition A.7 is the same as in (111) so that
(144) |

By the definition of and in (112) and the continuity of on its domain we have that
(145) |
By (143), (144) and (145) we have for that
From (144) we have that
So that . Adding the inequalities above we get
(146) |
In local coordinates about define
By Lemma 5.2(b) and (146) we have that
Since the pairs of segments and have the same collections of endpoints
Therefore, since is constant,
(147) |
The integral of on closed curves is zero. Therefore
(148) |
Since is a closed curve and , using (7),
(149) |
(150) |
Since , using (103), on the curve we have that
(151) |
From (147), (149) and (151) we get that
Case 2: If , from (150) we also have
Adding inequality (142) and using (93) we obtain a positive lower bound for the action independent of :
Since is semi-static for , and then also for , and by (148) , the total action is finite:
Therefore there must be at most finitely many ’s.
By item (5) in claim 5.4.2, we have that -limit. Since -limits of semi-static orbits are static (Mañé [24, theorem V.(c)]), we obtain that . This finishes the proof of proposition 5.3.
∎
Appendix A Shadowing
Let be the flow of a vector field on a compact manifold . A compact -invariant subset is hyperbolic for if the tangent bundle restricted to is decomposed as the Whitney sum , where is the 1-dimensional vector bundle tangent to the flow and there are constants such that
-
(a)
, for all .
-
(b)
for all , .
-
(c)
for all , .
It follows from the definition that the hyperbolic splittig over is continuous.
From now on we shall assume that does not contain fixed points for . For define the following stable and unstable sets:
(152) | ||||
Let be the Banach manifold of the vector fields on , . Let be the vector field of . For denote by the flow of .
A.1 Proposition.
Proposition A.1 can be proven by a characterization of hyperbolicity using cones (cf. Hasselblatt-Katok [18, Proposition 17.4.4]) and obtaining uniform contraction (expansion) for a fixed iterate in . See Fisher-Hasselblatt [17] prop. 5.1.8 p. 256].
A.2.
There are constants such that, for small ,
-
(a)
when , , .
-
(b)
when , , .
There are for which the following is true: If and then there is a unique with such that
(153) |
This set consists of a single point, which we denote . The maps and are continuous on the set .
A.4 Lemma.
There are , , and open sets , such that
if ,
, and then
(154) | |||
(155) |
Proof:.
We have that and . By uniform continuity, given , for small enough
(156) |
and is so small that
(157) |
The continuity of the hyperbolic splitting implies that the angles , and are bounded away from zero, uniformly on , for some and all in an open set with . There is such that if and then
The strong local invariant manifolds , are tangent to , at and for a fixed as submanifolds they vary continuously on the base point and on the vector field in the topology (cf. [15, Thm. 4.3],[19, Thm. 4.1]). There is a family of small cones , defined on a neighborhood of invariant under and respectively, for in a neighborhood of . The exponential of these cones contain and for and . The angles between these cones are uniformly bounded away from zero, so for example if , and , are small, then for some . We can construct similiar cones separating from .
Shrinking and if necessary there are and such that if , and , taking and such that , i.e. , then
(158) | ||||
(159) | ||||
We can assume that and are so small that the constants , , in Proposition A.2 can be taken uniform for all and in . By Proposition A.2, since , we have that
Take . Then if and we obtain that .
Since we have that
Thus if then .
By (156) and (157) there is such that if then , and are small enough to satisfy the above inequalities. Now let
∎
A.5 Proposition.
There are open sets and and , such that
if is the flow of , and continuous with satisfy
(160) |
then
(161) |
(162) |
also
(163) |
In particular
Proof:.
Let with from A.4. We may assume that is so small that
(164) | |||
(165) |
Let
(166) |
where and are from lemma A.4. Consider , and as in the hypothesis. Since we have that . Using lemma A.4 we can define
(167) |
we also have
(168) |
Define the sets
Since is continuous, and , we have that . Using (165) twice with , (169) and the triangle inequality we obtain
Hence . From (167), , and then
(170) |
Since , using (165) twice with , and (170) with , and the triangle inequality, we get
Hence . We have shown that
(171) |
Since and by (160),
(172) |
equation (171) implies that
By Lemma A.4, (172) and (166),
(173) | |||
(174) |
Since , from (165), (174) and (164), we get that
From (173) and (168) we have that
These statements contradict . Hence .
Similarly one shows that . Since , inequality (175) holds for all . From (167), and by (164), ; thus inequality (175) also holds for .
(175) |
Therefore
(176) |
From Proposition A.2 we get
Similarly, imples that
(177) |
Adding these inequalities we obtain
(178) |
This proves inequality (162).
From (168), . The fact also gives for . This proves (161). From (176), (177) and (178) we get inequality (163).
∎
A.6 Proposition.
Let , and be from Proposition A.5. Given
-
(a)
If and continuous with satisfy
then for all and there is such that .
-
(b)
Similarly, if , is continuous with and
then for all and there is such that .
Proof:.
We only prove item (a). The same proof as in Proposition A.5 shows that taking
we have that and
Therefore for all and . Since we get that .
∎
A.7 Proposition.
There are , and open sets , , such that
if , is the flow of , and continuous with satisfy
(179) |
then for all and there is such that
Moreover for all ,
(180) |
and is determined by
Proof:.
Let , , and be from Proposition A.5. The continuity of the hyperbolic splitting implies that the angle is bounded away from zero. As in the argument after (157), there are invariant families of cones separating from whose image under the exponential map contain the local invariant manifolds , . And hence as in (158) there are such that if , and
then
(181) |
Suppose that and , , , , satisfy (179). Apply Proposition A.5 with .
Then , and
if is small enough. So that is well defined. Similarly and . Since the time map preserves the family of strong invariant manifolds, in equation (162) we have that
Therefore, using (181),
(182) | ||||
for some , because by Proposition A.5, , and , so that
A similar estimate holds for and hence from (182),
Replacing this in (162) we have that
where .
∎
A.8 Definition.
We say that is flow expansive if for every there is such that if , and there is continuous with and for all , then for some .
A.9 Remark.
Observe that Proposition A.5 implies uniform expansivity in a neighbourhood of , namely there are neighbourhoods and such that for every there is such that if , , continuous and , ; then for some . See also Fisher-Hasselblatt [17, cor. 5.3.5].
This also implies uniform h-expansivity of their time-one maps as in Definition A.11.
A.10 Definition.
Let be a homeomorphism. For and define
We say that is entropy expansive or h-expansive if there is such that
Such an is called an h-expansive constant for .
A.11 Definition.
Let be a topological subspace of and compact. We say that is uniformly h-expansive on if there is such that
In our applications will be a neighbourhood of a diffeomorphism endowed with the topology. An h-expansive homeomorphism corresponds to .
A.12 Definition.
Let , we say that is an -specification if
-
(a)
.
-
(b)
and .
We say that the specification is -possible if
A.13 Theorem.
Given there are and such that if and is a -possible -specification on then there exist and continuous, piecewise linear, strictly increasing with and such that
(183) |
Moreover, if the specification is periodic then is a periodic point for .
Theorem A.13 does not need that the hyperbolic set is locally maximal, but if not the point is not in . In Fisher-Hasselbaltt [17] the shadowing theorem A.13 is proved without a local maximality assumption and with the Lipschitz estimate (183) and a homeomorphism such that has Lipschitz constant . But then proposition A.7 above proves the bound and moreover, that can be taken constant on each interval .
Theorem A.13 is proved in Bowen [4] (2.2) p. 6 with constant on each and without the estimate . A proof of theorem A.13 for flows without the local maximality hypothesis and with the explicit estimate appears in Palmer [26] theorem 9.3, p. 188. In [26], [27] the theorem requires an upper bound on the lengths of the intervals in . This is because there the theorem is proven also for perturbations of the flow. Indeed by Proposition A.7 longer intervals in improve the estimate.
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