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Reducing spheres of genus-2 Heegaard splitting of S3S^{3}

Sreekrishna Palaparthia , Swapnendu Pandab
Abstract

The Goeritz group of the standard genus-g Heegaard splitting of the three sphere, GgG_{g}, acts on the space of isotopy classes of reducing spheres for this Heegaard splitting. Scharlemann [7] uses this action to prove that G2G_{2} is finitely generated. In this article, we give an algorithm to construct any reducing sphere from a standard reducing sphere for a genus-2 Heegaard splitting of the S3S^{3}. Using this we give an alternate proof of the finite generation of G2G_{2} assuming the finite generation of the stabilizer of the standard reducing sphere.

aSreekrishna Palaparthi, Department of Mathematics, Indian Institute of Technology Guwahati, Assam 781039, India, email : passkrishna@iitg.ac.in
b
Swapnendu Panda, Department of Mathematics, Indian Institute of Technology Guwahati, Assam 781039, India, email : p.swapnendu@iitg.ac.in

Keywords : Goeritz Group, Automorphisms of three sphere, Heegaard splittings, Reducing sphere, Mapping class groups.
Mathematics Subject Classification : 57M60, 20F38, 57K30

Acknowledgements: We are thankful to the Department of Mathematics, Indian Institute of Technology Guwahati for its support while carrying out this work. A part of this work intersects with the thesis work of the second author.

1 Introduction

The genus-gg Goeritz group of S3S^{3}, denoted GgG_{g}, is the group of isotopy classes of homeomorphisms of S3S^{3} which preserve a genus-gg Heegaard surface of S3S^{3}. By a theorem of Waldhausen [9], every Heegaard splitting of S3S^{3} of genus greater than 11 is stabilized. So the group GgG_{g} can be taken to be the group of isotopy classes of homeomorphisms of S3S^{3} which preserve the standard genus-gg Heegaard splitting of S3S^{3}. Scharlemann [7] proved that the genus-2 Goeritz group, G2G_{2}, of S3S^{3} is finitely generated by four generators. He did so by considering a certain simplicial complex whose vertices are the isotopy classes of reducing spheres of the standard genus-22 Heegaard splitting of S3S^{3}. Akbas [1] used Scharlemann’s complex to give a finite presentation for G2G_{2}. Cho [2] independently used a certain disk complex to give a finite presentation for G2G_{2}. For g3g\geq 3, Zupan [10] generalized Scharlemann’s work and defined a reducing sphere complex for genus-gg Heegaard splittings of S3S^{3} and showed that the group GgG_{g} is finitely generated if and only if this complex is connected. Freedman and Scharlemann [4] proved that G3G_{3} is also finitely generated. They conjectured that the five generators mentioned in Powell [5] generate GgG_{g} for all g3g\geq 3. Much is unknown about GgG_{g} for g4g\geq 4.

The literature on the Goeritz group of S3S^{3} shows the importance of describing an arbitrary reducing sphere for reducible Heegaard splittings of S3S^{3}, and for reducible Heegaard splittings of 3-manifolds in general. In this article, we look at the set of all the reducing spheres for the genus-2 Heegaard splitting of S3S^{3}. We give structure theorems for such spheres. We then give an algorithm to construct any reducing sphere for the standard genus-2 Heegaard splitting of S3S^{3}, upto isotopy, from the standard reducing sphere.

The layout of this article is as follows. In section 2, we prove Theorem 2.2 which gives some intersection conditions satisfied by the curve of intersection of a reducing sphere with the standard genus-2 Heegaard surface of S3S^{3}. In section 3, we use the fundamental group of a genus-2 handlebody to deduce some conditions which apply to the arcs of intersection of a reducing sphere with a certain component pair of pants of the genus-2 Heegaard surface of S3S^{3}. We then use these conditions to prove Theorem 3.6 for such arcs of a reducing sphere. In section 4, we prove Theorem 4.1 which is a key tool to de-construct a given reducing sphere. In section 5, we give an algorithm to de-construct and transform any reducing sphere into the standard reducing sphere. Using this algorithm and assuming that the stabilizer of the standard reducing sphere of the genus-2 Heegaard splitting of S3S^{3} is finitely generated, we show that the Goeritz group G2G_{2} is finitely generated.

2 Reducing Curves - Intersection Numbers

For preliminaries regarding Heegaard splittings of 3-manifolds, one can consult [6] and for preliminaries on mapping class groups and simple closed curves on surfaces, one can consult Farb and Margalit [3]. We start by considering the standard genus-2 Heegaard splitting of S3S^{3}, written S3=VΣWS^{3}=V\cup_{{\Sigma}}W and denoted by {\mathcal{H}}, where both VV and WW are unknotted genus-2 handlebodies embedded in S3S^{3} with disjoint interiors glued along their common boundary Σ{\Sigma}. The Heegaard surface, Σ{\Sigma}, of the above splitting is a closed orientable surface of genus two embedded in S3S^{3}. Since {\mathcal{H}} is stabilized, one can find a reducing sphere for {\mathcal{H}} i.e. a sphere which intersects each of VV and WW in an embedded disk with a common boundary circle on Σ{\Sigma}. Such a reducing sphere intersects Σ{\Sigma} in an essential separating simple closed curve, which we call a reducing curve for Σ{\Sigma}. A reducing curve on Σ{\Sigma} uniquely determines a reducing sphere, upto isotopy in S3S^{3}. Two reducing spheres of {\mathcal{H}} are said to be isotopic with respect to {\mathcal{H}}, if any of their isotopy in S3S^{3} restricts to an isotopy of the corresponding reducing curves on the surface Σ{\Sigma}. Likewise, if two reducing curves for Σ{\Sigma} are isotopic on Σ{\Sigma}, this isotopy can be extended to an isotopy of the corresponding reducing spheres with respect to {\mathcal{H}}. This allows one to study reducing curves on Σ{\Sigma} in order to study reducing spheres of {\mathcal{H}}.

The Heegaard splitting {\mathcal{H}} of S3S^{3} admits the following four automorphisms, as described in Scharlemann [7], which preserve the structure of {\mathcal{H}}. The automorphisms α\alpha and γ\gamma are the automorphisms of S3S^{3} induced by the π\pi-rotations of Σ{\Sigma} about the axes indicated in Figures 1(a) and 1(c). The automorphism β\beta is the half twist of the Σ{\Sigma} about the central separating curve as indicated in Figure 1(b).

Refer to caption
(a) Automorphism α\alpha
Refer to caption
(b) Automorphism β\beta
Refer to caption
(c) Automorphism γ\gamma
Refer to caption
(d) Automorphism δ\delta
Figure 1: The generators of the genus-2 Goeritz group of S3S^{3}

The automorphism δ\delta is of order three which can be described as follows. Consider a graph on the unit sphere in 3\mathbb{R}^{3} whose vertices are the north and the south pole and whose edges are three distinct half meridians on the sphere connecting the north pole and the south pole such that the rotation of the sphere by an angle 2π3\frac{2\pi}{3} about the axis connecting the north and south pole permutes the three edges cyclically. If VV^{\prime} is a regular neighborhood in S3S^{3} of this graph such that VV^{\prime} is homeomorphic to the handlebody VV, then δ\delta is the order three automorphism which cyclically permutes the 1-handles of VV^{\prime} by rotation by an angle 2π3\frac{2\pi}{3} as shown in Figure 1(d).

Figure 2 shows an embedding of the Heegaard surface Σ{\Sigma} of {\mathcal{H}} in 3\mathbb{R}^{3}. PP is the reducing sphere whose reducing curve, PΣP_{\Sigma}, is shown in Figure 2. We call PP as the standard reducing sphere. Consider the non-separating curves A,B,C,X,Y,ZA,B,C,X,Y,Z on Σ{\Sigma} as shown in Figure 2.

Refer to caption
Figure 2: The standard set of curves on Σ\Sigma

ABCA\cup B\cup C separates Σ{\Sigma} into two thrice boundered spheres, call them Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}}. We will refer to the curves in Figure 2 throughout this article.

Any reducing sphere QQ of {\mathcal{H}} intersects Σ{\Sigma} in the corresponding reducing curve, which we denote by QΣQ_{{\Sigma}}. Such a QΣ{Q_{{\Sigma}}} is an essential separating simple closed curve on Σ{\Sigma} which separates Σ{\Sigma} into two surfaces, each of which is a surface of genus 11 with one boundary component. Since QΣ{Q_{{\Sigma}}} cannot be null-homotopic on Σ\Sigma, QΣ{Q_{{\Sigma}}} will intersect both Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}} and will also intersect at least one of A,BA,B or CC. For any QQ, we assume that QΣ{Q_{{\Sigma}}} intersects A,B,C,X,YA,B,C,X,Y and ZZ minimally and transversally (refer to Figure 2). QΣΣ1{Q_{{\Sigma}}}\cap{\Sigma_{1}} or QΣΣ2{Q_{{\Sigma}}}\cap{\Sigma_{2}} is a collection of simple essential arcs on the thrice boundered spheres Σ1{\Sigma_{1}} or Σ2{\Sigma_{2}}, respectively. For D,E{A,B,C}D,E\in\{A,B,C\}, an arc of type DEDE, or a DEDE arc, for short, on Σ1{\Sigma_{1}} (or on Σ2{\Sigma_{2}}) is a connected arc of QΣ{Q_{{\Sigma}}} which is contained in Σ1{\Sigma_{1}} (or in Σ2{\Sigma_{2}}) and which has its end-points on the curves DD and EE. So there are six possible types of arcs of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} or Σ2{\Sigma_{2}} namely an AAAA arc, a BBBB arc, a CCCC arc, an ABAB arc, an ACAC arc and a BCBC arc. Some arc types intersect the others. So a reducing curve, QΣ{Q_{{\Sigma}}}, cannot have intersecting arc types.

Table 1 shows arc types which necessarily intersect and hence cannot be components of the same reducing curve on Σ1{\Sigma_{1}} and likewise on Σ2{\Sigma_{2}}:

AAAA ABAB ACAC BBBB BCBC CCCC
AAAA X X X
ABAB X
ACAC X
BBBB X X X
BCBC X
CCCC X X X
Table 1: X indicates arc types necessarily intersect

For an arbitrary reducing sphere QQ, the number of arcs of QΣΣ1{Q_{{\Sigma}}}\cap{\Sigma_{1}} and of QΣΣ2{Q_{{\Sigma}}}\cap{\Sigma_{2}} have to be equal, as a mismatch will leave an open end which is impossible for a closed curve. For D,E{A,B,C}D,E\in\{A,B,C\}, let |DE|Q,1|DE|_{Q,1} and |DE|Q,2|DE|_{Q,2} denote the number of arcs of QΣ{Q_{{\Sigma}}} of type DEDE on Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}}, respectively. For instance, |AB|Q,1|AB|_{Q,1} denotes the number of arcs of QΣ{Q_{{\Sigma}}} of type ABAB on Σ1{\Sigma_{1}} and |BB|Q,2|BB|_{Q,2} denotes the number of BBBB arcs of QΣ{Q_{{\Sigma}}} on Σ2{\Sigma_{2}}. When the context is clear, we will drop QQ in the subscript. For instance, we will just use |BB|2|BB|_{2}, instead of |BB|Q,2|BB|_{Q,2}. We define aQ:=|QΣA|,bQ:=|QΣB|a_{Q}:=|{Q_{{\Sigma}}}\cdot A|,b_{Q}:=|{Q_{{\Sigma}}}\cdot B| and cQ:=|QΣC|c_{Q}:=|{Q_{{\Sigma}}}\cdot C|. Since QΣ{Q_{{\Sigma}}} is a separating curve, aQ,bQa_{Q},b_{Q} and cQc_{Q} are non-negative even numbers.

The four automorphisms of {\mathcal{H}} described above, namely, α,β,γ\alpha,\beta,\gamma and δ\delta affect the numbers aQ,bQa_{Q},b_{Q} and cQc_{Q} of a reducing sphere QQ of {\mathcal{H}} as follows:

  1. 1.

    δ\delta cyclically permutes aQ,bQa_{Q},b_{Q} and cQc_{Q},

  2. 2.

    γ\gamma permutes bQb_{Q} and cQc_{Q} and keeps aQa_{Q} unchanged,

  3. 3.

    α\alpha keeps aQ,bQa_{Q},b_{Q} and cQc_{Q} unchanged and

  4. 4.

    β\beta or its inverse increase or decrease aQa_{Q}, while keeping bQb_{Q} and cQc_{Q} unchanged.

Table 2 lists the contribution of each arc type to aQa_{Q}, bQb_{Q} and cQc_{Q}.

Type of arc Each arc’s contribution to
 aQa_{Q}  bQb_{Q}  cQc_{Q}
AAAA +2 0 0
ABAB +1 +1 0
ACAC +1 0 +1
BBBB 0 +2 0
BCBC 0 +1 +1
CCCC 0 0 +2
Table 2: Contribution of each type of arc to aQ,bQa_{Q},b_{Q} and cQc_{Q}
Lemma 2.1.

For any reducing sphere QQ, let l,ml,m and nn denote any distinct non-negative integers in the set {aQ,bQ,cQ}\{a_{Q},b_{Q},c_{Q}\}. Then lm+nl\neq m+n.

Proof.

By the order three symmetry of {\mathcal{H}}, it suffices to prove the statement for l=aQ,m=bQl=a_{Q},m=b_{Q} and n=cQn=c_{Q}. If QQ is isotopic to PP with respect to {\mathcal{H}}, i.e. QΣ{Q_{{\Sigma}}} is isotopic to PΣP_{{\Sigma}} on Σ{\Sigma} then aQ=2a_{Q}=2, bQ+cQ=0b_{Q}+c_{Q}=0 and the lemma holds.
Now suppose QΣ{Q_{{\Sigma}}} is not isotopic to PΣP_{{\Sigma}}. Using Table 2 for QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} we have, aQ=2|AA|1+|AB|1+|AC|1a_{Q}=2|AA|_{1}+|AB|_{1}+|AC|_{1}, bQ=|AB|1+2|BB|1+|BC|1b_{Q}=|AB|_{1}+2|BB|_{1}+|BC|_{1} and cQ=|AC|1+|BC|1+2|CC|1c_{Q}=|AC|_{1}+|BC|_{1}+2|CC|_{1}. If aQ=bQ+cQa_{Q}=b_{Q}+c_{Q} then |AA|1=|BB|1+|CC|1+|BC|1|AA|_{1}=|BB|_{1}+|CC|_{1}+|BC|_{1}. So if one of |BB|1,|CC|1|BB|_{1},|CC|_{1} or |BC|1|BC|_{1} is non-zero, then |AA|10|AA|_{1}\neq 0 and vice versa which means that QΣ{Q_{{\Sigma}}} has an AAAA arc along with one of BBBB, BCBC or CCCC arc which is impossible by table 1. We can also arrive at this contradiction by counting arcs on Σ2{\Sigma_{2}} instead of Σ1{\Sigma_{1}}. Therefore, we should have |AA|i=|BB|i=|CC|i=|BC|i=0|AA|_{i}=|BB|_{i}=|CC|_{i}=|BC|_{i}=0 for i=1,2i=1,2.

Therefore, for aQa_{Q} to be equal to bQ+cQb_{Q}+c_{Q}, QΣ{Q_{{\Sigma}}} can only have ABAB and ACAC type arcs on both Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}}. But, if these are the only type of arcs of QΣ{Q_{{\Sigma}}}, then following QΣ{Q_{{\Sigma}}} starting on any point of QΣA{Q_{{\Sigma}}}\cap A, an ABAB arc should be followed by a BABA arc and an ACAC arc should be followed by a CACA arc and so QΣ{Q_{{\Sigma}}} will intersect AA in only one orientation. Hence the absolute value of the algebraic intersection number of QΣ{Q_{{\Sigma}}} with AA, BB or CC will be non-zero, contradicting the fact that QΣ{Q_{{\Sigma}}} is a separating curve on Σ{\Sigma}. This shows that aQbQ+cQa_{Q}\neq b_{Q}+c_{Q}. ∎

Theorem 2.2.

For any reducing sphere QQ for {\mathcal{H}}, we have:

  1. (i)

    aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} if and only if QΣ{Q_{{\Sigma}}} contains at least one AAAA arc on each of Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}}.

  2. (ii)

    bQ>cQ+aQb_{Q}>c_{Q}+a_{Q} if and only if QΣ{Q_{{\Sigma}}} contains at least one BBBB arc on each of Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}},

  3. (iii)

    cQ>aQ+bQc_{Q}>a_{Q}+b_{Q} if and only if QΣ{Q_{{\Sigma}}} contains at least one CCCC arc on each of Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}}.

Furthermore, exactly one of the above three holds for QQ.

Proof.

By the order three symmetry of {\mathcal{H}}, it suffices to prove statement (i). The other two statements follow. Let i=1i=1 or i=2i=2 for this proof. As in the proof of Lemma 2.1, aQ=2|AA|i+|AB|i+|AC|ia_{Q}=2|AA|_{i}+|AB|_{i}+|AC|_{i}, bQ=|AB|i+2|BB|i+|BC|ib_{Q}=|AB|_{i}+2|BB|_{i}+|BC|_{i} and cQ=|AC|i+|BC|i+2|CC|ic_{Q}=|AC|_{i}+|BC|_{i}+2|CC|_{i}. So, aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} implies |AA|i>|BB|i+|CC|i+|BC|i|AA|_{i}>|BB|_{i}+|CC|_{i}+|BC|_{i}. The strict inequality implies that |AA|i1|AA|_{i}\geq 1. Thus aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} implies QΣ{Q_{{\Sigma}}} has an AAAA arc on both Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}}.

Conversely, suppose QΣ{Q_{{\Sigma}}} has an AAAA arc on Σi{\Sigma}_{i}. Then, |AA|i0|AA|_{i}\neq 0 and using Table 1, QΣ{Q_{{\Sigma}}} cannot simultaneously have any of BB,CCBB,CC or BCBC arcs on Σi{\Sigma}_{i}. This implies |BB|i=|BC|i=|CC|i=0|BB|_{i}=|BC|_{i}=|CC|_{i}=0. Then,

bQ+cQ=|AB|i+|AC|i<2|AA|i+|AB|i+|AC|i=aQb_{Q}+c_{Q}=|AB|_{i}+|AC|_{i}<2|AA|_{i}+|AB|_{i}+|AC|_{i}=a_{Q}

This proves statement (i) of the lemma.

Now we show that exactly one of the three inequalities hold for any QQ. For that, we consider the complement of the case aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} and show that bQ>cQ+aQb_{Q}>c_{Q}+a_{Q} or cQ>aQ+bQc_{Q}>a_{Q}+b_{Q} must hold. By Lemma 2.1 aQbQ+cQa_{Q}\neq b_{Q}+c_{Q}. So the complement of aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} is when aQ<bQ+cQa_{Q}<b_{Q}+c_{Q}. If aQ<bQ+cQa_{Q}<b_{Q}+c_{Q}, by lemma 2.2, QΣ{Q_{{\Sigma}}} cannot have any AAAA arc on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}}. By the work of Volodin et al. [8], since QΣ{Q_{{\Sigma}}} bounds a disk in the handlebody VV, QΣ{Q_{{\Sigma}}} must have a ‘wave’ on V\partial V with respect to YY or ZZ (also refer [1]). In other words, QΣ{Q_{{\Sigma}}} must either have a YBYYBY arc (see figure 3(a)) disjoint from XZX\cup Z or a ZCZZCZ arc disjoint from XYX\cup Y. Likewise, since QΣ{Q_{{\Sigma}}} must also bound a disk in WW, cQc_{Q} must also have a ‘wave’ on W\partial W with respect to BB or CC i.e. a BYBBYB arc disjoint from XZX\cup Z or a CZCCZC arc disjoint from XYX\cup Y respectively. The ‘wave’ on W\partial W with respect to BB when viewed on V\partial V, is a BBBB arc on V\partial V, since there are no AAAA type arcs on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}}. The ‘wave’ on W\partial W with respect to BB is shown in figure 3(b), 3(c) and 3(d) respectively.

Refer to caption
(a) Wave on V\partial V with respect to YY
Refer to caption
(b) Wave on W\partial W with respect to BB
Refer to caption
(c) Wave on V\partial V with respect to BB
Refer to caption
(d) Wave w.r.t. BB after isotopy
Figure 3: Wave of QΣ{Q_{{\Sigma}}} w.r.t. YY and BB

Similarly, the ‘wave’ on W\partial W with respect to CC when viewed on V\partial V, is a CCCC arc on V\partial V since there are no AAAA arcs on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}}.

Therefore, when aQ<bQ+cQa_{Q}<b_{Q}+c_{Q}, by an isotopy, we can assume that QΣ{Q_{{\Sigma}}} has a BBBB or a CCCC arc on one of Σ1{\Sigma_{1}} or Σ2{\Sigma_{2}}. Without loss of generality let us assume that this wave is on Σ1{\Sigma_{1}}. By Table 1, QΣ{Q_{{\Sigma}}} can have only one of BBBB or CCCC arc types on Σ1{\Sigma_{1}}.

First suppose that QΣ{Q_{{\Sigma}}} has a BBBB arc on Σ1{\Sigma_{1}}. In this case, by Table 1 QΣ{Q_{{\Sigma}}} cannot have AAAA, CCCC or ACAC arcs on Σ1{\Sigma_{1}}. Then, since, |BB|1>0|BB|_{1}>0,

bQ=2|BB|1+|BC|1+|AB|1>|BC|1+|AB|1=cQ+aQ.b_{Q}=2|BB|_{1}+|BC|_{1}+|AB|_{1}>|BC|_{1}+|AB|_{1}=c_{Q}+a_{Q}.

Likewise if QΣ{Q_{{\Sigma}}} has a CCCC arc on Σ1{\Sigma_{1}} then by Table 1 QΣ{Q_{{\Sigma}}} cannot have AAAA, BBBB or ABAB arcs on Σ1{\Sigma_{1}}. Then, since, |CC|1>0|CC|_{1}>0,

cQ=2|CC|1+|BC|1+|AC|1>|BC|1+|AC|1=bQ+aQ.c_{Q}=2|CC|_{1}+|BC|_{1}+|AC|_{1}>|BC|_{1}+|AC|_{1}=b_{Q}+a_{Q}.

Remark 2.3.

We note that by the work of Volodin et al. [8], when the inequality aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} holds, there is a ‘wave’ on W\partial W with respect to AA, which when viewed on V\partial V is an AAAA type arc which either surrounds BB on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} or surrounds CC on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}}. Such an arc is shown in Figure 4.

Refer to caption
(a) AZXA arc
Refer to caption
(b) AYXA arc
Figure 4: A wave on W\partial W w.r.t. AA viewed on V\partial V

The proof of Theorem 2.2 also shows the following:

Corollary 2.4.

(i) If a reducing sphere QQ satisfies aQ>bQ+cQa_{Q}>b_{Q}+c_{Q}, then QQ contains only AA,ABAA,AB and ACAC type arcs on Σ1{\Sigma_{1}} and on Σ2{\Sigma_{2}}.
(ii) If a reducing sphere QQ satisfies bQ>aQ+cQb_{Q}>a_{Q}+c_{Q}, then QQ contains only BB,ABBB,AB and BCBC type arcs on Σ1{\Sigma_{1}} and on Σ2{\Sigma_{2}}.
(iii) If a reducing sphere QQ satisfies cQ>bQ+aQc_{Q}>b_{Q}+a_{Q}, then QQ contains only CC,ACCC,AC and BCBC type arcs on Σ1{\Sigma_{1}} and on Σ2{\Sigma_{2}}.
In any of the above three cases, the number of arcs of any type are equal on Σ1{\Sigma_{1}} and on Σ2{\Sigma_{2}}.

3 Arcs of a reducing curve

We assume the setup of the previous section. By Theorem 2.2, and by invoking the order three symmetry, δ\delta, of {\mathcal{H}}, in order to describe an arbitrary reducing sphere, QQ, of {\mathcal{H}}, it is enough to describe a reducing sphere in the case aQ>bQ+cQa_{Q}>b_{Q}+c_{Q}. Also, by Theorem 2.2, the inequality aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} implies the existence of an AAAA arc on Σ1{\Sigma_{1}} and an AAAA arc on Σ2{\Sigma_{2}}. Further, by Remark 2.3, there must be an AAAA arc on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} which is as shown in Figure 4.

So, throughout this section, we assume that a reducing sphere QQ satisfies the inequality aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} and describe how the AAAA, ABAB and ACAC arcs of the corresponding reducing curve QΣ{Q_{{\Sigma}}} can be presented on Σ1{\Sigma_{1}} and on Σ2{\Sigma_{2}}.

Refer to caption
Figure 5: Setup of Σ{\Sigma} with zz coordinate as height

Let the two distinct arcs of AA each of which has one end-point on YY and another end-point on ZZ be denoted by A1A_{1} and A2A_{2}.

We can arrange the standard embedded genus-2 surface, V\partial V, in 3\mathbb{R}^{3} such that: (i) AA is the intersection of the yzy-z plane with Σ{\Sigma} (ii) the points YAY\cap A and ZAZ\cap A lie along the zz-axis with the zz-coordinate of points on AA increasing from YAY\cap A to ZAZ\cap A, (iii) no two points of A1A_{1} or no two points of A2A_{2} have the same zz-coordinate. We will refer to this arrangement throughout this section. With this arrangement the zz-coordinate can be thought of as a height function on A1A_{1} and likewise on A2A_{2}. See Figure 5. Owing to this observation, if x1,x2A1x_{1},x_{2}\in A_{1} and if the height of x1x_{1} is greater than the height of x2x_{2}, then we say x1x_{1} is above x2x_{2} or that x2x_{2} is below x1x_{1}. If x3A1x_{3}\in A_{1} such that the height of x3x_{3} is between the heights of x1x_{1} and x2x_{2} then we say that x3x_{3} is in between x1x_{1} and x2x_{2}.

By an isotopy of QΣ{Q_{{\Sigma}}}, we can assume that it does not intersect the points ZA,ZB,YAZ\cap A,Z\cap B,Y\cap A or YCY\cap C. Since |QΣA||{Q_{{\Sigma}}}\cap A| is finite, there are only finitely many AAAA arcs on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}}. These arcs are essential on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} as inessential arcs on a thrice boundered sphere are boundary reducible and a boundary reducing disk gives an isotopy of QΣ{Q_{{\Sigma}}} reducing the intersection number of QΣ{Q_{{\Sigma}}} with AA. Also these AAAA arcs do not intersect each other as QΣ{Q_{{\Sigma}}} is a simple curve. Since every essential arc on a thrice-boundered sphere from a boundary component to itself is separating, these AAAA arcs are separating arcs of Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}}.

The curve QΣ{Q_{{\Sigma}}} is a finite collection of 2n2n arcs on Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}} for some natural number nn. Fix an orientation of QΣ{Q_{{\Sigma}}} and number these arcs sequentially as ρ1,ρ2,,ρ2n\rho_{1},\rho_{2},\ldots,\rho_{2n} following the orientation of QΣ{Q_{{\Sigma}}} such that ρiρjABC\rho_{i}\cap\rho_{j}\in A\cup B\cup C if and only if i,j{1,2,,2n}i,j\in\{1,2,...,2n\} and ij±1mod 2ni-j\equiv\pm 1\;\textrm{mod}\;2n. Without loss of generality we assume that for each kk\in{\mathbb{N}}, ρ2k1\rho_{2k-1} is on Σ1{\Sigma_{1}} and ρ2k\rho_{2k} is on Σ2{\Sigma_{2}}.

Lemma 3.1.

For i=1,2i=1,2, an AAAA arc of QΣ{Q_{{\Sigma}}} on Σi{\Sigma}_{i} intersects XΣiX\cap{\Sigma}_{i} exactly once.

Proof.

Let X1:=XΣ1X_{1}:=X\cap{\Sigma_{1}} Cut Σ1{\Sigma_{1}} along X1X_{1} to get an annulus SS, which has two boundary components. One boundary component is the curve AA and the other boundary component is a union of BB and CC with two copies of X1X_{1}. For brevity, we denote these two boundary components of SS by AS\partial_{A}S and XS\partial_{X}S respectively.

If an AAAA arc does not intersect X1X_{1}, then it is an arc in the annulus SS with both its endpoints on the same boundary component of SS and hence is boundary-reducible. The boundary-reducing disk is a bigon as the AAAA arc intersects AA only at its endpoints. Then by the bigon criterion, we have an isotopy of QΣ{Q_{{\Sigma}}} reducing its intersection with AA contradicting the minimal intersection position of QΣ{Q_{{\Sigma}}} with AA. So an AAAA arc on Σ1{\Sigma_{1}} has to intersect X1X_{1} at least once.

Suppose now that an AAAA arc, call it λ\lambda, intersects X1X_{1} more than once. Orient λ\lambda from one end point on AA to another and let x1,x2,,xnx_{1},x_{2},...,x_{n} be the points of intersection of λ\lambda with X1X_{1} listed in order when following the orientation of λ\lambda. SS cuts λ\lambda into its component arcs on SS. All such component arcs on the annulus SS run from XS\partial_{X}S to itself and hence are boundary reducible. Two boundary-reducing disks of such component arcs of λ\lambda are either disjoint or one is contained in the other, otherwise λ\lambda will have self-intersections. Hence by following a chain of containment of these boundary reducing disks, we can get an innermost disk EE which does not contain any other disk. We will now show that EE is a bigon on the surface Σ{\Sigma} formed by λ\lambda and X1X_{1}.

Let EE be the boundary reducing disk for an arc λ1\lambda_{1} on SS which is a component arc of λ\lambda on SS. Let λ1\lambda_{1} considered on Σ1{\Sigma_{1}} join xix_{i} to xjx_{j}. EE on SS is bounded by λ1\lambda_{1} and a portion, call it ρ\rho, of the boundary component XS\partial_{X}S of SS. If ρ\rho includes BB or CC or both, then following the arc λ\lambda, in the orientation of λ\lambda or in the opposite orientation, beyond λ1\lambda_{1}, we arrive at yet another component arc of λ\lambda, call it λ2\lambda_{2}, on SS which enters EE. See Figure 6.

Refer to caption
Figure 6: Any AAAA arc intersects XX exactly once

Since λ2\lambda_{2} enters EE, it is completely contained in EE. This is because, λ2\lambda_{2} cannot intersect λ1\lambda_{1}, BB or CC, so it has to intersect X1X_{1} which then means that λ2\lambda_{2} is contained in EE. Now, as remarked earlier, λ2\lambda_{2} is also boundary reducible and the boundary reduction disk of λ2\lambda_{2} to the boundary XS\partial_{X}S is completely contained inside EE, contradicting the assumption that EE is the innermost disk. This proves that ρ\rho cannot include BB or CC or both.

This implies that ρ\rho contains only an arc from X1X_{1}. So λ1\lambda_{1} along with ρ\rho forms a bigon on the surface Σ{\Sigma}. So by the bigon criterion there is an isotopy of QΣ{Q_{{\Sigma}}} reducing the intersection with X1X_{1}. So if QΣ{Q_{{\Sigma}}} is in minimal intersection position with XX, then an AAAA arc on Σ1{\Sigma_{1}} cannot intersect XX more than once.

Hence, we conclude that any AAAA arc of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} intersects X1X_{1} in exactly one point.

Likewise, we can repeat the same argument for an AAAA arc on Σ2{\Sigma_{2}} and conclude that such an arc intersects XΣ2X\cap{\Sigma_{2}} in exactly one point. ∎

We now use the fundamental group of the handlebody VV to get more information about the AAAA, ABAB and ACAC arcs of QΣ{Q_{{\Sigma}}} when aQ>bQ+cQa_{Q}>b_{Q}+c_{Q}. In particular we will show that an AAAA arc of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} can wind around the circles BB or CC at most once.

Let DX,DYD_{X},D_{Y} and DZD_{Z} be the essential disks in VV bounded by the curves X,YX,Y and ZZ respectively. Consider the core curves of the handlebody VV, dual to the disks DZD_{Z} and DYD_{Y}, based at a point x0x_{0} lying in the interior of DXD_{X} and denote them by Bx0B_{x_{0}} and Cx0C_{x_{0}} respectively. Note that Bx0B_{x_{0}} and Cx0C_{x_{0}} are freely isotopic in VV to BB and CC respectively. The element in π1(V,x0)\pi_{1}(V,x_{0}) whose representative is a loop which traces Bx0B_{x_{0}} once in the direction shown in Figure 7 will be denoted by bb and the element which traces Cx0C_{x_{0}} once in the direction shown in Figure 7 will be denoted by cc.

Refer to caption
Figure 7: Handlebody VV: core curves and dual disks

We consider the presentation b,c|\langle b,c|-\rangle of the fundamental group of VV based at x0x_{0} and henceforth refer to this presentation simply as π1(V)\pi_{1}(V). With a slight abuse of notation, we use the same letters to indicate the elements in π1(V)\pi_{1}(V) and the loops in VV. By this abuse of notation the loop Bx0B_{x_{0}} in Figure 7 is also denoted by bb, for instance.

Now, let QQ be a reducing sphere which is in minimal position with the curves A,B,C,X,YA,B,C,X,Y and ZZ and which satisfies aQ>bQ+cQa_{Q}>b_{Q}+c_{Q}. Consider some orientation of QΣ{Q_{{\Sigma}}} and view it as a union of oriented arcs ρ1,ρ2,,ρ2n\rho_{1},\rho_{2},\ldots,\rho_{2n} as mentioned earlier, where the orientation on ρi\rho_{i}, 1i2n1\leq i\leq 2n, is the one induced from the orientation of QΣ{Q_{{\Sigma}}}. Let ii denote an integer in the set {1,2,,2n}\{1,2,...,2n\} throughout the following discussion with addition and subtraction performed modulo 2n2n when indices are added or subtracted. Each ρi\rho_{i} is an AAAA, ABAB or an ACAC arc with a starting point indicated by its orientation. Since ρi\rho_{i} is an oriented arc we would distinguish between an ACAC arc and a CACA arc, and likewise between an ABAB and a BABA arc depending upon the orientation of ρi\rho_{i}. Let δi\delta_{i} be an arc contained in the interior of VV oriented from x0x_{0} to the starting point of ρi\rho_{i} such that δi\delta_{i} does not intersect DYD_{Y} or DZD_{Z}. By δi¯\overline{\delta_{i}}, we mean δi\delta_{i} with the reversed orientation. Now, σi:=δiρiδi+1¯\sigma_{i}:=\delta_{i}\cdot\rho_{i}\cdot\overline{\delta_{i+1}} is a loop in VV based at x0x_{0}. This loop, σi\sigma_{i}, represents a word in the in the generators bb and cc in π1(V)\pi_{1}(V), which we call the word of ρi\rho_{i}.

Also, QΣ{Q_{{\Sigma}}} is freely homotopic to the product loop i=12nσi\prod_{i=1}^{2n}\sigma_{i} and correspondingly represents a product word in the generators bb and cc in π1(V)\pi_{1}(V). Since QΣ{Q_{{\Sigma}}} bounds a disk in VV, the corresponding reduced word must be cyclically trivial. This last requirement imposes restrictions on the arcs ρi\rho_{i}’s which we discuss in the following.

The union of curves ABCXYZA\cup B\cup C\cup X\cup Y\cup Z divides Σ{\Sigma} into four disks, which we call the component hexagons of Σ{\Sigma}, owing to the fact that the boundary of each of these disks contain exactly one arc each of the six curves A,B,C,X,YA,B,C,X,Y and ZZ. In this context, an arc of ρi\rho_{i} on a component hexagon of Σ{\Sigma} is of the type DEDE if it starts on the curve DD and ends on the curve EE in the orientation of ρi\rho_{i}, where D,E{A,B,C,X,Y,Z}D,E\in\{A,B,C,X,Y,Z\}. A sub-arc of ρi\rho_{i} is called its initial-arc if it is completely contained in one of the component hexagons of Σ{\Sigma} and is of the type DEDE where D{A,B,C}D\in\{A,B,C\} and E{X,Y,Z,A,B,C}E\in\{X,Y,Z,A,B,C\}. Similarly, a sub-arc of ρi\rho_{i} is called its terminal-arc if it is completely contained in one of the component hexagons of Σ{\Sigma} and is of the type DEDE where D{X,Y,Z,A,B,C}D\in\{X,Y,Z,A,B,C\} and E{A,B,C}E\in\{A,B,C\}. Note that neither the terminal nor the initial arc of ρi\rho_{i} of type DEDE can have D=ED=E.

Lemma 3.2.

Consider any two component hexagons D1D_{1} and D2D_{2} of Σ{\Sigma} both of which have a side A1A_{1} in common or both of which have a side A2A_{2} in common. If D1D_{1} intersects QΣ{Q_{{\Sigma}}} in an AZAZ or a ZAZA arc, then D2D_{2} cannot intersect QΣ{Q_{{\Sigma}}} in an AZAZ or a ZAZA arc. Likewise, both D1D_{1} and D2D_{2} cannot simultaneously intersect QΣ{Q_{{\Sigma}}} in a YAYA or an AYAY arc.

Proof.
Refer to caption
(a) tt and rr coincide
Refer to caption
(b) tt is below rr
Refer to caption
(c) tt is above rr
Figure 8: A Z-A-Z bigon

Let χ\chi be an arc of QΣ{Q_{{\Sigma}}} in D1D_{1} with one endpoint on ZZ and the other on A1A_{1}. Let t:=χA1t:=\chi\cap A_{1}. If possible let ζ\zeta be an arc on D2D_{2} with end-points on ZZ and A1A_{1} and r:=ζA1r:=\zeta\cap A_{1}. If t=rt=r, then χ\chi and ζ\zeta bound a bigon with ZZ on Σ{\Sigma} contradicting the minimal intersection position of QΣ{Q_{{\Sigma}}} with ZZ. If tt is below rr on A1A_{1}, then the continuation arc of ζ\zeta on D1D_{1} is contained in the disk cut out of D1D_{1} by χ\chi, ZZ and A1A_{1} and hence is another arc ζ1\zeta_{1} with one endpoint as rr and the other on ZZ. But then, ζ\zeta and ζ1\zeta_{1} bound a bigon with ZZ on Σ{\Sigma}, once again contradicting the minimal intersection position of QΣ{Q_{{\Sigma}}} with ZZ. If rr is below tt, then the continuation arc of χ\chi on D2D_{2} and χ\chi together bound a bigon with ZZ leading us to a similar contradiction. See Figure 8.

So rr cannot be above or below tt on A1A_{1} nor can it coincide with tt and hence ζ\zeta does not exist. The proof for the case where χ\chi is an arc of QΣ{Q_{{\Sigma}}} in D1D_{1} with one endpoint on YY and the other on A1A_{1} is similar. ∎

Corollary 3.3.

When the word of a ρi\rho_{i} which is an AAAA, BABA or a CACA arc of QΣ{Q_{{\Sigma}}} is concatenated with word of ρi+1\rho_{i+1}, which is an AAAA, ABAB or an ACAC arc the concatenated word cannot have trivial relators of π1(V)\pi_{1}(V).

Proof.

This is so because a trivial relator at the word interface contradicts Lemma 3.2.

Suppose that ρi\rho_{i} is an AAAA, BABA or a CACA arc on Σ1{\Sigma_{1}} whose word ends with a letter b1b^{-1}, and that ρi+1\rho_{i+1} is an AAAA, ABAB or an ACAC arc on Σ2{\Sigma_{2}} whose word starts with a letter bb. See Figure 8(a). The terminal-arc of ρi\rho_{i} on Σ1{\Sigma_{1}} is a ZAZA arc and the initial-arc of ρi+1\rho_{i+1} on Σ2{\Sigma_{2}} is an AZAZ arc, contradicting Lemma 3.2.

Similarly, if ρi\rho_{i} is an arc on Σ1{\Sigma_{1}} with a word which ends with any letter xx, where x{b,b1,c,c1}x\in\{b,b^{-1},c,c^{-1}\} and the word of ρi+1\rho_{i+1} begins with x1x^{-1} then QΣ{Q_{{\Sigma}}} forms a bigon with YY or ZZ on Σ{\Sigma} and this will lead to a contradiction with the minimal position of QΣ{Q_{{\Sigma}}} with YY and ZZ. Since the roles of Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}} can be reversed in the above argument, the corollary is proved. ∎

Corollary 3.4.

If the word of a ρi\rho_{i}, which is an ABAB arc (on Σ1{\Sigma_{1}} or Σ2{\Sigma_{2}}), ends in bb or b1b^{-1} then the word of ρi+1\rho_{i+1}, which has to be a BABA arc (on Σ2{\Sigma_{2}} or Σ1{\Sigma_{1}}, respectively) cannot start with b1b^{-1} or bb, respectively. Similarly, if the word of a ρi\rho_{i}, which is an ACAC arc (on Σ1{\Sigma_{1}} or Σ2{\Sigma_{2}}), ends in cc or c1c^{-1} then the word of ρi+1\rho_{i+1} which has to be a CACA arc (on Σ2{\Sigma_{2}} or Σ1{\Sigma_{1}}, respectively) cannot start with c1c^{-1} or cc, respectively.

Proof.

As in the proof of Corollary 3.3 if ρi\rho_{i} is an ABAB arc on Σ1{\Sigma_{1}} (or on Σ2{\Sigma_{2}}) whose word ends with a letter bb or b1b^{-1}, then ρi+1\rho_{i+1} will be a BABA arc on Σ2{\Sigma_{2}} (or on Σ1{\Sigma_{1}}), and its word cannot begin with b1b^{-1} or bb respectively, because if it does, then the terminal-arc of ρi\rho_{i} and the initial-arc of ρi+1\rho_{i+1} form a bigon with ZZ on Σ{\Sigma} leading to a contradiction with the assumption that QΣ{Q_{{\Sigma}}} is in minimal position with ZZ. See Figure 9.

Refer to caption
Figure 9: AB,BAAB,BA concatenation cannot have trivial relators

Similarly, if ρi\rho_{i} is an ACAC arc on either Σ1{\Sigma_{1}} (or Σ2{\Sigma_{2}}), whose word ends with a letter cc or c1c^{-1}, then ρi+1\rho_{i+1} will be a CACA arc on Σ2{\Sigma_{2}} (or Σ1{\Sigma_{1}}), and its word cannot begin with c1c^{-1} or cc respectively, because if it does, then the terminal-arc of ρi\rho_{i} and the initial-arc of ρi+1\rho_{i+1} form a bigon with YY leading to a contradiction with the assumption that QΣ{Q_{{\Sigma}}} is in minimal position with YY. ∎

Lemma 3.5.

A concatenated word of a sequence ρi1,ρi\rho_{i-1},\rho_{i} and ρi+1\rho_{i+1} of arcs of QΣ{Q_{{\Sigma}}} where ρi\rho_{i} is an ABAB arc cannot contain the trivial relators bb1bb^{-1} or b1bb^{-1}b. Similarly, a concatenated word of a sequence ρi1,ρi\rho_{i-1},\rho_{i} and ρi+1\rho_{i+1} of arcs of QΣ{Q_{{\Sigma}}} where ρi\rho_{i} is an ACAC arc cannot contain the trivial relators cc1cc^{-1} or c1cc^{-1}c.

Proof.

Corollary 3.3 implies that a trivial relator bb1bb^{-1} or b1bb^{-1}b cannot occur when the word of ρi1\rho_{i-1} is concatenated with the word of a ρi\rho_{i} when ρi1\rho_{i-1} is an AA,BAAA,BA or a CACA arc and ρi\rho_{i} is an ABAB arc. Corollary 3.4 implies that a trivial relator bb1bb^{-1} or b1bb^{-1}b cannot occur when the word of ρi\rho_{i} is concatenated with the word of a ρi+1\rho_{i+1} when ρi\rho_{i} is an ABAB arc and ρi+1\rho_{i+1} is a BABA arc. So we need to prove that when ρi\rho_{i} is an ABAB arc whose word is empty word, {}\{\}, the concatenated words of ρi1,ρi\rho_{i-1},\rho_{i} and ρi+1\rho_{i+1} arc sequence cannot be of the form w1b{}b1w2w_{1}b\{\}b^{-1}w_{2} or of the form w1b1{}bw2w_{1}b^{-1}\{\}bw_{2} where w1w_{1} and w2w_{2} are some words in b,b1,cb,b^{-1},c and c1c^{-1}. But if this happens, then as in the proof of Corollary 3.4, the terminal arc of the ρi1\rho_{i-1}, the whole of ρi\rho_{i} and the initial-arc of ρi+1\rho_{i+1} form a bigon with ZZ as shown in figure 10.

Refer to caption
Figure 10: Concatenation of A,AB,BA*A,AB,BA arcs bounds bigon on Σ{\Sigma} with ZZ

This contradicts the assumption that QΣ{Q_{{\Sigma}}} is in minimal position with ZZ. This proves the first statement of the lemma. The proof of the second statement of this lemma is similar. ∎

Now, we describe the words of AA,AB,BA,ACAA,AB,BA,AC and CACA arcs. For j=1,2j=1,2, let Xj=XΣj,Yj=YΣjX_{j}=X\cap{\Sigma}_{j},Y_{j}=Y\cap{\Sigma}_{j} and Zj=ZΣjZ_{j}=Z\cap{\Sigma}_{j}.

We will first describe the words of AAAA arcs on Σ1{\Sigma_{1}}. The same argument applies to words of AAAA arcs on Σ2{\Sigma_{2}}. An AAAA arc on Σ1{\Sigma_{1}} can be described completely upto isotopy by a sequence of arc types in the component hexagons of Σ1{\Sigma_{1}} because these hexagons are disks. Further, it is possible to give an exhaustive description of these arc sequences owing to the conditions on an AAAA arc imposed by Lemma 3.1. Let mm be a non-negative integer, ϵ1,ϵ2{0,1}\epsilon_{1},\epsilon_{2}\in\{0,1\} and kk be any integer for the following discussion.

Table 3 gives all possible arc sequences of an AAAA arc on Σ1{\Sigma_{1}} which starts on AjA_{j} and ends on AjA_{j^{\prime}}, where j,j{1,2}j,j^{\prime}\in\{1,2\}, and gives its corresponding word in π1(V)\pi_{1}(V). Note that the arc types alternate on the two component hexagons of Σ1{\Sigma_{1}}. The first, third, etc. arc-types are on the component hexagon which has A1A_{1} as an edge and the second, fourth etc. arc-types are on the component hexagon which has A2A_{2} as an edge.

Start End Arc-type sequence and Word
A1A_{1} A2A_{2} AX,XAAX,XA
empty
A1A_{1} A2A_{2} AZ,(ZY,YZ)m,ZX,XY,(YZ,ZY)m,YAAZ,(ZY,YZ)^{m},ZX,XY,(YZ,ZY)^{m},YA
b(cb)m(c1b1)mc1b(cb)^{m}(c^{-1}b^{-1})^{m}c^{-1}
A1A_{1} A2A_{2} AZ,(ZY,YZ)m,ZY,YX,XZ,(ZY,YZ)m,ZAAZ,(ZY,YZ)^{m},ZY,YX,XZ,(ZY,YZ)^{m},ZA
b(cb)mcb1(c1b1)mc1b(cb)^{m}cb^{-1}(c^{-1}b^{-1})^{m}c^{-1}
A1A_{1} A2A_{2} AY,(YZ,ZY)m,YX,XZ,(ZY,YZ)m,ZAAY,(YZ,ZY)^{m},YX,XZ,(ZY,YZ)^{m},ZA
c1(b1c1)m(bc)mbc^{-1}(b^{-1}c^{-1})^{m}(bc)^{m}b
A1A_{1} A2A_{2} AY,(YZ,ZY)m,YZ,ZX,XY,(YZ,ZY)m,YAAY,(YZ,ZY)^{m},YZ,ZX,XY,(YZ,ZY)^{m},YA
c1(b1c1)mb1c(bc)mbc^{-1}(b^{-1}c^{-1})^{m}b^{-1}c(bc)^{m}b
Table 3: Arc-type sequences and Words in π1(V)\pi_{1}(V)

Figure 11 shows these arc sequences for a sample.

Refer to caption
(a) A1A1A_{1}A_{1} arc
Refer to caption
(b) A1A2A_{1}A_{2} arc
Refer to caption
(c) A1A1A_{1}A_{1} arc
Figure 11: Arcs for AAAA words

Using this technique, we summarize the reduced word forms in π1(V)\pi_{1}(V) of various arc-types as follows. Let ww represent some reduced word in π1(V)\pi_{1}(V). An AAAA arc of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} starting on A1A_{1} and ending on A2A_{2} has words with three possible reduced forms, viz: empty, bwc1bwc^{-1}, c1wbc^{-1}wb. An AAAA arc starting on A2A_{2} and ending on A1A_{1} has words with three possible reduced forms, viz: empty, cwb1cwb^{-1}, b1wcb^{-1}wc. An AAAA arc starting on A1A_{1} and ending on A1A_{1} has words with the following possible reduced forms: bb, b1b^{-1}, cc, c1c^{-1}, bwb1bwb^{-1}, c1wcc^{-1}wc. An AAAA arc starting on A2A_{2} and ending on A2A_{2} has words with following possible reduced forms: bb, b1b^{-1}, cc, c1c^{-1}, cwc1cwc^{-1}, b1wbb^{-1}wb. The AB,BA,ACAB,BA,AC and CACA arcs of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} have reduced word forms based on the word form of its AAAA arc, which necessarily exists when aQ>bQ+cQa_{Q}>b_{Q}+c_{Q}. Depending on the beginning letter of the word described by an AAAA arc, an ABAB arc starting on A1A_{1} describes a reduced word of the following forms: bkb^{k}, bwcbkbwcb^{k}, c1bkc^{-1}b^{k} or c1wc1bkc^{-1}wc^{-1}b^{k}. Depending on the beginning letter of the word described by an AAAA arc, an ABAB arc starting on A2A_{2} describes a reduced word of the following forms: bkb^{k}, cbkcb^{k}, cwcbkcwcb^{k}, b1wc1bkb^{-1}wc^{-1}b^{k}. Likewise, an ACAC arc starting on A1A_{1} describes a reduced word of the following forms: ckc^{k}, bckbc^{k}, bwbckbwbc^{k}, c1wb1ckc^{-1}wb^{-1}c^{k}. An ACAC arc starting on A2A_{2} describes a reduced word of the following forms: ckc^{k}, cwbckcwbc^{k}, b1ckb^{-1}c^{k}, b1wb1ckb^{-1}wb^{-1}c^{k}. The word forms of a BABA arc are the inverses of the word forms of an ABAB arc and the word forms of a CACA arc are the inverses of the word forms of an ACAC arc of the corresponding kind.

Since QΣ{Q_{{\Sigma}}} represents the conjugacy class of the trivial reduced word, the following Theorem shows that the variable word ww in the word-form summary, presented above, has to be trivial.

Theorem 3.6.

The word in π1(V)\pi_{1}(V) of an AAAA arc of QΣ{Q_{{\Sigma}}} can have a length at most 22. Correspondingly, the word of an AB,BA,ACAB,BA,AC or CACA arc of QΣ{Q_{{\Sigma}}} can have a word of the form wbkwb^{k} and wckwc^{k} respectively, for some integer kk, where ww can have a length at most 11.

Proof.

When we concatenate the words of the arcs ρi\rho_{i} of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}} from i=1i=1 to i=2ni=2n, then the words should reduce to an empty word. Since the words described by various arcs, as summarized above are already in their reduced form, at least one trivial relator, a relator of the form xx1xx^{-1}, where xx could be any of b,c,b1,c1b,c,b^{-1},c^{-1}, has to occur at the join of some ρi\rho_{i} and ρi+1\rho_{i+1}. Referring to the summary of word-forms of arcs, if the word ww in the word of an arc which is of the form xwyxwy is non-trivial, where x,y{b,c,b1,c1}x,y\in\{b,c,b^{-1},c^{-1}\} then a trivial relator does not arise when words of arcs which form the word of QΣ{Q_{{\Sigma}}} are concatenated, leaving us with a conclusion that QΣ{Q_{{\Sigma}}} cannot have arcs with non-trivial words ww.

Now consider an arc ρi\rho_{i} of QΣ{Q_{{\Sigma}}}. Suppose that ρi\rho_{i} is a BABA or a CACA arc, whose word is of any of the types described above where ww is not the empty word.

  • Case 1:

    ρi+1\rho_{i+1} and ρi+2\rho_{i+2} is an AB,BAAB,BA or an AC,CAAC,CA arc combination. Suppose first that ρi+1\rho_{i+1} is an ABAB arc and ρi+2\rho_{i+2} is a BABA arc. In this case, by Corollary 3.3 and Lemma 3.5, for any trivial relator to arise, if at all it does, when words in π1(V)\pi_{1}(V) are concatenated, the words of both ρi+1\rho_{i+1} and ρi+2\rho_{i+2} must be empty. But this is impossible as both ρi+2\rho_{i+2} and ρi\rho_{i} are on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} and ρi+2\rho_{i+2} is a BABA arc which cannot describe an empty word when ww is not the empty word. So no trivial relator arises when concatenating the words of ρi,ρi+1\rho_{i},\rho_{i+1} and ρi+2\rho_{i+2}. A similar argument shows that no trivial relator arises when concatenating the words of ρi,ρi+1\rho_{i},\rho_{i+1} and ρi+2\rho_{i+2} when ρi+1,ρi+2\rho_{i+1},\rho_{i+2} is an AC,CAAC,CA arc combination.

  • Case 2:

    ρi+1\rho_{i+1} is an AAAA arc. Even in this case, by Corollary 3.3, there cannot be a trivial relator when the words of ρi\rho_{i} and ρi+1\rho_{i+1} are concatenated. However, the word of ρi+1\rho_{i+1} could be empty, in which case it should be an arc from A1A_{1} to A2A_{2} or an arc from A2A_{2} to A1A_{1}.

    1. Subcase 1:

      ρi\rho_{i} ends on A2A_{2}: In this sub-case, the word of ρi\rho_{i} ends with bb or c1c^{-1}. Here we refer to the summary of words of arcs. So if the word of ρi+1\rho_{i+1} is empty it must be an arc from A2A_{2} to A1A_{1}, and so ρi+2\rho_{i+2} has to start on A1A_{1} and hence has a word starting with either bb or c1c^{-1}. As a result there is no trivial relator while concatenating these three words.

    2. Subcase 2:

      ρi\rho_{i} ends on A1A_{1}: In this sub-case, the word of ρi\rho_{i} ends with b1b^{-1} or cc. So if the word of ρi+1\rho_{i+1} is empty it must be an arc from A1A_{1} to A2A_{2}, and so ρi+2\rho_{i+2} has to start on A2A_{2} and hence has a word starting with either b1b^{-1} or cc. As a result there is no trivial relator while concatenating these three words.

If ρi\rho_{i} is an ABAB or an ACAC arc whose word is of any of the types described above where ww is not the empty word, then the corresponding AB,BAAB,BA arc combination or an AC,CAAC,CA arc combination can never be the empty word by Corollary 3.4.

The arcs ρi\rho_{i} for i=1i=1 to i=2ni=2n of QΣ{Q_{{\Sigma}}} are a sequence of AAAA arcs, AB,BAAB,BA arc combinations and AC,CAAC,CA arc combinations. When the corresponding words in π1(V)\pi_{1}(V) are concatenated by following the order of ρi\rho_{i}’s, at-least one of these pieces gives a non-trivial reduced word when ww is not the empty word and none of the concatenation results in a trivial relator. This shows that the word described by QΣ{Q_{{\Sigma}}} cannot be the empty word resulting in a contradiction to the assumption that QΣ{Q_{{\Sigma}}} bounds a disk in VV. This shows that the word of any AAAA arc on Σ1{\Sigma_{1}} or Σ2{\Sigma_{2}} can only be of the form xwyxwy with an empty ww and where x,y{b,c,b1,c1,{}}x,y\in\{b,c,b^{-1},c^{-1},\{\}\}. Hence the words of AAAA arc on Σ1{\Sigma_{1}} or Σ2{\Sigma_{2}} can contain at most two letters. Correspondingly, we infer from the summary of arcs above that the word of an ABAB or of an ACAC arc of QΣ{Q_{{\Sigma}}} is of the form wbkwb^{k} and wckwc^{k} respectively, for some integer kk, where ww can have a length at most 11. ∎

Remark 3.7.

An AAAA arc with empty word on Σ1{\Sigma_{1}} (or on Σ2{\Sigma_{2}}) will intersect an AAAA arc with two-letter word on Σ1{\Sigma_{1}} (or on Σ2{\Sigma_{2}}). So QΣ{Q_{{\Sigma}}} cannot contain two AAAA arcs on Σ1{\Sigma_{1}} (or on Σ2{\Sigma_{2}}), one with an empty word and another with a two-letter word.

Remark 3.8.

By the word forms arrived at, preceding the Theorem 3.6, we can further refine the words of AB,BA,ACAB,BA,AC and CACA arcs based on whether their AA-end is on A1A_{1} or A2A_{2} as follows.

  • An ABAB arc which starts on A1A_{1} can only have a word of the form bkb^{k} or c1bkc^{-1}b^{k} and correspondingly a BABA arc which ends on A1A_{1} can only have the inverse words bkb^{k} or bkcb^{k}c.

  • An ABAB arc which starts on A2A_{2} can only have a word of the form bkb^{k}, cbkcb^{k} and correspondingly a BABA arc which ends on A2A_{2} can only have the inverse words bkb^{k} or bkc1b^{k}c^{-1}.

  • An ACAC arc which starts on A1A_{1} can only have a word of the form ckc^{k}, bckbc^{k} and correspondingly a CACA arc which ends on A1A_{1} can only have the inverse words ckc^{k} or ckb1c^{k}b^{-1}.

  • An ACAC arc which starts on A2A_{2} can only have a word of the form ckc^{k}, b1ckb^{-1}c^{k} and correspondingly a CACA arc which ends on A2A_{2} can only have the inverse words ckc^{k} or ckbc^{k}b.

When aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} for a reducing sphere QQ, the following proposition gives one more condition which applies to word lengths of AAAA arcs.

Proposition 3.9.

Suppose that aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} and that QΣ{Q_{{\Sigma}}} has no AAAA arc on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} describing a single letter word in π1(V)\pi_{1}(V). Then Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}}, cannot simultaneously contain AAAA arcs each of which describe a two letter word in π1(V)\pi_{1}(V).

Proof.

Assume that QΣ{Q_{{\Sigma}}} has no AAAA arc on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} describing a single letter word in π1(V)\pi_{1}(V) and assume to the contrary that both Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}} contain an AAAA arc which describe a two letter word in π1(V)\pi_{1}(V). Without loss of generality, assume that Σ1{\Sigma_{1}} contains an AAAA arc with end points on A1A_{1} and A2A_{2} which describes the word bc1bc^{-1} in the orientation of QΣ{Q_{{\Sigma}}}. In this case Σ2{\Sigma_{2}} cannot contain an AAAA arc describing the same word bc1bc^{-1} or the inverse word cb1cb^{-1} owing to Lemma 3.2. So, the AAAA arc on Σ2{\Sigma_{2}} will have to describe the word b1cb^{-1}c or the word c1bc^{-1}b depending on whether it starts on A2A_{2} or A1A_{1}, respectively. We will now show that even this cannot occur. For the purpose of this argument, we note that an ABAB arc of Σ{\Sigma} has to continue as a BABA arc. So we tie up such AB,BAAB,BA arc combinations and call them ABAABA arcs. We concatenate the words described by the ABAB and the BABA arcs involved and call the concatenated and reduced word in π1(V)\pi_{1}(V) as the word of the ABAABA arc. Likewise we tie up AC,CAAC,CA arc combinations and call them ACAACA arcs. We likewise define the words of ACAACA arcs. Now, QΣ{Q_{{\Sigma}}} can be seen as a sequence of AAAA, ABAABA and ACAACA arcs. Further, the concatenation of the words described by these arcs should reduce to the empty word. Now, we gather the possible words described by these arcs when they are traced from AiA_{i} to AjA_{j} for i,j{1,2}i,j\in\{1,2\} in Table 4.

In this table 4 an arc starts on A1A_{1}^{\prime} means that an arc starts on A1A_{1} and on Σ1{\Sigma_{1}}, whereas an arc starts on A1′′A_{1}^{\prime\prime} means that it starts on A1A_{1} and on Σ2{\Sigma_{2}}. An arc ends on A1A_{1}^{\prime} means that the arc ends on A1A_{1} and on Σ1{\Sigma_{1}} whereas it ends on A1′′A_{1}^{\prime\prime} means that the arc ends on A1A_{1} and on Σ2{\Sigma_{2}}.

Ends on \longrightarrow A1A_{1}^{\prime} A1′′A_{1}^{\prime\prime} A2A_{2}^{\prime} A2′′A_{2}^{\prime\prime}
Starts on \downarrow
A1A_{1}^{\prime} c,bc,b,bcc,bc,b,bc bc1bc^{-1} ϕ,b\phi,b
A1′′A_{1}^{\prime\prime} c1,b1,c1b1c^{-1},b^{-1},c^{-1}b^{-1} ϕ,c1\phi,c^{-1} c1bc^{-1}b
A2A_{2}^{\prime} cb1cb^{-1} ϕ,c\phi,c c,b,cbc,b,cb
A2′′A_{2}^{\prime\prime} ϕ,b1\phi,b^{-1} b1cb^{-1}c c1,b1c1,b1c^{-1},b^{-1}c^{-1},b^{-1}
Table 4: Words described by the AA,ABAAA,ABA, and ACAACA arcs traced from AiA_{i} to AjA_{j}, i,j{1,2}i,j\in\{1,2\}

Figure 12(a) shows the possible arcs on Σ1{\Sigma_{1}} along with the AAAA arc whose word is bc1bc^{-1}. Figure 12(b) shows the possible arcs on Σ2{\Sigma_{2}} along with the AAAA arc whose word is b1cb^{-1}c or c1bc^{-1}b depending on how it is traced.

Refer to caption
(a) When AAAA describes bc1bc^{-1}
Refer to caption
(b) When AAAA describes b1cb^{-1}c
Figure 12: Possible arcs on Σ1\Sigma_{1} with two-lettered AAAA arcs

Let κ1\kappa_{1} be the AAAA arc of QΣ{Q_{{\Sigma}}} whose word is bc1bc^{-1}. Starting at κ1\kappa_{1} and following the orientation of κ1\kappa_{1}, we list the AAAA, ABAABA and ACAACA arcs of QΣ{Q_{{\Sigma}}} as κi\kappa_{i}’s 1ip1\leq i\leq p for some positive integer pp. The end point of κp\kappa_{p} is the starting point of κ1\kappa_{1}. We first define w1w_{1} to be the word of κ1\kappa_{1}. At the ithi^{th} step, for 1ip11\leq i\leq p-1, we define wi+1w_{i+1} to be the reduced word corresponding to concatenation of wiw_{i} with the word of κi+1\kappa_{i+1}. By induction on ii, we show that the length of wiw_{i}, written |wi||w_{i}|, is always more than one. Since wpw_{p} represents the word of QΣ{Q_{{\Sigma}}} and wpw_{p} should have length zero, we have a contradiction. Initially |w1|=|bc1|2|w_{1}|=|bc^{-1}|\geq 2. κ1\kappa_{1} ends on A2A_{2}. So κ2\kappa_{2} has its initial arc on Σ2{\Sigma_{2}} and has the possible words from the row against A2′′A_{2}^{\prime\prime} in Table 4. Note that none of the words start with cc. So the concatenation of w1w_{1} with the word of κ2\kappa_{2} is already reduced and |w2||w1|2|w_{2}|\geq|w_{1}|\geq 2. This can be taken as the base case. Now suppose that, for some integer k,1kp1k,1\leq k\leq p-1, the reduced word wkw_{k} is formed and |wl|2|w_{l}|\geq 2 for all l,1lkl,1\leq l\leq k. The arc κk\kappa_{k} ends on any of A1,A1′′,A2A_{1}^{\prime},A_{1}^{\prime\prime},A_{2}^{\prime} or A2′′A_{2}^{\prime\prime} and so the κk+1\kappa_{k+1} will start on A1′′,A1,A2′′A_{1}^{\prime\prime},A_{1}^{\prime},A_{2}^{\prime\prime} or A2A_{2}^{\prime} respectively. In the above table, for any of these combinations, we notice that there is no reduction upon concatenation of the words, except possibly when the word of κk\kappa_{k} is empty. So, except possibly in the case that the word of κk\kappa_{k} is empty, |wk+1|2|w_{k+1}|\geq 2. Let us now consider the remaining case when the word of κk\kappa_{k} is empty and suppose that κk+1\kappa_{k+1} starts on A1A_{1}^{\prime}. Then κk\kappa_{k} should have ended on A1′′A_{1}^{\prime\prime}. From the Table 4, there is only one possibility for an arc describing the empty word and ending on A1′′A_{1}^{\prime\prime}, namely an ACAACA arc which starts on A2A_{2}^{\prime}, which in turn means that the κk1\kappa_{k-1} must have ended on A2′′A_{2}^{\prime\prime}. For all arcs ending on A2′′A_{2}^{\prime\prime} we notice that the ending letter of such arcs is bb or cc, unless it is the empty word. So the possible words for κk1\kappa_{k-1}, when κk\kappa_{k} has an empty word, have no reduction when concatenated with the word of κk+1\kappa_{k+1}, unless the word of κk1\kappa_{k-1} is trivial. So unless the κk1\kappa_{k-1} has an empty word, |wk+1|2|w_{k+1}|\geq 2. If κk1\kappa_{k-1} has an empty word then from the Table 4, we infer that it must have been an ABAABA arc starting on A1A_{1}^{\prime}. Continuing thus, we see that unless κk+1\kappa_{k+1} is preceded by a finite sequence of ACAACA and ABAABA arcs which end on A1′′A_{1}^{\prime\prime} and A2′′A_{2}^{\prime\prime}, respectively, contributing empty words to wk+1w_{k+1}, we have that |wk+1|2|w_{k+1}|\geq 2. Even in the case when there are a sequence of ACAACA and ABAABA arcs preceeding κk+1\kappa_{k+1} which end on A1′′A_{1}^{\prime\prime} and A2′′A_{2}^{\prime\prime}, respectively, contributing empty words to wk+1w_{k+1}, this sequence has to end in finite number of steps as the index starts reducing and when such a sequence ends, the arc immediately preceding this sequence of arcs will contribute a word which ends with bb or cc. So there is no reduction on concatenation with the word of κk+1\kappa_{k+1}. Hence |wk+1|2|w_{k+1}|\geq 2. The argument when κk+1\kappa_{k+1} starts on A2,A1′′A_{2}^{\prime},A_{1}^{\prime\prime} or A2′′A_{2}^{\prime\prime} is similar to the case when κk+1\kappa_{k+1} starts on A1A_{1}^{\prime}. So, even in the case that the word of κk\kappa_{k} is empty, we see that |wk+1|2|w_{k+1}|\geq 2 and so by induction, we conclude that |wl|2|w_{l}|\geq 2 for all ll\in\mathbb{N} when the indexing is taken modulo pp. This contradicts the fact that QΣ{Q_{{\Sigma}}} must have a trivial word and so |wp|=0|w_{p}|=0. This completes the proof of this theorem. ∎

Using Proposition 3.9, we conclude that when aQ>bQ+cQa_{Q}>b_{Q}+c_{Q}, for a reducing sphere QQ, and when QPQ\neq P, the word length of AAAA arcs on Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}} can have the following possibilities:

  • Case (i):

    one of Σ1{\Sigma_{1}} or Σ2{\Sigma_{2}} have an AAAA-arc describing a single letter word

  • Case (ii):

    neither Σ1{\Sigma_{1}} nor Σ2{\Sigma_{2}} have an AAAA-arc describing a single letter word and both Σ1{\Sigma_{1}} and Σ2{\Sigma_{2}} have an AAAA-arc with an empty word, and

  • Case (iii):

    neither Σ1{\Sigma_{1}} nor Σ2{\Sigma_{2}} have an AAAA-arc describing a single letter word and one of Σ1{\Sigma_{1}} or Σ2{\Sigma_{2}} has an AAAA-arc describing a two-letter word and the other has an AAAA-arc describing an empty word.

For Case (ii) we can choose an isotopy so that we can convert this case into Case (i) as follows: QΣ{Q_{{\Sigma}}} has to intersect YY or ZZ, else by cutting along YZY\cup Z, we notice that QΣ{Q_{{\Sigma}}} is a separating curve on a four-boundered sphere and either piece separated by QΣ{Q_{{\Sigma}}} cannot be a torus with one boundary component, which is a contradiction to the fact that QQ is a reducing sphere. So suppose QΣ{Q_{{\Sigma}}} intersects ZZ without loss of generality. Since AAAA arcs have empty words, an ABAB or a BABA arc must intersect ZZ in an essential way. A finite sequence of AB,BAAB,BA arcs connect this intersecting ABAB or a BABA arc to an AAAA arc. Sliding the curve QΣ{Q_{{\Sigma}}} past ZZ so that the intersection is shifted onto the first AAAA arc gives the required isotopy. See Figure 13.

Refer to caption
Figure 13: Sliding QΣ{Q_{{\Sigma}}} past ZZ making empty-word AAAA to single lettered AAAA

Even for Case (iii) we can choose an isotopy to convert this case into Case (i). Without loss of generality, suppose that Σ1{\Sigma_{1}} has an AAAA arc describing the word bc1bc^{-1}. Choose such an AAAA arc, κ\kappa, which has the topmost zz coordinate on A1A_{1}. Now any arc of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} having a zz-coordinate above the zz-coordinate of κ\kappa, cannot end on A2A_{2}. This can be inferred by looking at the component hexagon of Σ1{\Sigma_{1}} containing A2A_{2} as shown in Figure 14. So for any such arc, including κ\kappa, the order of intersection on Σ1{\Sigma_{1}} of first with ZZ and then with A1A_{1} can be swapped as intersection with A2A_{2} and then an intersection with ZZ on Σ2{\Sigma_{2}} as shown in Figure 14.

Refer to caption
Figure 14: Isotopy taking two lettered AAAA to single lettered AAAA

Using these isotopies, whenever aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} for a reducing sphere QPQ\neq P, we can always assume that there is an AAAA arc of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} which describes a single letter word in π1(V)\pi_{1}(V).

4 Lowering Intersections Using β\beta

In this section we study the action of the automorphism β\beta, which is as described in the section 1. If QQ is a reducing sphere with QPQ\neq P and aQ>bQ+cQa_{Q}>b_{Q}+c_{Q}, we show that an application of one of β1\beta^{-1} or β\beta to QQ decreases its geometric intersection number with AA. We do so by showing that the geometric intersection number of QΣ{Q_{{\Sigma}}} with one of the curves η1:=β(A)\eta_{1}:=\beta(A) or η2:=β1(A)\eta_{2}:=\beta^{-1}(A) shown in Figure 15 is lesser than that with AA.

Refer to caption
Figure 15: Curves η1=β(A)\eta_{1}=\beta(A) and η2=β1(A)\eta_{2}=\beta^{-1}(A)
Theorem 4.1.

If aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} for a reducing sphere QQ then either |β(QΣ)A|<|QΣA||\beta({Q_{{\Sigma}}})\cap A|<|{Q_{{\Sigma}}}\cap A| or |β1(QΣ)A|<|QΣA||\beta^{-1}({Q_{{\Sigma}}})\cap A|<|{Q_{{\Sigma}}}\cap A|.

Without loss of generality, as remarked at the end of the previous section, we can assume that QΣ{Q_{{\Sigma}}} contains an AAAA-arc on Σ1{\Sigma_{1}} or on Σ2{\Sigma_{2}} which describes a single letter word b,b1,cb,b^{-1},c or c1c^{-1} in π1(V)\pi_{1}(V). Before we prove this Theorem, we need a few results which give some conditions on AA,AB,BA,ACAA,AB,BA,AC and CACA arcs.

Let us assume that QΣ{Q_{{\Sigma}}} has an AAAA arc on Σ1{\Sigma_{1}}, call it χ\chi, which has both its endpoints on A1A_{1} and its word is bb or b1b^{-1} based on its orientation. Every AAAA arc on Σ1{\Sigma_{1}} which satisfies the description of χ\chi, i.e. which starts and ends on A1A_{1} and has the word bb or b1b^{-1} will be called an AAAA arc parallel to χ\chi.

Let ω1\omega_{1} and ω2\omega_{2} be distinct AAAA arcs of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} parallel to χ\chi. Let the zz-coordinates of the endpoints of ω1\omega_{1} be z11z_{11} and z12z_{12} with z11<z12z_{11}<z_{12} and the zz-coordinates of the endpoints of ω2\omega_{2} be z21z_{21} and z22z_{22} with z21<z22z_{21}<z_{22}. Then either z11<z21<z22<z12z_{11}<z_{21}<z_{22}<z_{12} or z21<z11<z12<z22z_{21}<z_{11}<z_{12}<z_{22}. This is because, if the endpoints of ω1\omega_{1} and ω2\omega_{2} alternate on A1A_{1}, then ω1\omega_{1} would intersect ω2\omega_{2} on Σ1{\Sigma_{1}}. If z11<z21<z22<z12z_{11}<z_{21}<z_{22}<z_{12} then we say that ω2\omega_{2} is nested inside ω1\omega_{1}. Or if z21<z11<z12<z22z_{21}<z_{11}<z_{12}<z_{22}, then we say that ω1\omega_{1} is nested inside ω2\omega_{2}.

Since χ\chi cuts an annulus SχS_{\chi} out of Σ1{\Sigma_{1}} containing the circle BB, all the AA-ends of the AB,BAAB,BA arcs of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} have to lie on A1A_{1} and between the endpoints of χ\chi. With the zz-coordinate as height we classify the points of QΣA1{Q_{{\Sigma}}}\cap A_{1} into five stacks. The first stack of points with the largest zz-coordinates consists of AA-ends of arc segments of QΣ{Q_{{\Sigma}}} which lie outside SχS_{\chi}, if any, which connect Z1Z_{1} to A1A_{1} and which are not end points of AAAA arcs on Σ1{\Sigma_{1}} parallel to χ\chi. Every AAAA arc on Σ1{\Sigma_{1}} which is parallel to χ\chi has two ends, one with a higher zz-coordinate and one with a lower zz-coordinate. The second stack of points consists of those AA-ends of AAAA arcs on Σ1{\Sigma_{1}} parallel to χ\chi, which have higher zz-coordinate than their counterparts. The fourth stack of points consists of those AA-ends of AAAA arcs on Σ1{\Sigma_{1}} parallel to χ\chi which have lower zz-coordinate than their counterparts. The third stack of points consists of the AA-ends of AB,BAAB,BA arcs of QΣ{Q_{{\Sigma}}}, if any on Σ1{\Sigma_{1}}. The fifth stack of points consists of the AA-ends of the arc segments of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}}, if any, which have a zz-coordinate lower than that of any point in the fourth stack of points and are not the end-points of AAAA arcs parallel to χ\chi. See figure 16.

Refer to caption
Figure 16: Stacks of points from QΣA{Q_{{\Sigma}}}\cap A on A1A_{1}

Now without loss of generality, we can assume that χ\chi is the innermost among all these parallel AAAA-arcs on Σ1{\Sigma_{1}} having word bb or b1b^{-1}.

Under the above circumstances, we note the following conditions on AAAA, AB,BA,ACAB,BA,AC and CACA arcs of QΣ{Q_{{\Sigma}}} on Σ2{\Sigma_{2}}.

Proposition 4.2.

QΣ{Q_{{\Sigma}}} cannot have an AAAA-arc on Σ2{\Sigma_{2}} with both ends on A1A_{1}, whose word is either bb or b1b^{-1}. Also QΣ{Q_{{\Sigma}}} cannot have an AAAA-arc on Σ2{\Sigma_{2}} with word bc1bc^{-1} or cb1cb^{-1}.

Proof.

The presence of such an arc (see figure 17) on Σ2{\Sigma_{2}} along with χ\chi contradicts Lemma 3.2. ∎

Refer to caption
(a)
Refer to caption
(b)
Figure 17: Impossible AAAA arcs on Σ2\Sigma_{2} with χ\chi on A1A_{1}
Proposition 4.3.

On Σ2{\Sigma_{2}}, if QΣ{Q_{{\Sigma}}} has an arc with word bk,kb^{k},k\in\mathbb{Z} such that one of its endpoints is on BB and another is on A1A_{1}, then its A1A_{1}-end should lie in stack one, two or three barring the point in stack three with the least zz-coordinate.

Proof.

If possible, suppose QΣ{Q_{{\Sigma}}} has an arc λ\lambda on Σ2{\Sigma_{2}} with word bk,kb^{k},k\in\mathbb{Z} such that one of its endpoints is on BB and another is on A1A_{1}, where its A1A_{1}-end in stack four or five or is the point in stack three with the least zz-coordinate. Then all arcs on Σ2{\Sigma_{2}} having their A1A_{1} ends on stacks one, two and three must end on BB. Including the A1A_{1}- end point of χ\chi in stack one and the A1A_{1}- end point of λ\lambda, there are at least bQ+1b_{Q}+1 points in stack one, two and three on A1A_{1} which are to be connected via arcs on Σ2{\Sigma_{2}} to bQb_{Q} points on BB, which is impossible. See Figure 18(a). So, such an arc λ\lambda cannot exist.

Refer to caption
(a) λ\lambda from A1A_{1} with bkb^{k}
Refer to caption
(b) λ\lambda from A1A_{1} with c1bkc^{-1}b^{k}
Refer to caption
(c) λ\lambda from A2A_{2} with cbkcb^{k}
Figure 18: Impossible AAAA arcs and ABAB arcs on Σ2\Sigma_{2} with χ\chi on A1A_{1} (Arc continuation of the top end of χ\chi must end on BB. Also all arcs on Σ2\Sigma_{2} with one end in stack 3 must have their other end on BB.)

Proposition 4.4.

If Σ2{\Sigma_{2}} contains an arc of QΣ{Q_{{\Sigma}}} with endpoints on A1A_{1} and BB with the word c1bkc^{-1}b^{k} then such an A1A_{1}-end should be in stack three, four or five, barring the topmost point in the third stack with the largest zz-coordinate.

Proof.

Suppose to the contrary that λ\lambda is such an ABAB-arc on Σ2{\Sigma_{2}} with an endpoint on A1A_{1} with word c1bkc^{-1}b^{k} and with its endpoint in stack one or two of A1A_{1} or the topmost point in stack three on A1A_{1}. See Figure 18(b). Then λ\lambda will force every arc of cQc_{Q} on Σ2{\Sigma_{2}} starting from stacks three, four and five to end on BB due to Theorem 3.6. Including the A1A_{1}- end point of χ\chi on stack four and the A1A_{1}- end point of λ\lambda, there are at least bQ+1b_{Q}+1 points in stack three four and five on A1A_{1} which are to be connected via arcs on Σ2{\Sigma_{2}} to bQb_{Q} points on BB, which is impossible. Hence such a λ\lambda cannot exist. ∎

Proposition 4.5.

If an arc of QΣ{Q_{{\Sigma}}} on Σ2{\Sigma_{2}} has its end points on A2A_{2} and BB, then its word has to be of the form bkb^{k} for some integer kk.

Proof.

If possible suppose λ\lambda is an arc on Σ2{\Sigma_{2}} with word cbkcb^{k} and having its end points on A2A_{2} and BB. See Figure 18(c). Note that by Theorem 3.6, this is the only other option for such an arc apart from having a word of the form bkb^{k} for some integer kk.

Due to Lemma 3.2, such a λ\lambda will force all arcs on Σ2{\Sigma_{2}} having one end-point on A1A_{1} to start with a word c1c^{-1} or end with cc, as the case maybe, and they must have the other end-point on BB. But, including the A1A_{1}-end-points of χ\chi, there are at-least bQ+2b_{Q}+2 points on A1A_{1} whereas only bQb_{Q} points on BB. Therefore, such a λ\lambda cannot exist. ∎

Proposition 4.6.

QΣ{Q_{{\Sigma}}} cannot have an ACAC-arc on Σ2{\Sigma_{2}} with word bckbc^{k}, where kk\in\mathbb{Z}

Proof.

The presence of such an arc on Σ2{\Sigma_{2}} along with χ\chi contradicts Lemma 3.2. ∎

We now define AAAA-arcs, η\eta^{\prime} and ζ\zeta^{\prime} on Σ1{\Sigma_{1}} which are not arcs of QΣ{Q_{{\Sigma}}} and are disjoint from arcs of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} and are parallel to χ\chi as follows. Define η\eta^{\prime} to be an arc whose ends on A1A_{1} are nested inside the ends of χ\chi so that AA-ends of all AB,BAAB,BA-arcs on Σ1{\Sigma_{1}}, if any, are between the ends of η\eta^{\prime}. Likewise, define ζ\zeta^{\prime} to be an arc whose ends on A1A_{1} are such that (i) every arc of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} parallel to χ\chi is nested inside ζ\zeta^{\prime}, (ii) the AA-ends of every AB,BAAB,BA-arc on Σ1{\Sigma_{1}} is also between the ends of ζ\zeta^{\prime} and (iii) the AA-ends of no other arc of QΣ{Q_{{\Sigma}}} on Σ1{\Sigma_{1}} is between the ends of ζ\zeta^{\prime}. Figure 19 shows η\eta^{\prime} and ζ\zeta^{\prime}.

Refer to caption
Figure 19: Construction of η\eta^{\prime} and ζ\zeta^{\prime}

Define η′′\eta^{\prime\prime} and ζ′′\zeta^{\prime\prime} to be AAAA arcs (also not of QΣ{Q_{{\Sigma}}}) on Σ2{\Sigma_{2}} such that: (i) η′′=η\partial\eta^{\prime\prime}=\partial\eta^{\prime}, ζ′′=ζ\partial\zeta^{\prime\prime}=\partial\zeta^{\prime}, (ii) the word of η′′\eta^{\prime\prime} or ζ′′\zeta^{\prime\prime} is c1c^{-1} or cc and (iii) η′′\eta^{\prime\prime} and ζ′′\zeta^{\prime\prime} intersect cQc_{Q} minimally on Σ2{\Sigma_{2}} where the end points of all arcs on Σ2{\Sigma_{2}} are rigid i.e.cannot be moved while considering their intersection numbers. The simple closed curves ηη′′\eta^{\prime}\cup\eta^{\prime\prime} or ζζ′′\zeta^{\prime}\cup\zeta^{\prime\prime} are isotopic to each other on Σ{\Sigma} and in turn are isotopic to A:=β1(A)A^{\prime}:=\beta^{-1}(A). We now show that |cQA|<|cQA||c_{Q}\cap A^{\prime}|<|c_{Q}\cap A|. By construction, |cQη|=|cQζ|=0|c_{Q}\cap\eta^{\prime}|=|c_{Q}\cap\zeta^{\prime}|=0. So it is enough to show that either |cQA|>|cQη′′||c_{Q}\cap A|>|c_{Q}\cap\eta^{\prime\prime}| or |cQA|>|cQζ′′||c_{Q}\cap A|>|c_{Q}\cap\zeta^{\prime\prime}|. We will first show that |cQA||cQη′′||c_{Q}\cap A|\geq|c_{Q}\cap\eta^{\prime\prime}| and |cQA||cQζ′′||c_{Q}\cap A|\geq|c_{Q}\cap\zeta^{\prime\prime}|.

Taking the restrictions on the possible AAAA arcs of QΣ{Q_{{\Sigma}}} on Σ2{\Sigma_{2}} into account, the intersection of such arcs with η′′\eta^{\prime\prime} and ζ′′\zeta^{\prime\prime} are as shown in Figure 20. Likewise, the intersection of possible AB,BAAB,BA arcs of QΣ{Q_{{\Sigma}}} on Σ2{\Sigma_{2}} with η′′\eta^{\prime\prime} and ζ′′\zeta^{\prime\prime} are as shown in Figure 21. The intersection of possible AC,CAAC,CA arcs of QΣ{Q_{{\Sigma}}} on Σ2{\Sigma_{2}} with η′′\eta^{\prime\prime} and ζ′′\zeta^{\prime\prime} are as shown in Figure 22.

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(a)
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(b)
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(c)
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(d)
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(e)
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(f)
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(g)
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(h)
Figure 20: Intersection of AAAA with η′′\eta^{\prime\prime} and ζ′′\zeta^{\prime\prime}
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(a)
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(b)
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(c)
Figure 21: Intersection of possible ABAB, BABA with η′′\eta^{\prime\prime} and ζ′′\zeta^{\prime\prime}
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(a)
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(b)
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(c)
Figure 22: Intersection of possible ACAC, CACA with η′′\eta^{\prime\prime} and ζ′′\zeta^{\prime\prime}

From the above discussion and Figures 20, 21 and 22, we conclude the following.

Proposition 4.7.

Every arc κ\kappa of QΣ{Q_{{\Sigma}}} on Σ2{\Sigma_{2}} satisfies |κη′′||κA||\kappa\cap\eta^{\prime\prime}|\leq|\kappa\cap A| and |κζ′′||κA||\kappa\cap\zeta^{\prime\prime}|\leq|\kappa\cap A|.

Next we show that at least one of the two strict inequalities: |QΣA|>|QΣη′′||{Q_{{\Sigma}}}\cap A|>|{Q_{{\Sigma}}}\cap\eta^{\prime\prime}| or |QΣA|>|QΣζ′′||{Q_{{\Sigma}}}\cap A|>|{Q_{{\Sigma}}}\cap\zeta^{\prime\prime}| holds, by showing the following.

Lemma 4.8.

There exists an arc λ\lambda of QΣ{Q_{{\Sigma}}} on Σ2{\Sigma_{2}} such that |λη′′|<|λA||\lambda\cap\eta^{\prime\prime}|<|\lambda\cap A| or |λζ′′|<|λA||\lambda\cap\zeta^{\prime\prime}|<|\lambda\cap A|.

Proof.

Consider the points χA1\chi\cap A_{1}. Let the arc of QΣ{Q_{{\Sigma}}} on Σ2{\Sigma_{2}} with the point in stack two of χA1\chi\cap A_{1} as an endpoint be θ1\theta_{1} and the arc with the point in stack four of χA1\chi\cap A_{1} as an endpoint be θ2\theta_{2}. By proposition 4.4, θ1\theta_{1} cannot be an ABAB arc with the word c1bkc^{-1}b^{k} or a BABA arc with the word bkcb^{k}c. We have the following cases.

  • Case 1

    Suppose that θ1\theta_{1} is an AAAA-arc with endpoints on A1A_{1} and A2A_{2} with the empty word. In this case, θ1\theta_{1} is disjoint from η′′\eta^{\prime\prime} and is the required λ\lambda. See Figure 23(a).

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    (a)
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    (b)
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    (c)
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    (d)
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    (e)
    Figure 23: The arc λ\lambda of QσQ_{\sigma} on Σ2\Sigma_{2}
  • Case 2

    Suppose θ1\theta_{1} is an AAAA-arc with both its endpoints on A1A_{1} with the word cc or c1c^{-1}. If the other end point of θ1\theta_{1} is in stack one or two, then θ1\theta_{1} cuts off an annulus from Σ2{\Sigma_{2}} containing CC as one boundary component and so θ2\theta_{2}, cannot be an ACAC arc. So, if the other end point of θ1\theta_{1} is in stack one or two then θ2\theta_{2} is an AAAA arc with the word c1bc^{-1}b, cc or c1c^{-1} or an ABAB arc with the word c1bkc^{-1}b^{k}, kk\in\mathbb{Z} (or a BABA arc with the inverse word), and in any case, θ2\theta_{2} is disjoint from η′′\eta^{\prime\prime} and is the required λ\lambda. If the other end point of θ1\theta_{1} is in stack three then it intersects η′′\eta^{\prime\prime} once, whereas θ1\theta_{1} intersects AA twice. So θ1\theta_{1} is the required λ\lambda. Finally, if the other end point of θ1\theta_{1} is in stack four or five then it is disjoint from η′′\eta^{\prime\prime} and θ1\theta_{1} is the required λ\lambda. See Figure 23(b).

  • Case 3

    If θ1\theta_{1} is an AAAA arc with endpoints on A1A_{1} and A2A_{2} with the word c1bc^{-1}b, then θ2\theta_{2} is either an AAAA arc with the word c1bc^{-1}b or is an ABAB arc with the word c1bkc^{-1}b^{k} (or a BABA arc with the inverse word). In any case, θ2\theta_{2} is disjoint from η′′\eta^{\prime\prime} and is the required λ\lambda. See Figure 23(c).

  • Case 4

    If θ1\theta_{1} is an ABAB arc with the word bkb^{k}, kk\in\mathbb{Z}, then it is disjoint from η′′\eta^{\prime\prime} and is the required λ\lambda. See Figure 23(d).

  • Case 5

    Suppose that θ1\theta_{1} is an ACAC-arc or a CACA-arc with the word ckc^{k}, kk\in\mathbb{Z}. Then, θ1\theta_{1} is disjoint from ζ′′\zeta^{\prime\prime} and is the required λ\lambda. See Figure 23(e).

Owing to the symmetry of Σ{\Sigma}, all of the above discussion holds even if we replace χ\chi by any AAAA arc on Σ{\Sigma} with both endpoints on A1A_{1} or both endpoints on A2A_{2} describing a single letter word in π1(V)\pi_{1}(V). For comprehensiveness, Figure 24 shows the eight possibilities for such an AAAA arc. We note that, in some cases we might have to use A′′=β(A)A^{\prime\prime}=\beta(A) instead of A=β1(A)A^{\prime}=\beta^{-1}(A) throughout the above discussion for the inequalities to hold.

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Figure 24: All eight possibilities for a single word AAAA arc

So the above discussion proves Theorem 4.1.

5 A Reduction Algorithm

We have the following:

Lemma 5.1.

Suppose that aQ>bQ+cQa_{Q}>b_{Q}+c_{Q} for a reducing sphere QQ of {\mathcal{H}}. Then bQcQb_{Q}\neq c_{Q}, unless bQ=cQ=0b_{Q}=c_{Q}=0 in which case aQa_{Q} is automatically 22.

Proof.

First we note that all three of aQ,bQa_{Q},b_{Q} and cQc_{Q} cannot be simultaneously zero because then QΣ{Q_{{\Sigma}}} will be a trivial curve on V\partial V implying that QQ is not a reducing sphere.

If bQ=cQ=0b_{Q}=c_{Q}=0, we can apply βk\beta^{k} for some integer kk to {\mathcal{H}} to reduce aQa_{Q} to 22 at which stage we get, PP, the standard reducing sphere. But then βk(P)=Q\beta^{-k}(P)=Q and PP is invariant under β\beta implying P=QP=Q, which means aQ=2a_{Q}=2.

If possible, suppose that bQ=cQ0b_{Q}=c_{Q}\neq 0. Since, aQ>bQ+cQa_{Q}>b_{Q}+c_{Q}, we can use Theorem 4.1 to lower aQa_{Q}. Suppose that kk is an integer of smallest absolute value such that βk(Q)=R\beta^{k}(Q)=R and aR<bR+cRa_{R}<b_{R}+c_{R}. Since β\beta does not change bQb_{Q} and cQc_{Q}, bR=cR=bQ=cQ0b_{R}=c_{R}=b_{Q}=c_{Q}\neq 0. So, neither bR>aR+cRb_{R}>a_{R}+c_{R} nor cR>bR+aRc_{R}>b_{R}+a_{R}, contradicting Theorem 2.2 as applied to RR. So, we cannot have bQ=cQ0b_{Q}=c_{Q}\neq 0. ∎

Among the four automorphisms of {\mathcal{H}} mentioned in section 2, we note that the non-zero integral powers of β\beta are the only ones which change the value of aQ+bQ+cQa_{Q}+b_{Q}+c_{Q}. Lemma 5.1 shows that the lowest possible value of aQ+bQ+cQa_{Q}+b_{Q}+c_{Q} is 22. Three possibilities for QQ with aQ+bQ+cQ=2a_{Q}+b_{Q}+c_{Q}=2 are: (i) aQ=2,bQ=cQ=0a_{Q}=2,b_{Q}=c_{Q}=0 giving the standard reducing sphere PP, (ii) bQ=2,aQ=cQ=0b_{Q}=2,a_{Q}=c_{Q}=0 giving the simple reducing sphere PP^{\prime} or (iii) cQ=2,bQ=aQ=0c_{Q}=2,b_{Q}=a_{Q}=0 giving the simple reducing sphere P′′P^{\prime\prime}. The reducing curves of P,PP,P^{\prime} and P′′P^{\prime\prime} are shown in Figure 25. We note that δ1(P)=P\delta^{-1}(P^{\prime})=P and δ(P′′)=P\delta(P^{\prime\prime})=P, where δ\delta is the order three automorphism of {\mathcal{H}} described in section 2.

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(a) Reducing curve of PP
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(b) Reducing curve of PP^{\prime}
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(c) Reducing curve of P′′P^{\prime\prime}
Figure 25: The reducing curves PΣ,PΣP_{\Sigma},P_{\Sigma}^{\prime}, and PΣ′′P_{\Sigma}^{\prime\prime}

Let QQ be a reducing sphere of {\mathcal{H}}. Using automorphisms β\beta and δ\delta, we have the following algorithm which transforms QQ into PP:

Algorithm 5.2.

Reduction Algorithm:

  1. Step 1:

    If aQ+bQ+cQ=2a_{Q}+b_{Q}+c_{Q}=2 then Q=P,PQ=P,P^{\prime} or P′′P^{\prime\prime}.
    If Q=PQ=P, Exit.
    Else: apply δ\delta or δ1\delta^{-1} to P′′P^{\prime\prime} or PP^{\prime}, respectively, to get PP. Exit.

  2. Step 2:

    While aQ+bQ+cQ>2a_{Q}+b_{Q}+c_{Q}>2, Do

    • Step (i):

      If aQ>bQ+cQa_{Q}>b_{Q}+c_{Q}, go to Step (ii), else: let δ(Q)=R\delta(Q)=R^{\prime}, δ1(Q)=R′′\delta^{-1}(Q)=R^{\prime\prime}. If aR>bR+cRa_{R^{\prime}}>b_{R^{\prime}}+c_{R^{\prime}}, set QQ to be RR^{\prime}. If aR′′>bR′′+cR′′a_{R^{\prime\prime}}>b_{R^{\prime\prime}}+c_{R^{\prime\prime}}, set QQ to be R′′R^{\prime\prime}. Go to Step (ii).

    • Step (ii):

      Let β(Q)=S\beta(Q)=S^{\prime}, β1(Q)=S′′\beta^{-1}(Q)=S^{\prime\prime}. If aS<aQa_{S^{\prime}}<a_{Q}, set QQ to be SS^{\prime}. If aS′′<aQa_{S^{\prime\prime}}<a_{Q}, set QQ to be S′′S^{\prime\prime}.

  3. Step 3:

    Now, aQ+bQ+cQ=2a_{Q}+b_{Q}+c_{Q}=2 and Q=P,PQ=P,P^{\prime} or P′′P^{\prime\prime}.
    If Q=PQ=P, Exit.
    Else: apply δ\delta or δ1\delta^{-1} to P′′P^{\prime\prime} or PP^{\prime}, respectively, to get PP. Exit.

Note that in Step (i) within the while-loop in the reduction algorithm for QQ, if aQ<bQ+cQa_{Q}<b_{Q}+c_{Q}, Theorem 2.2 asserts that one of aR>bR+cRa_{R^{\prime}}>b_{R^{\prime}}+c_{R^{\prime}} or aR′′>bR′′+cR′′a_{R^{\prime\prime}}>b_{R^{\prime\prime}}+c_{R^{\prime\prime}} will hold. Also, in Step (ii) within the while-loop, Theorem 4.1 asserts that one of aS<aQa_{S^{\prime}}<a_{Q} or aS′′<aQa_{S^{\prime\prime}}<a_{Q} holds. So each iteration of the while loop indeed updates QQ to a new reducing sphere QQ^{\prime} such that aQ+bQ+cQ<aQ+bQ+cQa_{Q^{\prime}}+b_{Q^{\prime}}+c_{Q^{\prime}}<a_{Q}+b_{Q}+c_{Q}.

By applying the reduction algorithm to the given reducing sphere QQ, we can obtain PP. So by applying the automorphisms β,β1,δ\beta,\beta^{-1},\delta or δ1\delta^{-1} in the inverse sequence, as dictated by the reduction algorithm, we can obtain QQ from PP. Note that this inverse process applies a reduced word, ww, of automorphisms β,β1,δ\beta,\beta^{-1},\delta or δ1\delta^{-1} to PP to obtain QQ.

Let hG2h\in G_{2}, then h(P)=Qh(P)=Q for some reducing sphere QQ. By using the reducing algorithm, we get a word ww in the automorphisms β,β1,δ\beta,\beta^{-1},\delta or δ1\delta^{-1} such that w(Q)=Pw(Q)=P, so wh(P)=w(Q)=Pw\circ h(P)=w(Q)=P. This implies that whStab(P)w\circ h\in Stab(P). If we assume that Stab(P)Stab(P) is finitely generated by the automorphisms α,β\alpha,\beta and γ\gamma, then since ww is also a finite word generated by β\beta and δ\delta, we have that hh, an arbitrary element in G2G_{2}, can also be written as a word in α,β,γ,δ\alpha,\beta,\gamma,\delta and their inverses. Hence we can conclude that G2G_{2} is finitely generated by {α,β,γ,δ}\{\alpha,\beta,\gamma,\delta\}.

We conclude this article by asking a question. Let a triple (x,y,z)(x,y,z) of non-negative integers be called a non-triangular triple if it satisfies one of the inequalities x>y+z,y>z+xx>y+z,y>z+x or z>x+yz>x+y. From Corollary 2.4, the set of triples (aQ,bQ,cQ)(a_{Q},b_{Q},c_{Q}) of intersection numbers with the curves A,B,CA,B,C as in Figure 2 of a given reducing sphere QQ for {\mathcal{H}} is a specific subset Λ\Lambda of the set of non-triangular triples of integers.

Question 5.1.

Describe the set Λ\Lambda which is in one-to-one correspondence with the set of reducing spheres for the genus-2 Heegaard splitting {\mathcal{H}} of S3S^{3}.

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