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Robust self-testing of multipartite GHZ-state measurements in quantum networks

Qing Zhou    Xin-Yu Xu    Shuai Zhao    Yi-Zheng Zhen    Li Li111eidos@ustc.edu.cn,{}^{\ ,}    Nai-Le Liu222nlliu@ustc.edu.cn,{}^{\ ,}    Kai Chen333kaichen@ustc.edu.cn,{}^{\ ,} Hefei National Laboratory for Physical Sciences at Microscale and Department of Modern Physics, University of Science and Technology of China, Hefei, Anhui 230026, People’s Republic of China CAS Center for Excellence and Synergetic Innovation Center in Quantum Information and Quantum Physics, University of Science and Technology of China, Hefei, Anhui 230026, People’s Republic of China
Abstract

Self-testing is a device-independent examination of quantum devices based on correlations of observed statistics. Motivated by elegant progresses on self-testing strategies for measurements [Phys. Rev. Lett. 121, 250507 (2018)] and for states [New J. Phys. 20083041083041 (2018)], we develop a general self-testing procedure for multipartite generalized GHZ-state measurements. The key step is self-testing all measurement eigenstates for a general NN-qubit multipartite GHZ-state measurement. Following our procedure, one only needs to perform local measurements on N2N-2 chosen parties of the NN-partite eigenstate and maintain to achieve the maximal violation of tilted Clauser-Horne-Shimony-Holt (CHSH) Bell inequality for remaining two parties. Moreover, this approach is physically operational from an experimental point of view. It turns out that the existing result for three-qubit GHZ-state measurement is recovered as a special case. Meanwhile, we develop the self-testing method to be robust against certain white noise.

1 Introduction

The rapid development of quantum communication in recent years creates an exigent requirement for devising certification methods to guarantee correctness of quantum information tasks. To rule out any potential attacks by malicious third party, such certification methods must be device-independent. As the first device-independent tool, the Bell nonlocality has been extensively studied in recent decades [1]. It has brought great breakthroughs in quantum physics. Recently, as the strongest form of device-independent certification, self-testing has been developed, which is also based on Bell nonlocality. Such certification method can characterize the target objects (quantum states, measurements) fully, only up to local isometries, in a device-independent manner.

Self-testing, acting as a device-independent certification method, has attracted lots of attention since the pioneer works of Mayers and Yao [2]. It can be used to certify entangled pure states and measurements [3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22]. Up to now, a wide range of entangled quantum states are proved to be self-testable, such as the elegant results for all pure bipartite entangled states [23], three-qubit W states [24], and graph states [25]. It has also been shown that all pure multipartite GHZ states and Dicke states can be self-tested [26]. Recently, the self-testing method for quantum channels has also been developed [27]. Moreover, there have been many applications about self-testing, such as quantum key distribution [28], randomness expansion [29], detection for entanglement [30], certification of genuinely entangled subspaces [31, 32], coarse-grained self-testing of a many-body singlet [33], as well as verification of quantum computations [34, 35].

In this work, we will focus on self-testing entangled measurements in quantum networks. Self-testing entangled quantum measurements is of great potential to develop practical quantum networks, which has been preliminarily studied [36, 37]. For a star-network as shown in Fig.  1, where NN observers share entangled states with central node, respectively. A self-testable entangled measurement can guarantee the success of quantum information tasks, which are based on distributing entangled states between remote parties in such a network. Meanwhile, the entanglement between observers and central node can also be certified. In Ref.  [36], the authors presented a self-testing method for the Bell-state measurement (BSM) and three-qubit GHZ-state measurement (GSM). Furthermore, a more robust self-testing scheme for BSM has also been proposed in Ref.  [37]. However, there have not been a detailed characterization for self-testing multipartite (N>3N>3) entangled measurements directly.

Refer to caption
Figure 1: Roy shares a Bell state with each of the other NN observers (Alice 11, Alice 22,\dots, Alice NN). If Roy performs multipartite tilted GSM, then the state shared by Alice 11, Alice 22,\dots, Alice NN will be projected into |GHZθr|GHZ^{r}_{\theta}\rangle. Conversely, if Alice 11, Alice 22,\dots, Alice NN observe that they are projected into |GHZθr|GHZ^{r}_{\theta}\rangle for all rr, the measurement performed by Roy is equivalent to the tilted GSM.

By generalizing the idea of Ref.  [36], we present herewith a self-testing method for NN-qubit tilted GSM, whose eigenstates are partially entangled NN-qubit GHZ states (tilted GHZ states). That is to say, one of the eigenstates of NN-qubit tilted GSM can be written as |GHZθ0=cosθ|0N+sinθ|1N,θ(0,π/4].|GHZ^{0}_{\theta}\rangle=\cos\theta|0\rangle^{\otimes N}+\sin\theta|1\rangle^{\otimes N},\ \theta\in(0,\pi/4]. In the N+1N+1-partite star-network shown in Fig.  1, after performing measurement in central node (Roy), the remaining particles shared with Alice 11, Alice 22,\dots, and Alice NN will be projected into the eigenstates of Roy’s measurement. If the particular correlations of remaining particles are observed by local measurements on Alice 11, Alice 22,\dots, and Alice NN, the measurement performed by Roy is equivalent to an NN-qubit tilted GSM, up to a local isometry. A local isometry is a linear local operation on quantum states that preserves inner products [38]. Thus, the first step to self-test tilted GSM is self-testing all its measurement eigenstates, and the problem of self-testing tilted GSM can be converted to the problem of self-testing states. Motivated by the method of self-testing multipartite entangled states in Ref.  [26], we have developed further a general method for self-testing multipartite tilted GSM in a star-network, and the method is operational from an experimental point of view. We also show that one can self-test more entangled measurements by our developed method straightforwardly.

The paper is organized as following. In Sec.  2, we provide a preparation review of tilted CHSH scenario which constitute important ingredient of our self-testing method. In Sec.  3, self-testing method of multipartite tilted GSM is presented. In Sec.  4, a noise-robust self-testing scheme of three-qubit GSM is presented, with the help of semidefinite program (SDP) method. Finally, we conclude our results and make a discussion on potential future works in Sec.  5.

2 Preliminaries

To self-test tilted multipartite GSM, the tilted CHSH inequality is necessary [39]. Let us consider a task: Alice and Bob share a two-qubit state and they want to know whether the shared state is partially entangled or not. They perform local measurements (dichotomic observables) respectively. The tilted CHSH inequality is given by

αA0+A0B0+A0B1+A1B0A1B12+α,\alpha\langle A_{0}\rangle+\langle A_{0}B_{0}\rangle+\langle A_{0}B_{1}\rangle+\langle A_{1}B_{0}\rangle-\langle A_{1}B_{1}\rangle\leq 2+\alpha, (1)

where the maximal value of violation is 8+2α2,α[0,2)\sqrt{8+2\alpha^{2}},\alpha\in[0,2), AiA_{i} and BiB_{i} being observables with outcomes {1,+1}\{-1,+1\} measured locally by Alice and Bob. Here, we omit the notation “\otimes” between systems AA and BB and write A0IA_{0}\otimes I as A0A_{0} for short. After performing local measurements, if Alice and Bob obtain the maximal violation of tilted CHSH inequality, the state shared by them is a certain partially entangled two-qubit state (tilted Bell state). For detailed case, the four tilted Bell states |Bellθb,b=0,1,2,3|Bell^{b}_{\theta}\rangle,b=0,1,2,3 are given by

|Bellθ0=cθ|00+sθ|11,|Bellθ1=sθ|00cθ|11,|Bellθ2=cθ|01+sθ|10,|Bellθ3=sθ|01cθ|10,\begin{split}&|Bell^{0}_{\theta}\rangle=c_{\theta}|00\rangle+s_{\theta}|11\rangle,\ |Bell^{1}_{\theta}\rangle=s_{\theta}|00\rangle-c_{\theta}|11\rangle,\\ &|Bell^{2}_{\theta}\rangle=c_{\theta}|01\rangle+s_{\theta}|10\rangle,\ |Bell^{3}_{\theta}\rangle=s_{\theta}|01\rangle-c_{\theta}|10\rangle,\end{split}

where cθ=cosθ,sθ=sinθ,θ(0,π4]c_{\theta}=\cos\theta,s_{\theta}=\sin\theta,\theta\in(0,\frac{\pi}{4}]. Let μ\mu satisfy tanμ=sin2θ\tan\mu=\sin 2\theta and σZ,σX\sigma_{Z},\sigma_{X} be Pauli matrices. If one fixes the measurement settings of Alice and Bob as A0=σZ,A1=σX,B0=cosμσZ+sinμσX,B1=cosμσZsinμσXA_{0}=\sigma_{Z},\ A_{1}=\sigma_{X},\ B_{0}=\cos\mu\sigma_{Z}+\sin\mu\sigma_{X},\ B_{1}=\cos\mu\sigma_{Z}-\sin\mu\sigma_{X}, the output statistics obtained by these measurements will maximally violate some tilted CHSH inequalities. The maximal violation is CHSHbα=Bellθb|Wbα|Bellθb=8+2α2CHSH_{b}^{\alpha}=\langle Bell^{b}_{\theta}|W_{b}^{\alpha}|Bell^{b}_{\theta}\rangle=\sqrt{8+2\alpha^{2}} with α=2cos2θ/1+sin22θ\alpha=2\cos 2\theta/\sqrt{1+\sin^{2}2\theta}, where

W0α=αA0+A0B0+A0B1+A1B0A1B1,W1α=αA0+A0B0+A0B1A1B0+A1B1,W2α=W1α,W3α=W0α.\begin{split}&W_{0}^{\alpha}=\alpha A_{0}+A_{0}B_{0}+A_{0}B_{1}+A_{1}B_{0}-A_{1}B_{1},\\ &W_{1}^{\alpha}=-\alpha A_{0}+A_{0}B_{0}+A_{0}B_{1}-A_{1}B_{0}+A_{1}B_{1},\\ &W_{2}^{\alpha}=-W_{1}^{\alpha},W_{3}^{\alpha}=-W_{0}^{\alpha}.\end{split}

Here the WbαW_{b}^{\alpha} is Bell operator acting on the Hilbert space AB\mathcal{H}_{A}\otimes\mathcal{H}_{B} of Alice and Bob. It is easy to show that the eigenvalue 8+2α2\sqrt{8+2\alpha^{2}} of the Bell operator WbαW_{b}^{\alpha} is nondegenerate with associated eigenvector |Bellθb|Bell^{b}_{\theta}\rangle. Hence, if the maximal violation of CHSHbαCHSH_{b}^{\alpha} is 8+2α2\sqrt{8+2\alpha^{2}}, the shared state will be |Bellθb|Bell^{b}_{\theta}\rangle. One can discriminate the four tilted Bell states by the maximally violations of four tilted Bell inequality with fix measurement settings. Furthermore, other tilted Bell states that are local-unitary (constructed by σZ,σX\sigma_{Z},\sigma_{X}) equivalent to the above four tilted Bell states can also be discriminated. For example, the state |Φ=cθ|00sθ|11=σZA|Bellθ0|\Phi\rangle=c_{\theta}|00\rangle-s_{\theta}|11\rangle=\sigma_{Z_{A}}|Bell_{\theta}^{0}\rangle. It can maximally violate tilted CHSH inequality with CHSHθ=σZAW0ασZA=αA0+A0B0+A0B1A1B0+A1B1CHSH_{\theta}=\langle\sigma_{Z_{A}}W_{0}^{\alpha}\sigma_{Z_{A}}^{{\dagger}}\rangle=\alpha\langle A_{0}\rangle+\langle A_{0}B_{0}+A_{0}B_{1}-A_{1}B_{0}+A_{1}B_{1}\rangle and fixed measurements given above.

In the entanglement swapping scenario [40] shown in Fig.  2, let Charlie perform tilted BSM whose measurement eigenstates are tilted Bell states with outcomes bb. Then, the remaining state will be projected into one of the four tilted Bell states |Bellθb|Bell^{b}_{\theta}\rangle conditioned on the outcomes bb. Conversely, if one finds that Alice and Bob share tilted Bell states |Bellθb|Bell^{b}_{\theta}\rangle for b{0,1,2,3}b\in\{0,1,2,3\}, the performed measurement of Charlie is a tilted BSM. Motivated by this idea, we will develop a procedure for preforming self-testing of tilted multipartite GSM.

Refer to caption
Figure 2: An entanglement swapping scenario: Charlie shares a maximally entangled two-qubit state with each of the other two observers (Alice and Bob). If Charlie performs tilted BSM and obtains outcome b, then Alice and Bob will be projected into |Bellθb|Bell^{b}_{\theta}\rangle, i.e., Alice and Bob can observe the maximal violation of the specific tilted CHSH inequality with CHSHbα=8+2α2CHSH_{b}^{\alpha}=\sqrt{8+2\alpha^{2}}.

3 Self-test tilted multipartite GSM

As shown in Ref.  [41], any completely positive and trace preserving (CPTP) map can be implemented, by tracing out degrees of freedom that does not involve effective information after applying a local isometry. Therefore, one can adopt the approach presented in [15, 36, 38] to present the definition for self-testing multipartite measurements via simulation: denote an ideal dd-outcome measurement for Roy acting on R1R2RN\mathcal{H}_{R_{1}^{\prime}}\otimes\mathcal{H}_{R_{2}^{\prime}}\otimes\dots\otimes\mathcal{H}_{R_{N}^{\prime}} as 𝒫={PR1R2RNr}r=1d\mathcal{P}^{\prime}=\{P_{R_{1}^{\prime}R_{2}^{\prime}\dots R_{N}^{\prime}}^{\prime r}\}_{r=1}^{d}, and a real measurement acting on R1R2RN\mathcal{H}_{R_{1}}\otimes\mathcal{H}_{R_{2}}\otimes\dots\otimes\mathcal{H}_{R_{N}} as 𝒫={PR1R2RNr}r=1d\mathcal{P}=\{P_{R_{1}R_{2}\dots R_{N}}^{r}\}_{r=1}^{d}. If there exist completely positive and unital maps ΛRj:(Rj)(Aj)\Lambda_{R_{j}}:\ \mathcal{L}(\mathcal{H}_{R_{j}})\to\mathcal{L}(\mathcal{H}_{A_{j}^{\prime}}), for j{1,2,,N}j\in\{1,2,\dots,N\}, such that

ΛR1ΛR2ΛRN(PR1R2RNr)=PR1R2RNr,\Lambda_{R_{1}}\otimes\Lambda_{R_{2}}\otimes\dots\otimes\Lambda_{R_{N}}(P_{R_{1}R_{2}\dots R_{N}}^{r})=P_{R_{1}^{\prime}R_{2}^{\prime}\dots R_{N}^{\prime}}^{\prime r}, (2)

for all rr, we say 𝒫\mathcal{P} is capable of simulating 𝒫\mathcal{P}^{\prime}. In the above definition, we adopt the assumption that the different physical sources are independent in a quantum network. The construction of a quantum network as shown in Fig.  1 guarantees the well-defined NN-partition for Roy’s measurement device, i.e., R=R1R2RN\mathcal{H}_{R}=\mathcal{H}_{R_{1}}\otimes\mathcal{H}_{R_{2}}\otimes\dots\otimes\mathcal{H}_{R_{N}}.

The idea of our self-testing method relies on the task of entanglement swapping as shown in Fig.  1. There are NN initially uncorrelated parties Alice 11 (A1A_{1}), Alice 22 (A2A_{2}),\dots, Alice NN (ANA_{N}). They are independently entangled with an additional party, Roy. Specifically, the AiA_{i} and Roy share a Bell state |Bellπ/40AiRiAiRi,i{1,2,,N}|Bell^{0}_{\pi/4}\rangle_{A_{i}R_{i}}\in\mathcal{H}_{A_{i}}\otimes\mathcal{H}_{R_{i}},i\in\{1,2,\dots,N\}. To distribute entanglement between A1,A2,,ANA_{1},A_{2},\dots,A_{N} in such a quantum network, Roy performs the tilted GSM and obtains outcomes r{k1k2kN}r\in\{k_{1}k_{2}\dots k_{N}\} with k1,k2,,kN{0,1}k_{1},k_{2},\cdots,k_{N}\in\{0,1\}. For simplicity, we denote the outcomes as r{0,1,,2N1}r\in\{0,1,\dots,2^{N}-1\}. Then, the states shared by A1,A2,,ANA_{1},A_{2},\dots,A_{N} are projected to one of the 2N2^{N} tilted GHZ states |GHZθr|GHZ^{r}_{\theta}\rangle based on the outcome rr. The tilted GHZ states are measurement eigenstates of tilted GSM given by

|GHZθr=(1)i=1Nkicosθ|k1k2kN+sinθ|k¯1k¯2k¯N,\begin{split}|GHZ^{r}_{\theta}\rangle=(-1)^{\sum\limits_{i=1}^{N}k_{i}}&\cos\theta|k_{1}k_{2}\dots k_{N}\rangle+\sin\theta|\bar{k}_{1}\bar{k}_{2}\dots\bar{k}_{N}\rangle,\end{split}

where k¯i=1ki\bar{k}_{i}=1-k_{i} and ki{0,1},i{1,,N}k_{i}\in\{0,1\},\ i\in\{1,\dots,N\}. The tilted GSM can be denoted as GSMθ={GHZθr}r=02N1GSM_{\theta}=\{GHZ^{r}_{\theta}\}_{r=0}^{2^{N}-1}, with GHZθr=|GHZθrGHZθr|GHZ^{r}_{\theta}=|GHZ^{r}_{\theta}\rangle\langle GHZ^{r}_{\theta}|. If A1,A2,,ANA_{1},A_{2},\dots,A_{N} obtain the outcomes rr of Roy, they can apply a special local unitary operation on their qubits, so that they share a special tilted GHZ state. With the above operations, we have implemented distribution of entanglement between NN remote parties.

The self-testing procedure is similar to the task of entanglement swapping, without assumptions on the dimensions, initial states and operators. From now on, let us adopt labels on the same letter to make a distinction between two Hilbert spaces, e.g., QQ and QQ^{\prime}. Specially, the QQ^{\prime} is in a two-dimensional Hilbert space and the dimension of QQ is unknown. Let us start with presenting a self-testing method for NN-partite tilted GHZ states given in Ref.  [26].

   Lemma 1.

(Please Refer to Ref.  [26]). Suppose an NN-partite state |ψ|\psi\rangle, and a pair of binary observables A0,iA_{0,i}, A1,iA_{1,i} for the ii-th party, for i=1,,Ni=1,...,N. For an observable DD, let PDa=[I+(1)aD]/2,a{0,1}P_{D}^{a}=[I+(-1)^{a}D]/2,a\in\{0,1\}. Let μ\mu satisfy tanμ=sin2θ\tan\mu=\sin 2\theta, Zi=A0,iZ_{i}=A_{0,i}, and Xi=A1,iX_{i}=A_{1,i}, for i=1,,N1i=1,...,N-1. Then, let ZNZ_{N}^{*} be (A0,N+A1,N)/(2cosμ)(A_{0,N}+A_{1,N})/(2\cos\mu) with zero eigenvalues replaced by 1 and XNX_{N}^{*} be (A0,NA1,N)/(2sinμ)(A_{0,N}-A_{1,N})/(2\sin\mu) with zero eigenvalues replaced by 1. Define ZN=ZN|ZN|1Z_{N}=Z_{N}^{*}|Z_{N}^{*}|^{-1} and XN=XN|XN|1X_{N}=X_{N}^{*}|X_{N}^{*}|^{-1}. If the following relations are satisfied:

ψ|PA0,i0|ψ=ψ|PA0,i0PA0,j0|ψ=cθ2,i,j{1,,N1},\displaystyle\langle\psi|P_{A_{0,i}}^{0}|\psi\rangle=\langle\psi|P_{A_{0,i}}^{0}P_{A_{0,j}}^{0}|\psi\rangle=c_{\theta}^{2},\ \ \forall i,j\in\{1,...,N-1\},
ψ|i=1N2PA1,iai|ψ=12N2,ai{0,1},\displaystyle\langle\psi|\prod_{i=1}^{N-2}P_{A_{1,i}}^{a_{i}}|\psi\rangle=\frac{1}{2^{N-2}},\ \ \forall a_{i}\in\{0,1\},
ψ|(i=1N2PA1,iai)(αA0,N1IN+A0,N1A0,N+A0,N1A1,N+\displaystyle\langle\psi|(\prod_{i=1}^{N-2}P_{A_{1,i}}^{a_{i}})(\alpha A_{0,N-1}\otimes I_{N}+A_{0,N-1}A_{0,N}+A_{0,N-1}A_{1,N}+
(1)i=1N2ai(A1,N1A0,NA1,N1A1,N))|ψ=8+2α22N2,\displaystyle(-1)^{\sum_{i=1}^{N-2}a_{i}}(A_{1,N-1}A_{0,N}-A_{1,N-1}A_{1,N}))|\psi\rangle=\frac{\sqrt{8+2\alpha^{2}}}{2^{N-2}},
ai{0,1},\displaystyle\forall a_{i}\in\{0,1\},

where α=2cos2θ/1+sin22θ\alpha=2\cos 2\theta/\sqrt{1+\sin^{2}2\theta} and cθ=cosθ,θ(0,π/4]c_{\theta}=\cos\theta,\theta\in(0,\pi/4], there exists a local isometry Φ\Phi such that

Φ(|ψ)=|junk|GHZθ0,\Phi(|\psi\rangle)=|junk\rangle|GHZ_{\theta}^{0}\rangle,

for some junk state |junk|junk\rangle. Hence, these relations for correlations self-test the state |GHZθ0=cosθ|0N+sinθ|1N|GHZ_{\theta}^{0}\rangle=\cos\theta|0\rangle^{\otimes N}+\sin\theta|1\rangle^{\otimes N}.

The junk state in the Lemma 1 can be any state and can be removed by tracing out the A1A2ANA_{1}A_{2}\dots A_{N} space. It should be noted that this self-testing method is also suitable for a general ρ\rho [26]. Without loss of generality, let the NN-partite state be a pure state. Here, the ZNZ_{N} and XNX_{N} act on |ψ|\psi\rangle in the same way as (A0,N+A1,N)/(2cosμ)(A_{0,N}+A_{1,N})/(2\cos\mu) and (A0,NA1,N)/(2sinμ)(A_{0,N}-A_{1,N})/(2\sin\mu), respectively [38]. For details, the ideal measurements achieving these correlations in the Lemma 1 are: A0,i=σZA_{0,i}^{\prime}=\sigma_{Z}, A1,i=σXA_{1,i}^{\prime}=\sigma_{X}, for i=1,,N1i=1,\dots,N-1, and A0,N=cosμσZ+sinμσXA_{0,N}^{\prime}=\cos\mu\sigma_{Z}+\sin\mu\sigma_{X}, A1,N=cosμσZsinμσXA_{1,N}^{\prime}=\cos\mu\sigma_{Z}-\sin\mu\sigma_{X}.

From the Lemma 1, all partially entangled NN-partite GHZ states can be self-tested by checking whether the projected state of the remaining two parties (AN1A_{N-1} and ANA_{N}) maximally violates the tilted CHSH inequality. The remaining two parties are the parties after performing local measurements on the other N2N-2 parties. Moreover, for different r{0,1,,2N1}r\in\{0,1,\dots,2^{N}-1\}, the |GHZθr|GHZ_{\theta}^{r}\rangle can all be self-tested by correlations in the Lemma 1 with different measurement settings up to local isometries. In other words, one can obtain a local isometry, such that Φr(|ψr)=|junk|GHZθr,\Phi^{r}(|\psi^{r}\rangle)=|junk\rangle|GHZ_{\theta}^{r}\rangle, for each rr. As the isometry can always be constructed by local operations which does not depend on rr, one can always construct a single isometry, such that Φ(|ψr)=|junk|GHZθr.\Phi(|\psi^{r}\rangle)=|junk\rangle|GHZ_{\theta}^{r}\rangle. The detailed description will be shown in the next lemma.

Now, let us firstly introduce some notations. For an observable OO^{\prime} acting on Hilbert space =i=1NAi\mathcal{H}^{\prime}=\otimes_{i=1}^{N}\mathcal{H}_{A_{i}^{\prime}}, let O~r=UrOUr\widetilde{O^{\prime}}^{r}=U^{\prime r{\dagger}}O^{\prime}U^{\prime r}, where Ur=i=1NUAirU^{\prime r}=\otimes_{i=1}^{N}{U^{\prime r}_{A_{i}^{\prime}}} acting on \mathcal{H}^{\prime}. The Ai,i{1,2,,N}\mathcal{H}_{A_{i}^{\prime}},i\in\{1,2,\dots,N\}, are two dimensional Hilbert spaces. The unitary operator UrU^{\prime r} satisfies the equation Ur|GHZθr=|GHZθ0U^{\prime r}|GHZ^{r}_{\theta}\rangle=|GHZ^{0}_{\theta}\rangle and is constructed by the product of identity matrix II^{\prime}, and Pauli matrices X,ZX^{\prime},Z^{\prime}. Then, one can define O~r=UrOUr\widetilde{O}^{r}=U^{r{\dagger}}OU^{r} by replacing the I,X,ZI^{\prime},X^{\prime},Z^{\prime} in O~r\widetilde{O^{\prime}}^{r} with I,X,ZI,X,Z. By the above special unitary transformation, one can obtain following Lemma 2.

   Lemma 2.

Let |ψ|\psi\rangle be an NN-partite state, and let A0,iA_{0,i}, A1,iA_{1,i} be a pair of binary observables for the ii-th party, for i=1,,Ni=1,...,N. Suppose that, for all r{0,1,,2N1}r\in\{0,1,\dots,2^{N}-1\}, the following relations are satisfied:

ψ|PA0,i0~r|ψ=ψ|PA0,i0~rPA0,j0~r|ψ=cθ2,i,j{1,,N1},\displaystyle\langle\psi|\widetilde{P_{A_{0,i}}^{0}}^{r}|\psi\rangle=\langle\psi|\widetilde{P_{A_{0,i}}^{0}}^{r}\widetilde{P_{A_{0,j}}^{0}}^{r}|\psi\rangle=c^{2}_{\theta},\ \forall i,j\in\{1,...,N-1\}, (3)
ψ|i=1N2PA1,iai~r|ψ=12N2,ai{0,1},\displaystyle\langle\psi|\prod_{i=1}^{N-2}\widetilde{P_{A_{1,i}}^{a_{i}}}^{r}|\psi\rangle=\frac{1}{2^{N-2}},\ \ \forall a_{i}\in\{0,1\}, (4)
ψ|(i=1N2PA1,iai~r)Wa¯α~r|ψ=8+2α22N2,ai{0,1}\displaystyle\langle\psi|(\prod_{i=1}^{N-2}\widetilde{P_{A_{1,i}}^{a_{i}}}^{r})\widetilde{W_{\bar{a}}^{\alpha}}^{r}|\psi\rangle=\frac{\sqrt{8+2\alpha^{2}}}{2^{N-2}},\forall a_{i}\in\{0,1\} (5)

where a¯a1aN2\bar{a}\equiv a_{1}\dots a_{N-2} and

Wa¯α~0=Wa¯α=αA0,N1IN+A0,N1A0,N+A0,N1A1,N+(1)Σi=1N2ai(A1,N1A0,NA1,N1A1,N).\begin{split}\widetilde{W_{\bar{a}}^{\alpha}}^{0}=W_{\bar{a}}^{\alpha}=&\alpha A_{0,N-1}\otimes I_{N}+A_{0,N-1}A_{0,N}+A_{0,N-1}A_{1,N}+\\ &(-1)^{\Sigma_{i=1}^{N-2}a_{i}}(A_{1,N-1}A_{0,N}-A_{1,N-1}A_{1,N}).\end{split}

The detailed forms for PA0,i0~r,PA1,iai~r\widetilde{P_{A_{0,i}}^{0}}^{r},\widetilde{P_{A_{1,i}}^{a_{i}}}^{r} are easy to calculate and the details for Wa¯α~r\widetilde{W_{\bar{a}}^{\alpha}}^{r} as an example are provided in the Appendix B. The measurements here are the same as shown in the Lemma 1. Then, there exists a single local isometry such that Φ(|ψr)=|junk|GHZθr,\Phi(|\psi^{r}\rangle)=|junk\rangle|GHZ_{\theta}^{r}\rangle, for all rr.

Proof.

For r=0r=0, the correlations in the Lemma 2 are same as the Lemma 1. Hence these correlations self-test state |GHZθ0|GHZ^{0}_{\theta}\rangle. Denote |ψ|\psi\rangle in the self-testing procedure as |ψ0|\psi^{0}\rangle. From the Lemma 1, there exists a local isometry Φ\Phi such that Φ(|ψ0)=|junk|GHZθ0\Phi(|\psi^{0}\rangle)=|junk\rangle|GHZ^{0}_{\theta}\rangle. Meanwhile, Xf2=Zf2=IX_{f}^{2}=Z_{f}^{2}=I and Xf,ZfX_{f},Z_{f} anti-commute over the support of the state |ψ0|\psi^{0}\rangle, for all f{A1,A2,,AN}f\in\{A_{1},A_{2},\dots,A_{N}\} [26]. Then, one can construct this isometry by ancillary qubits |0N|0\rangle^{\otimes N} and swap gates {SXf,Zf}\{S_{X_{f},Z_{f}}\} as

Φ(|ψ0)=|junk|GHZθ0=(i=1NSXAi,ZAi)|0N|ψ0.\Phi(|\psi^{0}\rangle)=|junk\rangle|GHZ^{0}_{\theta}\rangle=(\otimes_{i=1}^{N}S_{X_{A_{i}},Z_{A_{i}}})|0\rangle^{\otimes N}|\psi^{0}\rangle. (6)

The detailed form of a swap gate is shown in Fig.  3. From the Lemma 1 in Ref.  [36], one knows that SXf,ZfX|0|ξf=XSXf,Zf|0|ξfS_{X_{f},Z_{f}}\cdot X\cdot|0\rangle|\xi_{f}\rangle=X^{\prime}\cdot S_{X_{f},Z_{f}}\cdot|0\rangle|\xi_{f}\rangle and SXf,ZfZ|0|ξf=ZSXf,Zf|0|ξfS_{X_{f},Z_{f}}\cdot Z\cdot|0\rangle|\xi_{f}\rangle=Z^{\prime}\cdot S_{X_{f},Z_{f}}\cdot|0\rangle|\xi_{f}\rangle. Let SA1A2AN=(i=1NSXAi,ZAi)S_{A_{1}A_{2}\dots A_{N}}=(\otimes_{i=1}^{N}S_{X_{A_{i}},Z_{A_{i}}}). As the UrU^{r} is constructed by I,X,ZI,X,Z, one has

Φ(Ur|ψ0)=SA1A2AN|0NUr|ψ0=UrSA1A2AN|0N|ψ0=UrΦ(|ψ0)=|junkUr|GHZθ0=|junk|GHZθr.\begin{split}\Phi(U^{r{\dagger}}|\psi^{0}\rangle)&=S_{A_{1}A_{2}\dots A_{N}}|0\rangle^{\otimes N}U^{r{\dagger}}|\psi^{0}\rangle\\ &=U^{\prime r{\dagger}}S_{A_{1}A_{2}\dots A_{N}}|0\rangle^{\otimes N}|\psi^{0}\rangle\\ &=U^{\prime r{\dagger}}\Phi(|\psi^{0}\rangle)=|junk\rangle\otimes U^{\prime r{\dagger}}|GHZ^{0}_{\theta}\rangle\\ &=|junk\rangle\otimes|GHZ^{r}_{\theta}\rangle.\end{split}

Here Ur|ψ0=|ψU^{r{\dagger}}|\psi^{0}\rangle=|\psi\rangle. One has Φ(|ψ)=|junk|GHZθr\Phi(|\psi\rangle)=|junk\rangle|GHZ^{r}_{\theta}\rangle. Therefore, the relations for correlations in the Lemma 2 self-test state |GHZθr|GHZ^{r}_{\theta}\rangle. The |ψ|\psi\rangle can be denoted as |ψr|\psi^{r}\rangle. Thus, one has Φ(|ψr)=|junk|GHZθr\Phi(|\psi^{r}\rangle)=|junk\rangle|GHZ^{r}_{\theta}\rangle

Refer to caption
Figure 3: Swap gate is constructed by unitary XX, ZZ and HH^{\prime}, where HH^{\prime} is the Hadamard gate, and XX, ZZ are anti-commute over the support of the state |ξf|\xi_{f}\rangle\in\mathcal{H}. The |0|0\rangle is in the qubit Hilbert space \mathcal{H}^{\prime}.

From the Lemma 2, self-testing method with fixed measurements can be used to distinguish special entangled pure states. Here, let {|GHZθr}r=02N1\{|GHZ_{\theta}^{r}\rangle\}_{r=0}^{2^{N}-1} be reference states and |GHZθ0|GHZ_{\theta}^{0}\rangle be a standard reference state. For example, there is a set of states {|ψs}s=02N1\{|\psi^{s}\rangle\}_{s=0}^{2^{N}-1} shared by A1,A2,,ANA_{1},A_{2},\dots,A_{N}. If one shared state |ψs1|\psi^{s_{1}}\rangle satisfies the correlations in the Lemma 2 with r=0r=0, one can specify the shared state |ψs1|\psi^{s_{1}}\rangle as state |ψ0|\psi^{0}\rangle according to standard reference state |GHZθ0|GHZ_{\theta}^{0}\rangle. Then, for another shared state |ψs2|\psi^{s_{2}}\rangle with s2{0,1,2,s11,s1+1,,2N1}s_{2}\in\{0,1,2,\dots s_{1}-1,s_{1}+1,\dots,2^{N}-1\} , if it satisfies correlations in the Lemma 2 for one rr with r{1,2,,2N1}r\in\{1,2,\dots,2^{N}-1\}, e.g., r=3r=3, then, one resets the s2s_{2} as s2=3s_{2}=3. In other words, the state |ψs2|\psi^{s_{2}}\rangle can be rewritten as |ψ3|\psi^{3}\rangle and these correlations have self-tested the |GHZθ3|GHZ_{\theta}^{3}\rangle. Therefore, the states |ψs1|\psi^{s_{1}}\rangle and |ψs2|\psi^{s_{2}}\rangle are actually different. Now, the main result of the paper is following.

Theorem 1.

Let A1,A2,,ANA_{1},A_{2},\dots,A_{N} share respectively a pair of quantum state with Roy as τA1R1A2R2ANRN=τA1R1τA2R2τANRN\tau_{A_{1}R_{1}A_{2}R_{2}\dots A_{N}R_{N}}=\tau_{A_{1}R_{1}}\otimes\tau_{A_{2}R_{2}}\otimes\cdots\otimes\tau_{A_{N}R_{N}} and let ={RR1R2RNr}r=02N1\mathcal{R}=\{R_{R_{1}R_{2}\cdots R_{N}}^{r}\}_{r=0}^{2^{N}-1} be a 2N2^{N}-outcome measurement acting on R1R2RN\mathcal{H}_{R_{1}}\otimes\mathcal{H}_{R_{2}}\otimes\cdots\otimes\mathcal{H}_{R_{N}}. For the A1,A2,,ANA_{1},A_{2},\dots,A_{N}, if there exist measurements such that the observed correlations conditioned on outcome rr of Roy’s measurement satisfy the relations in the Lemma 2, then there exist completely positive and unital maps ΛRi:(Ri)(Ai)\Lambda_{R_{i}}:\ \mathcal{L}(\mathcal{H}_{R_{i}})\to\mathcal{L}(\mathcal{H}_{A_{i}^{\prime}}), i{1,2,,N}i\in\{1,2,\dots,N\}, for dim(Ai)=2dim(\mathcal{H}_{A_{i}^{\prime}})=2 such that

ΛR1ΛR2ΛRN(RR1R2RNr)=GHZθr\Lambda_{R_{1}}\otimes\Lambda_{R_{2}}\otimes\cdots\otimes\Lambda_{R_{N}}(R_{R_{1}R_{2}\cdots R_{N}}^{r})=GHZ_{\theta}^{r} (7)

for r{0,1,2,,2N1}r\in\{0,1,2,\dots,2^{N}-1\}.

The detailed proof is shown in Appendix A. Here, we present a brief description. Let the τA1A2ANr=|ψrψr|\tau_{A_{1}A_{2}\dots A_{N}}^{r}=|\psi^{r}\rangle\langle\psi^{r}| acting on i=1Ni\otimes_{i=1}^{N}\mathcal{H}_{i} be the state shared by A1,A2,,ANA_{1},A_{2},\dots,A_{N} conditioned on outcome rr. From the Lemma 2, there exists a single isometry such that Φ(|ψr)=|junk|GHZθr\Phi(|\psi^{r}\rangle)=|junk\rangle|GHZ_{\theta}^{r}\rangle. By tracing out the subsystems 1,,N\mathcal{H}_{1},\dots,\mathcal{H}_{N}, one can construct a single pair of swap channels ΓAi:(Ai)(Ai),i{1,2,,N}\Gamma_{A_{i}}:\mathcal{L}(\mathcal{H}_{A_{i}})\to\mathcal{L}(\mathcal{H}_{A_{i}^{\prime}}),i\in\{1,2,\dots,N\}, such that

(i=1NΓAi)(τA1A2ANr)=|GHZθrGHZθr|,(\otimes_{i=1}^{N}\Gamma_{A_{i}})(\tau_{A_{1}A_{2}\dots A_{N}}^{r})=|GHZ_{\theta}^{r}\rangle\langle GHZ_{\theta}^{r}|,

for all rr. With the help of Choi-Jamiołkowski map [36], one can construct completely positive and unital maps which are associated with above swap channels, such that

(i=1NΛRi)(RR1R2RNr)=(i=1NΓAi)(τA1A2ANr)=GHZθr.\begin{split}(\otimes_{i=1}^{N}\Lambda_{R_{i}})(R_{R_{1}R_{2}\cdots R_{N}}^{r})=(\otimes_{i=1}^{N}\Gamma_{A_{i}})(\tau_{A_{1}A_{2}\dots A_{N}}^{r})=GHZ_{\theta}^{r}.\end{split}

The 2N2^{N} equations given by Eq.  (7) imply that a real measurement ={RR1RNr}r=02N1\mathcal{R}=\{R_{R_{1}\dots R_{N}}^{r}\}_{r=0}^{2^{N}-1} is capable of simulating ideal tilted GSM, {GHZθr}r=02N1\{GHZ_{\theta}^{r}\}_{r=0}^{2^{N}-1}, i.e., the Theorem 1 self-tests the tilted GSM. The method presents a unified form of the theorem for multipartite case without resorting to different Bell inequalities. Furthermore, one can also self-test multipartite GSM, if α=0,θ=π/4\alpha=0,\theta=\pi/4. Moreover, if N=3N=3, one can recover the case of three-qubit GSM [36].

Remarkably, for any self-testing method of tilted GHZ-states, if the ideal measurements in the self-testing procedure are constructed by Pauli matrices, it can be adopted to self-test tilted GSM. Such a property can be a rule to construct the self-testing method for tilted GSM.

4 Robust self-testing of the GSM

The ideal self-testing method is an excellent tool to device-independently certify quantum information tasks. However, due to the imperfection of quantum devices, the accurate correlations in the above theorem may not be satisfied. Hence, a robust version of self-testing is necessary from an experimental point of view. For convenience, we will study here a robust self-testing scheme of three-qubit GSM, where N=3,α=0,θ=π/4N=3,\alpha=0,\theta=\pi/4. The method for studying robustness of other cases is similar.

Before presenting the robustness of GSM, let us firstly study the robust self-testing of the GHZ state with semi-definite programs (SDP) method. One can rewrite A1,A2,A3A_{1},A_{2},A_{3} as A,B,CA,B,C and let Ai,1=Ai,Ai,2=Bi,Ai,3=Ci,i{0,1}A_{i,1}=A_{i},A_{i,2}=B_{i},A_{i,3}=C_{i},i\in\{0,1\}. Let the state shared by A,BA,\ B and CC with outcome r=0r=0 be τABC0=|ψ0ψ0|\tau_{ABC}^{0}=|\psi^{0}\rangle\langle\psi^{0}|. In a general way, one can adopt the fidelity F=GHZ|σABC0|GHZF=\langle GHZ|\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{0}|GHZ\rangle to capture the distance of the unknown state to the target state [42], where |GHZ=|000+|1112|GHZ\rangle=\frac{|000\rangle+|111\rangle}{\sqrt{2}} and σABC0=ΓAΓBΓC(τABC0)\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{0}=\Gamma_{A}\otimes\Gamma_{B}\otimes\Gamma_{C}(\tau_{ABC}^{0}). The maps Γf,f{A,B,C}\Gamma_{f},f\in\{A,B,C\} are defined from Fig.  3 as Γf(|ξfξ|)=Trf(SXf,Zf|00||ξfξ|SXf,Zf)\Gamma_{f}(|\xi\rangle_{f}\langle\xi|)=Tr_{\mathcal{H}_{f}}(S_{X_{f},Z_{f}}|0\rangle\langle 0|\otimes|\xi\rangle_{f}\langle\xi|S_{X_{f},Z_{f}}^{{\dagger}}) with f{A,B,C}f\in\{A,B,C\}. Here, the assumption that X,ZX,Z are anti-commutative in the definition of Γ\Gamma has been removed. The state σABC0\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{0} can be written as

σABC0=TrABC(SABC|000ABC000|τABC0SABC).\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{0}=Tr_{ABC}(S_{ABC}|000\rangle_{A^{\prime}B^{\prime}C^{\prime}}\langle 000|\otimes\tau_{ABC}^{0}S_{ABC}^{{\dagger}}). (8)

From the definition of fidelity, one has

F=GHZ|σABC0|GHZ=1128TrABC{8(1+ZA)(1+ZB)(1+ZC)τABC0+8(1ZA)(1ZB)(1ZC)τABC0+(Πf{A,B,C}(1+Zf)Xf(1Zf))τABC0+(Πf{A,B,C}(1Zf)Xf(1+Zf))τABC0},\begin{split}F&=\langle GHZ|\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{0}|GHZ\rangle\\ &=\frac{1}{128}Tr_{ABC}\{8(1+Z_{A})(1+Z_{B})(1+Z_{C})\tau_{ABC}^{0}\\ &\quad+8(1-Z_{A})(1-Z_{B})(1-Z_{C})\tau_{ABC}^{0}\\ &\quad+(\Pi_{f\in\{A,B,C\}}(1+Z_{f})X_{f}(1-Z_{f}))\tau_{ABC}^{0}\\ &\quad+(\Pi_{f\in\{A,B,C\}}(1-Z_{f})X_{f}(1+Z_{f}))\tau_{ABC}^{0}\},\end{split} (9)

where the fidelity can be expressed as a linear function of the expectation values. Suppose the channel suffers with white noise (weight ϵ\epsilon), one can transform the problem of robustness into the problem that finding a lower bound on the fidelity. It can be solved by SDP [24, 42, 43, 44]:

minF=GHZ|σABC0|GHZ,s.t.M0,ψ|PA00|ψ=ψ|PB00|ψ=12,ψ|PA00PB00|ψ=1ϵ2+ϵ4,ψ|PA1a|ψ=12,fora{0,1},ψ|PA1a(αB0+B0C0+B0C1+(1)a(B1C0B1C1))|ψ=2(1ϵ),\begin{split}&min\ \ F=\langle GHZ|\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{0}|GHZ\rangle,\\ &s.t.\ \ M\geq 0,\\ &\qquad\langle\psi|P_{A_{0}}^{0}|\psi\rangle=\langle\psi|P_{B_{0}}^{0}|\psi\rangle=\frac{1}{2},\\ &\qquad\langle\psi|P_{A_{0}}^{0}P_{B_{0}}^{0}|\psi\rangle=\frac{1-\epsilon}{2}+\frac{\epsilon}{4},\\ &\qquad\langle\psi|P_{A_{1}}^{a}|\psi\rangle=\frac{1}{2},\ \ for\ a\in\{0,1\},\\ &\qquad\langle\psi|P_{A_{1}}^{a}(\alpha B_{0}+B_{0}C_{0}+B_{0}C_{1}\\ &\qquad+(-1)^{a}(B_{1}C_{0}-B_{1}C_{1}))|\psi\rangle=\sqrt{2}(1-\epsilon),\end{split} (10)

where MM is a moment matrix defined by Mij=Tr(τABC0DiDj)M_{ij}=Tr(\tau_{ABC}^{0}D_{i}^{{\dagger}}D_{j}) with set {D1=I,D2=ZA,D3=XA}\{D_{1}=I,D_{2}=Z_{A},D_{3}=X_{A}\dots\} [45]. For an ideal case, the fidelity is 1 when error ϵ=0\epsilon=0. For other ϵ\epsilon up to 0.1225, the relations between minimal fidelity and error are shown in Fig.  4. Thus, the Fig.  4 gives a lower bound of fidelity for different ϵ\epsilon. Without loss of generality, one can define the relation between minimal fidelity and ϵ\epsilon as a function G(ϵ0)G(\epsilon^{0}), which will be used to study the robustness of GSM. Here, the ϵ\epsilon has been rewritten as ϵ0\epsilon^{0}.

Refer to caption
Figure 4: The lower bound on the fidelity FF between GHZ state and unknown state σABC0\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{0} for different white noise ϵ\epsilon. When the fidelity is above the nontrivial bound of 0.50.5 (i.e., ϵ12.25%\epsilon\leq 12.25\%), the unknown state is close to a GHZ state.

For defining quality of real measurement \mathcal{R} as a simulation of ideal GSM 𝒫\mathcal{P}, where ={RR1R2R3r}07\mathcal{R}=\{R_{R_{1}R_{2}R_{3}}^{r}\}_{0}^{7} and 𝒫={GHZr}07\mathcal{P}=\{GHZ^{r}\}_{0}^{7}, we directly extend the definition in Ref.  [36] to three parties as

𝒬(,𝒫)=18×maxΛR1ΛR2ΛR3r=07(ΛR1ΛR2ΛR3)(RR1R2R3r),GHZr.\begin{split}&\mathcal{Q}(\mathcal{R},\mathcal{P})\\ &=\frac{1}{8}\times\mathop{max}\limits_{\Lambda_{R_{1}}\Lambda_{R_{2}}\Lambda_{R_{3}}}\sum\limits_{r=0}^{7}\langle(\Lambda_{R_{1}}\otimes\Lambda_{R_{2}}\otimes\Lambda_{R_{3}})(R_{R_{1}R_{2}R_{3}}^{r}),GHZ^{r}\rangle.\end{split} (11)

Here, we omit the subscript of GHZπ4rGHZ_{\frac{\pi}{4}}^{r} as GHZrGHZ^{r} and ΛR1,ΛR2,ΛR3\Lambda_{R_{1}},\ \Lambda_{R_{2}},\ \Lambda_{R_{3}} are unital CPTP maps with ΛR1:(R1)(A),ΛR2:(R2)(B),ΛR3:(R3)(C)\Lambda_{R_{1}}:\ \mathcal{L}(\mathcal{H}_{R_{1}})\to\mathcal{L}(\mathcal{H}_{A^{\prime}}),\ \Lambda_{R_{2}}:\ \mathcal{L}(\mathcal{H}_{R_{2}})\to\mathcal{L}(\mathcal{H}_{B^{\prime}}),\ \Lambda_{R_{3}}:\ \mathcal{L}(\mathcal{H}_{R_{3}})\to\mathcal{L}(\mathcal{H}_{C^{\prime}}). The symbol ,\langle\ ,\ \rangle for two matrices L1L_{1} and L2L_{2} implies

L1,L2=Tr(L1L2).\langle L_{1},L_{2}\rangle=Tr(L_{1}L_{2}^{{\dagger}}).

Now, the robust version of self-testing method is presented as following.

Theorem 2.

Let A,B,CA,\ B,\ C share a pair of quantum state with Roy respectively as τAR1BR2CR3=τAR1τBR2τCR3\tau_{AR_{1}BR_{2}CR_{3}}=\tau_{AR_{1}}\otimes\tau_{BR_{2}}\otimes\tau_{CR_{3}} and let ={RR1R2R3r}r=07\mathcal{R}=\{R_{R_{1}R_{2}R_{3}}^{r}\}_{r=0}^{7} be a 8-outcome measurement acting on R1R2R3\mathcal{H}_{R_{1}}\otimes\mathcal{H}_{R_{2}}\otimes\mathcal{H}_{R_{3}}. Let prp_{r} be the probability of Roy observing the outcome rr. Define the function G(ϵr)G(\epsilon^{r}) as the lower bound on the fidelity between ΓAΓBΓC(τABCr)\Gamma_{A}\otimes\Gamma_{B}\otimes\Gamma_{C}(\tau_{ABC}^{r}) and GHZrGHZ^{r} under noise ϵr\epsilon^{r}. For A,BA,\ B and CC, suppose there exist measurements, such that the observed correlations conditioned on outcomes rr satisfy the relations in the Lemma 2 with error ϵr\epsilon^{r} and G(ϵr)>0.5G(\epsilon^{r})>0.5. Define q=ΣrprG(ϵr)q=\Sigma_{r}p_{r}G(\epsilon^{r}), then one has

𝒬(,𝒫)12(1+2q(1q))2minu[0,2q(1q)](2q1(1u2)+1(1+u)).\begin{split}\mathcal{Q}(\mathcal{R},&\mathcal{P})\geq\frac{1}{2(1+2\sqrt{q(1-q)})^{2}}\cdot\\ &\mathop{min}\limits_{u\in[0,2\sqrt{q(1-q)}]}(\frac{2q-1}{\sqrt{(1-u^{2})}}+\frac{1}{(1+u)}).\end{split} (12)

The detailed proof is given in Appendix C. One can always let every ϵr\epsilon^{r} be max{ϵr}r=07max\{\epsilon^{r}\}_{r=0}^{7} and denote it as ϵ\epsilon. Then, one has q=G(ϵ)q=G(\epsilon), which can be obtained by numerical method of SDP problem. The relation between quality of unknown real measurement and the noise ϵ=max{ϵr}r=07\epsilon=max\{\epsilon^{r}\}_{r=0}^{7} is shown in Fig.  5. Thus, we have shown the robust self-testing scheme of the GSM with the noise tolerance up to  0.28%\leavevmode\nobreak\ 0.28\%. From the definition of quality 𝒬(,𝒫)\mathcal{Q}(\mathcal{R},\mathcal{P}) (11), it should go through all possible unital CPTP maps ΛR1,ΛR2,ΛR3\Lambda_{R_{1}},\ \Lambda_{R_{2}},\ \Lambda_{R_{3}} and then choose the maximal value. However, our result is currently based on only one choice of these maps. Hence, if one optimizes this question and finds the maximum result, a better robustness can be expected. With the help of SDP method, one can straightforwardly obtain the robust version of our self-testing method for multipartite tilted GSM, similar to the robust self-testing method done for three-qubit GSM here.

Refer to caption
Figure 5: The lower bound on the quality of the unknown real measurement is numerically estimated as a function about the weight of white noise ϵ\epsilon. When the weight of white noise ϵ0.28%\epsilon\leq 0.28\% (i.e., the quality is above the nontrivial bound of 0.5), the presented procedure guarantees the unknown measurement is close to a three-qubit GHZ-state measurement.

5 Conclusion

In quantum network, it is extremely vital to certify multipartite entangled measurements. Here, we have presented the first self-testing method for the important class of general GHZ-state measurements. The procedure is operational for arbitrary number of parties from experimental point of views, and does not resort to the common method of verifying NN-partite Bell inequalities. Meanwhile, the approach can recover the case of three-qubit GHZ-state measurement directly. In addition, we have provided robustness of the self-testing procedure with the help of semi-definite program. The noise tolerance is up to 0.28%\% when certifying a three-qubit GHZ-state measurement.

For future works, it is interesting to develop more robust method to open the possibility to estimate the robustness of arbitrary multipartite entangled measurements, and enable experiments about self-testing quantum networks. It is expected that our approach can also be extended to high dimensional case, as the self-testing method done for high dimensional entangled states [26].

6 Acknowledgements

We sincerely thank Xinhui Li for insightful discussions about the technology of semi-definite programs. This work has been supported by the National Natural Science Foundation of China (Grants No. 62031024, 11874346), the National Key R&\&D Program of China (2019YFA0308700) and the Anhui Initiative in Quantum Information Technologies (AHY060200).

Appendix A: Proof of the Theorem 1

As shown in the Theorem 1, if the observed correlations conditioned on outcome of Roy’s measurement satisfy the relations in the Lemma 2, the measurement performed by Roy is a tilted GHZ-state measurement. Now, let us present the detailed proof of it.

Proof.

Let prp_{r} be the probability of Roy observing the outcome rr, and τA1A2ANr=|ψrA1A2ANψr|\tau^{r}_{A_{1}A_{2}\dots A_{N}}=|\psi^{r}\rangle_{A_{1}A_{2}\dots A_{N}}\langle\psi^{r}| be the state shared between A1ANA_{1}\dots A_{N} conditioned on outcome r{0,,2N1}r\in\{0,\dots,2^{N}-1\}, i.e., prτA1ANr=TrR1R2RN[(IA1A2ANRR1R2RNr)(i=1NτAiRi)]p_{r}\tau_{A_{1}\dots A_{N}}^{r}=Tr_{R_{1}R_{2}\dots R_{N}}[(I_{A_{1}A_{2}\dots A_{N}}\otimes R_{R_{1}R_{2}\dots R_{N}}^{r})(\otimes_{i=1}^{N}\tau_{A_{i}R_{i}})]. One can always choose pr=12Np_{r}=\frac{1}{2^{N}}. By the definition of swap gate in Fig.  3, one can construct swap channels as

Γf(|ξfξ|)=Trf(SXf,Zf|00||ξfξ|SXf,Zf),\Gamma_{f}(|\xi\rangle_{f}\langle\xi|)=Tr_{\mathcal{H}_{f}}(S_{X_{f},Z_{f}}|0\rangle\langle 0|\otimes|\xi\rangle_{f}\langle\xi|S_{X_{f},Z_{f}}^{{\dagger}}),

where f{A1,A2,AN}f\in\{A_{1},A_{2},\dots A_{N}\}. Define

σAiRiΓAi(τAiRi),i{1,2,,N},σA1A2ANr(i=1NΓAi)(τA1A2ANr)=(1pr)TrR1R2RN(RR1R2RNr(i=1NσAiRi))=(2N)TrR1R2RN(RR1R2RNr(i=1NσAiRi)).\begin{split}&\sigma_{A_{i}^{\prime}R_{i}}\equiv\Gamma_{A_{i}}(\tau_{A_{i}R_{i}}),i\in\{1,2,\dots,N\},\\ &\sigma_{A_{1}^{\prime}A_{2}^{\prime}\dots A_{N}^{\prime}}^{r}\equiv(\otimes_{i=1}^{N}\Gamma_{A_{i}})(\tau_{A_{1}A_{2}\dots A_{N}}^{r})\\ &\quad\quad\ \ \ =(\frac{1}{p_{r}})Tr_{R_{1}R_{2}\dots R_{N}}(R_{R_{1}R_{2}\dots R_{N}}^{r}(\otimes_{i=1}^{N}\sigma_{A_{i}^{\prime}R_{i}}))\\ &\quad\quad\ \ \ =(2^{N})Tr_{R_{1}R_{2}\dots R_{N}}(R_{R_{1}R_{2}\dots R_{N}}^{r}(\otimes_{i=1}^{N}\sigma_{A_{i}^{\prime}R_{i}})).\end{split} (A1)

Then, one has

(ΓA1ΓA2ΓAN)(τA1A2ANr)=TrA1A2AN(SA1A2AN|0A1ANN0|NτA1A2ANrSA1A2AN)=TrA1A2AN(SA1A2AN|0A1ANN|ψr0|Nψr|SA1A2AN)=TrA1A2AN(|junkA1A2ANjunk||GHZθrGHZθr|)=|GHZθrGHZθr|.\begin{split}&\quad(\Gamma_{A_{1}}\otimes\Gamma_{A_{2}}\otimes\dots\otimes\Gamma_{A_{N}})(\tau_{A_{1}A_{2}\dots A_{N}}^{r})\\ &=Tr_{A_{1}A_{2}\dots A_{N}}(S_{A_{1}A_{2}\dots A_{N}}|0\rangle^{\otimes N}_{A_{1}^{\prime}\dots A_{N}^{\prime}}\langle 0|^{\otimes N}\otimes\tau_{A_{1}A_{2}\dots A_{N}}^{r}S_{A_{1}A_{2}\dots A_{N}}^{{\dagger}})\\ &=Tr_{A_{1}A_{2}\dots A_{N}}(S_{A_{1}A_{2}\dots A_{N}}|0\rangle^{\otimes N}_{A_{1}^{\prime}\dots A_{N}^{\prime}}|\psi\rangle^{r}\langle 0|^{\otimes N}\langle\psi^{r}|S_{A_{1}A_{2}\dots A_{N}}^{{\dagger}})\\ &=Tr_{A_{1}A_{2}\dots A_{N}}(|junk\rangle_{A_{1}A_{2}\dots A_{N}}\langle junk|\otimes|GHZ_{\theta}^{r}\rangle\langle GHZ_{\theta}^{r}|)\\ &=|GHZ_{\theta}^{r}\rangle\langle GHZ_{\theta}^{r}|.\end{split} (A2)

The third equality is from the Lemma 2. From the definition of the state σA1A2ANr\sigma_{A_{1}^{\prime}A_{2}^{\prime}\dots A_{N}^{\prime}}^{r}, one has

σA1A2ANr=GHZθr,\sigma_{A_{1}^{\prime}A_{2}^{\prime}\dots A_{N}^{\prime}}^{r}=GHZ_{\theta}^{r},

for all r{0,1,,2N1}r\in\{0,1,\dots,2^{N}-1\}. Let us firstly present the definition of Choi-Jamiołkowski map [36]. If ρAB\rho_{AB} acts on AB\mathcal{H}_{A}\otimes\mathcal{H}_{B}, the Choi-Jamiołkowski map (ΛB:BA\Lambda_{B}:\mathcal{H}_{B}\to\mathcal{H}_{A}) associated to it is defined by ΛB(σB)=TrB[(IAσBT)ρAB]\Lambda_{B}(\sigma_{B})=Tr_{B}[(I_{A}\otimes\sigma_{B}^{T})\rho_{AB}] for σB\forall\sigma_{B}. Here, ρAB\rho_{AB} is the Choi state and can be unnormalized. Now, let ΛRi:(Ri)(Ai)\Lambda_{R_{i}}:\ \mathcal{L}(\mathcal{H}_{R_{i}})\to\mathcal{L}(\mathcal{H}_{A_{i}^{\prime}}), be respectively the Choi-Jamiołkowski maps associated to the operators 2σAiRi,i{1,2,,N}2\sigma_{A_{i}^{\prime}R_{i}},i\in\{1,2,\dots,N\}. By decomposing the operator RR1R2RNrR_{R_{1}R_{2}\dots R_{N}}^{r} as RR1R2RNr=Σlkωk,lrR_{R_{1}R_{2}\dots R_{N}}^{r}=\Sigma_{l}\bigotimes_{k}\omega_{k,l}^{r}, where ωk,lr\omega_{k,l}^{r} is the operator of Rk\mathcal{H}_{R_{k}}, one has ΛR1ΛR2ΛRN(RR1R2RNr)=(2N)TrR1R2RN(RR1R2RNr(i=1NσAiRi))=σA1A2ANr=GHZθr\Lambda_{R_{1}}\otimes\Lambda_{R_{2}}\otimes\dots\otimes\Lambda_{R_{N}}(R_{R_{1}R_{2}\dots R_{N}}^{r})=(2^{N})Tr_{R_{1}R_{2}\dots R_{N}}(R_{R_{1}R_{2}\dots R_{N}}^{r}(\otimes_{i=1}^{N}\sigma_{A_{i}^{\prime}R_{i}}))=\sigma_{A_{1}^{\prime}A_{2}^{\prime}\dots A_{N}^{\prime}}^{r}=GHZ_{\theta}^{r}. Moreover, we will prove that these Choi maps ΛRi,i{1,2,,N}\Lambda_{R_{i}},i\in\{1,2,\dots,N\}, are unital maps. Let us first consider ΛR1\Lambda_{R_{1}}, the other cases being similar. By the definition of Choi-Jamiołkowski map, one has

ΛR1(IR1)=TrR1(2σA1R1)=2TrR1R2RNA2AN(i=1NσAiRi)=2Σr=02N1TrR1R2RNA2AN(RR1R2R3r(i=1NσAiRi))=12N1Σr=02N1TrA2AN(σA1A2ANr)=IA1,\begin{split}\Lambda_{R_{1}}(I_{R_{1}})&=Tr_{R_{1}}(2\sigma_{A_{1}^{\prime}R_{1}})\\ &=2Tr_{R_{1}R_{2}\dots R_{N}A_{2}^{\prime}\dots A_{N}^{\prime}}(\otimes_{i=1}^{N}\sigma_{A_{i}^{\prime}R_{i}})\\ &=2\Sigma_{r=0}^{2^{N}-1}Tr_{R_{1}R_{2}\dots R_{N}A_{2}^{\prime}\dots A_{N}^{\prime}}(R_{R_{1}R_{2}R_{3}}^{r}(\otimes_{i=1}^{N}\sigma_{A_{i}^{\prime}R_{i}}))\\ &=\frac{1}{2^{N-1}}\Sigma_{r=0}^{2^{N}-1}Tr_{A_{2}^{\prime}\dots A_{N}^{\prime}}(\sigma_{A_{1}^{\prime}A_{2}^{\prime}\dots A_{N}^{\prime}}^{r})=I_{A_{1}^{\prime}},\end{split}

where we have used the fact that Σr=02N1RR1R2RNr=I\Sigma_{r=0}^{2^{N}-1}R_{R_{1}R_{2}\dots R_{N}}^{r}=I and σA1A2ANr=GHZθr\sigma_{A_{1}^{\prime}A_{2}^{\prime}\dots A_{N}^{\prime}}^{r}=GHZ_{\theta}^{r}. ∎

Therefore, we have proven that the joint measurement performed by central node Roy is actually a tilted GHZ-state measurement under the conditions in the Lemma 2.

Appendix B: The detailed form of Wa¯α~r\widetilde{W_{\bar{a}}^{\alpha}}^{r} in the Lemma 2

In the Lemma 2, a new form of self-testing statement has been presented. The notation “~r{\widetilde{\quad}}^{r}” in the O~r{\widetilde{O}}^{r} means that local unitary transformations are performed on the observable OO. Here, we will provide the details of Wa¯α~r\widetilde{W_{\bar{a}}^{\alpha}}^{r}, where a¯=a1aN2\bar{a}=a_{1}\cdots a_{N-2}. For convenience, let N=3N=3. Rewrite A1,A2,A3A_{1},\ A_{2},\ A_{3} as A,B,CA,\ B,\ C and let Ai,1=Ai,Ai,2=Bi,Ai,3=Ci,i{0,1}A_{i,1}=A_{i},\ A_{i,2}=B_{i},\ A_{i,3}=C_{i},\ i\in\{0,1\}. Now, the a¯\bar{a} is a1a_{1}, and rewritten as a{0,1}a\in\{0,1\}. The W0αW_{0}^{\alpha} and W1αW_{1}^{\alpha} can been obtained from the Lemma 2 as W0α=αB0I+B0C0+B0C1+B1C0B1C1,W1α=αB0I+B0C0+B0C1B1C0+B1C1W_{0}^{\alpha}=\alpha B_{0}\otimes I+B_{0}C_{0}+B_{0}C_{1}+B_{1}C_{0}-B_{1}C_{1},W_{1}^{\alpha}=\alpha B_{0}\otimes I+B_{0}C_{0}+B_{0}C_{1}-B_{1}C_{0}+B_{1}C_{1}. Firstly, by adding superscript in the formula of W0αW_{0}^{\alpha} and W1αW_{1}^{\alpha}, one has W0α=αB0+W0,W1α=αB0+W1W_{0}^{\prime\alpha}=\alpha B_{0}^{\prime}+W_{0}^{\prime},W_{1}^{\prime\alpha}=\alpha B_{0}^{\prime}+W_{1}^{\prime}, where W0=B0C0+B0C1+B1C0B1C1,W1=B0C0+B0C1B1C0+B1C1W_{0}^{\prime}=B_{0}^{\prime}C_{0}^{\prime}+B_{0}^{\prime}C_{1}^{\prime}+B_{1}^{\prime}C_{0}^{\prime}-B_{1}^{\prime}C_{1}^{\prime},\ W_{1}^{\prime}=B_{0}^{\prime}C_{0}^{\prime}+B_{0}^{\prime}C_{1}^{\prime}-B_{1}^{\prime}C_{0}^{\prime}+B_{1}^{\prime}C_{1}^{\prime}. From the Lemma 1, one knows that B0=Z,B1=XB_{0}^{\prime}=Z^{\prime},B_{1}^{\prime}=X^{\prime} and C0=cosμZ+sinμX,C1=cosμZsinμXC_{0}^{\prime}=\cos\mu Z^{\prime}+\sin\mu X^{\prime},C_{1}^{\prime}=\cos\mu Z^{\prime}-\sin\mu X^{\prime} with tanμ=sin2θ\tan\mu=\sin 2\theta. The local unitary transformation performed on WaαW_{a}^{\prime\alpha} is Ur=UArUBCrU^{\prime r}=U_{A^{\prime}}^{\prime r}\otimes U^{\prime r}_{B^{\prime}C^{\prime}}. As the UrU^{\prime r} is the local unitary transformation between tilted GHZ states, one can always choose UBCr{XX,IX,XI,II}U^{\prime r}_{B^{\prime}C^{\prime}}\in\{X^{\prime}\otimes X^{\prime},I^{\prime}\otimes X^{\prime},X^{\prime}\otimes I^{\prime},I^{\prime}\otimes I^{\prime}\}. For r=7r=7 case, one has XZXX|GHZθ7=|GHZθ0X^{\prime}Z^{\prime}\otimes X^{\prime}\otimes X^{\prime}|GHZ_{\theta}^{7}\rangle=|GHZ_{\theta}^{0}\rangle, where |GHZθ7=sinθ|000cosθ|111|GHZ_{\theta}^{7}\rangle=\sin\theta|000\rangle-\cos\theta|111\rangle and |GHZθ0=cosθ|000+sinθ|111|GHZ_{\theta}^{0}\rangle=\cos\theta|000\rangle+\sin\theta|111\rangle. Here, the U7=XZXXU^{\prime 7}=X^{\prime}Z^{\prime}\otimes X^{\prime}\otimes X^{\prime}. Thus, W0α~7=U7W0αU7=αB0+W0\widetilde{W_{0}^{\prime\alpha}}^{7}=U^{\prime 7{\dagger}}W_{0}^{\prime\alpha}U^{\prime 7}=-\alpha B_{0}^{\prime}+W_{0}^{\prime} and W1α~7=U7W1αU7=αB0+W1\widetilde{W_{1}^{\prime\alpha}}^{7}=U^{\prime 7{\dagger}}W_{1}^{\prime\alpha}U^{\prime 7}=-\alpha B_{0}^{\prime}+W_{1}^{\prime}. After calculating Waα~r\widetilde{W_{a}^{\prime\alpha}}^{r} for all r{0,1,,7}r\in\{0,1,\dots,7\} and a{0,1}a\in\{0,1\}, the detailed formulas of Waα~r\widetilde{W_{a}^{\prime\alpha}}^{r} can be obtained. By replacing the symbols I,Bi,Ci,i{0,1}I^{\prime},B_{i}^{\prime},C_{i}^{\prime},i\in\{0,1\} in Waα~r\widetilde{W_{a}^{\prime\alpha}}^{r} with I,Bi,Ci,i{0,1}I,B_{i},C_{i},i\in\{0,1\}, one can obtain the detailed form of Waα~r\widetilde{W_{a}^{\alpha}}^{r}.

In short, the Wa¯α~r\widetilde{W_{\bar{a}}^{\alpha}}^{r} is acquired by deleting the superscript prime of Wa¯α~r\widetilde{W_{\bar{a}}^{\prime\alpha}}^{r}. The Wa¯α~r\widetilde{W_{\bar{a}}^{\prime\alpha}}^{r} is obtained by performing local unitary transformations on Wa¯αW_{\bar{a}}^{\prime\alpha}. The local unitary transformation depends on the transformation between states |GHZθr|GHZ_{\theta}^{r}\rangle and |GHZθ0|GHZ_{\theta}^{0}\rangle. Therefore, one can easily write the detailed form of Wa¯α~r\widetilde{W_{\bar{a}}^{\alpha}}^{r} in the Lemma 2.

Appendix C: Proof of the Theorem 2

In this section, we give a proof of the Theorem 2 that shows the robust self-testing of three-qubit GHZ-state measurement. If the observed correlations can not perfectly satisfy the conditions in the Lemma 2, one can not adopt the ideal self-testing method presented in the Theorem 1 directly. We should bound the quality of the unknown measurement under the certain white noise, i.e., study how close the unknown measurement performed by Roy to ideal three-qubit GHZ-state measurement. Before presenting proof of the Theorem 2, we firstly generalize the result of semi-definite program in main text as following lemma.

   Lemma 3.

Let A0,A1,B0,B1,C0,C1A_{0},\ A_{1},\ B_{0},\ B_{1},\ C_{0},\ C_{1}, be the pairs of observables for the three parties. If the correlations in the Lemma 2 with error ϵr\epsilon^{r} (θ=π/4,α=0\theta=\pi/4,\alpha=0) satisfy the following relations:

ψ|PA00~r|ψ=ψ|PB00~r|ψ=12,\displaystyle\langle\psi|\widetilde{P_{A_{0}}^{0}}^{r}|\psi\rangle=\langle\psi|\widetilde{P_{B_{0}}^{0}}^{r}|\psi\rangle=\frac{1}{2}, (C1)
ψ|PA00~rPB00~r|ψ=(1ϵr)2+ϵr4,\displaystyle\langle\psi|\widetilde{P_{A_{0}}^{0}}^{r}\widetilde{P_{B_{0}}^{0}}^{r}|\psi\rangle=\frac{(1-\epsilon^{r})}{2}+\frac{\epsilon^{r}}{4}, (C2)
ψ|PA1a~r|ψ=12,fora{0,1},\displaystyle\langle\psi|\widetilde{P_{A_{1}}^{a}}^{r}|\psi\rangle=\frac{1}{2},\ \ for\ a\in\{0,1\}, (C3)
ψ|PA1a~rWaα~r|ψ=2(1ϵr),a{0,1},\displaystyle\langle\psi|\widetilde{P_{A_{1}}^{a}}^{r}\widetilde{W_{a}^{\alpha}}^{r}|\psi\rangle=\sqrt{2}(1-\epsilon^{r}),\ \ \ a\in\{0,1\}, (C4)

then there exist fixed CPTP maps ΓA,ΓB,ΓC\Gamma_{A},\Gamma_{B},\Gamma_{C} as shown in Appendix A, such that

F((ΓAΓBΓC)(τABCr),GHZABCr)G(ϵr),F((\Gamma_{A}\otimes\Gamma_{B}\otimes\Gamma_{C})(\tau_{ABC}^{r}),GHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}})\geq G(\epsilon^{r}),

for all r{0,1,,7}r\in\{0,1,\dots,7\}. The function G(x)G(x) is defined in main text as a function about lower bound of fidelity and white noise ϵr\epsilon^{r}. It is a numerical solution from SDP.

Proof.

For r=0r=0, we have given the detailed process of SDP to derive this result in Sec. 4. The CPTP maps are fixed for all r{0,1,,7}r\in\{0,1,\dots,7\}. For different rr, the observables in above correlations are all equivalent to the r=0r=0 case, up to local unitary transformations. Thus, the lower bound of fidelity for different rr have the same form, i.e., they have a same function G(x)G(x). ∎

Now, we start to prove the Theorem 2 that finding the lower bound on the quality of the unknown real measurement {RR1R2R3r}r=07\{R_{R_{1}R_{2}R_{3}}^{r}\}_{r=0}^{7}. As GHZABCrGHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}} are pure states and from Eq.  (A1), one has

prF((ΓAΓBΓC)(τABCr),GHZABCr)=pr(ΓAΓBΓC)(τABCr),GHZABCr=σAR1σBR2σCR3,GHZABCrRR1R2R3r.\begin{split}&\quad p_{r}F((\Gamma_{A}\otimes\Gamma_{B}\otimes\Gamma_{C})(\tau_{ABC}^{r}),GHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}})\\ &=p_{r}\langle(\Gamma_{A}\otimes\Gamma_{B}\otimes\Gamma_{C})(\tau_{ABC}^{r}),GHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}}\rangle\\ &=\langle\sigma_{A^{\prime}R_{1}}\otimes\sigma_{B^{\prime}R_{2}}\otimes\sigma_{C^{\prime}R_{3}},GHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}}\otimes R_{R_{1}R_{2}R_{3}}^{r}\rangle.\end{split}

From the Lemma 3, there is

σAR1σBR2σCR3,GHZABCrRR1R2R3rprG(ϵr).\langle\sigma_{A^{\prime}R_{1}}\otimes\sigma_{B^{\prime}R_{2}}\otimes\sigma_{C^{\prime}R_{3}},GHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}}\otimes R_{R_{1}R_{2}R_{3}}^{r}\rangle\geq p_{r}G(\epsilon^{r}). (C5)

To derive the main result, one should construct unital CPTP maps ΛR1:(R1)(A)\Lambda_{R_{1}}:\ \mathcal{L}(\mathcal{H}_{R_{1}})\to\mathcal{L}(\mathcal{H}_{A^{\prime}}), ΛR2:(R2)(B)\Lambda_{R_{2}}:\ \mathcal{L}(\mathcal{H}_{R_{2}})\to\mathcal{L}(\mathcal{H}_{B^{\prime}}) and ΛR3:(R3)(C)\Lambda_{R_{3}}:\ \mathcal{L}(\mathcal{H}_{R_{3}})\to\mathcal{L}(\mathcal{H}_{C^{\prime}}), and then find the lower bound on ΛR1ΛR2ΛR3(RR1R2R3r),GHZABCr\langle\Lambda_{R_{1}}\otimes\Lambda_{R_{2}}\otimes\Lambda_{R_{3}}(R_{R_{1}R_{2}R_{3}}^{r}),GHZ_{A^{\prime}B^{\prime}C^{\prime}}^{r}\rangle. Let λAR1,λBR2\lambda_{A^{\prime}R_{1}},\lambda_{B^{\prime}R_{2}} and λCR3\lambda_{C^{\prime}R_{3}} be the Choi states of the maps ΛR1,ΛR2\Lambda_{R_{1}},\Lambda_{R_{2}} and ΛR3\Lambda_{R_{3}}. One has

ΛR1ΛR2ΛR3(RR1R2R3r),GHZABCr=TrR1R2R3[(λAR1λBR2λCR3)(IABC(RR1R2R3r)T)],GHZABCr=λAR1λBR2λCR3,GHZABCr(RR1R2R3r)T=λAR1TλBR2TλCR3T,GHZABCrRR1R2R3r.\begin{split}&\quad\langle\Lambda_{R_{1}}\otimes\Lambda_{R_{2}}\otimes\Lambda_{R_{3}}(R_{R_{1}R_{2}R_{3}}^{r}),GHZ_{A^{\prime}B^{\prime}C^{\prime}}^{r}\rangle\\ &=\langle Tr_{R_{1}R_{2}R_{3}}[(\lambda_{A^{\prime}R_{1}}\otimes\lambda_{B^{\prime}R_{2}}\otimes\lambda_{C^{\prime}R_{3}})(I_{A^{\prime}B^{\prime}C^{\prime}}\otimes(R_{R_{1}R_{2}R_{3}}^{r})^{T})]\\ &\qquad\qquad,GHZ_{A^{\prime}B^{\prime}C^{\prime}}^{r}\rangle\\ &=\langle\lambda_{A^{\prime}R_{1}}\otimes\lambda_{B^{\prime}R_{2}}\otimes\lambda_{C^{\prime}R_{3}},GHZ_{A^{\prime}B^{\prime}C^{\prime}}^{r}\otimes(R_{R_{1}R_{2}R_{3}}^{r})^{T}\rangle\\ &=\langle\lambda_{A^{\prime}R_{1}}^{T}\otimes\lambda_{B^{\prime}R_{2}}^{T}\otimes\lambda_{C^{\prime}R_{3}}^{T},GHZ_{A^{\prime}B^{\prime}C^{\prime}}^{r}\otimes R_{R_{1}R_{2}R_{3}}^{r}\rangle.\end{split} (C6)

To utilize the relation in Eq.  (C5) into above equation, the Choi states should be constructed by σAR1,σBR2,σCR3\sigma_{A^{\prime}R_{1}},\sigma_{B^{\prime}R_{2}},\sigma_{C^{\prime}R_{3}}, respectively. One can bound the marginals σA,σB\sigma_{A^{\prime}},\sigma_{B^{\prime}} and σC\sigma_{C^{\prime}} to guarantee the marginals of the constructed Choi states are proportional to II. From the Eq.  (A1), we have

F((ΓAΓBΓC)(τABCr),GHZABCr)=F(σABCr,GHZABCr)=σABCr,GHZABCrG(ϵr).\begin{split}F((\Gamma_{A}\otimes\Gamma_{B}\otimes\Gamma_{C})(\tau_{ABC}^{r}),GHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}})&=F(\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{r},GHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}})\\ &=\langle\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{r},GHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}}\rangle\\ &\geq G(\epsilon^{r}).\end{split}

Here, we adopt the definition in main text about notation {..}~r\widetilde{\{..\}}^{r} and define

σABC=r=07pr(σABCr~r)=r=07pr(UArUBrUCr)σABCr(UArUBrUCr).\begin{split}\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{\prime}&=\sum\limits_{r=0}^{7}p_{r}(\widetilde{\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{r}}^{r})^{{\dagger}}\\ &=\sum\limits_{r=0}^{7}p_{r}(U_{A^{\prime}}^{\prime r}\otimes U_{B^{\prime}}^{\prime r}\otimes U_{C^{\prime}}^{\prime r})\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{r}(U_{A^{\prime}}^{\prime r}\otimes U_{B^{\prime}}^{\prime r}\otimes U_{C^{\prime}}^{\prime r})^{{\dagger}}.\end{split}

By calculation, one has

F(σABC,GHZABC0)=σABC,GHZABC0=r=07prσABCr,GHZABCrr=07prG(ϵr)=q.\begin{split}F(\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{\prime},GHZ^{0}_{A^{\prime}B^{\prime}C^{\prime}})&=\langle\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{\prime},GHZ^{0}_{A^{\prime}B^{\prime}C^{\prime}}\rangle\\ &=\sum\limits_{r=0}^{7}p_{r}\langle\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{r},GHZ^{r}_{A^{\prime}B^{\prime}C^{\prime}}\rangle\\ &\geq\sum\limits_{r=0}^{7}p_{r}G(\epsilon^{r})=q.\end{split} (C7)

Furthermore, the spectrum of σA\sigma_{A^{\prime}} is the same as σA\sigma_{A^{\prime}}^{\prime} because of

σA=TrR1σAR1=TrBCR1R2R3(σAR1σBR2σCR3)=ΣrTrBCR1R2R3(RR1R2R3r(σAR1σBR2σCR3))=ΣrprTrBCσABCr=ΣrprσAr=σA,\begin{split}\sigma_{A^{\prime}}&=Tr_{R_{1}}\sigma_{A^{\prime}R_{1}}=Tr_{B^{\prime}C^{\prime}R_{1}R_{2}R_{3}}(\sigma_{A^{\prime}R_{1}}\otimes\sigma_{B^{\prime}R_{2}}\otimes\sigma_{C^{\prime}R_{3}})\\ &=\Sigma_{r}Tr_{B^{\prime}C^{\prime}R_{1}R_{2}R_{3}}(R_{R_{1}R_{2}R_{3}}^{r}(\sigma_{A^{\prime}R_{1}}\otimes\sigma_{B^{\prime}R_{2}}\otimes\sigma_{C^{\prime}R_{3}}))\\ &=\Sigma_{r}p_{r}Tr_{B^{\prime}C^{\prime}}\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{r}=\Sigma_{r}p_{r}\sigma_{A^{\prime}}^{r}=\sigma_{A^{\prime}}^{\prime},\end{split}

where we use that Σr=02N1RR1R2R3r=I.\Sigma_{r=0}^{2^{N}-1}R_{R_{1}R_{2}R_{3}}^{r}=I. Next, we will bound the spectrum of σA\sigma_{A^{\prime}}^{\prime}. One can always find a pure state σABC\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{\prime} to achieve the upper and lower bounds. Without loss of generality, let σABC=α|000+β|111\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{\prime}=\alpha|000\rangle+\beta|111\rangle. By inequality Eq.  (C7), 0.5<q10.5<q\leq 1 and α2+β2=1\alpha^{2}+\beta^{2}=1, one has 12q(1q)2α21+2q(1q)2\frac{1-2\sqrt{q(1-q)}}{2}\leq\alpha^{2}\leq\frac{1+2\sqrt{q(1-q)}}{2}. Thus, spectrum(σA)=spectrum(σA)[12q(1q)2,1+2q(1q)2]spectrum(\sigma_{A^{\prime}})=spectrum(\sigma_{A^{\prime}}^{\prime})\in[\frac{1-2\sqrt{q(1-q)}}{2},\frac{1+2\sqrt{q(1-q)}}{2}]. One can write the spectrum of σA\sigma_{A^{\prime}} as

spectrum(σA)={1ηA2,1+ηA2},spectrum(\sigma_{A^{\prime}})=\{\frac{1-\eta_{A^{\prime}}}{2},\frac{1+\eta_{A^{\prime}}}{2}\},

where 0ηA2q(1q)<10\leq\eta_{A^{\prime}}\leq 2\sqrt{q(1-q)}<1. The same bound on ηB\eta_{B^{\prime}} and ηC\eta_{C^{\prime}} will be obtained in a similar way for

spectrum(σB)={1ηB2,1+ηB2}spectrum(\sigma_{B^{\prime}})=\{\frac{1-\eta_{B^{\prime}}}{2},\frac{1+\eta_{B^{\prime}}}{2}\}

and

spectrum(σC)={1ηC2,1+ηC2}.spectrum(\sigma_{C^{\prime}})=\{\frac{1-\eta_{C^{\prime}}}{2},\frac{1+\eta_{C^{\prime}}}{2}\}.

Now, the detailed form of Choi states are:

λAR1T=(σA1/2I)σAR1(σA1/2I),λBR2T=21+ηBσBR2+σR2(I21+ηBσB),λCR3T=21+ηCσCR3+σR3(I21+ηCσC),\begin{split}&\lambda_{A^{\prime}R_{1}}^{T}=(\sigma_{A^{\prime}}^{-1/2}\otimes I)\sigma_{A^{\prime}R_{1}}(\sigma_{A^{\prime}}^{-1/2}\otimes I),\\ &\lambda_{B^{\prime}R_{2}}^{T}=\frac{2}{1+\eta_{B^{\prime}}}\sigma_{B^{\prime}R_{2}}+\sigma_{R_{2}}\otimes(I-\frac{2}{1+\eta_{B^{\prime}}}\sigma_{B^{\prime}}),\\ &\lambda_{C^{\prime}R_{3}}^{T}=\frac{2}{1+\eta_{C^{\prime}}}\sigma_{C^{\prime}R_{3}}+\sigma_{R_{3}}\otimes(I-\frac{2}{1+\eta_{C^{\prime}}}\sigma_{C^{\prime}}),\end{split} (C8)

where σA=TrR1σAR1,σB=TrR2σBR2,σC=TrR3σCR3\sigma_{A^{\prime}}=Tr_{R_{1}}\sigma_{A^{\prime}R_{1}},\sigma_{B^{\prime}}=Tr_{R_{2}}\sigma_{B^{\prime}R_{2}},\sigma_{C^{\prime}}=Tr_{R_{3}}\sigma_{C^{\prime}R_{3}} and σR2=TrBσBR2,σR3=TrCσCR3\sigma_{R_{2}}=Tr_{B^{\prime}}\sigma_{B^{\prime}R_{2}},\sigma_{R_{3}}=Tr_{C^{\prime}}\sigma_{C^{\prime}R_{3}}. As the spectrum(σB)={1ηB2,1+ηB2}spectrum(\sigma_{B^{\prime}})=\{\frac{1-\eta_{B^{\prime}}}{2},\frac{1+\eta_{B^{\prime}}}{2}\} and spectrum(σC)={1ηC2,1+ηC2}spectrum(\sigma_{C^{\prime}})=\{\frac{1-\eta_{C^{\prime}}}{2},\frac{1+\eta_{C^{\prime}}}{2}\} are bounded by 0ηB2q(1q), 0ηC2q(1q)0\leq\eta_{B^{\prime}}\leq 2\sqrt{q(1-q)},\ \ 0\leq\eta_{C^{\prime}}\leq 2\sqrt{q(1-q)}, the σR3(I21+ηCσC),σR2(I21+ηBσB)\sigma_{R_{3}}\otimes(I-\frac{2}{1+\eta_{C^{\prime}}}\sigma_{C^{\prime}}),\sigma_{R_{2}}\otimes(I-\frac{2}{1+\eta_{B^{\prime}}}\sigma_{B^{\prime}}) are positive semidefinite. Thus, one has

λAR1TλBR2TλCR3TλAR1T21+ηBσBR221+ηCσCR3.\lambda_{A^{\prime}R_{1}}^{T}\otimes\lambda_{B^{\prime}R_{2}}^{T}\otimes\lambda_{C^{\prime}R_{3}}^{T}\geq\lambda_{A^{\prime}R_{1}}^{T}\otimes\frac{2}{1+\eta_{B^{\prime}}}\sigma_{B^{\prime}R_{2}}\otimes\frac{2}{1+\eta_{C^{\prime}}}\sigma_{C^{\prime}R_{3}}.

From the Lemma 3 in the supplement material for Ref.  [36], the inequality

λAR1Ts(ηA)σAR1t(ηA)I2σR1\begin{split}\lambda_{A^{\prime}R_{1}}^{T}\geq s(\eta_{A^{\prime}})\sigma_{A^{\prime}R_{1}}-t(\eta_{A^{\prime}})\frac{I}{2}\otimes\sigma_{R_{1}}\end{split} (C9)

holds, where s(x)=21x2,t(x)=41x241+xs(x)=\frac{2}{\sqrt{1-x^{2}}},t(x)=\frac{4}{\sqrt{1-x^{2}}}-\frac{4}{1+x} and σR1=TrAσAR1\sigma_{R_{1}}=Tr_{A^{\prime}}\sigma_{A^{\prime}R_{1}}. Therefore, one has

λAR1TλBR2TλCR3T(s(ηA)σAR1t(ηA)I2σR1)21+ηBσBR221+ηCσCR3,\begin{split}\lambda_{A^{\prime}R_{1}}^{T}&\otimes\lambda_{B^{\prime}R_{2}}^{T}\otimes\lambda_{C^{\prime}R_{3}}^{T}\geq(s(\eta_{A^{\prime}})\sigma_{A^{\prime}R_{1}}-t(\eta_{A^{\prime}})\frac{I}{2}\otimes\sigma_{R_{1}})\\ &\otimes\frac{2}{1+\eta_{B^{\prime}}}\sigma_{B^{\prime}R_{2}}\otimes\frac{2}{1+\eta_{C^{\prime}}}\sigma_{C^{\prime}R_{3}},\end{split}

where the inequality is from Eq.  (C9) and positive semidefinite matrices 21+ηBσBR2,21+ηCσCR3\frac{2}{1+\eta_{B^{\prime}}}\sigma_{B^{\prime}R_{2}},\ \ \frac{2}{1+\eta_{C^{\prime}}}\sigma_{C^{\prime}R_{3}}. As

σR1σR2σR3,RR1R2R3r=TrR1R2R3((σR1σR2σR3)RR1R2R3r)=TrABCR1R2R3((σAR1σBR2σCR3)RR1R2R3r)=prTrABCσABCr=pr,\begin{split}&\langle\sigma_{R_{1}}\otimes\sigma_{R_{2}}\otimes\sigma_{R_{3}},R_{R_{1}R_{2}R_{3}}^{r}\rangle\\ &=Tr_{R_{1}R_{2}R_{3}}((\sigma_{R_{1}}\otimes\sigma_{R_{2}}\otimes\sigma_{R_{3}})\cdot R_{R_{1}R_{2}R_{3}}^{r})\\ &=Tr_{A^{\prime}B^{\prime}C^{\prime}R_{1}R_{2}R_{3}}((\sigma_{A^{\prime}R_{1}}\otimes\sigma_{B^{\prime}R_{2}}\otimes\sigma_{C^{\prime}R_{3}})\cdot R_{R_{1}R_{2}R_{3}}^{r})\\ &=p_{r}Tr_{A^{\prime}B^{\prime}C^{\prime}}\sigma_{A^{\prime}B^{\prime}C^{\prime}}^{r}=p_{r},\end{split}

one has IσR1IσR2σCR3,GHZABCrRR1R2R3r=12σR1σR2σR3,RR1R2R3r=pr2.\quad\langle I\otimes\sigma_{R_{1}}\otimes I\otimes\sigma_{R_{2}}\otimes\sigma_{C^{\prime}R_{3}},GHZ_{A^{\prime}B^{\prime}C^{\prime}}^{r}\otimes R_{R_{1}R_{2}R_{3}}^{r}\rangle=\frac{1}{2}\langle\sigma_{R_{1}}\otimes\sigma_{R_{2}}\otimes\sigma_{R_{3}},R_{R_{1}R_{2}R_{3}}^{r}\rangle=\frac{p_{r}}{2}. Then, one arrives at

λAR1TλBR2TλCR3T,GHZABCrRR1R2R3r4s(ηA)prG(ϵr)t(ηA)pr(1+ηB)(1+ηC).\begin{split}&\quad\langle\lambda_{A^{\prime}R_{1}}^{T}\otimes\lambda_{B^{\prime}R_{2}}^{T}\otimes\lambda_{C^{\prime}R_{3}}^{T},GHZ_{A^{\prime}B^{\prime}C^{\prime}}^{r}\otimes R_{R_{1}R_{2}R_{3}}^{r}\rangle\\ &\geq\frac{4s(\eta_{A^{\prime}})p_{r}G(\epsilon^{r})-t(\eta_{A^{\prime}})p_{r}}{(1+\eta_{B^{\prime}})(1+\eta_{C^{\prime}})}.\end{split}

The inequality is derived from the fact that the fidelity can only increase after tracing out the subsystem. Now, we can obtain

𝒬(,𝒫)18r=07λAR1TλBR2TλCR3T,GHZABCrRR1R2R3r18(4s(ηA)r=07prG(ϵr)t(ηA)r=07pr(1+ηB)(1+ηC))=4s(ηA)qt(ηA)8(1+ηB)(1+ηC).\begin{split}&\mathcal{Q}(\mathcal{R},\mathcal{P})\geq\frac{1}{8}\sum\limits_{r=0}^{7}\langle\lambda_{A^{\prime}R_{1}}^{T}\otimes\lambda_{B^{\prime}R_{2}}^{T}\otimes\lambda_{C^{\prime}R_{3}}^{T},GHZ_{A^{\prime}B^{\prime}C^{\prime}}^{r}\otimes R_{R_{1}R_{2}R_{3}}^{r}\rangle\\ &\geq\frac{1}{8}(\frac{4s(\eta_{A^{\prime}})\sum_{r=0}^{7}p_{r}G(\epsilon^{r})-t(\eta_{A^{\prime}})\sum_{r=0}^{7}p_{r}}{(1+\eta_{B^{\prime}})(1+\eta_{C^{\prime}})})\\ &=\frac{4s(\eta_{A^{\prime}})q-t(\eta_{A^{\prime}})}{8(1+\eta_{B^{\prime}})(1+\eta_{C^{\prime}})}.\end{split}

As 0.5<q10.5<q\leq 1, the numerator is positive. Hence, one obtains the result

𝒬(,𝒫)12(1+2q(1q))2(2q1(1ηA2)+1(1+ηA))12(1+2q(1q))2minu[0,2q(1q)](2q1(1u2)+1(1+u)).\begin{split}\mathcal{Q}(\mathcal{R},\mathcal{P})&\geq\frac{1}{2(1+2\sqrt{q(1-q)})^{2}}(\frac{2q-1}{\sqrt{(1-\eta_{A^{\prime}}^{2})}}+\frac{1}{(1+\eta_{A^{\prime}})})\\ &\geq\frac{1}{2(1+2\sqrt{q(1-q)})^{2}}\\ &\cdot\mathop{min}\limits_{u\in[0,2\sqrt{q(1-q)}]}(\frac{2q-1}{\sqrt{(1-u^{2})}}+\frac{1}{(1+u)}).\end{split}

Here, we have presented a lower bound for the quality of unknown joint measurement performed by Roy under certain white noise. The quality implies the ability that the unknown measurement try to simulate the ideal three-qubit GHZ-state measurement. Therefore, a robust self-testing statement for three-qubit GHZ-state measurement has been shown.

References