Shrinking Schauder Frames and their Associated Bases
Abstract.
For a Banach space with a shrinking Schauder frame we provide an explicit method for constructing a shrinking associated basis. In the case that the minimal associated basis is not shrinking, we prove that every shrinking associated basis of dominates an uncountable family of incomparable shrinking associated bases of . By adapting a construction of Pełczyński, we characterize spaces with shrinking Schauder frames as space having the -bounded approximation property.
Key words and phrases:
frames, Schauder frames, shrinking bases, bounded approximation property2020 Mathematics Subject Classification:
46B15, 42C15, 46B101. Introduction
A frame for a separable infinite dimensional Hilbert space is a sequence of vectors in such that there exists constants so that for all . If is a frame of then there exists a possibly different frame of called a dual frame such that
(1) |
That is, frames can be used like a basis to give a linear reconstruction formula for vectors in . The difference between frames and bases is that a frame allows for redundancy in that the coefficients given for reconstruction in (1) are not required to be unique.
Frames have been generalized to Banach spaces in various ways such as atomic decompositions [7, 9], framings [6], and Schauder frames [3, 5]. We will focus on Schauder frames in this paper which are a direct generalization of the reconstruction formula given in (1). Let be a separable infinite dimensional Banach space. A sequence of pairs in is called a Schauder frame for if
(2) |
We make the convention that for . Though Schauder frames were not explicitly defined until 2008, the first appearance of a Schauder frame, without the name Schauder frame, is in A. Pełczyński’s proof [16] that every space with the bounded approximation property (BAP) is isomorphic to complemented subspace of a space with a basis111In the same year (1971) Johnson, Rosenthal, and Zippin [10] proved the same result with a completely different method.. In 1987, S. Szarek showed that spaces with the BAP but without bases exist [17]. Indeed, Pełczyński showed that a separable Banach space has the BAP if and only if it has a Schauder frame (in the above sense) and that, furthermore, there is a space with a basis so that the identity on factors through the identity on in a natural way. Formally, if is a Schauder frame for and is a Banach space with a Schauder basis then is an associated space for (and is an associated basis for the frame ) if the maps (analysis operator) and (synthesis operator) defined by and are bounded.
In the case that both and are frames for a Hilbert space , then the associated space can be chosen to be and the associated basis can be chosen to be the unit vector basis for . This is of fundamental importance in frame theory as well as in applications such as signal processing. Indeed, given some vector , the analysis operator maps to . One can then apply filters to the sequence of frame coefficients to obtain a sequence . Applying the synthesis operator then gives a vector which is an approximation of but is improved in some way such as being compressed or having noise or artifacts removed.
If one wishes to use similar techniques for a Schauder frame then it is advantageous to construct the associated basis to be as nice as possible. That is, if has some desirable property such as being unconditional, shrinking, or boundedly complete then one would like to share the property as well. If is unconditional, then it is straightforward to construct an unconditional associated basis. In [1], the authors of the current paper and R. Liu prove that if is shrinking then it has a shrinking associated basis. However, the construction in [1] is relatively difficult and involves the method of bounds on branches of weakly null trees developed by E. Odell and Th. Schlumprecht [15] [8]. One of the main goals of this paper is to give a more direct and much simpler construction of a shrinking associated basis, which we state in the following theorem.
Theorem 1.1.
Let be a shrinking Schauder frame for a Banach space . For each , we denote to be the operator . Then there exists an increasing sequence of natural numbers such that
(3) |
Furthermore, if satisfies (3) then is an associated space of and is a shrinking associated basis where for , the norm is given by
(4) |
Given a Schuader frame with for all , the most natural associated space is now referred to as the minimal associated space [5][12] and is defined as follows. Denote by the unit vector basis for and for consider the norm
(5) |
The minimal associated space is defined to be the completion of under the above norm and the basis is called the minimal associated basis. A Schauder frame may have many non-equivalent associated bases. However, the basis defined in (5) is minimal in the sense that if is any associated basis for then dominates . That is, there exists a constant so that for all [12].
We now consider the problem of determining if a shrinking Schauder frame has a minimal shrinking associated basis. That is, if is a shrinking Schauder frame, then when does there exist a shrinking associated basis of such that if is any shrinking associated basis of then dominates ? In Section 4 we prove that a Schauder frame has a minimal shrinking associated basis if and only if the minimal associated basis defined in (5) is shrinking. Our construction of a shrinking associated basis in Theorem 1.1 is defined solely in terms of the shrinking Schauder frame and some sequence of natural numbers . In Section 4 we prove that if is a shrinking Schauder frame and is any shrinking associated basis then there exists such that the resulting shrinking associated basis from our construction is dominated by . In other words, Theorem 1.1 produces a set of shrinking associated bases such that every shrinking associated basis of dominates some basis in that set. Furthermore, we prove that if the minimal associated basis is not shrinking then for every shrinking associated basis there exists uncountably many mutually incomparable shrinking associated bases which are all dominated by . Hence, except for the trivial case where the minimal associated basis is shrinking, we have that the collection of shrinking associated bases will have a very rich lattice structure under the domination partial order.
In the final section we make some observations about how this work relates to now classical results about the BAP and give an alternative proof of the theorem of Johnson, Rosenthal, and Zippin that for a Banach space with separable dual, has the BAP if and only if is isomorphic to a complemented subspace of a Banach space with a shrinking basis.
2. Shrinking Schauder bases and shrinking Schauder frames
A sequence of vectors in a separable Banach space is called a Schauder basis if for all there exists a unique sequence of scalars such that . If is a Banach space with dual then a Schauder basis is called shrinking if the biorthogonal functionals form a Schauder basis for . In particular, a Banach space with a shrinking basis necessarily has a separable dual with a basis. There are, however, Banach spaces with bases whose duals are separable but fail the approximation property [11, Theorem 1.e.7.(b)]. Naturally, a Schauder frame for is shrinking if and only if is a Schauder frame for . Using the terminology atomic decomposition instead of Schauder frame, Carando and Lassalle [2] give the following useful characterization of shrinking Schauder frames which is analogous to James’ well-known characterization for Schauder bases.
Theorem 2.1 ([2], Theorem 1.4).
Let be a Schauder frame for . For each interval , let be the operator . Then is a Schauder frame for if and only if for each we have that
(6) |
We sketch a short proof for completeness.
Proof.
Consider the reverse direction and assume that (6) holds. Let . It suffices to show that is a Cauchy sequence. This follows readily from (6) as
Therefore is a Schauder frame for . A similar proof shows that the converse holds. ∎
Let be a Banach space with a Schauder frame and let be a Banach space with a Schauder basis . Recall that is said to be an associated space of the Schauder frame and is said to an associated basis if the maps and are bounded where for all and for all . It follows immediately that if a Schauder frame has a shrinking associated basis then the Schauder frame must be shrinking. In [1], the authors of the current paper and R. Liu prove a more general and technical theorem which implies that every shrinking Schauder frame has a shrinking associated basis. Unfortunately, the argument does not provide an explicit construction of the associated basis and the proofs are relatively difficult. In Section 3 we give an explicit method which will give a shrinking associated basis for any shrinking Schauder frame. Before proceeding we show that the minimal associated basis for a shrinking Schauder frame need not be shrinking.
Example 1.
Let be the unit vector basis for . Let and . For all we let , , , and . Then is a shrinking Schauder frame for but the minimal associated space for has the norm
(7) |
The basis is not shrinking since the sequence of odd vectors is equivalent to the summing basis of .
The above example, although simple, is rather instructive in that it reveals that redundancy in a frame can make the minimal associated basis not shrinking.
A sequence in a Banach space is called - for some if whenever is a summable sequence of non-negative scalars. We conclude this section by recalling the following useful and well known characterization of shrinking bases.
Lemma 2.2.
Let be a Banach spaces with a Schauder basis . The following are equivalent:
-
1.
is not shrinking.
-
2.
There is a normalized block sequence of that is not weakly null.
-
3.
There is a normalized block sequence of that is - for some .
3. Constructing a shrinking associated basis
We start by setting some notation. Let be a shrinking Schauder frame for a Banach space . Let be an associated space and be an associated basis. The analysis operator is the map given by for all . The synthesis operator is the map given by for all . For , we use the following notation when we wish to use partial sums.
-
1.
for all ,
-
2.
for all ,
-
3.
.
It follows from the uniform boundedness principle that , , and are all finite. The value is the basis constant of and the value is called the frame constant of .
The following proposition is contained in [1] and we include the short proof for completeness.
Proposition 3.1.
Let be a shrinking Schauder frame for a Banach space . Then there is an increasing sequence of natural numbers so that
(8) |
Proof.
Let and . It suffices to show that there is an satisfying
As is shrinking we have that is a Schauder frame for . Thus, for sufficiently large we have that
This suffices as for fixed , , and with we have that
The claim follows. ∎
Remark 3.2.
We now define a norm on which we will later prove gives a shrinking associated basis.
Definition 3.3.
Proposition 3.1 gives a condition satisfied by each shrinking Schauder frame. The idea behind the definition of the norm above is to force the associated space to satisfy some version of this condition. The goal then is to show that satisfying this condition is sufficient to establish that the associated basis is shrinking.
Remark 3.4.
A slight weakening of the norm was introduced in [1] where the authors prove that the basis is strongly shrinking relative to , which is a weaker condition than shrinking.
Theorem 3.5.
Let be a shrinking frame for a Banach space and let satisfy Proposition 3.1. Then is an associated space for and is a shrinking basis for the space .
Proof.
Assuming satisfies Proposition 3.1, we will first show that is as an associated space to the frame . This is the only place in the proof we use Proposition 3.1. Let us see that the analysis operator satisfies where is the frame constant of . Let . Then, the first part of in (9) satisfies
We now fix , , and . Then by Proposition 3.1 we have that the second part of (9) satisfies
Thus, we have that and hence . The synthesis operator is bounded, since it is bounded on and . Thus, is an associated space to .
Let be a normalized block sequence of in . In order to show that is shrinking it suffices to show by Lemma 2.2 that there is a subsequence of which is weakly null. We claim that we may pass to a subsequence of and find an increasing sequence in so that for all we have that
-
(i)
,
-
(ii)
for all with .
Indeed, (i) is easily obtained as is a block sequence of . We may obtain (ii) by choosing sufficiently large as is convergent for all . The following additional properties are implied by (i) and (ii).
-
(iii)
for and ,
-
(iv)
For each , ,
-
(v)
For in , .
Item (iii) follows from (i) and the fact that . Item (v) follows from (iii) if and follows from (ii) if . Item (iv) is a consequence of (ii) and (iii) as
Before dividing the proof into two cases, we fix and and will show that
(11) |
Let and . Let be the least integer such that . By (i), we have that for all . Since , (9) implies that . By (iii),
(12) |
Thus, we have that
This proves (11). We now pass to a further subsequence of such that exactly one of the following holds.
-
(vi a.)
for each .
-
(vi b.)
For some , we have .
Assume (vi a.) holds. Fix . Let and let be the least integer such that and let be the greatest integer such that . We have the following.
Combining this with (11) gives that is -dominated by the unit vector basis of and therefore is weakly null, which completes the proof for this case.
We now assume item (vi b.) holds. We will prove that in this case that and are equivalent basic sequences and that is weakly null. Let be the frame constant of . We first prove that is -basic.
Let and let be such that . We have that
Thus, we have that
(13) |
We now fix and consider the following partial sum.
This proves that is -basic.
Since is a bounded linear operator, dominates . We now prove that is equivalent to by proving that dominates . Fix . Let with and let be the smallest interval containing . Thus by (vi b.),
(14) |
We now have that
Therefore, to prove that dominates it will suffice to prove that for fixed we have that
(15) |
As, is a block sequence of , there exists so that
By taking the norm of both sides we now have that
This proves (15) and hence and are equivalent basic sequences. All that remains is to prove that is weakly null. Let be some functional.
Thus, is weakly null which implies that is weakly null as they are equivalent basic sequences. Hence, is a shrinking basis as every normalized block sequence is weakly null. ∎
The proof of the above theorem admits the following corollary.
Corollary 3.6.
Let be a shrinking frame for a Banach space and let satisfy Proposition 3.1. Let be a normalized block sequence in .
-
1.
If there is a subsequence of so that , then there is a further subsequence of that is equivalent the the unit vector basis of .
-
2.
If there is no subsequence of so that , then there is a subsequence of so that is equivalent to .
Note that the example given in Section 2 shows that Corollary 3.6 is false for the minimal associated . In that example, is a normalized block sequence in with for all , but has no subsequence which is equivalent to a sequence in .
Remark 3.7.
Let have a Schauder frame with associated space , analysis operator and synthesis operator . The following are fundamental properties of Schauder frames.
-
1.
is isomorphic to , which is a complemented subspace of .
-
2.
is a projection of onto .
-
3.
is isomorphic to the range of , where is the identity operator on .
Proposition 3.8.
Let be a shrinking frame for a Banach space and let satisfy Proposition 3.1. Then is saturated. That is, every infinite dimensional subspace of contains a further subspace which is isomorphic to .
Proof.
Using Remark 3.7, is isomorphic to the range of in . Let be an infinite dimensional subspace of the range of . There exists a normalized block sequence in and a sequence in so that . After passing to a subsequence, we may assume that and are equivalent basic sequences. As is contained in the range of and is a projection operator, we have that for all . Therefore . Since is a an isomorphic embedding, we have that . Therefore we are in the first alternative of Corollary 3.6 and so has a subsequence equivalent to the unit vector basis of . ∎
The above can be compared to the result of Liu-Zheng [13] in which the authors prove that if is the minimal associated space for a Schauder frame of , then contains an isomorphic copy of if and only if is infinite dimensional.
4. Comparing Associated Spaces with Shrinking Bases
Our next result illustrates that associated spaces of the form are a minimal collection, with respect to domination, among associated spaces with shrinking bases.
Theorem 4.1.
Suppose that is a shrinking Schauder frame for and that is an associated space of with a shrinking associated basis . Then there exists so that, the basis of is dominated by .
We isolate the following remark.
Remark 4.2.
Let be a finite collection of finite rank operators on a Banach space with a shrinking basis . Then,
Proof of Theorem 4.1.
Fix , and as in the statement of the theorem and as in Remark 4.2. Since dominates the minimal associated basis of there exists so that
(16) |
Let be the synthesis operator. For each , the set is a finite collection of finite rank operators on . By the previous remark, for each there exists so that for all and . Thus we have for all that
Hence, we have that -dominates the basis of . ∎
Let be a shrinking Schauder frame and let be an increasing sequence of natural numbers which satisfies Proposition 3.1. If is an increasing subsequence of natural numbers then we denote to be the Banach space with basis which is the completion of under the norm:
(17) |
Recall that for and ,
(18) |
It follows from Remark 3.2 and Theorem 3.5 that is an associated space of and that is a shrinking basis for .
Theorem 4.3.
Suppose that is a shrinking Schauder frame for a Banach space so that the minimal associated basis is not shrinking. Then for any sequence satisfying Proposition 3.1, there exists an increasing sequence so that for all infinite subsets , the following are equivalent.
-
1.
dominates .
-
2.
is finite.
Before proving Theorem 4.3 we state and prove the following corollary.
Corollary 4.4.
Let be a shrinking Schauder frame so that the minimal associated basis is not shrinking. Then for each shrinking associated basis there are increasing sequences of natural numbers and and a set of increasing sequences of natural numbers with having cardinality the continuum so that
-
1.
For each , the basis of is a shrinking associated basis of which is dominated by .
-
2.
For in , the bases and are incomparable.
Proof.
Fix a shrinking associated basis . By Theorem 4.1, there is a sequence so that the basis of is dominated by . Let be a sequence which satisfies the conclusion of Theorem 4.3. For every infinite , the basis of is a shrinking associated basis of which is dominated by . Hence, is also dominated by . Let be a collection of infinite subsets of with cardinality the continuum so that is finite for all . This is called a collection of almost disjoint sets and is known to exist. In particular, is infinite for all . By Theorem 4.3, and are incomparable basic sequences for all . ∎
Proof of Theorem 4.3.
Let be a shrinking Schauder frame for so that the minimum associated basis is not shrinking. Let be an increasing sequence of natural numbers which satisfies Proposition 3.1. By Theorem 3.5 the basis of is a shrinking associated basis of and, moreover for each sequence , the basis of is a shrinking associated space of .
As the minimal associated basis of is not shrinking, there exists a normalized block sequence in which is - for some . The norm -dominates the norm. Hence, for all non-negative scalars we have that
As is a shrinking basis for , every bounded block sequence converges weakly to and is hence not . Thus, cannot be norm bounded as a sequence in . After passing to a subsequence, we assume that for all .
Let be the frame constant of . Thus, for all , and we have that . As for all and is unbounded in , after passing to a subsequence of we may assume that there exists a sequence so that for all , and . We now assume that is infinite and will prove that the basis does not dominate the basis . Let with . We have that the following holds
Thus, the basis does not dominate the basis as is infinite. We now assume that is finite. Let be the least element of so that . Let . Thus, for all . We have that
Thus, -dominates the basis . This implies that -dominates for some . ∎
5. Shrinking Bounded Approximation Property
A separable Banach space has the Bounded Approximation Property BAP if there is a sequence of finite rank operators on so that for all . The uniform boundedness principle implies that whenever this condition holds there is a with for each . A space with this property for is said to have the -AP. Moreover, setting and for we can replace with . We note that the definition of the -AP is that there for each and compact set in there is finite rank operator with so that for all .
To mirror the definition of shrinking basis, one may wish to define a space to have the shrinking-BAP if there are finite rank operators on so that for all and for all . That is, the operators in the space approximating the identity also have the property that their dual operator approximate the identity. This is analogous to: A basis is shrinking if and only if the coordinate functionals form a basis for .
The above definition of shrinking-BAP is formally stronger than simply having the BAP and has been isolated before under the name duality-BAP [4, page 288]. The surprising fact that these notions are equivalent is the content of the following proposition [4, Proposition 3.5].
Theorem 5.1.
A space has the shrinking BAP if and only if has the BAP.
In fact a lot more is known: A dual space has the AP if and only if and have the -AP (i.e. the metric approximation property). Another result related to the current work is the following [4, Theorem 4.9].
Theorem 5.2.
Let be a Banach space with separable dual. Then has the BAP if and only if embeds complementably in a Banach space with a shrinking basis.
Theorem 5.2 is a complemented version of Zippin’s theorem [18] stating that every Banach space with a separable dual embeds into a space with a shrinking basis. It is also a refinement of the aforementioned theorem of Pełczynski and Johnson-Rosethal-Zippin stating that every space with the BAP embeds complementably into a space with a basis. The proof of Theorem 5.2 (as stated [4]) follows the results in [10]. Here the authors show that if has the BAP then has a shrinking basis where is the sum of finite dimensional spaces which are dense (with the Banach Mazur distance) in the space of all finite dimensional spaces.
We present an alternative proof Theorem 5.2 using the language of frames and modifying the proof of Pełczyński[16]. The technique we employ for this proof is also used by Mujica and Vieira in [14] to give a quantitative improvement of Pełczyński’s theorem.
Theorem 5.3.
Let be a Banach space. Then has the BAP only if and only if has a shrinking Schauder frame.
Proof of Theorem 5.3.
If has a shrinking Schauder frame then is a Schauder frame of and hence has the BAP. Before proving the reverse direction we prove the following finite dimensional result. Let be a Banach space and let be a finite rank operator. Let be the rank of and let . Then there exists such that the sequence of rank one operators satisfies
(19) |
Indeed, let be an Auerbach basis of with bi-orthogonal functionals . In particular, for all and is the identity on . For each , we let and where for some and . Let and . Then,
Thus the first part of (LABEL:E:Pel) holds. To prove the second part we let , and . We have that,
Thus we have proven (LABEL:E:Pel). We now assume that has the BAP and hence by Theorem 5.1 we have that has the shrinking-BAP. Let be a sequence of finite rank operators so that for all and that for each we have that where is the identity operator on . Let be the dimension of and let be a sequence of natural numbers with .
As described above, we construct for all a finite sequence which satisfies (LABEL:E:Pel) for the finite rank operator . We claim that the infinite sequence is a shrinking Schauder frame of when enumerated in the natural way. We will prove that is shrinking, and we note that the proof that is a Schauder frame follows the same argument. Let and . Choose large enough so that for all we have and . Thus we also have that . Let . Then for some , , and . The approximation of by the partial sum consisting of the first terms of satisfies
Thus we have that is a Schauder frame of and hence is shrinking. ∎
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