Solutions for linear conservation laws with gradient constraints
José Francisco Rodrigues
Lisa Santos
Abstract
We consider variational inequality solutions with prescribed gradient constraints for first order linear boundary value problems. For operators with coefficients only in , we show the existence and uniqueness of the solution by using a combination of parabolic regularization with a penalization in the nonlinear diffusion coefficient. We also prove the continuous dependence of the solution with respect to the data, as well as, in a coercive case, the asymptotic stabilization as time towards the stationary solution. In a particular situation, motivated by the transported sandpile problem, we give sufficient conditions for the equivalence of the first order problem with gradient constraint with a two obstacles problem, the obstacles being the signed distances to the boundary. This equivalence, in special conditions, illustrates also the possible stabilization of the solution in finite time.
Dedicado a João Paulo Dias, no seu ativo septuagésimo aniversário!
1 Introduction
Several works have developed solutions to the linear equation of first order
(1)
for and in an open subset of , where is a given vector field and and are given functions.
The well-known DiPerna and Lions theory of renormalized solutions, when is given in Sobolev spaces, has been extended by Ambrosio to BV coefficients for the Cauchy problem and has found several applications in the study of hyperbolic systems of multidimensional conservation laws (see, for instance [1], for an introduction and references). The initial-boundary value problem for (1) with a vector field has been studied in the pioneer work of Bardos [2] using essentially a approach for the transport operator. This method also holds for Lipschitz vector fields, as observed in [8], and was extended by Boyer [5] for solenoidal vector fields in Sobolev spaces that do not need to be tangential to the boundary of , i.e. on for .
The delicate point is then to prescribe the boundary data to the normal trace of on the portion of the space-time boundary where the characteristics are entering the domain . In the case when does not vary with , Besson and Pousin [3] have treated the initial-inflow problems for the continuity equation (1) with velocity fields with also in . Recently Crippa et al. [7] have also considered this problem without that restriction on and with similar assumptions on in BV.
Here we are interested in the initial-boundary value problem for (1) under the additional gradient constraint
(2)
where is a given strictly positive and bounded function. This problem was already considered in [20] in the framework of a quasilinear continuity equation
(3)
and a Lipschitz semilinear lower order term , with a gradient bound in (2) that may depend also on the solution but not on time. As observed in [20], in the linear transport equation (1), corresponding to
with regular coefficients and independent of , the problem is well-posed in terms of a first order variational inequality with the convex set
(4)
In [20] it is also proved the existence and asymptotic behaviour of quasivariational solutions for positive nonlinear gradient constraints depending continuously on the solution . Here denotes the usual Sobolev space of functions vanishing on the boundary , as the gradient bound allows to prescribe values on the whole boundary. Moreover, it allows also to consider the data , and only in , provided is bounded from below.
A motivation for the constraint (2) applied to the equation (1) is the “transported sandpile” problem. Following Prigozhin [14, 15], the gradient of the shape of a growing pile of grains characterized by its angle of repose is constrained by its surface slope, i.e. . A general conservation of mass, in the form (3) with and source density , with transport directed by and dropping flow directed to the steepest descent , should be then subjected to the unilateral conditions
We illustrate this problem with the interesting example of the one dimensional special case announced in [19]: , , i.e. and . Taking as initial condition the parabola , up to the point , and the straight line , for , the profile of the “transported sandpile” growth attains a steady state exactly at . This happens with the first free boundary point increasing from up to , touching then the boundary , and decreasing till the midpoint . At this point, the free boundary meets a second increasing free boundary , that appears at and increases up to the final stabilization at
Figure 1: The free boundary of the transported sandpile problem at and .
The explicit sandpile profile is given by
where ,
if , and , if .
It is clear that .
We introduce the function and the convex set
Since in , by simple computation and integration in , we easily conclude that , which (using and ) can be written as
is then the unique solution in of the variational inequality
(5)
But since , is also the solution of the variational inequality (5) with , which has at most one solution also in the convex set , defined as in (4) with .
In Section 2 we establish the existence and the uniqueness of the solution of the first order variational inequality associated with the general linear equation (1) in a family of time dependent convex sets with gradient constraints of the type (4) with . We improve the results of [20] under general square integrability assumptions on the coefficients and on the data, by direct estimates in the parabolic-penalized problem and passage to the limit, first in the penalization parameter , and afterwards in the regularization parameter . The continuous dependence of the solution with respect to the gradient constraint variations in , to the coefficients of the operator and the data in , is proven in Section 3 under the weak coercive condition (7), as well as the asymptotic convergence towards the unique stationary solution under the stronger coercive assumption (23).
Finaly, in Section 4, we consider the special case of a constant vector , with and bounded, to show the equivalence of the variational inequalities with the gradient constraint and with the two obstacles, i.e. with the signed distances to the boundary constraints on the solution. This is a first result of this type for first order variational inequalities, similar to the elliptic well-known case of the elastoplastic torsion problem (see, for instance, [16] and its references) and to the parabolic case without convection considered in [21, 22], where it was shown that this equivalence is not always possible in the general case. With additional conditions, that include the above one dimensional transported sand pile problem, we establish the finite time stabilization of the solution. This extends to the convective problem a similar result by Cannarsa et al. [6] and raises the interesting open question of establishing more general conditions on the finite time stabilization of evolutionary problems with gradient constraints.
2 Existence and uniqueness of the variational solution
Let be a bounded open subset of with a Lipschitz boundary and, for any , denote
.
Assume that
(6)
and there exists such that
(7)
being this inequality satisfied in the distributional sense, since does not need to be a function.
Consider the following variational inequality problem: To find , in an appropriate space, such that
(10)
Theorem 2.1
With the assumptions (6)-(9), problem (10) has a unique solution
Proof To prove the uniqueness of the solution we assume there exist two solutions and . Using as test function in (10) for the variational inequality of and reciprocally, setting at a.e. , we obtain
To prove the existence of a solution, we consider a family of approximating quasilinear parabolic problems for , with , defined as follows
(11)
where , , and are appropriate regularizations of , , and , respectively,
with and is a smooth real function such that if and if . Notice that this problem has a unique solution ,
by the classical theory of parabolic quasilinear problems (see, for instance, [10]).
We prove first several a priori estimates.
Estimate 1
(12)
for some constant dependent only on , , , and .
Multiplying the equation of the problem (11) by and integrating over
, we have
Observing that
and using the coercive inequality for the regularized coefficients
we have
Hence, by the integral Gronwall’s inequality, there exists a positive constant , independent of and , such that
and recalling that, for all and all , ,
we get, for any ,
Given , we have
(16)
and, since is bounded, we can
estimate, for any , the second integral in the second term of (16) as follows,
The first integral in the second term of (16) is clearly bounded since
and the conclusion follows easily, first for and afterwards for any .
Estimate 3
(17)
where, for , is an upper bound, independent of , of the Poincaré constant for and is a positive constant depending only on , , , and .
We multiply the equation of problem (11) by and we integrate over , noting that on . Denoting , we have
We choose and , and so we have . Then
and
So
being a Poincaré constant. Observe that, since is bounded we may find a positive upper bound of , independently of .
On one hand
because .
On the other hand, if we set , we have
Consequently, for a.e. ,
So,
and the proof of Estimate 3 is concluded.
By (15) and (17), we know there exist
constants , and , independent of , such that, for each ,
Since is bounded in , independently of , for , by a known compactness theorem ([23], page 84), is relatively compact
in . Then,
at least for a subsequence,
The above estimates also imply that we may choose, always with fixed ,
Given such that for a.e. , we multiply the equation of problem (11) by , we use the
monotonicity of and we integrate over , , to conclude that
Letting , since and are arbitrary, we obtain that for a.e.
for all , such that, for a.e. .
Set .
Since
in , then we have
by (12), being a constant independent of as we have seen. So we have
(18)
where is an upper bound of ,
independent of . Consequently,
and so for a.e. . Let be such that .
Defining ,
, then . Using as test function in (10) and dividing both sides of the inequality
by , we get
and, letting , we conclude that solves the following variational inequality
(19)
Recalling the Estimate 3 we have
Passing to the when and arguing as in (18), we conclude that
and, consequently,
Observing that
we have the sequence uniformly bounded in .
Moreover, the sequence is uniformly bounded in , independently of , since each
belongs to . So, there exists a function and,
at least for a subsequence,
Integrating in (19) between and , for , and passing to the limit when , we get
for all such that for a.e. . Since and are arbitrary, we can drop the integration in time.
Since for a.e. , the same holds for , concluding that solves the variational inequality (10).
Remark 2.2
We observe that in the proof of the uniqueness of the solution it is sufficient to assume only
Similarly, we may replace (7) by the different weak coercive assumption by assuming the existence of , such that, in the sense of distributions,
in order to have also the uniqueness of the solution to the variational inequality (10).
In fact, assuming that there are two solutions and , we may choose for test function in the variational inequality
for , where
is a sequence
of increasing odd functions approximating pointwise the sign function and is sufficient small. Then, choosing also in the variational inequality
for , we get
Noting and , by the dominated convergence theorem, we have
and so
Since , by the Gronwall’s inequality, we conclude the uniqueness from
3 Stability and asymptotic behaviour in time
In this section, the stability of the solutions of the variational inequality (10), as well as its asymptotic limit when is based in the following Lemma, which is due essentially to [22].
Lemma 3.1
For , let belong to .
If , , is such that for a.e. then there exists
such that for a.e. and a positive constant such that
Proof Let . Define
and .
Since
and
then for a.e. . The conclusion follows immediately from
The continuous dependence result is a consequence of the boundedness of the solution and of its gradient, when we impose the weakly coercive assumption (7).
Theorem 3.2
For , let denote the solution of the variational inequality (10) with data satisfying assumptions (6)-(9).
Then there exists a positive constant , depending on , such that
Proof Let be defined as in Lemma 3.1, for the solution and be the corresponding function for . Using as test function in the variational inequality (10), we obtain
and a similar inequality is true using the variational inequality of , by replacing the data by and by . Then we have
(20)
with
Using the boundedness of the solutions , and their gradients and recalling the estimates of , we have
where is a positive constant depending on , on the norms of the solutions and their derivatives (which can be bounded in terms of the data) and on the constant of Lemma 3.1.
Setting in the inequality (20), we obtain using (7),
Applying Gronwall’s inequality, we conclude
In order to consider the corresponding time independent solution to the first order variational inequality, we give stationary data satisfying the
assumptions
(21)
(22)
(23)
in the distributional sense,
where we set accordingly
(24)
Then, the stationary problem can be written as
(25)
Since the convex set is bounded in and the first order linear operator in the left hand side of (25) is pseudo-monotone, by the classical theory (see, for instance, [12]) it has a solution, which is unique by the strict coerciveness induced by the condition in (23).
In order to study the asymptotic convergence of the solution of the variational inequality (10)
to the stationary solution of (25), we consider solutions global in time. This is easily obtained if we assume that (6)-(8) are satisfied for any and replace (9) by
(26)
We need an auxiliary lemma.
Lemma 3.3
([9], pg. 286) Let be a nonnegative
function, absolutely continuous in any compact subinterval of
, a nonnegative function and
a positive constant, such that,
(27)
Then, for any ,
In order to apply this Lemma to
(28)
we shall require the additional assumptions on the coefficients and on the data
(29)
Theorem 3.4
Assume that satisfy the assumptions (6)-(8), (26), (29)
and satisfy the assumption (21),(22) and (23).
Suppose, in addition, that
and there exists , such that, for some constant ,
(30)
If and are, respectively, the unique solutions of the variational inequalities (10) and (25) then, for every , ,
Proof First we need to return to the estimate (17) of the existence proof in order to prove that, under the additional assumptions of this theorem, there are positive constants , independent of , such that,
Since for a.e. and , we have now . This yields the estimate
where the constant is independent of . Using similar estimates for with the constant replaced by , as well as for and , we may conclude that the constant of (12), in the Estimate 1, grows also linearly with , i.e. , where depends only on and depends on , , , and . Using this fact in the Estimate 3, we may now easily deduce (3) from (17), with and , since , depending on and on grows also linearly with .
Using Lemma 3.1, we choose , for a.e. , as test function in (10). Then
Analogously, with , for a.e. , we obtain the inequality
Then, simple algebraic manipulations lead to
(31)
where
Using (23) and the definition (28), from (31), we obtain the differential inequality with and where, taking into account (3), we may choose given by
Then, using the assumptions and observing that the number in (30) is greater than , we have
Therefore, by Lemma 3.3, in . Since belongs to , the compact inclusion of in implies, first for a subsequence, and after for the whole sequence, that in , concluding the proof.
4 Finite time stabilization in a special case
In this section we assume that is of class and
(32)
We consider the following two obstacles problem
(33)
where
Here is the distance function to the boundary . Notice that , , a.e. and for some constant . Observe that .
Theorem 4.1
Under the assumptions (32), the inequality (33) has a unique solution
which satisfies a.e. in and is the unique solution of the variational inequality (10).
Proof For , we consider the following family of penalized
problems for ,
(34)
where and are regularizations of the functions and , with . This problem has a unique solution ,
since the operator
We obtain firstly an estimate of on . Since is of class , there exists such that, if denotes the ball with centre in and radius , then for all there exists such that
. Placing the origin of the coordinates in the point , let
and
where is a positive constant, depending on , to be chosen later. We show that is a supersolution
of (34). Analogously, it can be verified that is a subsolution. We start by observing that
Since , then
We compute
(36)
and
Let
Then, recalling that there exists a positive constant such that and choosing sufficiently small, such that, we have
(37)
Observe now that the term is negative and, since , we have the following inequality
We can fix such that, for , we have . From (4), we obtain then
provided
(38)
concluding then that is a supersolution of (34).
Analogously, is a subsolution of (34) and so we have
for an arbitrary point at any .
We wish to prove that this estimate is true a.e. in .
Differentiate the first equation of (34) with respect to , multiply it by and sum over . Setting
and noticing that we get
being . Using the Cauchy-Schwartz inequality, we obtain
Multiplying the above inequality by and integrating over , we have
We can now pass easily to the limit when in inequality (43). Observing that converges to
some function weakly* in and converges weakly in
to , we find for all
and it follows also
Since for a.e. , we also have and the proof of existence of solution for the variational inequality (33) is complete. The uniqueness is also clear.
The inclusion and the fact for a.e. implies that the function also solves the problem (10).
Remark 4.2
The first order variational inequalities of obstacle type have been introduced by Bensoussan and Lions in [4] and have been studied in [13] and in [17], for general linear operators and general obstacles, and extended to a quasilinear two obstacles problem in [11]. In all those cases the notion of solution is less regular and the boundary data can only be prescribed on part of the boundary. In addition, the solution cannot have a gradient in and the best that can be expected in general is the operator , as a consequence of Lewy-Stampacchia inequalities. These estimates can be obtained from the regularized parabolic inequality (43) and, as in [18], it allows the passage to the limit without the estimates on the gradient and on the time derivative. It is an open question to establish the equivalence of the first order obstacle problem with the variational inequality with gradient constraint for more general first order linear operators.
Since the sequence of continuous functions is increasing in and is bounded from above by , this conclusion follows immediatly.
However, in this special case we have a finite time stabilization.
First we prove that the function coincides with . We recall that , for any ,
and we set . Observe that , where denotes the Lebesgue measure of . Since is
increasing, then and
This implies that
Choosing as test function in (33) we obtain, for a.e. ,
and so
Since , taking to both sides of the inequality and using the assumption (46), we obtain
which is a contradiction unless .
Consider the following subsets of
Since solves the two obstacle problem (33), it is well known that the following inequalities are verified a.e. in :
If there is no finite time stabilization of the solution, since is increasing in time, we may find a point and an open subset of with , such that,
for . So,
Then, for any and any open set , we have
As a consequence,
and this is a contradiction with (46). So must stabilize in finite time.
Acknowledgments
This research was partially supported by CMAT - “Centro de Matemática da Universidade do Minho”, financed by FEDER Funds through “Programa Operacional Factores de Competitividade - COMPETE” and by
Portuguese Funds through FCT, “Fundação para a Ciência e a Tecnologia”,
within the Project PEst-OE/MAT/UI0013/2014.
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