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Some theorems on decomposable continua

Hayato Imamura Faculty of Economics, The International University of Kagoshima, 8-34-1 Sakanoue, Kagoshima-shi, Kagoshima, 891-0197, Japan. hayato-imamura@asagi.waseda.jp Eiichi Matsuhashi Department of Mathematics, Shimane University, Matsue, Shimane, 690-8504, Japan. matsuhashi@riko.shimane-u.ac.jp  and  Yoshiyuki Oshima Department of Mathematics, Shimane University, Matsue, Shimane, 690-8504, Japan. oshima@riko.shimane-u.ac.jp
Abstract.

We prove some theorems on decomposable continua. In particular, we prove;

(i) the property of being a Wilder continuum is not a Whitney reversible property,

(ii) inverse limits of DD^{**}-continua with surjective monotone upper semi-continuous bonding functions are DD^{**}, and

(iii) there exists a DD^{**}-continuum which contains neither Wilder continua nor DD^{*}-continua.

Also, we show the existence of a Wilder continuum containing no DD^{*}-continua and a DD^{*}-continuum containing no Wilder continua.

Key words and phrases:
Whitney reversible property, Wilder continua, DD^{*}-continua, DD^{**}-continua, inverse limits
2020 Mathematics Subject Classification:
Primary 54F15 ; Secondary 54F16, 54F17

1. Introduction

In this paper, all spaces are assumed to be metrizable. A mapmap is a continuous single-valued function. A map f:XYf:X\to Y is said to be monotonemonotone if for each yYy\in Y, f1(y)f^{-1}(y) is connected. If XX is a space and AA is a subset of XX, then we denote the closure of AA in XX by ClXA{\rm Cl}_{X}A. By a continuumcontinuum we mean a compact connected metric space. An arcarc is a space which is homeomorphic to the closed interval [0,1][0,1]. If AA is an arc, then we denote the set of end points of AA by E(A)E(A). A continuum is said to be decomposabledecomposable if it is the union of two proper subcontinua. If a continuum XX is not decomposable, then XX is said to be indecomposableindecomposable.

Let XX be a continuum. Then, 2X2^{X} denotes the space of all closed subsets of XX with the topology generated by the Hausdorff metric. Also, C(X)C(X) denotes the subspace of 2X2^{X} consisting of all nonempty subcontinua of XX. A WhitneyWhitney mapmap is a map μ:C(X)[0,μ(X))\mu:C(X)\to[0,\mu(X)) satisfying μ({x})=0\mu(\{x\})=0 for each xXx\in X, and μ(A)<μ(B)\mu(A)<\mu(B) whenever A,BC(X)A,B\in C(X) and ABA\subsetneq B. It is well-known that for each Whitney map μ:C(X)[0,μ(X)]\mu:C(X)\to[0,\mu(X)] and for each t[0,μ(X)]t\in[0,\mu(X)], μ1(t)\mu^{-1}(t) is a continuum ([4, Theorem 19.9]).

A topological property PP is called a Whitney property if a continuum XX has property PP, so does μ1(t)\mu^{-1}(t) for any Whitney map μ\mu for C(X)C(X) and for any t[0,μ(X))t\in[0,\mu(X)). Also, a topological property PP is called a Whitney reversible property provided that whenever XX is a continuum such that μ1(t)\mu^{-1}(t) has property PP for each Whitney map μ\mu for C(X)C(X) and for each t(0,μ(X))t\in(0,\mu(X)), then XX has property PP. For information about Whitney properties and Whitney reversible properties, see [4, Chapter 8].

In this paper, we show some theorems on decomposable continua. In particular, we deal with topics on Wilder continua, DD-continua, DD^{*}-continua and DD^{**}-continua (definitions of these continua are given in the following section). Studies on these continua are seen in [1], [2], [10], [11], [12], [13], [14] and [18].

The paper is divided as follows:

In Section 2, we introduce some basic definitions and terminology that are used throughout this paper.

In Section 3, we show that the properties of being a Wilder continuum is not a Whitney reversible property. This result gives a partial answer to [14, Qusetion 5.2]. Note that the properties of being a Wilder continuum, being a DD-continuum, being a DD^{*}-continuum and being a DD^{**}-continuum are all Whitney properties (see [14]).

In Section 4, we deal with topics on inverse limits with set-valued bonding functions. The notion of inverse limits with set-valued bonding functions was introduced by Ingram and Mahavier ([5]). In Section 4, we prove that inverse limits of DD^{**}-continua with surjective monotone upper semi-continuous bonding functions are DD^{**}. This result is in contrast to [17, Examples 5.1 and 5.2], which state that there exists an inverse sequence {Xi,fi}i=1\{X_{i},f_{i}\}_{i=1}^{\infty} of DD-continua (resp. DD^{*}-continua) with surjective monotone upper semi-continuous bonding functions such that lim{Xi,fi}i=1\underleftarrow{{\rm lim}}\{X_{i},f_{i}\}_{i=1}^{\infty} is not a DD-continuum (resp. a DD^{*}-continuum).

In Section 5, we show that there exists a DD^{**}-continuum which contains neither Wilder continua nor DD^{*}-continua. Also, we show the existence of a Wilder continuum containing no DD^{*}-continua and a DD^{*}-continuum containing no Wilder continua.

2. preliminaries

In this section, we introduce some basic definitions and terminology.

Definition 2.1.

A continuum XX is called a Wilder continuum if for any three distinct points x,y,zXx,y,z\in X, there exists a subcontinuum CC of XX such that xCx\in C and CC contains exactly one of yy and zz.

Wilder introduced the notion of Wilder continua in [18].111Wilder named the continua as CC-continua. However, we use the term Wilder continua following the notion proposed in [8].

Let XX be a continuum. If XX is not Wilder, then there exist three distinct points x,y,zXx,y,z\in X such that for each subcontinuum CC of XX with xCx\in C and {y,z}C\{y,z\}\cap C\neq\emptyset, {y,z}C\{y,z\}\subseteq C. In this case, we say that yy and zz are pointspoints ofof nonnon-WildernessWilderness ofof XX.

Definition 2.2.

Let XX be a continuum. Then:

  • The continuum XX is called a D-continuum if for any pairwise disjoint nondegenerate subcontinua AA and BB of XX, there exists a subcontinuum CC of XX such that

    (i) ACBCA\cap C\neq\emptyset\neq B\cap C, and

    (ii) ACA\setminus C\neq\emptyset or BCB\setminus C\neq\emptyset.

  • The continuum XX is called a DD^{**}-continuum if for any pairwise disjoint nondegenerate subcontinua AA and BB of XX, there exists a subcontinuum CC of XX such that

    (i) ACBCA\cap C\neq\emptyset\neq B\cap C, and

    (ii) BCB\setminus C\neq\emptyset.

  • The continuum XX is called a DD^{*}-continuum if for any pairwise disjoint nondegenerate subcontinua AA and BB of XX, there exists a subcontinuum CC of XX such that

    (i) ACBCA\cap C\neq\emptyset\neq B\cap C, and

    (ii) ACA\setminus C\neq\emptyset and BCB\setminus C\neq\emptyset.

Note that a continuum XX is a DD^{**}-continuum if and only if for each aXa\in X and for each nondegenerate subcontinuum BB of XX with aBa\notin B, there exists a subcontinuum CC of XX such that aCa\in C, BCB\cap C\neq\emptyset and BCB\setminus C\neq\emptyset.

It is clear that every DD^{*}-continuum is a DD^{**}-continuum and every DD^{**}-continuum is a DD-continuum. Note that the sin1x\sin\frac{1}{x}-continuum is a DD-continuum which is not a DD^{**}-continuum.

In [14, Section 2], it is proven that the classes of Wilder continua and DD^{*}-continua are strictly contained in the class of DD^{**}-continua. Since every nondegenerate indecomposable continuum has uncountably many composants [16, Theorem 11.15], we can easily see that every nondegenerate DD-continuum is decomposable. For other relationships between the classes of the above continua and other classes of continua, see [2, Figure 6].

Let XX and YY be any compacta. Then, a set-valued function f:X2Yf:X\to 2^{Y} is called an upperupper semisemi-continuouscontinuous functionfunction provided that for each xXx\in X and each open subset VV of YY containing f(x)f(x), there exists an open subset UU of XX which contains xx such that if zUz\in U, then f(z)Vf(z)\subset V. The graphgraph of a set-valued function f:X2Yf:X\to 2^{Y} is the set G(f)={(x,y)X×Y|yf(x)}G(f)=\{(x,y)\in X\times Y~|~y\in f(x)\}. We say that a set-valued function f:X2Yf:X\to 2^{Y} is surjectivesurjective if for each yYy\in Y, there exists xXx\in X such that yf(x)y\in f(x).

Every map f:XYf:X\to Y induces the upper semi-continuous function f~:X2Y\tilde{f}:X\to 2^{Y} defined by f~(x)={f(x)}\tilde{f}(x)=\{f(x)\} for each xXx\in X. Therefore, if necessary, we may regard a map f:XYf:X\to Y as the upper semi-continuous function f~:X2Y\tilde{f}:X\to 2^{Y}.

An inverseinverse sequencesequence is a double sequence {Xi,fi}i=1\{X_{i},f_{i}\}_{i=1}^{\infty} of compacta XiX_{i} and upper semi-continuous functions fi:Xi+12Xif_{i}:X_{i+1}\to 2^{X_{i}}. The spaces XiX_{i} are called the factorfactor spacesspaces and the upper semi-continuous functions fif_{i} the bondingbonding functionsfunctions. We denote the subspace {(xi)i=1i=1Xi|\{(x_{i})_{i=1}^{\infty}\in\prod_{i=1}^{\infty}X_{i}~|~for each i1,xifi(xi+1)}i\geq 1,~x_{i}\in f_{i}(x_{i+1})\} of i=1Xi\prod_{i=1}^{\infty}X_{i} by lim{Xi,fi}i=1\underleftarrow{{\rm lim}}\{X_{i},f_{i}\}_{i=1}^{\infty}. lim{Xi,fi}i=1\underleftarrow{{\rm lim}}\{X_{i},f_{i}\}_{i=1}^{\infty} is also denoted by XX_{\infty}. XX_{\infty} is called the inverseinverse limitlimit ofof {Xi,fi}i=1\{X_{i},f_{i}\}_{i=1}^{\infty}.

3. Being a Wilder continuum is not a Whitney reversible property

First, we show the following result which can yield a lot of examples of non-Wilder continua whose all positive Whitney levels are Wilder continua.

Theorem 3.1.

Let XX be a nondegenerate continuum and let μ:C(X)[0,μ(X)]\mu:C(X)\to[0,\mu(X)] be a Whitney map. Assume there exists a totally disconnected subset TT of XX satisfying the following property:

\bullet If a,ba,b and cc are pairwise distinct points in XTX\setminus T, then there exists a subcontinuum LL of XX such that aLa\in L and LL contains exactly one of bb and cc.

Then, μ1(t)\mu^{-1}(t) is a Wilder continuum for each t(0,μ(X))t\in(0,\mu(X)).

Proof.

The proof is obtained by slightly modifying the proof of [14, Theorem 4.2] as follows:

(\sharp) In Case 3 of the proof of [14, Theorem 4.2], the second author and the third author chose points aA(BC)a\in A\setminus(B\cup C), bB(AC)b\in B\setminus(A\cup C) and cC(AB)c\in C\setminus(A\cup B). Instead of it, choose points aA(BCT)a\in A\setminus(B\cup C\cup T), bB(ACT)b\in B\setminus(A\cup C\cup T) and cC(ABT)c\in C\setminus(A\cup B\cup T).

Then, we can prove the theorem. ∎

By the following example, we see that the property of being a Wilder continuum is not a Whitney reversible property. This result gives a partial answer to [14, Question 5.2].

Example 3.2.

Let

X={(t+|cos(1t)|,sin(1t))2|0<t1}{(cos(t),sin(t))2|0t2π}{(t|cos(1t)|,sin(1t))2|0<t1}({1cos(1)}×[2,sin(1)])([1cos(1),1+cos(1)]×{2})({1+cos(1)}×[2,sin(1)])\begin{array}[]{ccl}X&=&\{(t+|{\rm cos}(\frac{1}{t})|,{\rm sin}(\frac{1}{t}))\in\mathbb{R}^{2}~|~0<t\leq 1\}\\ &&\cup\{({\rm cos}(t),{\rm sin}(t))\in\mathbb{R}^{2}~|~0\leq t\leq 2\pi\}\\ &&\cup\{(-t-|{\rm cos}(\frac{1}{t})|,{\rm sin}(\frac{1}{t}))\in\mathbb{R}^{2}~|~0<t\leq 1\}\\ &&\cup(\{-1-{\rm cos}(1)\}\times[-2,{\rm sin}(1)])\\ &&\cup([-1-{\rm cos}(1),1+{\rm cos}(1)]\times\{-2\})\\ &&\cup(\{1+{\rm cos}(1)\}\times[-2,{\rm sin}(1)])\\ \end{array}

(see Figure 1). XX has two arc components. One of them is a simple closed curve, and the other is homeomorphic to \mathbb{R}. Let xx, yy and zz be points in XX as in Figure 1. Since there does not exist a subcontinuum of XX which contains xx and exactly one of yy and zz, XX is not Wilder.

Let μ:C(X)[0,μ(X)]\mu:C(X)\to[0,\mu(X)] be a Whitney map. Let T={y,z}T=\{y,z\}. Then, it is easy to see that TT is totally disconnected. Also, we see that if a,ba,b and cc are pairwise distinct points in XTX\setminus T, then there exists a subcontinuum LL of XX such that aLa\in L and LL contains exactly one of bb and cc. Hence, by the previous result, we see that μ1(t)\mu^{-1}(t) is a Wilder continuum for each t(0,μ(X))t\in(0,\mu(X)).

Remark 3.3.

In [2, Example 3.5], Espinoza and the second author constructed an example of a DD^{*}-continuum which is not Wilder. Compared to their example, it is easy to see that the continuum XX in the previous example has such properties.

Remark 3.4.

Let XX, yy, zz be as in Example 3.2. Let cc be the midpoint of the line segment yzyz. Let n1n\geq 1 and let XkX_{k} be the subcontinuum of 2\mathbb{R}^{2} with XX rotated kπ2n\frac{k\pi}{2n} clockwise around cc for each 1kn1\leq k\leq n. Let Z0=X×{0}3Z_{0}=X\times\{0\}\subseteq\mathbb{R}^{3} and let Zk=Xk×{1k}3Z_{k}=X_{k}\times\{\frac{1}{k}\}\subseteq\mathbb{R}^{3} for each 1kn1\leq k\leq n. Now, let SS be the arc component of XX which is a simple closed curve, and for each 0kn0\leq k\leq n, let Sk=S×{1k}ZkS_{k}=S\times\{\frac{1}{k}\}\subseteq Z_{k}. Let 𝒟\mathcal{D} be the upper semi-continuous decomposition of k=0nZk\bigcup_{k=0}^{n}Z_{k} defined by 𝒟={{a}×{0,1,12,,1n}|aS}{{z}|zk=0n(ZkSk)}\mathcal{D}=\{\{a\}\times\{0,{1},\frac{1}{2},\ldots,\frac{1}{n}\}\ |\ a\in S\}\cup\{\{z\}\ |\ z\in\bigcup_{k=0}^{n}(Z_{k}\setminus S_{k})\}. Then, by similar arguments in Example 3.2, we can easily see that the quotient space X/𝒟X/\mathcal{D} is a non-Wilder continuum whose all positive Whitney levels are Wilder continua.

Refer to caption
Figure 1. The continuum XX in Example 3.2.
Question 1.

(See [14, Question 5.2].) Is the property of being a DD-continuum (or a DD^{*}-continuum, or a DD^{**}-continuum) a Whitney reversible property?

4. Inverse limits with monotone upper semi-continuous bonding functions

In this section, we deal with topics on inverse limits with set-valued bonding functions.

Note that if a map f:XYf:X\to Y between compacta is monotone, then it satisfies the condition of ff in the following definition.

Definition 4.1 ([7, Definition 3.2]).

Let XX and YY be compacta. Then, an upper semi-continuous function f:X2Yf:X\to 2^{Y} is said to be monotone if each of the projection maps pXG(f):G(f)Xp_{X}^{G(f)}:G(f)\to X and pYG(f):G(f)Yp_{Y}^{G(f)}:G(f)\to Y is a monotone map.

The following results are proven in [17].

Theorem 4.2.

([17, Example 5.1]) There exists an inverse sequence {Xi,fi}i=1\{X_{i},f_{i}\}_{i=1}^{\infty} of DD^{*}-continua with surjective monotone upper semi-continuous bonding functions such that lim{Xi,fi}i=1\underleftarrow{{\rm lim}}\{X_{i},f_{i}\}_{i=1}^{\infty} is not a DD^{*}-continuum.

Theorem 4.3.

([17, Example 5.4]) There exists an inverse sequence {Xi,fi}i=1\{X_{i},f_{i}\}_{i=1}^{\infty} of DD-continua with surjective monotone upper semi-continuous bonding functions such that lim{Xi,fi}i=1\underleftarrow{{\rm lim}}\{X_{i},f_{i}\}_{i=1}^{\infty} is not a DD-continuum.

The main aim of this section is to prove Theorem 4.8, which is in contrast to the above results. To prove the theorem, we need Theorem 4.6 proven in [17].

Definition 4.4.

([17, Definition 3.1]) Let 𝒫\mathcal{P} be a topological property of continua. Then, we say that property 𝒫\mathcal{P} satisfies the monotonic condition I if for any continua XX and YY with property 𝒫\mathcal{P} and for each surjective monotone upper semi-continuous function f:X2Yf:X\to 2^{Y}, G(f)G(f) is a continuum having property 𝒫\mathcal{P}.

Definition 4.5.

([17, Definition 3.2]) Let 𝒫\mathcal{P} be a topological property of continua. Then, we say that property 𝒫\mathcal{P} satisfies the monotonic condition II if for any inverse sequence {Xi,fi}i=1\{X_{i},f_{i}\}_{i=1}^{\infty} of continua having property 𝒫\mathcal{P} with surjective monotone bonding maps, XX_{\infty} is a continuum having property 𝒫\mathcal{P}.

Theorem 4.6.

([17, Theorem 3.6]) Let 𝒫\mathcal{P} be a topological property of continua. Then, property 𝒫\mathcal{P} satisfies the monotonic conditions I and II if and only if for each inverse sequence {Xi,fi}i=1\{X_{i},f_{i}\}_{i=1}^{\infty} of continua having property 𝒫\mathcal{P} with surjective monotone upper semi-continuous functions, XX_{\infty} is a continuum having property 𝒫\mathcal{P}.

Furthermore, we need the following result. The proof is similar to the proof of [2, Theorem 4.3]. Hence, we omit the proof.

Lemma 4.7.

(See also [2, Theorem 4.3]) Let {Xi,fi}i=1\{X_{i},f_{i}\}_{i=1}^{\infty} be an inverse sequence of DD^{**}-continua with surjective monotone maps. Then, lim{Xi,fi}i=1\underleftarrow{{\rm lim}}\{X_{i},f_{i}\}_{i=1}^{\infty} is also a DD^{**}-continuum.

The following theorem is the main result in this section.

Theorem 4.8.

Let {Xi,fi}i=1\{X_{i},f_{i}\}_{i=1}^{\infty} be an inverse sequence of compacta with surjective monotone upper semi-continuous bonding functions. If XiX_{i} is a DD^{**}-continuum for each i1i\geq 1, then lim{Xi,fi}i=1\underleftarrow{{\rm lim}}\{X_{i},f_{i}\}_{i=1}^{\infty} is also a DD^{**}-continuum.

Proof.

By Theorem 4.6, it is enough to show that the property of being DD^{**} satisfies the monotonic conditions I and II. By Lemma 4.7, it is easy to see that the property of being DD^{**} satisfies the monotonic condition II. Hence, we only show that the property of being DD^{**} satisfies the monotonic condition I.

Let XX and YY be DD^{**}-continua and let f:X2Yf:X\to 2^{Y} be a surjective monotone upper semi-continuous function. First, since ff is upper semi-continuous, by Theorem [5, Theorem 2.1], G(f)G(f) is compact. Also, by the monotonicity of ff, G(f)G(f) is connected. Hence, G(f)G(f) is a continuum.

Let (x,y)G(f)(x,y)\in G(f) and let AA be a nondegenerate subcontinuum of G(f)G(f) such that (x,y)A(x,y)\notin A. Put pX=pXG(f)p_{X}=p_{X}^{G(f)} and pY=pYG(f)p_{Y}=p_{Y}^{G(f)}.

  • Case 1

    xpX(A)x\notin p_{X}(A) and ypY(A)y\notin p_{Y}(A)

    Since AA is not a one point set, we may assume pX(A)p_{X}(A) is not a one point set. Since XX is DD^{**}, there exists a subcontinuum CXC\subset X such that xCx\in C, pX(A)Cp_{X}(A)\cap C\neq\emptyset and pX(A)Cp_{X}(A)\setminus C\neq\emptyset. Then, pX1(C)p_{X}^{-1}(C) is a subcontinuum of G(f)G(f) such that (x,y)pX1(C)(x,y)\in p_{X}^{-1}(C), pX1(C)Ap_{X}^{-1}(C)\cap A\neq\emptyset and ApX1(C)A\setminus p_{X}^{-1}(C)\neq\emptyset.

  • Case 2.

    xpX(A)x\in p_{X}(A) or ypY(A)y\in p_{Y}(A).

    In this case, we may assume xpX(A)x\in p_{X}(A).

    • Case 2.1.

      pX(A)p_{X}(A) is not a one point set.

      In this case, by using the fact that ff is monotone, we see that pX1(x)p_{X}^{-1}(x) is a subcontinuum of G(f)G(f) such that (x,y)pX1(x)(x,y)\in p_{X}^{-1}(x), pX1(x)Ap_{X}^{-1}(x)\cap A\neq\emptyset and ApX1(x)A\setminus p_{X}^{-1}(x)\neq\emptyset.

    • Case 2.2.

      pX(A)p_{X}(A) is a one point set.

      In this case, note that pY(A)p_{Y}(A) is a nondegenerate subcontinuum of YY and ypY(A)y\notin p_{Y}(A). Since YY is DD^{**}, there exists a subcontinuum DD of YY such that yDy\in D, pY(A)Dp_{Y}(A)\cap D\neq\emptyset and pX(A)Dp_{X}(A)\setminus D\neq\emptyset. Then, pX1(D)p_{X}^{-1}(D) is a subcontinuum of G(f)G(f) such that (x,y)pX1(D)(x,y)\in p_{X}^{-1}(D), pX1(D)Ap_{X}^{-1}(D)\cap A\neq\emptyset and ApX1(D)A\setminus p_{X}^{-1}(D)\neq\emptyset.

From the above, we see that G(f)G(f) is a DD^{**}-continuum. Hence, the property of being DD^{**} satisfies the monotonic condition I. This completes the proof. ∎

Example 4.9.

Let A1A_{1}, A2A_{2}, A3A_{3} and A4A_{4} be subspaces of 2\mathbb{R}^{2} defined by

A1={(cos(t)+3,sin(t)2)2|0t2π},A2={(t+|cos(1t)|+3,sin(1t)2)2|0<t1}([cos(1)+4,5]×{sin(1)2}){(t+6,sin(1t)2)2|0<t1}({6}×[3,sin(16)+2)),A3={(6,sin(16)+2)},andA4={(t,sin(1t)+2)2|0<t<6}({0}×[sin(1)2,3])([0,cos(1)+2]×{sin(1)2}){(t|cos(1t)|+3,sin(1t)2)2|0<t1}.\begin{array}[]{ccl}A_{1}&=&\{({\rm cos}(t)+3,{\rm sin}(t)-2)\in\mathbb{R}^{2}~|~0\leq t\leq 2\pi\},\\ A_{2}&=&\{(t+|{\rm cos}(\frac{1}{t})|+3,-{\rm sin}(\frac{1}{t})-2)\in\mathbb{R}^{2}~|~0<t\leq 1\}\\ &&\cup([{\rm cos}(1)+4,5]\times\{-{\rm sin}(1)-2\})\\ &&\cup\{(-t+6,-{\rm sin}(\frac{1}{t})-2)\in\mathbb{R}^{2}~|~0<t\leq 1\}\\ &&\cup(\{6\}\times[-3,{\rm sin}(\frac{1}{6})+2)),\\ A_{3}&=&\{(6,{\rm sin}(\frac{1}{6})+2)\},{\rm and}\\ A_{4}&=&\{(t,{\rm sin}(\frac{1}{t})+2)\in\mathbb{R}^{2}~|~0<t<6\}\cup(\{0\}\times[-{\rm sin}(1)-2,3])\\ &&\cup([0,-{\rm cos}(1)+2]\times\{-{\rm sin}(1)-2\})\\ &&\cup\{(-t-|{\rm cos}(\frac{1}{t})|+3,-{\rm sin}(\frac{1}{t})-2)\in\mathbb{R}^{2}~|~0<t\leq 1\}.\end{array}

Note that A1,A2,A3,andA4A_{1},~A_{2},~A_{3},~{\rm and}~A_{4} are pairwise disjoint. Let X=A1A2A3A4X=A_{1}\cup A_{2}\cup A_{3}\cup A_{4} (see figure 2). We can see that there is a homeomorphism h:A2A4A2A4h:A_{2}\cup A_{4}\to A_{2}\cup A_{4} such that h(A2)=A4andh(A4)=A2h(A_{2})=A_{4}~{\rm and}~h(A_{4})=A_{2}.

Refer to caption
Figure 2. The continuum XX in Example 2

Let f:X2Xf:X\to 2^{X} be the upper semi-continuous function defined by

f(x)\displaystyle f(x) ={A3(xA1),{h(x)}(xA2),A1(xA3),{h(x)}(xA4).\displaystyle=\begin{cases}~A_{3}&(x\in A_{1}),\\ ~\{h(x)\}&(x\in A_{2}),\\ ~A_{1}&(x\in A_{3}),\\ ~\{h(x)\}&(x\in A_{4}).\end{cases}

It is easy to see that ff is a surjective monotone upper semi-continuous function.

For each i1i\geq 1, let Xi=XX_{i}=X and let fi=f:Xi+12Xif_{i}=f:X_{i+1}\to 2^{X_{i}}. By Theorem 4.8, the inverse limit lim{Xi,fi}i=1\underleftarrow{{\rm lim}}\{X_{i},f_{i}\}_{i=1}^{\infty} is a DD^{**}-continuum.

Remark 4.10.

The continuum XX in the previous example also appears in [14, Example 2.3] as an example of DD^{**}-continuum which is neither Wilder nor DD^{*}.

Remark 4.11.

In [17], the third author showed that inverse limits of Wilder continua with surjective monotone upper semi-continuous bonding functions are also Wilder continua.

5. A DD^{**}-continuum containing neither Wilder continua nor DD^{*}-continua

Let XX be a nondegenerate continuum. Then XX is said to be arc-like if for each ε>0\varepsilon>0, there exists a surjective map f:X[0,1]f:X\to[0,1] such that for each y[0,1]y\in[0,1], diamf1(y)<ε{\rm diam}f^{-1}(y)<\varepsilon. A continnuum is said to be hereditarilyhereditarily decomposabledecomposable if each of its all subcontinua is decomposable.

Theorem 5.1.

([2, Remark 5,11]) There exists an arc-like hereditarily decomosable continuum containing no DD-continua.

A continuum XX is said to be hereditarily arcwise connected if each of its subcontinuum is arcwise connected. Also, if each subcontinuum of XX is a Wilder continuum (resp. a DD-continuum, a DD^{*}-continuum, a DD^{**}-continuum), then XX is called a hereditarily Wilder continuum (resp. a hereditarily DD-continuum, a hereditarily DD^{*}-continuum, a hereditarily DD^{**}-continuum).

Theorem 5.2.

(See [2, Cororally 5,12]) and [14, Cororally 3.2]) There exists an arc-like hereditarily DD-continuum containing no DD^{**}-continua.

Hence, it is natural to ask whether or not there exists a hereditarily DD^{**}-continuum containing no DD^{*}-continua. The answer to this question is negative by the following result.

Corollary 5.3.

[14, Corollary 3.4]) Let XX be a nondegenerate continuum. Then, the following are equivalent.

  • (1)

    XX is a hereditarily Wilder continuum;

  • (2)

    XX is a hereditarily DD^{*}-continuum;

  • (3)

    XX is a hereditarily DD^{**}-continuum;

  • (4)

    XX is a hereditarily arcwise connected continuum.

However, in Theorem 5.4, we show that there exists a DD^{**}-continuum containing neither Wilder continua nor DD^{*}-continua.

Let BB be the subcontinuum of 2\mathbb{R}^{2} defined by

B=({16π+1}×[(sin(1)+2),3]){(t+|cos(4t)|+8π+1,sin(4t)+2)2| 0<t8π}{(cos(t)+8π+1,sin(t)+2)2| 0t2π}{(t|cos(4t)|+8π+1,sin(4t)+2)2| 0<t8π}([1,1]×{3})({1}×[1,3]){((t+1),sin(16πt)+2)2| 0<t16π}({(16π+1)}×[3,sin(1)+2]){((t+|cos(4t)|+8π+1),(sin(4t)+2))2| 0<t8π}{(cos(t)(8π+1),sin(t)2)2| 0t2π}{((t|cos(4t)|+8π+1),(sin(4t)+2))2| 0<t8π}([1,1]×{3})({1}×[3,1]){(t+1,(sin(16πt)+2))2| 0<t16π}\begin{array}[]{ccl}B&=&(\{\frac{16}{\pi}+1\}\times[-(\sin{(1)}+2),3])\\ &&\cup\{(t+|\cos{(\frac{4}{t})}|+\frac{8}{\pi}+1,\sin{(\frac{4}{t})}+2)\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\}\\ &&\cup\{(\cos{(t)}+\frac{8}{\pi}+1,\sin{(t)}+2)\in\mathbb{R}^{2}\ |\ 0\leq t\leq 2\pi\}\\ &&\cup\{(-t-|\cos{(\frac{4}{t})}|+\frac{8}{\pi}+1,\sin{(\frac{4}{t})}+2)\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\}\\ &&\cup([-1,1]\times\{3\})\\ &&\cup(\{-1\}\times[1,3])\cup\{(-(t+1),\sin{(\frac{16}{\pi t})}+2)\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{16}{\pi}\}\\ &&\cup(\{-(\frac{16}{\pi}+1)\}\times[-3,\sin{(1)}+2])\\ &&\cup\{(-(t+|\cos{(\frac{4}{t})}|+\frac{8}{\pi}+1),-(\sin{(\frac{4}{t})}+2))\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\}\\ &&\cup\{(\cos{(t)}-(\frac{8}{\pi}+1),\sin{(t)}-2)\in\mathbb{R}^{2}\ |\ 0\leq t\leq 2\pi\}\\ &&\cup\{(-(-t-|\cos{(\frac{4}{t})}|+\frac{8}{\pi}+1),-(\sin{(\frac{4}{t})}+2))\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\}\\ &&\cup([-1,1]\times\{-3\})\\ &&\cup(\{1\}\times[-3,-1])\cup\{(t+1,-(\sin{(\frac{16}{\pi t})}+2))\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{16}{\pi}\}\end{array}

(see Figure 3). Let PP and QQ be the subcontinua of BB defined by

P=({16π+1}×[0,3]){(t+|cos(4t)|+8π+1,sin(4t)+2)2| 0<t8π}{(cos(t)+8π+1,sin(t)+2)2| 0t2π}{(t|cos(4t)|+8π+1,sin(4t)+2)2| 0<t8π}([1,1]×{3})({1}×[1,3]){((t+1),sin(16πt)+2)2| 0<t16π}({(16π+1)}×[0,sin(1)+2]),Q=({(16π+1)}×[3,0]){((t+|cos(4t)|+8π+1),(sin(4t)+2))2| 0<t8π}{(cos(t)(8π+1),sin(t)2)2| 0t2π}{((t|cos(4t)|+8π+1),(sin(4t)+2))2| 0<t8π}([1,1]×{3})({1}×[3,1]){(t+1,(sin(16πt)+2))2| 0<t16π}({16π+1}×[(sin(1)+2),0]).\begin{array}[]{ccl}P&=&(\{\frac{16}{\pi}+1\}\times[0,3])\\ &&\cup\{(t+|\cos{(\frac{4}{t})}|+\frac{8}{\pi}+1,\sin{(\frac{4}{t})}+2)\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\}\\ &&\cup\{(\cos{(t)}+\frac{8}{\pi}+1,\sin{(t)}+2)\in\mathbb{R}^{2}\ |\ 0\leq t\leq 2\pi\}\\ &&\cup\{(-t-|\cos{(\frac{4}{t})}|+\frac{8}{\pi}+1,\sin{(\frac{4}{t})}+2)\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\}\\ &&\cup([-1,1]\times\{3\})\\ &&\cup(\{-1\}\times[1,3])\cup\{(-(t+1),\sin{(\frac{16}{\pi t})}+2)\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{16}{\pi}\}\\ &&\cup(\{-(\frac{16}{\pi}+1)\}\times[0,\sin{(1)}+2]),\\ Q&=&(\{-(\frac{16}{\pi}+1)\}\times[-3,0])\\ &&\cup\{(-(t+|\cos{(\frac{4}{t})}|+\frac{8}{\pi}+1),-(\sin{(\frac{4}{t})}+2))\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\}\\ &&\cup\{(\cos{(t)}-(\frac{8}{\pi}+1),\sin{(t)}-2)\in\mathbb{R}^{2}\ |\ 0\leq t\leq 2\pi\}\\ &&\cup\{(-(-t-|\cos{(\frac{4}{t})}|+\frac{8}{\pi}+1),-(\sin{(\frac{4}{t})}+2))\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\}\\ &&\cup([-1,1]\times\{-3\})\\ &&\cup(\{1\}\times[-3,-1])\cup\{(t+1,-(\sin{(\frac{16}{\pi t})}+2))\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{16}{\pi}\}\\ &&\cup(\{\frac{16}{\pi}+1\}\times[-(\sin{(1)}+2),0]).\end{array}

Also, let R0R^{0}, Q0Q^{0}, R1R^{1} and Q1Q^{1} be the subspaces of BB defined by

R0={((t+1),sin(16πt)+2)2| 0<t16π},Q0={(t|cos(4t)|+8π+1,sin(4t)+2)2| 0<t8π},R1={(t+1,(sin(16πt)+2))2| 0<t16π},Q1={(t+|cos(4t)|8π1,(sin(4t)+2))2| 0<t8π}.\begin{array}[]{ccl}R^{0}&=&\{(-(t+1),\sin{(\frac{16}{\pi t})}+2)\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{16}{\pi}\},\\ Q^{0}&=&\{(-t-|\cos{(\frac{4}{t})}|+\frac{8}{\pi}+1,\sin{(\frac{4}{t})}+2)\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\},\\ R^{1}&=&\{(t+1,-(\sin{(\frac{16}{\pi t})}+2))\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{16}{\pi}\},\\ Q^{1}&=&\{(t+|\cos{(\frac{4}{t})}|-\frac{8}{\pi}-1,-(\sin{(\frac{4}{t})}+2))\in\mathbb{R}^{2}\ |\ 0<t\leq\frac{8}{\pi}\}.\end{array}

Then, R0R^{0}, Q0Q^{0}, R1R^{1} and Q1Q^{1} are homeomorphic to [0,1)[0,1) respectively. Also, note that ClBR0{\rm Cl}_{B}R^{0}, ClBQ0{\rm Cl}_{B}Q^{0}, ClBR1{\rm Cl}_{B}R^{1} and ClBQ1{\rm Cl}_{B}Q^{1} are homeomorphic to the sin1x\sin\frac{1}{x}-continuum. Furthermore, let aa, bb, pp, pp^{\prime}, qq, qq^{\prime}, ss, ss^{\prime}, tt, tt^{\prime}, uu, uu^{\prime}, vv, vBv^{\prime}\in B be the points as in Figure 3. Finally, let S(B)={aS(B)=\{a, bb, pp, pp^{\prime}, qq, qq^{\prime}, ss, ss^{\prime}, tt, tt^{\prime}, uu, uu^{\prime}, vv, v}v^{\prime}\}.

In the following theorem, if {Xi,fi}i=0\{X_{i},f_{i}\}_{i=0}^{\infty} is an inverse sequence with single valued bonding maps, then we denote the map fifj1:XjXif_{i}\circ\cdots\circ f_{j-1}:X_{j}\to{X_{i}} by fi,jf_{i,j} if j>i+1j>i+1. Also, let fi,i+1=fif_{i,i+1}=f_{i}. Furthermore, for each n0n\geq 0, let πn:XXn\pi_{n}:X_{\infty}\to X_{n} be the projection. Finally, if f:XYf:X\to Y is a map and yYy\in Y is a point such that f1(y)f^{-1}(y) is a one point set, then we also denote the point in f1(y)f^{-1}(y) by f1(y)f^{-1}(y).

Theorem 5.4.

There exists a DD^{**}-continuum containing neither Wilder continua nor DD^{*}-continua.

Proof.

We follow the scheme from [3, Section 3], which is originally based on the idea of the construction of Janiszewski’s hereditarily decomposable, arc-like, and arcless continuum [6]. In particular, almost all notations and terminology in the proof are taken from [3, Section 3]. In order to avoid complications, we will omit the parts of the way of construction of the required continuum that overlap with the construction of the planar arcless continuum-chainable continuum that appeared in [3]. There are three differences in construction between the continuum in [3, Section 3] and ours. Two of them are as follows:

(i) Instead of BB in [3, Section 3], in our example, we let BB be the continuum defined before Theorem 5.4.

(ii) Let X0={(x,0)2|1x1}X_{0}=\{(x,0)\in\mathbb{R}^{2}\ |\ -1\leq x\leq 1\} and d0=(0,0)d_{0}=(0,0). Also, let X1=B{(x,0)2|16π2x16π1or16π+1x16π+2}X_{1}=B\cup\{(x,0)\in\mathbb{R}^{2}\ |\ -\frac{16}{\pi}-2\leq x\leq-\frac{16}{\pi}-1\ {\rm or}\ \frac{16}{\pi}+1\leq x\leq\frac{16}{\pi}+2\} and let f01:X1X0f_{0}^{1}:X_{1}\to X_{0} be the map defined by

f01(x,y)={(x+16π+1,y)(x16π1),(0,0)(16π1x16π+1),(x16π1,y)(x16π+1)).f_{0}^{1}(x,y)=\left\{\begin{array}[]{l}(x+\frac{16}{\pi}+1,y)\hskip 12.0pt(x\leq-\frac{16}{\pi}-1),\\ (0,0)\hskip 12.0pt(-\frac{16}{\pi}-1\leq x\leq\frac{16}{\pi}+1),\\ (x-\frac{16}{\pi}-1,y)\hskip 9.60004pt(x\geq\frac{16}{\pi}+1)).\end{array}\right.

See Figure 4. We say that X1X_{1} is obtained from X0X_{0} by blowing up the point d0=(0,0)X0d_{0}=(0,0)\in X_{0} to a copy of BB. Also, following the scheme in [3, Section 3], we continue blowing up points of an appropriately chosen sequence {dn}n=0\{d_{n}\}_{n=0}^{\infty} to copies of BB, and for each n0,n\geq 0, we can obtain Xn+1X_{n+1} from XnX_{n} and fn:Xn+1Xnf_{n}:X_{n+1}\to X_{n}. For each n1n\geq 1, let Bn=fn11(dn1)B_{n}=f_{n-1}^{-1}(d_{n-1}) and let PnP_{n}, QnQ_{n}, Rn0R_{n}^{0}, Qn0Q_{n}^{0}, Rn0R_{n}^{0}, Rn1R_{n}^{1}, ana_{n}, bnb_{n}, pnp_{n}, pnp^{\prime}_{n}, qnq_{n}, qnq^{\prime}_{n}, sns_{n}, sns_{n}^{\prime}, tnt_{n}, tnt_{n}^{\prime}, unu_{n}, unu_{n}^{\prime}, vnv_{n}, vnv_{n}^{\prime} be subsets and points in BnB_{n} corresponding to PP, QQ, R0R^{0}, Q0Q^{0}, R1R^{1}, Q1Q^{1}, aa, bb, pp, pp^{\prime}, qq, qq^{\prime}, ss, ss^{\prime}, tt, tt^{\prime}, uu, uu^{\prime}, vv, vv^{\prime} in BB respectively. Let S(X0)=E(X0)S(X_{0})=E(X_{0}). Also, for each n1n\geq 1, let

S(Xn)=f0,n1(S(X0))(k=1nfk,n1({ak,bk,pk,pk,qk,qk,sk,sk,tk,tk,uk,uk,vk,vk}))S(X_{n})=f_{0,n}^{-1}(S(X_{0}))\cup(\bigcup_{k=1}^{n}f_{k,n}^{-1}(\{a_{k},b_{k},p_{k},p^{\prime}_{k},q_{k},q^{\prime}_{k},s_{k},s_{k}^{\prime},t_{k},t_{k}^{\prime},u_{k},u_{k}^{\prime},v_{k},v_{k}^{\prime}\}))

.

We may assume the following condition (this is the third difference in construction between the planar arcless continuum-chainable continuum that appeared in [3, Section 3]) and ours):

(iii) For each n1n\geq 1, dnXnS(Xn)d_{n}\in X_{n}\setminus S(X_{n}).

Let X=lim{Xn,fn}n=0X_{\infty}=\underleftarrow{{\rm lim}}\{X_{n},f_{n}\}_{n=0}^{\infty}. We show that XX_{\infty} has the required property.

Claim 1. XX_{\infty} is a DD^{**}-continuum.

Proof of Claim 1. To prove Claim 1, first, we prove that XnX_{n} is a DD^{**}-continuum for each n0n\geq 0. To prove it , we need to prove the following subclaim.

Subclaim. Let n0n\geq 0. Let zXnS(Xn)z\in X_{n}\setminus S(X_{n}) and AA be a subarc of XnX_{n} such that AXnA\neq X_{n} and zAE(A)z\in A\setminus E(A). Then, for each xXnAx\in X_{n}\setminus A, there exists a subcontinuum CC of XnX_{n} such that xC,ACx\in C,\ A\cap C\neq\emptyset and zCz\notin C.

Before the proof of Subclaim, note that the following holds:

()(\star) Let bBS(B)b\in B\setminus S(B) and let LL be a subarc of BB such that bLE(L)b\in L\setminus E(L). Then, for each yBLy\in B\setminus L, there exists a subcontinuum DD of BB such that yD,LDy\in D,\ L\cap D\neq\emptyset and bDb\notin D.

Proof of Subclaim. We prove Subclaim by induction on nn. If n=0n=0, then we can easily see the assertion holds. Let k1k\geq 1 and assume that the assertion holds for nk1n\leq k-1. Now, we prove that the assertion holds for n=kn=k.

Case A. z,xBkz,x\notin B_{k}.

Case B. zBk,xBkz\notin B_{k},\ x\in B_{k}.

In the cases above, by using inductive assumption, we can easily find a subcontinuum CC of XX with the required properties.

Case C. z,xBkz,x\in B_{k}.

In this case, by (\star) it is easy to see that there is a subcontinuum CC of XX with the required properties.

Case D. zBkz\in B_{k}, xBkx\notin B_{k} .

In this case, take a sufficiently small subarc JJ of Xk1X_{k-1} such that dk1(=fk1(Bk))JE(J)d_{k-1}(=f_{k-1}(B_{k}))\in J\setminus E(J) and fk1(x)Jf_{k-1}(x)\notin J. Then, by inductive assumption, there is a subcontinuum CC^{\prime} of Xk1X_{k-1} such that fk1(x)C,JCf_{k-1}(x)\in C^{\prime},\ J\cap C^{\prime}\neq\emptyset and dk1Cd_{k-1}\notin C^{\prime}. Take cJCc\in J\cap C^{\prime}. Then, we can take a subarc PP of XkX_{k} from fk11(c)f_{k-1}^{-1}(c) to the one of aka_{k} and bkb_{k}, and (PE(P))Bk=(P\setminus E(P))\cap B_{k}=\emptyset. We may assume akPa_{k}\in P. Let LL^{\prime} be a subarc of BkB_{k} such that zLE(L)LAE(A)z\in L^{\prime}\setminus E(L^{\prime})\subseteq L^{\prime}\subseteq A\setminus E(A) and akLa_{k}\notin L^{\prime}. Then, by ()(\star), there exists a subcontinuum DD^{\prime} of BkB_{k} such that akDa_{k}\in D^{\prime}, LDL^{\prime}\cap D^{\prime}\neq\emptyset and zDz\notin D^{\prime}. Let C=fk11(C)PDC=f_{k-1}^{-1}(C^{\prime})\cup P\cup D^{\prime}. Then, it is easy to see that CC has the required properties.

Hence, in every case we can find a subcontinuum CC of XkX_{k} with the required properties. This completes the proof of Subclaim.

Now, we prove XnX_{n} is a DD^{**}-continuum for each n0n\geq 0. Let FXnF\subsetneq X_{n} be a nondegenerate subcontinuum and xXnFx\in X_{n}\setminus F. Take any subarc AA of FF and any zA(E(A)S(Xn))z\in A\setminus(E(A)\cup S(X_{n})). By Subclaim, there exists a subcontinuum CC of XnX_{n} such that xC,ACx\in C,\ A\cap C\neq\emptyset and zCz\notin C. Note that FCF\setminus C\neq\emptyset. Hence, we see that XnX_{n} is a DD^{**}-continuum.

Therefore, XX_{\infty} is an inverse limit of DD^{**}-continua with surjective monotone bonding maps. Hence, by Lemma 4.7, XX_{\infty} is a DD^{**}-continuum. This completes the proof of Claim 1.

Refer to caption
Figure 3. The continuum BB
Refer to caption
Figure 4. X0,X1andf01.X_{0},\ X_{1}\ {\rm and}\ f_{0}^{1}.

Claim 2. XX_{\infty} contains no Wilder continua.

Proof of Claim 2. Let DD be a nondegenerate subcontinuum of XX_{\infty}. Then, there exists n00n_{0}\geq 0 such that πn0(D)\pi_{n_{0}}(D) is not a singleton. Take any subarc AA of πn0(D)S(Xn0)\pi_{n_{0}}(D)\setminus S(X_{n_{0}}). Let n1=min{n|nn0n_{1}=\min\{n\ |\ n\geq n_{0} and dnfn0,n1(AE(A))}d_{n}\in f_{n_{0},n}^{-1}(A\setminus E(A))\} and n2=min{n|n>n1anddnfn1,n1(fn0,n11(AE(A)){dn1})}n_{2}=\min\{n\ |\ n>n_{1}\ {\rm and}\ d_{n}\in f_{n_{1},n}^{-1}(f_{n_{0},n_{1}}^{-1}(A\setminus E(A))\setminus\{d_{n_{1}}\})\}. Note that fn1+1,n2+11(an1+1)f_{n_{1}+1,n_{2}+1}^{-1}(a_{n_{1}+1}), fn1+1,n2+11(bn1+1)f_{n_{1}+1,n_{2}+1}^{-1}(b_{n_{1}+1}), an2+1a_{n_{2}+1}, bn2+1πn2+1(D)b_{n_{2}+1}\in\pi_{n_{2}+1}(D). Since πn2+1(D)\pi_{n_{2}+1}(D) is connected, the one of the following holds:

(i) There is a subcontinuum TT of fn1,n2+11(dn1)f_{n_{1},n_{2}+1}^{-1}(d_{n_{1}}) containing fn1+1,n2+11(an1+1)f_{n_{1}+1,n_{2}+1}^{-1}(a_{n_{1}+1}) and fn1+1,n2+11(bn1+1)f_{n_{1}+1,n_{2}+1}^{-1}(b_{n_{1}+1}).

(ii) There is a subcontinuum of TT^{\prime} of fn21(dn2)f_{n_{2}}^{-1}(d_{n_{2}}) containing an2+1a_{n_{2}+1} and bn2+1b_{n_{2}+1}.

Assume (i) holds. Then, it is easy to see that either {pn1+1,qn1+1}fn1+1,n2+1(T)\{p_{n_{1}+1},q_{n_{1}+1}\}\subseteq f_{n_{1}+1,n_{2}+1}(T) or {pn1+1,qn1+1}fn1+1,n2+1(T)\{p^{\prime}_{n_{1}+1},q^{\prime}_{n_{1}+1}\}\subseteq f_{n_{1}+1,n_{2}+1}(T) holds. Hence, we may assume {pn1+1,qn1+1}fn1+1,n2+1(T)\{p_{n_{1}+1},q_{n_{1}+1}\}\subseteq f_{n_{1}+1,n_{2}+1}(T). In this case, we can easily see that πn1+11(pn1+1)\pi_{n_{1}+1}^{-1}(p_{n_{1}+1}) and πn1+11(qn1+1)\pi_{n_{1}+1}^{-1}(q_{n_{1}+1}) are points of non-Wilderness of DD. Hence, if (i) holds, then DD is not a Wilder continuum. We also see that DD is not a Wilder continuum if (ii) holds. This completes the proof of Claim 2.

Claim 3. XX_{\infty} contains no DD^{*}-continua.

Proof of Claim 3. Let D,n0,n1,n2D,\ n_{0},\ n_{1},\ n_{2} be as in the proof of Claim 2. Then, as in the proof of Claim 2, the one of the following holds:

(i) There is a subcontinuum TT of fn1,n2+11(dn1)f_{n_{1},n_{2}+1}^{-1}(d_{n_{1}}) containing fn1+1,n2+11(an1+1)f_{n_{1}+1,n_{2}+1}^{-1}(a_{n_{1}+1}) and fn1+1,n2+11(bn1+1)f_{n_{1}+1,n_{2}+1}^{-1}(b_{n_{1}+1}).

(ii) There is a subcontinuum of TT^{\prime} of fn21(dn2)f_{n_{2}}^{-1}(d_{n_{2}}) containing an2+1a_{n_{2}+1} and bn2+1b_{n_{2}+1}.

Assume (i) holds. We may assume that Pn1+1fn1+1,n2+1(T)P_{n_{1}+1}\subseteq f_{n_{1}+1,n_{2}+1}(T). Let R=ClX(πn1+11(Rn1+10))πn1+11(Rn1+10)R^{\prime}={\rm Cl}_{X_{\infty}}(\pi_{n_{1}+1}^{-1}(R_{n_{1}+1}^{0}))\setminus\pi_{n_{1}+1}^{-1}(R_{n_{1}+1}^{0}) and Q=ClX(πn1+11(Qn1+10))πn1+11(Qn1+10)Q^{\prime}={\rm Cl}_{X_{\infty}}(\pi_{n_{1}+1}^{-1}(Q_{n_{1}+1}^{0}))\setminus\pi_{n_{1}+1}^{-1}(Q_{n_{1}+1}^{0}). Then, RR^{\prime} and QQ^{\prime} are pairwise disjoint subcontinua of XX_{\infty}. Also, it is not difficult to see that if ZZ is a subcontinuum of XX_{\infty} such that RZQZR^{\prime}\cap Z\neq\emptyset\neq Q^{\prime}\cap Z and RZQZR^{\prime}\setminus Z\neq\emptyset\neq Q^{\prime}\setminus Z, then πn1+1(Z)\pi_{n_{1}+1}(Z) is a subcontinuum of Xn1+1X_{n_{1}+1} such that (ClXn1+1(Rn1+10)Rn1+10)πn1+1(Z)(ClXn1+1(Qn1+10)Qn1+10)πn1+1(Z)({\rm Cl}_{X_{n_{1}+1}}(R_{n_{1}+1}^{0})\setminus R_{n_{1}+1}^{0})\cap\pi_{n_{1}+1}(Z)\neq\emptyset\neq({\rm Cl}_{X_{n_{1}+1}}(Q_{n_{1}+1}^{0})\setminus Q_{n_{1}+1}^{0})\cap\pi_{n_{1}+1}(Z) and (ClXn1+1(Rn1+10)Rn1+10)πn1+1(Z)(ClXn1+1(Qn1+10)Qn1+10)πn1+1(Z)({\rm Cl}_{X_{n_{1}+1}}(R_{n_{1}+1}^{0})\setminus R_{n_{1}+1}^{0})\setminus\pi_{n_{1}+1}(Z)\neq\emptyset\neq({\rm Cl}_{X_{n_{1}}+1}(Q_{n_{1}+1}^{0})\setminus Q_{n_{1}+1}^{0})\setminus\pi_{n_{1}+1}(Z). However, there is not such a subcontinuum in Xn1+1X_{n_{1}+1}. Hence, this is a contradiction. Therefore, there is not a subcontinuum ZZ of XX_{\infty} such that RZQZR^{\prime}\cap Z\neq\emptyset\neq Q^{\prime}\cap Z and RZQZR^{\prime}\setminus Z\neq\emptyset\neq Q^{\prime}\setminus Z. Hence, if (i) holds, then DD is not a DD^{*}-continuum. We also see that DD is not a DD^{*}-continuum if (ii) holds. This completes the proof of Claim 3.

Thus, XX_{\infty} is a DD^{**}-continuum containing neither Wilder continua nor DD^{*}-continua. ∎

Also, we can get the following result. The proof is very similar to the proof of Theorem 5.4. The essential difference is the continuum obtained by blowing up a point of the factor space at each step. Hence, we only write about it in the proof.

Theorem 5.5.

There exists a Wilder continuum which contains no DD^{*}-continua.

Proof.

The proof of this theorem can be easily obtained by replacing the corresponding continua drawn in Figures 3 and 4 with the continua drawn in Figures 5 and 6 in the proof of the previous theorem. ∎

Refer to caption
Figure 5. The continuum BB
Refer to caption
Figure 6. X0,X1andf01.X_{0},\ X_{1}\ {\rm and}\ f_{0}^{1}.

Furthermore, we can get the following result.

Theorem 5.6.

There exists a DD^{*}-continuum which contains no Wilder continua.

Proof.

As in the previous theorem, the proof of this theorem can be obtained by replacing the corresponding continua drawn in Figures 3 and 4 with the continua drawn in Figures 7 and 8 in the proof of Theorem 5.4. To be exact, let

T1={(t+|cos(arcsin(11+t(sin(1t)+t)))|,11+t(sin(1t)+t))2| 0<t1},p1=(1+|cos(arcsin(12sin(1)+12))|,12sin(1)+12),T2={(t+|cos(arcsin(11+t(sin(1t)t)))|,11+t(sin(1t)t))2| 0<t1},p2=(1+|cos(arcsin(12sin(1)12))|,12sin(1)12),R(θ)=(cos(θ)sin(θ)sin(θ)cos(θ)),pq={(1λ)p+λq| 0λ1}(foreachp,q2),S1={(cos(t),sin(t))2| 0t2π},and\begin{array}[]{ccl}T_{1}&=&\{(t+|\cos{(\arcsin{(\frac{1}{1+t}(\sin{(\frac{1}{t})}+t))})}|,\frac{1}{1+t}(\sin{(\frac{1}{t})}+t))\in\mathbb{R}^{2}\ |\ 0<t\leq 1\},\\ p_{1}&=&(1+|\cos{(\arcsin{(\frac{1}{2}\sin{(1)}+\frac{1}{2})})}|,\frac{1}{2}\sin{(1)}+\frac{1}{2}),\\ T_{2}&=&\{(t+|\cos{(\arcsin{(\frac{1}{1+t}(\sin{(\frac{1}{t})}-t))})}|,\frac{1}{1+t}(\sin{(\frac{1}{t})}-t))\in\mathbb{R}^{2}\ |\ 0<t\leq 1\},\\ p_{2}&=&(1+|\cos{(\arcsin{(\frac{1}{2}\sin{(1)}-\frac{1}{2})})}|,\frac{1}{2}\sin{(1)}-\frac{1}{2}),\\ R(\theta)&=&\begin{pmatrix}\cos{(\theta)}&-\sin{(\theta)}\\ \sin{(\theta)}&\cos{(\theta)}\end{pmatrix},\\ pq&=&\{(1-\lambda)p+\lambda q\ |\ 0\leq\lambda\leq 1\}\ ({\rm for\ each}\ p,q\in\mathbb{R}^{2}),\\ S^{1}&=&\{(\cos{(t)},\sin{(t)})\in\mathbb{R}^{2}\ |\ 0\leq t\leq 2\pi\},\ {\rm and}\end{array}
B=(6,4)(R(π2)p2+(0,4))(R(π2)T2+(0,4))(6,4)(R(π2)p1+(0,4))(R(π2)T1+(0,4))(S1+(0,4))(R(π2)T1+(0,4))(R(π2)p1+(0,4))(6,4)(R(π2)T2+(0,4))(R(π2)p2+(0,4))(6,4)(6,4)(6,4)(6,4)(R(π2)p2+(0,4))(R(π2)T2+(0,4))(6,4)(R(π2)p1+(0,4))(R(π2)T1+(0,4))(S1+(0,4))(R(π2)T1+(0,4))(R(π2)p1+(0,4))(6,4)(R(π2)T2+(0,4))(R(π2)p2+(0,4))(6,4)(6,4)(6,4).\begin{array}[]{ccl}B&=&(6,4)(R(\frac{\pi}{2})p_{2}+(0,4))\cup(R(\frac{\pi}{2})T_{2}+(0,4))\\ &&\cup(6,4)(R(-\frac{\pi}{2})p_{1}+(0,4))\cup(R(-\frac{\pi}{2})T_{1}+(0,4))\\ &&\cup(S^{1}+(0,4))\\ &&\cup(R(\frac{\pi}{2})T_{1}+(0,4))\cup(R(\frac{\pi}{2})p_{1}+(0,4))(-6,4)\\ &&\cup(R(-\frac{\pi}{2})T_{2}+(0,4))\cup(R(-\frac{\pi}{2})p_{2}+(0,4))(-6,4)\\ &&\cup(-6,4)(-6,-4)\\ &&\cup(-6,-4)(R(-\frac{\pi}{2})p_{2}+(0,-4))\cup(R(-\frac{\pi}{2})T_{2}+(0,-4))\\ &&\cup(-6,-4)(R(\frac{\pi}{2})p_{1}+(0,-4))\cup(R(\frac{\pi}{2})T_{1}+(0,-4))\\ &&\cup(S^{1}+(0,-4))\\ &&\cup(R(-\frac{\pi}{2})T_{1}+(0,-4))\cup(R(-\frac{\pi}{2})p_{1}+(0,-4))(6,-4)\\ &&\cup(R(\frac{\pi}{2})T_{2}+(0,4))\cup(R(\frac{\pi}{2})p_{2}+(0,-4))(6,-4)\\ &&\cup(6,-4)(6,4).\end{array}

Then, using the same idea as the proof of Theorem 5.4, we can prove this theorem. ∎

Refer to caption
Figure 7. The continuum BB
Refer to caption
Figure 8. X0,X1andf01.X_{0},\ X_{1}\ {\rm and}\ f_{0}^{1}.

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