The cohomology of the classifying space of
Abstract.
Let be the classifying space of the projective unitary group . We determine the integral cohomology ring of , and the Steenrod algebra structure of its mod cohomology.
2020 Mathematics Subject Classification:
55R35, 55R40, 55S10, 55T101. Introduction
Let be a topological group. The classifying space of is characterized as the base space of a universal -bundle . The cohomology of is the main tool in the theory of classifying principal -bundles.
Let be the group of unitary matrices. The projective unitary group is the quotient group of by its center subgroup , where denotes the identity matrix. is homotopy equivalent to , the projective general linear group , which is the automorphism group of the algebra of complex matrices. Therefore, for a pointed space , the set of pointed homotopy classes of maps also classifies bundles of complex matrix algebras over , known as the topological Azumaya algebras of degree over . (See [9].)
The cohomology ring of also plays a significant role in the study of the topological period-index problem, which was introduced by Antieau and Williams [1, 2] as an analogue of period-index problems in algebraic geometry (cf. [3, 7, 19]). Gu [10, 11], Crowley and Grant [6] also investigated this problem for certain topological spaces.
Since can also be viewed as the quotient group of the special unitary group by its center subgroup generated by , there is an induced fibration of classifying spaces:
Hence, for a commutative ring , if , then
It follows that if is a torsion element, then there exists such that . (In the case of Chow rings, Vezzosi [23] proved the stronger result that all torsion classes in the Chow ring of are -torsion.)
However, if is not invertible in the coefficient ring , the ring structure of is very complicated for general . Here we list some of the known results on the cohomology of for special values of .
Since , the ring is well understood as a special case of the result of Brown [4].
The ring is computed in Kono-Mimura-Shimada [16]. The Steenrod algebra structure of and the Brown-Peterson cohomology of are determined in Kono-Yagita [17].
In [24], Vistoli provided a description of , as well as the Chow ring of , for any odd prime . In particular, the ring structure of is given in terms of generators and relations there. We will explicitly explain Vistoli’s result in the next Section.
More interesting results on the ordinary cohomology ring (resp. on the Brown-Peterson cohomology of ) for an arbitrary prime can be found in Vavpetič-Viruel [22] (resp. in Masaki-Yagita [20]).
For an arbitrary integer , the cohomology of is only known in certain finite range of dimensions. For instance, Gu [12] determined the ring structure of in dimensions less than or equal to . Other partial results on the -local cohomology groups of for an odd prime , , can be found in Gu-Zhang-Zhang-Zhong [14] and Zhang-Zhang-Zhong [25].
Summarizing these results, the only examples of , whose integral cohomology rings can be described via generators and relations, are the cases . Also, these are the only cases for which the Steenrod algebra structure of , a prime such that , are known. The main goal of this paper is to determine the integral cohomology ring of and the Steenrod algebra structure of its mod cohomology.
2. Main results
Notations.
For an integer , let be the ring of symmetric polynomials over in variables. It is known that , where is the th elementary symmetric polynomial in variables. Let be the -submodule of symmetric polynomials of degree .
Let be the linear differential operator acting on the polynomial algebra . It is easy to see that on preserves symmetric polynomials, so can be restricted to . Let be the kernel of on . Generally, for a commutative ring with unit, we use the notation to denote the map .
For the graded polynomial ring with , define a graded algebraic homomorphism , , by . In fact, this is the ring homomorphism induced by the embedding , , , . Let be the restriction of to , and let . The result of Vistoli [24] can be described as follows.
Theorem 2.1 (Vistoli [24, Theorem 3.4]).
For any prime , the integral cohomology ring of is given by
For the element , one easily checks that
It is shown in [24, Proposition 3.1] that the image of is generated by , so for , as -module,
where means the exterior algebra over with the generator . Since the rank of is the same as the rank of , the additive structure of are determined completely.
One reason for the difficulty of describing is that the ring is hard to compute for large . For small values of , here are some results. , , is obvious. Vezzosi [23, Lemma 3.2] (see also [24, Theorem 14.2]) proved that
Here we give the description of .
Theorem 2.2.
There is a ring isomorphism
For , the complexity of grows very quickly as grows. To the author’s knowledge, there is no one computed for by writing down the generators and relations explicitly so far.
As in the case of for a prime, can be viewed as the quotient ring of by torsion elements.
Theorem 2.3.
The cohomology ring is isomorphic to the graded ring
where is the ideal generated by
One of the results in Toda [21] gives , . In particular, this gives the mod cohomology of , since it is known that is homeomorphic to .
Theorem 2.4 (Toda [21, (4.10)]).
The mod cohomology of is given by
where is the ideal generated by
In the notation of Theorem 2.4, we determine the Steenrod algebra structure of as follows.
Theorem 2.5.
, , , , ; , , , , ; , , , ; , .
In the next two sections, we review Gu’s work in [12], where he constructs a fibration with as the total space, and provides an approach to calculate the Serre spectral sequence associated to this fibration.
3. Serre spectral sequences in the computation of
3.1. The spectral sequence
The short exact sequence of Lie groups
induces a fibration of their classifying spaces
(3.1) |
Since is of the homotopy type of the Eilenberg-Mac Lane space , we obtain another induced fibration:
(3.2) |
(Cf. [8].) Let be the cohomological Serre spectral sequence associated to this fibration. The page of this spectral sequence has the form
Notice that is concentrated in even rows, so all differentials are trivial, and we have .
3.2. The spectral sequences and
Let and be the maximal tori of and respectively, and let and be the inclusions. Then there is an exact sequence of Lie groups
which as above induces a fibration
We also consider the path fibration
where denotes a contractible space. Let and denote the cohomological Serre spectral sequences associated to and respectively.
Let be the diagonal map. Then there is the following homotopy commutative diagram of fibrations
(3.10) |
We write , , for the differentials of , , and , respectively. We also use the simplified notation if there is no ambiguity.
3.3. Spectral sequence maps on pages
Recall that the cohomology rings of the fibers , and in (3.10) are
Here is the th universal Chern class of the classifying space for -dimensional complex bundles. The induced homomorphisms between these cohomology rings are given by
where is the th elementary symmetric polynomial in the variables . Hence, from (3.10) we obtain the maps and of spectral sequences on pages.
The strategy in [12] for computing is to compare its differentials with the differentials in and , which we will explain in the next section.
4. The cohomology of and differentials of and
Throughout this section, we write , for the polynomial algebra and exterior algebra respectively, with coefficients in a commutative ring , and with one generator of degree . We also use the simplified notation for .
Let be the (differential graded) -algebra
For notational convenience, we set and for . The differential of is given by
Gu [12] showed that the integral cohomology ring of is isomorphic to the cohomology of , which is dual to the DGA construction of Cartan in [5].
Let denote the -primary component of a commutative ring , a prime. For a graded commutative ring without unit, let be the (graded commutative) unital ring, where the degree zero summand has a generator acting as the unit of the ring.
Theorem 4.1 ([12, Proposition 2.14]).
The cohomology ring of is given by
where ranges over all prime numbers, and is the -subalgebra (without unit) of generated by the elements of the form
for any ordered sequence of nonnegative integers . For , we simply write for .
Remark 4.2.
For a prime, the mod cohomology ring of is also given by the cohomology of the differential graded -algebra , which has an easier description (see [12, (2.13)]). Furthermore, the Steenrod algebra structure of can be determined from the fact that (resp. ) is the the transgression image of (resp. ) in the mod Serre spectral sequence , using Kudo’s transgression theorem [18]. In particular, for , we have the following analogue of [13, Proposition 2.4].
Proposition 4.3.
. Moreover, , , , .
The differentials of the integral spectral sequence are described in [12] as follows. Here we only list a part of the results in [12, Corollary 2.16], which will be sufficient for our purposes.
Proposition 4.4 ([12, Corollary 2.16]).
The higher differentials of satisfy
and the Leibniz rule. Here is generated by .
To describe the differential of , we first rewrite as . Then is generated by elements of the form , where and is a polynomial in with coefficients . Let for , and write , .
Proposition 4.5 ([12, Propositions 3.2-3.6]).
In the above notation, the differential is given by
where is simply with replaced by . In particular, the differential is given by the “formal devergence”
in such a way that . Moreover, the spectral sequence degenerates at , i.e.,
Since the operator preserves symmetric polynomials, for and , we have the following corollary of Proposition 4.5 by the Leibniz rule.
Corollary 4.6 ([12, Corollary 3.10]).
.
In particular, the fact that shows that for , , we have ([12, Corollary 3.4])
(4.1) |
Corollary 4.7.
.
Proof.
This comes from the fact that , , where by Corollary 4.6. ∎
5. Proof of Theorem 2.2
The proof of Theorem 2.2 is essentially a analogue of the proof of Lemma 3.2 for in [23] (also Theorem 14.2 in [24]).
Firstly, we give the explicit expression of in . Let
(5.1) |
A direct calculation shows that for all above, and
Consider the ring homomorphism
It is easy to see that this map is injective. After tensoring with , this map becomes an isomorphism, and the inverse is obtained by sending to . The commutative diagram below shows that .
On the other hand, the inclusion is an isomorphism, so in fact we have
Hence if then for sufficient large , and the following lemma shows that , , , generate by descending induction on .
Lemma 5.1.
For , if , then too.
Proof.
The images of , , , in is , , , respectively. The ideal of relations between these four polynomials is generated by , which is the image of . Hence if we write for some integral polynomial , then there are two integral polynomials and such that
Dividing by we get . ∎
Consider the surjective ring homomorphism that sends to . Let be its kernel. Then the following lemma is an equivalent statement of Theorem 2.2.
Lemma 5.2.
In the above notation, .
Proof.
Let . We know that . Note that
which is isomorphic to as we saw above. This implies that if , then some multiple is in . However, since dose not divide in the UFD , is actually in , and we get the desired equality in the lemma. ∎
We end this section with an algebraic result, which will be used in Section 7.
Proposition 5.3.
is a subring of , where acts on .
Proof.
Since , and , for any . So the order of in divides . If its order is not , there would exist such that , and then . Let be the mod map, and write for an element . Then , where , , , . This means that there is a polynomial over such that in . We may assume that and are homogeneous polynomials in , so that , an odd number, which implies that divides . However, since is a UFD and dose not divide and , can not divide . This gives a contradiciton. So the order of must be , and the proposition follows immediately. ∎
6. On the homomorphism from to
In this section, we study the homomorphism induced by the fibration map defined in (3.2). Throughout this section, let denote the mod reduction map on cohomology.
Since , the following result is a special case of [4].
Theorem 6.1.
Let be the th universal Stiefel-Whitney class of , and the first Pontryagin class. Then
Here is the degree- integral Stiefel-Whitney class.
Theorem 6.2.
In the notation of Proposition 4.3, the mod cohomology homomorphism satisfies
Proof.
First we show that . This follows from the computation in [12] that is generated by . Here we give a short explanation to this. Since and is , it follows that . Therefore, for degree reasons
Now we give the formula for by induction on , starting with . Since by Proposition 4.3, we have . Hence , the only nonzero element of degree . Inductively, suppose that is congruent to modulo the ideal generated by . Then since by Proposition 4.3, we have
Since preserves and in , is the only degree- element mapped by to , it follows that mod , and the induction step is finished. ∎
Corollary 6.3.
Proof.
Proposition 6.4.
Let be an interger such that . Then for any ,
(a) in .
(b) in .
Here we abuse the notations , , , to denote their images under the cohomology ring homomorphism induced by the fibration map .
7. On the spectral sequence
Proposition 7.1.
In the integral spectral sequence associated to , we have . Moreover, is a submodule of .
Proof.
By Corollary 4.7, . Since the differentials in the spectral sequence satisfy the Leibniz rule and is generated by , , , , it suffices to show that these generators survive to . For , , , this was proved in [12], so we only consider .
The differentials in have the form . Hence from Theorem 4.1 we see that the only possible nontrivial differentials , , originating at , are , and . Note that , and by Theorem 4.1.
From Proposition 6.4 we know that is a permanent cycle, so it can not be hitten by any differential in . Furthermore, from (4.1) we see that mod , so . Hence the proposition will follow once we prove that . This is an easy calculation using the following commutative diagram
The right vertival map is only an injection since besides , also contributes to , but this does not effect our computation. It can be shown that and . Then we have .
Using Proposition 5.3, we see that in has order for any . Since , and are all permanent cycles, so is , and the second statement follows. ∎
Proposition 7.1 says that there exist elements , , such that . Let , be the maps defined in the proof of Proposition 6.4. We consider the images of and under the maps and respectively.
Let and be the th universal Chern classes of and respectively. Since the map factors through the diagonal map , using the Whitney sum formula and the functorial property of total Chern classes we immediately get
In other words,
(7.1) |
Proposition 7.2.
The elements , , can be chosen such that , and for .
Proof.
It follows from (5.1) and (7.1) that mod for , and . On the other hand, for the spectral sequence associated to , an easy calculation shows that . This means that for , .
Recall from Theorem 6.1 that
Since , combining the above computations, we obtain and mod . We have seen that , hence by adding to or to if necessary, we can also obtain mod . ∎
8. On
In this section we prove some facts about the generators of in Theorem 2.4.
Proposition 8.1.
In the notation of Proposition 4.3, , , or .
Proof.
From Proposition 6.4 we know that , , . Since and is the only nonzero element in , . Similarly, .
Recall from Proposition 4.3 that , , , , and . Then we have the following corollary of Proposition 8.1.
Corollary 8.2.
In , , , , , or .
Before proceeding further, let us review a result in [21]. Let be the quotient group of by the center , and let be the induced map of classifying spaces. It is known that is homeomorphic to , so there is an induced homomorphism
where is the th universal Stiefel-Whitney class of .
Proposition 8.3 ([21, Proposition 3.7 and 4.5]).
, , , , , where , , , and .
(See [21, p. 91] for the formulas of , .)
Proof.
Let be the map in (3.1). The following result in [21] gives the induced mod cohomology ring homomorphism .
Proposition 8.5 ([21, (4.11)]).
In , , , .
Let and be the maps defined in the proof of Proposition 6.4, and to avoid ambiguity of notations, let denote the th universal Stiefel-Whitney class of .
Proposition 8.6.
, , , and , , , , , .
Proof.
Since , the equation follows from the fact that . Let also denote the map . Then by Proposition 8.5 and (7.1). This gives since and .
We see from Proposition 8.3 that . Hence since and . Recall from Theorem 6.1 that . Hence , , since . Furthermore, by Proposition 8.5, , and then by (7.1), which implies that the coefficient is since .
Similarly, we have in . Since and , it follows that . The relation in shows that
Solving this equation we obtain . ∎
Let and , , be as in Section 7, and let denote the mod reduction map.
Proposition 8.7.
, , , .
9. Proof of Theorem 2.5
The strategy of the proof is to compute the action of steenrod squares on the images of the generators under the map
As in Section 8, we use and to denote the th universal Stiefel-Whitney class of and respectively.
First we consider on .
Proposition 9.1.
, , , , .
Proof.
Recall that , and . Then the calculation can be carried out by using the Cartan formula for Steenrod squares and the Wu formula for the mod Chern classes:
For , we have , , , , , , , . Thus,
In the last equation, we use
∎
Next we consider on . The following proposition contains all we need.
Proposition 9.2.
, , , , ,
Proof.
By Proposition 8.6, , and . Using the Wu formula and the Cartan formula, it is straightforward to verify the formulas in the proposition. is obvious.
∎
For on , we only need a partial result.
Proposition 9.3.
, and
Proof.
Recall from Proposition 8.3 that . One easily computes that , , , , hence the formula for holds.
Now we compute the action of on each terms in the expression of , modulo the ideal . mod is obvious.
since , and .
Then the formula for follows. ∎
Now we are ready to prove Theorem 2.5. The action of on all generators , and , were given in Section 8. since .
Since and , by Proposition 8.6, it follows from Proposition 9.2 that . Similarly, the formula follows from Proposition 9.2, and the fact that , using and .
Since , we may assume that . Then
Hence, the relation gives and . On the other hand, if , then would not appear in the expression of , but this is not true by an easy computation, so .
Notice that is spanned by , , , , , . Then in the expression , , by Proposition 9.1, and , by Proposition 9.3 and the fact that , , mod from Proposition 8.3, which proves .
An easy calculation shows that is spanned by , , , , , and monomials in , , of degree . Proposition 9.1 says that among monomials in , , of degree , only appears in the expression of . Furthermore, since , , , , , mod by Proposition 8.3, we obtain from Proposition 9.3 that .
The proof of Theorem 2.5 is completed.
10. Proof of Theorem 2.3
Let , , be the elements constructed in Section 7, and for simplicity let , denote , for .
Proposition 10.1.
The cohomology ring is generated by , , and , , .
Before proving Proposition 10.1, we need a result on the image of under the mod reduction.
Lemma 10.2.
The image of is the subalgebra generated by , , , , , , .
Proof.
Let be the subring generated by the elements in the Lemma. First we prove that . By Proposition 8.7, , , , . Recall from Section 4 that in we have , and . Hence from Proposition 8.1 and the second part of Proposition 8.4 we have , , . It follows immediately that .
For the reverse inclusion , we use the fact that , where is the Bockstein homomorphism in the long exact sequence
induce by the sequence , noting that . We claim that the kernel of on is the subalgebra generated by , , , , , , whose proof is defered to the last Section for reader’s convenience. Then from the ring structure of it is easy to see that there is a -module isomorphism
Furthermore, we know that and for any . Hence the universal coefficient theorem shows that . The sequence also induces a long exact sequence of cohomology, and there is a commutative diagram
Suppose that generates . Then , and . Hence, the above diagram shows that , and then
This implies that for any , by the second part of Proposition 7.1. Since , it follows that , and then . ∎
Proof of Proposition 10.1.
Let be the subring generated by the elements in the proposition, and let be the quotient -module. Then lemma 10.2 and the first paragraph of its proof show that , i.e. . We need to show that itself is zero.
Let be the ideal consisting of torsion elements of , and let . Since , using Proposition 7.1 and the fact that torsion free elements in concentrated in , we see that
Hence we get a commutative diagram of short exact sequences
This implies that as -modules. Recall that the torsion elements of are all -primary. So if , then . However, since , we must have . Hence . ∎
Let be the ring defined in Theorem 2.3.
Proposition 10.3.
There is a surjective homomorphism of graded rings:
Proof.
By Proposition 10.1, we only need to show that this map is well-defiend, in other words, the element and all generators of the ideal map to zero.
We already know that in , has order by [12, Theorem 1.1], and , , are all of order by Theorem 4.1 and the fact that , , in . From this one can see that the order of a torsion element of even degree in is at most .
Let . Then for , since by Proposition 7.1. Hence is a torsion element. From Proposition 8.7 we know that , and so . Then we get since is of even degree.
Since and , we have . Hence , , and then , since , are of even degree.
It is easy to see that since , so . Since , . Then the fact that gives .
Since , we have , then . Checking each element of degree , one can show that or . But the later is impossible, since if this is the case, it would imply that in has order because of the Serre filtration construction, which contradicts the second part of Proposition 7.1. Hence we get the relation . The proof of is easier, using the fact that all elements of degree have order .
Let . Then using the computations in the first paragraph of the proof Lemma 10.2 and the relation in , one readily checks that . Since has even degree, by the same reasoning.
The above calculations verify that and all generators of map to zero, finishing the proof. ∎
The following Proposition completes the proof of Theorem 2.3.
Proposition 10.4.
The homomorphism in Proposition 10.3 is injective.
Proof.
The proposition is equivalent to saying that if a polynomial in the variables , , , , , maps to zero in , then , where .
Write . Since is zero in , , and then can be written as , where belongs to the ideal of generated by , and . Hence it suffices to show that . Here we identify with the corresponding ideal of .
Let be the map in Section 8, and let
Then belongs to the ideal of relations between the elements in .
Let us compute the ideal . By Proposition 8.3, modulo ,
It is easy to see that the four elements are algebraically independent. Hence the Krull dimension of the subalgbra of generated by , , is at least , which means that is a principal ideal of . To see this, note that is the kernel of the map with target a UFD, so is a prime ideal of . Since the Krull dimension of is at least , the height of is at most , and then is principal since is a UFD.
Suppose that generates . Since the powers only appear in the expressions of and , it follows that if , then the degrees of and in are both nonzero. Furthermore, since the degree of in (resp. in ) is (resp. ), the degree of in is at least when . We have seen in the proof of Proposition 10.3 that in , where , hence we must have .
Since and , the above analysis implies that
We know that and are zero in , so in . Since , , and are all zero in and the order of is for any by the second part of Proposition 7.1, it follows that is actually in the ideal
which is contained in . The proof is completed. ∎
11. Kernel of on
In this section we prove the claim in the proof of Lemma 10.2 that the kernel of the action on is the subalgebra generated by , , , , , . To make the computation easier, we shall establish a -algebra isomorphic to , and define a operation on it corresponding to .
Let be the quotient of the polynomial algebra by the ideal generated by , , and . Then it is easy to see that there is an algebra isomporphism given by for , , . Define an operation on by for , , , and the Leibniz rule . Then using Theorem 2.5, one easily verifies that there is a commutative diagram
Thus, can be viewed as a DGA with differential . We compute its cohomology as follows
Proposition 11.1.
.
Our desired result on is a direct consequence of the following corollary of Proposition 11.1.
Corollary 11.2.
is the subalgebra of generated by , , , , , .
Proof.
Since , it follows from Proposition 11.1 that as -modules
Now we compute . For a monomial , , by the rule of we have
Here means the mod number. Hence is a -vector space spanned by elements of the forms:
where , , . Note that by definition. Then an easy calculation gives the result. ∎
Proof of Proposition 11.1.
Define a -linear map by if or , , and for all other monomials. It is easy to show that is a chain map associated to the differential . We claim that is chain homotopic to the identity map. Since restricted to is zero and any element in is clearly not in , the proposition follows immediately from this claim.
Now we construct the chain homotopy as follows. For a monomial , , let
It is straightforward to show that on all monomials in case by case. ∎
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