The -Gaussian Minkowski problem
Abstract.
In this paper, we extend the article that Minkowski problem in Gaussian probability space of Huang et al. to -Gaussian Minkowski problem, and obtain the existence and uniqueness of -symmetry weak solution in case of .
Key words and phrases:
Minkowski problem, -Gaussian Minkowski problem, Monge-Ampère equation, degree theory2010 Mathematics Subject Classification:
52A40, 52A38, 35J96.1. Introduction
The Brunn-Minkowski theory mainly studies the geometric functional of convex bodies and their differential. The differentiable functional will generate some intrinsic geometric measures. In Euclidean space , the most significant functional of convex body is volume denoted by , and Aleksandrov [1] gave the variational formula
(1.1) |
where , is the support function of convex body . It naturally generates the surface area measure of convex body . The classical Minkowski problem characterizes the surface area measure, it reads : given a finite Borel measure on , what are the necessary and sufficient conditions on does there exist a convex body in such that surface area measure ? If exists, is it unique? In the smooth case, it is equivalent to solve a certain fully nonlinear elliptic equation. The classical Minkowski problem was solved by Minkowski in [26] for polytope, and later solved by Aleksandrov [1], Fenchel and Jessen [16] in general.
In 1993, Lutwak developed the Brunn-Minkowski theory to -Brunn-Minkowski theory. The -Minkowski problem, characterizing -surface area measure . Clearly, when , the -surface area measure is just the classical surface measure. Lutwak [39] testified that there exists a unique -symmetry convex body such that for . The -Minkowski problem has been studied extensively in [3, 4, 11, 27, 24, 33, 43, 48, 47, 49] and so on. The uniqueness of the Minkowski problem is related to Brunn-Minkowski inequality. For , the -Brunn-Minkowski inequality can be obtained easily. In case of , -Brunn-Minkowski inequality and its condition of the equality holds have not been improved much until [8]. While the logarithmic Minkowski problem and the centro-affine Minkowski problem are two special cases; see, e.g., [5], and [12]. The regularity of the -Minkowski problem, for example [12, 28, 40].
In [38], the dual Brunn-Minkowski theory was developed in the 1970s. The most significant dual curvature measure and its associated Minkowski problem in the dual Brunn-Minkowski theory were studied in [29]. The work of [29] play a key role in promoting the development of partial differential equation and dual Brunn-Minkowski theory as [9, 31, 6, 41, 10, 45]. Recently, a number of meaningful and interesting work emerged on the Orlicz-Minkowski problem, such as [19, 20, 25, 34, 35, 46, 52].
In [30], the authors posed the Minkowski problem in Gaussian probability space. Gaussian volume functional denoted by plays a central role, which is given by
Using the variational formula from Huang et al. [29], the variational formula of is obtained as follows:
(1.2) |
where Gaussian surface area measure is given by
About the mainly result of Gaussian Minkowski problem showed in [30] Theorem 1.4, stated as: Let be a finite even Borel measure on that is not concentrated on any closed hemisphere and . Then there exists a unique -symmetry convex body with such that
As remarked in [30], Gaussian Minkowski problem is different from the Minkowski problem in Lebesgue measure space in these aspects. At first, the Gaussian surface area of all convex set in is not more than which is shown detailed in Ball [2] and [18]. That is to say, the allowable in Gaussian Minkowski problem can not have an arbitrarily big total mass. Secondly, Gaussian probability measure has neither translation invariance nor homogeneity, which makes our research more difficult. As a final remark, by the definition of Gaussian surface area, we can know that not only small convex bodies can have smaller Gaussian surface areas, but also large convex bodies. For instance, let be a centered ball with radius the Gaussian surface area’s density of is . One can observe that as or
Naturally, we develop the -Brunn-Minkowski theory in Gaussian probability space. The purpose of this paper is to continue the study in [30] and to construct -Gaussian surface area measures. A -variational formula similar to Lemma 3.2 in Lutwak [39] is gained as below:
where is -combination for , and it leads to define the -Gaussian surface area measures as follows
The -Gaussian Minkowski problem reads : given a finite Borel measure on , what are the necessary and sufficient conditions on does there exist a convex body in such that -Gaussian surface area measure ? If exist, is it unique?
The first assertion involves the uniqueness result, it is known to us that the Gaussian surface area’s density of tends to as or this means that Gaussian surface area is may not unique. Our study in the restricted context that the Gaussian volume grater than or equal to , then obtain the following uniqueness result. The same fact was firstly found in [30] in the situation of .
Theorem 1.1 (Uniqueness).
For , let with the same -Gaussian surface area, i.e.,
If then
Aleksandrov’s variational method implies the existence of solution with lagrange multipliers.
Theorem 1.2.
For let be a nonzero finite Borel measure on and be not concentrated in any closed hemisphere. Then there exist a and a positive constant such that
Due to the lack of homogeneity of measure, just like all previous Orlicz-Minkowski problems, in the solving process, the lagrange multipliers produced by Aleksandrov’s variational method can not eliminated. Recently, the work of Huang et al. in [30], the first one overcame this obstruct. Inspired their work, we obtain the existence of smooth solution.
Theorem 1.3 (Existence of smooth solution).
For let even function is positive and , the and are chosen such that , symmetry strip . Then there exists a unique convex body with , the support function solves the equation
(1.3) |
Finally, the existence of weak solution of the -Gaussian Minkowski problem follows by an approximation method with the help of a uniform estimate.
Theorem 1.4 (Existence of weak solution ).
For let be a nonzero finite even Borel measure on and be not concentrated in any closed hemisphere with the and are chosen such that , symmetry strip . Then there exists a unique with such that
We overcome the most important obstacle of the Gaussian Minkowski problem about whether the solution degenerates or not, and obtain that it holds for asymmetric convex bodies see Theorem 3.3. But the limitation of this item is the lack of Gaussian isoperimetric type inequality for general convex body such that it can only achieve the -symmetry convex body, see Theorem 4.7 and Theorem 5.5.
The paper is organized into five sections: we list some conceptual knowledge of convex bodies in Preliminaries part, and gain the key -variational formula in Section 2. In Section 3, Aleksandrov’s variational method is applied to obtain the non-symmetry solution with lagrange multipliers for . The uniqueness of solution is proved in Section 4. Section 5 provides the existence result of -symmetry smooth solution for by means of the degree theory of partial differential equation, then the -symmetry weak solution is obtained with the help of approximation argument.
2. -Gaussian surface area and the -Gaussian Minkowski problem
In this section, we make a brief review of some relevant notions about convex bodies. More detailed information of convex body theory can be found in the Schneider [44].
Let represent the -dimensional Euclidean space, be the unit sphere in be positive functions defined on and denote total measure of the Borel measure on
Convex body in is compact convex set with nonempty interior denoted by . Let denote the boundary of , be convex bodies that contain the origin in interior, and denote the -symmetry convex bodies.
The support function of a compact convex subset in is defined as
for , where represents the inner product.
For , the radial function is defined by
for . A simple observation allows us to obtain
In fact, is the space of compact convex set in and it can be equipped with Hausdorff metric which associated norm is
We can easily show that is the distance between . Therefore, the convergence of compact convex set sequence can be characterized by the convergence of support function. That is to say, if
as Or if ,
as then .
Let , the Wulff shape generated by is a convex body defined by
Obviously, if ,
Let , the convex hull generated by is a convex body defined by
Clearly, if ,
For and real , the Minkowski combination, defined as follow
and support function is
Firey was the first to define the -combination of , for
and
Here .
In case of is just the support function, but for is not necessarily.
For , its polar body in is defined by
It is easy to show that, if ,
(2.1) |
for . In addition, we can get if .
For , by (2.1) and the previous characterization of convex body convergence, then if and only if
For convex body , then its supporting hyperplane with outward unit normal vector represented by
The boundary point of only has one supporting hyperplane called regularity point, otherwise, it is a singular point. The set of singular points denoted as , it is well known that has spherical Lebesgue measure (see Schneider [44], p.84).
For , its Gauss map is represented by
Correspondingly, for Borel set , its reverse Gauss map denoted by ,
For Borel set , its surface area measure is defined as
where is -dimensional Hausdorff measure.
Then
(2.2) |
For Borel set , denotes its radial Gauss image and is defined as
for . When Borel set have only one element , we will abbreviate as . The subset of which make contain more than one element denoted by for each . The set has spherical Lebesgue measure (see Schneider [44], Theorem 2.2.5).
The radial Guass map of is a map denoted by , the only difference between and is that the former is defined on not on which lead to may have many elements but has only one. In other words, if , then .
For -integrable function ,
(2.3) |
where is defined -a.e. on by
For Borel set , its reverse radial Gauss image is shown as
for .
When Borel set have only one element , we will abbreviate as . The subset of which make contain more than one element denoted by for each . The spherical Lebesgue measure of set is (see Schneider [44], Theorem 2.2.11).
The reverse radial Gauss map of is a map denoted by , if , then .
For this part, we give the definition of the -Gaussian surface area measure as follows.
Definition 2.1.
Let , for Borel set , , define -Gaussian surface area as below
which is a Borel measure on .
The above definition is deduced from the -variational formula, and the proof of variational formula requires the following lemma. Our proof mainly relies on ideas developed in [29].
Lemma 2.2.
For let , be a continuous function. For enough small , and each , define the continuous function as
Then,
holds for almost all . In addition, there exists such that
for all and .
Proof.
The following -variational formula, as we shall see in the next section, is the key to solve the -Gaussian Minkowski problem.
Theorem 2.3 (-variational formula in Gaussian space ).
For let , be continuous function. For sufficiently small , and each , define the continuous function by
Then,
(2.4) |
Proof.
Applying polar coordinates, shows that
Since and uniformly as , by Aleksandrov’s Convergence Lemma, we can get , then radial function of converges to the radial function of , i.e., , and there exist such that .
For simplify, denote . By mean value theorem, there exists such that
the is arisen as in Lemma 2.2. With the simple calculation,
for some constant as .
By the definition of , together with the conclusions that the Gauss surface area measure is weakly convergent and is absolutely continuous which were got in [30], it sufficient to reveal that is weakly convergent with respect Hausdorff metric, and is absolutely continuous with respect to surface area measure.
3. The variational method to generate solution
This section aims to transform the -Gaussian Minkowski problem into an optimization problem by employing variational method, and prove the optimizer is just the solution to the Minkowski problem of .
3.1. An associated optimization problem
For any nonzero finite Borel measure on , define by
for each . We take into account the following minimum problem
(3.1) |
Lemma 3.1.
If and satisfies
equivalent to
where is defined by
Proof.
For the Wulff shape
it is easy to get and , thus we have
Clearly, and satisfies
if and only if
∎
Lemma 3.2.
For let be a nonzero finite Borel measure on . If and satisfies
(3.2) |
then there exists a constant such that .
3.2. Existence of an optimizer
Theorem 3.3.
For let be a nonzero finite Borel measure on and be not concentrated on any closed hemisphere. Then there exists a such that
Proof.
Suppose is a minimal sequence, i.e.,
(3.4) |
We now claim that is uniformly bounded. If not, then there exists such that as . By the definition of support function, , then
where } for any . Since is not concentrated on any closed hemisphere, there exists a positive constant such that
Therefore,
as But this is contradicted to (3.4). Then we conclude is uniformly bounded. By Blaschke selection theorem, has convergent subsequence, still denoted by , converges to a compact convex set of . By the continuity of Gaussian volume, we get
Now we prove the uniform lower bound of support function by contradiction. For with . Suppose that there exists such that . Then for any , . Combining the fact that has upper bound, then . Let be halfspace, as computed in [2],
Then
which shows that for some , , and naturally for small enough, there is , this contradicts to the condition . Therefore, we conclude that is non-degenerate. Namely, is the desired convex body. ∎
Now we return to deal with the origin problem.
3.3. Existence of solution to the -Gaussian Minkowski problem
Combining with Lemma 3.1, Lemma 3.2 and Theorem 3.3, we prove sufficiently the main existence theorem for the -Gaussian Minkowski problem stated in the introduction.
Theorem 3.4.
For let be a nonzero finite Borel measure on and be not concentrated in any closed hemisphere. There exist and constant such that
The existence of a solution has been done as above, now we are devoted to solving the uniqueness.
4. Uniqueness of solution
In general, Brunn-Minkowski inequality implies the uniqueness of solution of Minkowski problem. There are many fruitful results on the inequality of Gaussian volume , such as [7, 15, 23]. In particular, Ehrhard inequality in [14] is one of the most significant Brunn-Minkowski type inequalities for Gaussian measure , stated as follows. But in Gaussian Minkowski problem, because there is no homogeneity, the uniqueness can not obtained from the Brunn-Minkowski inequality. Fortunately, by using Ehrhard inequality, we can get the uniqueness result when the Gaussian volume is more than or equal to half.
Theorem 4.1 (Ehrhard inequality).
Let be convex bodies in , , then
with equality holds if and only if Where .
In view of Ehrhard inequality, we obtain the log-concave property of as below.
Lemma 4.2.
Let be convex bodies in , , then
(4.1) |
with equality holds if and only if
Indeed, this follows directly from the above Lemma and the fact that for .
Lemma 4.3.
Let be convex bodies in , for and , then
(4.2) |
with equality holds if and only if And its differential equivalent form is
(4.3) |
Naturally, it tells that
Lemma 4.4.
Let be convex bodies in . For , if then
with equality holds if and only if
Finally, we attempt to deal with the uniqueness. The main idea of proof is inspired by Lemma 5.1 in [30].
Lemma 4.5.
For , if with the same -Gaussian surface area, i.e.,
If then
Proof.
By the Ehrhard inequality,
with equality holds if and only if Where
For convenience, we write , then
For , together with the fact that is and strictly monotonically increasing, it follows that
Then by applying the Theorem 2.3 we have,
(4.4) |
Interchanging the position of and , we have
or equivalently,
(4.5) |
Theorem 4.6.
For , if with the same -Gaussian surface area, i.e.,
If then
Proof.
The following isoperimetric type inequality can be derived from Ehrhard inequality, and will be used in the Section 5.
Theorem 4.7.
For let be an -symmetry convex body in and symmetric strip with . Then,
where is chosen such that .
5. Existence of weak solution
In this section, we do some prior estimates and apply degree theory to obtain the existence of -symmetry smooth solution, then with the help of approximation argument to get the existence of weak solution of -Gaussian Minkowski problem for .
5.1. prior estimates
Lemma 5.1 ( estimate).
For , and , assume is the solution of the following equation
If for some positive constant , then there exists a constant such that .
Proof.
Now we prove the upper bounded. There exists such that , and , then
which implies
The bound from blew of support function is guaranteed by the condition that . The proof is same as established as in Theorem 3.3. ∎
Lemma 5.2.
For , assume function and there exists constant such that and . For with , if and satisfies
(5.1) |
then there exists a positive constant which only depends on such that the following priori estimates hold:
(1) estimate:
(2) estimate: and higher estimate .
Proof.
Assume . It admits
at , i.e.,
In view of (5.1), it tells that the element of the matrix we have , and , the second inequality is immediately from Lemma 5.1 and is only depends on .
To get estimate, the key is to show that the eigenvalues of matrix are bounded from above and below. In other words, the Monge-Ampere equation (5.1) is uniformly elliptic. Thus, an immediate consequence of the standard Evans-Krylov-Safonov theory [21] is .
On the one hand, in light of the fact that have positive upper and lower bounds, then combined with , we conclude
also has positive upper and lower bounds.
On the other hand, we end the proof by claiming that the trace of has an upper bound.
For convenience, denote
Assume , then and . We can make the Hessian of , , is diagonal by choosing the suitable local orthogonal frame . Denote , setting , the inverse matrix of .
Then, based on the above conclusions, at we have
(5.2) |
the second equality of (5.2) is from the commutator identity [22]:
Next we are going to estimate
From the equation
i.e.,
Carry out differential operation twice on the above formula, we obtain
and
Since
i.e.,
then we have
and
From the equation (4.11) in Cheng-Yau[13], we have
Due to , , , thus, at ,
(5.4) |
Put this in (5.2), then
(5.5) |
Since , , , are bounded, which implies
Next we focus on obtaining the existence of smooth solution by the degree theory for second-order nonlinear elliptic operators, the reader can conference to the Li [37] for some details. ∎
Theorem 5.3 (Existence and uniqueness of smooth solution).
Let , for , which is positive even function and satisfies , the and are chosen such that , symmetry trip , then there exists a unique convex body with , its support function satisfies
(5.6) |
Proof.
On the one hand, the uniqueness result is guaranteed by Theorem 4.6 .
On the other hand, define as follows:
where .
Define by
For , the eigenvalues of its hessian are bounded from above and below, the operator is uniformly elliptic on for any
When is small enough, applying mean value theorem, it reveals that there exists a unique constant solution such that . Since spherical Laplacian has a discrete spectrum, then we can select suitably such that , and the operator is invertible.
Now we claim that is an open bounded set under the norm , that is, we need to prove that if , then .
If , in other words, is the solution of
Since then , from Theorem 4.7, we have , which is contracted to the condition .
By means of the Proposition 2.2 of Li[37], we conclude that
It is clear that if then there exists such that . Subsequently, we need to claim The Proposition 2.3 and Proposition 2.4 of Li [37] told that if the linearized operator of at is invertible, then we have
Our final goal is to verify :,
is invertible.
The choice of ensures the reversibility of , then we completed the claim. ∎
We via approximation argument to obtain the existence of weak solution of -Gaussian Minkowski problem as follows.
Lemma 5.4.
If is not concentrated on any closed hemisphere, let be a sequence of measure which converges to weakly as Then there exist and such that for any ,
Proof.
Argue via contradiction. Take , , a subsequence which converges to we conclude that
Since weakly, fix any for large enough,
Let we have , which is contradicted to the condition that is not concentrated on any closed hemisphere. ∎
At the end, we are ready to state the Theorem for the existence of unique symmetry weak solution as exhibited in the following.
Theorem 5.5.
For , let be a finite even Borel measure on and be not concentrated in any closed hemisphere with , the and are chosen such that , symmetry trip . Then there exists a unique with such that
Proof.
Let be a sequence of even measure which converges to weakly as with . Then combine Theorem 5.3, there are convex bodies with , its support function satisfies
i.e.,
We will set about claiming that is uniformly bounded. Suppose that is attained at , and the corresponding point on is In fact, . Then by Lemma 5.4, there exist and such that for any
(5.7) |
Denote , the points on corresponding to the vector on satisfy . Hence,
as Which contradicts to (5.7).
In view of the fact that is uniformly bounded, , it follows that . In summary, we have as is the desired convex body. ∎
Acknowledgement
I would like to thank my supervisor, professor Yong Huang, for his patient guidance and encouragement. I am also deeply indebted to professor Shibing Chen for providing the valuable advice of Lemma 5.1.
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