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The skew-symmetric-Laplace-uniform distribution

\nameRaju. K. Lohota [Uncaptioned image] and V. U. Dixitb [Uncaptioned image] CONTACT Raju. K. Lohot. Email: rajulohot.92@gmail.com aDepartment of Statistics, SVKM’s Mithibai College of Arts, Chauhan Institute of Science & Amrutben Jivanlal College of Commerce and Economics, Vile Parle (W), Mumbai, Maharashtra, India; bDepartment of Statistics, University of Mumbai, Vidyanagari, Santacruz (E), Mumbai, Maharashtra, India
Abstract

Laplace distribution is popular in the field of economics and finance. Still, data sets often show a lack of symmetry and a tendency of being bounded from either side of their support. In view of this, we introduce a new family of skew distribution using the skewing mechanism of Azzalini, (1985), namely, skew-symmetric-Laplace-uniform distribution (SSLUD). Here uniform distribution is used not only to introduce skewness in Laplace distribution but also to restrict distribution support on one side of the real line. This paper provides a comprehensive description of the essential distributional properties of SSLUD. Estimators of the parameter are obtained using the method of moments and the method of maximum likelihood. The finite sample and asymptotic properties of these estimators are studied using simulation. It is observed that the maximum likelihood estimator is better than the moment estimator through a simulation study. Finally, an application of SSLUD to real-life data on the daily percentage change in the price of NIFTY 50, an Indian stock market index, is presented.

keywords:
Estimation; Indian stock market index; one side bounded support distribution; simulation; skew-symmetric-Laplace-uniform distribution
{jelcode}

C10, C13

{amscode}

62E10, 62F10

1 Introduction

Symmetry is something which we try to seek naturally in everything, but not everything in the world is symmetric. So expecting symmetry in everything is unrealistic. In statistics, most classical procedures assume some kind of symmetry. However, the absence of symmetry is much more common in many data sets. In particular, much interest has been shown recently in a family of distributions called “Skew-symmetric distributions”. Let ff be a density function symmetric about zero, and KK an absolutely continuous distribution function such that the corresponding density function KK\,^{\prime} is symmetric about zero. Then, Azzalini’s form of skew-symmetric density function for any real λ\lambda, as mentioned in Azzalini, (1985), is given as

2f(x)K(λx).2\,f(x)\,K(\lambda x). (1)

Arnold and Lin, (2004) studied a special case using KK as the cumulative distribution function (cdf) of ff in (1). Nadarajah and Kotz, (2003) introduced the skew-symmetric-normal distribution family by replacing ff with ϕ\phi, the probability density function (pdf) of the standard normal distribution in (1). Further, they studied various skew-symmetric distributions by choosing KK as the cdf of normal, Student’s t, Laplace, logistic, and uniform distributions. Nadarajah, (2009) introduced and studied the skew logistic distribution considering ff and KK as pdf and cdf of logistic distribution, respectively in (1).

When ff and KK are the density and distribution functions of the Laplace distribution in (1), respectively, it is called a skew-Laplace distribution. Aryal and Rao, (2005) studied some properties of truncated skew-Laplace distribution, and Kozubowski and Nolan, (2008) showed that a skew-Laplace distribution is infinitely divisible. Further, Nekoukhou and Alamatsaz, (2012) introduced a more general family of skew-Laplace distributions by considering ff as a standard Laplace pdf, KK as an arbitrary symmetric cdf, and ww as any odd continuous function in place of λx\lambda x in (1). That is,

e|x|F(w(x)).e^{-\lvert x\rvert}\,F(w(x)). (2)

Recently much interest has been shown in the construction of flexible parametric classes of distributions that exhibit skewness and kurtosis, which is different from the normal distribution. While much of classical statistical analysis is based on Gaussian distributional assumptions, statistical modeling with the Laplace distribution has gained importance in many applied fields. The motivation originates from data sets, including environmental, financial, and biomedical ones, which often do not follow the normal law. Models based on the Laplace distributions are popular in economics and finance; see Zeckhauser and Thompson, (1970); Rachev and SenGupta, (1993); Rydén et al., (1998); Theodossiou, (1998); Kotz et al., (2001); Kozubowski and Podgórski, (2001). They are rapidly becoming distributions of the first choice whenever “something” with heavier than normal tail is observed in the data. The interesting characteristic has often bound on its support from either end along with skew nature. i.e., data is positively skewed but bounded below or negatively skewed but bounded above. For example, consider the scenario of family income, which is typically positively skewed and bounded below by a certain amount. In this paper, by considering interesting applications of Laplace distribution, the need for skewness and restriction on the support of variable of interest, skew-symmetric-Laplace-uniform distribution (SSLUD) is introduced. Here, we consider ff as the standard Laplace density function and KK as a distribution function of Uniform(θ,θ)(-\theta,\theta) in (1). It provides a more flexible model representing the data as adequately as possible. Thus, we can expect this to be useful in more practical situations. The standard Laplace pdf is

f(x)=12e|x|,x.f(x)=\frac{1}{2}\,e^{-\lvert x\rvert},\quad x\in\mathbb{R}. (3)

The distribution function of Uniform(θ,θ)(-\theta,\theta) where θ>0\theta>0 is

K(x)={ 0ifx<θ,x+θ2θifθx<θ, 1ifxθ.K(x)=\begin{cases}\;0&\text{if}\ x<-\theta,\\ \displaystyle\;\frac{x+\theta}{2\theta}&\text{if}\ -\theta\leqslant x<\theta,\\ \;1&\text{if}\ x\geqslant\theta.\end{cases} (4)

Thus, the density function of SSLUD is

g(x)=2f(x)K(λx),x,λ.g(x)=2\,f(x)\,K(\lambda x),\quad x,\lambda\in\mathbb{R}. (5)

We define μ=θλ\displaystyle\mu=\frac{\theta}{\lambda} so that model is identifiable. Here λ\lambda\in\mathbb{R}, θ>0\theta>0 and hence μ{0}\mu\in\mathbb{R}-\{0\}. Thus,

g(x)={ 0ifxμ<1,e|x|(x2μ+12)if1xμ<1,e|x|ifxμ1.g(x)=\begin{cases}\;0&\text{if}\ \displaystyle\frac{x}{\mu}<-1,\\ \displaystyle\;e^{-\lvert x\rvert}\ \left(\frac{x}{2\mu}+\frac{1}{2}\right)&\text{if}\ \displaystyle-1\leqslant\frac{x}{\mu}<1,\\ \displaystyle\;e^{-\lvert x\rvert}\ &\text{if}\ \displaystyle\frac{x}{\mu}\geqslant 1.\end{cases} (6)

Here, one can notice that the support of XX is bounded above if μ<0\mu<0 and bounded below if μ>0\mu>0 by μ-\mu. The corresponding cdf G(x)G(x) is as follows. When μ<0\mu<0,

G(x)={exifx<μ,ex2μ(x+μ1)+eμ2μifμx<0, 1+eμ2μex2μ(x+μ+1)if 0x<μ, 1ifxμ,\begin{split}G(x)&=\begin{cases}\displaystyle\;e^{x}&\text{if}\ x<\mu,\vspace{0.25 cm}\\ \displaystyle\;\frac{e^{x}}{2\mu}(x+\mu-1)+\frac{e^{\mu}}{2\mu}&\text{if}\ \mu\leqslant x<0,\vspace{0.25 cm}\\ \displaystyle\;1+\frac{e^{\mu}}{2\mu}-\frac{e^{-x}}{2\mu}(x+\mu+1)&\text{if}\ 0\leqslant x<-\mu,\vspace{0.25 cm}\\ \;1&\text{if}\ x\geqslant-\mu,\end{cases}\\ \end{split} (7a)

and when μ>0\mu>0,

G(x)={ 0ifx<μ,ex2μ(x+μ1)+eμ2μifμx<0, 1+eμ2μex2μ(x+μ+1)if 0x<μ, 1exifxμ.\begin{split}G(x)&=\begin{cases}\;0&\text{if}\ x<-\mu,\vspace{0.25 cm}\\ \displaystyle\;\frac{e^{x}}{2\mu}(x+\mu-1)+\frac{e^{-\mu}}{2\mu}&\text{if}\ -\mu\leqslant x<0,\vspace{0.25 cm}\\ \displaystyle\;1+\frac{e^{-\mu}}{2\mu}-\frac{e^{-x}}{2\mu}(x+\mu+1)&\text{if}\ 0\leqslant x<\mu,\vspace{0.25 cm}\\ \;1-e^{-x}&\text{if}\ x\geqslant\mu.\end{cases}\end{split} (7b)

Throughout the rest of this paper, unless otherwise stated, we shall assume that λ>0\lambda>0, i.e., μ>0\mu>0, since the corresponding results for λ<0\lambda<0, i.e., μ<0\mu<0, can be obtained using the fact that X-X has a pdf given by 2f(x)K(λx)2f(x)K(-\lambda x). Figure 1 illustrates the shape of the pdf (6) for μ=0.25,0.5,0.75,1,3\mu=0.25,0.5,0.75,1,3.

Refer to caption
Figure 1: The skew-symmetric-Laplace-uniform pdf (6) for μ=0.25,0.5,0.75,1,3\mu=0.25,0.5,0.75,1,3

The skew-symmetric-Laplace-uniform distribution with parameter μ\mu, SSLUD(μ)SSLUD(\mu) appears not to have been introduced yet. We provide a comprehensive description of the mathematical properties of (6). This paper follows up on Nadarajah, (2009), where a comprehensive description of the mathematical properties for the skew-logistic distribution is provided. Here, we have derived formulas for moment generating function, characteristic function, and first four raw moments (Sect. 2), mode and median (Sect. 3), hazard rate function (Sect. 4), mean deviation about ‘aa’ (Sect. 5), Rènyi entropy and Shannon entropy (Sect. 6), simulation and estimation by the methods of moments and maximum likelihood (Sect. 7). We also discuss these estimators’ finite sample and asymptotic properties (Sect. 7). Finally, the application of SSLUD(μ)SSLUD(\mu) to real-life data on the daily percentage change in the price of NIFTY 50, an Indian stock market index, is discussed. Comparison of fitting of SSLUD(μ)SSLUD(\mu) is done with fitting of normal distribution N(θ,σ2)N(\theta,\sigma^{2}), Laplace distribution L(θ,β)L(\theta,\beta), and skew-Laplace distribution SL(λ)SL(\lambda) for the above data (Sect. 8).

2 Moment generating function, characteristic function, and moments

Here, we derive the moment generating function and the characteristic function of r. v. XX having pdf given in (6). The moment generating function (MGF) is MX(t)=E(etX)M_{X}(t)=E(e^{tX}). By using (6), one obtains

MX(t)=12μ{1+eμ(1+t)(1+t)2+1eμ(1t)(1t)2}+1(1t2),fort<1.M_{X}(t)=\frac{1}{2\mu}\left\{\frac{-1+e^{-\mu(1+t)}}{(1+t)^{2}}+\frac{1-e^{-\mu(1-t)}}{(1-t)^{2}}\right\}+\frac{1}{(1-t^{2})}\ ,\quad\text{for}\ t<1. (8)

The corresponding characteristic function defined by ϕX(t)=E(eitX)\phi_{X}(t)=E(e^{itX}) is given as

ϕX(t)=12μ{1+eμ(1+it)(1+it)2+1eμ(1it)(1it)2}+1(1+t2),forit<1,\phi_{X}(t)=\frac{1}{2\mu}\left\{\frac{-1+e^{-\mu(1+it)}}{(1+it)^{2}}+\frac{1-e^{-\mu(1-it)}}{(1-it)^{2}}\right\}+\frac{1}{(1+t^{2})}\ ,\quad\text{for}\ it<1, (9)

where i=1i=\sqrt{-1} is the complex imaginary unit.

The moments of a probability distribution are a collection of descriptive constants used for measuring its properties. Here, we derive the expression of the first four raw moments of XX. They are as follows.

μ1=2μ(1+2μ)eμ,μ2=2,μ3=24μeμ[μ2+6μ+18+24μ],μ4=24.\begin{split}\mu_{1}^{{}^{\prime}}&=\frac{2}{\mu}-\left(1+\frac{2}{\mu}\right)e^{-\mu}\,,\\ \mu_{2}^{{}^{\prime}}&=2\,,\\ \mu_{3}^{{}^{\prime}}&=\frac{24}{\mu}-e^{-\mu}\left[\mu^{2}+6\mu+18+\frac{24}{\mu}\right]\,,\\ \mu_{4}^{{}^{\prime}}&=24\,.\end{split} (10)

We see that μ2r=(2r)!\mu_{2r}^{{}^{\prime}}=(2r)! for r=1,2,r=1,2,\ldots and corresponding central moments can be obtained using these raw moments but can not be simplified further. Note that, expressions given in (10) are valid only for μ>0\mu>0. If μ<0\mu<0, one must replace μ\mu by μ-\mu in each of these expressions; in addition, the expressions for the odd order moments must be multiplied by -1.

Refer to caption
Figure 2: Variation of the four measures: (a) E(XX), (b) Variance(XX), (c) Skewness(XX) and
(d) Kurtosis(XX) for μ=10,,10\mu=-10,\ldots,10

Figure 2 illustrates the behavior of the four measures E(XX), Var(XX), Skewness(XX) and Kurtosis(XX) for μ=10,,10\mu=-10,\ldots,10. Mean and skewness are decreasing functions of μ\mu over the range (,0)(-\infty,0) and (0,)(0,\infty), while variance and kurtosis are even functions of μ\mu. The variance strictly decreases as μ\mu moves from -\infty to 0 and increases as μ\mu moves from 0 to \infty.

3 Mode and median

Mode is the value of the r. v. XX at which pdf g(x)g(x) is maximum. When μ>0\mu>0, g(x)g^{\prime}(x) is,

g(x)={ex(x+12μ+12)ifμx<0,ex(1x2μ12)if 0x<μ,exifxμ.g^{\prime}(x)=\begin{cases}\displaystyle\;e^{x}\left(\frac{x+1}{2\mu}+\frac{1}{2}\right)&\text{if}\ -\mu\leqslant x<0,\\ \displaystyle\;e^{-x}\ \left(\frac{1-x}{2\mu}-\frac{1}{2}\right)&\text{if}\ 0\leqslant x<\mu,\\ \displaystyle\;-\,e^{-x}\ &\text{if}\ x\geqslant\mu.\end{cases} (11)

It is clear from (11) that the function g(x)g(x) is increasing in [μ,0)[-\mu,0) and decreasing in [μ,)[\mu,\infty). Hence, mode M0M_{0} of (6) lies in the interval [0,μ][0,\mu]. Accordingly, we equate g(x)g^{\prime}(x) to zero and solve for x. Thus, the value of M0M_{0} is M0=1μM_{0}=1-\mu for 12μ<1\displaystyle\frac{1}{2}\leqslant\mu<1. But when μ<12\mu<\displaystyle\frac{1}{2}, the function g(x)g(x) increases in [μ,μ)[-\mu,\mu) and decreases in [μ,)[\mu,\infty). Hence, M0=μM_{0}=\mu. Similarly, when μ>1\mu>1, the function g(x)g(x) increases in [μ,0)[-\mu,0) and decreases in [0,)[0,\infty). Hence, M0=0M_{0}=0. On similar lines, one can derive the expression of M0M_{0} for μ<0\mu<0. Thus, combining these two expressions of M0M_{0}, we get

M0={μif 0<|μ|<12,sign(μ)μif12|μ|<1, 0if|μ|1.M_{0}=\begin{cases}\;\mu&\text{if}\ \displaystyle 0<|\mu|<\frac{1}{2},\\ \;\text{sign}(\mu)-\mu&\text{if}\ \displaystyle\frac{1}{2}\leqslant|\mu|<1,\\ \;0&\text{if}\ |\mu|\geqslant 1.\end{cases} (12)

The median MM of (6) is the value of r. v. XX such that G(M)=12G(M)=\frac{1}{2}. Thus, for μ>0\mu>0 using (7b),

M={Solution of the equation,ifG(0)>12,eM(M1+μ)+eμμ=0Solution of the equation,ifG(0)12<G(μ),eM(M1μ)+eμ+μ=0ln2ifG(μ)12,M=\begin{cases}\;\text{Solution of the equation,}&\text{if}\ \displaystyle G(0)>\frac{1}{2},\\ \;e^{M}(M-1+\mu)+e^{-\mu}-\mu=0\vspace{0.35 cm}\\ \;\text{Solution of the equation,}&\text{if}\ \displaystyle G(0)\leqslant\frac{1}{2}<G(\mu),\\ \;e^{-M}(-M-1-\mu)+e^{-\mu}+\mu=0\vspace{0.35 cm}\\ \;\ln 2&\text{if}\ \displaystyle G(\mu)\leqslant\frac{1}{2},\par\end{cases} (13)

where G(0)=12+eμ12μ\displaystyle G(0)=\frac{1}{2}+\frac{e^{-\mu}-1}{2\mu} and G(μ)=1eμ\displaystyle G(\mu)=1-e^{-\mu}. Table 1 represents values of the median of (6) for different positive values of μ\mu using the Newton-Raphson iterative procedure in R-software. If μ<0\mu<0, one can obtain the median MM on similar lines using (7a).

Table 1: Median of SSLUD(μ\mu) for μ=\mu=0.25, 0.5, …, 1.5
μ\mu 0.25 0.5 0.75 1 1.25 1.5
MM 0.6931472 0.6931472 0.6920484 0.6681079 0.6273646 0.5811654

4 Hazard rate function

The reliability function R(x)=1G(x)R(x)=1-G(x) for μ>0\mu>0 is obtained using (7b) as,

R(x)={ 1ifx<μ, 1ex2μ(x+μ1)eμ2μifμx<0,eμ2μ+ex2μ(x+μ+1)if 0x<μ,exifxμ.R(x)=\begin{cases}\;1&\text{if}\ x<-\mu,\vspace{0.25 cm}\\ \displaystyle\;1-\frac{e^{x}}{2\mu}(x+\mu-1)-\frac{e^{-\mu}}{2\mu}&\text{if}\ -\mu\leqslant x<0,\vspace{0.25 cm}\\ \displaystyle\;-\frac{e^{-\mu}}{2\mu}+\frac{e^{-x}}{2\mu}(x+\mu+1)&\text{if}\ 0\leqslant x<\mu,\vspace{0.25 cm}\\ \displaystyle\;e^{-x}&\text{if}\ x\geqslant\mu.\end{cases} (14)

The hazard rate function is an important quantity, characterizing life phenomena. After some simple steps, one can get the hazard function h(x)=g(x)R(x)\displaystyle h(x)=\frac{g(x)}{R(x)} for μ>0\mu>0 as follows.

h(x)={ 0ifx<μ,[1+1+(2μeμ)exx+μ]1ifμx<0,[1+1e(xμ)x+μ]1if 0x<μ, 1ifxμ.h(x)=\begin{cases}\;0&\text{if}\ x<-\mu,\vspace{0.25 cm}\\ \displaystyle\;\left[-1+\frac{1+(2\mu-e^{-\mu})e^{-x}}{x+\mu}\right]^{-1}&\text{if}\ -\mu\leqslant x<0,\vspace{0.25 cm}\\ \displaystyle\;\left[1+\frac{1-e^{(x-\mu)}}{x+\mu}\right]^{-1}&\text{if}\ 0\leqslant x<\mu,\vspace{0.25 cm}\\ \;1&\text{if}\ x\geqslant\mu.\end{cases} (15)

One can easily check that h(x)h(x) is increasing function of xx for μ<0\mu<0 as well as for μ>0\mu>0. Hence, SSLUD(μ)SSLUD(\mu) is increasing failure rate (IFR) distribution.

5 Mean deviation

The amount of scatter in a population is evidently measured to some extent by the totality of deviations from the mean and median. These are known as the mean deviation about the mean and the mean deviation about the median, respectively. Mean deviation about an arbitrary real number ‘aa’ is defined by ηa=E|Xa|\eta_{a}=E\lvert X-a\rvert.

It leads to expression as

ηa={(1+2μ)eμ+(2μa)ifa<μ,(aμ)eμ+(aμ2μ+1)ea+(2μa)ifμa<0,(aμ)eμ+(aμ+2μ+1)ea+(a2μ)if 0a<μ,(1+2μ)eμ+2ea+(a2μ)ifaμ.\eta_{a}=\begin{cases}\displaystyle\;-\left(1+\frac{2}{\mu}\right)e^{-\mu}+\left(\frac{2}{\mu}-a\right)&\text{if}\ a<-\mu,\vspace{0.35cm}\\ \displaystyle\;\left(\frac{a}{\mu}\right)e^{-\mu}+\left(\frac{a}{\mu}-\frac{2}{\mu}+1\right)e^{a}+\left(\frac{2}{\mu}-a\right)&\text{if}\ -\mu\leqslant a<0,\vspace{0.35 cm}\\ \displaystyle\;\left(\frac{a}{\mu}\right)e^{-\mu}+\left(\frac{a}{\mu}+\frac{2}{\mu}+1\right)e^{-a}+\left(a-\frac{2}{\mu}\right)&\text{if}\ 0\leqslant a<\mu,\vspace{0.35cm}\\ \displaystyle\;\left(1+\frac{2}{\mu}\right)e^{-\mu}+2e^{-a}+\left(a-\frac{2}{\mu}\right)&\text{if}\ a\geqslant\mu.\end{cases} (16)

To obtain mean deviation about mean and mean deviation about median, ‘aa’ in the above expression can be replaced by mean and median, respectively.

6 Entropy

The entropy of a random variable XX measures the variation of uncertainty. The Rènyi entropy of order α\alpha is

Hα=11αlog2{gα(x)𝑑x},α>0,α1,H_{\alpha}=\frac{1}{1-\alpha}\,\log_{2}\left\{\int g^{\alpha}(x)dx\right\},\ \ \alpha>0\ ,\ \alpha\neq 1, (17)

where g(x)g(x) is pdf of random variable XX. By using (6), one can write

gα(x)𝑑x=I1+I2+eαxα,\int g^{\alpha}(x)dx=I_{1}+I_{2}+\frac{e^{-\alpha x}}{\alpha},

where I1=μ0eαx(x2μ+12)α𝑑x=(1α)(12)α[j=0α(1μα)jα!(αj)!(1μα)αeμα]I_{1}=\int\displaylimits_{-\mu}^{0}e^{\alpha x}\left(\frac{x}{2\mu}+\frac{1}{2}\right)^{\alpha}dx=\left(\frac{1}{\alpha}\right)\left(\frac{1}{2}\right)^{\alpha}\left[\sum_{j=0}^{\alpha}\left(\frac{-1}{\mu\alpha}\right)^{j}\frac{\alpha!}{(\alpha-j)!}-\left(\frac{-1}{\mu\alpha}\right)^{\alpha}e^{-\mu\alpha}\right] and I2=0μeαx(x2μ+12)α𝑑x=j=0αα!(αj)!(2μα)j[2(αj)eμαα].I_{2}=\int\displaylimits_{0}^{\mu}e^{-\alpha x}\left(\frac{x}{2\mu}+\frac{1}{2}\right)^{\alpha}dx=\sum_{j=0}^{\alpha}\frac{\alpha!}{(\alpha-j)!(2\mu\alpha)^{j}}\left[\frac{2^{-(\alpha-j)}-e^{-\mu\alpha}}{\alpha}\right].

Therefore,

gα(x)𝑑x=1αj=0αα!(αj)![2(αj)(1+(1)j)eμα(2μα)j]+eμαα[1(12μα)α].\begin{split}\int g^{\alpha}(x)dx=&\frac{1}{\alpha}\sum_{j=0}^{\alpha}\frac{\alpha!}{(\alpha-j)!}\left[\frac{2^{-(\alpha-j)}(1+(-1)^{j})-e^{-\mu\alpha}}{(2\mu\alpha)^{j}}\right]\\ &+\frac{e^{-\mu\alpha}}{\alpha}\left[1-\left(\frac{-1}{2\mu\alpha}\right)^{\alpha}\right].\end{split} (18)

One can obtain the Rènyi entropy of order α\alpha by substituting (18) in (17).

The Shannon entropy function is the particular case of (17) for α1\alpha\uparrow 1, and it is H=E[log2g(X)]H=E[-\log_{2}g(X)], where g(x)g(x) is pdf of random variable XX. Using this definition, after some simplification we get,

H=1ln20μxex2μlog2[(x2μ+12)(x2μ+12)]𝑑x0μex2log2[(x2μ+12)(x2μ+12)]𝑑x.\begin{split}H=&\frac{1}{\ln 2}-\int\displaylimits_{0}^{\mu}\frac{xe^{-x}}{2\mu}\ \log_{2}\left[\frac{\left(\displaystyle\frac{x}{2\mu}+\frac{1}{2}\right)}{\left(\displaystyle\frac{-x}{2\mu}+\frac{1}{2}\right)}\right]dx\\ &-\int\displaylimits_{0}^{\mu}\frac{e^{-x}}{2}\ \log_{2}\left[\left(\frac{-x}{2\mu}+\frac{1}{2}\right)\left(\frac{x}{2\mu}+\frac{1}{2}\right)\right]dx.\end{split} (19)

Since the above integration is cumbersome, we numerically evaluate HH for different values of μ\mu using R-software. Figure 3 represents a graph of μ\mu (μ>0)(\mu>0) versus HH.

Refer to caption
Figure 3: Behavior of Shannon entropy function

7 Estimation

Here, we first consider simulating values of a random variable XX with the pdf (6) using the inverse transformation technique. Let rr be a random number between zero and one. The generator to generate a random sample is

X={Solution of the equation,if 0r<G(0),ex(x1+μ)+eμ2rμ=0Solution of the equation,ifG(0)r<G(μ),ex(x1μ)+eμ+2(1r)μ=0ln(1r)ifG(μ)r1.X=\begin{cases}\;\text{Solution of the equation,}&\text{if}\ 0\leqslant r<G(0),\\ \;e^{x}(x-1+\mu)+e^{-\mu}-2r\mu=0\vspace{0.35 cm}\\ \;\text{Solution of the equation,}&\text{if}\ G(0)\leqslant r<G(\mu),\\ \;e^{-x}(-x-1-\mu)+e^{-\mu}+2(1-r)\mu=0\vspace{0.35 cm}\\ \;-\ln(1-r)&\text{if}\ G(\mu)\leqslant r\leqslant 1.\par\end{cases} (20)

One can use the Newton-Raphson method to solve the equation in (20) and generate a random sample from SSLUD(μ)SSLUD(\mu) given in (6).

Now, we consider the estimation of μ\mu by the method of moments and the method of maximum likelihood. To estimate unknown parameter μ\mu, we have to consider both the cases μ<0\mu<0 and μ>0\mu>0 together. Suppose x1,,xnx_{1},...,x_{n} is an observed random sample of size ‘nn’ from (6). For the method of moments estimation, after equating sample mean x¯\overline{x} to the first population raw moment of (6), one obtains the equation

x¯={2μ+(12μ)eμifμ<0,2μ(1+2μ)eμifμ>0.\overline{x}=\begin{cases}\displaystyle\;\frac{2}{\mu}+\left(1-\frac{2}{\mu}\right)e^{\mu}&\quad\text{if}\ \mu<0,\\ \displaystyle\;\frac{2}{\mu}-\left(1+\frac{2}{\mu}\right)e^{-\mu}&\quad\text{if}\ \mu>0.\end{cases} (21)

From Figure 2, we see that μ1\mu_{1}^{{}^{\prime}} decreases from 0 to -1 when <μ<0-\infty<\mu<0 and it decreases from 1 to 0 when 0<μ<0<\mu<\infty, i.e., always 1<μ1<1-1<\mu_{1}^{{}^{\prime}}<1. Therefore, if x¯<1\overline{x}<-1 or x¯>1\overline{x}>1 for a particular sample, then (21) will not have an exact solution. As per Figure 2, μ\mu corresponds to the closest value of μ1\mu_{1}^{{}^{\prime}} to x¯\overline{x} if x¯<1\overline{x}<-1 or x¯>1\overline{x}>1 is a value close to zero. But as per parameter space, μ\mu can not take the value zero. Hence, we define the moment estimator μ~\tilde{\mu} of μ\mu as 105-10^{-5} if x¯<1\overline{x}<-1 and 10510^{-5} if x¯>1\overline{x}>1. Thus, the moment estimator μ~\tilde{\mu} of μ\mu is obtained as follows.

μ~={105ifx¯1,Solution of the equation,if1<x¯<0,2μ+(12μ)eμx¯=0Solution of the equation,if 0x¯<1,2μ(1+2μ)eμx¯=0 105ifx¯1.\tilde{\mu}=\begin{cases}\;-10^{-5}&\quad\text{if}\ \ \overline{x}\leqslant-1,\vspace{0.35 cm}\\ \;\text{Solution of the equation,}&\quad\text{if}\ \ -1<\overline{x}<0,\\ \;\displaystyle\frac{2}{\mu}+\left(1-\frac{2}{\mu}\right)e^{\mu}-\overline{x}=0\vspace{0.35 cm}\\ \;\text{Solution of the equation,}&\quad\text{if}\ \ 0\leqslant\overline{x}<1,\\ \;\displaystyle\frac{2}{\mu}-\left(1+\frac{2}{\mu}\right)e^{-\mu}-\overline{x}=0\vspace{0.35 cm}\\ \;10^{-5}&\quad\text{if}\ \ \overline{x}\geqslant 1.\end{cases} (22)

We consider the estimation of μ\mu by the method of maximum likelihood in the following. Let x(1),x(2),,x(n)x_{(1)},x_{(2)},\ldots,x_{(n)} be the order statistics of given sample. Suppose μ<0\mu<0 and ‘r1r_{1}’ denotes the number of observations less than μ\mu such that <x(1)<x(2)<<x(r1)μx(r1+1)<<x(n)<μ<-\infty<x_{(1)}<x_{(2)}<\ldots<x_{(r_{1})}\leqslant\mu\leqslant x_{(r_{1}+1)}<\ldots<x_{(n)}<-\mu<\infty, i.e. <μ<min(0,x(n))-\infty<\mu<\min(0,\,-x_{(n)}) where r1=0,1,2,,nr_{1}=0,1,2,\ldots,n. Similarly, suppose μ>0\mu>0 and ‘r2r_{2}’ denotes the number of observations lying in the interval [μ,μ][-\mu,\mu] such that <μ<x(1)<x(2)<<x(r2)μx(r2+1)<<x(n)<-\infty<-\mu<x_{(1)}<x_{(2)}<\ldots<x_{(r_{2})}\leqslant\mu\leqslant x_{(r_{2}+1)}<\ldots<x_{(n)}<\infty, i.e. max(0,x(1))<μ<\max(0,\,-x_{(1)})<\mu<\infty where r2=0,1,2,,nr_{2}=0,1,2,\ldots,n. Hence, the log-likelihood function of μ\mu is written as

l={l1=i=1n|x(i)|+i=r1+1nln(x(i)+μ2μ)if<μ<min{0,x(n)},l2=i=1n|x(i)|+i=1r2ln(x(i)+μ2μ)ifmax{x(1), 0}<μ<.l=\begin{cases}\;l_{1}=\displaystyle-\sum\limits_{i=1}^{n}\lvert x_{(i)}\rvert+\sum\limits_{i=r_{1}+1}^{n}ln\left(\frac{x_{(i)}+\mu}{2\mu}\right)&\text{if}\ -\infty<\mu<\min\{0,\,-x_{(n)}\},\\ \;l_{2}=\displaystyle-\sum\limits_{i=1}^{n}\lvert x_{(i)}\rvert+\sum\limits_{i=1}^{r_{2}}ln\left(\frac{x_{(i)}+\mu}{2\mu}\right)&\text{if}\ \max\{-x_{(1)},\,0\}<\mu<\infty.\end{cases} (23)

In the following, we give a step-wise procedure for computation of the MLE μ^\hat{\mu} of μ\mu.

  1. Step 1:

    Numerically maximize l1l_{1} over the range (a,min{0,x(n)})(-a,\min\{0,-x_{(n)}\}). Suppose the maximum value of l1l_{1} is l^1\hat{l}_{1} which is attained at μ^1\hat{\mu}_{1}, say, where ‘aa’ is a sufficiently large positive number chosen for computation purposes.

  2. Step 2:

    Numerically maximize l2l_{2} over the range (max{x(1),0},a)(\max\{-x_{(1)},0\},a). Suppose the maximum value of l2l_{2} is l^2\hat{l}_{2} which is attained at μ^2\hat{\mu}_{2}, say.

  3. Step 3:

    MLE μ^\hat{\mu} of μ\mu is

    μ^=\displaystyle\hat{\mu}= {μ^1ifl^1>l^2,μ^2otherwise.\displaystyle\begin{cases}\;\hat{\mu}_{1}\quad\text{if}\ \hat{l}_{1}>\hat{l}_{2},\\ \;\hat{\mu}_{2}\quad\text{otherwise}.\end{cases} (24)

Finite sample properties of μ~\tilde{\mu} and μ^\hat{\mu} are studied using simulation, and computations are done using R- software. Table 2 and Table 3 presents bias and MSE of μ~\tilde{\mu} and μ^\hat{\mu} for n=100(100)1000n=100(100)1000 and for μ=1.5,0.75,0.25,0.25,0.75,1.5\mu=-1.5,-0.75,-0.25,0.25,0.75,1.5. We see that bias and MSE decrease as sample size nn increases for both MLE μ^\hat{\mu} and moment estimator μ~\tilde{\mu}, with few exceptions only for bias. Further, the MSE of μ^\hat{\mu} is always less than the corresponding MSE of μ~\tilde{\mu}. Also, one can observe that sign of bias of MLE μ^\hat{\mu} is opposite to the sign of parameter μ\mu. As parameter μ\mu approaches zero from any side, MSE and magnitude of bias of μ^\hat{\mu} decrease. But, no such observation in the case of the moment estimator μ~\tilde{\mu}. To check the asymptotic nature of the distribution of μ^\hat{\mu} and μ~\tilde{\mu} using simulation, we plotted observed densities for various values of the sample size nn. We observe that as nn increases, the distribution of both μ^\hat{\mu} and μ~\tilde{\mu} converges to the normal distribution, but the rate of convergence to normal distribution seems to be much higher for μ^\hat{\mu} than μ~\tilde{\mu}. Thus, based on all the above results, we conclude that MLE is better than the moment estimator of μ\mu for SSLUD(μ\mu).

Table 2: Bias and MSE of MLE and moment estimator for μ=1.5,0.75,0.25\mu=-1.5,-0.75,-0.25, sample size n=100(100)1000n=100(100)1000, and simulation size N=2000N=2000
μ\mu nn MLE Moment estimator
Bias MSE Bias MSE
-1.5 100 0.06024381 0.045176654 0.0003797204 0.50541564
200 0.03906522 0.021357856 0.0157055747 0.26786436
300 0.02933963 0.012989993 -0.0008644177 0.16465504
400 0.02375948 0.009209691 -0.0085926100 0.12896987
500 0.01766114 0.007451091 -0.0065899772 0.10033671
600 0.01808905 0.006370478 0.0075580998 0.08311324
700 0.01456689 0.005214147 -0.0003676365 0.06853064
800 0.01492506 0.004456640 -0.0164346584 0.05661172
900 0.01381575 0.003861085 -0.0079539753 0.05188121
1000 0.01378036 0.003294051 0.0052817371 0.04687188
-0.75 100 0.032511901 0.0134889603 -0.02488011 0.37927153
200 0.023375017 0.0062341973 0.02678563 0.24807994
300 0.022614234 0.0040753483 0.05442608 0.18159122
400 0.013782428 0.0026481775 0.02407104 0.14540491
500 0.014188578 0.0019942288 0.04011415 0.12661616
600 0.010531113 0.0016580024 0.02741234 0.10965835
700 0.009567891 0.0014142729 0.02247448 0.09215384
800 0.008969822 0.0012107034 0.03299546 0.08416938
900 0.008833928 0.0010258905 0.02604549 0.07738691
1000 0.007307065 0.0009473139 0.01597401 0.06532169
-0.25 100 0.026910685 0.0043941552 -0.20148295 0.28701317
200 0.014633591 0.0016442189 -0.12561277 0.18340413
300 0.011298482 0.0010134272 -0.11008763 0.14648063
400 0.008403715 0.0007178242 -0.07115405 0.11693260
500 0.006866262 0.0005193217 -0.05475621 0.10104767
600 0.006577965 0.0004359336 -0.04101810 0.09227325
700 0.005574953 0.0003294627 -0.03931742 0.08363312
800 0.005196938 0.0002914057 -0.02245561 0.07867760
900 0.004681950 0.0002552058 -0.03305608 0.07551096
1000 0.003797666 0.0002160883 -0.01393033 0.06746986
Table 3: Bias and MSE of MLE and moment estimator for μ=0.25,0.75,1.5\mu=0.25,0.75,1.5, sample size n=100(100)1000n=100(100)1000, and simulation size N=2000N=2000
μ\mu nn MLE Moment estimator
Bias MSE Bias MSE
0.25 100 -0.026141601 0.0040926127 0.19908173 0.30299408
200 -0.015706993 0.0017378035 0.11979148 0.18277572
300 -0.010537695 0.0009629724 0.10281278 0.15122684
400 -0.009388154 0.0006823647 0.07138595 0.11273918
500 -0.007654403 0.0005241705 0.06670007 0.10613451
600 -0.006541976 0.0004273222 0.04710248 0.09317236
700 -0.005775066 0.0003498924 0.03681952 0.08264223
800 -0.005424833 0.0003076071 0.02613340 0.07893736
900 -0.004687041 0.0002641379 0.02308814 0.07288723
1000 -0.004587965 0.0002188929 0.02168387 0.07098162
0.75 100 -0.039403641 0.0141163154 0.02381151 0.36120747
200 -0.023215667 0.0057148979 -0.01903135 0.24011612
300 -0.018010206 0.0037173032 -0.04910507 0.18917471
400 -0.013004298 0.0026953723 -0.02435556 0.13988301
500 -0.011937422 0.0020292707 -0.04849263 0.13064004
600 -0.010423756 0.0016294899 -0.02277927 0.10673985
700 -0.009229675 0.0013339162 -0.03201923 0.09343322
800 -0.009286969 0.0011661790 -0.02381294 0.08053673
900 -0.008850638 0.0010360152 -0.02366172 0.07657251
1000 -0.008957869 0.0009469547 -0.01562601 0.06498910
1.5 100 -0.05884554 0.047383765 -0.013127745 0.54926083
200 -0.03000957 0.020339855 -0.006090958 0.25400260
300 -0.03186303 0.013144354 -0.010153344 0.16976755
400 -0.02284458 0.009625618 -0.002482506 0.13057787
500 -0.02293975 0.007759937 -0.008421723 0.09775602
600 -0.01841574 0.005969112 -0.009321518 0.08234397
700 -0.01724714 0.005152509 -0.004056375 0.06780765
800 -0.01197158 0.004282729 -0.008411236 0.06338525
900 -0.01484989 0.004060138 -0.009773787 0.05273530
1000 -0.01228560 0.003408502 0.003389947 0.04925195

8 Application

In this section, we present the application of skew-symmetric-Laplace-uniform distribution for modeling daily percentage change in the price of NIFTY 50, an Indian stock market index. Further, we have fitted and compared the proposed distribution SSLUD(μ)SSLUD(\mu) with normal distribution N(θ,σ2)N(\theta,\sigma^{2}), Laplace distribution L(θ,β)L(\theta,\beta), and skew-Laplace distribution SL(λ)SL(\lambda) for percentage change data. Here, SL(λ)SL(\lambda) refers to a special case of skew-Laplace distribution using ff and KK as pdf and cdf of standard Laplace distribution in (1). The NIFTY 50 is a benchmark Indian stock market index representing the weighted average of 50 of the largest Indian companies listed on the National Stock Exchange (NSE). It is one of the two leading stock indices used in India. The daily price of NIFTY 50 quoted in the National Stock Exchange of India Ltd. is available at https://in.investing.com/indices/s-p-cnx-nifty-historical-data and is selected for the current study. We consider the daily percentage change YtY_{t} on day t given by Yt=XtXt1Xt1×100\displaystyle Y_{t}=\frac{X_{t}\,-\,X_{t-1}}{X_{t-1}}\times 100, where XtX_{t} denotes the price of NIFTY 50 on day t. This transformed data covering the period 16th16^{th} December 2021 to 13th13^{th} April 2022 (82 working days) is as follows :
0.16, - 1.53, - 2.18, 0.94, 1.10, 0.69, - 0.40, 0.49, 0.86, - 0.11, - 0.06, 0.87, 1.57, 1.02, 0.67, - 1.00, 0.38, 1.07, 0.29, 0.87, 0.25, - 0.01, 0.29, - 1.07, - 0.96, - 1.01, - 0.79, - 2.66, 0.75, - 0.97, - 0.05, 1.39, 1.37, 1.16, - 1.24, - 0.25, - 1.73, 0.31, 1.14, 0.81, - 1.31, - 3.06, 3.03, - 0.17, - 0.10, - 0.16, - 0.40, - 0.67, - 0.17, - 4.78, 2.53, 0.81, - 1.12, - 0.65, - 1.53, - 2.35, 0.95, 2.07, 1.53, 0.21, 1.45, - 1.23, 1.87, 1.84, - 0.98, 1.16, - 0.40, - 0.13, - 0.40, 0.40, 0.60, 1.00, - 0.19, 1.18, 2.17, - 0.53, - 0.83, - 0.94, 0.82, - 0.62, - 0.82, - 0.31.

Mean, variance, and skewness for the above data is 0.027, 1.671, and - 0.639 respectively. The Wald-Wolfowitz runs test for randomness of YtY_{t} yields a p-value of 0.076, justifying the assumption of independence of the YtY_{t} values. We consider fitting the proposed skew-symmetric-Laplace-uniform distribution SSLUD(μ)SSLUD(\mu) along with normal distribution N(θ,σ2)N(\theta,\sigma^{2}), Laplace distribution L(θ,β)L(\theta,\beta), and skew-Laplace distribution SL(λ)SL(\lambda) to the data on percentage change. Using R-software, the MLE of the parameters and hence, the estimated value of log-likelihood are obtained. Akaike’s Information Criteria (AIC) and Bayesian Information Criteria (BIC) are used for model comparison. Table 4 shows that the proposed SSLUD(μ)SSLUD(\mu) provides the best fit for the data set which is very close to SL(λ)SL(\lambda) in terms of BIC. But in terms of AIC, N(θ,σ2\theta,\sigma^{2}) seems to be better than SSLUD(μ)SSLUD(\mu) and the best among the four distributions.

Table 4: MLEs, log-likelihood, AIC and BIC for daily percentage change in Nifty 50 index price (YtY_{t}) of 82 days
Distribution MLEs lnLL AIC BIC
SSLUD(μ)SSLUD(\mu) μ^\hat{\mu}= 62.38674 - 138.7604 279.5207 281.9274
SL(λ)SL(\lambda) λ^\hat{\lambda}= -6.247468e-05 - 138.7782 279.5564 281.9631
L(θ,β)L(\theta,\beta) θ^\hat{\theta}= - 0.03 , β^\hat{\beta}= 0.9990244 - 138.7580 281.5161 286.3295
N(θ,σ2)N(\theta,\sigma^{2}) θ^\hat{\theta}= 0.02682927, σ^2\hat{\sigma}^{2}= 1.650275 - 136.9081 277.8162 282.6296
Refer to caption
Figure 4: Plot of observed and expected densities of Normal distribution, Laplace distribution, skew-Laplace distribution, and SSLUD for daily percentage change in Nifty 50 index price (YtY_{t}) of 82 days

For SSLUD(μ)SSLUD(\mu), MLE of μ\mu is μ^\hat{\mu}=62.38674 which is relatively high, and by definition of g(x)g(x) in (6) for a large value of μ\mu, SSLUD approaches to Laplace distribution. But, from the histogram in Figure 4 and the value of skewness for YtY_{t}, one can observe that data is negatively skewed. It might be due to a single parameter in the proposed distribution unable to give the best fit to the data. By changing the data location, significant change observed in SSLUD’s curve in terms of location, scale, and shape. So, by observation, one can choose an appropriate change in location such that the value of μ^\hat{\mu} is significantly small for possible better fitting of data using the proposed distribution. Through the trial and error method, here we consider a change as - 0.8 and define transformed daily percentage change in Nifty 50 index price, Zt=Yt0.8Z_{t}=Y_{t}-0.8 which gives μ^=2.589259\hat{\mu}=-2.589259, a significantly small value. A possible generalization of proposed distribution with additional location parameter to avoid hindrance to employ it is under consideration, in order to make it more flexible and apt to catch the features present in real data.

Table 5 shows the MLEs, estimated log-likelihood, AIC, and BIC by fitting the distributions mentioned above to ZtZ_{t}. The graphical representation of the results is given in Figure 5. It is clear from Table 5 that the proposed SSLUD(μ)SSLUD(\mu) provides the best fit for the data set in terms of both AIC and BIC, but close to SL(λ)SL(\lambda). The plot of observed and expected densities presented in Figure 5 also confirms our findings. Thus, SSLUD(μ)SSLUD(\mu) is better for modeling daily percentage change in the price of NIFTY 50 in comparison to normal distribution N(θ,σ2)N(\theta,\sigma^{2}) and Laplace distribution L(θ,β)L(\theta,\beta), and one good alternative to skew-Laplace distribution SL(λ)SL(\lambda).

Table 5: MLEs, log-likelihood, AIC and BIC for transformed daily percentage change in Nifty 50 index price (ZtZ_{t}) of 82 days
Distribution MLEs lnLL AIC BIC
SSLUD(μ)SSLUD(\mu) μ^\hat{\mu}= - 2.589259 - 136.8343 275.6685 278.0752
SL(λ)SL(\lambda) λ^\hat{\lambda}= - 0.6988722 - 137.0020 276.0040 278.4107
L(θ,β)L(\theta,\beta) θ^\hat{\theta}= - 0.83 , β^\hat{\beta}= 0.9990244 - 138.7580 281.5161 286.3295
N(θ,σ2)N(\theta,\sigma^{2}) θ^\hat{\theta}= - 0.7731707, σ^2\hat{\sigma}^{2}= 1.650275 - 136.9081 277.8162 282.6296
Refer to caption
Figure 5: Plot of observed and expected densities of Normal distribution, Laplace distribution, skew-Laplace distribution, and SSLUD for transformed daily percentage change in Nifty 50 index price (ZtZ_{t}) of 82 days

Declarations

Conflict of interest

The authors declare that they have no conflict of interest to disclose.

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