Thurston’s Bounded image theorem
Abstract.
Thurston’s bounded image theorem is one of the key steps in his proof of the uniformisation theorem for Haken manifolds. Thurston never published its proof, and no proof has been known up to today, although a proof of its weaker version, called the bounded orbit theorem is known. In this paper, we give a proof of the original bounded image theorem, relying on recent development of Kleinian group theory.
1. Introduction
From the late 1970s to the early 1980s, Thurston gave lectures on his uniformisation theorem for Haken manifolds ([20, 21]). The theorem states that every atoroidal Haken 3-manifold with its (possibly empty) boundary consisting only of incompressible tori admits a complete hyperbolic metric in its interior. His proof of this theorem is based on an induction making use of a hierarchy for Haken manifolds invented by Waldhausen [24], i.e., a system of incompressible surfaces cutting the manifold down to balls, together with Maskit’s combination theorem (see for instance [10, §VII]).
For simplicity, we now focus on the case of closed atoroidal Haken manifolds. In the last step of the induction, we are in the situation where is a closed atoroidal Haken manifold obtained from a 3-manifold with non-empty boundary (without torus components) by pasting to itself by an orientation reversing involution. The induction hypothesis guarantees the existence of a convex cocompact hyperbolic structure on . There, Thurston used the so-called bounded image theorem to find a convex compact hyperbolic structure on , obtained by quasi-conformally deforming the given hyperbolic structure, which can be pasted up along to give a hyperbolic structure on .
Let us explain the setting in more detail. Let be an atoroidal Haken manifold with an even number of boundary components all of which are incompressible. In the same way as we assumed that is closed, we assume that no boundary component of is a torus, for simplicity. Suppose that there is an orientation-reversing involution taking each component of to another one. Let be the closed manifold obtained from by identifying the points on with their images under . Suppose moreover that is also atoroidal.
We assume, as the hypothesis of induction, that admits a convex compact hyperbolic structure; in other words, that the interior of is homeomorphic to for a convex cocompact Kleinian group . The space of convex compact hyperbolic structures on , which is not empty by assumption, modulo isotopy is parameterised by , as can be seen in the works of Ahlfors, Bers, Kra, Maskit, Marden and Sullivan. From each convex compact hyperbolic structure on , by taking the covering of associated with each component of , we get a quasi-Fuchsian group isomorphic to , and by considering the second coordinate of the parameterisation of the quasi-Fuchsian space, we obtain a map from to , where denotes the Teichmüller space of with orientation reversed. By considering this for every component of , we get a map called the skinning map, where denotes the product of for the components of . Since is orientation-reversing, it induces a homeomorphism .
Then the bounded image theorem can be stated as follows.
Theorem 1.1.
Suppose that is a compact (orientable) atoroidal Haken manifold having an even number of boundary components all of which are incompressible and none of which are tori, and assume that is not homeomorphic to an -bundle over a closed surface. Assume moreover that admits a convex compact hyperbolic structure. Suppose that there is an orientation reversing involution taking each component of to another component, and that by pasting each component of to its image under , we get a closed atoroidal manifold . Then there exists depending only on the topological type of such that the image of is bounded (i.e. precompact) in .
There are several expository papers and books on Thurston’s uniformisation theorem ([16, 18, 7] among others). In all of them, a weaker version of the bounded image theorem called the bounded orbit theorem, which is sufficient for the proof of the uniformisation theorem, was proved and used, instead of this original one.
Up to now, no complete proof of the bounded image theorem as stated above was known. Kent [8] gave a proof of this theorem under the assumption that is acylindrical, in which case the deformation space of hyperbolic structures on is compact.
The purpose of this paper is to give a proof of the original bounded image theorem.
Our argument relies on recent progress in Klenian group theory, in particular, the embedding of partial cores in the geometric limit from [4], the relation between the presence of short curves and their relative positions and the behaviour of ends invariant from [3], and criteria of convergence/divergence given in [2].
1.1. Outline
We are going to find such that if the image of is unbounded then contains a non-peripheral incompressible torus, contradicting our assumption. For that purpose we shall use the invariant introduced in [2].
Given a simple closed curve on a closed surface equipped with a hyperbolic metric , we define
where is a shortest marking for , is a full marking, and the supremum of the first term in the maximum is taken over all incompressible subsurfaces of whose boundaries contain . See Definition 4.1 for more details.
It is not difficult to see that in the setting of Theorem 1.1, for a given sequence in , if the sequence is unbounded, then there is a simple closed curve such that is unbounded (see Lemma 4.3). The core of our argument consists in showing, with the help of arguments from [3] and [2], that in this situation, there is a simple closed curve such that is unbounded and that bounds an essential annulus in . Using this argument repeatedly, we build (when is unbounded) an annulus in which goes through the interior of (viewed as a subset of ) times. If is large enough, this annulus must create an essential torus in , and contradicts the assumption that is atoroidal.
Although this is the overall logic of the proof, in the following sections, we shall present the main steps in a different order. After setting up some preliminary definitions in Section 2, we shall discuss the topological part of the proof in Section 3. First we show that we can add some assumptions on the topology of which will simplify the arguments later on. Next, we study incompressible surfaces on which can be extended multiple times through the characteristic submanifold of when it is viewed as a submanifold of . This will give us an integer which appears in Theorem 1.1. In Section 4 we shall discuss the relation between the behaviour of the invariant defined above, and the convergence and divergence of Kleinian groups. In Section 5 we shall prove our key proposition, and obtain the curve mentioned above. Finally in Section 6 we shall put these pieces together to prove our main theorem.
2. Preliminaries
2.1. Haken manifolds and characteristic submanifolds
An orientable irreducible compact 3-manifold which contains a non-peripheral incompressible surface is called a Haken manifold. We note that a compact irreducible 3-manifold with non-empty boundary is always Haken except for a 3-ball. We say that a Haken manifold is atoroidal when it does not contain a non-peripheral incompressible torus, and acylindrical when it does not contain a non-peripheral incompressible annulus. By the torus theorem for Haken manifolds ([25, 5, 6]), the former condition of the atoroidality is equivalent to the one that every monomorphism from into the fundamental group is peripheral, i.e. is conjugate to the image of the fundamental group of a boundary component.
The Jaco-Shalen-Johannson theory [5, 6] tells us that in a Haken manifold, incompressible tori and incompressible annuli can stay only in a very restricted place. Let us state what the theory says in the case when a Haken manifold is atoroidal and boundary-irreducible.
For an orientable atoroidal Haken boundary-irreducible 3-manifold , there exists a 3-submanifold of each of whose components is one of the following and which satisfies the following condition:
-
(a)
An -bundle whose associated -bundle coincides with its intersection with . Such a component is called a characteristic -pair.
-
(b)
A solid torus such that consists of annuli which are incompressible on both and . When is connected, it winds around the core curve of more than once.
-
(c)
A thickened torus at least one of whose boundary components lies on a component of .
Every properly embedded essential annulus (i.e. an incompressible annulus which is not homotopic into the boundary) is properly isotopic into , and no component of is properly isotopic into another component.
Such is unique up to isotopy, and is called the characteristic submanifold of . We note that in the case when has no torus boundary component, which is the assumption of our main theorem, a component of the last type (c) does not appear.
Thurston’s celebrated uniformisation theorem for Haken manifolds says that every atoroidal Haken manifold whose boundary consists of incompressible tori admits a hyperbolic structure of finite volume. More generally, he proved that every atoroidal Haken manifold, including the case when it has non-torus boundary components, admits a (minimally parabolic) convex hyperbolic structure of finite volume. The term ‘convex hyperbolic structure’ will be explained in the following subsection.
2.2. Kleinian groups and their deformation spaces
A Kleinian group is a discrete subgroup of . In this paper, we always assume Kleinian groups to be torsion free, and finitely generated except for the case when we talk about geometric limits. For a Kleinian group , we can consider the complete hyperbolic 3-manifold . The convex core of is the smallest convex submanifold that is a deformation retract. The Kleinian group and the corresponding hyperbolic 3-manifold are said to be geometrically finite when the convex core of has finite volume. In particular, is said to be convex compact, and to be convex cocompact if the convex core is compact. We also say that is minimally parabolic when every parabolic element in is contained in a rank-2 parabolic subgroup. Any convex cocompact Kleinian group is automatically minimally parabolic since it does not have parabolic elements.
A 3-manifold is said to have a hyperbolic structure when is homeomorphic to for a Kleinian group , and we regard the pull-back of the hyperbolic metric to as a hyperbolic structure on . In particular if is taken to be geomerically finite or convex cocompact, we say that has a geometrically finite or convex compact hyperbolic structure. If admits a hyperbolic structure, then must be atoroidal.
The set of hyperbolic structures on modulo isotopy, which we denote by , can be identified with a subset of the set of faithful discrete representations of into modulo conjugacy. We put on a topology induced from the weak topology on the representation space. We regard an element of both as a hyperbolic structure on and as a representation of into depending on the situation.
A Kleinian group is said to be a quasi-conformal deformation of another Kleinian group if there is a quasi-conformal homeomorphism such that as Möbius transformations on . When is a quasi-conformal deformation of , there is a diffeomorphism from to preserving the parabolicity in both directions, which induces an isomorphism between the fundamental groups coinciding with the isomorphism given by the conjugacy . We note that a quasi-conformal deformation of geometrically finite (resp. convex cocompact, minimally parabolic geometrically finite) group is again geometrically finite (resp. convex cocompact, minimally parabolic geometrically finite).
Let be a compact 3-manifold admitting a minimally parabolic geometrically finite hyperbolic structure . Let denote the set of all minimally parabolic geometrically finite hyperbolic structures on modulo isotopy, which is regarded as a subset of . Marden [9] showed that every minimally parabolic geometrically finite hyperbolic structures on is obtained as a quasi-conformal deformation of . Therefore we call the quasi-conformal deformation space. Furthermore, if is incompressible, combined with the work of Ahlfors, Bers, Kra, Maskit and Sullivan, there is a parameterisation , where denotes the Teichmüller space of , i.e. the direct product of the Teichmüller spaces of the components of . We shall refer to this map as the Ahlfors-Bers map.
In the case when is homeomorphic to for a closed oriented surface , the deformation spaces are denoted by respectively. The quasi-conformal deformation space consists of quasi-Fuchsian representations of , i.e. quasi-conformal deformations of a Fuchsian representation, and is therefore called the quasi-Fuchsian space. The Ahlfors-Bers map can be expressed as , where the second coordinate denotes the Teichmüller space of with orientation reversed, which is a more natural way for parametrisation since the boundary component has the opposite orientation from the one given on if we identify them with by dropping the second factor.
Now, let be an atoroidal Haken 3-manifold with non-empty incompressible boundary which does not contain a torus. Suppose that has a convex compact hyperbolic metric , and let be a component of . Take a covering of associated with , and lift the hyperbolic structure to the hyperbolic structure on . It is known (see [16, Proposition 7.1]) that the lifted structure is also convex cocompact, hence can be regarded as an element of . Therefore in turn corresponds to a point in . Let be the components of that are not tori, and we consider the point for each . We define to be . The map taking to is called the skinning map, which we shall denote by .
2.3. Curve complexes and projections
Let be a connected compact orientable surface possibly with boundary, satisfying where denotes the genus and denotes the number of the boundary components. The curve complex of with is a simplicial complex whose vertices are isotopy classes of non-peripheral, non-contractible simple closed curves on such that vertices span an -simplex when they are represented by pairwise disjoint simple closed curves. In the case when , we define to be a graph whose vertices are isotopy classes of simple closed curves such that two vertices have smallest possible intersection. In the case when is an annulus, we define to be a graph whose vertices are isotopy classes (relative to the endpoints) of non-peripheral simple arcs in such that two vertices are connected when they can be represented by arcs which are disjoint at their interiors. Masur-Minsky [11] proved that is Gromov hyperbolic with respect to the path metric for any .
A marking on consists of a pants decomposition of , which is denoted by and whose components are called base curves, and a collection of simple closed curves, called transversals of , such that each component of intersects at most one among them essentially. For two markings on and a subsurface , we define to be the distance between and , where the projection is obtained by taking the intersection of curves on with and connecting the endpoints by arcs on when the intersection contains arcs. In [12], a marking defined as such is called clean. In this paper, we only consider clean markings. A marking is called full when every base curve has a transversal. In general, for two sets of simple closed curves and a subsurface of , we define to be the distance in between and provided that both of them are non-empty. If one of them is empty, the distance is not defined.
For a point in , its shortest marking, which is a full marking and is denoted by , has a shortest pants decomposition of as , and consisting of shortest transversals, one for each component of . When we talk about the distance between two points in or between a point in and a marking, we identify points with .
2.4. Geometric limits and compact cores
Let be an atoroidal boundary-irreducible Haken 3-manifold. Let be a sequence of faithful discrete representations of into . We define a geometric limit of to be a Kleinian group such that every element of is a limit of some sequence , and every convergent sequence has its limit in .
Fixing a point , and considering its projections in and in , the geometric convergence implies the existence of pointed Gromov-Hausdorff convergence of to . This latter convergence means that there exist real numbers going to , converging to , and -bi-Lipschitz diffeomorphisms (called approximate isometries) between -balls and . Suppose that converges to as representations and that converges to geometrically. Then, is a subgroup of the geometric limit .
For an open irreducible 3-manifold with finitely generated fundamental group, a compact 3-dimensional submanifold in is called a compact core when the inclusion induces an isomorphism between their fundamental groups. The existence of compact cores was proved by Scott [19]. The case which interests us is when is a hyperbolic 3-manifold.
Let be a hyperbolic 3-manifold associated with a finitely generated, torsion free Kleinian group . By Margulis’s lemma, there is a positive constant such that the set of points of where the injectivity radii are less than consists of a finite disjoint union of tubular neighbourhoods of closed geodesics of length less than , called Margulis tubes, and cusp neighbourhoods each of which is stabilised by a maximal parabolic subgroup of , and whose quotient by its stabiliser is homeomorphic to when the stabiliser has rank 1, and to when the stabiliser has rank 2. The former cusp neighbourhood is called a -cusp neighbourhood, and the latter a torus cusp neighbourhood. The union of the cusp neighbourhoods is called the cuspidal part of . The complement of the cuspidal part is called the non-cuspidal part and is denoted by . Each boundary component of is either an open annulus or a torus. By the relative compact core theorem by McCullough [13], there is a compact core such that for each boundary component of , the intersection is a core annulus when is an open annulus, and is the entire when is a torus. We call such a compact core a relative compact core of .
Let be the covering map associated with the inclusion of into the geometric limit . Let be a relative compact core of . Suppose that has a torus cusp neighbourhood . We say that wraps around when is homotoped to an immersion which goes around non-trivially, and hence cannot be homotoped to an embedding.
3. Topological features
3.1. Coverings
In this subsection, we shall show that to prove Theorem 1.1, we can put an extra assumption that all the characteristic -pairs of are product bundles.
We consider an atoroidal Haken manifold as is given in Theorem 1.1. Let be a finite-sheeted regular covering. Then induces the covering map between the boundaries . This map induces a proper embedding between Teichmüller spaces, which is obtained by pulling back the conformal structures by . Also the involution lifts to an orientation-reversing involution taking each component to another one. Since is also an atoroidal boundary-irreducible Haken manifold, we can consider the skinning map .
Lemma 3.1.
If has bounded image for some , then so does .
Proof.
The map properly embeds into . By the definition of the maps and , we have , and hence . Therefore, if the image of is bounded, the properness of implies that the image of must also be bounded. ∎
This result allows us to work on manifolds with topological features that will make the arguments simpler.
Lemma 3.2.
Let be an orientable atoroidal Haken manifold with incompressible boundary. Then there is a double covering of all of whose characteristic -pairs are product -bundles.
Proof.
Let be the characteristic -pairs of that are twisted -bundles. Take their double coverings corresponding to the orientation double coverings of the base surfaces. For each among , its frontier components (i.e. the closures of the components of ) are annuli. Each of such annuli has two pre-images in which are taken to each other by the unique non-trivial covering translation.
Let be the closure of a component of . Let be the components of , which are annuli on . We prepare two copies and of . Each among , which is contained some among , has two lifts and in . Now we identify the copy of in to in and the one in to in for each annulus among . We repeat the same procedure for every component of , and get a manifold , which will turn out to be a double cover of as shown below.
Define a homeomorphism to be the covering translation on each and the map taking to preserving the identification with for each of . It is clear from the definition that this homeomorphism is a free involution. By taking the quotient of under , we get a manifold naturally identified with . Thus we see that is a double cover of . Since is a product -bundle and all of the characteristic -pairs contained in are product bundles by our definition of , we see that is a double cover as desired. ∎
For some of our arguments we will need a stronger assumption than having only product bundles:
Definition 3.3.
Let be a compact orientable Haken -manifold with incompressible boundary. We say that is strongly untwisted if and only if:
-
(A)
Every characteristic -pair is a product bundle.
-
(B)
For any characteristic -pair and any simple closed curve , the simple closed curve can be homotoped on into at most one component of .
We are going to construct a cover with the properties (A) and (B) above. In order to do that, we need to examine how characteristic -pairs are attached to other components of the characteristic submanifold. In the following proof of Lemma 3.4, it will turn out that there are two situations ((a) and (b) below) where the second condition of ‘strong untwistedness’ breaks down.
Lemma 3.4.
Let be a compact orientable atoroidal Haken manifold with incompressible boundary. Then there is a finite-sheeted regular covering of which is strongly untwisted.
Proof.
By Lemma 3.2, we have a double covering all of whose characteristic -pairs are product -bundles. Therefore, we may assume that satisfies the first condition (A) of ‘strong untiwistedness’, and we shall construct a covering satisfying the second condition.
To construct such a covering, let us analyse how this second condition (B) can fail to hold. Let be a simple closed curve, and let a characteristic -pair. Since no components of are annuli, can be homotoped on into at most two components of . Furthermore, if can be homotoped into two such components, then lies (up to isotopy on ) on a component (characteristic solid torus or a characteristic thickened torus) of , and there are two possibilities: (a) is an annulus when is a solid torus, and is the union of an annulus and a torus when is a thickened torus; or (b) separates two consecutive components of both lying in the same characteristic -pair. We shall show that we can take a finite-sheeted covering of so that neither (a) nor (b) can happen.
First, we consider the condition (a). Let be a component of such that is an annulus (and is a solid torus) or the union of an annulus and a torus (when is a thickened torus). This implies that is connected, hence is an annulus, which we denote by . Since is a characteristic solid torus or characteristic thickened torus, the annulus is essential, and hence is not homotopic to fixing the boundary. Then, we can choose a simple closed curve , which is not contractible in , on the component of on which lies so that both and are connected, i.e. arcs. Since is either or , we can take a -sheeted cyclic covering of so that cannot be lifted homeomorphically, whereas the annulus is homeomorphically lifted. (For instance, in the case when , we choose which is coprime with the element represented by .) Then the preimage of the annulus is copies of , which we denote by . Let be . We prepare copies of , which we denote by . By pasting along to , we can make a -sheeted cyclic covering of in which does not satisfy the condition (a). If there is another component of with the condition (a), we repeat the same process for all the lifts of at the same time. Repeating the process, we get a finite-sheeted covering of in which there is no characteristic solid torus or a characteristic thickened torus with the condition (a). We use the same symbol and for this finite-sheeted covering, abusing the notation.
Now we turn to the condition (b). We consider three colours named the colour , and and we choose a colour for each annulus of so that, on , no two consecutive annuli have the same colour. We take three copies of each component of and of which we name the lift , and . Consider a component of , a component of and an annulus with the colour . For every , we glue the lift of to the lift mod of along the appropriate lifts of . Using the same construction for each component of , we get a triple cover of in which any two consecutive components of lie in different components of . In particular there is no characteristic solid torus or characteristic thickened torus in for which the condition (b) holds.
Thus, we have shown that by taking a finite-sheeted covering, we can make both of the situations (a) and (b) disappear, which means, as we saw above, that the covering is strongly untwisted. ∎
Lemmas 3.1 and 3.4 show that to prove Theorem 1.1, we have only to consider the case when is strongly untwisted.
3.2. Vertically extendible surfaces
Let be an atoroidal Haken manifold as in Theorem 1.1. Let be the characteristic submanifold of . Assume that every -bundle in is a product -bundle.
Definition 3.5.
Given an incompressible subsurface , we say that is one-time vertically extendible if there is an incompressible surface and an essential -bundle with and up to isotopy. We call a first elevation of .
It follows from the definition of characteristic submanifold that there is an isotopy which takes into the characteristic submanifold . From now on, we assume that if is one-time vertically extendible then and .
We note solid torus
components in
may add some complications in the case when is an annulus.
If is contained in such a component of , there may be more than one possible first elevation (even up to isotopy) and the -bundles corresponding to two disjoint annuli may intersect (even up to isotopy).
We now define multiple elevations by induction.
Definition 3.6.
Given an incompressible subsurface in and , we say that is -time vertically extendible if there is an essential surface and an essential -bundle with and is -time vertically extendible. An -th elevation of is defined to be an -th elevation of .
We say that two multi-curves intersect minimally if for every multicurves homotopic to and respectively, . Let be two incompressible surfaces. We say that and intersect minimally if intersects minimally.
Lemma 3.7.
Let be connected incompressible subsurfaces which intersect minimally and are not disjoint. If and are -time vertically extendible, then so is .
Proof.
If and are one-time vertically extendible, as was remarked before, we may assume that . Since they intersect minimally and are not disjoint, they must lie in the same component of which is not an annulus. Then the component of containing is an -bundle, which is a product -bundle by assumption, and can be parametrised as .
Then, by moving and by isotopies, we have and , and . Since , resp. , lies in the component of which does not contain and , and lie in the same component of . Therefore lies in . Thus we have proved that if and are one-time vertically extendible then is also one-time vertically extendible and is its first elevation.
The case of follows by induction. ∎
Corollary 3.8.
For any natural number , there is an (possibly empty) incompressible surface such that each component of is -time vertically extendible, no component of can be isotoped on into another component of and every -time vertically extendible surface can be isotoped into .
Proof.
If there is no surface that is -time vertically extendible, we set to be . Otherwise, let be an -time vertically extendible incompressible surface. If every -time vertically extendible surface can be isotoped into , we are done, by taking .
Otherwise, there is an -time vertically extendible surface which cannot be isotoped into . Moving by an isotopy we can assume that intersects minimally. By Lemma 3.7, each connected component of is -time vertically extendible, and we replace with , and call this enlarged surface . We repeat this operation as long as there is an -time vertically extendible surface which cannot be isotoped into . Every time we add a surface, either we decrease the Euler characteristic of or we add a disjoint annulus which cannot be isotoped into . Hence this process must terminate after finitely many steps. The final resulting surface is . ∎
Since an -time vertically extendible surface is -vertically extendible for any , we have up to isotopy.
In the next lemma we show that, when is atoroidal, cannot contain an -time extendible surface for sufficiently large . In the last section, this result will lead us to the constant of Theorem 1.1.
Lemma 3.9.
There is depending only on the topological type of such that if there is an -time vertically extendible surface, then is not atoroidal.
Proof.
Letting denote the genus of , we set , which is the number of curves in a pants decomposition of . Since no components of can be isotoped into another component, has at most boundary components. Using this observation, we show in the following claim that must be a proper subsurface of even up to isotopy.
Claim 3.10.
For any , if is non-empty and any component of can be isotoped into , then cannot be atoroidal.
Proof.
Suppose that , and that any component of can be isotoped into . Since is contained in for any up to isotopy as observed above, and no component of can be isotoped into another component, we have then for any up to isotopy. Let be a component of with minimal Euler characteristic, and its -th elevation. By definition, is -time vertically extendible for any . Therefore can be isotoped into . Since and has minimal Euler characteristic, is a component of , up to isotopy. In particular up to isotopy.
Let be the -bundle cobounded by and . We note that by definition, and are identified in and that the interior of is embedded in . Taking the union of the -bundles in for , we get a map such that is sent to . Let be a component of . The image of the annulus goes times through . Since has at most components, there is a component of through which goes at least twice. The image of the part of this annulus between two such instances forms a torus embedded in . Considering the component of through which goes, we can construct an infinite cyclic covering of in which lifts to an infinite incompressible annulus. It follows that is incompressible and non-peripheral. Hence is not atoroidal. ∎
As mentioned before, we have for any . Consider monotone increasing indices such that is smaller than in the sense that at least one component of cannot be isotoped into . Since no component of can be isotoped into another component, we have then either or has fewer connected components than . It follows that there are at most such , namely, there is such that for any , we have . By Claim 3.10, if for some or if , then is not atoroidal. Since , we can now conclude the proof just by setting . ∎
4. Convergence, divergence and subsurface projections
In this section, we shall review the relations between the invariant mentioned in the introduction and the convergence and divergence of Fuchsian and Kleinian groups.
4.1. Subsurface projections and Fuchsian groups
We first recall the definition of the invariant from [2], and see how it controls the behaviour of sequences of Fuchsian groups.
Definition 4.1.
Let be a (possibly disconnected) closed surface of genus at least and a point in its Teichmüller space. Regarding as a hyperbolic structure on , we let be a shortest marking for (See Section 2.3). Although there might be more than one shortest markings, its choice does not matter for our definition and arguments. We fix a full and clean marking consisting of a pants decomposition and transversals on independent of . For any essential simple closed curve on , we define
where the supremum of the first term in the maximum is taken over all incompressible subsurfaces of whose boundaries contain .
It follows from [2, Lemma 5.2] that two curves with unbounded cannot intersect:
Lemma 4.2.
Let be a sequence in and let be simple closed curve on . If for both , then .
Proof.
This is just a special case of [2, Lemma 5.2] for Fuchisan groups. We note that the assumption of bounded projections of end invariants is unnecessary in this special case for which end invariants are empty. ∎
The invariant is related to the divergence and convergence of a sequence by the following lemma:
Lemma 4.3.
Let be a full marking on , and let be a sequence in . Then every subsequence of contains a convergent subsequence if and only if is bounded for every essential simple closed curve on .
Proof.
Let be a shortest marking for . It follows from classical results on Fenchel-Nielsen coordinates that any subsequence of contains a converging subsequence if and only if the sequence is a finite set and is bounded. By [2, Lemma 2.3], the sequence is infinite if and only if passing to a subsequence, there is an incompressible subsurface such that (and hence for any component of ).
On the other hand, if the sequence is constant, then is unbounded if and only if passing to a subsequence, there is a curve with (and hence ). ∎
4.2. Relative convergence of Kleinian groups
We shall next establish a necessary condition on the invariant for algebraic convergence on a submanifold. We start with a fundamental result. Thurston proved in [23] the following which is the first half of the theorem often referred to as the ‘broken window only’ theorem. We note that the latter half of the broken window only theorem should need some rectification (see [17]) but is irrelevant to the present paper.
Theorem 4.4.
Let be an atoroidal Haken 3-manifold and its characteristic submanifold. Then for any curve in and any sequence , the length of the closed geodesic in representing the free homotopy class of is bounded as .
Using arguments from [2], we establish the following necessary condition for algebraic convergence on a submanifold.
Theorem 4.5.
Let be an atoroidal Haken boundary-irreducible -manifold all of whose characteristic -pairs are product -bundles. Let be a sequence in , and a sequence of representations corresponding to . Let be a full and clean marking, and a submanifold with ‘paring locus’ which is a union of disjoint non-parallel essential annuli on . We assume the following:
-
(a)
The closure of is a union of essential annuli contained in .
-
(b)
For any non-contractible simple closed curve in , is bounded as .
-
(c)
For any essential annulus disjoint from , there is a component of such that is bounded for the component of on which lies.
-
(d)
If is an -bundle, then .
Then the sequence of the restrictions has a convergent subsequence up to conjugation.
Proof.
We follow the argument of [2, Proposition 6.1] with some modifications as below. Denote by a shortest pants decomposition of with respect to . Note that is bounded for any essential subsurface that is not an annulus with its core curve in if and only if so is . Let be a multicurve consisting of core curves of , one taken from each component of . We define to be empty if is empty. Let be the characteristic submanifold of . Consider a multicurve of containing which is maximal in the sense that any simple closed curve in either intersects or is homotopic on to a component of . By our assumption (b) and Theorem 4.4, there is such that .
Let be the union of the characteristic -pairs in . By assumption, is a product -bundle in the form ( may be disconnected). We denote by the projection along the fibres, and for a subsurface and for , we use the symbol to denote . For each component of that is not a pair of pants, by the assumption (c), there is such that is bounded. Let be the component of containing , and denote by the representation induced by the inclusion . The quotient manifold covers , and has end invariant on one side. Now, replacing with , we can follow the proof of [2, Lemma 6.2] starting at the penultimate paragraph. This gives us a constant and a sequence of curve on such that and is bounded.
Up to isotopy, consists of boundary components of . We denote by . Still following [2], if has a constant subsequence, then we pass to an appropriate subsequence of , and add (independent of ) to . If not, by [2, Lemma 2.3], there is a subsurface with , passing to a subsequence. Since and are bounded, must be a proper subsurface of (even up to isotopy). If, passing to a subsequence, there is such that is an annulus containing a component of for all , we add the projection by of this component of to . Otherwise, by the assumption (c), there exists with bounded . Hence, passing to a subsequence, , and by [15, Theorem B], . In this case, we add to . We repeat the above construction letting be a component of until becomes a union of annuli and pair of pants. Adding to , we obtain a pants decomposition of , which we shall still denote by , such that is bounded.
Next we attach a transversal with bounded length to each component of . Let be a curve in , by the assumption (c), there is such that is bounded, where . We replace with a shortest pants decomposition not containing . Since is bounded, there is a positive lower bound on }, and there is an upper bound on by our definition of . Considering the covering associated with the inclusion we can use the arguments of [2] (proof of Proposition 6.1, the part after the proof of Lemma 6.2) to obtain a transversal to with bounded length .
5. Unbounded skinning and annuli
The following proposition is the main step of our proof of Theorem 1.1.
Proposition 5.1.
Let be an orientable atoroidal boundary-irreducible Haken -manifold that is strongly untwisted. Let be a sequence in , let be the skinning map, and assume that there is a simple closed curve on such that for a full clean marking . Then, passing to a subsequence, there is a properly embedded essential annulus with such that .
We are going to show that any subsequence of contains a further subsequence for which the conclusion holds. To simplify the notations we shall use the same subscript for all subsequences.
5.1. Re-marking
Our manifold is either connected or has two components. In the case when has two components, by considering the component on which lies, and abusing the symbol to denote this component, we can assume that is connected. Recall that, by the assumption throughout this section, is strongly untwisted. Let be a representation corresponding to .
As a first step for the proof of Proposition 5.1, we change the markings of so that the behaviour of the can be read more easily from the behaviour of their end invariants.
Lemma 5.2.
Let be an essential simple closed curve on , and let be disjoint simple closed curves on representing the homotopy classes of simple closed curves on homotopic to in , where . Furthermore, we assume that
-
(*)
is bounded for every .
Then there is a sequence of orientation-preserving homeomorphisms such that, passing to a subsequence, the following hold:
-
(1)
For any essential simple closed curve , either is bounded or ,.
-
(2)
If is an essential annulus disjoint from all the such that for both boundary components and of , then .
-
(3)
For every among defined above,
-
(i)
for every and ,
-
(ii)
for every , is bounded if and only if is bounded, and
-
(iii)
is bounded if and only if is bounded.
-
(i)
Proof.
We shall first define the homeomorphisms , and then verify the desired properties. Let be a component of the characteristic submanifold of . Suppose first that is a solid torus. The components of are incompressible annuli. We define on soid-torus components of to be a composition of Dehn twists along these frontier annuli with the following properties:
-
(a)
If is a solid torus, then is constant with respect to for every component of except for at most one.
By the assumption (*), passing to a subsequence, we need not compose Dehn twists along annuli of the frontier components of to achieve the condition (a) when contains an annular neighbourhood of (up to isotopy), and hence , as defined for the moment, also satisfies the following:
-
(b)
For every , we have and for an annulus on whose core curve is .
If is not a solid torus, is a product . (Recall that we have an assumption that every characteristic -pair of is a product bundle. This implies that an -pair in the characteristic submanifold of is also a product -bundle.) Let be a component of which does not contain a curve homotopic on to (there is always such a component since is strongly untwisted). Since the curve complex of has finitely many orbits under the action of the mapping class group of (relative to ), there is a sequence of orientation-preserving homeomorphisms fixing such that, passing to a subsequence, is constant. We then define on by extending along the fibres, i.e. for any .
Thus we have the following.
-
(c)
there are and a component of not containing any curve homotopic on to such that for any incompressible subsurface .
We note that since is a component of the characteristic submanifold of , if contains a curve , then it must be peripheral, and hence the action of on does not affect the property (b).
We repeat the construction above for all the components of the characteristic submanifold , and we extend the resulting homeomorphisms to a homeomorphism of which is isotopic to the identity on the complement of the characteristic submanifold.
The first property (1) can be obtained by passing to a subsequence for any sequence of homeomorphisms. Therefore, we are done with (1).
We next turn to proving the property (3). By the assumption (*), taking a subsequence, we may assume that is constant whenever is an annulus containing a curve for . Wet first show the following claim.
Claim 5.3.
For every and for any sequence of incompressible subsurfaces with its boundary containing which are not a pair of pants, is bounded.
Proof.
Fix , and consider a sequence of incompressible subsurfaces each of which contains in its boundary. If all of the are annulli after passing to a subsequence, the conclusion follows from the property (b). From now on, taking a subsequence, we assume that none of the are annuli.
Assume first that there is a simple closed curve intersecting which lies outside the characteristic submanifold . Then by our construction of , we have , and hence
where the last inequality is due to Masur–Minsky [11, Lemma 2.1]. Thus we are done in this case.
Otherwise, taking a subsequence, we may assume that is contained in for a component of the characteristic submanifold . Taking a further subsequence, we may assume that does not depend on . Since is not an annulus, is a product -pair . Let be the component of given by the property (c). Let us denote by the projection of to along the fibres, (setting if ). By our definition of , the boundary of contains some with . Then, is bounded by the assumption (*), and by the property (b). In particular is bounded. On the other hand, by the property (c), is bounded. Thus we see that is bounded. It follows from the construction of that , and hence is also bounded. ∎
Now we can show that the sequence satisfies the property (3) by the condition (*) and the following claim.
Claim 5.4.
For any , the sequence is bounded if and only if is bounded, and is bounded if and only if is bounded.
Proof.
Let be a sequence of incompressible subsurfaces with which are not pairs of pants. Since , the triangle inequalities
lead to
Thus by applying Claim 5.3, we see that is bounded if and only if is bounded.
Since by the property (b), we also have , and we conclude that is bounded if and only if is bounded.
Since commutes with , the same argument shows that that is bounded if and only if is bounded. ∎
To conclude the proof of Lemma 5.2, it remains to establish the property (2). We restate the property as a claim.
Claim 5.5.
Let be an essential annulus with its boundary components denoted by and . Suppose that for both and . Then .
Proof.
Let be homotopically distinct simple closed curves on representing all the homotopy classes (in ) homotopic to in . By renumbering them, we can assume for . If for some , we are done.
To deal with the remaining case, we now assume that there is a positive constant such that for every and . Then, there are a constant and simple closed curves for every and such that intersects essentially and . There is also such that for any and any incompressible subsurface intersecting that is neither an annulus nor a pair of pants, since by definition, the length of is also bounded from above by a constant.
Since and for , there are incompressible subsurfaces such that and for . If, passing to a subsequence, and are both annuli, then, up to homotopy, they lie on the boundary of the same component of the characteristic submanifold (which is, up to passing to a further subsequence independent of ). However, the assumption that contradicts (a) when is a solid torus, and (c) when is an -pair. Therefore, we can assume that one of the , say is not an annulus.
Suppose now that is not eventually contained in the characteristic submanifold (up to homotopy), even after passing to a subsequence. By taking a subsequence, we can assume that none of the are contained in . Then, there is a simple closed curve disjoint from which intersects for all , by passing to a further subsequence. By Theorem 4.4 there is a constant such that . Since by our assumption, we have . Then it follows from [15, Theorem B] that , and hence in particular, we have .
Next suppose that eventually lies in . Taking a subsequence, we can assume that all the surfaces lie in the same component of . Since is not an annulus, must be an -bundle, which has a form of . By (c), there is another surface such that and bound an -bundle compatible with the -bundle structure of , and are projected along the fibres of to the same surface in and . We note that by our definition of , there is such that lies on . Then since , we have . We shall make use of and to apply [15, Theorem B] as before. Since they do not lie on the same surface, we first need to project them to . This leads to the following claim:
Claim 5.6.
There are and two sequences of simple closed curves and on such that for all and , and .
Proof.
Let be either or . If is contained in for sufficiently large , then we let be the projection of to . We also note that then.
Suppose that this is not the case. We let be the component of containing . Following [15, page 138] we extend the multicurve to a complete geodesic lamination by performing Dehn twists around infinitely many times to and adding finitely many isolated leaves spiralling around . There is a unique pleated surface realising which induces between the fundamental groups. Let be the -thick part of with respect to the hyperbolic metric induced by . By the efficiency of pleated surfaces ([22, Theorem 3.3], [15, Theorem 3.5]), there is a constant such that (the relation between the alternation and intersection numbers comes from (4.3) in [15]). In particular, there is an arc in intersecting and having length at most . By Theorem 4.4, the length of each component of on is bounded by a constant independent of . By joining one or two copies of (depending on whether intersects one or two components of ) with arcs on , we can construct in a simple closed curve such that . Furthermore, this construction implies that there is a constant such that for any incompressible subsurface intersecting both and , and in particular for . We use the same symbol to denote the projection of on along the fibres of .
Thus we have and . ∎
Continuation of Proof of 5.5. Set where is the homomorphism induced by the inclusion. Following [15], we denote by the set of simple closed curves on whose translation lengths with respect to are less than or equal to . By the claim above, we see that both and lie in and that . In particular, . It follows from [15, Theorem B] that . In particular, , and hence . ∎
This also concludes the proof of Lemma 5.2. ∎
5.2. End invariants and wrapping
In this subsection, we shall discuss how algebraic limits projects to geometric limits and how this is reflected in the behaviour of the end invariants.
Let us now fix the assumptions and notations which will be used in most results of this section.
Setting 5.7.
We consider an orientable atoroidal compact boundary-irreducible Haken -manifold without torus boundary components, and a sequence of representations corresponding to Ahlfors-Bers coordinates . We have a non-contractible simple closed curve , and we denote by simple closed curves representing all homotopy classes of on which are homotopic to in , with . We assume that .
We also assume that we have a submanifold of whose frontier consists of incompressible annuli and which has the following three properties:
-
(i)
contains all the curves , and is not peripheral in for every .
-
(ii)
The restriction of to converges to a representation .
-
(iii)
If is an essential annulus disjoint from with core curve which is not homotopic to in , then if and only if is properly homotopic to the closure of a component of .
Suppose first . If a component of the characteristic submanifold containing (up to isotopy) is a solid torus, then it contains all of up to isotopy. We let be this characteristic solid torus in this case. If the component is an -pair, then , and it contains up to isotopy. In this case, we let be such that is an annular neighbourhood of whereas is that of . Since consists of annuli, by the condition (i) above, can be assumed to be contained in by moving it by an isotopy in both cases. If , we set .
Given , we denote by the component of containing .
The sequence of groups converges geometrically to a Kleinian group containing , passing to a subsequence.
In the next section, we shall construct having the properties above, which shows that our argument in the present section really works.
Assuming the existence of for the moment, we now prove that every component of has a compact core which is embedded in the geometric limit making use of the work of [4].
Lemma 5.8.
In 5.7, let be a submanifold of which is the closure of a component of . Then there is a relative compact core which is homeomorphic to and on which the restriction of the covering projection induced by the inclusion is injective. Furthermore, for the closures of two components of (in the case when is non-empty and separates ), the compact cores and can be taken so that their images in are disjoint.
Proof.
Our conditions in 5.7 imply the assumptions of [4, Proposition 4.4], and applying this proposition, we see that there is a compact submanifold of which lifts to a compact core of such that the restriction of the covering projection to is injective. Let be the geometric limit of . Then the restriction of the covering projection to must also be injective.
We next show that by performing Dehn twists along embedded annuli bounded by and , we can make each embedded in the algebraic limit and mapped injectively in the geometric limit by the covering projection.
In the next lemma and the following, we shall use the expression ‘the outward side of a cusp’. We say that an embedding of the surface into the geometric limit lies on the outward side of a cusp if the cusp lies on the same side of the embedding of as the embeddings of the components of intersecting . Otherwise we say that the embedding of lies on the inward side of the cusp.
Lemma 5.9.
In 5.7, we denote by the right-hand Dehn twist along an embedded annulus bounded by and (). Then for each , there is a sequence of integers with the following properties:
-
–
The sequence converges algebraically to a representation .
-
–
There is an embedding inducing such that the restriction of the covering projection to is an embedding and its image lies on the outward side of the cusp corresponding to when the latter is a rank-2 cusp.
Proof.
This is a relative version of [2, Lemma 4.5].
Let and be the components of intersecting (we set if there is only one such component), and set and . By Lemma 5.8, there are compact cores and , homeomorphic to and respectively, on which the restrictions of the covering projections to are injective. The inclusions induce embeddings and which lift to embeddings and . The restrictions of the covering projection to and to are embeddings.
If does not separate , we set , otherwise, we put and together to get an embedding . Moving , and by isotopies, we may assume that they send the boundary of into the -thin part. Then for an appropriate choice of , the map sends the boundary of to the boundary of the -thin part of , where is smaller than the three-dimensional Margulis constant. It is then easy to extend to an embedding such that lies on the boundary of the -thin part with . By Lemma 5.8 and by our construction, the restriction of to , which is , is an embedding and with an appropriate choice of , the composition maps to the boundary of the -thin part of .
If belongs to a rank- maximal parabolic subgroup of , then it is easy to change on so that is an embedding. In this case, we simply take to be .
Otherwise, belongs to a rank- maximal parabolic subgroup of . We denote by the boundary of the corresponding torus cusp-neighbourhood in , i.e. the boundary of the corresponding component of the -thin part. Let be the union of and . Then is contained in by our way of extending to as described above. As is explained in [2, Lemma 3.1], is homotopic to a standard map wrapping times around for some , and there are two standard embeddings such that lies on the outward side of the cusp associated with and lies on its inward side, both without wrapping around .
Let be a sequence of -bi-Lipschitz approximate isometry on the -ball with given by the geometric convergence as explained in Section 2.4. By [2, Lemma 3.1], there is such that is homotopic to . The conclusion follows, taking and setting to be the lift of to . ∎
Next we study how the embedding of a compact core in the geometric limit as above affects the end invariants.
Lemma 5.10.
In 5.7, for each , suppose that there is an embedding inducing such that the restriction of the covering projection to is an embedding.
If lies on the outward side of the cusp associated with , then is bounded whereas . If lies on the inward side of the cusp associated with then is bounded whereas .
Proof.
Suppose that lies on the outward side of the cusp associated with . Let be a simple closed curve intersecting essentially, the closed geodesic homotopic to , and denote by an approximate isometry associated with the geometric convergence of to as explained in Section 2.4. For large enough, is a quasi-geodesic lying outside the thin part. on the same side as of the Margulis tube associated with . Let be the component of containing . In the covering of , the closed geodesic homotopic to lies above the Margulis tube associated with . Therefore, by [3, Theorem 1.3] there is a constant such that for any surface with . Thus for any full marking , there is such that for any surface with .
To conclude that is bounded, it remains to show that is bounded away from . Assume the contrary, that after passing to a subsequence. Then, there is an annulus joining the closed geodesic representing with corresponding to , which lies entirely in the -thin part with . Since has bounded length, it cannot intersect such an annulus, whereas lies in a uniformly bounded neighbourhood of the convex core for large . Since and lie on the same side of the cusp associated with , this contradicts the assumption that lies on the outward side of the cusp associated with .
Since and is bounded, it follows from [14, Short Curve Theorem] that .
A quite similar argument works also when lies on the inward side of the cusp associated with . ∎
Corollary 5.11.
In 5.7, assume that , and consider such that is bounded. Then there is an embedding inducing such that the restriction of the covering projection to is an embedding whose image lies on the outward side of the cusp corresponding to .
Proof.
As can be seen in the proof of Lemma 5.9, if belongs to a rank- maximal parabolic subgroup of , then for any and . Therefore, our claim of this corollary follows immediately from Lemmas 5.9 and 5.10.
Otherwise, belongs to a rank- maximal parabolic subgroup of . By Lemma 5.9, there is a sequence of integers and an embedding inducing between the fundamental groups such that the restriction of the covering projection to is an embedding and its image lies on the outward side of the cusp corresponding to . By Lemma 5.10, is bounded. Since is bounded by assumption, this is possible only when is bounded. Then we may take for any in Lemma 5.9 so that , and the conclusion follows. ∎
We now put these results together to get the result which we shall use to prove Proposition 5.1.
Lemma 5.12.
In 5.7, suppose that is bounded for . Then, there is a relative compact core for homeomorphic to on which the restriction of the covering projection is injective. Furthermore, a cusp neighbourhood corresponding to intersects the compact core in an annular neighbourhood of .
Proof.
By Lemma 5.8, for the components of , we have embeddings inducing , on the union of which the restriction of is injective.
If , then by definition, and hence . We can take a cusp neighbourhood corresponding to intersecting along an annulus in the homotopy class of . Since , such an annulus is isotopic on to an annular neighbourhood of .
Suppose that , and assume that is bounded for every . Then by Corollary 5.11, for every , there is an embedding inducing on which the restriction of is injective. Furthermore, it follows from the construction that and agree on . Putting together the maps for all the components of and the for all , we get an embedding inducing on which the restriction of is injective.
Changing by an isotopy, we may assume that intersects a cusp neighbourhood associated with along an annulus which is a regular neighbourhood of for some . Then lies on the inward side of . This is possible only if lies on the inward side of ; for the restriction of is injective on , and hence it cannot wrap around .
By assumption, for every , is bounded. It follows then from Corollary 5.11 that lies on the outward side of for . Hence the only possibility is that is a regular neighbourhood of . ∎
5.3. Completion of the proof of Proposition 5.1
Proof of Proposition 5.1.
If is an -bundle, then and the conclusion follows. In the other cases, we shall prove the proposition by contradiction. Assume that is not an -bundle, that , and that is bounded for every .
By Lemma 5.2, after re-marking and passing to a subsequence, we may assume that satisfies:
-
(1)
for any simple closed curve , either (resp. ) is bounded or (resp. );
-
(2)
if is an essential annulus such that does not intersect (hence any of ) and for both boundary components and of , then .
We note that by Lemma 5.2, is bounded for every and even after re-marking.
Taking a further subsequence, we can also assume that for any essential annulus of , either or is bounded away from . Let be a maximal family of pairwise disjoint non-isotopic essential annuli such that
-
[i]
the length of the core curve of each annulus tends to ( for any ),
-
[ii]
does not intersect , and
-
[iii]
no component of contains a curve homotopic to .
Denote by the component of containing , where denotes a thin regular neighbourhood of . Let be the closure of , which is a union of annuli. Next we shall control the geometry of and the length of .
Claim 5.13.
Passing to a subsequence, the restrictions converge and .
Proof.
Let us first assume that , and verify the hypotheses of Theorem 4.5 with . The hypothesis (a) follows from the construction of . The hypothesis (b) follows from the property (2) above. By Lemma 4.2, is bounded for any simple closed curve intersecting . This observation combined with the assumption that is bounded for any , the property (2) above and the maximality of yields the hypothesis (c). Now by Theorem 4.5 we can take a subsequence in such a way that the restrictions converge.
If , we are done. Otherwise, since we are assuming that , there is a sequence of subsurfaces such that and . Consider a simple closed curve intersecting . Since converges, is bounded. Then we have (for ) and it follows from [15, Theorem 2.5] that .
Suppose now that is bounded. Since by assumption, by [14, Short Curve Theorem]. We add to a thin regular neighbourhood of on and we can verify as above that the hypotheses of Theorem 4.5 are satisfied for . ∎
Now we are in the situation of 5.7, and we use its notations. By Lemma 5.12, lies on the inward side of the cusp corresponding to , and lies on the outward side for every . Then Lemma 5.10 implies that is bounded. This contradicts our assumption. ∎
6. The proof of Theorem 1.1
Now we shall complete the proof of Theorem 1.1. By Lemmas 3.1 and 3.4, we can assume that every is strongly untwisted. Let be the number provided by Lemma 3.9, and consider a sequence such that has no convergent subsequence. By Lemma 4.3, passing to a subsequence, there is a simple closed curve such that . Then we have . By Proposition 5.1, passing to a further subsequence, there is an incompressible annulus bounded by and another simple closed curve with . Repeating this, we get a family of simple closed curves such that bounds an incompressible annulus. This means that an annular neighbourhood of is -time vertically extendible, contradicting Lemma 3.9. This completes the proof of Theorem 1.1.
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