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Violation of Svetlichny’s inequality in a system of spins jj

Yang Xiang xiangyang@vip.henu.edu.cn (corresponding author) School of Physics and Electronics, Henan University, Kaifeng, Henan 475004, China    Yuan Tao taoyuan012@outlook.com School of Physics and Electronics, Henan University, Kaifeng, Henan 475004, China
Abstract

Quantum multi-particle correlations are one of the most intriguing properties of quantum entanglement, arising from collective entangled states of multiple particles. Svetlichny’s inequality (SI) was the first method proposed to test the existence of such correlations. Previous studies have primarily focused on 1/21/2-spin particle systems. In this paper, we present a unified scheme that enables the violation of SI in arbitrary non-zero spin particle systems. Specifically, for all fermion systems, our scheme achieves the maximal quantum violation of SI for any number of particles. For boson systems, when the particle spin j2j\geq 2, our scheme consistently realizes the violation of SI for any number of particles. When the particle spin j=1j=1, our scheme can yield SI violation for up to 77 particles. Furthermore, as the particle spin jj approaches infinity, our scheme achieves the maximal quantum violation of SI. To obtain these results, we also prove that the upper bound of Svetlichny’s operator within the framework of local hidden variable theory is 2N+1\sqrt{2^{N+1}}. These findings not only enhance our understanding of quantum correlations across various particle systems but also provide valuable insights for the development of quantum communication protocols that utilize entanglement and non-locality in multi-particle configurations.

quantum multi-particle correlations, Svetlichny’s inequality, local hidden variable theory
pacs:
03.65.Ud, 03.65.Ta, 03.67.-a

I Introduction

Quantum correlations are one of the most peculiar properties of quantum mechanics, which overturn classical epistemology based on local hidden variable theories. The violation of Bell’s inequality [1, 2, 3] demonstrates that quantum correlations surpass the correlation strength predicted by local hidden variable theories. Beyond two-particle quantum correlations, even more intriguing are multiparticle quantum correlations [4, 5, 6, 7, 8, 9, 10]. These correlations arise from multiple particles being in a collectively entangled quantum state, and thus they are not produced by the sharing of so-called local hidden variables among the particles, nor are they the result of the superposition of correlations from a subset of the particles; instead, they represent a genuine collective correlation effect involving all particles. This multi-particle quantum correlation leads to a richer array of non-classical phenomena in the measurement outcomes among particles [11, 12, 13]. Such phenomena not only challenge our traditional understanding of locality but also provide a foundation for numerous applications in quantum information science, such as quantum computing, quantum communication, and quantum key distribution [14, 15, 16, 17, 18, 19, 20].

Unlike Bell’s inequalities, Svetlichny’s inequality (SI) [21, 22] is specifically designed for systems involving three or more particles and was the first method proposed to detect the existence of genuine multi-particle collective correlations. Even if there are correlations among some particles, or even correlations that exceed the strength of quantum correlations, SI will not be violated unless there are genuine multi-particle collective correlations present. The violation of SI indicates that the system exhibits true quantum entanglement. For instance, in a Greenberger-Horne-Zeilinger (GHZ) state, the inequality can be violated, thereby revealing the presence of genuine multi-particle quantum correlations [21, 23, 24]. SI has significant implications for quantum information science, including quantum communication and cryptography, as it aids in understanding how entanglement can be utilized for secure information transfer and in the advancement of quantum technologies [25, 26, 27].

In studies of Bell’s inequality and SI, researchers typically focus on 1/21/2-spin particle systems due to the binary nature of the measurement outcomes [9, 10]. This choice simplifies the theoretical model design and facilitates the observation of quantum correlations. However, for arbitrary spin particle systems, the design of quantum states and measurements that can achieve maximal violations of Bell’s inequality and SI presents an intriguing and compelling theoretical challenge. While significant progress has been made in achieving violations of Bell’s inequality in systems with arbitrary spin [28, 29, 30, 31, 32, 33, 34], there has yet to be a dedicated examination of how to design quantum states and measurements for arbitrary spin particle systems to realize violations of SI. Therefore, our work aims to address this gap by exploring methods to achieve violations of SI in systems with various spins.

This research presents a unified scheme that enables the violation of SI in arbitrary non-zero spin particle systems. For all fermion systems, our scheme achieves the maximal quantum violation of SI for any number of particles. In the case of boson systems, when the particle spin j2j\geq 2, our scheme consistently realizes the violation of SI for any number of particles. For boson systems with particle spin j=1j=1, our scheme can yield SI violation for up to 77 particles. Furthermore, as the particle spin jj approaches infinity, our scheme achieves the maximal quantum violation of SI. To obtain these results, we also prove that the upper bound of Svetlichny’s operator within the framework of local hidden variable theory is 2N+1\sqrt{2^{N+1}}. Our findings not only expand the understanding of genuine multi-particle quantum correlations but also provide new insights for applications of multi-particle entanglement and non-locality in quantum information science, particularly in how various spin particle systems can be utilized to achieve specific quantum communication and computational tasks.

II The violation of three-particle SI in a system of spins jj

Let us assume that Alice, Bob, and Carol each share one particle, and that each of them can choose from two possible measurements. We use A^0\hat{A}_{0} and A^1\hat{A}_{1} to represent the measurements Alice can make, and similarly, B^0\hat{B}_{0} and B^1\hat{B}_{1} for Bob, and C^0\hat{C}_{0} and C^1\hat{C}_{1} for Carol. All of these measurements can yield values of either 1-1 or +1+1. The three-particle SI is used to detect collective correlations between the outcomes of three-particle measurements and can be expressed in the following form

|S3|=|A0B0C0+A0B0C1+A0B1C0\displaystyle\left|\langle S_{3}\rangle\right|=\big{|}\langle A_{0}B_{0}C_{0}\rangle+\langle A_{0}B_{0}C_{1}\rangle+\langle A_{0}B_{1}C_{0}\rangle
+A1B0C0A0B1C1A1B0C1A1B1C0\displaystyle+\langle A_{1}B_{0}C_{0}\rangle-\langle A_{0}B_{1}C_{1}\rangle-\langle A_{1}B_{0}C_{1}\rangle-\langle A_{1}B_{1}C_{0}\rangle
A1B1C1|4,\displaystyle-\langle A_{1}B_{1}C_{1}\rangle\big{|}\leq 4, (1)

where A0A_{0} and A1A_{1} are Alice’s outcomes for corresponding measurements A^0\hat{A}_{0} and A^1\hat{A}_{1}, and similarly B0B_{0} and B1B_{1} (C0C_{0} and C1C_{1}) for Bob’s (Carol’s), and all AiBjCk\langle A_{i}B_{j}C_{k}\rangle’s represent average values of AiBjCkA_{i}B_{j}C_{k}’s. If one chooses a 3-particle system in a GHZ state and applies an appropriate measurement protocol, one can achieve the maximal quantum violation of 424\sqrt{2} [21].

In traditional SI (and Bell’s inequality), 1/21/2-spin particles are typically employed, with A^i\hat{A}_{i}, B^j\hat{B}_{j}, and C^k\hat{C}_{k} representing operators that measure spin in specific directions. The measurement outcomes are thus precisely 1-1 or +1+1. To investigate SI violations involving arbitrary bosons (j1j\geq 1) and fermions, we must first construct operators for particles with arbitrary spin jj. Additionally, we need to ensure that these operators are Hermitian and that their eigenvalues are restricted to 1-1 or +1+1.

Inspired by the work of Peruzzo and Sorella [33], we define the operators A^i\hat{A}_{i}, B^j\hat{B}_{j}, and C^k\hat{C}_{k} as follows. Let {|m;jmj}\{\left|m\right\rangle;-j\leq m\leq j\} represent an orthonormal basis that spans the Hilbert space of a particle with spin jj. These states {|m}\{\left|m\right\rangle\} can serve as eigenstates of a spin operator in any direction. We can define A^i\hat{A}_{i}, B^j\hat{B}_{j}, and C^k\hat{C}_{k} based on their action on the basis {|m;jmj}\{\left|m\right\rangle;-j\leq m\leq j\}:

A^i|m=ei(αi)m|m,(αi)m=(αi)m,i=0,1\displaystyle\hat{A}_{i}\left|m\right\rangle=e^{i(\alpha_{i})_{m}}\left|-m\right\rangle,~{}~{}(\alpha_{i})_{-m}=-(\alpha_{i})_{m},~{}~{}i=0,1
B^i|m=ei(βi)m|m,(βi)m=(βi)m,i=0,1\displaystyle\hat{B}_{i}\left|m\right\rangle=e^{i(\beta_{i})_{m}}\left|-m\right\rangle,~{}~{}(\beta_{i})_{-m}=-(\beta_{i})_{m},~{}~{}i=0,1
C^i|m=ei(γi)m|m,(γi)m=(γi)m,i=0,1.\displaystyle\hat{C}_{i}\left|m\right\rangle=e^{i(\gamma_{i})_{m}}\left|-m\right\rangle,~{}~{}(\gamma_{i})_{-m}=-(\gamma_{i})_{m},~{}~{}i=0,1. (2)

The quantities (αi)m(\alpha_{i})_{m}, (βi)m(\beta_{i})_{m}, and (γi)m(\gamma_{i})_{m} are real numbers, and we refer to them as the ‘phases’ of the corresponding operators. Later, we will prove that the conditions (αi)m=(αi)m(\alpha_{i})_{-m}=-(\alpha_{i})_{m} and similar relations are necessary to guarantee the Hermitian properties of the operators. For the case where the spin jj is an integer, we will focus on the phases (αi)0(\alpha_{i})_{0}, (βi)0(\beta_{i})_{0}, and (γi)0(\gamma_{i})_{0}, and show that these phases can only take values of 0 or π\pi in order to ensure the Hermitian nature of the operators. In the following, we take the operator C^i\hat{C}_{i} as an example to demonstrate that when the condition (γi)m=(γi)m(\gamma_{i})_{-m}=-(\gamma_{i})_{m} is satisfied, and (γi)0(\gamma_{i})_{0} can only take the values 0 or π\pi, C^i\hat{C}_{i} is a Hermitian operator and C^i2=I\hat{C}_{i}^{2}=I.

To prove that C^i\hat{C}_{i} is a Hermitian operator, it is sufficient to show that the matrix elements of C^i\hat{C}_{i} and C^i\hat{C}_{i}^{\dagger} in the {|m}\{\left|m\right\rangle\} representation satisfy the relation m|C^i|n=m|C^i|n\left\langle m\right|\hat{C}_{i}^{\dagger}\left|n\right\rangle=\left\langle m\right|\hat{C}_{i}\left|n\right\rangle. If both mm and nn are non-zero, it is easy to prove the above equation using condition (γi)m=(γi)m(\gamma_{i})_{-m}=-(\gamma_{i})_{m},

m|C^i|n\displaystyle\left\langle m\right|\hat{C}_{i}^{\dagger}\left|n\right\rangle =\displaystyle= (n|C^i|m)\displaystyle\left(\left\langle n\right|\hat{C}_{i}\left|m\right\rangle\right)^{\ast} (3)
=\displaystyle= (ei(γi)mn|m)\displaystyle\left(e^{i(\gamma_{i})_{m}}\left\langle n|-m\right\rangle\right)^{\ast}
=\displaystyle= ei(γi)mδn,m\displaystyle e^{-i(\gamma_{i})_{m}}\delta_{n,-m}
=\displaystyle= ei(γi)nδn,m\displaystyle e^{i(\gamma_{i})_{n}}\delta_{-n,m}
=\displaystyle= m|C^i|n.\displaystyle\left\langle m\right|\hat{C}_{i}\left|n\right\rangle.

For the case where the spin jj is an integer, we need to show that the following three equations hold true: (i) 0|C^i|0=0|C^i|0\left\langle 0\right|\hat{C}_{i}^{\dagger}\left|0\right\rangle=\left\langle 0\right|\hat{C}_{i}\left|0\right\rangle, (ii) m|C^i|0=m|C^i|0\left\langle m\right|\hat{C}_{i}^{\dagger}\left|0\right\rangle=\left\langle m\right|\hat{C}_{i}\left|0\right\rangle, and (iii) 0|C^i|m=0|C^i|m\left\langle 0\right|\hat{C}_{i}^{\dagger}\left|m\right\rangle=\left\langle 0\right|\hat{C}_{i}\left|m\right\rangle. It’s obvious that if (γi)0=0(\gamma_{i})_{0}=0 these three equations hold true. If (γi)0=π(\gamma_{i})_{0}=\pi we can prove that the above three equations still hold. For example,

m|C^i|0\displaystyle\left\langle m\right|\hat{C}_{i}^{\dagger}\left|0\right\rangle =\displaystyle= (0|C^i|m)\displaystyle\left(\left\langle 0\right|\hat{C}_{i}\left|m\right\rangle\right)^{\ast} (4)
=\displaystyle= (ei(γi)m0|m)\displaystyle\left(e^{i(\gamma_{i})_{m}}\left\langle 0|-m\right\rangle\right)^{\ast}
=\displaystyle= ei(γi)mδ0,m\displaystyle e^{-i(\gamma_{i})_{m}}\delta_{0,-m}
=\displaystyle= eiπδm,0\displaystyle e^{-i\pi}\delta_{m,0}
=\displaystyle= eiπδm,0\displaystyle e^{i\pi}\delta_{m,0}
=\displaystyle= m|C^i|0.\displaystyle\left\langle m\right|\hat{C}_{i}\left|0\right\rangle.

Similarly, we can prove Equation (i) and Equation (iii). To summarize, we have proven that when the condition (γi)m=(γi)m(\gamma_{i})_{-m}=-(\gamma_{i})_{m} is satisfied, and (γi)0(\gamma_{i})_{0} can only take the values 0 or π\pi, C^i\hat{C}_{i} is a Hermitian operator.

We can also prove that under the same conditions, C^i2=I\hat{C}_{i}^{2}=I.

C^i2|m\displaystyle\hat{C}_{i}^{2}\left|m\right\rangle =\displaystyle= C^iei(γi)m|m\displaystyle\hat{C}_{i}e^{i(\gamma_{i})_{m}}\left|-m\right\rangle (5)
=\displaystyle= ei[(γi)m+(γi)m]|m\displaystyle e^{i\left[(\gamma_{i})_{m}+(\gamma_{i})_{-m}\right]}\left|m\right\rangle
=\displaystyle= |m,\displaystyle\left|m\right\rangle,

and

C^i2|0\displaystyle\hat{C}_{i}^{2}\left|0\right\rangle =\displaystyle= C^ieiπ|0\displaystyle\hat{C}_{i}e^{i\pi}\left|0\right\rangle (6)
=\displaystyle= ei2π|0\displaystyle e^{i2\pi}\left|0\right\rangle
=\displaystyle= |0.\displaystyle\left|0\right\rangle.

So the eigenvalues of C^i\hat{C}_{i} are restricted to 1-1 or +1+1.

Next, we will prove that using the operators A^i\hat{A}_{i}, B^j\hat{B}_{j}, and C^k\hat{C}_{k} designed in Eq. (2), along with the three-particle entangled state |ψ=12j+1m=jj|m|m|m\left|\psi\right\rangle=\frac{1}{\sqrt{2j+1}}\sum_{m=-j}^{j}{\left|m\right\rangle\otimes\left|m\right\rangle\otimes\left|m\right\rangle}, we can achieve the violation of three-particle SI for any bosons (with j0j\neq 0) and fermions, and that we can achieve the maximum quantum violation. We first calculate AiBjCk\langle A_{i}B_{j}C_{k}\rangle,

AiBjCk\displaystyle\langle A_{i}B_{j}C_{k}\rangle (7)
=\displaystyle= ψ|A^iB^jC^k|ψ\displaystyle\left\langle\psi\right|\hat{A}_{i}\hat{B}_{j}\hat{C}_{k}\left|\psi\right\rangle
=\displaystyle= 12j+1n=jjm=jjei[(αi)m+(βj)m+(γk)m]δn,m\displaystyle\frac{1}{2j+1}\sum_{n=-j}^{j}\sum_{m=-j}^{j}{e^{i\left[(\alpha_{i})_{m}+(\beta_{j})_{m}+(\gamma_{k})_{m}\right]}\cdot\delta_{n,-m}}
=\displaystyle= 12j+1m=jjei[(αi)m+(βj)m+(γk)m].\displaystyle\frac{1}{2j+1}\sum_{m=-j}^{j}{e^{i\left[(\alpha_{i})_{m}+(\beta_{j})_{m}+(\gamma_{k})_{m}\right]}}.

Then we have

S3=12j+1m=jj[ei[(α0)m+(β0)m+(γ0)m]\displaystyle\langle S_{3}\rangle=\frac{1}{2j+1}\sum_{m=-j}^{j}\bigg{[}e^{i\left[(\alpha_{0})_{m}+(\beta_{0})_{m}+(\gamma_{0})_{m}\right]}
+ei[(α0)m+(β1)m+(γ0)m]+ei[(α1)m+(β0)m+(γ0)m]\displaystyle+e^{i\left[(\alpha_{0})_{m}+(\beta_{1})_{m}+(\gamma_{0})_{m}\right]}+e^{i\left[(\alpha_{1})_{m}+(\beta_{0})_{m}+(\gamma_{0})_{m}\right]}
ei[(α1)m+(β1)m+(γ0)m]][ei[(α0)m+(β1)m+(γ1)m]\displaystyle-e^{i\left[(\alpha_{1})_{m}+(\beta_{1})_{m}+(\gamma_{0})_{m}\right]}\bigg{]}-\bigg{[}e^{i\left[(\alpha_{0})_{m}+(\beta_{1})_{m}+(\gamma_{1})_{m}\right]}
+ei[(α1)m+(β0)m+(γ1)m]+ei[(α1)m+(β1)m+(γ1)m]\displaystyle+e^{i\left[(\alpha_{1})_{m}+(\beta_{0})_{m}+(\gamma_{1})_{m}\right]}+e^{i\left[(\alpha_{1})_{m}+(\beta_{1})_{m}+(\gamma_{1})_{m}\right]}
ei[(α0)m+(β0)m+(γ1)m]].\displaystyle-e^{i\left[(\alpha_{0})_{m}+(\beta_{0})_{m}+(\gamma_{1})_{m}\right]}\bigg{]}. (8)

For the case of jj half-integer.

S3=22j+1m=1/2j[cos(000)+cos(010)+cos(100)\displaystyle\langle S_{3}\rangle=\frac{2}{2j+1}\sum_{m=1/2}^{j}\bigg{[}\cos(000)+\cos(010)+\cos(100)
cos(110)][cos(011)+cos(101)+cos(111)\displaystyle-\cos(110)\bigg{]}-\bigg{[}\cos(011)+\cos(101)+\cos(111)
cos(001)].\displaystyle-\cos(001)\bigg{]}. (9)

In Eq. (9), we use a shorthand notation, where cos(ijk)=cos[(αi)m+(βj)m+(γk)m]\cos(ijk)=\cos\left[(\alpha_{i})_{m}+(\beta_{j})_{m}+(\gamma_{k})_{m}\right]. If we let (αi)m(\alpha_{i})_{m}, (βi)m(\beta_{i})_{m}, and (γi)m(\gamma_{i})_{m} take the following values, we will obtain the maximum value of S3\langle S_{3}\rangle:

(α0)m=π4,(α1)m=π4,\displaystyle(\alpha_{0})_{m}=-\frac{\pi}{4},~{}~{}(\alpha_{1})_{m}=\frac{\pi}{4},
(β0)m=0,(β1)m=π2,\displaystyle(\beta_{0})_{m}=0,~{}~{}~{}~{}~{}(\beta_{1})_{m}=\frac{\pi}{2},
(γ0)m=0,(γ1)m=π2,\displaystyle(\gamma_{0})_{m}=0,~{}~{}~{}~{}~{}(\gamma_{1})_{m}=\frac{\pi}{2}, (10)

and

S3max\displaystyle\langle S_{3}\rangle_{max} =\displaystyle= 22j+1m=1/2j42\displaystyle\frac{2}{2j+1}\sum_{m=1/2}^{j}{4\sqrt{2}} (11)
=\displaystyle= 42.\displaystyle 4\sqrt{2}.

We see that our scheme directly gives the maximum quantum violation of SI for any fermions.

For the case of j1j\geq 1 integer. If we take (α0)0=(α1)0=(β0)0=(β1)0=(γ0)0=0(\alpha_{0})_{0}=(\alpha_{1})_{0}=(\beta_{0})_{0}=(\beta_{1})_{0}=(\gamma_{0})_{0}=0 and (γ1)0=π(\gamma_{1})_{0}=\pi, Eq. (8) becomes the following equation:

S3=22j+1{2+m=1j[cos(000)+cos(010)\displaystyle\langle S_{3}\rangle=\frac{2}{2j+1}\bigg{\{}2+\sum_{m=1}^{j}\big{[}\cos(000)+\cos(010)
+cos(100)cos(110)][cos(011)+cos(101)\displaystyle+\cos(100)-\cos(110)\big{]}-\big{[}\cos(011)+\cos(101)
+cos(111)cos(001)]}.\displaystyle+\cos(111)-\cos(001)\big{]}\bigg{\}}. (12)

We still let (αi)m(\alpha_{i})_{m}, (βi)m(\beta_{i})_{m}, and (γi)m(\gamma_{i})_{m} (m0m\neq 0) take the values of Eq. (10), and obtain the maximum value of S3\langle S_{3}\rangle for bosons:

S3max=22j+1(2+42j).\displaystyle\langle S_{3}\rangle_{max}=\frac{2}{2j+1}\left(2+4\sqrt{2}j\right). (13)

We find that the value of S3max\langle S_{3}\rangle_{max} increases monotonically as jj grows, and when j=1j=1, S3max5.1>4\langle S_{3}\rangle_{max}\approx 5.1>4. Therefore, for all bosons with j1j\geq 1, our scheme can lead to a violation of SI. Additionally, we find that as jj approaches infinity, our scheme can achieve the maximum quantum violation of SI, i.e. limj22j+1(2+42j)=42\lim_{j\to\infty}\frac{2}{2j+1}\left(2+4\sqrt{2}j\right)=4\sqrt{2}.

III The violation of NN-particle SI in a system of spins jj

In the NN-particle SI, there are NN observers, each sharing one particle. We denote the measurement operator of the ii-th observer as A^xi(i)\hat{A}_{x_{i}}^{(i)}, where xix_{i} can take values 0 or 11, representing two measurement choices A^0i\hat{A}_{0}^{i} and A^1i\hat{A}_{1}^{i} for each observer. The eigenvalues of each operator A^xi(i)\hat{A}_{x_{i}}^{(i)} are 1-1 and 11. Similarly to the case of the 33-particle system, we use {|mi;jmj}\{\left|m\right\rangle_{i};-j\leq m\leq j\} to represent an orthonormal basis that spans the Hilbert space of the ii-th particle with spin jj. We can define all A^xi(i)\hat{A}_{x_{i}}^{(i)} by their action on the basis {|mi;jmj}\{\left|m\right\rangle_{i};-j\leq m\leq j\}

A^xi(i)|mi=ei(αxi(i))m|mi,(αxi(i))m=(αxi(i))m.\displaystyle\hat{A}_{x_{i}}^{(i)}\left|m\right\rangle_{i}=e^{i\left(\alpha_{x_{i}}^{(i)}\right)_{m}}\left|-m\right\rangle_{i},~{}~{}\left(\alpha_{x_{i}}^{(i)}\right)_{-m}=-\left(\alpha_{x_{i}}^{(i)}\right)_{m}.
(14)

As we have proven in the case of the 33-particle system, when the condition (αxi(i))m=(αxi(i))m\left(\alpha_{x_{i}}^{(i)}\right)_{-m}=-\left(\alpha_{x_{i}}^{(i)}\right)_{m} is satisfied, and (αxi(i))0\left(\alpha_{x_{i}}^{(i)}\right)_{0} can only take the values 0 or π\pi, A^xi(i)\hat{A}_{x_{i}}^{(i)} is a Hermitian operator and (A^xi(i))2=I\left(\hat{A}_{x_{i}}^{(i)}\right)^{2}=I.

We can express NN-particle SI as

|SN|\displaystyle\left|\langle S_{N}\rangle\right| =\displaystyle= |{xi}vkA^x1(1)A^x2(2)A^xN(N)|\displaystyle\left|\langle\sum_{\{x_{i}\}}{v_{k}\hat{A}_{x_{1}}^{(1)}\hat{A}_{x_{2}}^{(2)}\cdot\cdot\cdot\hat{A}_{x_{N}}^{(N)}}\rangle\right| (15)
\displaystyle\leq 2N1,\displaystyle 2^{N-1},

where {xi}\{x_{i}\} represents an NN-tuple (x1,,xN)(x_{1},...,x_{N}) that denotes the measurement choices of NN observers, and the sum is taken over all such tuples, or equivalently, over all possible measurement choices. The vkv_{k} is the sign function associated with the corresponding term A^x1(1)A^x2(2)A^xN(N)\hat{A}_{x_{1}}^{(1)}\hat{A}_{x_{2}}^{(2)}\cdot\cdot\cdot\hat{A}_{x_{N}}^{(N)}, and is given by vk=(1)[k(k1)/2]v_{k}=(-1)^{[k(k-1)/2]}, where kk denotes the number of times the index 11 appears in the tuple (x1,x2,,xN)(x_{1},x_{2},...,x_{N}). We will herealfter refer to SNS_{N} as Svetlichny’s operator, whose quantum mechanical maximum value is 2N122^{N-1}\sqrt{2} [22].

Below, we will demonstrate through calculation that by taking the following NN-particle entangled state |ψN\left|\psi_{N}\right\rangle and applying the measurement operators A^xi(i)\hat{A}_{x_{i}}^{(i)} defined in Eq. (14), we can always achieve a violation of the NN-particle SI for any bosons (j1j\geq 1) and fermions, and we can attain the maximal quantum violation. We assume that the NN particles are in the entangled state

|ψN=12j+1m=jj|m1|m2|mN,\displaystyle\left|\psi_{N}\right\rangle=\frac{1}{\sqrt{2j+1}}\sum_{m=-j}^{j}{\left|m\right\rangle_{1}\otimes\left|m\right\rangle_{2}\otimes\cdot\cdot\cdot\otimes\left|m\right\rangle_{N}}, (16)

and by using Eq. (14), we can derive

SN\displaystyle\langle S_{N}\rangle =\displaystyle= ψN|SN|ψN\displaystyle\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle (17)
=\displaystyle= 12j+1m=jj[{xi}vkeii=1N(αxi(i))m],\displaystyle\frac{1}{2j+1}\sum_{m=-j}^{j}\left[\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{m}}}\right],

where i=1N(αxi(i))m=(αx1(1))m+(αx2(2))m++(αxN(N))m\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{m}}=\left(\alpha_{x_{1}}^{(1)}\right)_{m}+\left(\alpha_{x_{2}}^{(2)}\right)_{m}+\cdot\cdot\cdot+\left(\alpha_{x_{N}}^{(N)}\right)_{m}.

For the case of jj half-integer. In this case Eq. (17) becomes the following equation

ψN|SN|ψN\displaystyle\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle (18)
=\displaystyle= 22j+1m=1/2j[{xi}vkcos(i=1N(αxi(i))m)].\displaystyle\frac{2}{2j+1}\sum_{m=1/2}^{j}\left[\sum_{\{x_{i}\}}v_{k}\cos\left(\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{m}}\right)\right].

Next, we need to find the appropriate values of the phases (αxi(i))m\left(\alpha_{x_{i}}^{(i)}\right)_{m} that will maximize ψN|SN|ψN\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle. The focus is on studying the sign function vk=(1)[k(k1)/2]v_{k}=(-1)^{[k(k-1)/2]}. We assume k=4q+lk=4q+l, where ll is the remainder when kk is divided by 44, so we have

vk\displaystyle v_{k} =\displaystyle= (1)[k(k1)/2]=(1)[(4q+l)(4q+l1)/2]\displaystyle(-1)^{[k(k-1)/2]}=(-1)^{[(4q+l)(4q+l-1)/2]} (19)
=\displaystyle= {1l=0,11l=2,3.\displaystyle\left\{\begin{aligned} 1\quad l=0,1\\ -1\quad l=2,3.\\ \end{aligned}\right.

We find that, depending on the value of ll, all NN-tuples (x1,,xN)(x_{1},...,x_{N}) can be classified into four categories, corresponding to l=0,1,2,3l=0,1,2,3, respectively. Therefore, if the values of (αxi(i))m\left(\alpha_{x_{i}}^{(i)}\right)_{m} corresponding to the different categorical NN-tuples (x1,,xN)(x_{1},...,x_{N}) satisfy the following condition, ψN|SN|ψN\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle can attain its maximum value.

i=1N(αxi(i))m=π4N-tuple{xi}ofl=0,\displaystyle\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{m}}=-\frac{\pi}{4}\Longleftrightarrow N\text{-tuple}~{}\{x_{i}\}~{}of~{}l=0,
i=1N(αxi(i))m=π4N-tuple{xi}ofl=1,\displaystyle\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{m}}=\frac{\pi}{4}\Longleftrightarrow N\text{-tuple}~{}\{x_{i}\}~{}of~{}l=1,
i=1N(αxi(i))m=3π4N-tuple{xi}ofl=2,\displaystyle\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{m}}=\frac{3\pi}{4}\Longleftrightarrow N\text{-tuple}~{}\{x_{i}\}~{}of~{}l=2,
i=1N(αxi(i))m=5π4N-tuple{xi}ofl=3.\displaystyle\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{m}}=\frac{5\pi}{4}\Longleftrightarrow N\text{-tuple}~{}\{x_{i}\}~{}of~{}l=3. (20)

We find that the values of (αi)m(\alpha_{i})_{m}, (βi)m(\beta_{i})_{m}, and (γi)m(\gamma_{i})_{m} in Eq. (10) satisfy the conditions outlined in Eq. (20) for the case N=3N=3. In the Appendix, we prove that appropriate values of the phases (αxi(i))m\left(\alpha_{x_{i}}^{(i)}\right)_{m} can always be found to satisfy the conditions in Eq. (20) for any NN. Finally we obtain the maximum value of ψN|SN|ψN\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle as

ψN|SN|ψNmax\displaystyle\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle_{max} =\displaystyle= 22j+1m=1/2j{xi}22\displaystyle\frac{2}{2j+1}\sum_{m=1/2}^{j}\sum_{\{x_{i}\}}\frac{\sqrt{2}}{2} (21)
=\displaystyle= 22j+1m=1/2j2N22\displaystyle\frac{2}{2j+1}\sum_{m=1/2}^{j}2^{N}\frac{\sqrt{2}}{2}
=\displaystyle= 2N12.\displaystyle 2^{N-1}\sqrt{2}.

We see that our scheme directly gives the maximum quantum violation of NN-particle SI for any fermions.

For the case of j1j\geq 1 integer. In this case Eq. (17) becomes the following equation

ψN|SN|ψN\displaystyle\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle (22)
=\displaystyle= 22j+1m=1j[{xi}vkcos(i=1N(αxi(i))m)]\displaystyle\frac{2}{2j+1}\sum_{m=1}^{j}\left[\sum_{\{x_{i}\}}v_{k}\cos\left(\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{m}}\right)\right]
+12j+1{xi}vkeii=1N(αxi(i))0.\displaystyle+\frac{1}{2j+1}\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}}.

Let’s first analyze the term {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} in the second term on the right-hand side of the above equation. We have already proven that, in order to ensure the Hermiticity of the operator A^xi(i)\hat{A}_{x_{i}}^{(i)}, (αxi(i))0\left(\alpha_{x_{i}}^{(i)}\right)_{0} can only take the values 0 or π\pi. Once (αxi(i))0\left(\alpha_{x_{i}}^{(i)}\right)_{0} is fixed to either 0 or π\pi, it is equivalent to setting ei(αxi(i))0e^{i\left(\alpha_{x_{i}}^{(i)}\right)_{0}} to be either 11 or 1-1. First of all, it is quite obvious that we can always ensure that {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} is greater than zero. Then, from the SI itself, we can obtain

{xi}vkeii=1N(αxi(i))02N1.\displaystyle\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}}\leq 2^{N-1}. (23)

We have seen that for the case of N=3N=3, by appropriately choosing (αxi(i))0\left(\alpha_{x_{i}}^{(i)}\right)_{0}, we can make {xi}vkeii=13(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{3}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} reach the right-hand side of Eq. (23), which equals 2N1=42^{N-1}=4, as shown in Eq. (12). However, 2N12^{N-1} represents the upper bound for SI, and in general, {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} cannot reach this value. In SI, we allow some particles (but not all) to have arbitrary correlations, even those that exceed quantum correlations. However, in the case of {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} , since all ei(αxi(i))0e^{i\left(\alpha_{x_{i}}^{(i)}\right)_{0}}’s are already fixed to either 11 or 1-1, what we are actually seeking is the upper bound of Svetlichny’s operator within the framework of local hidden variable theory. In the Appendix, we will prove that the stricter upper bound for {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} is actually 2N+1\sqrt{2^{N+1}}. In the case of N=3N=3, 2N+1=2N1\sqrt{2^{N+1}}=2^{N-1}, which explains why {xi}vkeii=13(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{3}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} reaches the upper bound for SI, as shown in Eq. (12). Finally, by choosing (αxi(i))m\left(\alpha_{x_{i}}^{(i)}\right)_{m} to satisfy the condition in Eq. (20), we obtain

2N122j2j+1\displaystyle 2^{N-1}\frac{2\sqrt{2}j}{2j+1} <\displaystyle< ψN|SN|ψNmax\displaystyle\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle_{max} (24)
\displaystyle\leq 2N122j2j+1+2N+12j+1\displaystyle 2^{N-1}\frac{2\sqrt{2}j}{2j+1}+\frac{\sqrt{2^{N+1}}}{2j+1}
=\displaystyle= 2N1(22j+23N22j+1).\displaystyle 2^{N-1}\left(\frac{2\sqrt{2}j+2^{\frac{3-N}{2}}}{2j+1}\right).

We see that for all cases where j2j\geq 2, we have ψN|SN|ψNmax>2N1\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle_{max}>2^{N-1}, meaning that we obtain SI violation; furthermore, as jj approaches infinity, we reach the maximum quantum violation limj2N122j2j+1=limj2N1(22j+23N22j+1)=2N12\lim_{j\to\infty}2^{N-1}\frac{2\sqrt{2}j}{2j+1}=\lim_{j\to\infty}2^{N-1}\left(\frac{2\sqrt{2}j+2^{\frac{3-N}{2}}}{2j+1}\right)=2^{N-1}\sqrt{2}. For the case of j=1j=1, from the upper bound of ψN|SN|ψNmax\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle_{max} in Eq. (24), we can see that when N9N\geq 9, our scheme cannot give rise to SI violation. Apart from the already discussed case of N=3N=3, for N=4,5,6,7,8N=4,5,6,7,8, we have found the values of (αxi(i))0\left(\alpha_{x_{i}}^{(i)}\right)_{0}’s that maximize ψN|SN|ψNmax\left\langle\psi_{N}\right|S_{N}\left|\psi_{N}\right\rangle_{max}. For N=4,5,6,7N=4,5,6,7, our scheme lead to a violation of SI, while for N=8N=8, no values of (αxi(i))0\left(\alpha_{x_{i}}^{(i)}\right)_{0}’s that cause a violation of SI were found. All these results are listed in the Appendix.

IV Conclusion

In this study, we have developed a comprehensive framework for understanding and demonstrating the violation of SI across various particle systems with non-zero spin. Our findings reveal that for fermion systems, the maximal quantum violation of SI can be achieved regardless of the number of particles involved. For boson systems, we established that when the particle spin j2j\geq 2, SI violation is attainable for any particle count. Additionally, we identified specific conditions under which SI can be violated for boson systems with j=1j=1 when the particle number does not exceed 77. As jj approaches infinity, our scheme consistently achieves the maximal quantum violation of SI. Furthermore, we have shown that the upper bound of Svetlichny’s operator within local hidden variable theory is 2N+1\sqrt{2^{N+1}}, providing a crucial insight into the limitations of classical correlations. Notably, our scheme enables the maximal quantum violation of SI for any fermion system. We believe that designing a scheme to achieve the maximal quantum violation of SI for arbitrary boson systems with j0j\neq 0 for any NN is an intriguing problem and will be a focus of future research. These findings contribute to a deeper understanding of quantum correlations in various particle systems and have practical implications for designing quantum communication protocols that leverage entanglement and non-locality in multi-particle setups.

Acknowledgments

This work is supported by the National Natural Science Foundation of China under Grant No. 11005031.

Appendix

1. The appropriate values of the phases (αxi(i))m\left(\alpha_{x_{i}}^{(i)}\right)_{m} can always be found to satisfy the conditions in Eq. (20) for any NN.

For the case N=3N=3, the values of (αi)m(\alpha_{i})_{m}, (βi)m(\beta_{i})_{m}, and (γi)m(\gamma_{i})_{m} in Eq. (10) satisfy the conditions outlined in Eq. (20). We prove by mathematical induction that for any NN, appropriate values of the phases (αxi(i))m\left(\alpha_{x_{i}}^{(i)}\right)_{m} can always be found to satisfy the conditions in Eq. (20). Assume that for N1N-1, appropriate values of (αxi(i))m\left(\alpha_{x_{i}}^{(i)}\right)_{m} (for i=1,2,,N1i=1,2,...,N-1) have already been found that satisfy Eq. (20). Since we have

i=1N(αxi(i))m=i=1N1(αxi(i))m+(αxN(N))m,\displaystyle\sum_{i=1}^{N}\left(\alpha_{x_{i}}^{(i)}\right)_{m}=\sum_{i=1}^{N-1}\left(\alpha_{x_{i}}^{(i)}\right)_{m}+\left(\alpha_{x_{N}}^{(N)}\right)_{m}, (25)

where i=1N1(αxi(i))m\sum_{i=1}^{N-1}\left(\alpha_{x_{i}}^{(i)}\right)_{m} already satisfies the conditions in Eq. (20), we can choose (αxN=0(N))m=0\left(\alpha_{x_{N}=0}^{(N)}\right)_{m}=0 and (αxN=1(N))m=π2\left(\alpha_{x_{N}=1}^{(N)}\right)_{m}=\frac{\pi}{2}. Then, from the above equation, it follows that i=1N(αxi(i))m\sum_{i=1}^{N}\left(\alpha_{x_{i}}^{(i)}\right)_{m} will also satisfy the conditions in Eq. (20).


2. The upper bound of Svetlichny’s operator SNS_{N} within the framework of local hidden variable theory is 2N+1\sqrt{2^{N+1}}.

Specifically, we prove that once all (αxi(i))0\left(\alpha_{x_{i}}^{(i)}\right)_{0}’s are fixed to either 0 or π\pi, we have

{xi}vkeii=1N(αxi(i))02N+1.\displaystyle\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}}\leq\sqrt{2^{N+1}}. (26)

For simplicity of notation, we define ei(αxi(i))0=Axi(i)e^{i\left(\alpha_{x_{i}}^{(i)}\right)_{0}}=A_{x_{i}}^{(i)}, so that when (αxi(i))0\left(\alpha_{x_{i}}^{(i)}\right)_{0} is fixed to either 0 or π\pi, Axi(i)A_{x_{i}}^{(i)} takes values 11 or 1-1. This leads to

{xi}vkeii=1N(αxi(i))0={xi}vkAx1(1)Ax2(2)AxN(N).\displaystyle\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}}=\sum_{\{x_{i}\}}{v_{k}A_{x_{1}}^{(1)}A_{x_{2}}^{(2)}\cdot\cdot\cdot A_{x_{N}}^{(N)}}. (27)

Next, we construct a complex function ff, whose value depends on all Axi(i)A_{x_{i}}^{(i)}:

f=(A0(1)+iA1(1))(A0(2)+iA1(2))(A0(N)+iA1(N)).\displaystyle f=\left(A_{0}^{(1)}+iA_{1}^{(1)}\right)\left(A_{0}^{(2)}+iA_{1}^{(2)}\right)\cdot\cdot\cdot\left(A_{0}^{(N)}+iA_{1}^{(N)}\right).
(28)

Noting the properties of the sign function vkv_{k} in Eq. (19), and comparing Eq. (27) with Eq. (28), we find that

{xi}vkeii=1N(αxi(i))0=Ref+Imf,\displaystyle\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}}=Ref+Imf, (29)

where RefRef and ImfImf represent the real and imaginary parts of the function ff, respectively. Clearly, the modulus of ff satisfies

|f|2=(Ref)2+(Imf)2=2N.\displaystyle\left|f\right|^{2}=\left(Ref\right)^{2}+\left(Imf\right)^{2}=2^{N}. (30)

Thus, we have

{xi}vkeii=1N(αxi(i))0\displaystyle\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} =\displaystyle= Ref+Imf\displaystyle Ref+Imf (31)
\displaystyle\leq 2((Ref)2+(Imf)2)\displaystyle\sqrt{2\left(\left(Ref\right)^{2}+\left(Imf\right)^{2}\right)}
=\displaystyle= 2N+1\displaystyle\sqrt{2^{N+1}}

3. The maximum value of {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} for N=4,5,6,7,8N=4,5,6,7,8.

We used Mathematica to calculate the maximum value of {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} when all (αxi(i))0\left(\alpha_{x_{i}}^{(i)}\right)_{0}’s are fixed to either 0 or π\pi.

(i) N=4N=4

We set (αx4=1(4))0=π\left(\alpha_{x_{4}=1}^{(4)}\right)_{0}=\pi and fix all other (αxi(i))0=0\left(\alpha_{x_{i}}^{(i)}\right)_{0}=0. This yields the maximum value of {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} as 44. Substituting this into Eq. (22), we calculate that for j=1j=1, SNmax2N11.10948\frac{\langle S_{N}\rangle_{max}}{2^{N-1}}\approx 1.10948, which results in a violation of SI.

(ii) N=5N=5

We set (αx5=0(5))0=(αx5=1(5))0=π\left(\alpha_{x_{5}=0}^{(5)}\right)_{0}=\left(\alpha_{x_{5}=1}^{(5)}\right)_{0}=\pi and fix all other (αxi(i))0=0\left(\alpha_{x_{i}}^{(i)}\right)_{0}=0. This yields the maximum value of {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} as 88. Substituting this into Eq. (22), we calculate that for j=1j=1, SNmax2N11.10948\frac{\langle S_{N}\rangle_{max}}{2^{N-1}}\approx 1.10948, which leads to a violation of SI.

(iii) N=6N=6

We take (αx6=0(6))0=(αx6=1(6))0=π\left(\alpha_{x_{6}=0}^{(6)}\right)_{0}=\left(\alpha_{x_{6}=1}^{(6)}\right)_{0}=\pi and set all other (αxi(i))0=0\left(\alpha_{x_{i}}^{(i)}\right)_{0}=0. This yields the maximum value of {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} as 88. Substituting this into Eq. (22), we calculate that for j=1j=1, SNmax2N11.02614\frac{\langle S_{N}\rangle_{max}}{2^{N-1}}\approx 1.02614, which leads to a violation of SI.

(iv) N=7N=7

We set (αx6=1(6))0=(αx7=0(7))0=(αx7=1(7))0=π\left(\alpha_{x_{6}=1}^{(6)}\right)_{0}=\left(\alpha_{x_{7}=0}^{(7)}\right)_{0}=\left(\alpha_{x_{7}=1}^{(7)}\right)_{0}=\pi and fix all other (αxi(i))0=0\left(\alpha_{x_{i}}^{(i)}\right)_{0}=0. This gives the maximum value of {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} as 1616. Substituting this into Eq. (22), we calculate that for j=1j=1, SNmax2N11.02614\frac{\langle S_{N}\rangle_{max}}{2^{N-1}}\approx 1.02614, which results in a violation of SI.

(v) N=8N=8

We set all (αxi(i))0=0\left(\alpha_{x_{i}}^{(i)}\right)_{0}=0, and the maximum value of {xi}vkeii=1N(αxi(i))0\sum_{\{x_{i}\}}v_{k}e^{i\sum_{i=1}^{N}{\left(\alpha_{x_{i}}^{(i)}\right)_{0}}} is obtained as 1616. However, this result does not lead to a violation of SI, because when we substitute this result into Eq. (22), we calculate that for j=1j=1, SNmax2N10.984476\frac{\langle S_{N}\rangle_{max}}{2^{N-1}}\approx 0.984476.

References